Describe how the line of best fit and the correlation coefficient can be used to determine the correlation between the two variables on your graph.


Thank you!

The y-coordinate of point P is 1.To find the y-coordinate of the point P on the parabola y = 3x^2 - 11x + 10 where the slope is 7, we can differentiate the equation to find the derivative. The derivative of y = 3x^2 - 11x + 10 is y' = 6x - 11.

To find the x-coordinate of point P, we can set the derivative equal to the given slope: 6x - 11 = 7. Solving for x, we get x = 3.

To find the y-coordinate of point P, we substitute the x-coordinate back into the original equation: y = 3(3^2) - 11(3) + 10. Simplifying, we find y = 1.

Therefore, the y-coordinate of point P is 1.

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Answer:

[tex]\textsf{(C)} \quad \dfrac{1}{4}[/tex]

Step-by-step explanation:

To find the probability of a point chosen at random being in the shaded area of the given diagram, we first need to calculate the areas of the larger circle and the shaded circle.

The formula for the area of a circle is A = πr², where r is the radius.

Given the radius of the larger circle is 8 units:

[tex]\begin{aligned}\sf Area\;of\;the\;larger\;circle&=\pi (8)^2\\&=64 \pi \end{aligned}[/tex]

Given the radius of the shaded circle is 4 units:

[tex]\begin{aligned}\sf Area\;of\;the\;shaded\;circle&=\pi (4)^2\\&=16 \pi \end{aligned}[/tex]

[tex]\boxed{\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}}[/tex]

To find the probability that a point chosen at random is in the shaded area, divide the area of the shaded circle by the area of the larger circle:

[tex]\sf Probability= \dfrac{16 \pi}{64 \pi}=\dfrac{1}{4}[/tex]

Therefore, the probability of a point chosen at random being in the shaded area is 1/4.

Answer:

[tex]\frac{x}{y}[/tex] 1 over 4 (one-fourth)

Step-by-step explanation:

a) Angle of line of sightFrom a point O in the school compound, Adeolu is 100 m away on a bearing N 35° E and Ibrahim is 80 m away on a bearing S 55° E. (a) How far apart are both boys? (b) (c) What is the bearing of Adeolu from point O, in three-figure bearings? What is the bearing of Ibrahim from point O, in three-figure bearings?The angle of the line of sight of Adeolu from the point O is given by:α = 90 - 35α = 55°.The angle of the line of sight of Ibrahim from the point O is given by:β = 90 - 55β = 35°.a) By using the Sine Rule, we can determine the distance between Adeolu and Ibrahim as follows:$

\frac{100}{sin55^{\circ}} = \frac{80}{sin35^{\circ}

100 sin 35° = 80 sin 55°=57.73 mT

herefore, both boys are 57.73 m apart. b) The bearing of Adeolu from the point O can be determined as follows:OAN is a right-angled triangle with α = 55° and OA = 100. Therefore, the sine function is used to determine the side opposite the angle in order to determine AN.

Thus:$$sin55^{\circ} = \frac{AN}{100}$$AN = 80.71 m.

To find the bearing, OAD is used as a reference angle. Since α = 55°, the bearing is 055°.

Therefore, the bearing of Adeolu from the point O is N55°E. c) Similarly, the bearing of Ibrahim from the point O can be determined as follows:OBS is a right-angled triangle with β = 35° and OB = 80. Therefore, the sine function is used to determine the side opposite the angle in order to determine BS.

Thus:$$sin35^{\circ} = \frac{BS}{80}$$BS = 46.40 m.

To find the bearing, OCD is used as a reference angle. Since β = 35°, the bearing is 035°.Therefore, the bearing of Ibrahim from the point O is S35°E. A boy walks 5 km due North and then 4 km due East. (a) Find the bearing of his current posi- tion from the starting point.

(b) How far is the boy now from the start- ing point?The boy's position is 5 km North and 4 km East from his starting position. The Pythagorean Theorem is used to determine the distance between the two points, which are joined to form a right-angled triangle. Thus

:$$c^2 = a^2 + b^2$$

where c is the hypotenuse, and a and b are the other two sides of the triangle. Therefore, the distance between the starting position and the boy's current position is:$$

c^2 = 5^2 + 4^2$$$$c^2 = 25 + 16$$$$c^2 = 41$$$$c = \sqrt{41} = 6.4 km$$

Therefore, the boy is 6.4 km from his starting point. (a) The bearing of the boy's current position from the starting point is given by the tangent function.

Thus:$$\tan{\theta} = \frac{opposite}{adjacent}$$$$\tan{\theta} = \frac{5}{4}$$$$\theta = \tan^{-1}{\left(\frac{5}{4}\right)}$$$$\theta = 51.34^{\circ}$$

Therefore, the bearing of the boy's current position from the starting point is N51°E.

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The value of x is equal to 15 units.

In Mathematics and Geometry, the Triangle midpoint theorem states that the line segment which joins the midpoints of two (2) sides of a triangle is parallel to the third side, and it's congruent to one-half of the third side.

In Mathematics and Geometry, a midsegment is a type of line segment that is used for connecting the midpoints of two sides of a triangle.

By applying the triangle midpoint theorem, we can determine the value of x as follows:

JH = 1/2(LM)

JH = 1/2 × 30

JH = x = 15 units.

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Answer:

Step-by-step explanation:

1) f(-4) --> if x < or equal to 3

2) 1/(-4)-4

3) The answer is - 1/8

Answer:

3x² (2x² + 4x + 5)

Step-by-step explanation:

Step 1: Identify the coefficients.

In the given expression, the coefficients are 6, 12, and 15.

Step 2: Find the GCMF of the coefficients.

The GCMF is the largest number that can divide each coefficient evenly. In this case, the GCMF of 6, 12, and 15 is 3.

Step 3: Identify the variables.

The variables in the expression are x^4, x^3, and x^2.

Step 4: Find the GCMF of the variables.

The GCMF of the variables is the highest power of x that appears in each term. Here, it is x^2.

Step 5: Combine the GCMF of the coefficients and variables.

The GCMF of the coefficients (3) and the GCMF of the variables (x^2) can be multiplied together to get the overall GCMF: 3x^2.

Step 6: Factor out the GCMF from the expression.

To factor out the GCMF 3x^2, divide each term of the expression by 3x^2:

(6x^4 + 12x^3 + 15x^2) / (3x^2) = 2x^2 + 4x + 5

Step 7: Write the factored form.

The factored form of 6x^4 + 12x^3 + 15x^2 is 3x^2(2x^2 + 4x + 5).

The rate at which the distance between the cars is increasing 2 hours later is 0 mi/h, by using the Pythagorean theorem.

To find the rate at which the distance between the cars is increasing, we can use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

Let's assume that after 2 hours, the distance traveled by the southbound car is d_south and the distance traveled by the westbound car is d_west.

Since the southbound car travels at a speed of 50 mi/h for 2 hours, we have d_south = 50 mi/h [tex]\times[/tex] 2 h = 100 mi.

Similarly, the westbound car travels at a speed of 20 mi/h for 2 hours, so d_west = 20 mi/h [tex]\times[/tex] 2 h = 40 mi.

Now, we can use the Pythagorean theorem to find the distance between the two cars:

[tex]distance^2 = d_south^2 + d_west^2distance^2 = 100^2 + 40^2distance^2 = 10000 + 1600distance^2 = 11600[/tex]

distance ≈ sqrt(11600) ≈ 107.68 mi

To find the rate at which the distance between the cars is increasing, we differentiate the equation with respect to time:

2 [tex]\times[/tex] distance [tex]\times[/tex] [tex]\(\frac{{d(\text{{distance}})}}{{dt}}\)[/tex] = 2 [tex]\times[/tex] d_south [tex]\times[/tex] [tex]\(\frac{{d(d_{\text{{south}}})}}{{dt}}\)[/tex] + 2 [tex]\times[/tex] d_west [tex]\times[/tex] (d(d_west)/dt)

Since d_south and d_west are constant (no mention of their rates of change), we can simplify the equation to:

2 [tex]\times[/tex] distance [tex]\times[/tex] [tex]\(\frac{{d(\text{{distance}})}}{{dt}}\)[/tex] = 0

Therefore, the rate at which the distance between the cars is increasing 2 hours later is 0 mi/h.

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The domain of (boa)(x) is [1, ∞].

In Mathematics and Geometry, a domain is the set of all real numbers (x-values) for which a particular equation or function is defined.

Based on the information provided above, we have the following functions:

a(x) = 3x+1

[tex]b(x) = \sqrt{x-4}[/tex]

Therefore, the composite function (boa)(x) is given by;

[tex]b(x) = \sqrt{3x+1 -4}\\\\b(x) = \sqrt{3x-3}[/tex]

By critically observing the graph shown in the image attached below, we can logically deduce the following domain:

Domain = [1, ∞] or {x|x ≥ 1}.

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The derivative of the function [tex]f(x) = \frac{1}{\sqrt{2x^2 + 5x + 3}}[/tex] is [tex]f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]f(x) = \frac{1}{\sqrt{2x^2 + 5x + 3}}[/tex]

Factor the expression

So, we ave

[tex]f(x) = \frac{1}{\sqrt{(x + 1)(2x + 3)}}[/tex]

The derivative of the function can be calculated using as follows:

[tex]f'(x) = (-\frac{1}{2})((x + 1)(2x + 3))^{-\frac{1}{2} - 1} \cdot \frac{d}{dx}[(x + 1)(2x + 3)][/tex]

Next, we have

[tex]f'(x) = -\frac{\frac{d}{dx}(x + 1) \cdot (2x + 3) + (x + 1) \cdot \frac{d}{dx}(2x + 3)}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

Differentiate

[tex]f'(x) = -\frac{1 \cdot (2x + 3) + (x + 1) \cdot 2}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

This gives

[tex]f'(x) = -\frac{2x + 3 + 2x + 2}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

Evaluate the like terms

[tex]f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

Hence, the derivative of the function is [tex]f'(x) = -\frac{4x + 5}{2((x + 1)(2x + 3))^\frac{3}{2}}[/tex]

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The probability of getting a sum less than 5 is 6/36, which can be simplified to 1/6.

When two dice are thrown simultaneously, the total number of outcomes is 36 (6 faces on each die, giving 6*6 = 36 possible outcomes).

To find the probability of getting a sum less than 5, we need to determine the favorable outcomes.

The possible favorable outcomes are:

1 + 1 = 2

1 + 2 = 3

1 + 3 = 4

2 + 1 = 3

2 + 2 = 4

3 + 1 = 4

There are a total of 6 favorable outcomes.

Thus, there is a 1 in 6 chance of getting a sum less than 5 when throwing two dice simultaneously.

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The given infinite sum 0.16 + 0.4 + 0.1 + 0.25 + ... is defined as it converges to a finite value. Option A is the correct answer.

To determine whether the given infinite sum is defined, let's examine its pattern.

If we observe the terms in the sum, we can see that each term is obtained by dividing the previous term by 4. Specifically, each term is one-fourth the value of the previous term.

Let's verify this pattern:

Term 1: 0.16

Term 2: Term 1 / 4 = 0.16 / 4 = 0.04

Term 3: Term 2 / 4 = 0.04 / 4 = 0.01

Term 4: Term 3 / 4 = 0.01 / 4 = 0.0025

It appears that each term is one-fourth the value of the previous term. If this pattern continues, we can write the nth term as:

Term n = (1/4)^(n-1) * 0.16

To determine whether the sum is defined, we need to check whether the terms approach a finite value or converge to a specific value.

As n approaches infinity, the term (1/4)^(n-1) * 0.16 will approach zero since (1/4)^(n-1) approaches zero exponentially. Therefore, the sum of the infinite terms in this sequence will converge to a finite value. Hence, Option A is the correct answer.

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The correct pairings are:

a) Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

b) Five times the difference of a number squared and six: 5(n² - 6)

c) Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

d) O twice the difference of nine and a number squared: 2(9 - n²)

The correct pairings of descriptions and expressions are as follows:

Four less than the quotient of a number cubed and seven, increased by three: (n³/7) - 4 + 3

This expression represents taking a number, cubing it, dividing the result by seven, subtracting four, and then adding three.

Five times the difference of a number squared and six: 5(n² - 6)

This expression represents taking a number, squaring it, subtracting six, and then multiplying the result by five.

Nine more than the quotient of six and a number cubed, decreased by four: (6/n³) + 9 - 4

This expression represents taking the cube of a number, dividing six by the cube, adding nine, and then subtracting four.

O twice the difference of nine and a number squared: 2(9 - n²)

This expression represents taking a number, squaring it, subtracting it from nine, and then multiplying the result by two.

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The area of a rectangle with a width of 5.1 cm and a height of 11.2 cm is 57.12 cm².

To find the area of a rectangle, we multiply its length by its width. In this case, the width is given as 5.1 cm and the height (or length) is given as 11.2 cm.

Area = length × width

Area = 11.2 cm × 5.1 cm

Calculating the product, we get:

Area = 57.12 cm²

Therefore, the area of the rectangle is 57.12 cm².

The correct answer is: 57.12 cm².

It is important to note that when calculating the area of a rectangle, we should always include the appropriate unit of measurement (in this case, cm²) to indicate that we are dealing with a two-dimensional measurement. The area represents the amount of space covered by the rectangle's surface.

So, the area of a rectangle with a width of 5.1 cm and a height of 11.2 cm is 57.12 cm².

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Answer:x=bx2 is the answer

Step-by-step explanation:

Triangle ABC and ADE are similar triangles

Similar triangles have the same corresponding angle measures and proportional side lengths.

This means that for two triangles to be similar, the corresponding angles must be equal and the ratio of corresponding sides of similar triangles are equal.

It has been shown that angles in ABC and ADE are equal.

To show that the ratio of corresponding sides are equal

6/12 = 8/16 = 10/20

The ratios all give a value of 1/2

Therefore we can say that the triangles ABC and ADE are similar.

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The two equations to solve for angle α are sinα = u/t and sinα = r/s using the trigonometric ratio of sine

The trigonometric ratios involves the relationship of an angle of a right-angled triangle to ratios of two side lengths. Basic trigonometric ratios includes; sine cosine and tangent.

The bigger triangle with sides t, u, v and the smaller triangle with sides q, r , s are both right triangle so we can use the ratio of sine for their angle α to get the two equations as:

sin α = u/t {opposite/hypotenuse} for the bigger triangle.

sin α = r/s {opposite/hypotenuse} for the smaller triangle.

Therefore, the two equations to solve for angle α are sinα = u/t and sinα = r/s using the trigonometric ratio of sine

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Answer:

3√41

Step-by-step explanation:

a^2+b^2=c^2

rearrange this to make x (a or b it doesn't matter) the subject

√b=c^2-a^2

now substitute this in:

√b=25^2-16^2

=369

then simple do the square root

√369

=3√41

Hope this helps!

The value of x in the secant intersection is 4.

If two secant segments are drawn to a circle from an exterior point, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.

Therefore, let's find the value of x using the secant intersection theorem as follows;

4(4+x + 2) = 5(5 + x - 1)

4(6 + x) = 5(4 + x)

24 + 4x = 20 + 5x

24 - 20 = 5x - 4x

x = 4

Therefore,

x = 4

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What Amy did wrong was not moving the pointer to the arc intersection with the horizontal side

An angle bisector is defined in geometry as a line that splits an angle into two equal angles.

The steps involved in constructing an angle bisector are;

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For the following equations:

1) In general, the solutions can be expressed as θ = π/6 + 2πn or θ = 5π/6 + 2πn, where n is an integer.

2) The solutions within the interval (π/2) ≤ θ < 3π can be represented as θ = 7π/6 or θ = 11π/6, both in terms of π.

To solve the equation cscθ = 2, we need to find the values of θ that satisfy the equation.

1) General Form for All Solutions:

The reciprocal of sine is cosecant (csc), so we can rewrite the equation as 1/sinθ = 2. To solve for θ, we can take the reciprocal of both sides:

sinθ = 1/2

Now, we need to determine the values of θ where the sine function equals 1/2. The sine function is positive in the first and second quadrants, so we'll focus on those quadrants.

In the first quadrant (0 ≤ θ < π), the reference angle with a sine of 1/2 is π/6.

In the second quadrant (π < θ < 2π), the reference angle with a sine of 1/2 is also π/6.

To account for all solutions, we can add multiples of the period of sine (2π) to the reference angles. Therefore, the general form for all solutions is:

θ = π/6 + 2πn  or  θ = 5π/6 + 2πn

where n is an integer representing the number of periods of sine added.

2) Solutions on the Interval (π/2) ≤ θ < 3π in Terms of π:

For the given interval, we need to find the values of θ that satisfy the equation and lie within the interval (π/2) ≤ θ < 3π.

From the general form, we can see that the solutions that satisfy the interval are:

θ = π/6 + 2π  or  θ = 5π/6 + 2π

Simplifying these expressions gives us:

θ = 7π/6  or  θ = 11π/6

Therefore, the solutions on the interval (π/2) ≤ θ < 3π in terms of π are:

θ = 7π/6π or θ = 11π/6π.

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Si mamá compra una caja de cubitos de azúcar y María se come la capa superior (S) de 77 cubitos, luego se come la cara lateral (L) de 55 cubitos y finalmente se come la cara frontal (F) también, podemos determinar cuántos cubitos quedan en la caja sumando todas las partes que María ha consumido.

En total, María se ha comido 77 cubitos de la capa superior, 55 cubitos de la cara lateral y otros cubitos de la cara frontal. Como no se proporciona el número exacto de cubitos de la cara frontal, no podemos calcular el número total de cubitos que quedan en la caja.

Para obtener la cantidad final de cubitos que quedan en la caja, necesitaríamos saber cuántos cubitos hay en la cara frontal y luego restar la suma de los cubitos que María se ha comido. Sin esa información adicional, no podemos determinar cuántos cubitos quedan en la caja.

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The linear relationship illustrated in the provided table can be effectively described by the equation Y = -4x + 2. Option D.

To determine the equation that represents the given table with the values of x and y, we can observe the pattern and find the equation of the line that fits these points.

Given the table:

X: 2 0 4

Y: -4 3 1

We can plot these points on a graph and see that they form a straight line.

Plotting the points (2, -4), (0, 3), and (4, 1), we can see that they lie on a line that has a negative slope.

Based on the given options, we can now evaluate each equation to see which one represents the line:

Y = 1/2x + 5

When we substitute the x-values from the table into this equation, we get the following corresponding y-values: -3, 5, and 6. These values do not match the given table, so this equation does not represent the table.

Y = -1/2x + 3

When we substitute the x-values from the table into this equation, we get the corresponding y-values: 4, 3, and 2. These values also do not match the given table, so this equation does not represent the table.

Y = 2x - 3

When we substitute the x-values from the table into this equation, we get the corresponding y-values: -4, -3, and 5. These values do not match the given table, so this equation does not represent the table.

Y = -4x + 2

When we substitute the x-values from the table into this equation, we get the corresponding y-values: -6, 2, and -14. Interestingly, these values match the y-values in the given table. Therefore, the equation Y = -4x + 2 represents the table.

In conclusion, the equation Y = -4x + 2 represents the linear relationship described by the given table. So Option D is correct.

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Using substitution method, the solution to the system of linear equations

x = 26667 and y = 533

Let's set up the system of equations based on the given information.

Let:

x = number of currency A

y = number of currency B

Equation 1: x + y = 3200 (Total budgeted spending money)

Equation 2: 1.30x + 1.50y = Total cost of purchasing currency (to be determined)

Based on the information provided, Abigail wants to have five times as much currency A as currency B:

Equation 3: x = 5y

Now, let's solve the system of equations using substitution method

Substitute Equation 3 into Equation 1:

5y + y = 3200

6y = 3200

y = 3200 / 6

y = 533.33 (approximately)

Substitute the value of y back into Equation 3 to find x:

x = 5(533.33)

x = 2666.67 (approximately)

Now, let's calculate the total cost of purchasing currency using Equation 2:

Total cost of purchasing currency = 1.30x + 1.50y

Total cost of purchasing currency = 1.30(2666.67) + 1.50(533.33)

Total cost of purchasing currency = 3466.67 + 800

Total cost of purchasing currency = 4266.67 (approximately)

Therefore, the system of equations has a solution where:

x ≈ 2667 (number of currency A)

y ≈ 533 (number of currency B)

This means that Abigail should exchange approximately 2667 units of currency A and 533 units of currency B. The total cost of purchasing the currency would be approximately $4266.67.

In practical terms, this means that Abigail will have a budgeted spending money of $3200, and she plans to allocate it between currency A and currency B based on the given exchange rates and her preference of having five times as much currency A as currency B.

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The triangles ∆UTS and ∆UBA are similar, hence we can write the similarity statement as:"Triangle ∆UTS is similar to triangle ∆UBA."

To determine if triangles ∆UTS and ∆UBA are similar, we need to check if their corresponding angles are congruent and if their corresponding sides are proportional.

If ∆UTS is similar to ∆UBA, the following conditions must be true, then each angle in ∆UTS must have a corresponding congruent angle in ∆UBA. Also, the ratio of the lengths of corresponding sides in ∆UTS and ∆UBA must be equal.

AB/ST = 984/1271 = 0.7742

UB/UT = 768/994 = 0.7742

UA/US = 648/837 = 0.7742

AB/ST = UB/UT = UA/US

Therefore triangles ∆UTS and ∆UBA are similar, hence we can write the similarity statement as:"Triangle ∆UTS is similar to triangle ∆UBA."

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Answer:

The probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068

Step-by-step explanation:

We use the Exponential distribution,

Since we are given that on average, 5 pregnant women with high blood pressure come per week,

So, average = m = 5

Now, on average, 5 people come every week, so,

5 women per week,

so, we get 1 woman per (1/5)th week,

Hence, the mean is m = 1/5 for a woman arriving

and λ = 1/m = 5 = λ

we have to find the probability that it takes higher than a week for a high BP pregnant woman to arrive, i.e,

P(X>1) i.e. the probability that it takes more than a week for a high BP pregnant woman to show up,

Now,

P(X>1) = 1 - P(X<1),

Now, the probability density function is,

[tex]f(x) = \lambda e^{-\lambda x}[/tex]

And the cumulative distribution function (CDF) is,

[tex]CDF = 1 - e^{-\lambda x}[/tex]

Now, CDF gives the probability of an event occuring within a given time,

so, for 1 week, we have x = 1, and λ = 5, which gives,

P(X<1) = CDF,

so,

[tex]P(X < 1)=CDF = 1 - e^{-\lambda x}\\P(X < 1)=1-e^{-5(1)}\\P(X < 1)=1-e^{-5}\\P(X < 1) = 1 - 6.738*10^{-3}\\P(X < 1) = 0.9932\\And,\\P(X > 1) = 1 - 0.9932\\P(X > 1) = 6.8*10^{-3}\\P(X > 1) = 0.0068[/tex]

So, the probability that on a particular week, the hospital will receive on high BP pregnant woman is 0.0068

Answer: rotation of 90 counter clockwise about the origin

Step-by-step explanation:

The important variables are the two types of test questions which can be represented as :

Variables are used to represent unknown values which could be worked out in a mathematical expression or problem.

The variables or unknown in this case are the type of test questions. which are : m for multiple choice, s for short answer

Therefore, the correct option is C. m for multiple choice, s for short answer

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Answer:

(x + 3)(5x + 2) , (2x - 1)(3x + 5)

Step-by-step explanation:

given

A = 5x² + 12x + 6

consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 5 × 6 = 30 and sum = 17

the factors are + 15 and + 2

use these factors to split the x- term

5x² + 15x + 2x + 6 ( factor the first/second and third/fourth terms )

= 5x(x + 3) + 2(x + 3) ← factor out (x + 3) from each term

= (x + 3)(5x + 2)

then

length = x + 3 , breadth = 5x + 2 or indeed the other way round

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given

A = 6x² + 7x - 5

consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × - 5 = - 30 and sum = + 7

the factors are - 3 and + 10

use these factors to split the x- term

6x² - 3x + 10x - 5 ( factor the first/second and third/fourth terms )

= 3x(2x - 1) + 5(2x - 1) ← factor out (2x - 1) from each term

= (2x - 1()3x + 5)

then

length = 2x - 1 , breadth = 3x + 5 or the other way round

The volume of the pyramid is 357.7 inches³.

The volume of the cone is 1230.9 yard³.

The volume of a pyramid can be represented as follows;

volume of the pyramid = 1 / 3 Bh

where

Therefore,

B = 10 × 8 = 80 inches²

Hence,

h² =  14² - 4²

h = √196 - 16

h = √180

h = √180 inches

volume of the pyramid = 1 / 3 × 80 × √180

volume of the pyramid = 357.7 inches³

Therefore, let's find the volume of the cone.

volume of the cone = 1 / 3 πr²h

h = √25² - 7²

h = √576

h = 24 yards

volume of the cone = 1 / 3 × 3.14 × 7² × 24

volume of the cone = 1230.9 yard³

learn more on volume here: brainly.com/question/27903912

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