Consider the following dice game, as played at a certain gambling casino: players 1 and 2 roll a pair of dice in turn. the bank then rolls the dice to determine the outcome according to the following rule: player i,i=1,2, wins if his roll is strictly


Ii={1 if i wins, 0 otherwise}


and show that I1 and I2 are positively correlated. Explain why this result was to be expected.

Answers

Answer 1

Answer:

they are positively correlated.

Step-by-step explanation:

We can calculate the individal expectations first. FIrst player will win if that player's roll is greater than the bank's roll. There are (6 possible rolls of player 1 * 6 possible rolls of bank =) 36 total possible rolls, out of which player 1 will win in 15 cases.

[tex]\therefore E(I_i) = 1\cdot \frac{15}{36} + 0 \cdot \frac{21}{36} = \frac{5}{12} \approx 0.4167[/tex]

For the joint expectation, there are (6 possible rolls of player 1 * 6 possible rolls of player 2 * 6 possible rolls of bank =) 216 total possible rolls.

Cases where both players win: Expectation = $2.

If bank rolls 1, both players will win in 5*5 = 25 cases. P1 is one of {2,3,4,5,6}, P2 is one of {2,3,4,5,6}

If bank rolls 2, both players will win in 4*4 = 16 cases.

If bank rolls 3, both players will win in 3*3 = 9 cases.

If bank rolls 4, both players will win in 2*2 = 4 cases.

If bank rolls 5, both players will win in 1*1 = 1 cases.

If bank rolls 6, both players will win in 0*0 = 0 cases.

Total cases = 25+16+9+4+1+0 = 55 cases.

Cases where player 1 wins $1 and player 2 loses: Expectation = $1.

If bank rolls 1, player 1 will win and player 2 will lose in 5*1 = 5 cases. P1 is one of {2,3,4,5,6}, P2 is {1}

If bank rolls 2, player 1 will win and player 2 will lose in 4*2 = 8 cases.

If bank rolls 3, player 1 will win and player 2 will lose in 3*3 = 9 cases.

If bank rolls 4, player 1 will win and player 2 will lose in 2*4 = 8 cases.

If bank rolls 5, player 1 will win and player 2 will lose in 1*5 = 5 cases.

If bank rolls 6, player 1 will win and player 2 will lose in 0*6 = 0 cases.

Total cases = 5+8+9+8+5+0 = 35

Cases where player 2 wins $1 and player 1 loses: Expectation = $1.

This is the same as above with player 1 and 2 exchanged.

Total cases = 35

Cases where both players lose: Expectation = $0.

If bank rolls 1, both players will lose in 1*1 = 1 cases. P1 is {1}, P2 is {1}

If bank rolls 2, both players will lose in 2*2 = 4 cases.

If bank rolls 3, both players will lose in 3*3 = 9 cases.

If bank rolls 4, both players will lose in 4*4 = 16 cases.

If bank rolls 5, both players will lose in 5*5 = 25 cases.

If bank rolls 6, both players will lose in 6*6 = 36 cases.

Total cases = 1+4+9+16+25+36 = 91 cases.

Total of all cases (we expect this to be 216 as mentioned above) = 55+35+35+91=216

So, joint expectation is:

[tex]E(I_1I_2) = \frac{2\cdot 55 +1\cdot 35+1\cdot 35+0\cdot 91}{216} = \frac{180}{216}= \frac{5}{6} \approx 0.8333[/tex]

So, the covariance is given by:

[tex]\texttt{Cov}(I_1I_2) =E(I_1I_2) -E(I_1)\cdot E(I_2)= \frac{5}{6}-\frac{5}{12}\cdot\frac{5}{12}=\frac{95}{144} \approx 0.6597[/tex]

As this is greater than 0 and closer to 1, they are positively correlated.

The reason why this result is expected is because the same bank roll is being used for both players. So, it is very likely that both players will win if the bank roll is 1 or even 2. Also, it is very likely that both players will lose if the bank roll is 6, 5, or even 4. This shows positive correlation between the events.


Related Questions

lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2:131F2:131 white squash, 3434 yellow squash, and 1010 green squash. Are these data consistent with a 12:3:112:3:1 dominant epistatic model of genetic inheritance( white being dominant)? The null hypothesis for the chi‑square goodness‑of‑fit test is

Answers

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is                

Answer:

The null  hypothesis for the chi-square goodness-of-fit test is :

[tex]\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }[/tex]

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the  chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null  hypothesis for the chi-square goodness-of-fit test is :

[tex]\mathbf{H_o:p_{white} = \frac{12}{16}, p_{yellow} = \frac{3}{16}; p_{green} = \frac{1}{16} }[/tex]

The results of a linear regression are shown below.
y= ax + b
a = -1.15785
b= 139.3171772
r= -0.896557832
r2 = 0.8038159461
Which phrase best describes the relationship between x and y?​

1)Strong Postive Correlation
2)Strong Negative Correlation
3)Weak Positive Correlation
4)Weak Negative Correlation

Answers

Answer:

2) Strong Negative Correlation

Step-by-step explanation:

With the value of r we have both the information about the sign of the relationship and the strength of this relationship.

As the value of r is negative, we can conclude that the correlation between x and y is negative.

Also, as the absolute value of r is close to 1, we can conclude that this relationship is strong.

The strength can also be seen in the value of r2, which is also close to 1, but this value does not give information about the sign.

The value of the slope a, being negative, can also tell us that the relation between x and y is a negative correlation.

What is the point-slope form of a line with slope 3 that contains the point
(2, 1)?

Answers

Answer:

y-1 = 3(x-2)

Step-by-step explanation:

The point slope form of a line is

y-y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

y-1 = 3(x-2)

The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation of 425 dollars and an unknown population mean. A random sample of 22 sociologists is taken and gives a sample mean of 1520 dollars.
Find the margin of error for the confidence interval for the population mean with a 98% confidence level.
z0.10 z0.05 z0.025 z0.01 z0.005
1.282 1.645 1.960 2.326 2.576
You may use a calculator or the common z values above. Round the final answer to two decimal places.

Answers

Answer:

[tex] ME =z_{\alpha/2} \frac{\sigma}{\sqrt{n}}[/tex]

The confidence level is 0.98 and the significance is [tex]\alpha=1-0.98 =0.02[/tex] and [tex]\alpha/2 =0.01[/tex] and the critical value using the table is:

[tex]z_{\alpha/2}= 2.326[/tex]

And replacing we got:

[tex] ME=2.326 \frac{425}{\sqrt{22}}= 210.760\ approx 210.76[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex]\sigma = 425[/tex] represent the population deviation

[tex] n =22[/tex] the sample size

[tex]\bar X =1520[/tex] represent the sample mean

We want to find the margin of error for the confidence interval for the population mean and we know that is given by:

[tex] ME =z_{\alpha/2} \frac{\sigma}{\sqrt{n}}[/tex]

The confidence level is 0.98 and the significance is [tex]\alpha=1-0.98 =0.02[/tex] and [tex]\alpha/2 =0.01[/tex] and the critical value using the table is:

[tex]z_{\alpha/2}= 2.326[/tex]

And replacing we got:

[tex] ME=2.326 \frac{425}{\sqrt{22}}= 210.760\ approx 210.76[/tex]

Gia is painting her wall. 1 liter of paint can cover 10 square metres. She has a rectangular wall that measures 4 metres by 5 meters. How many liters of paint will Gia need to cover her wall?

Answers

Answer:

2 liters of paint.

Step-by-step explanation:

First we nned to know to total area of the wall by using the formula A = lw

A = 4*5 = 20m²

then we given 1 liter cover 10 m², 20 m² = 2 liters of paint.

The lines shown below are perpendicular if the green line has a slope of 3/4 what is the slopes of the red line?

Answers

Answer:

b) -4/3

Step-by-step explanation:

perpendicular lines have slopes that are opposite reciprocals. the opposite of 3/4 is -3/4, and the reciprocal of -3/4 is -4/3. hope this helps!

Answer:

It is -4/3

Step-by-step explanation:

What are the next two numbers in the pattern of numbers 45,15,44,17,40,20,31,25

Answers

Answer:

14, 32

Step-by-step explanation:

45,15,44,17,40,20,31,25

this is combination of 2 series:

45-44-40-31- ?15-17-20-25-?

In the first series we can see the pattern as:

-1, -4, -9 = -1², -2², -3² so next difference must be -4², which is 31- 16= 14

In the second series we can see the pattern as:

2, 3, 5 prime numbers, so next difference must be 7, which is 25+7=32

The series will continue as:

45, 15, 44, 17, 40, 20, 31, 25, 14, 32

x/2 = -5 solve for x

Answers

Answer:

[tex]x=-10[/tex]

Step-by-step explanation:

[tex]\frac{x}{2}=-5\\\mathrm{Multiply\:both\:sides\:by\:}2\\\frac{2x}{2}=2\left(-5\right)\\Simplify\\x=-10[/tex]

pls help it due tomorrow​

Answers

Answer:

Finding 1/5 of something is the same as dividing that number by 5. Since 24 isn't divisible by 5, 24 / 5 is not an integer. Since you can't have 4.8 species of animals the answer to (a) is no.

For (b), 1/3 * 24 = 8 and 24 - 8 = 16.

Quick Start Company makes a 12-volt car batteries. After many years of product testing, the company knows the average life of a Quick Start battery is normally distributed, with mean=45 months and a std. deviation = 8 months.

If Quick start guarantees a full refund on any battery that fails within the 36 month period after purchase, what percentage of its batteries will the company expect to replace?

If quick Start does not want to make refunds for more than 10% ofits batteries under the full refund guarantee policy, for how longshould the company guarantee the batteries (to the nearest month)

Answers

Answer:

The company will expect to replace 13.03% of batteries.

The company should guarantee the batteries for 35 months.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

[tex]\mu = 45, \sigma = 8[/tex]

If Quick start guarantees a full refund on any battery that fails within the 36 month period after purchase, what percentage of its batteries will the company expect to replace?

This is the pvalue of Z when X = 36. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{36 - 45}{8}[/tex]

[tex]Z = -1.125[/tex]

[tex]Z = -1.125[/tex] has a pvalue of 0.1303.

The company will expect to replace 13.03% of batteries.

If quick Start does not want to make refunds for more than 10% ofits batteries under the full refund guarantee policy, for how longshould the company guarantee the batteries

They should guarantee to the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.28 = \frac{X - 45}{8}[/tex]

[tex]X - 45 = -1.28*8[/tex]

[tex]X = 34.76[/tex]

Rounding to the nearest month

The company should guarantee the batteries for 35 months.

According to a report released by CIBC entitled "Women Entrepreneurs: Leading the Charge," the average age for Canadian businesswomen in 2008 was 41. In the report, there was some indication that researchers believed that this mean age will increase. Suppose now, a few years later, business researchers in Canada want to test to determine if, indeed, the mean age of Canadian businesswomen has increased. The researchers randomly sample 97 Canadian businesswomen and ascertain that the sample mean age is 43.4. From past experience, it is known that the population standard deviation is 8.95. Test to determine if the mean age of Canadian businesswomen has increased using a 1% level of significance. What is the p-value for this test? What is the decision? If the null hypothesis is rejected, is the result substantive?

Answers

Answer:

We conclude that the mean age of Canadian businesswomen has increased.

Step-by-step explanation:

We are given that according to a report released by CIBC entitled "Women Entrepreneurs: Leading the Charge," the average age for Canadian businesswomen in 2008 was 41.

The researchers randomly sample 97 Canadian businesswomen and ascertain that the sample mean age is 43.4. From past experience, it is known that the population standard deviation is 8.95.

Let [tex]\mu[/tex] = mean age of Canadian businesswomen.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\leq[/tex] 41      {means that the mean age of Canadian businesswomen has decreased or remained same}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > 41     {means that the mean age of Canadian businesswomen has increased}

The test statistics that would be used here One-sample z-test statistics because we know about population standard deviation;

                               T.S. =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\bar X[/tex] = sample mean age of Canadian businesswomen = 43.4

             [tex]\sigma[/tex] = population standard deviation = 8.95

             n = sample of Canadian businesswomen = 97

So, the test statistics  =  [tex]\frac{43.4-41}{\frac{8.95}{\sqrt{97} } }[/tex]

                                     =  2.64

The value of z test statistic is 2.64.

Also, P-value of the test statistics is given by;

             P-value = P(Z > 2.64) = 1 - P(Z < 2.64)

                           = 1 - 0.99585 = 0.00415

Now, at 1% significance level the z table gives critical value of 2.33 for right-tailed test.

Since our test statistic is more than the critical value of z as 2.64 > 2.33, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean age of Canadian businesswomen has increased.

An intravenous fluid is infused at the rate shown in the table. What is the missing value?
Minutes
Milliliters
3
ܢܚܪ
2.
?
3
9
4
12
3
6
9
24

Answers

Answer:

the answer is 6!!!!!!

Step-by-step explanation:

The missing value in the table is 5

What is Slope of Line?

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

An intravenous fluid is infused at the rate shown in the table

Minutes         Milliliters

3                            4

?                             12

2.                            3

?                             6

3                             9

9                             24

Slope=24-9/9-3

=15/3

=5

Now 5=12-4/x-3

5=8/x-3

5x-15=8

5x=23

x=23/5

x=4.6

x=5

The missing number is 5.

Hence, the missing value in the table is 5

To learn more on slope of line click:

https://brainly.com/question/14511992

#SPJ6

A cereal box has a volume of 225 cubic inches. The length of the base is 9 inches and the width of the base is
2.5 inches. What is the height of the box?​

Answers

Answer:

10

Step-by-step explanation:

First multiply 9 by 2.5

Then divide 225 by 22.5

find the area enclosed by the curve y^2=x^2-x^4

Answers

Answer: 4/3

Step-by-step explanation:

As you know this graph is a lemniscate

[tex]4\int\limits^1_0 {x\sqrt{1-x^{2} } \, dx =\frac{4}{3} =1.33$[/tex]

Plz help. Dora calculated the mean absolute deviation for the data set 35, 16, 23, 42, and 19. Her work is shown below. Step 1: Find the mean. mean = StartFraction 35 + 16 + 23 + 42 + 19 Over 5 EndFraction = 27 Step 2: Find each absolute deviation. 8, 11, 4, 15, 8 Step 3: Find the mean absolute deviation. M A D = StartFraction 8 + 11 + 4 + 15 Over 5 EndFraction = 9.5 What is Dora’s error?

A. Dora should have divided by 4 when finding the mean

B. Dora found the absolute deviation of 35 incorrectly

C. Dora used only four numbers in finding the mean

D. Dora used only four numbers in finding the mean absolute deviation

Answers

Answer:

step 3 is wrong

Step-by-step explanation:

i know it because i did the unit test review

Answer:

D

ヾ(•ω•`)o

Step-by-step explanation:

The table shows the daily sales (in $1000) of shopping mall for some randomly selected days Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 Days 18 27 31 40 56 55 23 Use it to answer questions 13 and 14. 13. What is the approximate value for the modal daily sales? A. $3,129.41 B. $2,629.41 C. $3,079.41 14. The approximate median daily sales is ... A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $3,123.53 D. $2,664.29

Answers

Answer:

Step-by-step explanation:

From the question; we are given the following inclusive frequency distribution information

Class                Frequency f

1.1-1.5                           18

1.6-2.0                         27

2.1-2.5                         31

2.6-3.0                        40

3.1-3.5                         56

3.6-4.0                        55

4.1-4.5                          23

Convert the above inclusive frequency distribution to exclusive frequency distribution with respect of the upper and lower class limit ; we have:

Class                             Frequency f

1.05 - 1.55                             18

1.55 - 2.05                           27

2.05 - 2.55                          31

2.55 - 3.05                          40

3.05 - 3.55                          56

3.55 - 4.05                          55

4.05 - 4.55                          23

Class                             Frequency f                     cf

1.05 - 1.55                             18                              18            

1.55 - 2.05                           27                               45

2.05 - 2.55                          31                               76

2.55 - 3.05                          40                               116

3.05 - 3.55                          56                               172

3.55 - 4.05                          55                               227

4.05 - 4.55                          23                               250

                                       n = 250

To determine the daily sales; we can derive that from estimated Mode by using the relation :

Estimated Mode = L + fm − fm-1(fm − fm-1) + (fm − fm+1) × w

here:

L  = the lower class boundary of the modal group

fm-1 =  the frequency of the group before the modal group

fm = the frequency of the modal group

fm+1 = the frequency of the group after the modal group

w  = the group width

However;

It is easier now to determine  the modal group (i.e the group with the highest frequency), which is 3.05 -3.55

L = 3.05

fm-1 =40

fm =56

fm+1 = 55

w = 0.5

∴[tex]mode = 3.05 + \dfrac{56 - 40 }{(56 - 40) + (56 -55)} * 0.5 \\ \\ mode = 3.05 + 0.4705 \\ \\ mode = 3.5205[/tex]

To find Median Class ; we use the formula;

Median Class = value of (n / 2)th observation

Median Class  = value of (250 / 2)th observation  

Median Class = value of 125th observation

From the column of cumulative frequency cf,

we will see that the 125th observation lies in the class 3.05-3.55.

∴ The median class is 3.05-3.55.

Thus;,  

L=lower boundary point of median class =3.05

n=Total frequency =250

cf=Cumulative frequency of the class preceding the median class =116

f=Frequency of the median class =56

c=class length of median class =0.5

[tex]Median M=L+n2-cff- c \\ \\ =3.05+125-11656⋅0.5 \\ \\=3.05+0.08036 \\ \\ =3.13036[/tex]

hence median sales = $3130.36

3 of 6
As an estimation we are told £3 is €4.
Convert £85.40 to euros.
Give your answer rounded to 2 DP

Answers

Answer:

€113.67

Step-by-step explanation:

£3 = €4

£85.40 is €x

Cross multiply.

[tex]4 \times 85.4=3x[/tex]

[tex]3x=341.6[/tex]

[tex]\frac{3x}{3}=\frac{341.6}{3}[/tex]

[tex]x=113.86666...[/tex]

Angle EFB is 108º

a)Find the size of angle x.


b) which one of these justifies your answer?

A-corresponding angles

B- Alternate angles

C- vertically opposite angles

Answers

Answer:

c of what im sure about

Step-by-step explanation:

Mrs. Brown has 16 children in her first-grade class, and Mr. Lopez has 23 children in his second-grade class. The principal has been asked to select 1 student from one of the classes to appear at a PTA meeting. How many ways can the selection be made?

Answers

Answer: 368 ways

Step-by-step explanation: To find the total number of probabilities, you multiply all the factors together to get total outcome. 16 * 23 = 368

The U.S. Department of Housing and Urban Development publishes data on the fair market monthly rent for existing one-bedroom housing by metropolitan area (The Federal Register, April 30 1997). The standard deviation for the monthly rent is about $80. Assume that a sample of metropolitan areas will be selected in order to estimate the population mean of the monthly rent for existing one-bedroom housing. Use 95% confidence. a. How large should the sample be if the desired margin of error is $25?

Answers

Answer:

[tex]n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247[/tex]

So the answer for this case would be n=247 rounded up to the nearest integer

Step-by-step explanation:

We know that the standard deviation is :

[tex]\sigma = 80[/tex] represent the deviation

The margin of error is given by this formula:

[tex] ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}[/tex]    (a)

And on this case we have that ME =25 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

[tex]n=(\frac{z_{\alpha/2} \sigma}{ME})^2[/tex]   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution and the critical value would be [tex]z_{\alpha/2}=1.960[/tex], replacing into formula (b) we got:

[tex]n=(\frac{1.960(80)}{25})^2 =246.73 \approx 247[/tex]

So the answer for this case would be n=247 rounded up to the nearest integer

7+2x/3=5 im stuck on this question pls hhelp my homework is due soon pls help

Answers

The value of X is 4

please see the attached picture for full solution

Hope it helps

Good luck on your assignment..

2. Students who wish to represent the school at a school board meeting are asked to stop

by the office after lunch. After lunch, 5 students wish to represent the school.

Answers

Answer: Biased sample

Step-by-step explanation:

This is a biased sample because only students with strong opinions are likely going to volunteer or show interest in representing the school at the board meeting. This sample is a voluntary type sample, and at such the conclusion is not valid. This sample is biased because a group or population of students have a higher or lower sampling probability.

Solve 5(2x-3a)+2b=3ax-4, for x

Answers

Answer:

10x-15a

Step-by-step explanation:

so im gna write smthn so jejjxhejxheidjieh uruxueudueususus

Lily paints 3 trees for a wall mural. The middle tree is 2 1/2 ft tall. The tree on the left is 3/4 as tall as the middle tree. The tree on the right is 1 3/4 times as tall as the middle tree. How tall is each tree?

Answers

Answer:

middle is 2.5 ft

right is 4375 ft

left is 1875 ft

Step-by-step explanation:

Solve for y
A)16
B)18
C)22
D) 30
Omg help me I need help, please help me I’m so nice and funny, I can make u laugh, help me freaks I’m big baller

Answers

Answer:

30

Step-by-step explanation:

It is an equalateral triangle

Calculate the surface area of the egg (in μm2). The formula for calculating the surface area (SA) of a sphere is given below. SA = 4Ïr2. Use 3.14 as the value for Ï.

Answers

Answer:

[tex]31400\mu m^2[/tex]

Step-by-step explanation:

We are given that

Diameter of egg,d=[tex]100\mu m[/tex]

We have to find the  surface area of egg in [tex]\mu m^2[/tex].

Radius of egg,r=[tex]\frac{d}{2}=\frac{100}{2}=50\mu m[/tex]

Surface area of sphere=[tex]4\pi r^2[/tex]

Where [tex]\pi=3.14[/tex]

Using the formula

Surface area of egg=[tex]4\times 3.14(50)^2[/tex]

Surface area of egg=[tex]31400\mu m^2[/tex]

Hence, the surface area of the egg=[tex]31400\mu m^2[/tex]

What is the greatest number of right angles a triangle can contain?
A. 0
B. 1
C. 3
D. 2

Answers

The answer is B..........

Answer:

B. 1

Step-by-step explanation:

If it was more than one it wouldn't be a triangle.

Write down the definition of a random sample.

Answers

Answer:

Step-by-step explanation:

Random sampling is a procedure for sampling from a population in which (a) the selection of a sample unit is based on chance and (b) every element of the population has a known, non-zero probability of being selected.

Answer:

A simple random sample is a subset of a statistical population in which each member of the subset has an equal probability of being chosen.

I hope this helped...

A​ four-year study of various brands of bottled water found that 25​% of bottled water is just tap water packaged in a bottle. Consider a sample of sevenseven ​bottled-water brands, and let x equal the number of these brands that use tap water. Complete parts a through d.

a. Is x​ (approximately) a binomial random​ variable?
b. Give the probability distribution for x as a formula.
c. Find p(x = 2).
d. Find P(x <= 1).

Answers

Answer:

Answers below

Step-by-step explanation:

a. Is x​ (approximately) a binomial random​ variable?

b. Give the probability distribution for x as a formula.

c. Find p(x = 2).

d. Find P(x <= 1).

Classify the triangle by its​ sides, and then by its angles.
60 degrees
60 degrees
60 degrees
4 ft
4 ft
4 ft
Classified by its​ sides, the triangle is​ a(n)

equilateral
scalene
isosceles
triangle.
Classified by its​ angles, the triangle is​ a(n)

obtuse
acute
right
triangle.

Answers

Answer:

Equilateral, acute

Step-by-step explanation:

Equilateral triangles have all sides the same length (all sides are 4 ft in this triangle, so it is equilateral).

Acute triangles have no angles that are greater than or equal to 90 degrees (all angles are 60, which is less than 90, so it is acute).

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