Consider points a, b, and c in the graph below. Determine which of these points are relative maxima on the interval x = –4 to x = 0.

A) None of these
B) B
C) a and b
D) c

Consider Points A, B, And C In The Graph Below. Determine Which Of These Points Are Relative Maxima On

Answers

Answer 1

Answer:

c

Step-by-step explanation:

Like I said in my previous answer, you have to look at the point that kinda "pokes out" of the graph, which in the interval (-4,0) is a and b

Answer 2

Answer:

See image.

Step-by-step explanation:

"Relative maxima" just means is this the highest spot in the graph in this very small neighborhood. (that's not a technical term)

On the interval x=-4 to x=0 is like asking you to only consider certain house addresses when you are looking for your answer. See image.

Consider Points A, B, And C In The Graph Below. Determine Which Of These Points Are Relative Maxima On

Related Questions

(1,-19),(-2,-7) finding slope

Answers

Answer:

The slope is -4.

Step-by-step explanation:

Slope(m)=(y2-y1)/(x2-x1)

y2=-7, y1=-19, x2=-2, x1=1

(-7+19)/(-2-1)

=12/-3

=-4

Answer: -4

Step-by-step explanation:

The slope formula is: [tex]y_{2} -y_{1}/x_{2}-x_{1} \\[/tex]

So it is: (-7+19)/(-2-1) = 12/-3 = -4

I hope this helped!

Jean can swim 100 meters in 1.86 minutes. Sean can swim the same distance in 2.12 minutes.

Answers

please where is the question

X

1

2

3

4

P


0,2

0,3

?

0,1

Answers

Rewrite the question plz

Answer:

(0,4)  will be point (P) at 3 because,

Step-by-step explanation:

by using newton interpolation method we can find P(0,4) at 3 .

Walnut High Schools Enrollment is exactly five times as large as the enrollment at walmut junior high the total enrollment for the two schools is 852 what is the enrollment at each school​

Answers

Answer:

142

Step-by-step explanation:

If the enrollment is five times as big, then that is six different things. So, take 852 and divide it by 6 to get 142. Or in other words:

852÷6=142

142x6=856

I hope this helps. Cheers^^

2 6 + 3 * 4 2 + 7 * - 2 /

Answers

Answer:

26 + 3 x 42 + 7 x -2 = 138

Step-by-step explanation:

Ok bud, first step we must convert our symbols (Makes it easier to solve)

26 + 3 x 42 + 7 x -2

* subsitutes for multiplication.

I recommend using PEMDAS at times:

1 - Parentheses

2 - Exponents and Roots

3 - Multiplication

4 - Division

5 - Addition

6 - Subtraction

Yet again your numbers were spaced out could they be exponents? if so:

3x^{42}+7x+24

Our answer would round to 24 but he equation was not put in a valid or straight forward way.

Solve this equation for x. Round your answer to the nearest hundredth.
1 = In(x + 7) ​

Answers

Answer:

[tex]\displaystyle x \approx -4.28[/tex]

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Algebra II

Natural logarithms ln and Euler's number e

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 1 = ln(x + 7)[/tex]

Step 2: Solve for x

[Equality Property] e both sides:                                                                     [tex]\displaystyle e^1 = e^{ln(x + 7)}[/tex]Simplify:                                                                                                             [tex]\displaystyle x + 7 = e[/tex][Equality Property] Isolate x:                                                                            [tex]\displaystyle x = e - 7[/tex]Evaluate:                                                                                                            [tex]\displaystyle x = -4.28172[/tex]

e^1 = x+7

e - 7 = x

x = -4.28

forty-five percent of the students in a dorm are business majors and fifty-five percent are non-business majors. business majors are twice as likely to do their studying at the library as non-business majors are. half of the business majors study at the library. if a randomly slected student from the dorm studies at the library, what is the probability the student is a business major

Answers

Solution :

Defining the following events as :

B : Being a Business major

α : Studying at the library

∴ Given that :

[tex]$P(B) = \frac{45}{100}$[/tex]

         = 0.45

Again, P [ Studying at the library | Being a Business major ] = 2 P [ Studying at the library | Being a non business major ]

[tex]$P[ \alpha | B] = 2 P[\alpha | B^C]$[/tex]   .......(1)

Again,

[tex]$P[\text{Studying at the library } | \text{ Being a business major}] = \frac{1}{2} = 0.50$[/tex]

[tex]$P(\alpha | B) = 0.50$[/tex]

From (1), we get

[tex]$P(\alpha | B^C) = \frac{1}{2} . P(\alpha | B)$[/tex]

              [tex]$=\frac{1}{2} \times 0.50$[/tex]

              = 0.25

Therefore, we need,

= P[  The students is a Business major | The student studies at the library ]

[tex]$=P(B | \alpha)$[/tex]

By Bayes theorem

[tex]$=\frac{P(B). P(\alpha | B)}{P(B).P(\alpha | B) + P(B^C). P(\alpha | B^C)}$[/tex]

[tex]$=\frac{0.45 \times 0.50}{0.45 \times 0.50 + 0.55 \times 0.25}$[/tex]

= 0.6207

What type of number can be written as a fraction

Answers

Answer:

a rational number is a number that can be written as a fraction

I hope this helps

take away 4/5 from 6 1/2​

Answers

Answer:

3-4/5=2.2

hope it helps

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[tex]5\frac{7}{10}[/tex]

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the answer...}}\\\\6\frac{1}{2}-\frac{4}{5} \\-------------\\6\frac{1}{2} = \frac{13}{2} \\\\\frac{13}{2} - \frac{4}{5}\\\\LCM(2,5): 10\\\\\frac{13}{2} =\frac{13*5}{2*5} =\frac{65}{10}\\\\\frac{4}{5}=\frac{4*2}{5*2}=\frac{8}{10}\\\\\frac{65}{10}-\frac{8}{10}\\\\ \frac{57}{10}\\\\\frac{57}{10}\rightarrow\boxed{5\frac{7}{10}}[/tex]

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

What is the equation of a line that passes through the point (8,-2) and is parallel to the line whose equation is 3x+4y=15?

Answers

Answer:

y = -3x/4 + 4

Step-by-step explanation:

slope m = -3/4

-2=(-3/4)×8+b

or, b = 4

y = mx + b

y = -3x/4 + 4

Answered by GAUTHMATH

Solve the following equation for
d
d. Be sure to take into account whether a letter is capitalized or not.

Answers

D=g/2t
Hope this helps

What is the distance from point N to LM in the figure below?
N
8.4
8.1
7.8
O
O A. 3.11
B. 0.8
C. 8.1
D. 2.18
E. 7.8
F. 8.4

Answers

Answer:

the answer to your question is 7.8 (E)

The  distance from point N to LM is 7.8, 8.1 and 8.4 unit.

What is perpendicular?

Perpendicular lines are those that cross at a straight angle to one another. Examples include the opposite sides of a rectangle and the steps of a straight staircase. the icon used to represent two parallel lines.

Perpendicular lines are two separate lines that cross one other at a right angle, or a 90° angle.

Given:

In ΔNOM

The Perpendicular distance is 7.8 unit

and, Hypotenuse distance id 8.1 unit

Now, In ΔNOL

The Perpendicular distance is 7.8 unit

and, Hypotenuse distance id 8.4 unit

Learn more about perpendicular here:

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Find the mean for the amounts: $17.482: $14.987: $13.587$14.500, $18.580. $14.993​

Answers

Answer:

The mean of these numbers is 15.68816 with a repeating 6.

Step-by-step explanation:

CAN SOMEBODY HELP WITH THIS QUESTION ASAP​

Answers

Answer:

The rectangles are not similar

Step-by-step explanation:

In order to check whether they are similar, we need to take the ratio of their similar sides and ensure they are equal to a constant k.

Hence;

AB/PL = AD/LM = k

32/26 = 18/12 = k

16/13 = 9/6 = k

Since the scale factor is not the same, hence the rectangles are not the same.

Simplify tan(arcsec 1)

Answers

Answer:

0

Step-by-step explanation:

Arc sec(1)=0, tan(0)=0

Which function describes this graph

Answers

Answer:

C.

Step-by-step explanation:

A P E X

The job Andrew has this summer paid 7.25 an hour and the job he had last Summer paid 6.50 an hour. how much more does Andrew earn in a 40 hour week this summer than he did in a 40 hour week last summer

Answers

Answer:

30 Dollars more

Step-by-step explanation:

This summer he earned = 7.25 X 40 = 290

Last summer he earned = 6.5 X 40 = 260

How much more he earned in 40 hours = 290-260= 30 dollars more

Answer from Gauthmath

Factorize (256⁴-1).
Use appropriate identity.

Answers

(256⁴-1)

= (256-1)⁴

Using identity (a-b)⁴ = a⁴−4a³b+6a²b²−4ab³+b⁴

Let a be 256 and b be 1

Then

256⁴−4(256)³(1)+6(256)²(1)²−4(256)(1)³+(1)⁴

After solving

(256²-1)²

(a-b)² = a²-2ab+b²

256²-2×256×1+1²

= (256²-1)(256²+1)

Must click thanks and mark brainliest

Answer:

Use identity:

a² - b² = (a + b)(a - b)

Consider that:

256 = 2⁸

Now factorize:

256⁴ - 1 = (2⁸)⁴ - 1 = 2³² - 1 = (2¹⁶ - 1)(2¹⁶ + 1) = (2⁸ - 1)(2⁸ + 1)(2¹⁶ + 1) = (2⁴ - 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1) = (2² - 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1) = (2 - 1)(2 + 1)(2² + 1)(2⁴ + 1)(2⁸ + 1)(2¹⁶ + 1)

A single die is rolled twice. The 36​ equally-likely outcomes are shown to the right. Find the probability of getting two numbers whose sum is 10 .

Answers

Answer:

The probability of getting two numbers whose sum is 10 is 25%.

Step-by-step explanation:

Given that a single die is rolled twice, and there are 36 equally-likely outcomes, to find the probability of getting two numbers whose sum is 10 the following calculation must be performed:

1 = +9

2 = +8

3 = +7

4 = +6

5 = +5

6 = +4

7 = +3

8 = +2

9 = +1

9/36 = 0.25

Therefore, the probability of getting two numbers whose sum is 10 is 25%.

Two coins are tossed. Assume that each event is equally likely to occur. ​a) Use the counting principle to determine the number of sample points in the sample space. ​b) Construct a tree diagram and list the sample space. ​c) Determine the probability that no tails are tossed. ​d) Determine the probability that exactly one tail is tossed. ​e) Determine the probability that two tails are tossed. ​f) Determine the probability that at least one tail is tossed.

Answers

Answer:

(a) 4 sample points

(b) See attachment for tree diagram

(c) The probability that no tail is appeared is 1/4

(d) The probability that exactly 1 tail is appeared is 1/2

(e) The probability that 2 tails are appeared is 1/4

(f) The probability that at least 1 tail appeared is 3/4

Step-by-step explanation:

Given

[tex]Coins = 2[/tex]

Solving (a): Counting principle to determine the number of sample points

We have:

[tex]Coin\ 1 = \{H,T\}[/tex]

[tex]Coin\ 2 = \{H,T\}[/tex]

To determine the sample space using counting principle, we simply pick one outcome in each coin. So, the sample space (S) is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

The number of sample points is:

[tex]n(S) = 4[/tex]

Solving (b): The tree diagram

See attachment for tree diagram

From the tree diagram, the sample space is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

Solving (c): Probability that no tail is appeared

This implies that:

[tex]P(T = 0)[/tex]

From the sample points, we have:

[tex]n(T = 0) = 1[/tex] --- i.e. 1 occurrence where no tail is appeared

So, the probability is:

[tex]P(T = 0) = \frac{n(T = 0)}{n(S)}[/tex]

This gives:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Solving (d): Probability that exactly 1 tail is appeared

This implies that:

[tex]P(T = 1)[/tex]

From the sample points, we have:

[tex]n(T = 1) = 2[/tex] --- i.e. 2 occurrences where exactly 1 tail appeared

So, the probability is:

[tex]P(T = 1) = \frac{n(T = 1)}{n(S)}[/tex]

This gives:

[tex]P(T = 1) = \frac{2}{4}[/tex]

[tex]P(T = 1) = \frac{1}{2}[/tex]

Solving (e): Probability that 2 tails appeared

This implies that:

[tex]P(T = 2)[/tex]

From the sample points, we have:

[tex]n(T = 2) = 1[/tex] --- i.e. 1 occurrences where 2 tails appeared

So, the probability is:

[tex]P(T = 2) = \frac{n(T = 2)}{n(S)}[/tex]

This gives:

[tex]P(T = 2) = \frac{1}{4}[/tex]

Solving (f): Probability that at least 1 tail appeared

This implies that:

[tex]P(T \ge 1)[/tex]

In (c), we have:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Using the complement rule, we have:

[tex]P(T \ge 1) + P(T = 0) = 1[/tex]

Rewrite as:

[tex]P(T \ge 1) = 1-P(T = 0)[/tex]

Substitute known value

[tex]P(T \ge 1) = 1-\frac{1}{4}[/tex]

Take LCM

[tex]P(T \ge 1) = \frac{4-1}{4}[/tex]

[tex]P(T \ge 1) = \frac{3}{4}[/tex]

construct the truth table (p ∧ q) =⇒ [(q ∧ ¬p) =⇒ (r ∧ q)]​

Answers

[tex]\begin{array}{c|c|c|c|c|c} p & q & r & p\land q & q\land \neg p & r \land q \\&&&&\\ T & T & T & T & F & T \\ T & T & F & T & F & F \\ T & F & T & F & F & F \\ T & F & F & F & F & F \\ F & T & T & F & T & T \\ F & T & F & F & T & F \\ F & F & T & F & F & F \\ F & F & F & F & F & F\end{array}[/tex]

An implication A => B is true if either A is false, or both A and B are true. So

[tex]\begin{array}{c|c|c}p\land q & (q\land\neg p) \implies (r\land q) & (p\land q) \implies \big[(q\land\neg p) \implies (r\land q)\big] \\&&\\T & T & \mathbf T\\T & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\\F & F & \mathbf T\\F & T & \mathbf T\\F & T & \mathbf T\end{array}[/tex]

and the given statement is a tautology.

HELP NEEDED PLEASE :(
Identify the center and the radius of a circle that has a diameter with endpoints at (5, 8)
and (7,6).

Answers

Answer:

Centre is,

((5+7)/2,(8+6)/2)

or, (12/2,14/2)

or, (6,7)

radius is,

[√{(5-7)²+(8-6)²}]/2

= [√(2²+2²)]/2

= [√(4+4)]/2

= [√8 ]= [2√2]/2 = √2

The center of a circle = (6, 7)

the radius of a circle = [tex]\sqrt{2}[/tex] units

What is the distance formula?

"The distance between two points [tex](x_1,y_1),(x_2,y_2)[/tex] is given by  [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2}[/tex]"

What is midpoint formula?

"The coordinates of the midpoint of the line segment having endpoints [tex](x_1,y_1),(x_2,y_2)[/tex] is given by [tex]m=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex] "

What is diameter of circle?

"It is the line segment through the center and touching two points on its edge. "

For given question,

The diameter of circle has endpoints at (5, 8) and (7,6).

Let [tex](x_1,y_1)=(5,8),(x_2,y_2)=(7,6)[/tex]

First we find the length of the diameter of the circle.

Using the distance formula,

[tex]\Rightarrow d=\sqrt{(x_2-x_1)^2+(y_2-y_2)^2} \\\\\Rightarrow d=\sqrt{(7-5)^2+(6-8)^2} \\\\\Rightarrow d=\sqrt{2^2+(-2)^2}\\\\\Rightarrow d=\sqrt{4+4}\\\\\Rightarrow d=2\sqrt{2}~units[/tex]

We know that the diameter = 2 × radius

⇒ radius (r) = [tex]\frac{2\sqrt{2} }{2}[/tex]

⇒ r = [tex]\sqrt{2}[/tex] units

We know that the midpoint of the diameter is the center of the circle.

Using midpoint formula the center of the circle would be,

[tex]\Rightarrow O=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\\\\Rightarrow O=(\frac{5+7}{2} ,\frac{8+6}{2} )\\\\\Rightarrow O=(\frac{12}{2} ,\frac{14}{2} )\\\\\Rightarrow O=(6,7)[/tex]

Therefore, the center of the circle is (6,7)

Hence, the center of a circle = (6, 7)

the radius of a circle = [tex]\sqrt{2}[/tex]

Learn more about the distance formula and mid-point formula here:

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please give me correct answer


by picture​

Answers

Answer:

hello,

a) answer: 600

b) answer: 840

Step-by-step explanation:

a)

20=2²*5,25=5²,30=2*3*5,40=2³*5

l.c.m(20,25,30,40)=2³*3*5²=8*3*25=800

b)

24=2³*3, 42=2*3*7,35=5*7

l.c.m=(24,42,35)=2³*3*5*7=840

What is the equation of a circle with a center at (4, -9) and a radius of 5?

Answers

Answer:

(x - 4)² + (y + 9)² = 25

Step-by-step explanation:

The equation of a circle is written as seen below.

(x – h)² + (y – k)² = r²

Where (h,k) represents the center of the circle and r represents the radius

We want to find the equation of a circle that has a center at (4,-9) and a radius of 5.

We know that (h,k) represents the center so h = 4 and k = -9

We also know that r represents the radius so r = 5

Now to find the equation of this specific circle we simply plug in these values into the equation of a circle formula

Equation: (x – h)² + (y – k)² = r²

h = 4, k = -9 and r = 5

Plug in values

(x - 4)² + (y - (-9))² = 5²

5² = 25

The two negative signs in front of the 9 cancel out and it changes to + 9

The equation of a circle with a center at (4,-9) and a radius of 5 is

(x - 4)² + (y + 9)² = 25

find b for (b-1)/4=(7b+2)/12

Answers

Answer:

-1.25

Step-by-step explanation:

you first have to cross multiply

12(b-1)=4(7b+2)

12b-12=28b+8

group the like terms

12b-28b=8+12

-16b/-16=20/-16

b= -1.25

I hope it helps

Step-by-step explanation:

Answer is in the picture..

hope it helps

An urn contains 12 balls, five of which are red. Selection of a red ball is desired and is therefore considered to be a success. If three balls are selected, what is the expected value of the distribution of the number of selected red balls

Answers

The expected value of the distribution of the number of selected red balls is 0.795.

What is the expected value?

The expected value of the distribution is the mean or average of the possible outcomes.

There are 12 balls in an urn, five of which are crimson. The selection of a red ball is desired and hence considered a success.

In this case, the possible outcomes are 0, 1, 2, or 3 red balls.

To calculate the expected value, we need to find the probability of each outcome and multiply it by the value of the outcome.

The probability of selecting 0 red balls is :

[tex]$\frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$[/tex].

The probability of selecting 1 red ball is :

[tex]$3 \cdot \frac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + 3 \cdot \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{315}{660}$[/tex].

The probability of selecting 2 red balls is

[tex]:$\dfrac{5}{12} \cdot \frac{7}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{5}{11} \cdot \frac{6}{10} + \frac{7}{12} \cdot \frac{6}{11} \cdot \frac{5}{10} = \frac{105}{660}$.[/tex]

The probability of selecting 3 red balls is

[tex]$\dfrac{5}{12} \cdot \frac{4}{11} \cdot \frac{3}{10} = \frac{15}{660}$[/tex]

The expected value is then :

[tex]$0 \cdot \frac{105}{660} + 1 \cdot \frac{315}{660} + 2 \cdot \frac{105}{660} + 3 \cdot \frac{15}{660} = \frac{525}{660} = \frac{175}{220} \approx \boxed{0.795}$[/tex]

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What are the domain and range of f(x) = |x + 6|?

Answers

9514 1404 393

Answer:

domain: all real numbersrange: y ≥ 0

Step-by-step explanation:

The function is defined for all values of x, so its domain is all real numbers.

The function can produce values of f(x) that are 0 or greater, so its range is ...

  y ≥ 0

Algebra word problem plz help me​

Answers

Step-by-step explanation:

here's the answer to your question

Put the following equation of a line into slope-intercept form, simplifying all
fractions.
12x - 3y = 15


Help pls

Answers

Answer:

Pretty sure its y=4x-5 hope it helped

Step-by-step explanation:

a figure skating school offers introductory lessons at $25 per session. There is also a registration fee of $30

Answers

Answer:

Part A: y = 25x + 30

Part B: $180

Step-by-step explanation:

for part A, 25 is the constant so that goes with the x, and you just add 30 because it is the extra fee. slope intercept form is y = mx + b

for part B you just plug 6 into the slope intercept equation

y = 25(6) + 30

y = 150 + 30

y = 180

$180

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