Consider the addition of an electron to the following atoms from the third period. Rank the atoms in order from the most negative to the least negative electron affinity values based on their electron configurations.
Atom or ion Electron configuration
Br 1s22s22p63s23p64s23d104p5
Ge 1s22s22p63s23p64s23d104p2
Kr 1s22s22p63s23p64s23d104p6

Answer:

[tex]m_{precipitated}=24.8g[/tex]

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

[tex]m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g[/tex]

Best regards.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is [tex]K_c = 14.39[/tex]

Explanation:

The chemical equation for this decomposition of ammonia is

                [tex]2 NH_3[/tex]  ↔   [tex]N_2 + 3 H_2[/tex]

The initial concentration of ammonia is mathematically represented a

          [tex][NH_3] = \frac{n_1}{V_1} = \frac{29}{75}[/tex]

          [tex][NH_3] = 0.387 \ M[/tex]

The initial concentration of nitrogen gas  is mathematically represented a

         [tex][N_2] = \frac{n_2}{V_2}[/tex]

         [tex][N_2] = 0.173 \ M[/tex]

So  looking at the equation

   Initially (Before reaction)

      [tex]NH_3 = 0.387 \ M[/tex]

      [tex]N_2 = 0 \ M[/tex]

      [tex]H_2 = 0 \ M[/tex]

During reaction(this is gotten from the reaction equation )

        [tex]NH_3 = -2 x[/tex](this implies that it losses two moles of concentration )

         [tex]N_2 = + x[/tex]  (this implies that it gains 1 moles)

         [tex]H_2 = +3 x[/tex](this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

        [tex]NH_3 = 0.387 -2x[/tex]

       [tex]N_2 = x[/tex]

        [tex]H_2 = 3 x[/tex]

Now since

     [tex][NH_3] = 0.387 \ M[/tex]

     [tex]x= 0.387 \ M[/tex]    

[tex]H_2 = 3 * 0.173[/tex]    

[tex]H_2 = 0.519 \ M[/tex]    

[tex]NH_3 = 0.387 -2(0.173)[/tex]

[tex]NH_3 = 0.041 \ M[/tex]

Now the equilibrium constant is

           [tex]K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}[/tex]

substituting values

           [tex]K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}[/tex]

           [tex]K_c = 14.39[/tex]

Answer:

a. Put a piece of fresh sliced yam with a bore into it into the soup.

Explanation:

b. Osmosis may occur

The chef can put a slice of yam in the soup with a hole in it as it will absorb excess of salt by process of diffusion.

Diffusion is defined as the process of movement of molecules which takes place under concentration gradient. It helps in movement of substances in and out from the cell.The molecules move from lower concentration region to a higher concentration region till the concentration becomes equal.

There are 2 main types of diffusion:

1) simple diffusion-process in which substances move through a semi-permeable membrane without the aid of transport proteins.

2) facilitated diffusion- It is a passive movement of molecules across cell membrane from higher concentration region to lower concentration.

There are 2 types of facilitated diffusion one is osmosis and dialysis.

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Answer: The molecular formula for the carcinogenic form of asbestos [tex]Mg_3Si_2H_4O_9[/tex]

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Mg = 26.31 g

Mass of Si= 20.20 g

Mass of H= 1.45 g

Mass of O= (100-(26.31+ 20.20+ 1.45)) =  52.04 g

Step 1 : convert given masses into moles

Moles of Mg=[tex]\frac{\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac{26.31g}{24g/mole}=1.10moles[/tex]

Moles of Si=[tex]\frac{\text{ given mass of Si}}{\text{ molar mass of Si}}= \frac{20.20g}{28g/mole}=0.72moles[/tex]

Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.45g}{1g/mole}=1.45moles[/tex]

Moles of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{52.04g}{16g/mole}=3.25moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = [tex]\frac{1.10}{0.72}=1.5[/tex]

For Si =[tex]\frac{0.72}{0.72}=1[/tex]

For H=[tex]\frac{1.45}{0.72}=2[/tex]

For O =[tex]\frac{3.25}{0.72}=4.5[/tex]

The ratio of  Mg : Si: H: O = 1.5 : 1 : 2 : 4.5

Converting them into whole numbers :

The ratio of  Mg : Si: H: O = 3 : 2 : 4 : 9

Hence the empirical formula is [tex]Mg_3Si_2H_4O_9[/tex]

Empirical mass =[tex]3\times 24+2\times 28+4\times 1+9\times 16=276g[/tex]

Molecular mass = 277 g

[tex]n= \frac{\text {Molecular mass}}{\text {Empirical mass}}=\frac{277}{276}=1[/tex]

Thus molecular formula =[tex]1\times Mg_3Si_2H_4O_9=Mg_3Si_2H_4O_9[/tex]

Answer:

  1703 mmHg

Explanation:

Volume and pressure are presumed to be inversely proportional. Hence a change in volume by a factor of 125/325 = 5/13 is expected to change the pressure by a factor of 13/5:

  (13/5)(655 mmHg) = 1703 mmHg

Answer:

[tex]n_N=0.041molN[/tex]

Explanation:

Hello,

In this case, for this mole-mass relationship, we are able to compute the moles of nitrogen atoms by firstly obtaining the moles of the given compound, considering its molar mass that is 194 g/mol:

[tex]n_{C_8H_{10}O_2N_4}=2.0gC_8H_{10}O_2N_4*\frac{1molC_8H_{10}O_2N_4}{194gC_8H_{10}O_2N_4} =0.01molC_8H_{10}O_2N_4[/tex]

Then, by knowing that one mole of the given compound has four moles of nitrogen atoms, we apply the following relationship:

[tex]n_N=0.01molC_8H_{10}O_2N_4*\frac{4molN}{1molC_8H_{10}O_2N_4} \\\\n_N=0.041molN[/tex]

Best regards.

Answer:

- Four for iron, three for oxygen and 2 for iron (III) oxide:

[tex]4Fe+3O_2\rightarrow 2Fe_2O_3[/tex]

Explanation:

Hello,

In this case, the oxidation of iron is a widely acknowledged reaction occurring in ships and other machines exposed to the air or highly oxidizing medias. Thus, by the effect of oxygen, iron undergoes oxidation typically to iron (III) oxide:

[tex]Fe+O_2\rightarrow Fe_2O_3[/tex]

Nonetheless, the law of conservation of mass must be respected, therefore the coefficients balancing the reaction are four for iron, three for oxygen and 2 for iron (III) oxide:

[tex]4Fe+3O_2\rightarrow 2Fe_2O_3[/tex]

Best regards.

Answer:

water stored in a dam

Explanation:

when the water is in dam it is ready to move bit is not moving

Answer:

I am not sure, but I think this is the answer 72.987 g/mol

Answer:

The correct answer is ice cold isopropanol.

Explanation:

Any compound in the initial stage is first dissolved in any suitable solvent and is heated for a certain duration for the process of recrystallization. Afterward, the compound is kept at room temperature so that it gets cooled gradually. In the process, the impurities remain dissolved in the solvent and the pure compound gets separated in the form of a precipitate.  

Post all this, the filtration of the pure compound is done and is then washed with the cold solvent, which was initially used to dissolve the compound. Therefore, the appropriate solvent to use in the process is ice-cold isopropanol.  

Answer: Transpiration---A

Explanation: Transpiration is the process in the water cycle whereby plant loose(excess) water by evaporation through the stomata of their leaves since not all water absorbed by the root is actually used for growth in plants.In order to allow the intake of carbon-dioxide, water must exit the leaves through transpiration which then  provides the plant with cooling, rigidity and maintaining the overall water balance of the plant.

Answer:

a) ammonium ion

b) amide ion

Explanation:

The order of decreasing bond angles of the three nitrogen species; ammonium ion, ammonia and amide ion is NH4+ >NH3> NH2-. Next we need to rationalize this order of decreasing bond angles from the valence shell electron pair repulsion (VSEPR) theory perspective.

First we must realize that all three nitrogen species contain a central sp3 hybridized carbon atom. This means that a tetrahedral geometry is ideally expected. Recall that the presence of lone pairs distorts molecular structures from the expected geometry based on VSEPR theory.

The amide ion contains two lone pairs of electrons. Remember that the presence of lone pairs causes greater repulsion than bond pairs on the outermost shell of the central atom. Hence, the amide ion has the least H-N-H bond angle of about 105°.

The ammonia molecule contains one lone pair, the repulsion caused by one lone pair is definitely bless than that caused by two lone pairs of electrons hence the bond angle of the H-N-H bond in ammonia is 107°.

The ammonium ion contains four bond pairs and no lone pair of electrons on the outermost nitrogen atom. Hence we expect a perfect tetrahedron with bond angle of 109°.

Answer:

The correct answer is Option A (There is no magnetic flux through the wire loop.)

Explanation:

Magnetic flux measures the entire magnetic field that passes through the wire loop.

The right hand rule can be demonstrated on how magnetic flux is generated through the moving current in the wire loop. The magnetic flux through the wire loop  will decrease as it moves upward through the magnetic field region.

If the direction of the vector area of the wire loop is to the right, and the switch is closed, it will push the magnetic flux to the right which will now be increased due to an equal increase in the current in the wire loop. But, when the switch is open, this will halt the movement of current through the wire loop thus affecting the generation of magnetic field. This would make the magnetic flux to be zero.

The statement related to the magnetic flux is option A i.e. no magnetic flux is there.

It determined the overall magnetic field that should be passed via the looping of the wire. here the right-hand rule represent how the magnetic flux should be created via the movement of the current.

Also, it should be decreased in the case when it should be moved upward. Also, in the case when the direction of the vector area should be right so the switch should be closed.

Therefore, the option A is correct.

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Answer:

saturated

Explanation:

Answer:

Grams , centimeters cubed, and grams per centimeter

Explanation:

Answer:

This water has a level acceptable, 0.1359ppm and 135.9ppb.

Explanation:

1.40g of Cl⁻ are:

1.40g Cl⁻ × (1000mg / 1g) = 1400mg Cl⁻

In 1.03x10⁴L:

1400mg / 1.03x10⁴L = 0.1359mg/L.

As the upper limit of Cl⁻ in water is 250mg/L, this water has a level acceptable

ppm are the ratio between mg of solute and liters of solution, that means the tank contains 0.1359mg/L = 0.1359ppm

ppb, parts per billion are 1000 times ppm, thus, parts per billion of the storage tank are:

0.1359ppm × 1000 = 135.9ppb

Explanation:

A Bronsted-Lowry base is a substance that accepts a proton in the form of a hydrogen (H) atom.

On the other hand;

Bronsted-Lowry acid is the substance that donates the proton.

HF (aq) + SO32- ⇌ F- + HSO3-

In the forward reaction;

Bronsted-Lowry acid : HF

Bronsted-Lowry base: SO32-

In the backward reaction;

Bronsted-Lowry acid : HSO3-

Bronsted-Lowry base: F-

The conjugate base of HF is F-

The conjugate acid of SO32- is HSO3-

Answer:

3–bromo–5–chloro–4–methylhexane.

Explanation:

To name the compound given in the question, the following must be observed:

1. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest chain is carbon 6 i.e Hexane.

2. Identify the substituents attached. In this case the substituents attached are:

a. Chloro i.e Cl.

b. Bromo ie Br.

c. Methyl i.e CH3.

3. Give the substituents the lowest possible count alphabetically. Bromo comes before Chloro alphabetically, so we shall consider bromo first. Their positions are given below:

Bromo i.e Br at carbon 3

Chloro i.e Cl is at carbon 5

Methyl i.e CH3 is at carbon 4

4. Combine the above to get the name of the compound.

Therefore, the name of the compound is:

3–bromo–5–chloro–4–methylhexane.

Answer:

A .    [tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

B.   [tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

C.  The system is at steady state but not at equilibrium

Explanation:

Given that:

The volumetric flow rate of the water = 15 gallons per minute

The diameter of the pipe that leaves the pump is 1 inch.

A. The objective here is  to determine how much work flow is done by the water as it leaves the pump and enters the pipe

The work flow that is said to be done can  be expressed by the relation :

W = P × V

where;

P = pressure

V = volume

Also the given outlet pressure is the gauge pressure

The pressure in the pump P  is can now be expressed by the relation:

[tex]P_{absolute} = P_{guage} + P_{atmospheric}[/tex]

[tex]P_{absolute}[/tex] =  10 psig + 14.7 psig

[tex]P_{absolute}[/tex] =  24.7 psig

W =  P × V

W =  24.7 psig  ×  15 gal/min

[tex]W = (24.7 \ psig * \dfrac{\frac{lb_f}{in^2}}{psig}) * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})[/tex]

[tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

Thus ; the rate of flow of work is said to be done by the water at [tex]\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }[/tex]

B.

Given that :

The water returns to the pool through an opening that is 1.5 inches in diameter.

where the pressure is 1 atm.

Then ; the rate of work done  by the water as it leaves the pipe and enter the pool is as follows:

W =  P × V

W = 1 atm  ×  15 gal/min

[tex]W = 1 \ atm * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})[/tex]

[tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

Thus ; the rate of flow of work done by the water leaving the pipe and enters into the pool is  at [tex]\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }[/tex]

C.

We can consider the system to be at steady state due to the fact that; the data given for the flow rate and pressure doesn't reflect upon the change in time in the space between the pump and the pool.

On the other-hand the integral factor why the system is not at equilibrium is that :

the pressure leaving the pipe is different from that of the water at the surface of the pool as stated in the question.

Answer:

Manganese(II) phosphate | Mn3(PO4)2 - PubChem

Answer:

Magnese(ll) posphate M23 (p042) Molecular weight.

That is what the leters stand for!

Answer:

5

Explanation:

Answer:

5

Explanation:

Answer:

Hydrogen peroxide is ans

Answer:

B. Their productive organisms play a major role in nutrient recycling.

Explanation:

Coral reefs contain photosynthetic algae that help coral reefs in processing nutrients and contribute in the nutrient cycle.

The process of photosynthesis in corals leads to carbon fixing in which corals transform, carbon dioxide, into organic carbon.  carbon fixing property allows corals to become primary producers.

Dissolve organic matter produced by corals is consumed by several organisms such as crabs, worms, fish, and snails.

Hence, coral reefs maintain the flow of energy and nutrient cycle in the biosphere and the correct option is B.

Answer:

It is the portion of internal energy that can be transferred from one substance to another.

Thermal energy is the portion of internal energy that can be transferred from one substance to another.

Thermal energy is the energy an object posses which is as a result of particles movement within it.

It is also the internal energy system in a state of thermodynamic equilibrium which is as a result of its temperature. Thermal energy cannot be concert to useful work easily.

Therefore, thermal energy is the portion of internal energy that can be transferred from one substance to another.

Learn more about thermal energy from the link below.

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Answer:

The brain

Explanation:

With all those instructions the body recqures to respond to it must be so

Hope it helps

Answer:

0.5 mole

Explanation:

The question isn't even clear

But I'm guessing you want to ask the number of moles

n= Number of molecules/ Avogadros number

n= 1/2

Answer:

1. density = 0.89 g/cm3

2. Yes is possible to identify the liquid

3. ethanolamine

Explanation:

Data:

mass = 682 g

volume = 0.767 L = 767 mL or cm3

1.

To calculate the density of the liquid it is necessary to know that the density formula is:

[tex]density=\frac{mass(g)}{volume(cm^{3}) }[/tex]

The data obtained is replaced in the formula:

[tex]density=\frac{682g)}{767(cm^{3}) }=0.89\frac{g}{cm^{3} }[/tex]

2.

With the given data it is possible to identify the liquid, this because the density value is a basic property of each liquid.

3.

It is possible to determine what liquid it is, since when comparing the value obtained with those reported in the collection of Material Safety Data Sheets (MSOS), the value that agrees is that of ethanolamine.

Answer:

Around 3.62 degrees kelvin

Explanation:

Assuming this is at STP:

The first step is to convert 2600mL to liters. There are 1000 milliliters in a liter, meaning that this is equal to 2.6L.

Now:

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\\\\\dfrac{196(1)}{273}=\dfrac{2.6(1)}{T_2} \\\\\\T_2\approx 3.62K[/tex]

Hope this helps!

Answer:

Explanation:

Condensation is the word you seek.

Answer:

Condensation

Explanation:

When a gas is subjected to decrease in temperature it is condensed