Choose the function whose graph is given below.

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Answer:  [tex]\textsf{x}^2\textsf{ - 14x + 24}[/tex]

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Given:  [tex]\textsf{x = 12 and x = 2}[/tex]

Find: [tex]\textsf{Determine the quadratic equation}[/tex]

Solution:  In order to determine the quadratic equation we need to move the integers onto the side where x is and then distribute.

Move the integers

Create and expression and distribute

Therefore, after completing the steps we were able to determine that the quadratic equation that will have solutions of x = 12 and x = 2 is x^2 - 14x + 24.

The remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

We know that the remainder theorem states that if a polynomial p(x) is divided by a linear polynomial q(x) whose zero is x = a, then the remainder is given by r = p(a).

Here p(x) = f(x) = 2x³ + 2x² - 3x - 3 and q(x) = x - 2. First, we have to find the zero of q(x).

Now, q(x) = 0

i.e. x - 2 = 0

i.e. x = 2.

So, the zero of q(x) is 2, i.e. a = 2.

Then by the remainder theorem,

r = p(a) = f(2) = 2(2)³ + 2(2)² - 3(2) - 3 = 2 × 8 + 2 × 4 - 6 - 3 = 16 + 8 - 9 = 16 - 1 = 15

We can conclude that the remainder when f(x) = 2x³ + 2x² - 3x - 3 is divided by x - 2 is 15.

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Answer:

HI i no  answer of this quetion but what grade are in school

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

"If the 2 is quantity use multiply it again"

NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

[tex]\large\bold{SOLUTION} \\ [/tex]

GIVEN :-

FIND :-

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

[tex] \bold{Formula:}[/tex]

[tex] \qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}[/tex]

Now let's start solving :-

[tex] \quad \sf \implies{Area = Length \times Width} \\ [/tex]

[tex] \quad \sf \implies{Area = 12ft \times 4.2ft} \\ [/tex]

[tex] \quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}} \\ [/tex]

[tex] \quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}} \\ [/tex]

Therefore, the area of the space that needs to be covered is 100.80ft² .

[tex] \underline{ \rule{185pt}{3pt}}[/tex]

Answer:

Hey there : y= 3x - 3

Answer:

y = [tex]\frac{3}{2}[/tex] x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line

m = [tex]\frac{3-0}{0-(-2)}[/tex] = [tex]\frac{3}{0+2}[/tex] = [tex]\frac{3}{2}[/tex]

the line crosses the y- axis at (0, 3 ) ⇒ c = 3

y = [tex]\frac{3}{2}[/tex] x + 3 ← equation of line

7h-15h+40=-72

40+72=15h-7h

112=8h

h=14

One complete period of a non-transformed cotangent function is π.

The period of the function is defined as the interval after which the function value repeats itself.

For example, f(T+x)=f(x)

where T is the period of the function.

Here given that there is a non-transformed function cotangent function.

We have to find the period of the function in which interval the value of the function will repeat.

So for the function y=f(x)=cot x

the period of the function is π. means after π the value of the cotangent repeats.

cot(π+x)=cot x

Then one cycle of the cotangent graph lies between 0 and π.

Therefore One complete period of a non-transformed cotangent function is π.

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Answer:

Graph B

Step-by-step explanation:

When graphing inequalities:

Given inequality:

[tex]y-5 > 2x-10[/tex]

Rearrange the given inequality to make y the subject:

[tex]\implies y-5+5 > 2x-10+5[/tex]

[tex]\implies y > 2x-5[/tex]

Therefore, we need to draw a dashed line and shade above it.

To draw the line:

Replace the > with = to find two points on the line:

[tex]\implies y=2x-5[/tex]

[tex]x=0 \implies y=2(0)-5=-5 \implies (0,-5)[/tex]

[tex]x=3 \implies y=2(3)-5=1 \implies (3,1)[/tex]

Plot the two found points: (0, -5) and (3, 1)

As the inequality is  y > 2x - 5

The inequality equation is solved and the solution is plotted on the graph

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Given data ,

Let the inequality equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

y - 5 > 2x - 10

On simplifying , we get

Adding 5 on both sides , we get

y > 2x - 5

where 2 is the slope and 5 is the the intercept

Now , let the first point be P ( 0 , -5 )

when x = 0 and y = -5

-5 > -5

And , the graph of the inequality is plotted

Hence , the inequality is solved

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The table is a function and the relation f(x) = 5x + 14 has a greater value when x = 9

The table of values is given as:

Input (x) 2 5 9 12

Output (y) 20 15 12 8

In the above table of values, each x value have a unique y value.

This means that the table is a one-to-one relation

A one-to-one relation is a function

Hence, the table is a function.

The function is given as:

f(x) = 5x + 14

This gives

f(9) = 5 * 9 + 14

Evaluate

f(9) = 59

From the table, we have:

y = 12 when x = 9

Hence, the relation f(x) = 5x + 14 has a greater value when x = 9

We have

f(x) = 5x + 14

This gives

5x + 14 = 64

Subtract 14 from both sides

5x = 50

Divide by 5

x = 10

Hence, the value of x when f(x) = 64 is 10

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when you subtract a negative number from any platitude number the equation changes to addition so you would add the value of the negative number to 1.

To subtract a negative number from one you will need to set it up like this

1- (-x) x equals the negative number you're talking about

so we use the method KCC (keep change change)

So we KEEP the positive one, CHANGE the subtraction sign in to a plus sign "+" then CHANGE the negative number to a positive

lets say the negative number is 2

1-(-2)

1+ (+2)

1+2 = 3

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: length = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = 4 \: \: in[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

Let the measures be :

[tex] \textsf{\large Area of rectangle :} [/tex]

[tex]\qquad \tt \rightarrow \: Area = length \sdot width [/tex]

[tex]\qquad \tt \rightarrow \: 44 = x \sdot(x + 7)[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x = 44[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 7x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: {x}^{2} + 11x - 4x - 44 = 0[/tex]

[tex]\qquad \tt \rightarrow \: x(x + 11) - 4(x + 11) = 0[/tex]

[tex]\qquad \tt \rightarrow \: (x + 11)(x - 4) = 0[/tex]

possible values of x = -11 and 4

[tex] \textsf{But the acceptable value of x = 4} [/tex]

[ length or width of rectangle can't be negative ]

[tex]\qquad \tt \rightarrow \: length = x + 7 = 4 + 7 = 11 \: \: in[/tex]

[tex]\qquad \tt \rightarrow \: width = x = 4 \: \: in[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The number of units that will maximize revenue will be 672 units.

From the given information, p = 336 - 0.5x. The revenue function will be:

= (336 - 0.5x)x

= 336x - 0.5x²

This will be equated to 0. This will be:

336x - 0.5x² = 0

0.5x² = 336x

0.5x = 336

x = 336/0.5

x = 672

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Step-by-step explanation:

1. let n=2, then, n+2= 2+2=4 so 2^2= 4 and 4^2=16 then 16-4=12 which is an even number

2. let n=4, the. n+3=4+3=7, and 4^2=16 and 7^2=49 then 49-16 =33 which is an odd number

please follow me

the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

To do this, we can think on the situation as a right triangle, where the hypotenuse is 4 miles, the angle that we look at measures 10.5°, and the change in elevation (let's call it x) will be the opposite cathetus to that angle.

Then we can use the relation:

Sin(a) = (opposite cathetus)/(hypotenuse)

Replacing what we know, we get:

sin(10.5°) = x/4mi

x = sin(10.5°)*4mi = 0.73mi

So the change in elevation is -0.73 miles (the negative sign is because the new elevation is smaller than the initial one).

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Let's take this problem step-by-step:

Let's convert the equation back into the standard form:

     ⇒ standard form: (x-h)² +(y-k)² = r²

       [tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]

Based on the equation found

  ⇒ center: (4, -5)

   ⇒ radius: 2

Answer:

Hope that helps!

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The transformation occurs from function g is a vertical translation 6 units down.

A function f, usually with some geometrical underpinning, that maps a set X to itself, i.e. f : X → X.

Given:

g(x) = 4x + 6

g(x) = 0

4x + 6=0

x= -6/4

Now,

f(-6/4) = 2 - 1

=-1

By seeing g(x), we can say that  function g is a vertical translation 6 units down.

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[tex]\textsf {21 cm}[/tex]

[tex]\textsf {If it is correct to the nearest centimeter, then the least side length}\\\textsf {would be 8 - 1 = 7 cm. }[/tex]

[tex]\textsf {Then, the least possible perimeter would be :}[/tex]

[tex]\mathsf {7 \times 3}[/tex]

[tex]\textsf {21 cm}[/tex]

Answer:

y=ax+b

a=-0.6020457867

b=-2.256697516   <------- There is your value for b, which is the answer to the problem.

You can use these values for a and b to generate an equation in slope-intercept form, which you can then enter under Y= and view the graph.

Step-by-step explanation:

The value of y is multiplied by 2 each time when the value of x increases by 1 and this can be determined by using the arithmetic operations.

Using operations like addition, subtraction, multiplication, and division, a mathematical expression is defined as a group of numerical variables and functions.

Given that,

Table --    x            y

                1            20

                2            40

                3            80

                4            160

                5            320

The following steps can be used in order to describe how the y values are changed over each interval:

Step 1 - When value of (x = 1) and the value of (y = 20).

Step 2 - When value of (x = 2) and the value of (y = 40).

Step 3 - When value of (x = 3) and the value of (y = 80).

Step 4 - When value of (x = 4) and the value of (y = 160).

Step 5 - From the above steps, it can be concluded that the value of y is multiplied by 2 each time when the value of x increases by 1.

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Answer:15

Step-by-step explanation:

Start off using Java. As u progress you cant move over to C and the then transfer to python.

Step-by-step explanation:

[tex] - \frac{3}{4} x + 2 \frac{1}{4 } = \frac{1}{2} x + 1[/tex]

[tex] - \frac{3}{4} x + \frac{9}{4} = \frac{1}{2} x + \frac{2}{2} [/tex]

[tex] \frac{ - 3x + 9}{4} = \frac{2x + 4}{4} [/tex]

[tex] - 3x + 9 = 2x + 4[/tex]

[tex] - 3x - 2x = 4 - 9[/tex]

[tex] - 5x = - 5[/tex]

[tex]x = \frac{ - 5}{ - 5} [/tex]

[tex]x = 1[/tex]

The answer is C.

Answer:

9,000 minutes (150 hours)

Step-by-step explanation:

You have 3,600 points total; you need to divide it by 2 points.
3,600 ÷ 2 = 1,800

So, now you need to multiply the 1,800 points by 5 minutes.

1,800 × 5 = 9,000

Another way:

You can figure out how long it takes to get 1 point. If 2 points takes 5 minutes, divide 5 by 2.

5 ÷ 2 = 2.5

Now you need to figure out how long it would take to get 3,600 points. If each point takes 2.5 minutes, just multiply.

3,600 × 2.5 = 9,000

It would take 9,000 minutes (which is equivalent to 150 hours) to get to 3,600 points.

Answer:

534

Step-by-step explanation:

The solution is in the image

Answer:

b = 2

Step-by-step explanation:

using the tangent ratio in the right triangle and the exact value

tan30° = [tex]\frac{1}{\sqrt{3} }[/tex] , then

tan30° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{b}{a}[/tex] = [tex]\frac{b}{2\sqrt{3} }[/tex] = [tex]\frac{1}{\sqrt{3} }[/tex] ( cross- multiply )

b × [tex]\sqrt{3}[/tex] = 2[tex]\sqrt{3}[/tex] ( divide both sides by [tex]\sqrt{3}[/tex] )

b = 2

Answer:

Given that a = 2√3.

Let's find value of b...

Answer:

200:1, Bryn is correct.

Step-by-step explanation:

Each 10 m is represented by a 5cm length on the diagram.  We first note that 100 cm = 1 meter.   5 cm is (0.5 cm)*(1 meter/100 cm) =0.05 meters.

The 0.05 meters on the diagram represents 10 meters on the actual building.  The ratio is (10 meters/0.05 meters) or 200:1.  This is what Bryn believes is the ratio.  

Answer:

{-3, 2, -5, 1, 6}

Step-by-step explanation:

The domain is the set of input values.

Answer:

x = ± [tex]\sqrt{2}[/tex] , x = ± i

Step-by-step explanation:

f(x) = [tex]x^{4}[/tex] - x² - 2

to find the zeros , equate f(x) to zero , that is

[tex]x^{4}[/tex] - x² - 2 = 0

using the substitution u = x² , then

u² - u - 2 = 0 ← in standard form

(u - 2)(u + 1) = 0 ← in factored form

equate each factor to zero and solve for u

u - 2 = 0 ⇒ u = 2

u + 1 = 0 ⇒ u = - 1

convert u back into terms of x

x² = 2 ( take square root of both sides )

x = ± [tex]\sqrt{2}[/tex]

x² = - 1 ( take square root of both sides )

x = ± [tex]\sqrt{-1}[/tex] = ± i

Answer: Positive or negative square root of 2, ±i

Proof o fvalidity is shown below.

Answer:

Step-by-step explanation:

1.  m³

2. cm³

3. s³

A unit of measurement is a definite magnitude of a quantity, defined and adopted by convention or by law, that is used as a standard for measurement of the same kind of quantity.

1. Volume is measure in m³

2.  volume of a rectangular pencil case in cm³

3. V = s x s x s or s³

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