The statement "Grouped data is a data that has not been organized into intervals" is false.
Data presented in class intervals, such as 0-20, 20-40, and so on, is referred to as "grouped data."
Ungrouped data is information presented as individual values or integers, such as 15, 63, 34, 20, 25, and so on.
Assume we have a set of data with values between 0 and 50, such as 2, 17, 0, 1, 8, 19, 43, 2, 1, 32, and so on. In this situation, we may divide the data into categories like 0-10, 10-20,...,40-50. The data in this case are simply grouped.
Hence, the statement "Grouped data is a data that has not been organized into intervals" is false.
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PLS HELP PLS In the diagram below, ΔABC ≅ ΔDEF. Complete the statement ∠A ≅
Answer:
∠A ≅ ∠D
Step-by-step explanation:
When writing a triangle congruency like ΔABC ≅ ΔDEF, the angles are congurent based on the orders listed. For example the first angle A is congruent with the first angle of the other triangle D.
∠A ≅ ∠D
∠B ≅ ∠E
∠C ≅ ∠F
graph f(x)= x if x < 2, 2 if x ≥ 2
The graph is shown below:
What is graph?A graph is a mathematical diagram which shows the relationship between two or more sets of numbers or measurements.
Given function: f(x) = x
We have to draw the graph for the function ,f(x) =x with two cases.
For x<2 and for x ≥ 2
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The surface area of a square pyramid is 189 square inches. The side length of the base is 7. What is the value of the height?
The value of the height of the prism is 8.68 inches
Surface of a square pyramidThe surface area is the sum of the area of the faces.
The formula for calculating the surface area of the pyramid is;
TSA = [tex]a^2+2a\sqrt{\frac{a^2}{4} + h^2}[/tex]
where
a is the side length. = 7in
h is the height
Substitute
[tex]189=7^2+2(7)\sqrt{\frac{7^2}{2} + h^2} \\189=49+14\sqrt{\frac{49}{2} + h^2}\\140=14\sqrt{\frac{49}{2} + h^2}\\10=\sqrt{\frac{49}{2} + h^2}\\[/tex]
Square both sides to have
100 = 49/2 + h²
h² = 100 - 49/2
h² = 151/2
h² = 75.5
h = 8.68in
Hence the value of the height of the prism is 8.68 inches
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Gavin likes biking. He never misses a chance to go for a ride when the weather is nice. This week his goal is to bike about 65 total miles over four days. Each day, he wants to ride 1.5 times as far as he rode the day before. What does the result in part d mean?
Answer:
Total Miles he drives first day = 8 miles
Total Miles he drive second day = 12miles
Total Miles he drives third day = 18miles
Total Miles he drives fourth day = 27 miles
Step-by-step explanation:
This is a problem of linear equations in 1 variable:
The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
It is given in the question that ,
This week his goal is to drive bike about 65 total miles over four days. Each day, he wants to ride 1.5 times as far as he rode the day before.
Let, on the first day, he drives x miles. On second day, he drives 1.5x. On the third day, he drives 1.5(1.5x) and on the fourth day, he drives 1.5(1.5(1.5x)).
So the equation is :
x +1.5x + 1.5(1.5x) + 1.5(1.5(1.5x)) = 65miles
x + 1.5x + 2.25x + 3.375x = 65miles
8.125x = 65 miles
x = 65/8.125 miles
x = 8 miles
so after solving the equation we get, on the first day Gavin drives 8 miles
similarly, on the second day he drives 12miles
on third day 18 miles
and on the fourth day 27miles
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Line AB and line BC form a right angle at point B with points A (2,5) and B(8,3). what is the equation of line BC?
Answer:
y=3x-21
Step-by-step explanation:
General outlineFind equation for line ABFind equation for perpendicular line BCStep 1. Find equation for line ABGiven points A(2,5) and B(8,3), line AB must contain them.
To calculate the slope, [tex]m_{\text{AB}}[/tex], of line AB, use the slope formula:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m_{\text{AB}}=\dfrac{(3)-(5)}{(8)-(2)}[/tex]
[tex]m_{\text{AB}}=\dfrac{-2}{6}[/tex]
[tex]m_{\text{AB}}=-\frac{1}{3}[/tex]
Since the slope isn't undefined, line AB must cross the y-axis somewhere. To find the y-intercept, build and equation in slope-intercept form:
[tex]y=m_{\text{AB}}x+b_{\text{AB}}[/tex]
[tex]y=\left(-\frac{1}{3} \right) x+b_{\text{AB}}[/tex]
Substituting values for a known point (point A) on line AB...
[tex](5)=\left(-\frac{1}{3} \right) (2)+b_{\text{AB}}[/tex]
[tex]5=-\frac{2}{3} +b_{\text{AB}}[/tex]
[tex](5)+\frac{2}{3} =(-\frac{2}{3} +b_{\text{AB}})+\frac{2}{3}[/tex]
Finding a common denominator...
[tex]\frac{3}{3}*5+\frac{2}{3} =b_{\text{AB}}[/tex]
[tex]\frac{15}{3}+\frac{2}{3} =b_{\text{AB}}[/tex]
[tex]\frac{17}{3}=b_{\text{AB}}[/tex]
So, the equation for line AB is [tex]y=-\frac{1}{3} x +\frac{17}{3}[/tex]
Step 2. Find equation for line BCSince line AB and line BC form a right angle, they are perpendicular. Perpendicular lines have slopes that are opposite (opposite sign) reciprocals (fraction flipped upside-down) of each other. Stated another way, the slopes multiply to make negative 1.
[tex]m_{\text{AB}}*m_{\text{BC}}=-1[/tex]
[tex]\left( -\frac{1}{3} \right) *m_{\text{BC}}=-1[/tex]
[tex]-3*\left( -\frac{1}{3} *m_{\text{BC}} \right) =-3*(-1)[/tex]
[tex]m_{\text{BC}} =3[/tex]
Since the slope isn't undefined, line BC must also cross the y-axis somewhere. To find the y-intercept, build and equation in slope-intercept form:
[tex]y=m_{\text{BC}}x+b_{\text{BC}}[/tex]
[tex]y=(3) x+b_{\text{BC}}[/tex]
Substituting values for a known point (point B) on line BC...
[tex](3)=3 * (8)+b_{\text{BC}}[/tex]
[tex]3=24+b_{\text{BC}}[/tex]
[tex](3)-24=(24+b_{\text{BC}})-24[/tex]
[tex]-21=b_{\text{BC}}[/tex]
So, the equation for line BC is [tex]y=3 x -21[/tex]
For the graph y=41 find the slope
Answer:
m=0 , b=41
Step-by-step explanation:
y=41y=0x+41, y=mx +by=0x+41, m=0, b=41therefore m=0, b=41There are two boxes of cereal in the shape of rectangular prisms on a shelf. The
dimensions of each box of cereal are listed below.
. Box B has a height of 25 centimeters, a length of 19 centimeters,
and a width of 6 centimeters.
• Box A has a height of 25 centimeters, a length of 20 centimeters,
and a width of 9 centimeters.
What is the difference in volume, in cubic centimeters, between the two boxes of cereal?
A 1,650
B 3,900
C 4,500
D 7,350
Answer:
1650 Cubic Centimeters
Step-by-step explanation:
To get the volume of the cereal boxes, you must multiply their 3 dimensions together.
Box A:
25×20=500
500×9=4500
Box B:
25×19=475
475×6=2850
Now, to find the difference of these volumes, you want to subtract the smaller volume from the larger volume.
4500-2850=1650
The answer is 1650 cubic centimeters.
Which expression is equivalent to (1−sinβ)(1+sinβ)/cos2β for all values of β for which (1−sinβ)(1+sinβ)/cos2β is defined?
Select the correct answer below:
tan2β
tanβ+secβ
tanβ
sec2β
1
Using a trigonometric identity, it is found that the equivalent expression is given by 1.
What are the trigonometric identities used to solve this question?Relating sine and cosine, we have that:
[tex]\sin^{2}{\beta} + \cos^{2}{\beta} = 1[/tex]
Then:
[tex]\cos^{2}{\beta} = 1 - \sin^{2}{\beta}[/tex]
For the tangent, we have that:
[tex]\tan{\beta} = \frac{\sin{\beta}}{\cos{\beta}}[/tex].
For the secant, we have that:
[tex]\sec{\beta} = \frac{1}{\cos{\beta}}[/tex].
In this problem, the expression is:
[tex]\frac{(1 - \sin{\beta})(1 + \sin{\beta})}{\cos^{2}{\beta}} = \frac{1 - \sin^2{\beta}}{\cos^2{\beta}} = \frac{\cos^2{\beta}}{\cos^2{\beta}} = 1[/tex]
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translate algebra 2 to standard form
Adding 2x to both sides, we get [tex]\boxed{2x+y=5}[/tex]
Terry wants to pour cement around the edge of the circular patio in her backyard.The patio has a radius of 5 feet.What is the distance,in feet,around the edge of the patio?Use 3.14 for Pi.PLEASE EXPLAIN
E.15.7
F.31.4
G.49.3
H.78.5
Answer:
F. 31.4 ft
Step-by-step explanation:
The distance around the edge of a circle is called the circumference.
Formula for the circumference of a circle
[tex]\sf Circumference\:of\:a\:circle=2 \pi r[/tex]
(where r is the radius)
Given values:
radius = 5 ftπ = 3.14Substitute the given values into the formula:
[tex]\begin{aligned}\implies \sf circumference & = \sf 2 \cdot 3.14 \cdot 5\\ & = \sf 31.4\:ft \end{aligned}[/tex]
Therefore, the distance around the edge of the circular patio is 31.4 ft.
The distance around the edge of the patio is 31.4 feet, which is determined by the circumference of a circle. The correct answer is option (F).
To find the distance around the edge of the circular patio, we need to calculate the circumference of the circle.
The formula for the circumference of a circle is given by:
Circumference = 2 × π × radius
Given that the radius of the patio is 5 feet and using the approximate value of π as 3.14, we can now calculate the circumference:
Circumference = 2 × 3.14 × 5
Circumference = 31.4 feet
Therefore, the distance around the edge of the patio is 31.4 feet.
Hence, the correct answer is option (F).
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-11-(-5)
————-
2x3
is an example of
A. a numerical equation
B. a numerical expression
C. an algebraic expression
D. an algebraic equation
Answer:
B.a numerical expression
need some help asap, giving brainliest
Answer:
16.19
Step-by-step explanation:
Use the cosine rule:
[tex]\sqrt{a^{2} +b^{2} -2abcosy} \\\\\sqrt{16^{2} +20^{2} -(2)(16)(20)cos(52)} \\\\\\= 16.19cm[/tex]
The law of cosines is a² + b² - 2abcosC = c². Find the value of 2abcosC.
A. 20
B. 40
C. 37
D. -40
Answer:
C
Step-by-step explanation:
a = 4
b = 5
c = 2
C = arccos((a² + b² - c²) / 2ab)
C = arccos((16 + 25 - 4) / 2(4)(5))
C = arccos(37 / 40)
C = 22.33°
2abcosC
2(4)(5)cos(22.33)
40(0.925)
37
Option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.
What is Trigonometry?Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
We have from law of cosines that a² + b² - 2abcosC = c²
We have to find the value of 2abcosC.
Now let us find the value of C
C = arccos((a² + b² - c²) / 2ab)
C = arccos((16 + 25 - 4) / 2(4)(5))
C = arccos(37 / 40)
C = 22.33°
Now plug in the value of C in 2abcosC.
2abcosC
=2(4)(5)cos(22.33)
=40(0.925)
=37
Hence, option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.
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On a coordinate plane, an image has points (negative 2, 2), (0, 2), (2, 0), (0, negative 2), (negative 2, negative 2).
Use the image shown and a scale factor of 1/2 to find the pre-image. Which is the pre-image of A’?
If the scale factor is 1/2. Then the coordinate of the pre-image will be (-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).
What is a transformation of geometry?A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.
Dilation does not change the shape, but changes the size of the geometry.
On a coordinate plane, an image has points (-2, 2), (0, 2), (2, 0), (0, -2), and (-2, -2).
The scale factor is 1/2. Then the coordinate of the pre-image will be
(-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).
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Answer:D (-4) (-4)
Step-by-step explanation:
(1 point)Let S be the part of the plane 2x+2y+z= 1 which lies in the first octant, oriented upward. Find the flux of the vector field
F = 2i+2j + 2k across the surface S.
The flux is 9.
What is Flux?Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface.
Given:
2x+2y+z= 1
F = 2i+2j + 2k
Now,
r = xi + yj + z( 1-2x-2y) K
dr/dx= i - 2k
dr/dy = j-2k
dr/dx* dr/dy
= ( i - 2k) * (j-2k)
= 2i + 2j + k
F(x)= 2i+2j + 2k
F(x). da = 4 +4 +2 = 10 dxdy
Hence, flux
= [tex]\int\limits^1_0 {\int\limits^{1-2y}_0 {10 } \, dx dy } \,[/tex]
= [tex]\int\limits^1_0[/tex] 10(1-2y) dx
= [tex]\int\limits^1_0[/tex] 10-2y
= 10(1) - (1)²
=9
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The plane has intercepts (1/2, 0, 0), (0, 1/2, 0), and (0, 0, 1). Parameterize [tex]S[/tex] by the vector function
[tex]\vec s(u,v) = \dfrac{(1-u)(1-v)}2 \, \vec\imath + \dfrac{u(1-v)}2 \, \vec\jmath + v \,\vec k[/tex]
with [tex]0\le u\le1[/tex] and [tex]0\le v\le1[/tex]. (More explicitly, we have the parameterization
[tex]\vec s(u,v) = (1-v)((1-u) p_1 + u p_2) + v p_3[/tex]
where [tex]p_i[/tex] denote the given points.)
The normal vector to [tex]S[/tex] is
[tex]\vec n = \dfrac{\partial\vec s}{\partial u} \times \dfrac{\partial\vec s}{\partial v} = \dfrac{1-v}2\,\vec\imath + \dfrac{1-v}2\,\vec\jmath + \dfrac{1-v}4\,\vec k[/tex]
Then the flux of [tex]\vec F = 2\,\vec\imath+2\,\vec\jmath+2\,\vec k[/tex] across [tex]S[/tex] is given by the surface integral,
[tex]\displaystyle \iint_S \vec F \cdot d\vec\sigma = \iint_S \vec F \cdot \vec n \, dA[/tex]
[tex]\displaystyle = \int_0^1 \int_0^1 \left(2\,\vec\imath+2\,\vec\jmath+2\,\vec k) \cdot \left(\frac{1-v}2\,\vec\imath + \frac{1-v}2\,\vec\jmath + \frac{1-v}4\,\vec k\right) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 \int_0^1 (1-v) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 (1-v) \, dv = \boxed{\frac54}[/tex]
Which of the following is the given function's
average rate of change on the interval
Sx≤1?
Answer: 2
Step-by-step explanation:
[tex]g(-2)=-2\\\\g(1)=4\\\\\frac{g(-2)-g(1)}{-2-1}=\frac{-2-4}{-3}=\boxed{2}[/tex]
In the figure below, lines I and mare parallel. What is the value of x?
1
(4x13)
X=
m
(2x + 37)
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: x = 25°[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: 4x - 13 = 2x + 37[/tex]
[ Alternate Exterior Angle ]
[tex]\qquad \tt \rightarrow \: 4x - 2x = 37 + 13[/tex]
[tex]\qquad \tt \rightarrow \: 2x = 50[/tex]
[tex]\qquad \tt \rightarrow \: x = \cfrac{50}{2} [/tex]
[tex]\qquad \tt \rightarrow \: x = 25 \degree[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Given a regular 26 sided polygon, complete the following statements.
Answers:
Sum of the interior angles = 4320One interior angle = 166.15=======================================================
Work Shown:
n = number of sides = 26
S = sum of the interior angles of a polygon with n sides
S = 180(n-2)
S = 180(26-2)
S = 180(24)
S = 4320 degrees is the sum of the interior angles.
i = measure of one interior angle of a regular polygon
i = S/n
i = 4320/26
i = 166.1538 approximately
i = 166.15 degrees is the approximate measure of each interior angle.
Side note: The formula to determine the interior angle i only works for regular polygons. This is because each angle is the same measure.
Find the value of: (4/5)^1 A. 4/5 B. 1 C. 0 D. 16/25
Answer:
A. 4/5
Step-by-step explanation:
Answer:
4/5 (option a)
Step-by-step explanation:
by following the exponent rule of [tex]a^1 = a[/tex], we know that
[tex](\frac{4}{5} )^1[/tex] = [tex]\frac{4}{5}[/tex]
So, the value of
[tex]\frac{4}{5}^{1}[/tex] is 4/5
Find the volume of the sphere of 5m
Use the Pythagorean Theorem to find the length of the leg in the triangle shown below.
The figure shows a right triangle with one leg marked 12. The hypotenuse is marked 15.
Answer:
9
Step-by-step explanation:
The Pythagorean Theorem is a² + b² = c². c² is the hypotenuse while a² and b² are the legs.
So plugging it into the equation,
a² + 12² = 15²
a² + 144 = 225
a² = 81
a = 9
steps:
1. square the values
2. isolate the missing value
3. take the square root of both sides
You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you survey? Assume that you want to be 90% confident that the sample percentage is within 1.5 percentage points of the true population percentage. Complete parts (a) and (b) below. Assume that nothing is known about the percentage of passengers who prefer aisle seats.
Using the z-distribution, it is found that 3,007 passengers must be surveyed.
What is a confidence interval of proportions?A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.
In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]
[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]
[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]
[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]
n = 3007.
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What are your top 3 theorems in higher mathematics? Why do you like them the most?
My theorems include the Pythagoras theorem, midpoint theorem, and angle bisector theorem.
How to illustrate the theorem?The Pythagoras theorem is used to find the length in a right angle.
The midpoint theorem states that the line segment in a triangle is parallel to the third side and is half the length.
The angle bisector theorem is concerned with the lengths of the two segments that the triangle side is divided into by a line which bisects the opposite angle.
I like them because they're important when solving triangle related problems.
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Use the graph to write the inequality that represents the shaded region
Answer:
4/2 is the wrong answer
Step-by-step explanation:
because it is
hi i really need help with this it is due tonight
Answer:
[tex]1)\text{ Friday}\\2)\text{ }7:00\\3a)\text{ }0\\3b)\text{ }4\\3c)\text{ }0\\4a)\text{ }6\\4b)\text{ }4\\4c)\text{ }2[/tex]
The cost of renting a car is $46/week plus $0.25/mile traveled during that week. An equation to represent the cost would be y=46+0.25x, where x is the number of miles traveled.
a. What is your cost if you travel 57 miles?
The cost is $ ____________.
b. If your cost was $65.00, how many miles were you charged for traveling?
You were charged for traveling ____________ miles.
c. Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?
The maximum number of miles you could travel is ____________ miles.
Answer:
A. $60.25
B. 76 miles
C. 216 miles
Step-by-step explanation:
x is miles
y is total amount spent
For A, 57 miles is the x value. Plug that in to x.
y= 46 + .25(57)
y= 60.25
For B, the total is the y. So plug 65 in for y.
65 = 46 + .25x Subtract 46 from both sides
19 = .25x Divide by .25
76 = x
For C, the maximum you can spend is $100. Plug that in for y.
100 = 46 + .25x Subtract 46 from both sides
54 = .25x Divide by .25
216 = x
The answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The equation to represent the cost would be y=46+0.25x
x is the number of miles.
a) What is your cost if you travel 57 miles?
Plug x = 57 in the above equation:
y = 46 + 0.25(57)
y = $60.25
b) If your cost was $65.00, how many miles were you charged for traveling?
Plug y = 65 in the equation:
65 = 46 + 0.25x
x = 76 miles
c) Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?
Plug y = 100 in the equation:
100 = 46 + 0.25x
x = 216 miles
Thus, the answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.
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Help me pleaseeeeeeeeeeeeeeeeeeeeee
Answer:
A
Step-by-step explanation:
[tex]s=\frac{a+b+c}{2}[/tex]
multiply both sides by 2
[tex]2s = a + b +c[/tex]
substract b and c from both sides to get a by itself
[tex]a = 2s - (b + c)\\a = 2s - b - c[/tex]
so the answer is A.
pls solve this question
Answer:
[tex] {( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } } [/tex]
Or ;
[tex] {( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} } [/tex]
If you subtract 0. 3 from a certain number, add 0. 4 times the original number to the result, and then add another 2. 78, you'll get 25. What was the original number?
After all the conditions you applied from the statement given you will get the original number as 16.08.
What is the algebraic equation?An algebraic equation is when two expressions are set equal to each other, and at least one variable is included.
Given that, if you subtract 0.3 from a certain number, add 0.4 times the original number to the result and then add another 2.78, you'll get 25.
We need to find the original number.
Let us take the original number as x.
Now, subtract 0.3 from the original number.
That is x-0.3.
0.4 times the original number is 0.4x.
Add 0.4 times the original number to the result.
That is, x-0.3+0.4x=1.4x-0.3
Now, add 2.78 to the result. That is 1.4x-0.3+2.78=1.4x+2.48.
As a result, you'll get 25. That is 1.4x+2.48=25
⇒1.4x=22.52
⇒x=16.08
There, the original number is 16.08.
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simplify (8x^2y^3)/(2x^4y)
Answer:
[tex]=\frac{4y^2}{x^2}[/tex]
Step-by-step explanation:
[tex]\frac{(8x^2y^3)}{(2x^4y)}[/tex]
[tex]=\frac{(8x^2y^3)}{(2x^4y)}\\[/tex]
[tex]=\frac{8y^2}{2x^2}[/tex]
[tex]=\frac{4y^2}{x^2}[/tex]
I Hope This helps :)