Answer:
246ft/min
Explanation:
In this problem we are faced with unit conversion.
We are expected to convert from km/h to ft/min
Given that
1.00 m = 3.28 ft
1km(1000m)= 3280 ft
But we need to convert 4.5km to ft
Hence in ft 4.5km= 3280*4.5
= 14760ft
We now convert hour to minutes
60min make 1 hour
Therefore the convert form km/h to ft/min is
= 14760/60= 246ft/min
The answer is 246ft/min
When a star is moving away from Earth, does the color of the star actually change? Explain - PLZZ HELP:)
Answer:
Yes the color changes. If the star is moving away from the earth the color of the star is shifted towards red (red-shift).
This is similar to the change in sound from an approaching train whistle (higher pitch) or a receding train whistle (lower pitch) - the Doppler Effect.
Note that the equations for the Doppler Effect for sound and for light are different - sound travels thru air but no such medium can be identified for light.
An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the force due to air resistance is proportional to the velocity of the object with proportionality constant b N-sec/m, determine the equation of motion of the object. When will the object strike the ground? Assume that the acceleration due to gravity is and let x(t) represent the distance the object has fallen in t second
Answer:
Explanation:
From, the given information: we are not given any value for the mass, the proportionality constant and the distance
Assuming that:
the mass = 5 kg and the proportionality constant = 50 kg
the distance of the mass above the ground x(t) = 1000 m
Let's recall that:
[tex]v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}[/tex]
Similarly, The equation of mption:
[tex]x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})[/tex]
replacing our assumed values:
where [tex]v_=0 \ and \ g= 9.81[/tex]
[tex]x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})[/tex]
[tex]x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m[/tex]
[tex]\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}[/tex]
So, when the object hits the ground when x(t) = 1000
Then from above derived equation:
[tex]\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}[/tex]
[tex]1000= 0.981t-0.981(1-e^{-(10)t}) \ m[/tex]
By diregarding [tex]e^{-(10)t} \ m[/tex]
[tex]1000= 0.981t-0.981[/tex]
1000 + 0.981 = 0.981 t
1000.981 = 0.981 t
t = 1000.981/0.981
t = 1020.36 sec
Calculate the volume of this regular solid,
What is the volume of the sphere? Round your answer
to the nearest tenth.
cm
8 cm
Answer:
2144.7
Explanation:
If you blow across the open end of a soda bottle and produce a toneof 290 Hz, what will be the frequency of the next harmonic heard ifyou blow much harder? (Hz)
Answer:
f = 96.56 Hz
Explanation:
A soda bottle can be simulated by a system of a tube with one end open and the other closed. In this case at the closed end we have a node and at the open end a maximum, so the wavelength is
λ = 4L / n
where n = 1, 3, 5, ...
for our case the speed of sound is
v = λ f
we substitute
f / v = 4L / n
calculate
290 / (340 4) = L / n
0.213 = L / n
In the exercise the value of n is not indicated, but we can assume that it is the fundamental answer, therefore n = 1
L = 0.213 m
now we can calculate the frequency of the following resonance n = 3
f = 4L v / n
f = 4 0.213 340/3
f = 96.56 Hz
I need help asap on these definitions if anyone could help me please :(
I'll give 20 points to whoever helps me!!
Answer:
Inertia: a tendency to do nothing or to remain unchanged; momentum:the quantity of motion of a moving body; velocity:the speed of something in a given direction; acceleration: a vehicles capacity to gain speed within a short time
A piece of wood that floats on water has a mass of 0.0175 kg. A lead weight is tied to the wood, and the apparent mass with the wood in air and the lead weight submerged in water is 0.0765 kg. The apparent mass with the wood and the lead weight both submerged in water is 0.0452 kg. What is the specific gravity of the wood
Answer:
Specific gravity is 0.56
Explanation:
We know that
mass of water displaced by the wood is, m1( apparent mass when wood in air and lead is submerged in water) - m2(the apparent mass when wood and lead both are submerged in water)
= 0.0765 - 0.0452 = 0.0313 Kg
So the specific gravity of the wood is, = mass of wood / mass of water displaced by the wood
= 0.0175/0.0313
=0.56
which statement illustrates a chemical change?
A) shredding paper
B) smashing a soda can
C) burning wood*
D) chopping wood
Answer:
The answer is C burning the wood
Two supports, made of the same material and initially of equal length, are 2.0 m apart. A stiff board with a length of 4.0 m and a mass of 10 kg is placed on the supports, with one support at the left end and the other at the midpoint. A block is placed on the board a distance of 0.50 m from left end. As a result the board is horizontal (that is, the downward force on each support is the same). The mass of the block is:
Answer:
20 kg
Explanation:
Assuming that the board remains horizontal with the unknown mass on it, then F = kx
If we add the vertical forces to zero, we have something like this
2F - (M + 10)g = 0
2F = (M + 10)g, next, divide both sides by 2
F = (M + 10)g/2
Since we were able to sum the moments at the right end of the board to zero, we then proceed to find the unknown mass M
To start, we say, Let the clockwise moment is positive, and so
F * 4 + F * 2 - Mg * 3.5 - 10 * g * 2 = 0
4F + 2F - 3.5Mg - 10 * 2 * g = 0
6F - 3.5Mg - 10 * 2 * g = 0,
Remember from above, we say that
F = M + 10)g/2, now, all we do is substitute it inside this equation
6 * (M + 10)g/2 - 3.5Mg - 10 * 2 * g = 0
3 * (M + 10)g - 3.5Mg - 10 * g * 2 = 0, divide all sides by g(so as to eliminate it)
3 (M + 10) - 3.5M - 10 * 2= 0
3M + 30 - 3.5M - 20 = 0
-0.5M + 10 = 0
0.5M = 10
M = 10/0.5
M = 20 kg
The mass of the block that was placed on the board is; M = 20 kg
Since the two supports are the same, then it means their forces will be the same.
Thus;
Force at left support = F
Force at right support = F
Now, we are told that a block of unknown mass is placed on the stiff board. This means that the sum of the weight of the board and and the block on it will be; (M + 10)g
where M is the mass of the block.
Now, from equilibrium we know that sum of upward forces is equal to sum of downward forces. Thus;
F + F = (M + 10)g
Thus;
2F = (M + 10)g
F = ¹/₂(M + 10)g
Now, taking moments about the right end gives;
(F × 4) + (F × 2) - (M × 3.5)g - (10 × 2)g = 0
6F - 3.5Mg - 20g = 0
Put ¹/₂(M + 10)g for F to get;
6(¹/₂(M + 10)g) - 3.5Mg - 20g = 0
Divide through by g to get;
3(M + 10) - 3.5M = 20
3M + 30 - 3.5M = 20
3.5M - 3M = 30 - 20
0.5M = 10
M = 10/0.5
M = 20 kg
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Materials expand when heated. Consider a metal rod of length L0 at temperature T0. If the temperature is changed by an amount ΔT, then the rod’s length changes by ΔL=????L0ΔT, where ???? is the thermal expansion coefficient. For steel, ????=1.24×10−5∘C−1. (a) A steel rod has length L0=70cm at T0=70∘C. What is its length at T=110∘C?
Answer:
[tex]\Rightarrow L=70 .03472 cm[/tex]
Explanation:
For convenience, let's represent the thermal expansion coefficient by [tex]\alpha[/tex], i.e. [tex]????=\alpha[/tex].
Given that, for steel [tex]\alpha =1.24\times 10^{-5}[/tex] °[tex]C^{-1}[/tex],
initial length, [tex]L_0=70 cm[/tex], initial temperature, [tex]T_0=70[/tex] °[tex]C[/tex], and the final temperature, [tex]T=110[/tex] °[tex]C[/tex].
Let the length of the rod at [tex]T=110[/tex] °[tex]C[/tex] be [tex]L[/tex].
Now, change in length, [tex]\Delta L=\alpha L_0 \Delta T[/tex]
[tex]\Rightarrow \Delta L=\alpha L_0 (T-T_0)[/tex]
[tex]\Rightarrow L-L_0=1.24\times 10^{-5}\times 70 (110-70)[/tex]
[tex]\Rightarrow L-70=1.24\times 10^{-5}\times 70 \times 40[/tex]
[tex]\Rightarrow L=70 + 0.03472 cm[/tex]
[tex]\Rightarrow L=70 .03472 cm[/tex]
Hence, the length of the rod at [tex]T=110[/tex] °[tex]C[/tex] be [tex]70.03472 cm[/tex].
1.How far is Object Z from the origin at t = 3 seconds?
2.Which object takes the least time to reach a position 4 meters from the origin?
3.Which object is farthest from the origin at t = 2 seconds?
Show work
Answer:
Please find the answer in the explanation
Explanation:
1.) How far is Object Z from the origin at t = 3 seconds
The distance of the object Z from the origin will be the slope of the graph.
Slope = 4/2 = 2m
2.) Which object takes the least time to reach a position 4 meters from the origin ?
According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.
3.) Which object is farthest from the origin at t = 2 seconds?
The correct answer is still object Z because it has the highest slope.
It is often illustrated in art, popular culture and everyday conversation that the Sun is Yellow. a. Using Wien’s Law and what you learned in class about the Sun’s temperature, explain why this is not true in reality. (20 points) b. In reality, what is the Sun’s true color? Why is this true? (20 points)
Answer:
a) surface λ = 5 10⁻⁷ m
nuecleus λ= 2,890 10⁻⁹ m
there is a mixture of wavelengths giving rise to white light
b) True color sun is White
Explanation:
Wien's law establishes a relationship between the temperature of a star and the maximum wavelength emitted
λ T = 2,898 10⁻³
if we calculate the wavelength of the Sun
T = 5800K λ = 5 10⁻⁷ m = 5000 nm
this is the surface temperature
in the part of the internal Sunspart (Nucleus) about 10⁶ degrees this is where the nuclear reaction occurs
in this region the photons are very short λ
λ = 2,890 10⁻³ / 106
λ= 2,890 10⁻⁹ m
these photons are absorbed and emitted on their way to the surface of the sun many times, therefore there is a mixture of wavelengths giving rise to white light
b) Sunlight when it reaches Earth is absorbed by atmospheric gases, mainly Blue, as it is absorbed by Nitrogen, it lets through mainly red and red
True color sun is White
A boy walked 22 m East then 43 m West , and then 3 meters East. What is the sum of the boys motion.
Given :
A boy walked 22 m East then 43 m West , and then 3 meters East.
To Find :
What is the sum of the boys motion.
Solution :
We need to find the sum of all the motion of boy .
So , we need to find the distance covered by the boy .
We know , total distance covered is absolute sum of all the motion .
[tex]D=22+43+3\\\\D=68\ meters[/tex]
Therefore , total distance covered is 68 meters .
Hence , this is the required solution .
Answer:
It's 18m West.
Explanation:
Imagine you have a number line. your starting point was 22 east of origin. Then you went 43 meters west which leaves you at 21m west. Then you go back east 3 meters. Which leaves you at 18 m west. I hope this helps.
0.00032 cm is equal to
the answer is c because you have to move the decimal back because of the negative
20-ohm resistor is connected to a 10 V battery. The battery is then replaced by a battery that provides a larger voltage what happens to the current through the resistor
Explanation:
It is given that,
Resistance, R = 20 ohms
Voltage of the battery, V = 10 V
We can find current flowing through the circuit using Ohm's law as follows :
V = IR
[tex]I=\dfrac{V}{R}\\\\I=\dfrac{10}{20}\\\\I=0.5\ A[/tex]
It can be seen from the Ohm's law, that the current is directly proportional to the voltage. It means that if the battery is replaced by a battery that provides a larger voltage, the current through the circuit will be more than 0.5 A i.e. it increases.
The current via the circuit will be more than 0.5 A i.e. it increases.
Ohm law:Since
Resistance, R = 20 ohms
The voltage of the battery, V = 10 V
Now we applied the above law i.e.
V = IR
I = V/R
I = 10/20
I = 0.5 A
Based on the above calculations, we can say that the current should be directly proportional to the voltage. That means in the case when the battery should be replaced by the battery that gives the larger voltage so the current should be more than 0.5 A due to this it increased.
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It's important to match your exercise shoes with the type of exercise in which you will be participating, Please select the best answer from the choices provided OT
Answer:
the answer is true
Explanation:
10. An object accelerates 2.0 m/s2 when a force of 12.0 newtons is applied
to it. What is the mass of the object?|
Explanation:
F = ma
m = F/a
= 12N / 2m/s2
= 6kg
The mass of the object is 6kg.
What is Force?A force is defined as an effect that can change the motion of an object by which an object with mass can change its velocity, that is, accelerate. Force can also be described simply as a push or pull. A force has both magnitude and direction which makes it a vector quantity.
According to the Newton's second law of motion is F = ma, or force is equal to mass times acceleration.
Where, F= Force applied
m= mass of the object
a= acceleration
For above given information,
F= 12 N
Acceleration= [tex]2 m/s^2[/tex]
So, mass will be m=F/a
m= 12/2 = 6kg
Thus, the mass of the object is 6kg.
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A motorcycle patrolman is monitoring traffic from behind a billboard along a stretch of road where the speed limit is 96.0 km/hr. He clocks a motorist at 107 km/hr and decides to give chase and award the driver a speeding ticket. By the time he gets onto the highway and up to his chase speed of 131 km/hr, he is 350 m behind the speeder. Determine the amount of time it takes the patrolman to catch the speeder.
Answer:
The time taken is [tex]t = 52.5 \ s [/tex]
Explanation:
From the question we are told that
The speed limit is [tex]v__{{l}}} = 96.0 \ km/hr = \frac{96 * 1000}{3600} = 26.7 \ m/s[/tex]
The velocity of the motorist is [tex]v_m = 107 \ km/hr = \frac{107 * 1000}{3600} = 29.72 \ m/s[/tex]
The chase speed of the motorcycle patrolman is [tex]v = 131 \ km/hr = \frac{131 *1000}{3600} = 36.39 \ m/s[/tex]
The relative distance between the motorcycle patrolman and the speeder is d= 350 m
Generally the relative speed between the the motorcycle patrolman and the speeder is mathematically represented as
[tex]v_r = v - v_m[/tex]
=> [tex]v_r = 36.39 - 29.72[/tex]
=> [tex]v_r = 6.67 \ m/s [/tex]
Generally the time taken is mathematically represented as
[tex]t = \frac{v_r}{d}[/tex]
=> [tex]t = \frac{350}{ 6.67}[/tex]
=> [tex]t = 52.5 \ s [/tex]
If you hit a nail that has a mass of .003 kg with a force of 300 N, what will
the acceleration of the nail be?
Answer:
Explanation:
M= 0.003 kg
F=300N
a=?
F=mass*acceleration
a=F/m
a=300/0.003
a=100,000m/s^2
1) A plane's velocity increases from 40 m/s to 100 m/s over a 10 second interval. What is the plane's average acceleration for this interval? *
Answer:
average acceleration = 6 [tex]\frac{m}{s^2}[/tex]
Explanation:
Recall that the average acceleration [tex](a)[/tex] is defined by the change in velocity from an initial velocity [tex](v_i)[/tex], to a final velocity [tex](v_f)[/tex] over the time (t) it took that change to happen. Then, in mathematical terms this is:
[tex]a=\frac{v_f-v_i}{t}[/tex]
with our information this becomes:
[tex]a=\frac{v_f-v_i}{t} = \frac{100-40}{10}=6\,\frac{m}{s^2}[/tex]
Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made of copper and is filled to its 16.0-L capacity when at 10.0∘C. What volume of radiator fluid will overflow when the radiator and fluid reach their 95.0∘C operating temperature, given that the fluid’s volume coefficient of expansion is 600×10−6/∘C? Note that this coefficient is approximate, because most car radiators have operating temperatures of greater than 95.0∘C.
Answer:
ΔV = 0.816 L
Explanation:
The change in volume of the fluid upon heating is given by the following formula:
ΔV = βVΔT
where,
ΔV = Increase in Volume of Fluid = Volume of Overflow = ?
β = Coefficient of volumetric expansion of fluid = 600 x 10⁻⁶ °C⁻¹
ΔT = Change in Temperature = Final Temperature - Initial Temperature
ΔT = 95°C - 10°C = 85°C
Therefore,
ΔV = (600 x 10⁻⁶ °C⁻¹)(16 L)(85° C)
ΔV = 0.816 L
Find the average velocity (in m/s) of a cyclist that starts 150 meters north of town and is 1200 meters north of town after 30 minutes
Answer:
v = 0.58 m/s
Explanation:
The velocity of an object is given as the ratio of the total distance traveled by the object to the time interval taken for traveling. Hence, we use the following formula to find the average velocity of the cyclist:
v = s/t
where,
v = average velocity = ?
s = distance traveled = final position - initial position =1200 m - 150 m =1050 m
t = time interval = (30 min)(60 s/1 min) = 1800 s
Therefore,
v = 1050 m/1800 s
v = 0.58 m/s
Notice that in each conversion factor the numerator equals the denominator when units are taken into account. A common error in dealing with squares is to square the units inside the parentheses while forgetting to square the numbers! QUESTION What is the numerical part of the time conversion factor, apart from units, that would be used to further convert the answer to km/h2
Answer:
he factor for the temporal part 1.296 107 s² = h²
m / s² = 12960 km / h²
Explanation:
This is a unit conversion exercise.
In the unit conversion, the size of the object is not changed, only the value with respect to which it is measured is changed, for this reason in the conversion the amount that is in parentheses must be worth one.
In this case, it is requested to convert a measure km/h²
Unfortunately, it is not clearly indicated what measure it is, but the most used unit in physics is m / s² , which is a measure of acceleration. Let's cut this down
the factor for the distance is 1000 m = 1 km
the factor for time is 3600 s = 1 h
let's make the conversion
m / s² (1km / 1000 m) (3600 s / 1h)²
note that as time is squared the conversion factor is also squared
m / s² = 12960 km / h²
the factor for the temporal part 1.29 107 s² = h²
Pea plants have 2 advantages as genetic specimens:
Answer:
it can be cross pollinated as well as self pollinated
it has short life style
pea plant has many contrasting character in pair example tall, short.
large number of offspring are produced from hybrid plants
The mass of the Sun is 2multiply1030 kg, and the mass of the Earth is 6multiply1024 kg. The distance from the Sun to the Earth is 1.5multiply1011 m. (a) Calculate the magnitude of the gravitational force exerted by the Sun on the Earth. N (b) Calculate the magnitude of the gravitational force exerted by the Earth on the Sun.
Answer:
a) 3.56 x 10^22 N
b) 3.56 x 10^22 N
Explanation:
Mass of the sun M = 2 x 10^30 kg
mass of the Earth m = 6 x 10^24 kg
Distance between the sun and the Earth R = 1.5 x 10^11 m
From Newton's law,
F = [tex]\frac{GMm}{R^2}[/tex]
where F is the gravitational force between the sun and the Earth
G is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2
m is the mass of the Earth
M is the mass of the sun
R is the distance between the sun and the Earth.
Substituting values, we have
F = [tex]\frac{6.67*10^{-11}*2*10^{30}*6*10^{24}}{(1.5*10^{11})^2}[/tex] = 3.56 x 10^22 N
A) The force exerted by the sun on the Earth is equal to the force exerted by the Earth on the Sun also, and the force is equal to 3.56 x 10^22 N
b) The force exerted by the Earth on the Sun = 3.56 x 10^22 N
Part A:
The magnitude of the gravitational force exerted by the Sun on the Earth is :
Mass of the sun M = 2 x 10^30 kgMass of the Earth m = 6 x 10^24 kgDistance between the sun and the Earth R = 1.5 x 10^11 mFrom Newton's law,
F = GmM/F
G is the gravitational constant = 6.67 × 10^-11 m^3 kg^-1 s^-2m is the mass of the EarthM is the mass of the sunR is the distance between the sun and the Earth.Substituting values,
F = = 3.56 x 10^22 N
The force exerted by the sun on the Earth is equal to the force exerted by the Earth on the Sun also, and the force is equal to 3.56 x 10^22 N.
Part B:
The force exerted by the Earth on the Sun = 3.56 x 10^22 N.
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Which of the following does not serve as a way to neutralize the charge in a body?
A. Adding more protons to a positively charged body until the number of protons matches the number of elec
B. Adding free electrons to a positively charged body
C. Allowing free electrons to escape from a negatively charged body
D. Bringing the charged body into contact with another body having an equal but opposite charge
Answer:
B. Adding more protons to a positively charged body until the number of protons matches the number of electrons
Explanation:
Felipe walks from the house to his truck on the way to work. He walks 20m to the truck and another 60m in his truck for a total of 20s. What is Felipes average velocity over the 20s period? What is Felipes average speed over the 20s period?
Answer:
Felipe's average speed over the 20s period is 14.4 km/h.
Explanation:
To determine the speed at which Felipe has walked, the distance traveled and the time it took him must be considered.
Thus, Felipe walked 80 meters (20 towards the truck, and 60 inside it) in a total of 20 seconds. That is, he traveled 4 meters per second (80/20 = 4).
Now, to transfer said speed to kilometers per hour, the following calculation must be performed:
1 hour = 60 minutes
1 = 60 seconds
Number of seconds in an hour: 60 x 60 = 3600
Thus, Felipe has walked at an average speed of 14,400 meters per hour (4 x 3,600 = 14,400). So, since a kilometer consists of 1000 meters, its average speed in kilometers per hour was 14.4 km / h (14,440 / 1,000 = 14.4).
Answer: the answer is 4.0 for both
Explanation: on khan academy !!!
Which statement describes a characteristic of an experimental design that
will improve the quality of the results?
Answer:
A.
Ok, suppose an experiment where you have a lot of dependent variables.
something like the variables y, z and k that change when you change the variable x.
Now, as you play with the variable x, you will notice changes in the variables z, y and k.
But there is now a question (a lot actually)
if the change in k was actually caused by the change in z?
Then you need to try to find a way of changing the value of z for a fixed value of x (designing an experiment) and see how k reacts.
This may be really hard, so as few responding variables you have, the simpler is the experiment, and easier will be to collect good data.
Now we also could discard the other options:
B: If the procedure is complex, then there are more ways in which the scientist can make a mistake that will introduce error to the data, so this will not improve the quality.
C: A larger sample will allow you to have more precision, as more subjects are being observed.
D: When we manipulate one variable, we may be actually introducing some quantity of error to the data.
For example, if the quantity is the voltage for an experiment, we actually do not know the exact voltage tath comes from the source, so there is a small source of error. Now as we start adding more and more independent variables, we also are adding more of these sources of errors, so an experiment with several independent variables will not improve the quality of the results.
How does the use of vectors
allow you to compare,
translate, and determine the
motion of a object?
Answer:
Explanation:
A vector is any substance that has both magnitude and direction. lndeed a vector quantity has both magnitude and direction. Example of a vector quantity is velocity. Determining the velocity of an object allows one to determine how fast and in what direction the object moves. Velocity also affords the opportunity to compare the motion of more than one vectors.
A train that is 268.7 m long undergoes constant acceleration the moment the last car (end of
the train) is outside of the station, how far is the front of the train from the station after 25.0 s
if its initial speed before acceleration is 4.48 m/s and its final speed is 27.4 meters per second?
Answer:
its 667m just took the test
Explanation:
otential difference ΔVΔV exists between the inner and outer surfaces of the membrane of a cell. The inner surface is negative relative to the outer surface. If 2.70×10−20 J2.70×10−20 J of work is required to eject a positive sodium ion (Na+)(Na+) from the interior of the cell, what is the magnitude of the potential difference (in millivolts) between the inner and outer surfaces of the cell?
Answer:
The value is [tex]V =168.75\ millivolt [/tex]
Explanation:
From the question we are told that
The workdone is [tex]W= 2.70 * 10^{-20 } \ J[/tex]
Generally charge on the positive sodium ion is equivalent to the charge on a proton, the value is [tex]e = 1.60 *10^{-19} \ C[/tex]
Generally the potential difference between the inner and outer surfaces of the cell is mathematically represented as
[tex]V = \frac{W}{e}[/tex]
=> [tex]V = \frac{2.70 * 10^{-20 } }{1.60 *10^{-19} }[/tex]
=> [tex]V = 0.16875 \ V[/tex]
converting to millivolt
[tex]V = 0.16875 * 1000 [/tex]
=> [tex]V =168.75\ millivolt [/tex]
