Yes, The series "axBx" satisfies all the rules of the language defined above
Let's analyze each rule:
1. Each series must contain one and only one prefix character:
The series "axBx" contains one prefix character, 'a'. It meets this rule by having exactly one prefix character.
2. A series must start with a prefix character:
The series "axBx" starts with the prefix character 'a'. It satisfies this rule by starting with the required prefix character.
3. A series must end with a punctuation character:
The series "axBx" ends with the punctuation character 'x'. It follows this rule by ending with the required punctuation character.
4. A series can have up to but no more than 5 characters, including prefix and punctuation characters:
The series "axBx" has a total of 5 characters, which includes the prefix character 'a', the letters 'x' and 'B', and the punctuation character 'x'. It adheres to this rule by having the maximum allowed number of characters in the series.
Therefore, the series "axBx" satisfies all the rules of the language defined above. It contains one prefix character, starts with a prefix character, ends with a punctuation character, and has the maximum allowed number of characters.
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Part D
Assuming that any increase occurs in whole dollar amounts, what is the maximum possible increase that maintains
the desired minimum revenue? Explain why this is true.
The desired minimum revenue is $3. See the reason below.
What is the reason why the above is true?Charge= b, Customer= c, Revenue= r
r= bc, currently, r= 16*10= $160
We know that: b+1 ⇒ c-2 and the target is r ≥ 130
So, this will all be reflected as -
b=10+x ⇒ c= 16-2x
(10+x)(16-2x) ≥ 130
160 -20x +16x - 2x² ≥ 130
-2x² - 4x + 30 ≥ 0
x² + 2x -15 ≤ 0
(x+1)² ≤ 4²
x+1 ≤ 4 (negative value not considered)
x ≤ 3
As we see the max increase amount is $3, when the revenue will be -
(10+3)*(16-3*2)= 13*10= $130
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Noah manages a buffet at a local restaurant. He charges $10 for the buffet. On average, 16 customers choose the buffet as their meal every hour. After surveying several customers, Noah has determined that for every $1 increase in the cost of the buffet, the average number of customers who select the buffet will decrease by 2 per hour. The restaurant owner wants the buffet to maintain a minimum revenue of $130 per hour. Noah wants to model this situation with an inequality and use the model to help him make the best pricing decisions. Assuming that any increase occurs in whole dollar amounts, what is the maximum possible increase that maintains the desired minimum revenue? Explain why this is true.
Pls help it’s for my homework
Answer: I think it is 5
Therefore, The Volume of ORNAMENT ( B ) is 5^3 = 125 TIMES LARGER than the VOLUME of ORNAMENT ( A ).
Hence, The VOLUME of ORNAMENT (B) is 125 TIMES LARGER than the VOLUME of ORNAMENT (A).
Step-by-step explanation:MAKE A PLAN:
We know that the Height of ORNAMENT ( B ) is FIVE (5) Times Larger than the Height of ORNAMENT ( A ). We need to Find the Ratio of their Volumes.
SOLVE THE PROBLEM:1) - Let the height of Ornament ( A ) be hA and the height of Ornament
( B ) be, hB
2) - We know the hB = 5 * hA
3) - Since the Ornaments are Mathematically Similar, Their Volumes are Proportional to the Cube of their heights.
4) - Calculate The Ratio of their Volumes:
(hB )^3 / (hA )^3 (5 * hA )^3 / (hA )^3
Draw the conclusion:Therefore, The Volume of ORNAMENT ( B ) is 5^3 = 125 TIMES LARGER than the VOLUME of ORNAMENT ( A ).
Hence, The VOLUME of ORNAMENT (B) is 125 TIMES LARGER than the VOLUME of ORNAMENT (A).
I hope this helps you!
Alan solved the proportion StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction as shown.
StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction. (8) (x) = (25) (200). 8 x = 5,000. StartFraction 8 x over 8 EndFraction = StartFraction 5,000 over 8 EndFraction. X = 625.
What is Alan’s error?
He got the wrong product when he multiplied 25 by 200.
He got the wrong quotient when he divided 5,000 by 8.
He mixed up the positions of 8 and 25 in the equation (8) (x) = (25) (200).
He mixed up the positions of 8 and 200 in the equation (8) (x) = (25) (200).
The correct answer is that Alan mixed up the positions of 8 and 25 in the equation (8)(x) = (25)(200). This mistake led to incorrect calculations and the wrong answer.
Alan's error lies in mixing up the positions of 8 and 25 in the equation (8)(x) = (25)(200). In the original proportion, the correct equation is (x/200) = (8/25).
However, Alan mistakenly wrote it as (8)(x) = (25)(200), reversing the positions of 8 and 25. This error leads to incorrect calculations and ultimately an incorrect answer of x = 625.
Let's break down Alan's steps to understand his mistake:
StartFraction x over 200 EndFraction = StartFraction 8 over 25 EndFraction.
Alan correctly writes down the proportion.
(8)(x) = (25)(200).
Here is where Alan's error occurs. Instead of multiplying 8 by x and 25 by 200, he mistakenly swaps their positions. This mistake results in incorrect products.
8x = 5,000.
Alan multiplies incorrectly and obtains 5,000 as the product of 25 and 200.
StartFraction 8x over 8 EndFraction = StartFraction 5,000 over 8 EndFraction.
Alan divides both sides of the equation by 8, which is the correct step.
x = 625.
Alan divides 5,000 by 8 to find the value of x, which is his final incorrect answer. So, the correct option is he mixed up the positions of 8 and 25 in the equation (8) (x) = (25) (200).
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A weight is attached to a spring and reaches its equilibrium position (x=0). It is then set in motion resulting in a displacement of x=12 cos t, where x is measured in centimeters and t is measured in seconds. See the figure shown to the right. Answer parts (a) and (b).
a. The spring's displacement when t = 0 is 12 cm.
The spring's displacement when t = π/3 is 6 cm.
The spring's displacement when t= 3π/4 is -6√2 cm.
b. The spring's velocity when t = 0 is 0 cm/sec.
The spring's velocity when t = π/3 is -6√3 cm/sec
The spring's velocity when t= 3π/4 is -6√2 cm/sec.
How to determine the spring's displacement?a. When t = 0, the spring's displacement can be calculated by using the given displacement equation:
x = 12cost
x(0) = 12cos(0)
x(0) = 12 cm.
When t = π/3, the spring's displacement can be calculated by using the given displacement equation:
x = 12cost
x(π/3) = 12cos(π/3)
x(π/3) = 12 × 1/2 = 6 cm.
When t = 3π/4, the spring's displacement can be calculated by using the given displacement equation:
x = 12cost
x(3π/4) = 12cos(3π/4)
x(3π/4) = 12 × -√2/2 = -6√2 cm.
Part b.
In order to determine the spring's velocity, we would have to take the first derivative of the displacement equation with respect to time;
v(t) = dx/dt = -12sint
When t = 0, the spring's velocity can be calculated as follows:
v(0) = -12sin(0)
v(0) = 0 cm/sec.
When t = π/3, the spring's velocity can be calculated as follows:
v(π/3) = -12sin(π/3)
v(π/3) = -6√3 cm/sec.
When t = 3π/4, the spring's velocity can be calculated as follows:
v(3π/4) = -12sin(3π/4)
v(3π/4) = -6√2 cm/sec.
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
1. Solve for x.
(4x + 1)º
47°
Answer:
x = 33
Step-by-step explanation:
(4x + 1)° and 47° lie on a straight line and sum to 180° , that is
4x + 1 + 47 = 180
4x + 48 = 180 ( subtract 48 from both sides )
4x = 132 ( divide both sides by 4 )
x = 33
The value of x is:
x = 33Work/explanation:
The two angles form a linear pair, which means they add to [tex]\sf{180^o}[/tex].
Because they add up to 180, we can set up an equation to find x.
[tex]\sf{4x+1+47=180}[/tex]
Combine like terms on the left side
[tex]\sf{4x+48=180}[/tex]
Subtract 48 on each side
[tex]\sf{4x=132}[/tex]
Divide each side by 4
[tex]\sf{x=33}[/tex]
Hence, x = 33.Cant figure this out,not even for the life of me.
Find f(1) for the
piece-wise function.
f(x) =
2x
NIT
if x < 1
+/ ifx>1
x+
f(1) = [?]
well, f(1) is indicating that x = 1, hmmm for the piecewise, on what section is that?
well, x < 1 is just whenever "x" is less than 1, but not 1.
x ⩾ 1 is whenever "x" is either 1 or greater than 1, so that's our guy, so we use that subfunction to get it.
[tex]f(x)= \begin{cases} 2x&x < 1\\\\ \cfrac{1}{2}x+\cfrac{5}{2}&x\geqslant 1\hspace{3em}\textit{f(1) is in this section} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(1)=\cfrac{1}{2}(1)+\cfrac{5}{2}\implies f(1)=3[/tex]
The graph below shows the percentages of ingredients in a salad mix.
A pie chart titled Percentages in salad mix. 40 percent is iceberg, 27 percent is romaine, 15 percent is spinach, 12 percent is arugula, 6 percent is carrots.
Dominic buys a 64-ounce container of salad mix. About how many ounces of romaine lettuce does the container have?
6 ounces
12 ounces
18 ounces
27 ounces
The correct Option is C. Dominic buys about 18 ounces of romaine lettuce in the 64-ounce container of salad mix.
From the pie chart, we can infer that the percentage of romaine lettuce in the salad mix is 27%.
We can find the number of ounces of romaine lettuce in a 64-ounce container of salad mix by multiplying 64 by 27/100.
This is because we want to find what fraction of the whole salad mix is romaine lettuce, and then multiply it by the total number of ounces in the container.
Using proportions, we can find that:Let x be the number of ounces of romaine lettuce in a 64-ounce container of salad mix.
27/100 = x/64
Solving for x, we get:x = (27/100) * 64 = 18.28
Therefore, there are about 18.28 ounces of romaine lettuce in a 64-ounce container of salad mix.
However, since we are asked to give an approximate answer, we can round this to the nearest whole number, which is 18.
So, Dominic buys about 18 ounces of romaine lettuce in the 64-ounce container of salad mix.
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What would the points be?
The points in the graph of the system of inequalities are:
(-2, 0) --> not a solution.
(5, 0) --> not a solution.
(7, 0) --> not a solution.
(0, 7) --> solution.
What would the points be?Here we can see the graph of a system of inequalities, and there we have the points:
(-2, 0)
(5, 0)
(7, 0)
(0, 7)
You can see that all the points lie on the lines (these are solid lines, meaning that the points on the lines are solutions for the corresponding inequality)
Now, a point is a solution of a system of inequalities only if it solves both of them at the same time.
The only point that is a solution of both inequalities at the same time is point (0, 7).
So the points are:
(-2, 0) --> not a solution.
(5, 0) --> not a solution.
(7, 0) --> not a solution.
(0, 7) --> solution.
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graph the line with slope of 4 and y-intercept 1
The graph of the line y = 4x + 1 is on the graph at the end.
How to graph the line?A linear equation in the slope-intercept form is written as:
y = ax + b
Where a is the slope and b is the intercept of the y-axis.
Here we know that:
slope = 4 ---> a = 4
y-intercept = 1 ---> b = 1
Then our line is:
y = 4x + 1
To graph this we just need two points on the linear equation, that then we can graph and connect with a line.
when x = 0
y = 4*0 + 1 = 1
So we have (0, 1)
when x = 1
y = 4*1 + 1 = 5
So we have (1,5)
With these two points we will get the graph of the line that you can see below.
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Help me pleaseeee. It my math hw you don’t have to do all of them at least do 4 please
Answer:
#5 - [tex]x=-2[/tex]
#6 - [tex]x=-4[/tex]
#7 - [tex]x=2[/tex]
#8 - [tex]x=10[/tex]
Step-by-step explanation:
Solve the following multi-step equations.
#5 - [tex]-10-7x=-3x-2[/tex]
#6 - [tex]-13-4x=x+7[/tex]
#7 - [tex]x-2=10-5x[/tex]
#8 - [tex]3x-1=4x-11[/tex]
[tex]\hrulefill[/tex]
I will use the SCAM method to solve these multi-step equations.
[tex]\mathbb{S}\text{implify each side of the equation} \\\\\\\mathbb{C}\text{ombine like terms, collect variables on one side }\\\\\\\mathbb{A}\text{dd and/or subtract}\\\\\\\mathbb{M}\text{ultiply and/or divide}[/tex]
What is our goal when solving equations?
Our goal is to isolate the variable.
Remember when solving equations, whatever you do to one side of the equation you must do to the other. [tex]\hrulefill[/tex]
Now solving #5,
[tex]-10-7x=-3x-2[/tex]
Observing the equation, we notice on either side of the equation we cannot simplify using the distributive property or order of operations ("PEMDAS"). Well will skip to the "C" in SCAM.
Add "7x" to each side of the equation.
[tex]\Longrightarrow -10-7x+7x=-3x-2+7x\\\\\\\Longrightarrow -10=4x-2[/tex]
The variable "x" now appears on one side of the equation. Now we are on the "A" in SCAM.
Add the value of "2" to each side of the equation.
[tex]\Longrightarrow -10+2=4x-2+2\\\\\\\Longrightarrow -8=4x[/tex]
Now on the "M" in SCAM.
Divide both sides of the equation by the value of "4."
[tex]\Longrightarrow \dfrac{-8}{4}=\dfrac{4}{4}x\\\\\\\Longrightarrow -2=x\\\\\\\therefore \boxed{x=-2}[/tex]
Thus, problem #5 is solved.
[tex]\hrulefill[/tex]
For the rest of the problems I will simply show the operations I am doing.
Now solving #6,
[tex]-13-4x=x+7\\\\\\\Longrightarrow -13-4x+4x=x+7+4x\\\\\\\Longrightarrow -13=5x+7\\\\\\\Longrightarrow -13-7=5x+7-7\\\\\\\Longrightarrow -20=5x\\\\\\\Longrightarrow \dfrac{-20}{5}= \dfrac{5}{5}x\\\\\\\Longrightarrow-4=x\\\\\\\therefore \boxed{x=-4}[/tex]
Thus, problem #6 is solved.
[tex]\hrulefill[/tex]
Now solving #7,
[tex]x-2=10-5x\\\\\\\Longrightarrow x-2+5x=10-5x+5x\\\\\\\Longrightarrow 6x-2=10\\\\\\\Longrightarrow 6x-2+2=10+2\\\\\\\Longrightarrow 6x=12\\\\\\\Longrightarrow \dfrac{6}{6}x=\dfrac{12}{6}\\\\\\\therefore \boxed{x=2}[/tex]
Thus, problem #7 is solved.
[tex]\hrulefill[/tex]
Now solving #8,
[tex]3x-1=4x-11\\\\\\\Longrightarrow 3x-1-3x=4x-11-3x\\\\\\\Longrightarrow -1=x-11\\\\\\\Longrightarrow -1+11=x-11+11\\\\\\\Longrightarrow 10=x\\\\\\\therefore \boxed{x=10}[/tex]
Find y' by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentiate.
y=(3-x^2)(x^3-5x+5)
a. Apply the Product Rule. Let u=(3-x^2) and v=(x^3-5x+5).
b. Multiply the factors of the original expression, u and v to produce a sum of simpler terms.
Find y'.
The factors of the original expression, u and v to produce a sum of simpler terms, the derivative of y with respect to x is: y' = -2x⁴ - x² - 10x + 15
Given the expression y = (3 - x²) (x³ - 5x + 5),
We need to find the derivative of y with respect to x.
We can find y' using two methods:
Method 1: Applying the Product RuleIf y = uv, then we know that y' = u'v + uv'Applying this formula to the given expression, We get:
y = (3 - x²) (x³ - 5x + 5)u = (3 - x²) and v = (x³ - 5x + 5)
Differentiating u and v, we get:u' = -2x and v' = 3x² - 5
Substituting these values into the formula for y', we get:
y' = u'v + uv' = (-2x) (x³ - 5x + 5) + (3 - x²) (3x² - 5)
Simplifying this expression, we get:
y' = -2x⁴ + 10x² - 10x - 3x² + 15 = -2x⁴ - x² - 10x + 15
Method 2: Multiplying the Factors to Produce a Sum of Simpler Terms to Differentiate
Expanding the given expression, we get:
y = 3x³ - 15x + 15 - x⁵ + 5x³ - 5x - 3x² + 15x² - 15x
Differentiating this expression, we get: y' = 9x² - 15 + 0 - 5x⁴ + 15x² - 5 - 6x + 30x - 15
Simplifying this expression, we get:
y' = -2x⁴ - x² - 10x + 15
Therefore, the derivative of y with respect to x is:y' = -2x⁴ - x² - 10x + 15
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are these functions. {(2, 3), (1, 3), (5, 3), (2, 6)}
you can approximate e by substituting large values for n into what expression
This method of approximation is derived from the mathematical concept of limits and the definition of the number e as the limit of (1 + 1/n)^n as n approaches infinity. By increasing the value of n, we approach closer and closer to the actual value of e.
To approximate the mathematical constant "e," you can use the expression (1 + 1/n)^n, where n is a large value. As n approaches infinity, this expression converges to the value of e. The larger the value of n, the closer the approximation will be to the actual value of e.
For example, let's substitute a large value, say n = 10,000, into the expression:
Approximation of e ≈ (1 + 1/10,000)^10,000
Calculating this expression, we get an approximation of e as approximately 2.7181459. Although it's not an exact value, it is a close approximation of the mathematical constant.
To use this approximation, choose a large value for "n", such as 10,000 or 100,000, and evaluate the expression (1 + 1/n)^n using a calculator or computer program. The result will be a close approximation of the value of "e". The larger the value of "n", the more accurate the approximation will be.
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[tex] \frac{x}{n} + 2 = w[/tex]
make x the subject
The variable x as the subject of the equation is x = n(w - 2)
How to make x the subject of the equationFrom the question, we have the following parameters that can be used in our computation:
x/n + 2 = w
Subtract 2 frm both sides of the equation
So, we have
x/n = w - 2
Next, we have
x = n(w - 2)
Hence, the solution is x = n(w - 2)
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What is the simplified form of the expression (-3x^2 + x + 5) − (4x^2 − 2x)
The simplified form of the expression (-3x² + x + 5) - (4x² - 2x) is -7x² + 3x + 5.
To simplify the expression (-3x² + x + 5) - (4x² - 2x)
you will have to perform the subtraction of the two polynomials.
This can be done by first removing the brackets by applying the negative sign of the second polynomial.
After removing the brackets, you can combine like terms.
Hence;
(-3x² + x + 5) - (4x² - 2x)
= -3x²+ x + 5 - 4x²+ 2x (applying negative sign)
= -3x² - 4x² + x + 2x + 5 (combining like terms)
= -7x² + 3x + 5
Therefore, the simplified form of the given expression is -7x² + 3x + 5.
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How many 9/4 hours are there in 3/4 hour?
1/3
3
1/4
4
Answer: 1/4
Step-by-step explanation:
Geometry
Answer fast
Answer:
Your correct
Step-by-step explanation:
The transversal,a, creates right angles for line b, c, and d. This they are parallel
please help find g(12)
Answer:
g(12) = 10
Step-by-step explanation:
To find g(12)
here t = 12 and lies in the range 6 ≤ t ≤ 12
so we use g(t) = [tex]\frac{5t}{6}[/tex]
⇒ g(12) = [tex]\frac{5*12}{6}[/tex]
= 5*2
= 10
g(12) = 10
Polygon ABCD with vertices at A(−4, 6), B(−2, 2), C(4, −2), and D(4, 4) is dilated using a scale factor of four fifths to create polygon A′B′C′D′. If the dilation is centered at the origin, determine the vertices of polygon A′B′C′D′.
A′(−3.2, 4.8), B′(−1.6, 1.6), C′(3.2, −1.6), D′(3.2, 3.2)
A′(−16, 24), B′(−8, 8), C′(16, −24), D′(16, 16)
A′(3.2, −4.8), B′(1.6, −1.6), C′(−3.2, 1.6), D′(−3.2, −3.2)
A′(4.5, −3), B′(1.5, −1.5), C′(−1.5, 3), D′(3, 3)
Answer:
A.
Step-by-step explanation:
New x-coordinate = (-4) * (4/5) = -16/5 = -3.2
New y-coordinate = 6 * (4/5) = 24/5 = 4.8
that's the only option with a -3.2 for A
HELP FIND TRIANGLE GRAPH TRANSFORMATION
The triangle after the reflection over the line y = x has image points: (x'k), (5,-2), and (-6,-1). The corresponding preimage points are: (3,4), (4,3), and (-2,5).
The given information describes a triangle undergoing a transformation with a reflection over the line y = x. Let's analyze the preimage and image points to determine the transformation.
Preimage points: (3,4), (4,3), and (-2,5)
Image points: (x'k), (5,-2), and (-6,-1)
Since we know the reflection is over the line y = x, we can determine the image points by swapping the x and y coordinates of the preimage points. Therefore, the reflection can be represented by the transformation: (x, y) -> (y, x).
Applying this transformation to the preimage points, we get the image points as follows:
(3,4) -> (4,3)
(4,3) -> (3,4)
(-2,5) -> (5,-2)
Now we can check if the image points match the given image points:
(4,3) matches (x'k)
(3,4) matches (5,-2)
(5,-2) matches (-6,-1)
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please awnser ASAP i will brainlist
The second coordinate of the given first coordinate is determined as;
f(0) = 1
(1) = 6.06.
What is the second coordinate of the given coordinate?
The second coordinate of the given first coordinate is calculated by applying the following method as follows;
The given function;
F(x) = [tex]4^{1.3x}[/tex]
The value of f(0) is calculated as;
f (0) = [tex]4^{1.3 \times 0}[/tex] = 4⁰ = 1
The value of f(1) is calculated as;.
f (1) = [tex]4^{1.3 \times 1} = 4^{1.3}[/tex] = 6.06
Thus, the second coordinate of the given first coordinate is determined by applying the appropriate substittue of the function as shown above.
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what is the probability that a data value in a normal distribution is between a z-score of 1.65 and a z-score of 2.24? Round your answer to the nearest tenth of a percent.
The probability that a data value in a normal distribution is between a z-score of 1.65 and a z-score of 2.24 is approximately 6.9%.
To calculate the probability, we need to use the standard normal distribution table or a statistical calculator.
Look up the cumulative probability for the lower z-score (1.65):
From the standard normal distribution table or a statistical calculator, we find that the cumulative probability for a z-score of 1.65 is approximately 0.9505.
Look up the cumulative probability for the higher z-score (2.24):
Similarly, the cumulative probability for a z-score of 2.24 is approximately 0.9875.
Calculate the probability between the two z-scores:
To find the probability between the two z-scores, we subtract the cumulative probability of the lower z-score from the cumulative probability of the higher z-score.
Probability = Cumulative probability (Higher z-score) - Cumulative probability (Lower z-score)
Probability = 0.9875 - 0.9505
Probability = 0.037
Convert the probability to a percentage:
Multiply the probability by 100 to express it as a percentage.
Probability (in percentage) = 0.037 × 100
Probability (in percentage) = 3.7%
Rounded to the nearest tenth of a percent, the probability that a data value in a normal distribution is between a z-score of 1.65 and a z-score of 2.24 is approximately 6.9%.
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An investor invested a total of $3,300 in two mutual funds. One fund earned a 4% profit while the other earned 2% profit. If the investors total profit was $94, how much was invested in each mutual fund
Answer:
.04x + .02($3,300 - x) = $94
.04x + $66 - .02x = $94
.02x = $28
x = $1,400 in 4% fund
$3,300 - $1,400 = $1,900 invested in 2% fund
Suppose f is a one-to-one function with the following values. f(−7)f(−2)=−8=5 Which of the following must be true? Select all correct answers. Select all that apply: f−1(−8)=5 f−1(−7)=8 f−1(5)=−2 f−1(−2)=−5 f−1(−8)=−7 f−1(5)=−7
Based on the analysis, the only statement that must be true is: -[tex]f^{(-1)(-8)} = -7[/tex]
How to determine the statement that must be trueGiven that f is a one-to-one function, it implies that it has an inverse function denoted as [tex]f^{(-1)}.[/tex] The inverse function undoes the operation of the original function, such that [tex]f(f^{(-1)(x))} = x[/tex] for any x in the domain.
Now let's analyze the given options:
1. [tex]f^{(-1)(-8)} = 5[/tex]: We cannot determine the truth of this statement based on the given information. It depends on the behavior of the function f and its inverse.
2.[tex]f^{(-1)(-7)} = 8:[/tex] This option contradicts the given information. The value of f(-7) is -8, so the inverse function evaluated at -8 should yield -7, not 8.
3. [tex]f^{(-1)(5)} = -2[/tex]: We cannot determine the truth of this statement based on the given information. It depends on the behavior of the function f and its inverse.
4.[tex]f^{(-1)(-2)} = -5:[/tex]We cannot determine the truth of this statement based on the given information. It depends on the behavior of the function f and its inverse.
5.[tex]f^{(-1)(-8)} = -7:[/tex] This option aligns with the given information. The value of f(-7) is -8, so the inverse function evaluated at -8 should yield -7.
6. [tex]f^{(-1)(5)} = -7:[/tex] We cannot determine the truth of this statement based on the given information. It depends on the behavior of the function f and its inverse.
Based on the analysis, the only statement that must be true is:
[tex]f^{(-1)(-8)} = -7[/tex]
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2. Find x if the mZFED= 1190, mZIED= x+61, and m/FEI= x + 66, is
Answer:
x = - 4
Step-by-step explanation:
∠ FEI and ∠ IED form ∠ FED , that is
∠ FEI + ∠ IED = ∠ FED ( substitute values )
x + 66 + x + 61 = 119
2x + 127 = 119 ( subtract 127 from both sides )
2x = - 8 ( divide both sides by 2 )
x = - 4
Using Company A's calling plan, the cost of an overseas phone call is a $0.85 connection fee plus 28 cents per minute. If the total cost of the call is $14.85, how long is the phone call?
Answer:
50 minutes
Step-by-step explanation:
28 cents = $0.28
Let the call be for x minutes
Total cost = connection fee + x*cost per minute
14.85 = 0.85 + 0.28x
14.85 - 0.85 = 0.28x
0.28x = 14
x = 14/0.28
x = 50
Answer:
50 min
Step-by-step explanation:
Let the call be for x minutes
14.85 = 0.85 + 0.28x
0.28x = 14
x = 14/0.28 = 50
This is the input-output table for the linear function y = 3x. Table_XY Which best describes how the y-values are increasing over each interval? Subtract 10 over each interval. Multiply by 2 over each interval. Add 3 over each interval..
Step-by-step explanation:
Can you provide an image please?
Answer:
C
Step-by-step explanation:
What is 8x6 explain
8 x 6 is 48.
8 x 6 can also be written as eight 6s or six 8s.
So 8 + 8 + 8 + 8 + 8 + 8 or 6 + 6 + 6 + 6 + 6 + 6 + 6 + 6.
Two number in ratio 4:1 sum is 60 find largest number
Answer:
48
Step-by-step explanation:
4 : 1
4 + 1 = 5
60/5 = 12
12 × 4 = 48
12 × 1 = 12
48 : 12 are numbers in a 4:1 ratio and add to 60.
Answer: 48
Answer:
larger # is 48
look at attachment
Step-by-step explanation:
4x+1x=60
Use the equation of the line to identify a point the line passes through and the slope of the line. Then, graph the line.
y+3=1/3(x+3)
The point is (3, 2 1/3).
Given the equation of the line,y + 3 = 1/3(x + 3)
To identify a point the line passes through and the slope of the line, we first need to convert the equation of the line into slope-intercept form.y + 3 = 1/3(x + 3) y = 1/3x + 1
As we can see from the slope-intercept form of the equation, the slope of the line is 1/3.
To graph the line, we need to choose two points on the line and connect them with a straight line.
Let's choose the y-intercept and another point on the line.
The y-intercept is (0,1). To find another point, we can choose x = 3.y = 1/3x + 1y = 1/3(3) + 1y = 2(1/3)
Thus, the point is (3, 2 1/3).
We can now plot these points and connect them with a straight line to get the graph of the line. Graph of the line y + 3 = 1/3(x + 3)
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