Cuánto es 2+2x23(24/6)

Answer:

4

Step-by-step explanation:

The constant is the number without a variable, usually being added or subtracted from the variable but not multiplied or divided by it.

It is saying that irrational numbers like pie can be broken down into approximate irrational numbers and plotted onto points.

Example [tex]\sqrt{1.6}[/tex] approximate value is 1.264911

That number can be plotted in place of [tex]\sqrt{1.6}[/tex]

Given :

Ellen sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pieces.

To Find :

How much does each wedge of cheese weigh.

Solution :

Let , weight of each wedge of cheese is x.

16 pieces of wedge of cheese weight 5 pounds .

So,

[tex]16x=5\\\\x=\dfrac{5}{16}\\\\x=0.3125\ pounds[/tex]

Therefore, weigh of cheese is 0.3125 pounds.

Hence, this is the required solution.

Answer:

n = -5

Step-by-step explanation:

-2(-7n-8)=-39+3n

Distribute

14n +16 = -39 +3n

Subtract 3n from each side

14n -3n +16 = -39 +3n -3n

11n +16 = -39

Subtract 16 from each side

11n +16 -16 = -39 -16

11n = -55

divide by 11

11n /11 = -55/11

n = -5

[tex]\tt Step-by-step~exlpanation:[/tex]

To find out the answer, we would have to try and divide all the numbers.

[tex]\tt \frac{34,776}{2}= 17,388\\ YES[/tex]

[tex]\tt \frac{34,776}{3}= 11,592\\YES[/tex]

[tex]\tt \frac{34,776}{9}=3,864\\ YES[/tex]

[tex]\tt \frac{34,776}{6}= 5,796\\YES[/tex]

[tex]\large\boxed{\tt Our~final~answer:~ALL ~(2,3,9,6)}[/tex]

Answer:

3. The tree increased in height each month until the time period between month 9 and month 11.

The statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

It should be noted that a table simply means a list of numbers to that depicts a particular information.

In this case, the statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

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Answer:

d = 40w x 2

Step-by-step explanation:

Answer:

y= 1 /4 x − 3 /4

Step-by-step explanation:

y=mx+b

Step-by-step explanation:

1.8(2/7x)15

1.8×15(2/7x)

27(2/7x)

54/7x

Answer: I’m pretty sure its A on e2020

Step-by-step explanation:

It is an obligation to pay, but the spender has some control over the amount.

Option A is the correct answer.

We have,

The reason that a data usage bill for a smartphone is an essential (variable) expense is that it is an obligation to pay.

In other words, the phone service is necessary for the phone to function properly, and therefore, the bill must be paid.

However, the spender has some control over its amount by managing their data usage, such as turning off data for certain apps or using Wi-Fi instead of cellular data.

This means that while the bill cannot be eliminated entirely, the spender can take steps to reduce the amount owed.

Statement b is incorrect because while the bill cannot be eliminated entirely, it can be reduced by managing data usage.

Statement c is incorrect because the amount of the bill is not expected to be the same every month, as it will depend on how much data is used. Statement d is incorrect because while bills for services rendered may be a priority, they do not necessarily have a higher priority than other types of essential expenses, such as food or housing.

Thus,

It is an obligation to pay, but the spender has some control over the amount.

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Answer:

6

Step-by-step explanation:

6x2.5=15

yeßssssssss I do math easy pressure

Answer:

1/10

Step-by-step explanation:

Answer:

1/100

Step-by-step explanation:

it would be 1/10 if the decimal was 1 space to the right.

Answer:.583

Step-by-step explanation:

Answer:

m = 2, b = 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Given

6x - 1 = 3y - 10 ( add 10 to both sides )

6x + 9 = 3y ( divide all terms by 3 )

2x + 3 = y , that is

y = 2x + 3 ← in slope- intercept form

with slope m = 2 and y- intercept b = 3

Answer:

This is simple,

Step-by-step explanation:

If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:

300$ budget - 200 of the bus = 100$ left

and if $4 per student:

100 divided by 4 = 25

she can take 25 students

Hope this helps!

12x + 16y = 96

Subtract 12x from both sides

16y = 96 - 12x

Divide each side by 16

y = 6 - 0.75x

Answer:

9x-5

Step-by-step explanation:

(4x - 6) + (5x + 1)

Add like terms

4x+5x=9x

-6+1=-5

Combine

9x-5

Hope this helps! Plz award Brainliest : )

To Expand: (2x + 5)(x - 5).

(2x + 5)(x - 5)

= 2x(x - 5) + 5(x - 5)

= 2x² - 10x + 5x - 25

= 2x² - 5x - 25 Ans.

(Combined the like terms)

Answer:

2x²  - 5x - 25

Step-by-step explanation:

Use FOIL method

(2x + 5)(x - 5) = 2x*x + 2x*[-5] + 5*x + 5*[-5]

                      = 2x² -10x + 5x - 25    {add like terms}

                      = 2x²  - 5x - 25

Answer:

B-2

Step-by-step explanation:

It is B, because On the first month, Armando has 12 and Daniel has 8, now on the 2nd month Armando has 9 because he gives away 3 each month and Daniel now has 9 because he adds one each month, so all in all, they have the same exact number of pencils on the 2nd month

After 5 months is when Armando and Daniel had the same number of pencils.

Answer:

1 over 36

Step-by-step explanation:

Answer:

1 over 36 or A

Step-by-step explanation:

Trust me bro;)

Answer:

When dividing numbers with the same base, you subtract the exponents.

Step-by-step explanation:

For example, 8^5/8^3 = 8^2 or 64

Answer:

12

Step-by-step explanation:

im taking the test jjiiiuy teñido itself

The proof for this is simple. Let's say that A + B + C = π. From here on we require several trigonometric identities that must be applied.

[tex]\cos \left(A\right)+\cos \left(B\right)+\cos \left(C\right) \\= 2 * cos((A + B) / 2) * cos((A - B) / 2) + \cos C \\= 2 * cos((\pi /2) - (C/2)) * cos((A - B) / 2) +\cos C \\= 2 * sin(C/2) * cos((A - B) / 2) + (1 - 2 * sin^2 (C/2)) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin (C/2) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin((\pi /2) - (A + B)/2 ))\\= 1 + 2 sin (C/2) * cos((A - B) / 2) - cos((A + B)/ 2)\\= 1 + 2 sin (C/2) * 2 sin (A/2) * sin(B/2) \\= 1 + 4 sin(A/2) sin(B/2) sin(C/2)[/tex]

Hope that helps!

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                     → A + B = π -  C

                                                     → C = π - (A + B)

Use Sum to Product Identity:  cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use Product to Sum Identity:  2 sin A · sin B = cos [(A + B)/2] - cos [(A - B)/2]

Use the Double Angle Identity:   cos 2A = 1 - 2 sin² A

Use the Cofunction Identity: cos (π/2 - A) = sin A

Proof LHS → RHS:

LHS:                       cos A + cos B + cos C

                           = (cos A + cos B) + cos C

[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{A+B}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Given:}\qquad 2\cos \bigg(\dfrac{\pi -C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C\\\\\\.\qquad \qquad =2\cos \bigg(\dfrac{\pi}{2} -\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Cofunction:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Double Angle:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos\bigg(2\cdot \dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)-2\sin^2\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Factor:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{C}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi-(A+B)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi}{2}-\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\cos\bigg(\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Product to Sum:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{LHS = RHS:}\ 1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)=1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)\quad \checkmark[/tex]

Answer:

1. [tex]\frac{10}{21}[/tex]

2. [tex]\frac{405}{49} = 8\frac{13}{49}[/tex]

Step-by-step explanation:

first one:

[tex]p^{2} q[/tex] = [tex](\frac{1}{3})^{2}[/tex] × [tex]4\frac{2}{7}[/tex] = [tex]\frac{1}{9}[/tex] × [tex]\frac{30}{7}[/tex] = [tex]\frac{1}{3}[/tex] × [tex]\frac{10}{7}[/tex] = [tex]\frac{10}{21}[/tex]

second one:

[tex]t^{2}[/tex]/[tex]s[/tex] = [tex](1\frac{2}{7})^{2}[/tex] / [tex]\frac{1}{5}[/tex] = [tex](\frac{9}{7})^{2}[/tex] × [tex]5[/tex] = [tex]\frac{81}{49}[/tex] × [tex]5[/tex] = [tex]\frac{405}{49}[/tex] = [tex]8\frac{13}{49}[/tex]

Answer: Yes, In mathematics, an inverse function (or anti-function) is a function that "reverses" another function: if the function f applied to an input x gives a result of y, then applying its inverse function g to y gives the result x, and vice versa, i.e., f(x) = y if and only if g(y) = x.

Answer:

c

Step-by-step explanation:

Answer:

Cube root of 8/27 is 2/3

[tex] \sqrt{ \frac{8}{27} } [/tex]

[tex] = \sqrt{ (\frac{2}{3} {)}^{2} } [/tex]

[tex] = \frac{2}{3} [/tex]