convert86400secs into day​

Answers

Answer 1

Answer:

86400 seconds is equal to 1 day.

Explanation:


Related Questions

how did the ptolemaic model explain the apparent retrograde motion of the planets? the planets resided on giant spheres that sometimes turned clockwise and sometimes turned counterclockwise. the planets resided on giant spheres that sometimes turned clockwise and sometimes turned counterclockwise. the planets sometimes stopped moving and then reversed to move backward along their circular orbits. the planets sometimes stopped moving and then reversed to move backward along their circular orbits. the model showed that apparent retrograde motion occurs as earth passes by another planet inits orbit of the sun. the model showed that apparent retrograde motion occurs as earth passes by another planet inits orbit of the sun. the planets moved along small circles that moved on larger circles around earth.

Answers

Some planetary phenomena defied explanation by Aristotle's universe model. Retrograde motion was the most obvious of these. Each planet appears to move in reverse at times when it is in retrograde motion, slowing down briefly before picking up speed again. As they move through the sky, planets also get brighter or dimmer. Neither phenomenon could be adequately explained by Aristotle's model.

What is Aristotle's model ?

The celestial and the terrestrial were Aristotle's two divisions of the cosmos. The Earth, Moon, and the region between them, known as the sub lunar region, were all considered to be parts of the terrestrial realm. The terrestrial world was characterized by change and flaws.

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A mineral, as geologists understand the term, is a naturally occurring solid substance with a definable chemical composition and:a fixed crystalline structure

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Answer:

Explanation:

Yes, that is correct! A mineral, as defined by geologists, is a naturally occurring solid substance with a definable chemical composition and a fixed crystalline structure. This definition is based on the idea that minerals have a specific chemical composition and crystal structure that can be used to identify and classify them. The crystalline structure of minerals gives them unique physical properties, such as hardness, luster, and cleavage, that can be used to distinguish them from other substances.

A person with a mass of 11.24 kg is accelerated to 9.15 m/s2. How much force was applied to him.

Answers

Answer:

102.846 Newtons

Explanation:

The equation relating mass, acceleration and force is

F = ma

where

F = force

m = mass

a = acceleration

Given

m = 11.24 kg

a = 9.15 m/s²

F = 11.24 kg x 9.15 m/s²

= 102.846 Newtons

what is the value and the direction of an electric field at a distance of 2.5 m from a 1 nc charge?

Answers

The electric field strength is positive, which means that the direction of the electric field is radially outward from the charge.

What is an electric field?

The electric field strength at a distance r from a point charge q is given by:

[tex]E = k*q/r^2[/tex]

where k is Coulomb's constant, which has a value of approximately[tex]9.0 x 10^9 N m^2/C^2.[/tex]

In this case, we have a point charge [tex]q = 1 nC = 1 x 10^-9 C[/tex]  located at a distance r = 2.5 m.

Substituting these values into the equation above, we get:

[tex]E = (9.0 x 10^9 N m^2/C^2) * (1 x 10^-9 C) / (2.5 m)^2[/tex]

[tex]E = 1.44 x 10^-6 N/C[/tex]

The electric field strength is positive, which means that the direction of the electric field is radially outward from the charge.

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the potential energy of an object u as a function of x looks like the plot shown above. 1)where is the force the biggest in the negative x direction?

Answers

The force on  an object is the rate of decrease in potential energy. Hence, in the plot the region having a negative slope is the one with biggest force. Then, c is correct.

What is potential energy ?

Potential energy of a body is generated by virtue of the position of the object. Hence, this form of energy is stored in the object when it is at rest. When the object starts moving its potential energy converts to kinetic energy.

Force is an external agent acting on a body to change its motion. The relation between potential energy force applied is given as:

F = - dU/dx

where potential energy U = mgh

then

F = - d/dx (mgh)

From the plot of potential energy,

F = -slope.

Hence, the x component with maximum slope have the biggest force. Here, it is the region C.

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which type of power source is typically located on or near customer facilities, requires little distribution infrastructure, and supplies power in the event of an interruption in power from the electric utility?

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The type of power source that is typically located on or near customer facilities, requires little distribution infrastructure, and supplies power in the event of an interruption in power from the electric utility is called a "standby generator."

Standby generators are usually powered by natural gas, propane, or diesel fuel and are designed to automatically start up and supply electricity to critical loads in the event of a power outage. They are commonly used in commercial and industrial facilities, as well as in residential homes where power outages may cause significant inconvenience or even health and safety risks. Standby generators can be sized to provide backup power to an entire facility or only to specific critical loads, depending on the customer's needs and budget.

Standby generators are typically fueled by natural gas, propane, or diesel fuel, and can be sized to meet the specific power needs of the facility. They can be connected to the facility's electrical system through a transfer switch, which allows the generator to automatically switch on in the event of a power outage, and then switch back to utility power once it is restored. Standby generators are an important part of a facility's emergency preparedness plan, and can help ensure that critical operations are not interrupted during power outages.

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Time and velocity are both vectors. True or false?

Answers

Answer:

false

Explanation:

only velocity  vector

Answer:

false

Explanation:

if the motorcycle has a deceleration of and its speed at position a is , determine the magnitude of its acceleration when it passes point b.

Answers

If the motorcycle has a deceleration of and its speed at position a is, then the magnitude of its acceleration when it passes point b will be two times of a.

Acceleration is a physical quantity that describes how quickly the velocity of an object is changing. More specifically, it is the rate of change of velocity with respect to time.

In mathematical terms, acceleration is defined as: a = Δv / Δt where a is the acceleration, Δv is the change in velocity, and Δt is the change in time. Acceleration is a vector quantity, meaning that it has both magnitude and direction. The SI unit for acceleration is meters per second squared (m/s²).

If an object is moving in a straight line and its velocity is increasing, its acceleration is said to be positive. If its velocity is decreasing, its acceleration is said to be negative. If the object is changing direction, its acceleration will also have a component in the direction perpendicular to the change in direction.

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an underwater vehicle has eightsensors, each having a 5 m range. the speed of sound in water is 1482 m/s. compute the frequency of measurement cycles, a cycle being one complete series of measurements from all eight sensors.

Answers

The frequency of measurement cycles is 148.2 Hz, a cycle being one complete series of measurements from all eight sensors.

Given the range of each sensor= 5m

The speed of sound in water = 1482m/s

Let the frequency cycles = n

The frequency of measurement cycles is based on the time it takes for sound waves to travel from each sensor to the vehicle and back.

The round trip time for each sensor is 2 x 5 m = 10 m, divided by the speed of sound in water, 1482 m/s. The result is [tex]6.73 * 10^{-3}[/tex]seconds or 6.73 milliseconds.

The frequency of measurement cycles is then [tex]1/6.73 * 10^{-3}[/tex], which is 148.2 Hz (cycles per second).

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if an energy transfer takes place due to a temperature difference, the energy crossing the boundary of the system is in the form of . multiple choice question. pressure heat work mass momentum

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If a temperature differential causes an energy transfer, heat is the form in which the energy travels across the system's border. Hence, the appropriate choice is (b).

When there is a temperature difference between two systems, heat energy can flow from the hotter system to the colder system. Heat is a form of energy that is transferred due to the difference in temperature between two systems. This energy transfer is caused by the random motion of the particles in the system. When there is a temperature difference between two systems, the particles in the hotter system have a higher kinetic energy than the particles in the colder system. This leads to the transfer of heat energy from the hotter system to the colder system, until both systems reach thermal equilibrium, i.e., they reach the same temperature and the net heat flow stops.

Therefore, when there is an energy transfer due to a temperature difference, the energy crossing the boundary of the system is in the form of heat.

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Question - If an energy transfer takes place due to a temperature difference, the energy crossing the boundary of the system is in the form of. Multiple choice question, choose one:-

(a) pressure

(b) heat

(c) work

(d) mass

(e) momentum

gootwo identical speakers are spaced 12 m apart, aimed toward each other. they each play a 171.5 hz tone with the same phase constant. if you stand at the center point between the speakers, what is the result of superposition of the sound waves from the speakers?

Answers

The speaker is construction interference is 0 and  destructive interference is 0.5.

a) The Center point of speaker between the speakers of the sound waves from the speaker is construction interference is 0.

b) Condition of destructive interference path difference -x/2.

6 + x - 6 + x = x/2

2x = x/2

x=x/4

x=v/uρ

x=343 / 171.5 x 4

x = 0.5m from the midpoint

Construction interference refers to any type of obstacle or hindrance that interferes with the construction process. It can arise from a range of sources such as natural disasters, design deficiencies, unforeseen conditions, or third-party actions. When there is interference, it could result in project delays, increased costs, and reduced productivity.

Construction interference can be caused by several factors, including the site location, weather conditions, poor management, poor communication between team members, poor planning, and materials shortage. For instance, poor management could lead to the lack of coordination among the workforce, while poor communication between the team members could result in duplication of work or rework, leading to delays in the project schedule.

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Complete Question:-

Two identical speakers are spaced 12 m apart, aimed toward each other. They each play a 171.5 Hz tone with the same phase constant. A. If you stand at the center point between the speakers, the result of superposition of the sound waves from the speakers is constructive inteference. Explain. B. How far must you move from the center toward one of the speakers in m to reach the next point of destructive interference?

an object whose center of gravity is below its point of support, will be in neutral equilibrium. true false

Answers

An object whose center of gravity is below its point of support will be in neutral equilibrium is a False Statement.

An object whose center of gravity is below its point of support will be in stable equilibrium, not neutral equilibrium. In stable equilibrium, if the object is displaced slightly from its equilibrium position, it will tend to return to that position. Neutral equilibrium occurs when the center of gravity is directly above the point of support, in which case the object will remain in its displaced position if moved slightly. Finally, unstable equilibrium occurs when the center of gravity is above the point of support, in which case the object will tend to fall over if displaced slightly.

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in a gas expansion, 87 j of heat is released to the surroundings, and the internal energy of the system decreases by 128 j. calculate the work done by the gas.

Answers

The work done by the gas is - 41 J.

As per the data given:

There is a gas expansion.

During this gas expansion 87 j of heat is released to the surroundings.

Heat = 87 j

Also the internal energy of the system decreases by 128 j.

Change in energy Δv = 128 j

Here we have to determine the work done by the gas.

Δv = Heat + work done by the gas

Work done by the gas = Heat - Δv

Work done by the gas = (128 - 87) J

= 41 J

As the the internal energy of the system decreases and gas is expanded  so the work done by the gas will be negative.

Therefore Work done by the gas = - 41 J

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Identify each lettered part of the circuit, and explain what each part does.

Help please!!!

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The 3 main parts of an electric circuit and their functions are:

Power source - Either electrical or battery, provides the power to the load.

Conducting path - The wires, carry the power from the power source to the load

Load - The device using the electricity such as a computer, light bulb, power saw, etc. More complicated circuits use switches, such as light switches, to control the flow of electricity.

What is an electric circuit?

A circuit that solely has resistors and perfect current and voltage sources is said to be resistive. Analysis of circuits without capacitors and inductors is more difficult than analysis of circuits with those components. A DC circuit will result if the sources are constant (DC) sources. Any arbitrary resistor network's effective resistance and current distribution qualities can be characterised in terms of its graph measurements and geometrical characteristics.An electronic circuit is a network of functional electronic components. Since such networks are typically nonlinear, more sophisticated design and analysis methods are needed.

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a charge of 21 nc is uniformly distributed along a straight rod of length 3.6 m that is bent into a circular arc with a radius of 2.5 m. what is the magnitude of the electric field at the center of curvature of the arc?

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A straight rod of length 3.6 m is bent into a circular arc with a radius of 2.5 m, dispersing a charge of 21 nc evenly throughout its length. The strength of the electric field at the arc's curvature center is 11.868 N/C.

l=rθ

3.6=2.5θ

θ=82.5°

E=[tex]\frac{\lambda }{4\pi E_{o}r }(sin\frac{\theta }{2} +sin\frac{\theta }{2} )[/tex]

E=[tex]\frac{a/l }{4\pi E_{o}r }(2 sin\frac{\theta }{2} )[/tex]

E=[tex]\frac{9*10^{9} }{2.5}*\frac{21*10^{-9}}{3.6} (2 sin\frac{82.5 }{2} )[/tex]

E=11.868 N/C

In physics, an electric field is a fundamental concept that describes the effect of electric charges on the space around them. Electric fields arise due to the presence of charged particles or electrically charged objects. The electric field is a vector field that describes the force experienced by a charged particle at any given point in space. The strength of the electric field is measured in units of volts per meter (V/m) and is directly proportional to the amount of charge and inversely proportional to the distance between the charges. The electric field plays a critical role in a variety of physical phenomena, including electric motors, electronics, and the behavior of charged particles in particle accelerators.

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A 1000 kg car traveling South at 20.0 m/s collides with a 1200 kg car traveling East at 20.0 m/s. The
two vehicles entangle after the collision and head off as one. What is the velocity of the combined
wreckage immediately after the collision?

Answers

The velocity of the combined wreckage immediately after the collision is approximately 10.91 m/s to the East and 9.09 m/s to the South.

How to solve this problem

First  we can use the , which states that the total momentum of a system is conserved in the absence of external forces. In this case, the system is the two cars before and after the collision.

The total momentum of the system before the collision can be calculated as the vector sum of the momenta of the two cars, where the momentum of each car is the product of its mass and velocity:

P_total,before = P_car1 + P_car2

where

P_car1 = m_car1 * v_car1_south (momentum of the first car, traveling South)P_car2 = m_car2 * v_car2_east (momentum of the second car, traveling East)

Substituting the given values, we have:

P_car1 = 1000 kg * 20.0 m/s * (-j) = -20,000 kg·m/s·j (using the South direction as the negative j direction)

P_car2 = 1200 kg * 20.0 m/s * i = 24,000 kg·m/s·i (using the East direction as the positive i direction)

Note that we are using a coordinate system where the x-axis is pointing East and the y-axis is pointing North, so the unit vectors i and j represent the East and North directions, respectively.

Thus, the total momentum of the system before the collision is:

P_total,before = -20,000 kg·m/s·j + 24,000 kg·m/s·i

= (-20,000 kg·m/s) j + (24,000 kg·m/s) i

After the collision, the two cars entangle and move as one object with a common velocity. Let's call this velocity v_combined. The momentum of the combined wreckage can be expressed as:

P_total,after = (m_car1 + m_car2) * v_combined

Substituting the given values, we have:

P_total,after = (1000 kg + 1200 kg) * v_combined

= 2200 kg * v_combined

According to the conservation of momentum, the total momentum of the system is conserved before and after the collision. Therefore, we can set the total momentum before the collision equal to the total momentum after the collision:

P_total,before = P_total,after

Solving for v_combined, we get:

v_combined = P_total,before / (m_car1 + m_car2)

Substituting the previously calculated values, we have:

v_combined = (-20,000 kg·m/s j + 24,000 kg·m/s i) / (1000 kg + 1200 kg)

= (-20,000/2200) m/s j + (24,000/2200) m/s i

= -9.09 m/s j + 10.91 m/s i

Therefore, the velocity of the combined wreckage immediately after the collision is approximately 10.91 m/s to the East and 9.09 m/s to the South.

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The SI unit for force is 1 Newton= 1kg x 1 m/s2 (N). The SI unit for work is _ 1NM _______(J)


I need help with these two:)

Answers

W= F x D indicates the relationship between force, distance and work.

What is work?

Work is defined as an activity in which one exerts force to do something. Work is also refers to an activity in which a person do something regularly to earn a livelihood. People looking for work, a particular task, duty, or assignment often being a part of some larger activity.

The definition of work in physics shows its relationship to energy. When work is done, energy is transferred from one place to another. Work is also known as the product of the force in the direction in which  displacement is covered and displacement.

So we can conclude that Work is the product of Force and Distance.

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45. Two football players collide. The offensive player, mass= 100, was running at

8. 00 m/s. A defensive player catches up to the offensive player from behind.

The defensive player was traveling 11 m/s when he tackled the other player.

a. What was the speed of the two players after the collision?

b. What impulse is felt by each player?

c. If the collision lasted 0. 05 seconds, then what was the force felt by each player?

Answers

You may use the impulse-momentum theorem to: Momentum shifts are impulses. It is known that the impulse is 0.05 Ns (1008+10011). As a result, each participant applied a force of 1008 + 10011 N split by 0.05.

What is the impulse momentum theorem's equation?

P equals F net t. The equation is also known as that of the impulse-momentum theorem. F net t F net t is referred to as the impulse. According to the equation, the impulse is equal to the average force on an object times how long it takes for that force to act. It is equivalent to the momentum shift.

What is an example of the impulse momentum theorem?

The usage of side airbags in cars is one such. In cars, air bags are employed because they may reduce the impact. of the force acting on a collision-involved item. Air bags make this possible by lengthening the length of time it takes so stop the driver and passenger's motion.

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does the distance between charged objects affect the magnitude of electrostatic interactions between them? what relevant evidence have you seen? explain how the evidence that you cite tells us that the distance between charged objects affect the magnitude of electrostatic interactions.

Answers

Yes, the distance between charged objects affects the magnitude of electrostatic interactions between them.

The relevant evidence is based on Coulomb's Law, which states that the electrostatic force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The formula for Coulomb's Law is:

F = k * (q1 * q2) / r^2

where F is the electrostatic force, q1 and q2 are the charges of the two objects, r is the distance between them, and k is Coulomb's constant (a fundamental constant in physics).

The evidence for this relationship is observed through various experiments, such as:

The experiment involving charged conductors: Two charged conductors were placed at a certain distance from each other, and the magnitude of the electrostatic force between them was measured. The experiment was repeated several times, each time with the conductors placed at a different distance from each other. The results showed that the magnitude of the electrostatic force decreased as the distance between the conductors increased, and it followed an inverse square law relationship.

The experiment involving charged balloons: Two balloons with the same charge were suspended from a ceiling and were initially close to each other. When the balloons were moved away from each other, the electrostatic force between them decreased. This indicated that the force was dependent on the distance between the balloons.

The experiment involving charged particles: Particles with opposite charges were accelerated toward each other, and the force between them was measured at different distances. The results showed that the force decreased as the distance between the particles increased, following an inverse square law relationship.

These experiments provide evidence that the distance between charged objects affects the magnitude of electrostatic interactions. As the distance between the objects increases, the force between them decreases, according to Coulomb's Law. This relationship is fundamental to our understanding of electrostatic interactions and is applied in various fields, such as electricity and magnetism, particle physics, and chemistry.

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Find the time for a pulse of laser light to reach the Moon and to bounce back to Earth Express your answer to two significant figures and include the appropriate units

Answers

The time for a pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s.

What is a laser light?

A laser light is a light produced by a laser, which is a device that amplifies and emits light by the process of stimulated emission. Laser light is highly directional and has a narrow beam, making it useful for many applications such as cutting, drilling, and welding. It can also be used to measure distances, scan barcodes, and measure speed. Laser light has a high intensity and is monochromatic, meaning it contains a single wavelength of light.

The speed of light is approximately 3.0 x 10^8 meters/second. The distance from the Earth to the Moon is approximately 3.8 x 10^8 meters. Therefore, the time for a pulse of laser light to reach the Moon is approximately 1.3 seconds, and the time for the light to bounce back to Earth is also approximately 1.3 seconds. The total time for the pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s, to two significant figures.

Therefore, the time for a pulse of laser light to reach the Moon and to bounce back to Earth is 2.6 s.

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It will take around 2.5 seconds for a pulse of laser light to reach the moon and bounce back to Earth.

What is Light?

Electromagnetic energy that can be seen by the human eye is known as light or visible light. [1] Typically, visible light is described as having wavelengths between 400 and 700 nanometers (nm), or frequencies between 750 and 420 terahertz, which fall between the longer-wavelength infrared and the shorter-wavelength ultraviolet (with shorter wavelengths).

There are 380,500 kilometres on average between the surface of the moon and the earth (km). In a vacuum, light, which is an electromagnetic wave, moves at a pace of about 3 x 108 m/s. The time it takes for a laser pulse to move from the earth to the moon is time = distance/speed because distance = speed*time. Round-trip duration is equal to 2*(distance/speed). Thus, time=2*(38500 x 103 m / 3 x 108 m/s) = 2.56 s is the result of the computation.

Therefore, A pulse of laser light will take around 2.5 seconds to reach the moon and bounce back to Earth.

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A 1.53 kg box is sliding to the right at a constant velocity of 15.44. If the box has a force 80.18 applied to the right, what is the magnitude of the force of friction?

Answers

The magnitude of the force of friction is 80.18 N.

traction refers to the: a) amount of weight able to be towed b) grip of the tire on the road c) rating of the engine d) wind resistance of the car

Answers

Traction refers to the grip of the tire on the road.

The correct option is B.

The definition of traction is the strength with which something holds onto something and advances without slipping or tugging. A tyre is said to have strong traction when it glides over the road's surface easily and grips firmly.

It refers to the ability of the tire to maintain contact with the road surface and provide the necessary grip to accelerate, brake, and turn the vehicle. Factors that affect traction include the quality and condition of the tires, road surface conditions, and driving style.

adhesion between a body and a surface, such as a tyre on a road or a wheel on a rail.

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Which one of the following properties most fundamentally distinguishes mechanical waves from electromagnetic waves? a. Mechanical waves have crests and troughs. b. Mechanical waves require a medium for propagation. c. Mechanical waves have well-defined wavelengths. d. Mechanical waves move at a finite speed.

Answers

The property that most fundamentally distinguishes mechanical waves from electromagnetic waves is that mechanical waves require a medium for propagation.

Mechanical waves are waves that propagate through a material medium, such as water, air, or a solid, and are caused by disturbances that propagate through the medium, such as vibrations or oscillations. This is in contrast to electromagnetic waves, which do not require a material medium and can propagate through a vacuum.

While mechanical waves do have crests and troughs, well-defined wavelengths, and move at a finite speed, these properties are not unique to mechanical waves and are also observed in electromagnetic waves. For example, electromagnetic waves also have crests and troughs, well-defined wavelengths, and move at a finite speed. However, they do not require a medium for propagation, which is the key difference between the two types of waves.

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where would you expect terrestrial planets to form in the solar nebula?

Answers

You expect terrestrial planets to form in the solar nebula in the inner part of the protoplanetary disk.

The solar nebular disc theory proposes that rocky planets develop in the inner region of the protoplanetary disc, near the frost line, where the temperature is high enough to prevent the condensing of water ice and other components into grains.

As a result, only rocky grains coagulate, and later, rocky planetesimals are created. These circumstances are thought to exist in the inner 3–4 AU region of the disc of a star similar to the Sun.

According to the so-called nebular hypothesis for the origin of the solar system, the Sun and planets were formed by condensation from the solar nebula, a gaseous cloud.

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a banjo band radiates sound at a maximum loudness of 67.05 w. what is the intensity of these sounds waves to a listener 93.52 m from the band?

Answers

The intensity of the sound waves to a listener 93.52 m from the band is approximately [tex]6.75 *10^{-7} W/m^2[/tex].

The formula for sound intensity is:

[tex]I = P/(4\pi r^2)[/tex]

where I is the intensity of the sound, P is the power of the sound source, and r is the distance from the sound source.

In this case, the power of the banjo band is 67.05 W, and the distance from the listener to the band is 93.52 m. Substituting these values into the formula, we get:

[tex]I = 67.05 W/(4\pi(93.52 m)^2)[/tex]

Simplifying this expression, we get:

[tex]I = 6.75 *10^{-7} W/m^2[/tex]

Therefore, the intensity of the sound waves to a listener 93.52 m from the band is approximately [tex]6.75 *10^{-7} W/m^2[/tex]. This is a relatively low value, as the threshold of hearing for most humans is around [tex]1 * 10^{-12} W/m^2[/tex]. However, the actual loudness of the sound heard by the listener will also depend on the sensitivity of the human ear and other factors.

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1. a charge of -2.50 nc and a charge of -4.00 nc are placed 50.00 mm apart. find the resultant force on a charge of 8.00 nc placed 20.00 mm from the -2.50 nc charge and 30.00 mm from the -2.50 nc charge.

Answers

The resultant force on the 8.00 nC charge is -0.010 N.

Using Coulomb's law, the electric force between two point charges is given by,

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.

The force on the 8.00 nC charge due to the -2.50 nC charge:

F1 = k * ((8.00 nC) * (-2.50 nC)) / (0.020 m)^2

= -0.090 N

Note that the negative sign indicates an attractive force, as the charges have opposite signs.

The force on the 8.00 nC charge due to the -4.00 nC charge,

F2 = k * ((8.00 nC) * (-4.00 nC)) / (0.030 m)^2

= -0.080 N

Add these forces vectorially. Since the forces are acting in opposite directions,

Fnet = F1 - F2

= -0.090 N - (-0.080 N)

= -0.010 N

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Sort each of the five terrestrial bodies into the appropriate category based on the type of atmosphere it currently retains, if any. secondary atmosphere, no atmosphere - venus, - earth,- mars- mercury, - earths - moon

Answers

Secondary atmosphere- venus, earth, mars

No atmosphere- mercury, earth's moon

What is the atmosphere?

The atmosphere is the layer of gases that surrounds the Earth and is held in place by gravity. It is composed of several different gases, including nitrogen (78%), oxygen (21%), and trace amounts of other gases such as carbon dioxide, neon, helium, and hydrogen.The atmosphere plays a critical role in sustaining life on Earth. It protects the planet from harmful radiation from the sun, regulates the temperature, and provides the air that humans and other organisms breathe. It also serves as a medium for weather and climate patterns, including wind, precipitation, and atmospheric pressure.The atmosphere is divided into several layers based on temperature and composition, including the troposphere, stratosphere, mesosphere, thermosphere, and exosphere. Each layer has unique characteristics and plays a specific role in the Earth's atmosphere and climate.

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Venus: Venus has a surface temperature of about 737 K (464 °C, or 867 °F), and its atmosphere is composed of roughly 96 percent carbon dioxide. On Venus, clouds are composed of sulphuric acid (H2SO4) and move in an easterly direction at a speed of about 100 m/s (224 miles per hour).

Earth: The atmosphere of Earth has five layers and is made up of nitrogen, oxygen, water vapour, carbon dioxide, and other trace elements. The troposphere, stratosphere, mesosphere, thermosphere, and exosphere are among them. As one ascends higher into the atmosphere and moves away from the surface, air pressure and density generally decline.

Mars: The planet has a narrow atmosphere that is primarily made of diatomic nitrogen and contains about 95% carbon dioxide. There are also traces of water vapour.

Mercury: It is too hot and too small to retain an atmosphere . However, it does have a tenuous and variable exosphere that is made up of hydrogen, helium, oxygen, sodium, calcium, potassium and water vapour.

Earth’s Moon: Until recently, most everyone accepted the conventional wisdom that the moon has virtually no atmosphere.

What is the Atmosphere?

An Atmosphere is a layer of gas or layers of gas that surround a planet and are kept in place by the gravity of the planetary body. When the gravity is strong and the temperature of the atmosphere is low, a planet maintains its atmosphere. The outer region of a star, which contains the layers above the opaque photosphere, is known as the stellar atmosphere ; low-temperature stars may have outer atmospheres with compound molecules.

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A 600 g bat is swung quickly and hits a 150 g baseball. Which is true? a. The bat exerts a larger force on the ball than the ball exerts on the bat. b. The bat exerts a force on the ball, but the ball does not exert a force on the bat. c. The bat exerts the same amount force on the ball as the ball exerts on the bat.d. The bat exerts less force on the ball than the ball exerts on the bat.

Answers

Answer:

C) Each exerts an equal force on each other - Newton's Third Law states that for every action there is an opposite and equal reaction.

what if? if the woman still pulls on the strap with a 34.5 n force but wishes to accelerate the suitcase at a rate of 0.500 m/s2, at what angle (in degrees) must she pull on the strap? assume that the rolling friction is independent of the angle of the strap.

Answers

The angle at which the woman pull on the strap with a 34.5N force but wishes to accelerate the suitcase at a rate of 0.500 m/s2 is 0°

Given:

F = 34.5 N

Friction force = 20.0 N

m = 16.5 kg

The net force, Fnet, must be equal to the mass of the suitcase, 16.5 kg, times the acceleration, 0.500 m/s^2, or 8.25 N.

Fnet = ma

8.25 N = 16.5 kg * 0.500 m/s^2

The net force, Fnet, will be equal to the force of the strap, F, minus the friction force, Ffriction, or 34.5 N - 20.0 N = 14.5 N.

Fnet = F - Ffriction

14.5 N = 34.5 N - 20.0 N

To find the angle, θ, at which the strap must be pulled, we can use the following equation:

Fnet = Fcosθ - Ffriction

14.5 N = 34.5 Ncosθ - 20.0 N

Solving for θ, we get:

θ = 0°

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complete question: A woman at an airport is towing her 16.5 kg suitcase at a constant speed by pulling on a strap at an angle θ above the horizontal (see figure). She pulls on the strap with a 34.5N force, and the friction force on the suitcase is 20.0 N. A woman holds the strap of a suitcase while pulling it to the right. The strap makes an angle θ measured counterclockwise from the horizontal. What If? If the woman still pulls on the strap with a 34.5 N force but wishes to accelerate the suitcase at a rate of 0.500 m/s2, at what angle (in degrees) must she pull on the strap? Assume that the rolling friction is independent of the angle of the strap

the block in the image has a mass of 1.00 kg. the coefficient of static friction between the block and the inclined plane is 0.675. the plane makes an angle of 39o with the horizontal direction. what is the minimum force that can be applied to the block to keep it from sliding down the plane?

Answers

The minimum force that can be applied to the block to keep it from sliding down the plane is 6.06 N. Any force greater than this value will cause the block to move down the plane.

To find the minimum force required to keep the block from sliding down the inclined plane, we need to calculate the maximum force of static friction that can act on the block, which is equal to the force required to keep the block at rest.

The maximum force of static friction is given by:

[tex]F _{friction}[/tex] = friction coefficient x N

where N is the normal force acting on the block, which is equal to the component of the weight of the block that is perpendicular to the plane. This can be calculated as:

N = m * g * cos(theta)

where m is the mass of the block, g is the acceleration due to gravity, and theta is the angle of the plane with respect to the horizontal.

In this problem, m = 1.00 kg, g = 9.81 m/[tex]s^{2}[/tex], and theta = 39 degrees. We need to convert the angle to radians before we can use it in the equation, which gives:

theta = 39 degrees = 0.68 radians

Substituting these values into the equation for N, we get:

N = m * g * cos(theta) = 1.00 kg * 9.81 m/[tex]s^{2}[/tex]  * cos(0.68) = 8.97 N

Now we can use the equation for the maximum force of static friction to find the minimum force required to keep the block at rest:

[tex]F _{friction}[/tex] = friction coefficient x N = 0.675 * 8.97 N = 6.06 N

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