The equation of the linear relationship between x and y is: y = 4x - 1.
How to Write the Equation that Describes the Relationship between x and y?If we are given a table of values that shows the relation of x to y, to find the equation, find the value of the slope (m) and the value of the y-intercept (b), then plug their values into the equation, y = mx + b.
Given the table:
x 0 1 2 3 4
y -1 3 7 11 15
Using two points from the table, (0, -1) and (1, 3), find the slope (m):
Slope (m) = change in y / change in x = (-1 - 3) / (0 - 1)
Slope (m) = -4/-1
m = 4
The y-intercept (b) = -1 [this is the value of y when x = 0, as seen in the table]
Substitute m = 4 and b = -1 into the equation, y = mx + b:
y = 4x - 1
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NO LINKS!!
f(x)= (x^2 + x - 12)/(x^2 + 6x + 9)
Discuss the behavior of f near any excluded x-values/
a. f(x) --> -∞ as x --> 3^+ and as x--> 4^-, f(x) --> ∞ as x --> 4^+ and as x --> 3^-
b. f(x) --> ∞ as x --> 4^+ and as x --> 4^-
c. f(x) --> -∞ as 4^+ and as x --> 4^-, f(x) --> ∞ as 3^+ and as x --> 3^-
d. f(x) --> -∞ as x --> 3^+ and as x --> 3^-, f(x) --> ∞ as x --> -4^+ and as x --> -4^-
e. f(x) --> -∞ as x --> -3^+ and as x --> -3^-
Answer:
e. f(x) --> -∞ as x --> -3^+ and as x --> -3^-
Step-by-step explanation:
You want to know the behavior of f(x)= (x^2 + x - 12)/(x^2 + 6x + 9) near any excluded x-values.
DomainThe function can be factored as ...
[tex]f(x)=\dfrac{x^2+x-12}{x^2+6x+9}=\dfrac{(x+4)(x-3)}{(x+3)^2}[/tex]
The excluded values are values of x where the denominator is zero. The only excluded value is x = -3. (eliminates all answer choices except E)
Asymptotic behaviorAt either side of x = -3, the sign of the numerator is negative and the sign of the denominator is positive. That makes f(3-) < 0 and f(3+) < 0.
f(x) will never approach +∞, but f(x) approaches -∞ as x nears -3 from either direction.
Answer:
[tex]\textsf{e)} \quad f(x) \rightarrow -\infty\;\;\textsf{as}\;\; x \rightarrow -3^+ \;\;\textsf{and as}\;\;x \rightarrow -3^-[/tex]
Step-by-step explanation:
Given function:
[tex]f(x)=\dfrac{x^2+x-12}{x^2+6x+9}[/tex]
Factor the numerator:
[tex]\implies x^2+x-12[/tex]
[tex]\implies x^2+4x-3x-12[/tex]
[tex]\implies x(x+4)-3(x+4)[/tex]
[tex]\implies (x-3)(x+4)[/tex]
Factor the denominator:
[tex]\implies x^2+6x+9[/tex]
[tex]\implies x^2+3x+3x+9[/tex]
[tex]\implies x(x+3)+3(x+3)[/tex]
[tex]\implies (x+3)(x+3)[/tex]
[tex]\implies (x+3)^2[/tex]
Therefore, the rational function is:
[tex]f(x)=\dfrac{(x-3)(x+4)}{(x+3)^2}[/tex]
As the degree of the numerator is equal to the degree of the denominator, there is a horizontal asymptote at y = 1.
A vertical asymptote occurs at the x-value(s) that make the denominator of a rational function zero.
[tex]\implies (x+3)^2=0[/tex]
[tex]\implies x+3=0[/tex]
[tex]\implies x=-3[/tex]
Therefore, there is a vertical asymptote at x = -3.
As there is a vertical asymptote at x = -3, the excluded x-value is x = -3.
As x approaches x = -3 from both sides, the numerator of the rational function approaches -6 and the denominator approaches a very small positive number. Therefore, the function approaches a very large negative number.
Therefore, the end behaviour of the function as it approaches the excluded value is:
[tex]f(x) \rightarrow -\infty\;\;\textsf{as}\;\; x \rightarrow -3^+ \;\;\textsf{and as}\;\;x \rightarrow -3^-[/tex]a person in a whispering gallery standing at one focus of the ellipse can whisper and be heard by a person standing at the other focus because all the sound waves that reach the ceiling are reflected to the other person. if a whispering gallery has a length of 130 feet, and the foci are located 30 feet from the center, find the height of the ceiling at the center. round your answer to 4 decimal places. submit questionquestion 9
The Height of the ceiling at the center is 57.6628 feet
In geometry, an ellipse is a two-dimensional shape, that is defined along its axes. An ellipse is formed when a cone is intersected by a plane at an angle with respect to its base.
It has two focal points. The sum of the two distances to the focal point, for all the points in curve, is always constant.
The General form of ellipse is [tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex]
According to the question,
Length of whispering gallery is 130 feet
The foci are located 30feet from the center (0,0)
So, 2a = 130
=> a = 130/2
=> a = 65
and c = 30
As we know ,
=> c² = a² - b²
=> (30)² = (65)² - b²
=> 900 = 4225 - b²
=> b² = 4225 - 900
=> b² = 3325
=> b = 57.7 feet
Therefore , the height of the ceiling at the center is 57.6628 feet
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DUE SOON! WILL GET 100 POINTS!
I NEED HELP!! SO CONFUSED AND RUNNING OUT OF TIME!!
The restrictions on the variables x and y are given as follows:
x ∈ W, y ∈ W.
How to obtain the restrictions to the variables x and y?The first step in obtaining the restrictions of the variables x and y are identifying them, which is done as follows:
Variable x: number of lower bowl tickets sold.Variable y: number of upper bowl tickets sold.Then we known that we usually hear it in the news things such as this sentence:
"On the last Buffalo Bills game, 60,000 tickets were sold".
The amount of tickets sold varies, but the type of number doesn't, it is always a positive non-decimal number.
The number of ticket sold cannot assume neither negative nor decimal values, thus the variables x and y belong to the whole number set and the first option is correct.
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DUE SOON!!! NEED HELP ON THESE TWO QUESTIONS PLEASE!
DUE SOON AND I DONT UNDERSTAND IT!
MANY THANKS!
WILL GET 100 POINTS! PLEASE HELP!!
The restrictions for x and y are given as follows:
3. x ∈ W, y ∈ W.
5. x ∈ W, y ∈ W.
What are the restrictions?To obtain the restrictions, the first step is classifying the variables as either discrete or continuous, as follows:
Discrete variables are countable values, that can assume only whole or integer values, that is, they do not assume decimal values.Continuous variables can assume decimal values, hence they are real values.In this problem, the variables are both resumed as follows:
Number of tickets sold in the Super Bowl.
The possible values are given as follows:
0, 1, 2, ...
Which are countable values, hence discrete, and that also cannot assume negative values, hence they belong to the whole set and not the integer set, thus the restrictions are:
x ∈ W, y ∈ W.
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The image of ΔABC after a reflection across Line E G is ΔA'B'C'. 2 triangles are shown. A line of reflection is between the 2 triangles. Line segment B B prime has a midpoint at point E. Line segment A A prime has a midpoint at point F. Line segment C C prime has a midpoint at point G. Which statement is true about point F? F is the midpoint of AA' because Line E G bisects AA'. F is the midpoint of EG because AA' bisects EG. F is the midpoint of AA' because AA' bisects EG. F is the midpoint of EG because Line E G bisects AA'.
By using the concept of midpoint of a line, it can be concluded that-
F is the midpoint of AA' because EG bisects AA'
First option is correct
What is midpoint of a line?
Midpoint of a line is the point which divides the line into two equal parts.
ΔA'B'C' is the reflection of ΔABC
E is the midpoint of BB'
F is the midpoint of AA'
G is the midpoint of CC'
EG is the bisector of BB', AA', CC'
F is the midpoint of AA' because EG bisects AA'
First option is correct
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Complete Question
The figure has been attached
Answer: D
Step-by-step explanation: trust
Lance Industries borrowed $130,000. The company plans to set up a sinking fund that will repay the loan at the end of 18 years. Assume a 6% interest rate compounded semiannually. What amount must Lance Industries pay into the fund each period? (Round your answer to the nearest cent.)
The amount must Lance Industries pay into the fund each period is $2,054.49
Define Sinking Funds
A fund set aside to cover a certain future expense is known as a sinking fund. The sinking fund can be thought of as an annuity if equal contributions are made on a regular basis; its value will rise until it is sufficient to pay the future expense.
Given,
Lance Industries borrowed = $130,000
Time = 18 years
Interest rate = 6%
The future value is,
FVₙ =PMT( (1+i/m)ⁿ - 1 ) / (i/m) )
PMT = payment fund semiannually.
i = 6% or 0.06
m = 2 (semiannually will be 2 times per year)
n = 18 * 2 = 36 periods
FV₃₆ = $130,000
Now, plug in the values in formula
FVₙ =PMT( (1+i/m)ⁿ - 1 ) / (i/m) )
130,000 = PMT ( (1 + 0.06/2)³⁶ - 1 ) / (0.06/2) )
130,000 = PMT ( (1.03)³⁶ - 1 ) / (0.03) )
PMT = 130,000 * ( 0.03 / (1.03)³⁶ - 1 ) )
= $2,054.49
Hence, the amount must Lance Industries pay into the fund each period is $2,054.49.
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4x + 19 = 8x please help
Answer:
x=4.75
Step-by-step explanation:
4x+19=8x
-4x -4x
19 = 4x
Divide 4 on each side
4.75=x or x=4.75
Find the Maclaurin series for f(x) = xe^2x and its radius of convergence. Use only the definition of a Maclaurin series.
The Maclaurin Series of xe²ˣ: x + 2x² + 2x³+ 4/3x⁴+ 2/3x⁵ +....
Given that,
f(x) = xe^2x
Taylor series of function f(x) at a is defined as:
f(x) = f(a) + f'(a)/1!/(x-a) +f''(a)/2! (x-a)² +....
Maclaurin series of Function F(x) is a Taylor series of Function f(x) at: a=0
f(x) = f(0) + f'(0)/1! /(x) +f''(0)/2!/ (x)² +....
Apply the Maclaurin Formula
= 0 +d/dx (xe²ˣ)(0)/1! x + d²/dx² (xe²ˣ)(0)/2! x² +....
Evaluate the derivatives :
= 0 + 1/1! x + 4/2! x² + 12/3! x³ + ...
Refine :
= x + 2x² + 2x³+ 4/3x⁴+ 2/3x⁵ +....
So, the Maclaurin series for f(x) = xe^2x is x + 2x² + 2x³+ 4/3x⁴+ 2/3x⁵ +....
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When you are doing a survey of the time it takes for a person to run 100m, which unit would you use?
When you are doing a survey of the time it takes for a person to run 100m, the unit that you would you use is seconds.
What is unit?A unit of measurement is a definite magnitude of a quantity that is defined and adopted by convention or law and is used as a standard for measuring the same type of quantity. Any other such quantity can be expressed as a multiple of the unit of measurement. A length, for example, is a physical quantity.
A unit is any standard that is used to compare measurements. Unit conversions allow measurements of a property to be converted from one unit to another, such as centimeters to inches.
In this case, time is measured in seconds.
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Find the sum of following two quantities if the number is reprensented by x
i. Seven multiplied by the sum of nine and a number.
ii. The sum of four and the number.
The sum of two (63 + 7x) and (4 + x) quantities will be 8x + 67.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
Let 'x' be the number.
The first number is given as,
⇒ 7(9 + x)
⇒ 63 + 7x
The second number is given as,
⇒ 4 + x
Then the sum of two numbers is given as,
⇒ 63 + 7x + 4 + x
⇒ 8x + 67
The sum of two (63 + 7x) and (4 + x) quantities will be 8x + 67.
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In Norway last year, the lowest temperature was −15°C. In Norway last year, the highest temperature was 42°C greater than the lowest temperature. Work out the highest temperature in Norway last year
Answer:
27°
Step-by-step explanation:
Let h = highest temperature
h = -15 + 42
h = 27°
The revenue and cost functions of a company are given as () = −5 2 + 750 and () = 100 + 20,000 respectively. (i) Determine the maximum revenue for the company (4 marks) (ii) By plotting the graph of () and () on the same axes, determine the break-even levels. (
The maximum revenue of the problem given at the end of the answer is of: $144.
$28,125.
The break-even point is of:
(50, 25000) and (80, 28000).
How to maximize revenue?The revenue function is given as follows:
R(x) = -5x² + 750x.
Which is a quadratic equation with the coefficients given as follows:
a = -5, b = 750.
Then the x-coordinate of the vertex is of:
x = -b/2a = -750/-10 = 75.
Thus the maximum revenue is of:
R(12) = -5(75)² + 750(75) = $28,125.
What are the break-even points?The break-even points are the points of intersection of the revenue and of the cost functions, given as follows:
Revenue: R(x) = -5x² + 750x.Cost: 100x + 20000.From the intersection of the graph given at the end of the answer, these points are of:
(50, 25000) and (80, 28000).
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A travel company has hired a management consultant company to analyze demand in twenty-six regional markets for one of its major products: a guided tour to a particular country. The consultant uses data to estimate the following equation:
Q=1500−4P+5A+10I+3PY
Where Q = amount of the product demanded;
P = price of the product in dollars;
A = advertising expenditures in thousands of dollars;
I = income in thousands of dollars;
PY = price of some other travel products offered by a competing travel company.
a) Calculate the amount demanded for this product using the following data:
P = $400
A = $20,000
I = $15,000
PY=$500
b) Suppose the competitor reduced the price of its travel product to $400 to match the price of this firm's product. How much would this firm have to increase its advertising in order to counteract the drop in its competitor's price? Would it be worth for them to do so? Explain your answer.
c) What other variables might be important in helping estimate the demand for this travel product?
Q falls to 251,400 to 201,400 which means a fall of 50,000 which should be counteracted by advertising. If advertising expenditure becomes 30,000 it will raise the Q again to 251,400.
Given that,
One of a travel company's main products, a guided tour to a specific country, was the subject of a demand analysis by a management consulting firm for 26 regional markets. The consultant estimates the following equation using data:
Q=1500−4P+5A+10I+3PY
Q is the quantity of the product that is demanded;
P represents the item's monetary price;
A represents advertising costs in thousands of dollars;
I represents income expressed in dollars;
PY is the cost of a different travel product provided by a rival travel agency.
We have to find
(a) Utilizing the information below, determine the amount demanded for this product:
P = $400
A = $20,000
I = $15,000
PY=$500
Q = 1,500 - 4 × 400 + 5 × 20,000 + 10 × 15,000 + 3 × 500
= 1,500 - 1,600 + 100,000 + 150,000 + 1,500
= 251,400
(b) In Income falls to 10,000
Q = 1,500 - 4 × 400 + 5 × 20,000 + 10 × 10,000 + 3 × 500
= 1,500 - 1,600 + 100,000 + 100,000 + 1,500
= 201,400
Q falls to 251,400 to 201,400 which means a fall of 50,000 which should be counteracted by advertising. If advertising expenditure becomes 30,000 it will raise the Q again to 251,400.
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find the least integer n such that n! is divisible by[tex]10^{6}[/tex]
Answer:
25!
in this type of questions you need to find 10 makers ( it's means you need to find numbers which has 2 or 5 in their prime factors) obviously there is a bunch of numbers which has 2 in their prime factors.
so we need to find multiples of 5. But you should be aware that some numbers have more than one prime factors of 5 e.g. 25 .
ok let's go back to the question.
starting from 1 , we've got 5, 10 , 15 ,20 &25(5²)
so the answer is 25!
assume that a and b are positive integers. for each statement below, determine whether the statement is true or false, and indicate your answer in the appropriate box
Given Statement (a!)b = ab! is false becuase it is not appropriate to represent factorial like this.
What is Factorial?
In mathematics, the term "Factorial" refers to the sum of all positive integers that are less than or equal to a certain positive integer, which is followed by an exclamation point. Thus, factorial seven is denoted by the symbol 7!, which stands for 1*2*3*4*5*6*7. Factorial 0 is equivalent to 1 by definition.
(a!)*b = ab!
this depends on the value of a and b.
I'm not sure if the phrase "ab!" means to multiply a by b and then compute the factorial of the resulting product, as in (ab)!, or to compute the factorial of b first and then multiply this by a, as in a(b!). Either way, the assertion is false.
Given Question is incomplete Complete Question here:
assume that a and b are positive integers. for each statement below, determine whether the statement is true or false, and indicate your answer in the appropriate box (a!)b = ab!
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If the VO2 max test scores were normally distributed with a mean, median, and mode of 44ml/kg/min and standard deviation of 8, which of the following would be true. a.We should expect 16% of college students to score at least 36 on the VO2max test. b. We should expect 50% of college students to score 44 on the VO2max test. c. We should expect 84% of college students to score at least 36 on the VO2max test. d. We should expect at least 68% college students to score 36 on the VO2max test.
The VO2max test resulted by z score should result in a minimum score of 36 for 84% of college students.
To find the answer, we will use the z-score formula:
z = (x - μ)/σ
We will use the given values for the mean (μ = 44), the standard deviation (σ = 8), and the value we are looking for (x = 36).
z = (36 - 44) / 8
z = -1
We can then look up the percentage of values equal to or below -1 on the standard normal distribution table. This value is 84%. Therefore, we should expect 84% of college students to score at least 36 on the VO2max test.
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Let P (t) represent the amount of _ certain drq milligrams; that = he bloodstream time hou? The rate at which the= drug leaves the bloodstream proportional to the amount of the drug bloodstream: The amount of the drug in the bloodstream can be modeled by # KP ; where constant and- time; hours At time 500 milligrams of the drug was administered. At the moment when the amount of the drug in the bloodstream 50 milligrams, the amount decreasing at a rate milligrams per hour Which of the following an expression for P (t) P (t) = 500 0.23t P (t) = 500 4t P (t) = s0e 0.23 P (t) = e-02x + 499
As proportional relationship, the amount decreasing at a rate milligrams per hour expression P(t) = 500 + e⁻⁰²ˣ
Proportional relationship:
In math, the relationships between two variables where their ratios are equivalent is known as proportional relationship.
Given,
Here we have the rate at which the= drug leaves the bloodstream proportional to the amount of the drug bloodstream: The amount of the drug in the bloodstream can be modeled by K; where constant and- time; hours At time 500 milligrams of the drug was administered. At the moment when the amount of the drug in the bloodstream 50 milligrams, the amount decreasing at a rate milligrams per hour.
Here we need to find the expression.
While we looking into the given question, we have identified the following details,
=> Bloodstream = 500 milligrams
Here they state that the bloodstream 50 milligrams, the amount decreasing at a rate milligrams per hour.
So, the expression for this proportional relationship is written as,
=> P(t) = 500 + e⁻⁰²ˣ
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find the indefinite integral using integration by parts with the given choices of u and dv. x2 ln(x) dx;
Indefinite integral using integration by parts from x2 ln(x) dx is
[tex]\frac{1}{3}[/tex] [tex]X^{3\\}[/tex] (ln(x) - [tex]\frac{1}{3}[/tex]) + C
The given choice of u and dv
∫ [tex]x^{2} ln(x) dx[/tex]
we can use the formula
∫ u dv = uv - ∫ v du
Then split the component
u = [tex]ln(x)[/tex] du = [tex]\frac{1}{x}[/tex][tex]dx[/tex]
dv = [tex]x^{2}[/tex] v = [tex]\frac{1}{3}x^{3}[/tex]
∫ u dv = uv - ∫ v du
∫ [tex]x^{2} ln(x) dx[/tex] = ln(x) [tex]\frac{1}{3}x^{3}[/tex] - ∫ [tex]\frac{1}{3}x^{3}[/tex] [tex]\frac{1}{x}[/tex] dx
= [tex]\frac{1}{3}x^{3}[/tex] ln(x) - [tex]\frac{1}{3}[/tex] ∫ [tex]x^{3}[/tex] [tex]\frac{1}{x}[/tex] dx
= [tex]\frac{1}{3}x^{3}[/tex] ln(x) - [tex]\frac{1}{3}[/tex] ∫ [tex]x^{3} . x^{-1}[/tex] dx
= [tex]\frac{1}{3}x^{3}[/tex] ln(x) - [tex]\frac{1}{3}[/tex] ∫ [tex]x^{2}[/tex] dx ----> ∫ [tex]x^{2}[/tex] dx = [tex]\frac{1}{3} x^{3} + C[/tex]
= [tex]\frac{1}{3}x^{3}[/tex] ln(x) - [tex]\frac{1}{3}[/tex] [tex]\frac{1}{3} x^{3} + C[/tex]
= [tex]\frac{1}{3} x^{3} ( ln(x) - \frac{1}{3} ) + C[/tex]
Therefore Indefinite integral using integration by parts
∫ [tex]x^{2} ln(x) dx[/tex] is [tex]\frac{1}{3} x^{3} ( ln(x) - \frac{1}{3} ) + C[/tex]
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I need help with this please help me
The translation rule that maps A(-4, -2), B(-2, 6) and C (4, 4) to A' (-2, -2) B' (0, -10) and C' (6, -8) is
(x + 2, y + 4)
How to find he translation rule that suit the transformationThe transformation rule is solved by comparing the both preimage and image transformations as follows
preimage image
A(-4, -2) A' (-2, -2)
B(-2, 6) B' (0, -10)
C (4, 4) C' (6, -8)
x direction
-4 + x = -2, x = -2 + 4 = 2
-2 + x = 0, x = 0 + 2 = 2
4 + x = 6, x = 6 - 4 = 2
y direction reflection on the x axis leads to change of sign
preimage image
A(-4, -2) A' (-2, 2)
B(-2, 6) B' (0, 10)
C (4, 4) C' (6, 8)
-2 + y = 2, y = 2 + 2 = 4
6 + y = 10, y = 10 - 6 = 4
4 + y = 8, y = 8 - 4 = 4
The transformation rule is (x + 2, y + 4)
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If I earn 100% more than you, then you must earn 50% less than me
Samuel has a watch that is faster than his alarm clock at home by 20 seconds in an hour. The alarm clock is, in turn, slower than the actual time by 30 seconds every hour. By how many seconds does his watch deviate from the actual time in a day?
Answer:
Samuel's watch is slower than the actual time 10 seconds.
Step-by-step explanation:
30 - 20 = 10 (seconds)
So Samuel's watch is slower than the actual time 10 seconds.
PLEASE GIVE ME BRAINLIEST IF THIS IS THE CORRECT ANSWER! THANKS!
Answer: 240 seconds
Step-by-step explanation:
So, here Samuel's watch gains 20 seconds every hour with respect to the alarm clock.
Also, alarm clock lags by 30 seconds every hour with respect to the actual time.
Therefore, Samuel's watch lags by (30-20) seconds every hour with respect to the actual time.
30-20=10 seconds
In 1 hour Samuel watch deviate by 10 seconds, then in 24 hours, it deviates by 24*10 seconds= 240 seconds..
S is the midpoint of RT. T has coordinates (-14,-15) and S has coordinates (11,-1) Find the coordinates of R
Answer:
(36, 13)
Step-by-step explanation:
to find the midpoint you have the add the x and the y and then divide by two
to find one of the endpoints you just do the opposite
you multiply the midpoint by 2
and then subtract the remaining endpoint from it
(11, -1) --> (22, -2)
now subtract T from it
(36, 13)
that is your answer
The stock of WAL-MAT pays a dividend of $.88. The stock opened at $18.25 and closed at $18.33. The stock yield is:
Multiple Choice
4.8%
4.2%
4.1%
The stock yield for the stocks will be 4.8%. The correct option is A.
What is an expression?The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
To get the stock to yield use this formula - annual dividend / current stock price or share price
Substitute the dividend of $.88 and the closing price of $18.33 to the formula above. Divide and simplify.
Stock yield = .88 / 18.33
Stock yield = 0.0480 x 100
Stock yield = 4.8%
Therefore, the stock yield for the stocks will be 4.8%. The correct option is A.
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mathematics and statistics teacher rex boggs, from australia, weighed the bar of soap in his shower stall before showering in the morning. the data on day and soap weight (in grams) appear in the table. (notice that he forgot to weigh the soap on some days!) here are the data.
As per the concept of linear regression, the equation of the data is y = 133.1807 − 6.3096x.
The term linear regression means to determine the character and strength of the association between a dependent variable and a series of other independent variables.
Here we have given that mathematics and statistics teacher rex boggs, from Australia, weighed the bar of soap in his shower stall before showering in the morning. And the data on day and soap weight (in grams) appear in the table.
Here we need to find the linear regression equation that represents the given situation.
Based on the concept of linear regression, we know the the general formula for the regression is written as,
=> y = a + bx
FRom the given data, we have identified the value of the functions as,
a = 133.1807
b = -6.3096
r² = 0.9962
r = -0.9981
When we apply these values on the formula, then we get the equation as,
Then it implies the regression line is,
=> ŷ = a + bx = 133.18076.3096x
here a represents the day and y represents the weight in grams.
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How much would you need to deposit in an account now in order to have $5,000.00 in the account in 821 days?
Assume the account earns 5 % simple interest.
You would need to deposit ___
in your account now.
The principal investment required to get an accrued amount of $5,000.00 in 821 days is $4,494.52.
What is the principal need for the investment?Simple interest is expressed as;
A = P(1 + rt)
Where A is accrued amount, P is principal, r is interest rate and t is time.
Given that;
Accrued amount A = $5,000.00Elapsed time t = 821 days = 821/365 yrsInterest rate r = 5% = 5/100 = 0.05Principal P = ?Plug the given values into the above formula and solve for principal P.
A = P(1 + rt)
P = A / (1 + rt)
P = $5,000.00 / ( 1 + ( 0.05 × 821/365 ) )
P = $5,000.00 / ( 1 + 821/7300 )
P = $5,000.00 / ( 8121/7300 )
P = $4,494.52
Therefore, the principal required is $4,494.52.
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john is jogging on a straight jogging trail toward a flagpole at a speed of 500 ft/min. he is currentyl 1500 feet from the flagpole.
As per the unitary method, it take 3 minutes will it take John to reach the flagpole.
The term unitary method in math is defined as in which the value of one article is first obtained to find out the value of any required articles.
Here we have given that John is jogging on a straight jogging trail toward a flagpole at a speed of 500 ft/min. He is currently 1500 feet from the flagpole. And here we have to write an absolute value function that models John's distance from the flagpole after x minutes.
Here let us consider x be the time taken by John to reach the flagpole.
And here we know that
speed = 500 ft/min
height = 1500 feet
Then the absolute function for the given situation is written as,
=> f(x) = 500|x|
Apply the value of f(x) as 1500, then we get
=> 1500 = 500|x|
=> x = 3
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If the diagonal of a square is 11.3meters, approximately what is the perimeter of the square?
The perimeter of the square will be equal to 31.96 meters.
What is a perimeter?The perimeter of the square is defined as the sum of all the sides of the square. The perimeter of the square when the diagonals of the square are given will be calculated by the product of 2√2 with the diagonal magnitude.
Given that the diagonal of the square is 11.3 meters. The perimeter of the square will be calculated as,
P = 2√2 x d
P = 2√2 x 11.3
P = 31.96 meters
Therefore, the perimeter of the square will be equal to 31.96 meters.
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The price of a gift plus 14% delivery charge comes to a total cost of $19.38. What was the price of the gift?
Step 1 of 2 : Describe the above situation as a linear equation, using "x" or "y" as variable names to describe the unknown quantity.
Answer:
1.14x = 19.38
$17
Step-by-step explanation:
Let the price before delivery charge = x.
The charge is 14%, so it is 14% of x, or 0.14x.
The original price plus charge is x + 0.14x, or 1.14x.
1.14x = 19.38
x = 19.38/1.14
x = 17
The price is $17
sin(theta) * sec(theta) - 2sin(theta) = 0
Solve with all possible answers for theta
(please)
Answer:
θ = 2 π n_1 + π/3 for n_1 element Z
or θ = 2 π n_2 + (5 π)/3 for n_2 element Z
or θ = π n_3 for n_3 element Z
θ = π n_3 for θ element Z and cos(θ)!=0 and n_3 element Z
Step-by-step explanation:
Solve for θ:
tan(θ) - 2 sin(θ) = 0
Factor sin(θ) from the left hand side:
sin(θ) (sec(θ) - 2) = 0
Split sin(θ) (sec(θ) - 2) into separate parts with additional assumptions.
Assume cos(θ)!=0 from sec(θ):
sec(θ) - 2 = 0 or sin(θ) = 0 for cos(θ)!=0
Add 2 to both sides:
sec(θ) = 2 or sin(θ) = 0 for cos(θ)!=0
Take the reciprocal of both sides:
cos(θ) = 1/2 or sin(θ) = 0 for cos(θ)!=0
Take the inverse cosine of both sides:
θ = 2 π n_1 + π/3 for n_1 element Z or θ = 2 π n_2 + (5 π)/3 for n_2 element Z
or sin(θ) = 0 for cos(θ)!=0
Take the inverse sine of both sides:
θ = 2 π n_1 + π/3 for n_1 element Z
or θ = 2 π n_2 + (5 π)/3 for n_2 element Z
or θ = π n_3 for cos(θ)!=0 and n_3 element Z
The roots θ = π n_3 never violate cos(θ)!=0, which means this assumption can be omitted:
Answer: θ = 2 π n_1 + π/3 for n_1 element Z
or θ = 2 π n_2 + (5 π)/3 for n_2 element Z
or θ = π n_3 for n_3 element Z
Solve for θ over the integers:
tan(θ) - 2 sin(θ) = 0
Factor sin(θ) from the left-hand side:
sin(θ) (sec(θ) - 2) = 0
Split sin(θ) (sec(θ) - 2) into separate parts with additional assumptions.
Assume cos(θ)!=0 from sec(θ):
sec(θ) - 2 = 0 or sin(θ) = 0 for cos(θ)!=0
Add 2 to both sides:
sec(θ) = 2 or sin(θ) = 0 for cos(θ)!=0
Take the reciprocal of both sides:
cos(θ) = 1/2 or sin(θ) = 0 for cos(θ)!=0
Take the inverse cosine of both sides:
θ = 2 π n_1 + π/3 for θ element Z and n_1 element Z or θ = 2 π n_2 + (5 π)/3 for θ element Z and n_2 element Z
or sin(θ) = 0 for cos(θ)!=0
The roots θ = 2 π n_1 + π/3 violate θ element Z for all n_1 element Z:
θ = 2 π n_2 + (5 π)/3 for θ element Z and n_2 element Z
or sin(θ) = 0 for cos(θ)!=0
The roots θ = 2 π n_2 + (5 π)/3 violate θ element Z for all n_2 element Z:
sin(θ) = 0 for cos(θ)!=0
Take the inverse sine of both sides:
Answer: θ = π n_3 for θ element Z and cos(θ)!=0 and n_3 element Z
As the number of degrees of freedom for t-distribution increases, the difference between the t-distribution and standard deviation:
a. becomes larger.
b. becomes smaller.
c. stays the same.
d. None of the above
As the number of degrees of freedom for t-distribution increases, the difference between the t-distribution and standard deviation becomes smaller. The correct answer is B.
What are degrees of freedom for t-distribution?A t-distribution is described by one parameter, that is, degrees of freedom (df) v = n – 1, where n is the sample size. Its variance = v, where v represents the number of degrees of freedom and v ≥ 2.
To calculate degrees of freedom of a 1-sample t-test, we have to determine the size of our sample (N). Then, subtract 1. The result is the number of degrees of freedom.
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