Initial magnetic flux through the coil = LI
where L = inductance and I current through the coil
Final magnetic flux when the switch was opened =0
Flux change = LI -0=LI
Average voltage generated across the switch just after it was opened
= |LI/dt|
Given L = 0.50 H
I = 0.20 Amp
dt = 250*10^-6 Sec
Voltage generated = (0.50*0.20)/(250*10^-6)=400 volt
Voltage, also called electromotive force, is surely the energy in line with unit charge. In other phrases, voltage is the difference in electric powered capacity among two factors. Cutting-edge is simply the price of drift of electrical charge.
We outline voltage as the amount of capability electricity among points on a circuit. One point has greater charge than any other. This distinction in fee among the 2 points is referred to as voltage.
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400 volt
Initial magnetic flux through the coil = LI
where L = inductance and I current through the coil
Final magnetic flux when the switch was opened =0
Flux change = LI -0=LI
Average voltage generated across the switch just after it was opened
= |LI/dt|
Given L = 0.50 H
I = 0.20 Amp
dt = 250*10^-6 Sec
Voltage generated = (0.50*0.20)/(250*10^-6)=400 volt
Magnetic Flux:
Specifically in electromagnetism, the magnetic flux through a surface is the integral of the normal component of the magnetic field B across that surface. Usually displayed as Φ or ΦB. The SI unit of magnetic flux is Weber and the CGS unit is Maxwell.
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which of these is a risk of speeding? a. Tire Damage b.Greater likelihood of being distracted c.longer barking distance d.mechanical failure
All of the above are risks of speeding.
Speeding is a type of aggressive driving behavior. Speeding is more than just breaking the law. The consequences are far-ranging:
Greater potential for loss of vehicle control;Reduced effectiveness of occupant protection equipment;Increased stopping distance after the driver perceives a danger;Increased degree of crash severity leading to more severe injuries;Economic implications of a speed-related crash; andIncreased fuel consumption/cost.Speed also affects your safety even when you are driving at the speed limit but too fast for road conditions, such as during bad weather, when a road is under repair, or in an area at night that isn’t well lit.
Speeding endangers not only the life of the speeder, but all of the people on the road around them, including law enforcement officers. It is a problem we all need to help solve.
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The non-reflective coating in eyeglasses is based on:
A. total internal reflection
B. destructive interference
C. resonance
D. constructive interference.
The non-reflective coating in eyeglasses is based on: destructive interference. So, option (B) is correct.
What is destructive interference?When waves combine and totally cancel each other out, destructive interference occurs. Two waves must have the same amplitude travelling in opposing directions in order to interfere destructively.
Nature is home to a variety of fascinating wave phenomena that are not reducible to a single wave. We must look at the phenomenon of destructive interference based on the wave combination. We use the superposition principle, which states the following, to examine these:
The resulting wave function is the algebraic sum of the individual wave functions when two or more waves are passing through a medium.
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What Happens After Water Vapor Condenses?
Answer:
after water vapor condenses it is cooled down enough to turn back into a liquid and forms clouds in the air
a 28.5 g piece of gold is heated and then allowed to cool. what is the change in temperature ( °c) if the gold releases 0.213 kj of heat as it cools? the molar heat capacity of gold is 25.4 j/mol･ °c.
Considering the definition of calorimetry and sensible heat, the change in temperature if the gold releases 0.213 kJ of heat as it cools is 57.83°C.
Calorimetry and sensible heatCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat. It is calculated by the expression:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat substance.ΔT is the temperature variation.Change in temperature in this caseIn this case, you know:
Q= 0.213 kJ= 213 J (being 1 kJ=1000 J)c= 25.4 J/molCm= 28.5 g× 196.967 g/mole= 0.145 moles (being 196.967 g/mole the molar mass of gold)ΔT= ?Replacing in the definition of sensible heat:
213 J= 25.4 J/molC× 0.145 moles× ΔT
Solving:
ΔT= 213 J÷ (25.4 J/molC× 0.145 moles)
ΔT= 57.83 °C
Finally, the change in temperature is 57.83°C.
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Wheel A has three times the moment of inertia about its axis of rotation as wheel B. Wheel B's angular speed is four times that of wheel A.
A) Which wheel has the greater rotational kinetic energy? A,B, Both wheels have the same rotational KE
B) If KA and KB are the rotational kinetic energies of the wheels, what is KA/KB?(express answer to 4 sig fig)
Wheel A has 3 times the moment of inertia as wheel B. Meanwhile Wheel B's angular speed is 4 times that of wheel A.
Wheel B has the greater rotational kinetic energyIf KA and KB are the rotational kinetic energies of the wheels, KA/KB is 0.188The moment of inertia is a quantitative measur of the rotational inertia of a body. The moment of inertia (I) is always specified with respect to the rotation axis.
Rotational kinetic energy is a form of kinetic energy that is caused by the rtation of an object. Rotational kinetic energy formula is:
K = 1/2 Iω²
where:
I = the moment of inertia
ω = angular velocity
From the case, we know that:
I(A) = 3 x I(B)
ω(B) = 4 x ω(A)
Using the Rotational kinetic energy formula, we could find the rotational kinetic energy for each wheelsby respecting the result to wheel B:
Wheel A
K(A) = 1/2 I(A).ω(A)²
K(A) = 1/2 [3I(B)] [1/4.ω(B)]²
K(A) = 1/2 [3I(B)] [1/16.ω(B)²]
K(A) = 3/32 I(B).ω(B)²
K(A) = 0.094 I(B).ω(B)²
Wheel B
K(B) = 1/2 I(B)ω(B)²
K(B) = 0.5 I(B)ω(B)²
From the comparison between both rotational kinetic energi, we know that K(A)<K(B). Hence wheel B has the greater rotational kinetic energy.
Then, KA/KB is:
KA = 0.094 I(B).ω(B)²
KB 0.5 I(B).ω(B)²
KA/KB = 0.188
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a cylinder is to be created with a volume of 60 cm3. what should be the dimensions of the cylinder (height, radius) that minimize surface area? recall that, for a cylinder, ix
In geometry, a cylinder's volume is referred to as its capacity, and this definition can be used to determine how much material it can carry.
What is the equation for a cylinder's volume? The product of a cylinder's base area and height provides the formula for calculating the cylinder's volume. A cylinder's volume is equal to r 2 h cubic units.
If you know the cylinder's height and volume: Make that the height and volume are expressed in the same units (for example, cm3 and cm), and the radius is expressed in radians. Multiply the height and pi to get the volume. the outcome squared. If you know the height (h) and surface area:
The cylinder formulas are: entire surface area = 2πr (r+h) square units Volume of cylinder = πr 2 h cubic units
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the correct relation for the emissive power of a diffuse, gray surface, where t is the absolute temperature is___
When t is the absolute temperature, the appropriate relationship for a diffuse, gray surface's emissive power is E = εσT^4
The energy emitted by a body per unit surface area within a unit wavelength range is known as its emissive power at a specific temperature. Stefan's constant, emissivity, and absolute temperature are all present in this equation. Kirchhoff's law states that the emissive power of a perfectly black body at a given temperature is equal to the ratio of emissive power to absorptive power for a given wavelength at a given temperature for all bodies. The diffuse-gray surface theory applies to surfaces where is wavelength-independent.
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Help please!
Zach drives his car with an average velocity of 24 m/s toward the east. How long will it take him to drive 560 km on a perfectly straight highway?
imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g
Mass of the Earth, M = 6 * 10²⁴
m = 200 kg
R = 6.4 * 10⁶
G = 6.67 * 10¹¹ Nm²/kg²
Height of the satellite, h = 300 km = 3 * 10⁵ m
Total energy of the satellite at height h = 1/2mv² + [G(M*m)/(R+h)]
Orbital velocity of the satellite, v = √[ (G*M) / (R+h) ]
Total energy at height h = 1/2[ (G*M) / (R+h) ]
The negative sign indicates that the satellite is bound to the Earth.
Energy required to send the satellite out of its orbit = – (Bound energy)
= GM*m/ 2(R+h)
= 6.67*10⁻¹¹ * 6*10²⁴* 200 / 2(6.4*10⁶ + 0.3*10⁶)
= 11.9*10⁹ J
If the satellite just escapes from the gravitational field, then total energy of the satellite is zero.
Therefore, we have to supply 11.9*10⁹ J of energy to just escape it.
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[NOTE:THIS IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: imagine a satellite in low-earth circular orbit, i.e., approximately 300 km above the surface of the earth. if the radius of the earth is 6.37 x 106 meters, and we assume the gravitational force on the satellite is approximately equal to mg with g. The mass of satellite is 200 kg. How much energy must be expended to rocket the satellite out of the earth's gravitational influence?]
Which of the following is the same for all kinds of electromagnetic waves?
frequency
speed
energy
transmission
wavelength
Out of The following speed is the same for all kinds of electromagnetic waves.
Electromagnetic waves travel at the same speed through space. That speed, also known as the speed of light is approximately 300 million meters per moment which are 3.0 x 108 m/s...Although all electromagnetic waves travel at the same speed over space, they may vary in their wavelengths, frequencies, and energy levels. Wavelength is the distance between comparing focuses of adjacent waves. Frequencies of electromagnetic waves run from thousands of waves per second to trillions of waves per second. The energy of electromagnetic waves depends on their frequency. Low-frequency waves have small energy and are ordinarily safe. High-frequency waves have a lot of energy.
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determine the modulus of elasticity of a composite material if the strain on the material was 0.09 and the following data are known:
If a composite material underwent a 0.09 strain, the material's modulus of elasticity be is 6.48*10⁶ psi
Ef=10.5*10⁶ psi
Em=0.45*10⁶ psi
Vf=0.6
Vm=1-Vf=0.4
Modulus of elasticity is
E=Vf.Ef+Vm.Em
=0.6*10.5*10⁶ psi+0.4*0.45*10⁶
=6.48*10⁶ psi
Therefore Modulus of elasticity E is 6.48*10⁶ psi
Young's modulus, also known as elastic modulus, tensile modulus, or modulus of elasticity in tension, is the ratio of stress to strain and is equivalent to the slope of a material's stress-strain diagram. Young's modulus is sometimes referred to as the modulus of elasticity and is equal to the longitudinal stress divided by the strain.
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A solenoidal coil with 30 turns of wire is wound tightly around another coil with 350 turns, The inner solenoid is 20.0 cm long and has a diameter of 2.10 cm. At a certain time, the current in the inner solenoid is 0.100 A and is increasing at a rate of 1500 A/s
Part A
For this time, calculate the average magnetic flux through each turn of the inner solenoid.
Part B
For this time, calculate the mutual inductance of the two solenoids.
The average magnetic flux passing through each inner solenoid turn is 8.45966*10(-8). Because a 350-turn solenoidal coil with 30 turns of wire is firmly twisted around it.
How many magnetic lines of force are present in a specific area is determined by the magnetic flux. For instance, the magnetic flux density is lower if fewer magnetic lines cross a large area of cross section. Knowing the magnetic flux also enables us to make an educated guess about the magnitude of the magnetic field in a particular area.
Inner solenoid has a certain number of turns.
N1 = 300
In an outer solenoid, there are
N2 = 30
Internal solenoid length is
L = 21.0[cm] = 0.21[m] .21[m]
Radius of the internal solenoid
r = diameter/2=2.00[cm]/2=1.00[cm] = 0 .01[m]
Current flowing through the inner solenoid
I = 0.150[A] .150[A]
the current's rate of growth is
di/dt equals 1800[A/s].
The inner solenoid's average magnetic flux through each revolution is
B.A is equal to μ*(N/L)*i.A is equal to [4(pi)*10-7]*[300/0.21]*[0.15]*&
pi;*(0.01) = 8.45966*10^(-8)
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an experienced astronomer can take one look at the h-r diagram of a star cluster and immediately estimate its age. select the statement that explains how this is possible.
The most massive stars remaining on the main sequence indicate the cluster's age.
What is the approximate age of the star cluster in the HR diagram quizlet?
Spectral types O and B main sequence stars have a core hydrogen supply that is enough for around 350 million years; types A and F, for about 2 billion years; type G, for about 10 billion years; and types K and M, for about 30 billion years.
Astronomers can establish the age of a globular cluster by plotting the stars in the cluster on a Hertzprung-Russell diagram and comparing the main sequence turnoff point with stellar evolution models.
Similar to our Sun, main sequence stars consume hydrogen. The upper left of the strip is home to hotter, more massive main sequence stars. Cooler, less massive stars can be observed at bottom right. Massive stars swiftly exhaust all of their hydrogen in a few of million years.
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how fast would a(n) 73 kgkg man need to run in order to have the same kinetic energy as an 8.0 gg bullet fired at 430 m/sm/s ?
The velocity of the 73 Kg man needed for him to have the same kinetic energy as the 8.0 g bullet fired at 430 m/s is 4.5 m/s
How do I determine the velocity of the man?First, we shall obtain the kinetic energy of the bullet. This can be obtained as follow:
Mass (m) = 8 g = 8 / 1000 = 0.008 KgVelocity (v) = 430 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.008 × 430²
KE = 739.6 J
Finally, we shall determine the velocity of the 73 Kg man. Details below:
Mass of man (m) = 73 KgKinetic energy (KE) = 739.6 JVelocity of man (v) = ?KE = ½mv²
739.6 = ½ × 73 × v²
739.6 = 36.5 × v²
Divide both side by 36.5
v² = 739.6 / 36.5
Take the square root of both side
v = √(739.6 / 36.5)
v = 4.5 m/s
Thus, the velocity man is 4.5 m/s
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he pushed the car beyond the tollgate and poured a bucket of water on the smoking hood. previousnext
He moved the car past the toll booth and doused the flaming hood with water using the comma.
What makes water vital to life?Chemical processes are necessary for life to produce energy, grow, and eliminate waste. Water is a liquid that facilitates the chemistry of life. Additionally, because it is a polar molecule, most other molecules can dissolve in it. As a result, we refer to water as a "solvent".
How does science define water?Water is a substance that exists in gaseous, fluid, and solid phases and is made up of the molecular elements both hydrogen and oxygen. One of the prevalent and necessary substances is it. a liquid that is flavorless and odorless at ambient temperature.
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if a capacitor is connected across the feedback resistor, the circuit acts as a practical integrated circuit.T/F
if a capacitor is connected across the feedback resistor, the circuit acts as a practical integrated circuit.is FALSE
What is practical integrated?
Because the mental process and learning information are applied, practical and integrated learning is the best type of learning. Because they are actively involved in the learning process, practical and integrated learning encourages students to greatly develop their learning skills.
The practical integrator is also called as lossy integrator as it integrates only frequencies greater than fa (i.e. higher frequencies) effectively. Thus we can have following observations from frequency response of practical integrator
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Electrical is lowered in the presence of water or moisture, so welders must take special precautions when working under damp or wet conditions.
Electrical ___Resistance____is lowered in the presence of water or moisture, so welders must take special precautions when working under damp or wet conditions.
The electrical resistance of an object is a measure of its resistance to the flow of electricity. Its reciprocal is electrical conductivity, which measures the ease with which current can flow. Electrical resistance shares some conceptual similarities with mechanical friction. The SI unit for electrical resistance is the ohm (Ω), while electrical conductivity is measured in Siemens (S) (formerly called "mho", expressed in ℧).
The durability of an object is highly dependent on its material. Items made from electrical insulators such as rubber tend to have very high resistance and low conductivity, whereas items made from conductors such as metal have very low resistance and high conductivity.
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archimedes' principle can be used to calculate the density of a fluid as well as that of a solid. suppose a chunk of copper with a mass of 400.0 g in air is found to have an apparent mass of 354.5 g when completely submerged in an unknown liquid.
The magnitude of net buoyant force in the liquid will be 1.029 N.
Whenever an object is submerged into water, the water exerts a force on an object in the upward direction. When an object push water, water pushes it back with more force. Basically buoyant force is the weight of fluid displaced by the object submerged in water.
B = weight of object in air - weight of object in water
Converting gram into N
We know that 1 kg = 9.8 N
Changing kg into gram by multiplying both sides with 1x10¯³
1 g = 9.8x10¯³ N
400 g = 400x9.8x10¯³N
400 g = 4.214 N
354.5 g = 354.5x9. 8x10¯³ N
354.5 g = 3.185 N
Now, finding buoyant force
B = weight of object in air - weight of object in water
B = 4.214 - 3.185
B = 1.029 N
Therefore the magnitude of net buoyant force in the liquid will be 1.029 N.
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Three enemy spacecraft have been causing trouble in the asteroid belt. They always travel in a line, evenly spaced apart, attempting to chase down local spacecraft to steal their goods. The local asteroid colonists have decided to set a trap to capture these three spacecraft. They'll get them to chase one of their fastest ships into an asteroid with a large hole in it and, once the three enemy ships are inside, close two giant trapdoors on each side of the asteroid to catch them. These spacecraft all travel close to the speed of light so the locals will have to take relativity into account. Intelligence about the enemy spacecraft reveals that, in their reference frame, they always travel 90 m behind their teammate, each spacecraft is 10 m in length, and their maximum velocity is 90% the speed of light (relative to the asteroids). The asteroid tunnel is only 215 m in length. In this problem we will analyze whether the locals will be able to capture the enemy spacecraft after taking into account relativity.
Part A: If the spacecraft are traveling at 90% the speed of light, what is the total length L of the three-spacecraft team as observed from the asteroid?
Part B: Suppose the trigger is set so that the moment the first enemy spacecraft enters the asteroid a signal is sent at the speed of light to the other end of the asteroid to trigger the rear trapdoor. How long a time will this signal take to get to the rear of the asteroid?
Part C:How close d_rear to the rear of the asteroid will the first enemy spacecraft be when the trapdoors close?
Part D:One of the local students had been studying relativity and began to question the plan. How would this all appear to the enemy spacecraft as they flew through the asteroid? Specifically, if the spacecraft were in an inertial frame (i.e., one with no acceleration) how long would the asteroid tunnel appear to be in their rest frame?
Part A: If the spacecraft is traveling at 90% the speed of light, the total length L of the three-spacecraft team as observed from the asteroid is 31 meters.
Part B: The signal will take 0.732 seconds to reach the rear of the asteroid.
Part C: The first enemy spacecraft will be 7.3 meters from the rear of the asteroid when the trapdoors close.
Part D: In the inertial frame of the enemy spacecraft, the asteroid tunnel would appear to be 639 meters long.
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(True or False) the energy carried by a photon of ir radiation is greater than the energy carried by a photon of uv radiation.
Answer:
false
ir = infrared radiation ....? right?
a long straight wire is in the plane of a rectangular conducting loop. the straight wire initially carries a constant current iin the direction shown. while the current i is being shut off, the current in the loop is:
The current in the rectangular conducting loop will be in the clockwise direction because of the long straight wire.
The long straight wire is carrying the current and it is in the Plane of the rectangular conducting loop.
The wire is carrying the current in the upward direction with respect to the plane of the paper.
When there is a current in the long straight wire there will be a magnetic field around the wire. When the current in the wire is being shut off the magnetic field will start to decrease as a result of the change in magnetic flux because of the change in magnetic field.
The induced current in the loop will generated in such a way that the decrease in magnetic field is opposed.
So, the current in the loop will be in the clockwise direction.
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which of the following measurements can be made only by recording and comparing the amount of light received from an astronomical source at many different times? which of the following measurements can be made only by recording and comparing the amount of light received from an astronomical source at many different times? the general shape of an interstellar cloud of gas the number of bright stars in a nearby star cluster the rate at which a variable star brightens and dims the color of a planet
The rate at which a variable star brightens and dims is determined by this process.
A light curve is the measurement of a celestial body's brightness at certain intervals and over a given period of time (hours, days, months...). This is called Light Curve Analysis.Asteroids shine due to the Sun's light reflecting off their surface, and their brightness might vary due to one or more of the following factors: The asteroid's distance to us is changing (closer objects appear brighter). The asteroid's phase, just like the Moon's, is changing as it orbits around the Sun (the larger the area of the asteroid that is illuminated, as seen from Earth, the brighter it will appear). The asteroid, because of its irregular shape, reflects light differently as it spins. If the orbit of an asteroid is well known, the first two effects can be numerically calculated and their contributions removed from the measured light curve. We are then left with a light curve whose changes are due solely to the spinning of the asteroid.To know more about stars visit;
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The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g). If initial concentrations are [SO2] = 2.40 M, [O2] = 0.45 M, and [SO3] = 3.60 M, the system is The equilibrium constant is equal to 5.00 at 1300 K for the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g). If initial concentrations are [SO2] = 2.40 M, [O2] = 0.45 M, and [SO3] = 3.60 M, A.the system is not at equilibrium and will shift to the right to achieve an equilibrium state. B.not at equilibrium and will remain in an unequilibrated state. C.at equilibrium. D.not at equilibrium and will shift to the left to achieve an equilibrium state
Option (C) is correct.
The given equation [tex]2SO_{2(g)} +O_{2(g)}[/tex] ⇄ [tex]2SO_{3(g)}[/tex] is at equilibrium.
Given equation,
[tex]2SO_{2(g)} +O_{2(g)}[/tex] ⇄ [tex]2SO_{3(g)}[/tex]
and
[tex]K_{c} =5.00[/tex] at 1300 K
To determine whether the reaction is at equilibrium or will shift to left or right, determine the Reaction Quotient, which is calculated at any instant of time,
Given,
[tex][SO_{2} ]=2.40M[/tex]
[tex][O_{2} ]=0.45M[/tex]
[tex][SO_{3} ]=3.60M[/tex]
[tex]Q_{c} =\frac{[SO_{3} ]^2}{[SO_{2} ]^2[O_{2} ]}[/tex]
[tex]Q_{c} =\frac{(3.60)^2}{(2.40)^2(0.45)}[/tex]
[tex]Q_{c} =5[/tex]
Since,
[tex]K_{c} =5.00[/tex] = [tex]Q_{c}[/tex]
The given reaction is at equilibrium.
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Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.
Moving at 1.2 m/s inside the opposite direction following the collision.
Define collision.
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The law of momentum conservation can be used to calculate Miguel's post-collision velocity.
Mass times velocity equals momentum, that is a vector quantity (p=mv). Well before collision, the system's momentum.
Miguel and Fernando's car—was equal to 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s). Just after collision,
The system's momentum is equal to 782 kg*m/s (m1=72 kg) (v1=? m/s) + (m2=125 kg) (v2=2 m/s).
We can calculate Miguel's post-collision velocity to be -1.2 m/s by solving for v1.
Miguel is therefore moving at 1.2 m/s inside the opposite direction following the collision.
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A 2.3 kg , 20-cm-diameter turntable rotates at 150rpm on frictionless bearings. Two 550 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick.What is the turntable's angular velocity, in rpm, just after this event
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
I'll suppose that the turntable is a solid disc with a moment of inertia of 0.5Mr2 and that the blocks stick out from the edge of the turntable, each 10cm (0.10 m) from the turntable's centre. This is the conservation equation:
0.5Mr²ω(i) = 0.5Mr²ω(f) + m₁r²ω(f) + m₂r²ω(f) ----(but m₁ = m₂ = m)
Mr²ω(i) = Mr²ω(f) + 4mr²ω(f)
Mr²ω(i) = ω(f)r²(M + 4m)
ω(f) = Mω(i) / (M + 4m)
ω(f) = (2.3kg)(150 rpm) / [2.3kg + (4 x 0.55 kg)]
The turntable's angular velocity, in rpm, just after this event is ω(f) = 78.40 rpm
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A metal object with a mass 5.50 kg is connected to a spring with a force constant of 225 N/m, and it oscillates horizontally with an amplitude of 4.20 cm. (a) What is the total mechanical energy (in J) of the object-spring system? (b) What is the maximum speed (in m/s) of the oscillating object? m/s (c) What is the maximum magnitude of acceleration (in m/s) of the oscillating object? m/s²
a) Total mechanical energy of the object-spring system = 0.198 J
b) Maximum speed of the oscillating object = 0.269 m/s
c) Maximum magnitude of acceleration of the oscillating object = 1.72 m/s2
What is acceleration?
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both.
Mass of the object = m = 5.5 kg
Force constant of the spring = k = 225 N/m
Amplitude of the motion = A = 4.2 cm = 0.042 m
Total mechanical energy of the object-spring system = E
Total mechanical energy is equal to the maximum potential the spring can store in this motion.
(a) [tex]$E=\frac{1}{2} \times 300 \times 0.037^2$[/tex]
[tex]$$E=0.20535 \text { Joules }$$[/tex]
Maxmium speed, [tex]$v_{\max }=$[/tex] AeO
[tex]$$\begin{gathered}\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{300}{5.5}} \\\omega=7.3855 \mathrm{rad} / \mathrm{s} \\v_{\max }=0.037 \times 7.3855 \\V=0.273 \mathrm{~m} / \mathrm{s}\end{gathered}$$[/tex]
(C) Maximim acceleration, [tex]$a_m=A \omega^2$[/tex]
[tex]$$\begin{aligned}a_{\max } & =0.037 \times 7.3855^2 \\a_{\max } & =2.018 \mathrm{~m} / \mathrm{s}^2\end{aligned}$$[/tex]
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A sound wave travels through water. What best describes the direction of the water particles?
The water particles move perpendicular to the source of the sound wave.
The water particles move in the same direction as the vibrating source of the sound wave.
The water particles move in random patterns because the sound is diffracted in many directions.
The water particles do not move because the sound wave does not have enough energy.
Answer:
The water particles move in the same direction as the vibrating source of the sound wave.
Explanation:
Answer:
The correct option is B.
Explanation:
A child is flying a kite. If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, the child is letting out cord at _____ feet per second when 245 feet of cord are out. Assume that the cord remains straight from hand to kite.
If the kite is 90 feet above the child's hand level and the wind is blowing it on a horizontal course at 5 feet per second, The child is letting out cord at 150 feet per second.
It's miles the price of growth of y as t increases. Loosely positioned, it is the size of the tiny increase in y that could rise up from making a tiny increase to t and setting that in the components for y.
In newtonian notation and dy/dx is leibniz notation. Newton and Leibniz independently invented calculus across the equal time so they used distinct notation to represent the equal thing (rate of change in this example).
A differential dx isn't always a actual wide variety or variable. alternatively, it is a convenient notation in calculus. it can intuitively be notion of as "a completely small alternate in x", and it makes plenty of the notation in calculus appear extra realistic.
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the vectors d and e are [-4,1] and [1,4] respectively .find the angle b/n and e (Use dot product )
measure and record the output voltage from the rc low-pass fi lter for each of the frequencies listed below. (use the oscilloscope to measure the output voltage.) next, calculate the decibel attenuation offered by the fi lter at each frequency.
Passive RC filters “filter-out” unwanted signals by separating and allowing to pass only sinusoidal input signals based upon their frequency. Here the most simple passive low pass filter network is utilized.
Filters are named according to the frequency range of signals allowed to pass through them, while blocking or “attenuating” the rest. Here are some common filter designs.
The Low Pass Filter : only allows low frequency signals from 0Hz to its cut-off frequency.
The High Pass Filter : only allows high frequency signals from its cut-off frequency.
The Band Pass Filter : allows signals falling within a certain frequency band setup between two points to pass through.
The question is incomplete. Answer is written giving basics of the concepts used in the question.
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