Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

Answers

Answer 1

The center is (1,0), thus the center lies on the x-axis, the radius is 3 units and the radius of the circle is the same with x² + y² = 9.

What is the radius and the center of a circle?

The radius is half the diameter of a circle and the center of the circle is a point from which all distance to the edge of the circle is equal.

The equation that represents the center of the circle equation is (x - h)² + (y - k)² = r², where h,k represents the center and r is the radius.

Our circle in this form is: (x − 1)² +(y − 0)² = 3. Thus, h = 1, k = 0, r = 3. The standard form is y² + (x − 1)² = 9.

We can conclude that the center is (1,0), thus the center lies on the x-axis, the radius is 3 units and the radius of the circle is the same with x² + y² = 9.

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Related Questions

(x - 2)/(x + 2) - (x + 2)/(x - 2)​

Answers

Answer:

[tex]-\cfrac{8x}{x^2-4}[/tex]

----------------------------------

Simplify in below steps:

[tex]\cfrac{x-2}{x+2} -\cfrac{x+2}{x-2} =[/tex]                                   Bring to common denominator

[tex]\cfrac{(x-2)^2}{(x+2)(x-2)} -\cfrac{(x+2)^2}{(x+2)(x-2)}=[/tex]       Multiply both fractions by x +2 or x - 2

[tex]\cfrac{(x-2)^2-(x+2)^2}{(x+2)(x-2)}=[/tex]                           Make a single fraction

[tex]\cfrac{(x-2+x+2)(x-2-x-2)}{(x+2)(x-2)}=[/tex]          Factorize the numerator

[tex]\cfrac{2x(-4)}{(x+2)(x-2)}=[/tex]                                   Simplify the numerator

[tex]-\cfrac{8x}{x^2-4}[/tex]                                                Answer

Used identity:

[tex](a+b)(a-b)=a^2-b^2[/tex]

(c) Write
3"
9-1
as a power of 3

Answers

Let's first start by rewriting the denominator to have a base of 3.

9 = 3^2

9^(n - 1) = 3^2(n - 1)

Now that we have two terms with the same base, we can subtract the exponents.

3^n / 3^2(n - 1) = 3^[n - 2(n - 1)]

3^[n - 2n + 2]

3^[-n + 2]

3^-(n - 2)

Answer: 3^(-n + 2) OR 3^-(n - 2)

Hope this helps!

two people leave their shared apartment at the same time. during a 500 second interval, one jogs 10 blocks south at a constant rate, whereas the second walks 5 blocks west, again, at a constant rate. what is their speed relative to each other during this interval? assume each block corresponds to 100 meters.

Answers

The relative speed between the jogger and the walker during the 500 second interval is 2.24 m/s.

To solve this problem, we need to first find the distances traveled by each person.

The jogger travels 10 blocks x 100 meters/block = 1000 meters south.

The walker travels 5 blocks x 100 meters/block = 500 meters west.

Using the Pythagorean theorem, we can find the distance between them: √((1000m)² + (500m)²) = 1118.03 meters.

To find their relative speed, we divide this distance by the time interval: 1118.03 meters / 500 seconds = 2.24 m/s.

Therefore, their speed relative to each other during this interval is 2.24 m/s.

The jogger traveled 1000 meters south, while the walker traveled 500 meters west. Using the Pythagorean theorem, the distance between them is 1118.03 meters. Dividing this distance by the time interval of 500 seconds, we get their relative speed, which is 2.24 m/s.

: The relative speed between the jogger and the walker during the 500 second interval is 2.24 m/s.

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this graph shows how fast the international space station travels in orbit around the earth. what is the meaning of the point x-coordinate of 3

Answers

The X-Coordinate of 3 only represents a specific moment in time during the orbit and not necessarily the speed of the ISS at all times.

Since the graph is showing how fast the International Space Station (ISS) is traveling in orbit around the Earth, the x-coordinate of 3 likely represents a specific point in time or duration of the orbit.

To find out what the x-coordinate of 3 represents, we need to know the units of time on the x-axis. If the units are in minutes, then a value of 3 would represent 3 minutes. Similarly, if the units are in hours, then a value of 3 would represent 3 hours.

Assuming the units on the x-axis are in minutes, the point with an x-coordinate of 3 represents the speed of the ISS 3 minutes into its orbit. This means that at that point in time, the ISS was traveling at a speed of approximately 27,500 kilometers per hour.

It's important to note that the speed of the ISS can vary throughout its orbit, depending on factors such as altitude, atmospheric conditions, and changes in the orbit itself. Therefore, the x-coordinate of 3 only represents a specific moment in time during the orbit and not necessarily the speed of the ISS at all times.

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Note the full question is

Representing Proportional Relationships

This graph shows how fast the International Space Station travels in orbit around Earth.

What is the meaning of the point with an x-coordinate of 3?

What is the answer to this question??

Answers

The missing length indicated has the value given as follows:

x = 25.

What is the geometric mean theorem?

The geometric mean theorem states that the length of the altitude drawn from the right angle of a triangle to its hypotenuse is equal to the geometric mean of the lengths of the segments formed on the hypotenuse.

The bases in this problem are given as follows:

x and 144.

The length of the altitude segment is given as follows:

60.

60 is the geometric mean of x and 144, hence the value of x is obtained as follows:

144x = 60²

x = 3600/144

x = 25.

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Use the formula to find the surface area of the figure. Show your work.

Answers

230 inches to the power of 2

Help me please I don’t understand this at all

Answers

The equation of the line represented by the points on the graph is  (5x+16)/6.

What is a line?

line is a straight one-dimensional figure that does not have a thickness, and it extends endlessly in both directions.

To calculate the equation of the line represented by the points on the graph, we use the formula below

Formula:

(y-y₁)/(x-x₁) = (y₂-y₁)/(x₂-x₁)....................... Equation 1

From the points in the graph,

Given:

y₁ = 1y₂ = 6x₁ = -2x₂ = 4

Substitute these values into equation 1

[y-1]/[x-(-2)] = (6-1)/[4-(-2)]y-1/x+2 = 5/66(y-1) = 5(x+2)6y-6 = 5x+106y = 5x+10+66y = 5x+16y = (5x+16)/6

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How do I solve this?

Answers

Prove of expression tan² θ - sin² θ = tan² θ × sin² θ is shown below.

Given that;

Expression is,

⇒ tan² θ - sin² θ = tan² θ × sin² θ

Now, We can simplify as;

⇒ tan² θ - sin² θ

⇒ sin² θ / cos² θ - sin²θ

⇒ sin² θ (1 / cos² θ - 1)

⇒ sin² θ (sec² θ - 1)

⇒ sin² θ × tan² θ

Thus, Prove of expression tan² θ - sin² θ = tan² θ × sin² θ is shown.

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Evaluate the indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.) st tan(2x + 9)dx

Answers

Answer:

1/2 ㏑(sec (2x + 9)) + c  ........ absolute sec (2x +9)

Step-by-step explanation:

∫tan (2x + 9) dx

let u = 2x + 9

du/dx = 2

dx = du/2 = (1/2) du

now we have ∫tan u (1/2  du)

= 1/2 ∫tan u du

= 1/2 ㏑ (sec u) ...... absolute

=1/2 ㏑(sec (2x + 9)) + c ........ absolute

Tommy and his friends are planning a trip to the Mega Vault trampoline park. The employee
Tommy spoke to on the phone said the total cost for all 5 of them would be $85. This includes
a $3 fee added to each entrance ticket to cover the cost of a pair of grip socks.
Which equation can you use to find c, the cost of an entrance ticket?
5(c + 3) = 85
5c + 3 - 85
3c+5 85
3(c+5)= 85

Answers

The equation to find the entrance cost is 5(c + 3) = 85.

Given that 5 five friends made plan for trip, which will cost them a total of $85,

This includes a $3 fee added to each entrance ticket to cover the cost of a pair of grip socks.

We need to establish an equation to find c, the cost of an entrance ticket,

So,

The total cost of one entrance ticket = c + 3,

So, for 5 people = 5(c+3)

Now, this is equal to 85.

So the equation is = 5(c + 3) = 85.

Hence the equation to find the entrance cost is 5(c + 3) = 85.

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pls help me im begging

Answers

The surface area of the triangular prism in square meters is:

549.15 m²

How to find the surface area of triangular prism?

The total surface area of the given prism would be the sum of the areas of the individual faces that make up the prism.

The formula for area of a triangle is:

Area = ¹/₂ * base * height

The formula for area of a rectangle is:

Area = Length * width

Thus:

Total surface area of prism is:

TSA = (15 * 13) + (15.81 * 15) + 2(¹/₂ * 9 * 13)

TSA = 549.15 m²

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can you guys help me with this

Answers

Answer:

The correct equation is D. 13x - 2y = 40

13(2) - 2(-7) = 26 + 14 = 40

13(4) - 2(6) = 52 - 12 = 40

y varies jointly as the square of x, the square of z, and when x = 3 and
z = 4, then y = 72
What’s the equation?

Answers

The equation will be y = kx²z², where k is the proportionality constant.

Given that y varies jointly as the square of x, the square of z,

And when x = 3 and z = 4, then y = 72,

So, we can write,

y ∝ x²z²

or,

y = kx²z² [k = proportionality constant]

Now, given x = 3 and z = 4, then y = 72,

Therefore,

72 = 3²·4²·k

72 = 9·16 k

k = 72 / 144

k = 0.5

Therefore, the value of proportionality constant k is 0.5.

Hence the equation will be y = kx²z², where k is the proportionality constant.

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. Francois has 8 feet of trim. He is
making 3 picture frames. Write a
fraction that represents the number of
feet of trim that can be used for each
picture frame. Fill in the bubble before
each number that is correct.

Pls help it’s a grade

Answers

Answer:  

[tex]\displaystyle \frac{8}{3} \;\text{feet per picture frame}[/tex]

Step-by-step explanation:

      We will divide the total amount of trim that Francois has, 8 feet, by the number of picture frames, 3. This will give us a fraction that represents how many feet of trim can be used for each picture frame.

       [tex]\displaystyle \frac{\text{8\;\;feet}}{\text{3 picture frames}} =\frac{8}{3} \;\text{feet per picture frame}[/tex]

a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $80 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the $20 coffee should be used

Answers

To obtain a mixture of coffee that can be sold for $60 a pound, the merchant must mix the $20 coffee with the $80 coffee in such a way that the resulting mixture is worth $60 per pound.

To determine how many pounds of the $20 coffee should be used, we can set up a system of equations using the weights of each type of coffee and their corresponding values per pound.

Let x be the number of pounds of the $20 coffee to be used. Then, the total weight of the mixture is 80 + x pounds. The value of the $20 coffee is $20 per pound, and the value of the $80 coffee is $80 per pound. The value of the mixture must be $60 per pound. Therefore, we can write the following equation:

$20x + 80(80) = 60(80 + x)$

Simplifying and solving for x, we get:

$x = 200$

Therefore, the merchant should use 200 pounds of the $20 coffee and mix it with 80 pounds of the $80 coffee to obtain a mixture that can be sold for $60 a pound.

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an answering service staffed with one operator takes phone calls from patients for a clinic after hours. patient phone calls arrive at a rate of lambda equals 15 per hour. the interarrival time of the arrival process can be approximated with an exponential distribution. patient phone calls can be processed at a rate of mu equals 25 per hour. the processing time for the patient phone calls can also be approximated with an exponential distribution. determine the utilization factor.

Answers

The utilization factor can be calculated as the ratio of the arrival rate to the service rate. In this case, the arrival rate (lambda) is 15 per hour, and the service rate (mu) is 25 per hour. Therefore, it is important for the clinic to monitor the utilization factor and adjust staffing levels as needed to ensure efficient and effective patient communication.

So the utilization factor is:
Utilization factor = lambda / mu
Utilization factor = 15 / 25
Utilization factor = 0.6
This means that on average, the operator is utilized 60% of the time. In other words, there is a 40% idle time during which no phone calls are being processed. This is a relatively low utilization factor, which suggests that there is some capacity to handle more phone calls if necessary. However, it is important to note that if the arrival rate were to increase, the utilization factor would increase as well, which could lead to longer wait times for patients and potential bottlenecks in the phone system.

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The figure shows △GHJ and △PQR on a coordinate plane.

a. Explain why the triangles are congruent using the ASA Triangle Congruence Theorem.

b. Explain why the triangles are congruent using rigid motions

Answers

Using the ASA Triangle Congruence Theorem, we can prove that triangles GHJ and PQR are congruent because they have Angle G and angle P are congruent, both being right angles.

The two triangles are congruent by rigid motions.

Using the ASA Triangle Congruence Theorem, we can prove that triangles GHJ and PQR are congruent because they have:

Angle G and angle P are congruent, both being right angles.

Side GH and side PQ are congruent, both having a length of 5 units.

Angle H and angle Q are congruent, both having a measure of 63.43 degrees (rounded to two decimal places).

Since the two triangles have two congruent angles and a congruent side between them, they are congruent by the ASA Triangle Congruence Theorem.

b. We can also prove that triangles GHJ and PQR are congruent using rigid motions.

Specifically, we can use a translation followed by a reflection to map triangle GHJ onto triangle PQR.

Translation: We can translate triangle GHJ 2 units to the left and 3 units down to get triangle G'H'J', where G'(-2, 1), H'(-2, -2), and J'(2, -2).

Reflection: We can reflect triangle G'H'J' across the x-axis to get triangle PQR, where P(-2, -4), Q(-2, -1), and R(2, -1).

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Determine which of the following statements is true for the function g(z) = 4x³ - 3r + 2r³ - 1.
A

D
As x→ ∞o, f(x) → ∞o and as x→→∞, f(x)→-00.
As x → ∞o, f(x) → ∞o and as x→-∞, f(x)→ 00.
As x→ ∞o, f(x)--∞o and as x→-∞, f(x) →∞0.
As x→ ∞, f(x)-- and as x→-∞, f(x)→-00.

Answers

The correct statement is:
As x → ∞, f(x) → ∞ and as x → -∞, f(x) → -∞.

I understand that you are asking about the behavior of the function g(z) as x approaches positive and negative infinity. Let's analyze the given function:
g(z) = 4x³ - 3r + 2r³ - 1
First, I believe "r" should be "x" to keep the variables consistent. So, the corrected function is:
g(x) = 4x³ - 3x + 2x³ - 1
Now, let's find the end behavior of this function as x approaches positive and negative infinity.
As x → ∞:
The highest degree term, x³, will dominate the function's behavior. The coefficients for x³ are 4 and 2, so the function will behave like 6x³. Since this term is positive and has an odd exponent, as x → ∞, f(x) → ∞.
As x → -∞:
Again, the x³ term will dominate the function's behavior. Since the exponent is odd, as x → -∞, f(x) → -∞.
So, the correct statement is:
As x → ∞, f(x) → ∞ and as x → -∞, f(x) → -∞.

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plot points H I and J on the coordinate plane​

Answers

In order to plot points H I and J on the coordinate planeIdentify the x-coordinate and y-coordinate of each point (H, I, and J). For example, let's say the coordinates are as follows:

Point H: (xH, yH)

Point I: (xI, yI)

Point J: (xJ, yJ)

How to explain the information

Locate the origin (0, 0) on the coordinate plane. This is the starting point for plotting any point.

Move along the x-axis according to the x-coordinate of each point. If the x-coordinate is positive, move to the right; if it's negative, move to the left. Mark a point on the x-axis at the appropriate location.

Move along the y-axis according to the y-coordinate of each point. If the y-coordinate is positive, move upward; if it's negative, move downward. Mark a point on the y-axis at the appropriate location.

The point where the x and y axes intersect is the location of the point. Mark that point on the coordinate plane.

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How to Plot points H I and J on the coordinate plane

3. A test has a maximum possible score of 200. The results achieved by a class of 20 stu * dentsarelisted / 168, 152, 112, 88, 95, 123, 177, 166, 145, 104, 112, 156, 110, 141 , 177, 166, 134, 190, 111, and 120. Calculate the percentile rank of a score of 141, to the nearest percentile. (4 marks)

Answers

The percentile rank of a score of 141, to the nearest percentile, is 53.

What is the percentile rank?

The percentile rank describes the percentage of scores in the frequency distribution that are equal to or lower than the achieved score.

To calculate the percentile rank of a score of 141, we can proceed as follows:

Firstly, the scores are arranged in ascending order: 88, 95, 104, 110, 111, 112, 112, 120, 123, 134, 141, 145, 152, 156, 166, 166, 168, 177, 177, 190.

The number of scores below 141 = 10

The number of scores equal to 141 = 1

The following percentile rank formula can be used to determine the percentile rank of a score of 141:

Percentile Rank = [(M + (0.5 * R)) / Y] x 100, where:

M = Number of Ranks below x

R = Number of Ranks equals x

Y = Total Number of Ranks

Percentile Rank = [(10 + (0.5 * 1)) / 20] x 100

= 52.5

Percentile Rank = 53

Thus, the percentile rank of a score of 141 in a test with a maximum possible score of 200 is 53.

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A cylinder has a height of 18 inches and a diameter of 40 inches. What is its volume? Use ​ ≈ 3.14 and round your answer to the nearest hundredth.

Answers

Answer:

≈226.1947

Step-by-step explanation:

have a great day and thx for your inquiry :)

Segments DE, EF and DF are all tangent to the circle. Find the perimeter of Triangle DEF.
*
73
26.5
37.8
84

Answers

The perimeter of the triangle is 73 unit.

We know that tangents drawn from external point are equal in length.

So, HE = EI = 16 unit

IF = GF = 9.5 unit

DG = DH = 11 unit

So, the length of sides are

DE = 16 + 11 = 27

EF = 9.5 + 16 = 25.5

FD = 11 + 9.5 = 20.5

Now, the perimeter of Triangle DEF is

= DE + EF + FD

= 27 + 25.5 + 20.5

= 73 unit

Therefore, the perimeter of the triangle is 73 unit.

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Simplify, (Write each expression without using the absolute value symbol)
x-(-12) if x<-12

Answers

Answer:

If x < -12, then (-x) > 12, and we have:

x - (-12) = x + 12

So, the simplified expression without using the absolute value symbol is:

x + 12

Step-by-step explanation:

Answer:

Since x is less than -12, then x-(-12) = x+12.

Here is a table of values for x and x-(-12):

x | x-(-12)

-13 | -1

-14 | -2

-15 | -3

...

Step-by-step explanation:

x^4-5x^3+7x^2-5x+6=0

Answers

Answer:Therefore, the solutions to the equation x^4 - 5x^3 + 7x^2 - 5x + 6 = 0 are x = 0, x = 1, x = 5.

Step-by-step explanation:

To solve the equation x^4 - 5x^3 + 7x^2 - 5x + 6 = 0, we can use factoring by grouping.

First, we can group the first two and last two terms:

x^4 - 5x^3 + 7x^2 - 5x + 6 = (x^4 - 5x^3) + (7x^2 - 5x + 6)

Next, we can factor out x^3 from the first group and factor out 1 from the second group:

(x^3(x - 5)) + (7x^2 - 5x + 6)

Now, we can group the last two terms of the second group:

x^3(x - 5) + (7x^2 - 3x - 2x + 6)

Then, we can factor out 1 from the terms inside the parentheses and group them:

x^3(x - 5) + (7x^2 - 3x) + (-2x + 6)

Now, we can factor out x from the second and third groups:

x^3(x - 5) + x(7x - 3) - 2( x - 3)

We can simplify the third group by distributing the negative sign:

x^3(x - 5) + x(7x - 3) - 2x + 6

Finally, we can combine the second and third groups:

x^3(x - 5) + x(7x - 5) + 6

So, the factored form of the equation x^4 - 5x^3 + 7x^2 - 5x + 6 = 0 is:

(x^3(x - 5) + x(7x - 5) + 6) = 0

This equation can be solved by setting each factor equal to zero and solving for x:

x^3(x - 5) + x(7x - 5) + 6 = 0

(x^3 - 7x^2 + 5x) + (6 - 5x) = 0

x(x^2 - 7x + 5) - (5x - 6) = 0

x(x - 5)(x - 1) - (5x - 6) = 0

x(x - 5)(x - 1) = 5x - 6

x^3 - 6x^2 + 10x - 6 = 5x - 6

x^3 - 6x^2 + 5x = 0

x(x^2 - 6x + 5) = 0

x(x - 1)(x - 5) = 0

Therefore, the solutions to the equation x^4 - 5x^3 + 7x^2 - 5x + 6 = 0 are x = 0, x = 1, x = 5.

A radio station runs a promotion at an auto show with a money box with 13 ​$50 ​tickets, 11​$25 ​tickets, and ​11$5 tickets. The box contains an additional ​20 "dummy" tickets with no value. Three tickets are randomly drawn. Find the probability that exactly two ​$50 prizes and no other money winners are chosen

Answers

The probability of choosing exactly two $50 tickets and no other money winners is:

34,320 / 21,455 ≈ 0.

we can use the hypergeometric    probability   distribution to solve this problem, since we are drawing without replacement from a finite population of tickets with different values.

the total number of tickets in the box is:

13 + 11 + 11 + 20 = 55

the number of ways to choose exactly two $50 tickets from the 13 available is:

${13 \choose 2} = 78$

the number of ways to choose one dummy ticket from the 20 available is:

${20 \choose 1} = 20$

the number of ways to choose one ticket from the remaining non-$50 tickets is:

11 + 11 = 22

, the total number of ways to choose exactly two $50 tickets and no other money winners is:

78 x 20 x 22 = 34,320

the number of ways to choose any three tickets from the 55 available is:

${55 \choose 3} = 21,455$ 60 or about 60%

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Isabell run 7 miles in 80 minutes at the same rate how many miles would she run in 64 minutes

Answers

7(64)/80 = 5.6 miles{ANSWER}♥️

What is tan A? use a slash for the fraction.

Answers

Remember - SOH CAH TOA

cos(A) = adjacent / hypotenuse

adjacent = 5

sin(A) = opposite / hypotenuse

opposite = 12

hypotenuse = 13

tan(A) = opposite / adjacent

tan(A) = 12 / 5

Answer: tan(A) = 12/5

Hope this helps!

Find the volume of a right circular cone that has a height of 15.4 m and a base with a circumference of 18 m. Round your answer to the nearest tenth of a cubic meter.

Answers

The volume of the right circular cone with a height of 15.4 m and a base circumference of 18 m is 15.68 cubic meters.

To find the volume of a right circular cone, we can use the formula:

Volume = (1/3) × π × r² × h,

where π is the mathematical constant pi, r is the radius of the base, and h is the height of the cone.

Given that the base has a circumference of 18 m, we can calculate the radius using the formula:

Circumference = 2 × π × r

18 = 2 × π × r

r = 18 / (2 × π) = 2.864 m.

Now we can substitute the values into the volume formula:

Volume = (1/3) × π × (2.864 m)² × 15.4 m,

Volume = 15.68 m³

Therefore, the volume of the right circular cone with a height of 15.4 m and a base circumference of 18 m is 15.68 cubic meters.

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A golfer played 7 rounds of golf with the following scores: 1 round at 3 over par, 2 rounds with 1 over par, 3 rounds with 3 under par, and the last round at 1 under par. How did she finish with respect to par?

Answers

Answer:

To determine how the golfer ended in terms of par, tally up all of her scores and deduct them from the total par for the seven rounds.

The total par for seven rounds multiply by eighteen is 126 (assuming the course is a regular par 72).

The golfer's score in relation to par for each round is:

1 round at 3 over par = 75 (72 + 3)

2 rounds with 1 over par = 73 (72 + 1) x 2 = 146

3 rounds with 3 under par = 69 (72 - 3) x 3 = 207

1 round at 1 under par = 71 (72 - 1)

you add all the pars working above, which is

75 + 146 + 207 + 71 = 499

Her score of 499 is 27 below par (126 - 499 = -373), meaning she ended significantly below par.

Find the volume of liquid needed to fill a sphere of radius R to height R/5.

Answers

To find the volume of liquid needed to fill a sphere of radius R to a height of R/5, we can consider the spherical cap formed by the liquid.

The volume of a spherical cap can be calculated using the formula:

V = (1/3)πh²(3R - h)

Where V is the volume, h is the height of the cap, and R is the radius of the sphere.

In this case, the height of the cap is R/5 and the radius of the sphere is R. Substituting these values into the formula, we get:

V = (1/3)π(R/5)²(3R - R/5)

= (1/3)π(R²/25)(15R - R/5)

= (1/3)π(R²/25)(74R/5)

= (74/75)πR³

So, the volume of liquid needed to fill the sphere to a height of R/5 is (74/75)πR³.

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