__________ could be the formula of an alkene. a. c3h8 b. c2h8 c. c6h6 d. c3h6 e. c17h36

The number of seconds in a 40-hour work week can be  c. 40 h x

You work a regular 40-hour workweek (eight hours a day).

That persisted up until 1926, when Henry Ford let his workers off the hook for one day of obligatory labour. Eight-hour days and six-day weeks totaled 48 hours of labour each week for Ford employees. The 40-hour workweek, as it is currently known, was created by eliminating one day and replacing it with five days of eight-hour shifts.

Four nine-hour days followed by an eight-hour Friday is the most typical pattern for doing this. The next week consists of four nine-hour days and a Friday off.

A full-time employee is one who works an average of at least 30 hours per week for the duration of a calendar month in order to qualify under the employer shared responsibility laws.

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Answer:

10.5 g

Explanation:

mass= vol × density

m= (1.5×2×5) × 0.7 g/mL

m= 15 × 0.7 g/mL

m= 10.5 g

i hope its correct^^!

Sample methane gas of contains more hydrogen atoms at STP.

At STP a 22.4 liter sample of gas contains the same number of molecules as one mole.

At standard temperature and pressure 1 mol of gas occupied 22.4 liters.

Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

V(CH4) = 1 L; volume of methane gas

n(CH4) = V(CH4) ÷ Vm.

n(CH4) = 1 L ÷ 22.4 L/mol.

n(CH4) = 0.045 mol; amount of methane

In one methane molecule, there are four hydrogen atoms.

n(H) = 4 × 0.045 mol

n(H) = 0.18 mol; amount of hydrogen atoms in 1 liter of methane

n(H2) = 1 L ÷ 22.4 L/mol.

n(H2) = 0.045 mol; amount of hydrogen molecule

In one hydrogen molecule, there are two hydrogen atoms.

n(H) = 2 × 0.045 mol

n(H) = 0.090 mol; amount of hydrogen in 1 liter of hydrogen gas

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The new concentration of the solution of HCl diluted to 750 mL is 0.76 M

To solve this problem, the formula and the procedure that we have to use is:

c1 * v1 = c2 * v2

Where:

Information about the problem:

Applying the dissolution of concentrations formula and clearing the concentration of the diluted solution(c2), we get:

c1 * v1 = c2 * v2

6.0 M * 95 mL = c2 * 750 mL

c2 = (6.0 M * 95 mL) / 750 mL

c2 = 0.76 M

In chemistry a dissolution is known as a homogeneous mixture of two or more components called:

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The molecular formula of a compound with the empirical formula [tex]C_{3}H_{7}[/tex]and a molar mass of 215.50 g/mol is [tex]C_{15}H_{35}[/tex].

A substance's molecular formula describes the kind and number of atoms of each element present in a molecular compound. The empirical formula and the molecular formula are typically the same. The empirical formula for methane is [tex]CH_{4}[/tex] because it only contains one carbon atom, which is also its molecular formula.

The molecular formula is the most useful when you want to know how many atoms of each element are present in the molecule. Since it offers more details than the empirical formula, it is more common. The importance of the molecular formula increases while working with organic chemistry.

The formula for the molecular formula is the molar mass/ empirical formula

So, the empirical formula of [tex]C_{3}H_{7}[/tex]=  C × 3 + H × 7

[tex]C_{3}H_{7}[/tex] = 12×3 + 1 × 7

[tex]C_{3}H_{7}[/tex] = 43

Then use the molecular formula = 215.50 / 43 = 5.01

Therefore, the molecular formula is 5 times the empirical formula which is [tex]C_{15}H_{35}[/tex].

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No, the atoms in buta-1,3-diene don't stay on the same plane due to steric repulsion, infract they change and rotate their planes and lie in separate planes.

What is same plane?

Since atoms with a pi bond cannot spin, they will all be in the same plane if they have a double or triple bond. The atoms also lie in the same plane if they are either trigonal or square planar.

Diatomic and triatomic molecules, as well as those that, with the exception of hydrogen, only exhibit sp2 and/or sp hybridization. Trigonal planar molecules (BF3) and typical diatomic molecules (CO2) will both be in the same plane.

The C-H bond twists as a result of sterric repulsion, moving the hydrogen atoms further from the molecular plane (like Ortho effect). However, there would be little to no sterric repulsions in the case of trans 1,3-butadiene, causing all atoms to lay in a single plane.

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The amount of energy released (to the nearest tenth) is 23.8 MJ

C₃H₈ + 5O₂ --> 3CO₂ + 4H₂O ΔH = 2043.9 KJ

Molar mass of C₃H₈ = (3 × 12) + (8 × 1) = 36 + 8 = 44 g/mol

Mass of C₃H₈ from the balanced equation = 1 × 44 = 44 g

Thus, we can say that:

From the balanced equation above,

44 g of propane were burned to release 2043.9 KJ of energy

From the balanced equation above,

44 g of propane were burned to release 2043.9 KJ

Therefore,

512 g of propane will burn to release = (512 g × 2043.9 KJ) 44 g = 23783.56 KJ = 23783.56 / 1000 = 23.8 MJ of energy

Thus, 23.8 MJ of energy were released from the reaction

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The ratio of the deprotonated form to protonated form is 1 : 100.

Henderson–Hasselbalch equation: pH = pKa + log(cs/ck)

pH = 4.75; pH of buffer solution

pKa = 6.75

4.75 = 6.75 + log(cs/ck)

log(cs/ck) = 4.75 - 6.75 = -2.0

cs/ck = 10⁻² = 0.01; ratio of the deprotonated form to protonated form

A buffer can be defined as a substance that prevents the pH of a solution from changing by either releasing or absorbing H⁺ in a solution.

Buffer is a solution that can resist pH change upon the addition of an acidic or basic components and it is able to neutralize small amounts of added acid or base, pH of the solution is relatively stable.

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The number of protons in an isotope atom does not change but the number of neutrons does. The iron atom has about twenty-eight isotopes. Such as 45Fe, 46Fe, 47Fe, 48Fe, 49Fe, 50Fe, 51Fe, 52Fe, 53Fe, 54Fe, 55Fe, 56Fe, 57Fe, 58Fe, 59Fe, 60Fe, 61Fe, 62Fe, 63Fe, 64Fe, 65Fe, 66Fe, 67Fe, 68Fe, 69Fe, 70Fe, 71Fe and 72Fe.

Among the isotopes, 54Fe (Observationally Stable), 56Fe, 57Fe, and 58Fe are stable and formed naturally. The remaining isotopes of iron are highly unstable and their half-lives are very short.

Isotope Mass number (A) Atomic number (Z) Neutron number = A – Z

45Fe 45.01458 26 19

46Fe 46.00081 26 20

47Fe 46.99289 26 21

48Fe 47.98050 26 22

49Fe 48.97361  26 23

50Fe 49.96299 26 24

51Fe 50.956820 26 25

52Fe 51.948114 26 26

53Fe 52.9453079 26 27

54Fe 53.9396090 26 28

55Fe 54.9382934 26 29

56Fe 55.9349363 26 30

57Fe 56.9353928 26 31

58Fe 57.9332744 26 32

59Fe 58.9348755 26 33

60Fe 59.934072 26 34

61Fe 60.936745 26 35

62Fe 61.936767 26 36

63Fe 62.94037 26 37

64Fe 63.9412 26 38

65Fe 64.94538 26 39

66Fe 65.94678 26 40

67Fe 66.95095 26 41

68Fe 67.95370 26 42

69Fe 68.95878 26 43

70Fe 69.96146 26 44

71Fe 70.96672 26 45

71Fe 71.96962 26 46

Answer:

Protons: 26

Neutrons: 30

Electrons: 24

Explanation:

Assuming the sun's energy is radiated uniformly in all directions,  the total power is (π [tex]r . ^{2}[/tex] * σ[tex]R^{2} T^{4}[/tex])/[tex]r^{2}[/tex]

According to Stefan's law, if the sun were a perfect blackbody, its energy output per second would be:

P=σA[tex]T^{4\left \ }[/tex]

(Where P is energy radiated per second and A is the area of the sun.)

⇒P=σ×4π[tex]R^{2} T^{4}[/tex].............(1)

Assuming r>>r., the strength of this power at the earth's surface is

I= P/4π[tex]r^{2}[/tex]

​⇒I= σ×4π[tex]R^{2} T^{4}[/tex]/4π[tex]r^{2}[/tex]

(Inserting the value obtained from equation (1))

⇒I= σ[tex]R^{2} T^{2}[/tex]/[tex]r^{2}[/tex]

Due to its great distance from the sun, the earth only receives a small portion of the energy that is radiated. The earth can be visualized as a little disc with a radius equal to that of the planet.

The disc's surface area is [tex]r .^{2}[/tex] hence the earth's total radiant energy as received is:

PE=π[tex]r. ^{2}[/tex]×I

P E = (π [tex]r . ^{2}[/tex] * σ[tex]R^{2} T^{4}[/tex])/[tex]r^{2}[/tex]

Assuming the sun's energy is radiated uniformly in all directions,  the total power is (π [tex]r . ^{2}[/tex] * σ[tex]R^{2} T^{4}[/tex])/[tex]r^{2}[/tex]

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The name of the CO32 polyanion is Carbonate.

It frequently appears in limestone. It is found bonded to metals in groups I and II of the periodic table because it cannot exist on its own. The name of the metal to which the compound is bonded is given first, followed by the word carbonate, as in calcium carbonate, sodium carbonate, and so forth. Calcite, also known as limestone, and dolomite, also known as dolostone, are the two different types of carbonates.

Calcite, aragonite, and dolomite are the three groups of common anhydrous (water-free) carbonates that are separated based on their different structural types. The only notable hydrous types are the copper carbonates azurite and malachite.

Anything with more than one negatively charged anion. Any compound with multiple anion moieties, particularly one that is based on a polymer.

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Using the first-order decomposition rate constant, the concentration of [tex]N_2O_5[/tex] after 12.5 minutes is found to be 0.805M.

The concentration of just one reactant determines the outcome of a first-order decomposition process. Even if additional reactants are present, the rate is unaffected by their concentration.

Given:

Rate constant of first-order decomposition, k = 1.70 x [tex]10^-^3 s^-^1[/tex]

Initial concentration of [tex]N_2O_5[/tex] = 2.88 M

Time, t = 12.5 min = 750 s

To Find:

Final concentration of [tex]N_2O_5[/tex] = ?

Formula:

By using the Rate law,

-d[A] / dt = k[A]

Calculations:

ln[[tex]N_2O_5[/tex]]t = - kt + ln[[tex]N_2O_5[/tex]]

= - (1.70 x [tex]10^-^3 s^-^1[/tex]) x 750s + ln2.88

= - 1.275 + 1.058

= - 0.217

[tex]e^\(ln[N_2O_5]t[/tex] = [tex]e^\-0.217[/tex]

= 0.805M

Therefore, the concentration of [tex]N_2O_5[/tex] after 12.5 minutes is 0.805 M.

Result:

The concentration of [tex]N_2O_5[/tex] after 12.5 minutes of reaction is found to be 0.805M

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Answer:

the answer is student 2

Explanation:

the student 2 has the right answer because student 1 is wrong

Atom X possesses eight more electrons than atom Y. Student 1 claims they are in the same class. Student 2 claims to be non-reactive. Students 1 and 2 are both correct.

Therefore,

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A calorimeter initially contains 175.0 ml of water at 23.6oc. when 1.23 g Na is added to the water, the temperature of the resulting solution rises to a maximum of 44.9oc. the reaction that occurs is-2Na(s)+H2O(l)→2NaOH(aq)+H2(g).

A calorimeter is a tool used in the process of calorimetry, which determines heat capacity and measures the heat produced by chemical reactions or other types of physical changes. Differential scanning calorimeters, isothermal micro calorimeters, titration calorimeters, and accelerated rate calorimeters are a few of the most common types.
Simply put, a simple calorimeter is a metal container with a thermometer placed above a combustion chamber. It is one of the measurement instruments used in the research of chemistry, biochemistry, and thermodynamics.
The enthalpy change per mole of a material A in a reaction between two substances A and B is calculated by adding the components separately to a calorimeter and recording the beginning and final temperatures.

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No chemical reaction occurs on combination of sodium sulfate and iron (III) nitrate.

This chemical reaction does not occur since none of the products are solids, insoluble gases, or water. Just aqueous iron (III), sodium, nitrate and sulfate ions are present.

Thus, iron (III) nitrate and sodium sulfate do not interact.

One or more substances, known as reactants, are changed into one or more new substances, known as products, during a chemical reaction. Substances are made up of chemical components or chemical elements. The atoms that constitute the reactants of a chemical reaction are rearranged to create different products.

Combustion, decomposition, neutralization, redox, precipitation or double-displacement, and synthesis are some of the numerous types of chemical reactions that can occur depending on the product that is produced.

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Three different atomic cations that have 22 protons-

Atomic cations are atoms that have a positive electric charge.

(Chromium) Cr has 24 protons therefore, Cr2+ has = 24 - 2 ⇒ 22 protons.

(Manganese) Mn has 25 protons therefore, Mn3+ has= 25-3 ⇒ 22 protons.

(Iron) Fe has 26 protons therefore, Fe4+ has= 26-4 ⇒ 22 protons.

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Cr²⁺, Mn³⁺ and Fe ⁴⁺ are the chemical symbols for three atomic cations with 22 electrons.

The number of protons inside the nucleus always remains constant.

∴Chemical symbol of three different atomic cation that have 22 electrons-  

1. Cr²⁺

2.Mn³⁺

3. Fe⁴⁺

Atomic cation is the ion with positive electric charge on it, it means it should have more protons than electrons.

•Chromium (Cr) has 24 electrons therefore, Cr²⁺ will have = 24- 2 ⇒22 electrons (+2 charge means it will lose 1 electron from its outer shell)

•Manganese (Mn) has 25 electrons therefore, Mn³⁺ will have = 25-3⇒ 22 electrons. (+3 charge means it will lose 3 electrons from its outer shell)

•Iron (Fe)  has 26 electrons therefore, Fe⁴⁺ will have = 26-4 ⇒ 22 electrons. (+4 charge means it will lose 3 electrons from its outer shell)

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Your question is incorrect. It should be - Write the chemical symbols for three different atomic cations that all have 22 electrons.

The ph of the resulting solution Ka = 1.8x10-5 /0.036-x

The e letters pH stand for the potential of hydrogen since pH is effectively a measure of the concentration of hydrogen ions.

a solution is a special type of homogeneous mixture composed of two or more substances.

3 ml x 3.00 M = 250 ml * x M

x = 0.036 M HAc

Ka = 1.8x10-5 /0.036-x

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The levels of protein structure would be affected if all hydrogen bonding interactions were prevented are primary, secondary, tertiary, and quarternary structures.

There are 4 levels of protein structures:

Primary structures: Protein primary structure is the linear sequence of amino acids in a peptide or protein.

secondary structures: Protein secondary structure is the three-dimensional form of local segments of proteins.

tertiary structures: Protein tertiary structure is due to interactions between R groups in the protein.

quarternary structures: Protein quaternary structure is the fourth classification level of protein structure.

The levels of protein structure would be affected if all hydrogen bonding interactions were prevented are primary, secondary, tertiary, and quarternary structures.

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The speed of the fluid in the pipe through the cross-section of 0.105 m² is 5.21 m/s.

The area of the first cross-section is A1.

A1 = 0.70 m²

The area of the second cross-section is A2.

A2 = 0.105 m²

The velocity of the fluid at the first cross-section is V1.

V1 = 3.50 m/s

Let the velocity of the fluid at the second cross-section be V2.

The speed of the fluid in the pipe through the cross-section of 0.105 m² is,

Area of the first cross-section × Velocity of the fluid through the first cross-section = Area of the second cross-section × Velocity of the fluid through the second cross-section

A1 × V1 = A2 × V2

0.070 × 3.50 = 0.047 × V2

[tex]V2 = \frac{0.070 × 3.50}{ 0.047} [/tex]

= 5.21 m/s

Therefore, the speed of the fluid in the pipe through the cross-section of 0.105 m² is 5.21 m/s.

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When water molecules interact, the positively charged hydrogen end of one molecule is attracted to the negatively charged oxygen end of another molecule.

Hydrogen bonding is a type of dipole-dipole attraction between molecules, it was not all the time that a covalent bond to a hydrogen atom.

The attractive force will be very strong between a hydrogen atom and the electronegative atoms i.e., N, O, or F atom, etc., as it was covalently bonded to electronegative atom.

Any molecule that has a hydrogen atom directly attached to an oxygen or nitrogen atom is capable of hydrogen bonding. When hydrogen is bonded to fluorine, the attraction of covalent bond was very well.

So, When water molecules interact, the positively charged hydrogen end of one molecule is attracted to the negatively charged oxygen end of another molecule.

Thus, the answer is positively and negatively respectively.

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C₁₂H₁₂BrO₁N₁ is the molecular formula.

An analytical technique used to measure the mass to charge ratio of the ions is known as mass spectrometry. This is one of the best technique used to analyse the structure of a molecule.  It is used in a a lot of applications such as carbon dating, food contamination detection, isotope detection, protein identification etc.

We have given that,

molecular ion at 265 m/z

another ion seen at 267 m/z

their ratio is 1:1

C₁₃H₉Cl₂ON₁ in this in here Cl have two isotopes that are

36 and 37 but   m/z is not equal to 265

in here C₁₂H₁₂BrO₁N₁  Br have  two isotopes

Br-79,  Br-81 and  m/z equals to 256 and 257

so the molecular formula is therefore  C₁₂H₁₂BrO₁N₁

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your question is incomplete, below you will find the missing content

here the options are not given, so options are

a. C₁₃H₉Cl₂ON₁ b. no isotopic atom  c. C₁₂H₁₂BrO₁N₁

The substance has a molar mass of 122.11 g/mol, an empirical formula of C2H5O2, and a molecular formula of C4 H10 O4.

We can determine the relative atomic ratios in a compound using an empirical formula.

The ratios also hold true at the molar level. H2O is made up of two hydrogen atoms and one oxygen atom.

The same is true for the mole of H2O, which is made up of 1.0 moles of oxygen and 2.0 moles of hydrogen.

Example: The chemical structure of glucose is C6H12O6. Every mole of carbon and oxygen is accompanied by two moles of hydrogen.

Glucose has the empirical formula CH2O.

Ribose has the chemical formula C5H10O5, which can be simplified to the empirical formula CH2O.

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A silent mutation occurs as there is no change according to the blast alignment of the query and subject sequences.

Both the subject sequence's site 1557 and the query sequence's site 1557 are ‘A’. The double-stranded DNA sequence seen above is the sense (+) strand of the pmoc gene, which is predicted to encode pmoc. On translation of the silent mutation gene, the amino acid sequence for the gene is same - glutamine leucine threonine arginine proline arginine proline threonine glutamine alanine valine glycine alanine.

The protein product is unaffected by silent mutations. A nucleotide change still might code for the exact same amino acid as though it had not undergone mutation. The phenotype of both structure and function is maintained when amino acids are constant.

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For unrestrained cube made from linear, isotropic, homogeneous material the temperature increase causes strain in (6,0) direction(s).

It is well known that for unrestrained cube made from linear, isotropic, homogeneous material the temperature increase causes strain in (6,0) direction(s). This is due to the fact that the cube is free to expand in all directions, and thus, the strain is evenly distributed throughout the cube. However, it is interesting to note that the strain in the (6,0) direction is actually slightly greater than in the other directions. This is because the (6,0) direction is the direction of the temperature gradient, and thus, the strain is greater in this direction.

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11.8 grams of H₂O will be produced.

Balanced chemical equation:

MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O

n(MnO₂) = 0.86 mol; amount of manganese(IV) oxide

m(HCl) = 48.2 g; mass of hydrochloric acid

n(HCl) = 48.2 g ÷ 36.5 g/mol

n(HCl) = 1.32 mol; amount of the acid

From balanced chemical equation: n(MnO₂) : n(HCl) = 1 : 4

Hydrochloric acid is limited reactant.

From balanced equation: n(HCl) : n(H₂O) = 2 : 1

n(H₂O) = 1.32 mol ÷ 2

n(H₂O) = 0.66 mol; amount of the water

m(H₂O) = n(H₂O) × M(H₂O)

m(H₂O) = 0.66 mol × 18 g/mol

m(H₂O) = 11.8 g; mass of the water

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The solubility of barium carbonate, BaCo₃ is 4.5 x 10⁻⁵ M.

To find the solubility, the given values are,

Ksp = 2.0·10⁻⁹.

Here, s(BaCO₃) = ?M.

In chemistry, Solubility is the ability of a substance, the solute, to form a solution with another substance, the solvent.

Formula for solubility is,

                           Ksp = [A^+]^a [B^-]^b

Ksp = solubility product constant

A^+ = cation in an aqueous solution

B^- = anion in an aqueous solution

a, b = relative concentrations of a and b

The Chemical reaction of Barium carbonate is :

BaCO₃(s) → Ba²⁺(aq) + CO₃²⁻(aq).

s(BaCO₃) = s(Ba²⁺) =s(CO₃²⁻) = x.

Ksp = s(Ba²⁺) · s(CO₃²⁻).

Ksp = x · x.

2.0·10⁻⁹ = x².

x = √2.0·10⁻⁹

  = 4.47x10⁻⁵ M.

So, The solubility of Barium carbonate is 4.5x10⁻⁵ M.

Hence, Option D is the correct answer.

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By solving for the density of the two metal cubes, we can determine if both cubes are made from the same material.

Density, denoted by ρ, is a property of any substance that is defined as the ratio between the mass and volume of the substance.

ρ = m/v

where ρ = density

m = mass

v =  volume

Solving the density of each cube.

Cube 1 :

ρ = m/v

ρ = m/e^3

ρ = 43. 63 g/(3. 2 cm)^3

ρ = 1.3315 g/cm^3

Cube 2 :

ρ = m/v

ρ = m/e^3

ρ = 683. 5 g/(8. 34 cm)^3

ρ = 1.1783 g/cm^3

If two objects have the same density, then they are made from the same material. Since the density of the two cubes are not equal, then they are not made form the same material.

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It is the name given to the combination of strong and weak nuclear forces.

We know that the nucleus of the atom is the place that houses the greatest amount of energy. We could obtain the highest energy by ripping open the nucleus of an atom. There is a huge energy that holds the particles in the nucleus together and this called the nuclear binding energy.

This energy must also be required to break the nucleus as is the case in the operation of the atomic bond and in nuclear reactors. The true statement about the nuclear energy is that; It is the name given to the combination of strong and weak nuclear forces.

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