Choose the system of inequalities that best match the graph below.

Using simple interest, it is found that the present value of the cash inflow is of 947.

Simple interest is used when there is a single compounding per time period.

The amount of money after t years in is modeled by:

A(t) = A(0)(1 + rt)

In which:

In this problem, the parameters are given as follows:

r = 0.08, t = 4, A(t) = 1250.

We have to solve for A(0) to find the present value, hence:

A(t) = A(0)(1 + rt)

1250 = A(0)(1 + 0.08 x 4)

A(0) = 1250/1.32

A(0) = 947.

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Answer: -120

Step-by-step explanation:

[tex]2\sum^{4}_{p=1} (p^{2}-9p)=2[(1^{2}-9(1))+(2^{2}-9(2))+(3^{2}-9(3))+(4^{2}-9(4))]=\boxed{-120}[/tex]

Answer: It is not a right angle.

The slope of line p is -5, so substitute into point-slope form, we get

[tex]\boxed{y-37=-5(x+2)}[/tex]

Answer:

Two points this line can pass through (1, 4/3) and (2, 8/3)

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

Given:

we can plug in a number for x to find y

when x = 0,

y = 4/3(0)

y = 0

point: (0,0)

when x = 1,

y = 4/3(1)

y = 4/3

point: (1, 4/3)

when x = 2,

y = 4/3(2)

y = 8/3

point: (2, 8/3)

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The set that represents the range of the diagram below is given as follows:

B. {3, 5, 7}.

It is the set that contains all possible output values.

In the diagram, we have that:

Hence the set that represents the range of the diagram below is given as follows:

B. {3, 5, 7}.

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Answer: D

Step-by-step explanation:  

6^4 = 6 x 6 x 6 x 6 = 1,296

6^4 = 1,296

From the slopes it is confirmed that PQ || RS OR|| SP and therefore it is a parallelogram .

A parallelogram is a quadrilateral in which the opposite sides are parallel.

The coordinates of a quadrilateral is given

To prove that it is a parallelogram

PQ || RS

OR|| SP

The slope of a straight line is given by

[tex]\rm m = \dfrac{y_2 -y_1}{x_2- x_1}[/tex]

For PQ

m = (-1/6) = -1/6

For QR

m = -6/1 = -6

For RS

m = 1/(-6) = -1/6

For SP

m = -6

From the slopes it is confirmed that

PQ || RS

OR|| SP

and therefore it is a parallelogram

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Answer:

$9

Step-by-step explanation:

Let, the price of pencils is x, and the price of rulers is y.

4x+2y=8.....(i)

2x+4y=10......(ii)

From eq(i),

2(2x+y)=8

2x+y=4

y=4-2x eq(iii)  .....put in eq(ii)

2x+4(4-2x)=10

2x+16-8x=10

-6x=10-16

x=-6/-6

x=1 put in eq (iii)

y=4-2(1)

y=2

Now, the price of 3 rulers and 3 pencils = 3x+3y=3(1)+3(2)

=9

Please give me brainlist.

Answer:

x = +1

x = -1

Step-by-step explanation:

x^4-1=0​

x^4=+1​

fourth root of x^4= fourth root of +1​

x = +1

x = -1

The baby is 111.3 ounces or 6.96 pounds lighter than an average baby.

Weight is the measurement of Gravitational force on an object.

It can be zero as in the space.

It is given in the question that

A baby weighed only 8.7 ounces at birth

weight of an average baby is 7lb 8 ounces

1 lb = 16 ounce

an average baby weight = 7 * 16 +8 = 120 ounces

The baby weight is just 8.7 ounces

so the baby is 120-8.7 = 111.3 ounces lighter than an average baby.

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The probability that a random passenger survived is 0.38

The probability that this passenger was in first class and survived is 0.153

The probability that the passenger in the first class survived is 0.620

The probability that the passenger that survived was in first class is 0.402

The probability that the passenger that survived was in third class is 0.362

The probability that a random passenger survived is 500 / 1317 = 0.38

The probability that this passenger was in first class and survived is 201 / 1317 = 0.153

The probability that the passenger in the first class survived is:  201 /324 = 0.620

The probability that the passenger that survived was in first class: 201/500 = 0.402

The probability that the passenger that survived was in third class is: 181 / 500 = 0.362

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Answer:

Look down my answer↓:

Step-by-step explanation:

Excluyendo el componente de ganancia del coste para el consumidor según (1), la impresora tuvo un coste de $ 211.111,11 para el vendedor.

En el enunciado tenemos el precio de una impresora para el consumidor, el cual comprende el dinero invertido por vendedor más la ganancia esperada. Este indicador observa la siguiente fórmula:

C' = C · (1 + r/100)     (1)

Donde:

Si sabemos que C' = $ 285.000 y r = 35 %, entonces el coste asumido por el vendedor es:

285.000 = 1,35 · C'

C' ≈ 211.111,11

Excluyendo el componente de ganancia del coste para el consumidor según (1), la impresora tuvo un coste de $ 211.111,11 para el vendedor.

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Step-by-step explanation:

both ends are going to the same direction so the degree is even. the right side is going up so the leading coefficient is positive.

The coordinates of the turning point of the graph of the quadratic equation is given by: (-6.25, -75.13).

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The vertex is given by:

[tex](x_v, y_v)[/tex]

In which:

In this problem, the function is given by:

y = 2x² + 25x + 3.

Hence the coefficients are a = 2, b = 25, c = 3, then the coordinates of the vertex are given as follows:

The coordinates of the turning point of the graph of the quadratic equation is given by: (-6.25, -75.13).

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Answer:

6.25, -75.13

Step-by-step explanation:

it just is

Answer:

115.38 is what I got when I tryed to work it out

Answer:

I can't answer this if you don't have the answer choices

I'm sorry

Answer:  A B C

Step-by-step explanation:

A whole number is like 1,500 and a nonwhole number is like 33.2 or like 55/100.  

And have a good day.

Answer:

meight you gotta do better then that

Step-by-step explanation:

a picture is probably necessary

Answer:

Step-by-step explanation:

(h+k)(1)=h(1)+k(1)=2+(-1)=2-1=1

(k-h)(4)=k(4)-h(4)=0-(-1)=1

(k/h)(3)[tex]=\frac{k(3)}{h(3)} =\frac{-1}{0} =- \infty[/tex]

(h.k)(0)=h(0).k(0)=3(-2)=-6

(k.h)(0)=k(0).h(0)=-2(3)=-6

(h.k)(3)=h(3).k(3)=0(-1)=0

h(k(-2))=h(-3)=0

X = 6

Y = (-6)

The z-score for 81 is 1.75

The given parameters are:

μ = 60 , X=81, and σ = 12

The z scores is calculated using:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

Substitute the given values

[tex]z = \frac{81 - 60}{12}[/tex]

Evaluate the difference

[tex]z = \frac{21}{12}[/tex]

Simplify

z = 1.75

Hence, the z-score for 81 is 1.75

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Answer: it could be

[tex](10^{4} ) ^{4}[/tex]

Step-by-step explanation:

Answer:

8 un^2

Step-by-step explanation:

to find this answer you must find the area of the rectangle and then the triangle

the rectangles area is

2 * 3 = 6 un^2

the traingle is

2 * 2 * 1/2 = 2 un^2

now you add them

6 + 2 = 8 un^2

Answer:

Relation 3 is not a function, as s has two outputs: tree and desk. Relation 4 is not a function for the same reason. -1 has three outputs: -2, -4, and -7.

There are 25773 foxes in the region in the year 2008

The given parameters are:

Let the number of years after 2000 be x.

So, the function is

f(x) = a * (1 + r)^x

This gives

f(x) = 15000 * (1 + 0.07)^x

In 2008, we have:

x = 8

So, the equation becomes

f(8) = 15000 * (1 + 0.07)^8

Evaluate

f(8) = 25773

Hence, there are 25773 foxes in the region in the year 2008

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By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an explicit expression (y = f(x)) if possible.

[tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex]

[tex](\ln y)^{2}\,dy = -y \cdot \sqrt{x}\, dx[/tex]

[tex]-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx[/tex]

[tex]-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx[/tex]

If u = ㏑ y and du = dy/y, then:

[tex]-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx[/tex]

[tex]-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C[/tex]

[tex]u^{3} = -2\cdot x^{\frac{3}{2} } + C[/tex]

[tex](\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C[/tex]

[tex]C = (\ln e)^{3}[/tex]

[tex]C = 1[/tex]

And finally we get the explicit expression:

[tex]\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}[/tex]

[tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex]

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation [tex]\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0[/tex] with y(0) = e is [tex]y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}[/tex].

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