Chromium (III) oxide reacts with hydrogen sulfide gas to form chromium (III) sulfide and water. To produce 421 g of cr2s3, how many moles of cr2o3 and grams of cr2o3 are required?

Answer:

A and B

Explanation:

A is crust

B is mantle

Lead will have the highest temperature .

What is Specific Heat ?

Specific Heat is defined as the amount of heat required to raise the temperature of a 1 gm of substance by 1 degree Celsius.

If heat is added to 25.0g of copper, calcium, aluminum, iron, lead

The missing given specific heat is

Copper, 0.377

Calcium, 0.656

Aluminum, 0.895

Iron, 0.448

Lead, 0.129

Higher specific heat means more temperature required to bring the same amount of change in temperature

Here the temperature change is fixed , The metal with the lowest Specific heat will have the highest temperature.

From the data it can be seen that

Specific Heat of Lead, 0.129

Therefore Lead will have the highest temperature.

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Atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

Atomic radius decreases across a period because of nuclear charge increases whereas atomic radius of atoms generally increases from top to bottom within a group because there is again an increase in the positive nuclear charge.

Ionization energy increases when we move from left to right across an period and decreases from top to bottom.

Electronegativity also increases from left to right across a period and decreases from top to bottom.

So we can conclude that atomic size decreases in a period but the ionization energy and electronegativity increases across a period.

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Considering the reaction's stoichiometry and the notion of molarity, 1.167 grams of solid barium sulfate form when 32.0 mL of 0.160 M barium chloride reacts with 70.0 mL of 0.065 M sodium sulfate.

The balanced reaction is:

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2 NaCl(aq)

The reactant that is consumed first in a chemical reaction is the limiting reagent because it stops any more reactions from taking place. The limiting reagent controls how much product is produced during the reaction.

Utilizing the reaction stoichiometry and the estimated number of moles, it is possible to identify the limiting reagent.

According to reaction stoichiometry, which describes the proportions of reagents and products in a chemical reaction, the following numbers of moles of each component are involved in the reaction:

Molarity, on the other hand, refers to how many moles of solute are dissolved in a certain volume.

Molarity is determined by the expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units[tex]\frac{moles}{L}[/tex].

In this case, 32.0 mL= 0.032L (being 1000 mL= 1 L) of barium chloride reacts. So, by definition of molarity, the number of moles that participate in the reaction is calculated as:

[tex]0.160 M=\frac{No. of moles of solute}{0.032L}[/tex]

No of moles of barium chloride(solute) = 0.160M × 0.032L

No of moles of barium chloride(solute) = 0.00512moles

On the other side,70.0mL= 0.070 L of 0.065 M sodium sulfate reacts. So, by definition of molarity, the number of moles that participate in the reaction is calculated as:

[tex]0.065 M =\frac{No of moles of solute}{0.070L}[/tex]

No of moles of Sodium sulfate= 0.065M × 0.070L

No of moles of Sodium sulfate = 0.0045moles

if by stoichiometry 1 mole of barium chloride reacts with 1 mole of sodium sulfate, 0.00512moles of barium sulfate reacts with how many moles of sodium sulfate?

No. of moles of sodium sulfate=

[tex]\frac{ 0.00512moles of barium sulfate * 1 mole of sodium sulfate}{1 mole of barium chloride}[/tex]

amount of moles of sodium sulfate= 0.00512 moles

But 0.00512moles of sodium sulfate are not available, 0.0045moles  moles are available. Since you have fewer moles than you need to react with  0.00512moles of barium chloride, sodium sulfate will be the limiting reagent.

Then, it is possible to determine the number of moles of barium sulfate produced by another rule of three: if by stoichiometry 1 mole of sodium sulfate produces 1 mole of barium sulfate, 0.00512 moles of sodium sulfate produces how many moles of barium sulfate?

[tex]Amt of mole of barium sulfate=\frac{0.00512 moles of sodium sulfate* 1mole of barium sulfate}{1 mole of sodium sulfate}[/tex]

amount of moles of barium sulfate=  0

Being the mass molar of barium sulfate is 233.34 g/mole, the mass-produced of the compound is calculated as:

                              = [tex]\frac{0.00512 moles * 233.34 gm}{1 mole}[/tex]

                              =1.167 gm

Hence, 1.167 gm of solid barium sulfate is formed.

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Answer:

0.217 ×2. =9.86×10moles

44

Answer:

15 seconds x (1 hour/3600 seconds)

Explanation:

By the factor label method. There are 60 seconds in a minute and 60 minutes in an hour.

15 seconds x (1 minute/60 seconds) x (1 hour/60 minutes) = your answer

Soon enough you'll realize that 60x60=3600 and so there are 3600 seconds in 1 hour. Then you will only need 1 conversion ratio;

15 seconds x (1 hour/3600 seconds) = your answer

Answer:

15 / 3600

Explanation:

15 / 3600

180.189 g was the mass of the zinc sample with a specific heat of zinc is 0.390 j/g°C.

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Using specific heat capacity formula here:

[tex]C_{Zn}[/tex] × [tex]m_{Zn}[/tex]×  Δ[tex]T_{Zn}[/tex] = [tex]C_{H_2O}[/tex]× [tex]m_{H_2O}[/tex] ×  Δ[tex]T_{H_2O}[/tex]

0.390J/g°C × [tex]m_{Zn}[/tex] ×77.4ºC = 4.184J/g°C×  65.0g ×  20.00ºC.

[tex]m_{Zn}[/tex] = 180.189 g

Hence, 180.189 g was the mass of the zinc sample.

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Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

c option is correct answer

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The mass in grams of each of the following using dimensional analysis is:

The mass of a substance can be calculated in different ways depending on whether molecules or moles are given.

First, we need to convert atoms/formula units/molecules to moles as follows:

Next, we convert each mole value to mass as follows:

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Answer:

Explanation:

A

Answer: 50.806 cm is the correct answer.

Explanation: First divide 6104.5 cm^2 by 22.3 cm.

[tex]\frac{6104.5cm^2}{22.3cm} = 273.74 cm[/tex]

*Note: When dividing units, subtract the exponents, and when multiplying units simply add the exponents.

Then continue by subtracting 324.55 cm - 273.74 cm.

This should give you an answer of 50.806 cm.

0.761 mol of [tex]C_7H_{16}[/tex]  would you have if you have 76.36 grams.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

Given data:

Mass=76.36 grams

[tex]Moles = \frac{mass}{molar \;mass}[/tex]

[tex]Moles = \frac{76.36 grams}{100.21 g/mol}[/tex]

Moles = 0.761

Hence,  0.761 mol of  [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.

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Running blades is the controversial prosthetics which may confer an athletic advantage over able-bodied runners.

This is also referred to as running prosthetics which allows someone move faster with less effort.

This happens when top speed has been achieved and offers an advantage over able-bodied runners.

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Answer:

Ammonia is easily made in the laboratory by heating an ammonium salt, such as ammonium chloride NH4Cl with a strong alkali, such as sodium hydroxide or calcium hydroxide.

The gas may also be made by warming concentrated ammonium hydroxide.

Explanation:

2NH4Cl + Ca(OH)2 → CaCl2 + 2H2O + 2NH3(g)

Answer:

4560 torr

Explanation:

PV = K

4 x 1.5 = k

k = 6

V = k / p

V = 6 / 1

V = 6

atm to torr = 1 to 760

760 x 6 = 4560

The heat that creates this temperature change coming from change in the internal energy of the system as per as first law of thermodynamics.

A law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature.

As we know, Boyle's law only works when the gas is kept at a constant temperature

Here,

When volume of gases decreased, it means work done has occurred on the system, so the work done is used for raising internal energy of the gas and the other is released as the thermal energy.

So,

According to 1st law of thermodynamics,

we know  Q =  ΔU + W  i.e, change in internal energy and work done. So this is a reason. Changing temperature occurs.

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1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 7O2 = 4CO2 + 6H20      A  

3. C3H8 + 502 = 3CO2 + 4H20            C

To find the appropriate end products, use the following rules

Thus for equation;

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 2O2 = 4CO2 + 6H20      A  

3. C2H8 + 502 = 2CO2 + 4H20            C  

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Answer:

A real gas will act as an ideal gas under high temperature and at a low pressure.

Real gases are non-ideal gases whose molecules occupy space and have interactions, consequently, they do not adhere to the ideal gas law.

An ideal gas has molecules that occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Explanation:

Answer: A. Wearing loose comfortable clothing so you can concentrate on the lab.

Explanation:

Wearing loose clothing can make it cling onto certain things, which could create a spill or a different hazard. B, C, and D are all things you SHOULD be doing to achieve safe lab behavior.

I hope this helps! Pls give brainliest!! :)

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid [tex]CH_3CO_2H[/tex]  reacts with baking soda [tex]NaHCO_3[/tex] according to the equation:

[tex]CH_3CO_2H + NaHCO_3[/tex] → [tex]CH_3CO_2Na + CO_2 + H_2O[/tex]

1. Molar mass of [tex]NaHCO_3[/tex] is 23+1+12+16×3 = 84 g/mol

= [tex]\frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]

= [tex]\frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]

=0.29 mol [tex]NaHCO_3[/tex]

2. From the balanced equation we see that 1 mole of [tex]NaHCO_3[/tex] reacts with 1 mole of [tex]CH_3CO_2H[/tex] , then 0.29 moles of [tex]NaHCO_3[/tex] react with 0.29 moles of [tex]CH_3CO_2H[/tex].

3. Mass of 1 mole of [tex]CH_3CO_2H[/tex] is 12+ 1×3+12+16×2=60 g/mol

= [tex]\frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}[/tex]

[tex]=17.4 g CH_3CO_2H[/tex]

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g [tex]CH_3CO_2H[/tex] is very close to 17.4 g [tex]CH_3CO_2H[/tex]. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

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Answer:

A nonmetal is a chemical element that generally lacks a predominance of metallic properties. Non-metals are mostly found in groups 5, 6 and 7. These non-metals will have 5, 6 or 7 electrons in the outer shell.

The outer shell of a non-metal is, therefore, more than half full of electrons.

Answer:

1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left

Explanation:

Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.

Adding a catalyst has no effect on equilibrium reactions.

When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.

Answer:

'Gay-Lussac's law is a gas law that states the pressure of a gas varies directly with temperature when mass and volume are kept constant. As the temperature increases, the pressure will also increase.'

Answer:

Gay Lussac’s law says that the pressure created by a gas is proportional to the temperature of the gas when the mass is constant or the same
so, when pressure increases so does the temperature and when pressure decreases so does the temperature

Answer:

OOO

Explanation:

OOOOOO

The error caused will lower the number of moles when he did not do the second heating.This question is related to the empirical formula.

A formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.

The empirical formula is the simplest ratio of atoms in a given compound.

we know that heating is used to eliminate most of the water molecules which are attached to the compound in the question, it's given that the second heating was not performed by the students.

This means that there are still some water molecules attached to the compound. This will imply that higher mass will be calculated for the compound because the water molecules are also considered.

So now, if we look at the calculation for the number of moles of water in this, we can say that this will be lower than the actual amount.

This is because there are some unaccounted moles of water which are still attached to the compound and these will be accounted in the compound mass rather than the waters. Therefore, the number of moles will be lower.

Hence, The error caused will lower the number of moles when he did not do the second heating.

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Answer:

0.8797 J/g oC

Explanation:

use mcAT=mcaT

The combustion of lauric acid is shown as CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

In a combustion reaction, a substance is burnt in oxygen. If the substance is an organic compound a the case is here, the products are carbon dioxide and hydrogen.

No the equation of the combustion of lauric acid is shown as;

CH3(CH2)10COOH(s) + 18O2(g) -----> 12H20(l) + 12CO2(g)

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