The expression z = 5 · (cos 315° + i sin 315°) is the closest to the complex number in polar form 3√2 · (cos 315° + i sin 315°).
How to determine the product of two complex numbers
In this question we need to determine the product of two complex numbers in polar form, that is, two numbers of the following form:
z = r · (cos θ + i sin θ)
Where:
r - Magnitudeθ - DirectionAnd the product of two complex numbers is defined by following expression:
z₁ · z₂ = r₁ · r₂ · [cos (θ₁ + θ₂) + i sin (θ₁ + θ₂)]
First, determine the product of the two complex numbers:
z₁ · z₂ = 3√2 · 1 · [cos (135° + 180°) + i sin (135° + 180°)]
z₁ · z₂ = 3√2 · (cos 315° + i sin 315°)
Second, find the closest choice for the complex number:
z = 5 · (cos 315° + i sin 315°)
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The expression that is closest to the polar form of z w is 4√2 (cos(315°) + i sin(315°)). This is obtained by multiplying the magnitudes and adding the angles of the original complex numbers.
Explanation:The problem asks for the product of two complex numbers in polar form: z = 3√2 (cos(135°) + i sin(135°)) and w = cos(180°) + i sin(180°). When multiplying complex numbers in polar form, you multiply the magnitudes and add the angles. Here, the magnitude 3√2 of z is multiplied by the magnitude 1 of w to get the magnitude of the result. The angle 135° of z is added to the angle 180° of w to get the angle of the result. Thus, the product z w = 3√2 (cos(135°) + i sin(135°)) * (cos(180°) + i sin(180°)) = 3√2 (cos(315°) + i sin(315°)). Hence, the expression that is closest to the polar form of z w is 3√2 (cos(315°) + i sin(315°)). Therefore, the correct option is 4√2 (cos(315°) + i sin(315°)).
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Compute the kernel for each of the following homomorphisms ϕ. (a) ϕ:Z→Z such that ϕ(1)=12 (b) ϕ:Z×Z→Z such that ϕ(1,0)=3 and ϕ(0,1)=6.
The kernel for the homomorphism ϕ: Z → Z with ϕ(1) = 12 is {0} and for the homomorphism ϕ: Z × Z → Z with ϕ(1, 0) = 3 and ϕ(0, 1) = 6 is the set of pairs (a, b) such that a = -2b.
(a) For the homomorphism ϕ: Z → Z such that ϕ(1) = 12, the kernel is the set of integers that map to the identity element in the codomain, which is 0. In other words, the kernel consists of all integers n such that ϕ(n) = 0. To find these integers, we can solve the equation ϕ(n) = 12n = 0. Since 12n = 0 implies n = 0, the kernel of ϕ is {0}.
(b) For the homomorphism ϕ: Z × Z → Z such that ϕ(1, 0) = 3 and ϕ(0, 1) = 6, the kernel is the set of pairs of integers that map to the identity element in the codomain, which is 0. We need to find all pairs (a, b) such that ϕ(a, b) = 0. From the given information, we have 3a + 6b = 0. Dividing both sides by 3, we get a + 2b = 0.
This equation implies that a = -2b. Therefore, the kernel of ϕ is the set of all pairs (a, b) such that a = -2b.
In conclusion, the kernel of the homomorphism ϕ in (a) is {0}, and the kernel of the homomorphism ϕ in (b) is the set of all pairs (a, b) such that a = -2b.
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Calculate the integral of f(z)=sin(z) from z=0 to z=1+i first along the straight line path from z=0 to z=1 then from z=1 to z=1+i. Next calculate the integral of the same function along the straight line path from z=0 to z=1+i. Show that both integrals give the same result.
Comparing this result with the earlier one, we see that both integrals give the same result.
To calculate the integral of f(z) = sin(z) from z=0 to z=1+i first along the straight line path from z=0 to z=1 then from z=1 to z=1+i, we use the additive property of complex integrals. We have:
∫[0,1] sin(z) dz + ∫[1,1+i] sin(z) dz
Along the path from 0 to 1, we parameterize z as z(t) = t for 0 ≤ t ≤ 1. Thus dz/dt = 1 and we get:
∫[0,1] sin(z) dz = ∫[0,1] sin(t) dt = 1 - cos(1)
Along the path from 1 to 1+i, we parameterize z as z(t) = 1 + ti for 0 ≤ t ≤ 1. Thus dz/dt = i and we get:
∫[1,1+i] sin(z) dz = ∫[0,1] sin(1+ti)i dt = i(cos(1) - 1)
Therefore,
∫[0,1] sin(z) dz + ∫[1,1+i] sin(z) dz = (1 - cos(1)) + i(cos(1) - 1)
To calculate the integral of f(z) = sin(z) from z=0 to z=1+i along the straight line path from z=0 to z=1+i directly, we parameterize z as z(t) = ti for 0 ≤ t ≤ 1+i. Thus dz/dt = i and we get:
∫[0,1+i] sin(z) dz = ∫[0,1+i] sin(ti) i dt = i(sin(1+i) - sin(0))
Using the identity sin(a+b) = sin(a)cos(b) + cos(a)sin(b), we can write:
sin(1+i) = sin(1)cos(1) + cos(1)sin(1)i
Thus,
∫[0,1+i] sin(z) dz = i(sin(1)cos(1) + cos(1)sin(1)i) = (cos(1) - 1) + i sin(1)
Comparing this result with the earlier one, we see that both integrals give the same result.
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If your speed s is increased from 30 miles per hour to 35 miles per hour over 30 seconds, what is the rate of change of your speed?
The rate of change of your speed can be calculated by finding the difference between the final speed and the initial speed, and then dividing it by the time taken for the change. In this case, the initial speed is 30 miles per hour, the final speed is 35 miles per hour, and the time taken is 30 seconds.
The rate of change of speed is determined by the formula:
Rate of Change = (Final Speed - Initial Speed) / Time
Substituting the given values into the formula:
Rate of Change = (35 mph - 30 mph) / 30 sec
Simplifying the expression:
Rate of Change = 5 mph / 30 sec
Therefore, the rate of change of your speed is 1/6 miles per hour per second. This means that your speed increases by approximately 1/6 miles per hour every second during the 30-second interval.
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Evaluate (Standard Normal Distribution)
a) P(Z<1. 02)
b) P(Z>1. 98)
c)P(Z>-1. 26)
d) P(Z>-1. 52)
e)P(0. 38
f)P(-0. 91
g)P(-1. 97
h)P(0
a) P(Z<1.02) = 0.8461
b) P(Z>1.98) = 0.0239
c) P(Z>-1.26) = 0.8962
d) P(Z>-1.52) = 0.9357
e) P(Z<0.38) = 0.6497
f) P(Z<-0.91) = 0.1814
g) P(Z<-1.97) = 0.0242
h) P(Z<0) = 0.5
The standard normal distribution is a probability distribution that has a mean of 0 and a standard deviation of 1. It is commonly denoted as Z, and its values represent the number of standard deviations away from the mean.
In part (a), we are asked to find the probability that a random variable from the standard normal distribution is less than 1.02 standard deviations away from the mean. Using a standard normal distribution table or calculator, we find that this probability is 0.8461.
In part (b), we are asked to find the probability that a random variable from the standard normal distribution is greater than 1.98 standard deviations away from the mean. This can be rephrased as finding the probability that a random variable is less than -1.98 standard deviations away from the mean. Again, using a standard normal distribution table or calculator, we find that this probability is 0.0239.
In part (c), we are asked to find the probability that a random variable is greater than -1.26 standard deviations away from the mean. This can be rephrased as finding the probability that a random variable is less than 1.26 standard deviations away from the mean. Using a standard normal distribution table or calculator, we find that this probability is 0.8962.
In part (d), we are asked to find the probability that a random variable is greater than -1.52 standard deviations away from the mean. This can be rephrased as finding the probability that a random variable is less than 1.52 standard deviations away from the mean. Using a standard normal distribution table or calculator, we find that this probability is 0.9357.
In part (e), there seems to be some missing inputs or instructions. If we assume that the question is asking for the probability that a random variable is less than 0.38 standard deviations away from the mean, then using a standard normal distribution table or calculator, we find that this probability is 0.6497.
In part (f), there also seems to be some missing inputs or instructions. If we assume that the question is asking for the probability that a random variable is less than -0.91 standard deviations away from the mean, then using a standard normal distribution table or calculator, we find that this probability is 0.1814.
In part (g), we are asked to find the probability that a random variable is less than -1.97 standard deviations away from the mean. Using a standard normal distribution table or calculator, we find that this probability is 0.0242.
In part (h), we are asked to find the probability that a random variable is less than 0 standard deviations away from the mean, which is simply the probability of getting a value between negative and positive infinity. This probability is equal to 0.5.
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. State the steps in determining the decision and conclusion using z-test and ttest. .
Answer:
see explanation :), It is important to note that the specific steps and procedures may vary depending on the specific context, type of data, and test assumptions. It is recommended to consult appropriate statistical resources or consult with a statistician for the accurate application of the z-test or t-test in a given scenario.
Step-by-step explanation:
Determining the decision and conclusion using a z-test and t-test typically involves the following steps:
1. Formulate the null and alternative hypotheses: Start by stating the null hypothesis (H₀) and the alternative hypothesis (H₁) based on the research question or problem at hand.
2. Select the appropriate test: Determine whether a z-test or t-test is appropriate based on the characteristics of the data and the population under consideration. The choice depends on factors such as sample size, population standard deviation availability, and the assumptions of the test.
3. Set the significance level (α): Determine the desired level of significance or the probability of rejecting the null hypothesis when it is true. Commonly used values for α include 0.05 or 0.01.
4. Calculate the test statistic: For a z-test, calculate the z-score by subtracting the population mean from the sample mean, dividing by the standard deviation, and considering the sample size. For a t-test, calculate the t-value using the appropriate formula based on the type of t-test (e.g., independent samples, paired samples) and the sample data.
5. Determine the critical value: Based on the chosen significance level and the type of test, identify the critical value from the corresponding distribution table (e.g., z-table or t-table).
6. Compare the test statistic and critical value: Compare the calculated test statistic to the critical value. If the test statistic falls in the rejection region (i.e., it is greater than or less than the critical value), then reject the null hypothesis. If the test statistic does not fall in the rejection region, fail to reject the null hypothesis.
7. State the decision: Based on the comparison in the previous step, make a decision regarding the null hypothesis. If the null hypothesis is rejected, it suggests evidence in favor of the alternative hypothesis. If the null hypothesis is not rejected, there is not enough evidence to support the alternative hypothesis.
8. Draw conclusions: Based on the decision, draw conclusions about the research question or problem. Summarize the findings and discuss the implications based on the statistical analysis.
Consider the line in R3 which
goes through the points (1, 2, 5) and (4, −2, 3). Does this line
intersect the sphere with radius 3 centered at (0, 1, 2), and if
so, where?
2. [Intersections] Consider the line in bb{R}^{3} which goes through the points (1,2,5) and (4,-2,3) . Does this line intersect the sphere with radius 3 centered at (0,1,2)
To determine if the line in [tex]R^3[/tex], which goes through the points (1, 2, 5) and (4, -2, 3), intersects the sphere with radius 3 centered at (0, 1, 2), we can find the equation of the line and the equation of the sphere, and then check for their intersection.
1. Equation of the line:
Direction vector = (4, -2, 3) - (1, 2, 5) = (3, -4, -2)
x = 1 + 3t
y = 2 - 4t
z = 5 - 2t
2. Equation of the sphere:
[tex](x - a)^2 + (y - b)^2 + (z - c)^2 = r^2x^2 + (y - 1)^2 + (z - 2)^2 = 3^2[/tex]
3. Finding the intersection:
[tex](1 + 3t)^2 + (2 - 4t - 1)^2 + (5 - 2t - 2)^2 = 9[/tex]
Simplifying the equation:
[tex]9t^2 - 9t - 16 = 0[/tex]
Solving this quadratic equation, we find two values for t: t = 1 and t = -2/3.
Substituting these values:
For t = 1:
x = 1 + 3(1) = 4
y = 2 - 4(1) = -2
z = 5 - 2(1) = 3
For t = -2/3:
x = 1 + 3(-2/3) = -1
y = 2 - 4(-2/3) = 4
z = 5 - 2(-2/3) = 9/3 = 3
Therefore, the line intersects the sphere at the points (4, -2, 3) and (-1, 4, 3).
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Find the lengths of the sides of the triangle
P(7,2,−1),Q(6,0,−2),R(4,1,−3).
|PQ|=
|QR|=
|PR|=
The length of sides of the triangle PQRS is |PQ| = 2.44 (approx) , |QR| = 2.44 (approx) and |PR| = 3.74 (approx)
Given three points in the 3D space as follows:
P(7, 2, −1), Q(6, 0, −2), R(4, 1, −3)
We need to find the length of sides of a triangle PQR triangle in the 3D space is formed by three points.
The length of any side of the triangle is calculated as the distance between the two points that form the side.Using the distance formula, the length of side PQ, QR, and PR is given by
|PQ| = √((x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²)
|PQ| = √((6-7)² + (0-2)² + (-2-(-1))²)
|PQ| = √(1² + (-2)² + (-1)²)
|PQ| = √(1+4+1)
|PQ| = √6|
PQ| = 2.44 (approx)
|QR| = √((x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²)
|QR| = √((4-6)² + (1-0)² + (-3-(-2))²)
|QR| = √((-2)² + 1² + (-1)²)
|QR| = √(4+1+1)
|QR| = √6
|QR| = 2.44 (approx)
|PR| = √((x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²)
|PR| = √((4-7)² + (1-2)² + (-3-(-1))²)
|PR| = √((-3)² + (-1)² + (-2)²)
|PR| = √(9+1+4)
|PR| = √14
|PR| = 3.74 (approx)
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Graph the curves given by the equations below and shade the region that is bounded between them. Integrate with respect to y to determine the area of the region. y^2=2x, and x=y+4.
The area of the region is 77 5/24 square units.
The curves are [tex]y^2=2x[/tex] and [tex]x=y+4.[/tex]
Let us first solve for x in the equation [tex]y^2=2x.[/tex]
So, [tex]x=1/2y^2[/tex], substituting this in the second equation [tex]x=y+4[/tex], we have:
[tex]y+4 = 1/2y^2[/tex]
Simplifying this, we have the quadratic equation: [tex]1/2y^2 - y - 4 = 0[/tex]
Multiplying by 2 throughout, we have[tex]y^2 - 2y - 8 = 0[/tex]
Factoring, we get [tex](y-4)(y+2) = 0[/tex]
So, y=4 or y=-2.
Hence, we have two points of intersection: (4,4) and (-2,-2).
We plot these on a graph: graph
[tex]{y^2=2x [-10, 10, -5, 5]} graph{x=y+4 [-10, 10, -5, 5]}[/tex]
We find the area of the region bounded between the curves by integrating with respect to y.
Since the curves intersect at y=-2 and y=4, we integrate with respect to y between the limits of -2 and 4.
The area, A is given by the integral:
[tex]`A = int_(-2)^4((y+4) - (1/2y^2)) dy` \\= `int_(-2)^4(y+4) dy - int_(-2)^4(1/2y^2) dy`\\= `[y^2/2 + 4y]_(-2)^4 - [(-1/2y)]_(-2)^4` \\= `64/3 + 12 + 1/2 + 1/8` = `77 5/24` square units.[/tex]
Therefore, the area of the region is 77 5/24 square units.
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Consider the differential equation u" + u = 0 on the interval (0,π). What is the dimension of the vector space of solutions which satisfy the homogeneous boundary conditions (a) u(0) = u(π), and (b) u(0) = u(π) = 0. Repeat the question if the interval (0,π) is replaced by (0, 1) and (0,2π).
Interval (0, π) with boundary condition u(0) = u(π):
Dimension of the vector space of solutions: 1.
Interval (0, π) with boundary condition u(0) = u(π) = 0:
Dimension of the vector space of solutions: 0.
Interval (0, 1) with boundary condition u(0) = u(1):
Dimension of the vector space of solutions: 0.
Interval (0, 2π) with boundary condition u(0) = u(2π):
Dimension of the vector space of solutions: 1.
For the differential equation u" + u = 0 on the interval (0, π), we can find the dimension of the vector space of solutions satisfying different homogeneous boundary conditions.
(a) If we have the boundary condition u(0) = u(π), it means that the solution must be periodic with a period of 2π. This condition implies that the solutions will be linear combinations of the sine and cosine functions.
The general solution to the differential equation is u(x) = A cos(x) + B sin(x), where A and B are constants. Since the solutions must satisfy the boundary condition u(0) = u(π), we have:
A cos(0) + B sin(0) = A cos(π) + B sin(π)
A = (-1)^n A
where n is an integer. This implies that A = 0 if n is odd and A can be any value if n is even. Thus, the dimension of the vector space of solutions is 1.
(b) If we impose the boundary condition u(0) = u(π) = 0, it means that the solutions must not only be periodic but also satisfy the additional condition of vanishing at both ends. This condition implies that the solutions will be linear combinations of sine functions only.
The general solution to the differential equation is u(x) = B sin(x). Since the solutions must satisfy the boundary conditions u(0) = u(π) = 0, we have:
B sin(0) = B sin(π) = 0
B = 0
Thus, the only solution satisfying the given boundary conditions is the trivial solution u(x) = 0. In this case, the dimension of the vector space of solutions is 0.
Now, let's consider the differential equation on different intervals:
For the interval (0, 1), the analysis remains the same as in case (b) above, and the dimension of the vector space of solutions with the given boundary conditions will still be 0.
For the interval (0, 2π), the analysis remains the same as in case (a) above, and the dimension of the vector space of solutions with the given boundary conditions will still be 1.
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(Finding constants) For functions f(n)=0.1n 6
−n 3
and g(n)=1000n 2
+500, show that either f(n)=O(g(n)) or g(n)=O(f(n)) by finding specific constants c and n 0
for the following definition of Big-Oh: Definition 1 For two functions h,k:N→R, we say h(n)=O(k(n)) if there exist constants c>0 and n 0
>0 such that 0≤h(n)≤c⋅k(n) for all n≥n 0
.
Given the functions f[tex](n)=0.1n^6−n^3 and$ g(n)=1000n^2+500[/tex]. To prove that either f(n)=O(g(n)) or g(n)=O(f(n)) by finding specific constants c and n0 for Definition 1: h(n)=O(k(n)).
Here, h(n)=f(n) and k(n)=g(n) We know that
[tex]f(n)=0.1n^6−n^3 and$\\ g(n)=1000n^2+500[/tex].
The proof requires to prove that either f(n) <= c g(n) or g(n) <= c f(n) for large n.
To do this, we need to find some constant c and n0 such that either of the two conditions above hold. Let's prove that f(n)=O(g(n)).
For Definition 1, there exist constants c>0 and n0>0 such that 0 ≤ f(n) ≤ cg(n) for all n≥n0, where c and n0 are the constants to be determined.
[tex]f(n)=0.1n^6−n^3\\g(n)=1000n^2+500[/tex]
Now, to prove that
f(n)=O(g(n)) or 0 ≤ f(n) ≤ cg(n),
we need to solve for c and n0 such that:
[tex]f(n) ≤ cg(n)0.1n^6−n^3 ≤ c\\g(n)0.1n^6−n^3 ≤ c(1000n^2+500)[/tex]
Dividing by [tex]n^3, we get: 0.1n^3−1 ≤ c(1000+500/n^3)[/tex]
As n approaches infinity, the RHS approaches c(1000).
Let's choose c(1000)=1, so c=1/1000.
Plugging this back into the inequality, we get: [tex]0.1n^3−1 ≤ 1/1000(1000+500/n^3)0.1n^3−1 ≤ 1+n^-3/2[/tex]
Multiplying by [tex]n^3/10, we get:n^3/10−n^3/1000 ≤ n^3/10+n^(3/2)/1000[/tex]
As n approaches infinity, the inequality holds.
Therefore, f(n)=O(g(n)) for c=1/1000 and n0=1
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Suppose 20% of the students graduated from a technical university are not employed within 6 months after graduation. A random sample of 20 graduated students were selected.
(a) State the random variable, X and write the appropriate distribution. (2 Marks)
(b) Based on (a), find the probability that, after graduation
i) three students are not employed within 6 months. (1 Mark)
ii) more than five students are not employed within 6 months. (2 Marks)
iii) No students are not employed within 6 months. (1 Mark)
iv) What is the average students are not employed within 6 months. (2 Marks)
(a) X represents the number of students not employed within 6 months. The appropriate distribution is the binomial distribution.
(b) i) P(X = 3), ii) P(X > 5), iii) P(X = 0), iv) E(X) = 4.
(a) The random variable X represents the number of students in the random sample who are not employed within 6 months after graduation. The appropriate distribution for this scenario is the binomial distribution.
(b) Based on the binomial distribution:
i) The probability that three students are not employed within 6 months is given by:
P(X = 3) = (20% of 20 choose 3) * (0.20)^3 * (0.80)^(20-3)
ii) The probability that more than five students are not employed within 6 months is given by:
P(X > 5) = 1 - P(X ≤ 5)
= 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)]
iii) The probability that no students are not employed within 6 months is given by:
P(X = 0) = (20% of 20 choose 0) * (0.20)^0 * (0.80)^(20-0)
iv) The average number of students not employed within 6 months can be calculated using the expected value of the binomial distribution, which is given by:
E(X) = n * p
In this case, E(X) = 20 * 0.20 = 4 students.
Please note that the actual calculations for the probabilities in (i), (ii), and (iii) may require numerical evaluation using a calculator or statistical software.
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Which of the following values will always be within the upper and lower limits of a confidence interval for μ ? the sample size the sample mean the standard deviation of the sample the population mean View hint for Question 1 Question 2 (1 point) A 95\% confidence interval for the mean increase in sound pressure levels in pens of cattle exposed to low-level military flights was calculated to be (84.5,108.2) decibels. Which of the following statements is true? The probability that the true mean is between 84.5 and 108.2 is 0.95. The probability that the next flight will raise the decibel levels between 84.5 and 108.2 is 0.95. The process used for this calculation has a probability of 0.95 of delivering an interval containing the true mean. 0.95 of the increase in sound pressure levels are in the range 84.5 and 108.2. Question 3 (1 point) The Margin of Error is found by The midpoint of the interval. the sample mean minus the standard of error. 2
( Upper Limit − Lower Limit )
2
(Lower Limit + Upper Limit )
Question 4 (1 point) Which of the following does is NOT a check to satisfy the assumptions underlying inference about one mean? S.W. p-value at least .05 S.W. p-value less than .05 the sample size at least equal to thirty. n>30
The answer to the question is: "the sample mean". In a confidence interval, the sample mean is always between the upper and lower limits of the confidence interval.
A confidence interval is a range of values, derived from a sample of data, that is used to estimate an unknown population parameter with a certain degree of confidence.
The correct answer is "The process used for this calculation has a probability of 0.95 of delivering an interval containing the true mean."
A 95% confidence interval means that if the study is repeated many times, 95% of the confidence intervals calculated would contain the true population mean. Therefore, the process used for this calculation has a probability of 0.95 of delivering an interval containing the true mean.
The answer is "( Upper Limit − Lower Limit ) / 2".
The margin of error is a measure of the accuracy of the sample mean as an estimate of the population mean. It is calculated by taking the difference between the upper and lower limits of the confidence interval and dividing it by two.
The answer is "S.W. p-value less than .05". There are three assumptions underlying inference about one mean: normality, independence, and equality of variances. The Shapiro-Wilk test of normality is a check to satisfy the normality assumption, and the p-value should be greater than .05. The assumption of independence is usually satisfied if the data are collected through a simple random sample. The equality of variances is checked with the F-test or by comparing standard deviations, and there is no specific cutoff for this check.
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Say that we take a random sample of 10 values from a population with median 50. The number of values in our sample that are below 50 will have this distribution:
(By definition, the probability of an outcome being below the median is 50%)
binomial, n = 10, p = 0.5
F distribution, D1 = 50, D2 = 10
Normal, mean = 50, standard deviation = 10
t-distribution, mean = 50, degrees of freedom = 10
The distribution of the number of values in a random sample of 10 from a population with median 50 that are below 50 is a binomial distribution with parameters n = 10 and p = 0.5.
This is because each value in the sample can be either above or below the median, and the probability of being below the median is 0.5 (assuming the population is symmetric around the median). We are interested in the number of values in the sample that are below the median, which is a count of successes in 10 independent Bernoulli trials with success probability 0.5. Therefore, this follows a binomial distribution with n = 10 and p = 0.5 as the probability of success.
The other distributions mentioned are not appropriate for this scenario. The F-distribution is used for hypothesis testing of variances in two populations, where we compare the ratio of the sample variances. The normal distribution assumes that the population is normally distributed, which may not be the case here. Similarly, the t-distribution assumes normality and is typically used when the sample size is small and the population standard deviation is unknown.
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Question 17 (1 point)
Find the surface area of the figure. Hint: the surface area from the missing prism
inside the prism must be ADDED!
2 ft 5ft
10 ft
7 ft
6 ft
The surface area of the rectangular prism is 462 square feet.
What is the surface area of the rectangular prism?Length, L = 10 ft
Width, W = 6 ft
Height, H = 7 ft
SA= 2(LW + LH + WH)
= 2(10×7 + 10×6 + 6×7)
= 2(70+60+42)
= 2(172)
= 344 square feet
Surface area of the missing prism:
Length, L = 5 ft
Width, W = 2 ft
Height, H = 7 ft
SA= 2(LW + LH + WH)
= 2(5×2 + 5×7 + 2×7)
= 2(10 + 35 + 14)
= 2(59)
= 118 square feet
Therefore, the surface area of the figure
= 344 square feet + 118 square feet
= 462 square feet
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he membership of a university club has 10 senior, 9 juniors, 13 sophomores, and 15 freshmen. Two club members are to be selected at random as social media officers. What is the probability that the two officers are both seniors or both freshmen?
The probability that the two officers are both seniors or both freshmen is approximately 0.132 or 13.2%.
To calculate the probability that the two officers are both seniors or both freshmen, we need to determine the total number of possible outcomes and the number of favorable outcomes.
Total number of outcomes:
The total number of club members is 10 + 9 + 13 + 15 = 47. Therefore, the total number of possible outcomes is C(47, 2), which represents selecting 2 club members out of 47 without replacement.
Number of favorable outcomes:
To have both officers as seniors, we need to select 2 seniors out of the 10 available. This can be represented as C(10, 2).
To have both officers as freshmen, we need to select 2 freshmen out of the 15 available. This can be represented as C(15, 2).
Now we can calculate the probability:
P(both officers are seniors or both are freshmen) = (C(10, 2) + C(15, 2)) / C(47, 2)
P(both officers are seniors or both are freshmen) = (45 + 105) / 1081
P(both officers are seniors or both are freshmen) ≈ 0.132
Therefore, the probability that the two officers are both seniors or both freshmen is approximately 0.132 or 13.2%.
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In a camival game, a person wagers $2 on the roll of two dice. If the total of the two dice is 2,3,4, 5 , or 6 then the person gets $4 (the $2 wager and $2 winnings). If the total of the two dice is 8,9,10, 11 , or 12 then the person gets nothing (loses $2 ). If the total of the two dice is 7 , the person gets $0.75 back (loses $0.25 ). What is the expected value of playing the game once? A) −$0.42 B) −$0.04 C) $0.00 D) $2.00
The expected value of playing the game once is approximately -$0.43.
To find the expected value of playing the game once, we need to calculate the weighted average of the possible outcomes based on their probabilities.
Let's calculate the expected value:
For the outcomes 2, 3, 4, 5, and 6, the person wins $4 with a probability of 5/36 (since there are 5 favorable outcomes out of 36 possible outcomes when rolling two dice).
The expected value for these outcomes is (5/36) * $4 = $20/36.
For the outcome 7, the person gets $0.75 back with a probability of 6/36 (since there are 6 possible outcomes that result in a sum of 7).
The expected value for this outcome is (6/36) * $0.75 = $1/8.
For the outcomes 8, 9, 10, 11, and 12, the person loses $2 with a probability of 20/36 (since there are 20 possible outcomes that result in sums of 8, 9, 10, 11, or 12).
The expected value for these outcomes is (20/36) * (-$2) = -$40/36.
Now, let's calculate the overall expected value:
Expected Value = ($20/36) + ($1/8) + (-$40/36)
= $0.5556 + $0.125 - $1.1111
= -$0.4305
Therefore, the expected value of playing the game once is approximately -$0.43.
The correct option from the given choices is A) -$0.42, which is the closest approximation to the calculated expected value.
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What is the value of the expression (2)/(5)-:(1)/(6)?
The value of the expression (2)/(5)-:(1)/(6) is -22/15. This expression involves fractions and division, which means that we need to follow the order of operations or PEMDAS (parentheses, exponents, multiplication and division, addition and subtraction) to simplify it.
The first step is to simplify the division sign by multiplying by the reciprocal of the second fraction. Thus, the expression becomes: (2/5) ÷ (1/6) = (2/5) × (6/1) = 12/5.Then, we subtract this fraction from 2/5. To do that, we need to have a common denominator, which is 5 × 3 = 15.
Thus, the expression becomes:(2/5) - (12/5) = -10/5 = -2. Therefore, the value of the expression (2)/(5)-:(1)/(6) is -2 or -2/1 or -20/10. We can also write it as a fraction in simplest form, which is -2/1. Therefore, the expression (2)/(5)-:(1)/(6) can be simplified using the order of operations, which involves PEMDAS (parentheses, exponents, multiplication and division, addition and subtraction).
First, we simplify the division sign by multiplying by the reciprocal of the second fraction. Then, we find a common denominator to subtract the fractions. Finally, we simplify the fraction to get the answer, which is -2, -2/1, or -20/10.
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13% of all Americans live in poverty. If 34 Americans are randomly selected, find the probability that a. Exactly 3 of them live in poverty. b. At most 1 of them live in poverty. c. At least 33 of them live in poverty.
Given data:
13% of all Americans live in poverty, n = 34 Americans are randomly selected.
In probability, we use the formula: P(E) = n(E)/n(A)Where, P(E) is the probability of an event (E) happeningn(E) is the number of ways an event (E) can happen
(A) is the total number of possible outcomes So, let's solve the given problems.
a) Exactly 3 of them live in poverty.The probability of 3 Americans living in poverty is given by the probability mass function of binomial distribution:
P(X = 3) = (34C3) × (0.13)³ × (0.87)³¹≈ 0.1203Therefore, the probability that exactly 3 of them live in poverty is 0.1203.
b) At most 1 of them live in poverty. The probability of at most 1 American living in poverty is equal to the sum of the probabilities of 0 and 1 American living in poverty:
P(X ≤ 1) = P(X = 0) + P(X = 1)P(X = 0) = (34C0) × (0.13)⁰ × (0.87)³⁴P(X = 1) = (34C1) × (0.13)¹ × (0.87)³³≈ 0.1068Therefore, the probability that at most 1 of them live in poverty is 0.1068.
c) At least 33 of them live in poverty.The probability of at least 33 Americans living in poverty is equal to the sum of the probabilities of 33, 34 Americans living in poverty:
P(X ≥ 33) = P(X = 33) + P(X = 34)P(X = 33) = (34C33) × (0.13)³³ × (0.87)¹P(X = 34) = (34C34) × (0.13)³⁴ × (0.87)⁰≈ 5.658 × 10⁻⁵Therefore, the probability that at least 33 of them live in poverty is 5.658 × 10⁻⁵.
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Solve the matrix equation Ax=B for x using the given matrices. SHOW ALL WORK. 13. A=[[5,1],[-2,-2]],B=[[-8],[24]]
The solution to the matrix equation Ax = B is x = [[1], [-13]].
To solve the matrix equation Ax = B, where A = [[5, 1], [-2, -2]] and B = [[-8], [24]], we need to find the matrix x.
To find x, we can use the formula x = A^(-1) * B, where A^(-1) represents the inverse of matrix A.
First, let's find the inverse of matrix A:
A = [[5, 1], [-2, -2]]
To find the inverse, we can use the formula:
A^(-1) = (1 / det(A)) * adj(A)
Where det(A) represents the determinant of matrix A, and adj(A) represents the adjugate of matrix A.
Calculating the determinant of A:
det(A) = (5 * -2) - (1 * -2) = -10 + 2 = -8
Next, let's find the adjugate of A:
adj(A) = [[-2, -1], [2, 5]]
Now, we can find the inverse of A:
A^(-1) = (1 / det(A)) * adj(A) = (1 / -8) * [[-2, -1], [2, 5]]
Simplifying:
A^(-1) = [[1/4, 1/8], [-1/4, -5/8]]
Now, we can find x by multiplying A^(-1) and B:
x = A^(-1) * B = [[1/4, 1/8], [-1/4, -5/8]] * [[-8], [24]]
Calculating the matrix multiplication:
x = [[1/4 * -8 + 1/8 * 24], [-1/4 * -8 + -5/8 * 24]]
Simplifying:
x = [[-2 + 3], [2 + (-15)]]
x = [[1], [-13]]
Therefore, the solution to the matrix equation Ax = B is x = [[1], [-13]].
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Please round your answers to three decimal places. Your answer will be checked to two dec
Consider the following ordered pairs: (1.7, 7.65), (1.8, 8.1), (3.4, 15.3), (5, 22.5)
a. Is the ratio of output to input constant or not?
The ratio is (enter without the quotes either "constant" or "not constant", as appropriate)
The ratios for all the pairs are equal to 4.5.Therefore, the ratio of output to input is constant.
To determine if the ratio of output to input is constant or not, we need to calculate the ratio for each pair of input and output values and check if the ratios are the same.
Let's calculate the ratios for the given ordered pairs:
Ratio for (1.7, 7.65): 7.65 / 1.7 = 4.5
Ratio for (1.8, 8.1): 8.1 / 1.8 = 4.5
Ratio for (3.4, 15.3): 15.3 / 3.4 ≈ 4.5
Ratio for (5, 22.5): 22.5 / 5 = 4.5
The ratios for all the pairs are equal to 4.5.
Therefore, the ratio of output to input is constant.
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Given sinA=(63)/(65) and that angle A is in Quadrant I, find the exact value of cosA in simplest radical form using a rational denominator.
The given sin A = 63/65 and that angle A is in Quadrant I. We need to find the exact value of cos A in simplest radical form using a rational denominator. In the simplest radical form using a rational denominator is (46/65) which cannot be further simplified since 46 and 65 have no common factors other than 1.
Given: sinA = 63/65 and A is in Quadrant I.In a right triangle, sinA = Opposite/Hypotenuse = BC/AC.Let BC = 63, AC = 65 and AB = √(AC² - BC²) = √(65² - 63²) = √(2116) = 46.So, cosA = Base/Hypotenuse = AB/AC = 46/65. Therefore, the exact value of cosA in simplest radical form using a rational denominator is (46/65) which cannot be further simplified since 46 and 65 have no common factors other than 1. The given problem is to find the exact value of cosA in simplest radical form using a rational denominator, given that sinA = 63/65 and angle A is in Quadrant I.In a right-angled triangle, the opposite side is the side that is opposite to the angle of interest and the hypotenuse is the longest side of the right-angled triangle, and it is always opposite to the right angle, while the adjacent side is the side adjacent to the angle of interest.
To calculate the cosine of an angle in a right-angled triangle, we need to calculate the ratio of the adjacent side to the hypotenuse, using the following formula: cosA = Base/Hypotenuse = AB/AC. In the given question, we are given that sinA = 63/65 and that angle A is in Quadrant I. In Quadrant I, all trigonometric functions are positive, i.e., sinA = BC/AC > 0. This implies that the length of the opposite side (BC) is positive, and the length of the hypotenuse (AC) is also positive. Using the Pythagorean theorem, we can calculate the length of the base (AB).We have AB = √(AC² - BC²).Substituting the values, we get AB = √(65² - 63²) = √(2116) = 46.Now, we can calculate the cosine of angle A using the formula mentioned above. cosA = AB/AC = 46/65.Therefore, the exact value of cosA in the simplest radical form using a rational denominator is (46/65) which cannot be further simplified since 46 and 65 have no common factors other than 1.
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f′′′ (t)+2f ′′ (t)−4f ′ (t)−8f(t)=0
The solution to the differential equation with the given initial conditions is:
f(t) = (1/3)*e^(2t) - (1/3)*e^(-t) + (5/9)te^(-t)
To solve the given differential equation:
f'''(t) + 2f''(t) - 4f'(t) - 8f(t) = 0
We can first find the roots of the characteristic equation by assuming a solution of the form:
f(t) = e^(rt)
Substituting into the differential equation gives:
r^3 + 2r^2 - 4r - 8 = 0
We can factor this equation as:
(r-2)(r+1)^2 = 0
So the roots are: r = 2 and r = -1 (with multiplicity 2).
Therefore, the general solution to the differential equation is:
f(t) = c1e^(2t) + c2e^(-t) + c3te^(-t)
where c1, c2, and c3 are constants that we need to determine.
To find these constants, we can use the initial conditions. Let's assume that f(0) = 0, f'(0) = 1, and f''(0) = 2. Then:
f(0) = c1 + c2 = 0
f'(0) = 2c1 - c2 + c3 = 1
f''(0) = 4c1 + c2 - 2c3 = 2
Solving these equations simultaneously, we get:
c1 = 1/3
c2 = -1/3
c3 = 5/9
Therefore, the solution to the differential equation with the given initial conditions is:
f(t) = (1/3)*e^(2t) - (1/3)*e^(-t) + (5/9)te^(-t)
Note that the third term is a particular solution that arises from the repeated root at r = -1.
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It takes 120ft−lb. of work to compress a spring from a natural length of 3ft. to a length of 2ft,, 6 in. How much work is required to compress the spring to a length of 2ft.?
Given that it takes 120ft-lb of work to compress a spring from a natural length of 3ft to a length of 2ft 6in. Now we need to find the work required to compress the spring to a length of 2ft.
Now the work required to compress the spring from a natural length of 3ft to a length of 2ft is 40 ft-lb.
So we can find the force that is required to compress the spring from the natural length to the given length.To find the force F needed to compress the spring we use the following formula,F = k(x − x₀)Here,k is the spring constant x is the displacement of the spring from its natural length x₀ is the natural length of the spring. We can say that the spring has been compressed by a distance of 0.5ft.
Now, k can be found as,F = k(x − x₀)
F = 120ft-lb
x = 0.5ft
x₀ = 3ft
k = F/(x − x₀)
k = 120/(0.5 − 3)
k = -40ft-lb/ft
Now we can find the force needed to compress the spring to a length of 2ft. Since the natural length of the spring is 3ft and we need to compress it to 2ft. So the displacement of the spring is 1ft. Now we can find the force using the formula F = k(x − x₀)
F = k(x − x₀)
F = -40(2 − 3)
F = 40ft-lb
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Does the equation specify a function with independent variable x ? If so, find the domain of the function. If not, find a value of x to which there corresponds more than one value of y. y(x+y)=4
The equation does not specify a function with independent variable x and the domain of the function is all real numbers.
The given equation is y(x + y) = 4. In the given equation, we have two variables, x and y. To check whether the equation specifies a function with independent variable x, let's assume y to be a function of x. Then we can write y as follows:
y = f(x)
Substituting this value of y in the given equation:
y(x + y) = 4x + f(x) + [f(x)]² = 4
This is a quadratic equation of f(x). The general form of a quadratic equation is:
ax² + bx + c = 0
where a, b, and c are constants.
In this case, we have:
x² + 2x f(x) + [f(x)]² - 4 = 0
Now let's find the discriminant of the above equation:
D = b² - 4ac
= 4 - 4[f(x)]² - 4(-4)
= 16 - 4[f(x)]²
The discriminant must be greater than or equal to zero for the equation to have real solutions. So we have:
16 - 4[f(x)]² ≥ 0[f(x)]² ≤ 4f(x) ≤ ±2
Let's take the positive value for simplicity:
f(x) ≤ 2
If we draw the graph of this quadratic function, we'll find that it is a downward-facing parabola, which means that there will be a value of x for which there corresponds more than one value of y. So the equation does not specify a function with independent variable x. Now let's find that value of x:
Let's assume y = k (a constant). Then we can write:
y(x + k) = 4x + ky² + kx - 4 = 0
This is a quadratic equation of y. Let's find the discriminant of this equation:
D = b² - 4ac= k² - 4(x)(kx - 4)= k² - 4kx + 16
Let's make this discriminant zero:
16 - 4kx + k² = 0kx = (k² + 16)/4
For any value of k, we can find a value of x that satisfies this equation.
Therefore, there corresponds more than one value of y for this value of x. Hence, the equation does not specify a function with independent variable x. The domain of the function is all real numbers.
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gow
do you andwer
Let \( X \) be a discrete random variable such that \( E[X] \) exists. Let \( Y=a+b X \). Show that \( E[Y]=a+b E[X] \)
[tex]\(E[Y] = a + bE[X]\)[/tex], which shows that the expected value of [tex]\(Y\)[/tex] is equal to [tex]\(a + b\)[/tex] times the expected value of [tex]\(X\)[/tex].
To show that [tex]\(E[Y] = a + bE[X]\)[/tex], we need to calculate the expected value of the random variable [tex]\(Y\)[/tex] and demonstrate that it is equal to [tex]\(a + b\)[/tex]times the expected value of [tex]\(X\)[/tex].
The expected value of a discrete random variable is calculated as the sum of each possible value multiplied by its corresponding probability. Let's denote the set of possible values of [tex]\(X\)[/tex] as [tex]\(x_i\)[/tex] with corresponding probabilities [tex]\(P(X=x_i)\)[/tex].
The random variable[tex]\(Y = a + bX\)[/tex] can be expressed as a linear transformation of [tex]\(X\)[/tex] with scaling factor [tex]\(b\)[/tex] and translation [tex]\(a\)[/tex].
Now, let's calculate the expected value of [tex]\(Y\)[/tex]:
[tex]\(E[Y] = \sum_{i} (a + b x_i) P(X=x_i)\)[/tex]
Using the linearity of expectation, we can distribute the summation and calculate it separately for each term:
[tex]\(E[Y] = \sum_{i} a P(X=x_i) + \sum_{i} b x_i P(X=x_i)\)[/tex]
The first term [tex]\(\sum_{i}[/tex] a [tex]P(X=x_i)\)[/tex]simplifies to [tex]\(a \sum_{i} P(X=x_i)\)[/tex], which is [tex]\(a\)[/tex] times the sum of the probabilities of [tex]\(X\)[/tex]. Since the sum of probabilities equals 1, this term becomes [tex]\(a\)[/tex].
The second term [tex]\(\sum_{i} b x_i P(X=x_i)\)[/tex] is equal to [tex]\(b\)[/tex] times the expected value of [tex]\(X\), \(bE[X]\)[/tex].
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Using the fact that the sum of the lengths of any two sides of a triangle exceeds the length of the third side, find all possible values of x for which the following triangle exists.
The valid range for x, the length of one side of the triangle, is given by:
x > |b - c| and x < b + c, where |b - c| denotes the absolute value of (b - c).
To find all possible values of x for which the given triangle exists, we can apply the triangle inequality theorem, which states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side.
Let's assume the lengths of the three sides of the triangle are a, b, and c. According to the triangle inequality theorem, we have three conditions:
1. a + b > c
2. b + c > a
3. c + a > b
In this case, we are given one side with length x, so we can express the conditions as:
1. x + b > c
2. b + c > x
3. c + x > b
By examining these conditions, we can determine the range of values for x. Each condition provides a specific constraint on the lengths of the sides.
To find all possible values of x, we need to consider the overlapping regions that satisfy all three conditions simultaneously. By analyzing the relationships among the variables and applying mathematical reasoning, we can determine the range of valid values for x that allow the existence of the triangle.
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From a deck of cards, you are going to select five cards at random without replacement. How many ways can you select five cards that contain (a) three kings (b) four spades and one heart
a. There are approximately 0.0138 ways to select five cards with three kings.
b. There are approximately 0.0027 ways to select five cards with four spades and one heart.
(a) To select three kings from a standard deck of 52 cards, there are four choices for the first king, three choices for the second king, and two choices for the third king. Since the order in which the kings are selected does not matter, we need to divide by the number of ways to arrange three kings, which is 3! = 6. Finally, there are 48 remaining cards to choose from for the other two cards. Therefore, the total number of ways to select five cards with three kings is:
4 x 3 x 2 / 6 x 48 x 47 = 0.0138 (rounded to four decimal places)
So there are approximately 0.0138 ways to select five cards with three kings.
(b) To select four spades and one heart, there are 13 choices for the heart and 13 choices for each of the four spades. Since the order in which the cards are selected does not matter, we need to divide by the number of ways to arrange five cards, which is 5!. Therefore, the total number of ways to select five cards with four spades and one heart is:
13 x 13 x 13 x 13 x 12 / 5! = 0.0027 (rounded to four decimal places)
So there are approximately 0.0027 ways to select five cards with four spades and one heart.
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Mergelyan's theorem -> a generalization of Stone–Weierstrass theorem for polynomialsProve and Describe the theorem.
Mergelyan's theorem is a generalization of Stone-Weierstrass theorem for polynomials, which states that any continuous function on a compact subset K of the complex plane can be uniformly approximated to arbitrary accuracy by polynomials.
More specifically, Mergelyan's theorem states that:
Let K be a compact subset of the complex plane, and let E be a closed subset of K. Suppose that f is a continuous function on E. Then for any ε > 0, there exists a polynomial p(z) such that |f(z) - p(z)| < ε for all z in E.
In other words, Mergelyan's theorem guarantees that any continuous function on a closed subset of a compact set can be uniformly approximated by polynomials on that subset.
The proof of Mergelyan's theorem relies on a construction involving complex analysis and geometric ideas. It involves using the Runge approximation theorem, which states that any function that is holomorphic on an open set containing a compact set K can be approximated uniformly on K by rational functions whose poles lie outside of K. The idea is to use this result to approximate the given continuous function f by a sequence of rational functions with poles outside of E, and then to use partial fraction decomposition to write each of these rational functions as a sum of polynomials. By taking a uniform limit of these polynomial approximations, one obtains a polynomial that approximates f to within any desired tolerance on E.
Overall, Mergelyan's theorem provides a powerful tool for approximating complex-valued functions by polynomials, which has many applications in complex analysis, numerical analysis, and engineering.
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Determine the critical value and critical region that would be used in the classical approach to test H0:P(1)=0.25,P(2)=0.40,P(3)=0.35, with a =0.1. x^2≥ bu may need to use the appropriate table in Appendix B to answer this question.
The critical value for the chi-square test is 4.605, and the critical region is x^2 ≥ 4.605.
To determine the critical value and critical region for testing the null hypothesis H0: P(1) = 0.25, P(2) = 0.40, P(3) = 0.35, with a significance level of α = 0.1, we can use the chi-square test.
Step 1: Determine the number of categories or levels, which in this case is 3.
Step 2: Determine the degrees of freedom (df) for the chi-square test. df = Number of categories - 1 = 3 - 1 = 2.
Step 3: Look up the critical value in the chi-square distribution table using a significance level of 0.1 and 2 degrees of freedom. From the table, the critical value for α = 0.1 and df = 2 is approximately 4.605.
Step 4: Determine the critical region. The critical region for the chi-square test is defined as the set of values for the test statistic (chi-square value) that lead to the rejection of the null hypothesis. In this case, the critical region is x^2 ≥ 4.605.
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Let B_{1}=\{1,2\}, B_{2}=\{2,3\}, ..., B_{100}=\{100,101\} . That is, B_{i}=\{i, i+1\} for i=1,2, \cdots, 100 . Suppose the universal set is U=\{1,2, ..., 101\} . Determine
The solutions are: A. $\overline{B_{13}}=\{1,2,...,12,15,16,...,101\}$B. $B_{17}\cup B_{18}=\{17,18,19\}$C. $B_{32}\cap B_{33}=\{33\}$D. $B_{84}^C=\{1,2,...,83,86,...,101\}$.
The given question is as follows. Let $B_1=\{1,2\}, B_2=\{2,3\}, ..., B_{100}=\{100,101\}$. That is, $B_i=\{i,i+1\}$ for $i=1,2,…,100$. Suppose the universal set is $U=\{1,2,...,101\}$. Determine. In order to find the solution to the given question, we have to find out the required values which are as follows: A. $\overline{B_{13}}$B. $B_{17}\cup B_{18}$C. $B_{32}\cap B_{33}$D. $B_{84}^C$A. $\overline{B_{13}}$It is known that $B_{13}=\{13,14\}$. Hence, $\overline{B_{13}}$ can be found as follows:$\overline{B_{13}}=U\setminus B_{13}= \{1,2,...,12,15,16,...,101\}$. Thus, $\overline{B_{13}}=\{1,2,...,12,15,16,...,101\}$.B. $B_{17}\cup B_{18}$It is known that $B_{17}=\{17,18\}$ and $B_{18}=\{18,19\}$. Hence,$B_{17}\cup B_{18}=\{17,18,19\}$
Thus, $B_{17}\cup B_{18}=\{17,18,19\}$.C. $B_{32}\cap B_{33}$It is known that $B_{32}=\{32,33\}$ and $B_{33}=\{33,34\}$. Hence,$B_{32}\cap B_{33}=\{33\}$Thus, $B_{32}\cap B_{33}=\{33\}$.D. $B_{84}^C$It is known that $B_{84}=\{84,85\}$. Hence, $B_{84}^C=U\setminus B_{84}=\{1,2,...,83,86,...,101\}$.Thus, $B_{84}^C=\{1,2,...,83,86,...,101\}$.Therefore, The solutions are: A. $\overline{B_{13}}=\{1,2,...,12,15,16,...,101\}$B. $B_{17}\cup B_{18}=\{17,18,19\}$C. $B_{32}\cap B_{33}=\{33\}$D. $B_{84}^C=\{1,2,...,83,86,...,101\}$.
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