Determine a series of transformations that would map Figure O onto Figure P. ​

Answer:

\sqrt(3)[cos((4\pi )/(45))+isin((4\pi )/(45))]

Step-by-step explanation:

The first one.

Answer:

Step-by-step explanation:

For SSS congruence, all three pairs of sides must be marked as congruent. That is, there needs to be 3 hash marks on sides SU and RP. (Note the order of the vertices.)

  needed: SU ≅ RP

If we label the triangles in order by hash marks, the congruence statement becomes ...

  ΔPQR ≅ ΔUTS

Answer:

x is amount of money

c + a = 646

2c + 7a = x

2(380) + 7(246) = 2486

x = $2486

Answer: 30   Hope this helps please mark brainliest! Thanks!

Step-by-step explanation:

Five tenths=5/10=50%=1/2

So basically it's 30 out of 60 students brought lunch from home.

So the answer is 30!

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]

Then

[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]

Note that since

[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]

But since

[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]

and

[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]

Since

[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]

where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]

and

[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]

This link contains another solved problem on permutations:

https://brainly.com/question/7951365

Answer:

Part A: $60

Part B: $54

Step-by-step explanation:

Answer:

60% adult

40% children

Reasoning:

Add the adults and children first.

Then find the ratios of the children and parent percentages.

16:40 children

24:40 adult

16/40=2/5=0.4=40% children

24/40=3/5=0.6=60% adult

Answer:

40% is children and 60% in adults

Step-by-step explanation:

so if you add the two you have 40, 100% of 40 is 40 and 50% is 20, so we know that the children percent is less than 50, if you go through you will find that 40% of 40 is 16 therefor leaving the rest (aka 60%) to be adults

Answer:

Step-by-step explanation:

Given function:

Find f(-8):

f(-8)

Answer:

Step-by-step explanation:

K, but what's the question?

Answer:

[tex]k=\pm3[/tex]

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant [tex]\Delta = b^2-4ac[/tex] (or, if b is an even number, 1/4 of it) is zero.

I see it! I see it!

Stare at it for a while. First term is [tex]3(2x)^2[/tex], third term is [tex]3(1)^2[/tex], we are missing a double product, but we can play with k. For the LHS to be [tex]3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3[/tex] you just need [tex]4k= \pm12 \rightarrow k=\pm3[/tex].

I don't see it...

Then number crunching it is. Set the discriminant to 0, solve for k

[tex]\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3[/tex]

Answer:

128 130

Step-by-step explanation:

128 129 130

Answer:

$ 43.25

Step-by-step explanation:

68 - 40% = 40.8

40.8 + 6% = $ 43.25

Answer:

21

Step-by-step explanation:

The average rate of change of function f(x) from x = a to x = b is

[tex] \dfrac{f(b) - f(a)}{b - a} [/tex]

Here we have

a = -1

b = 2

f(a) = f(-1) = 1

f(b) = f(2) = 64

[tex] \dfrac{f(b) - f(a)}{b - a} = [/tex]

[tex] = \dfrac{f(2) - f(-1)}{2 - (-1)} = [/tex]

[tex] = \dfrac{64 - 1}{2 + 1} [/tex]

[tex] = \dfrac{63}{3} [/tex]

[tex] = 21 [/tex]

Answer:

0.9804

Step-by-step explanation:

0.68 ÷ 0.6936 = 0.98039215686275

Answer:

d = 3

Step-by-step explanation:

The sum to n terms of an AP is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] ( a + l)

where a is the first term and l the last term

Here a = 2, l = 59 and sum = 610 , then

[tex]\frac{n}{2}[/tex] (2 + 59) = 610

[tex]\frac{n}{2}[/tex] × 61 = 610 ( divide both sides by 61 )

[tex]\frac{n}{2}[/tex] = 10 ( multiply both sides by 2 to clear the fraction )

n = 20

Then the sequence has 20 terms with a₂₀ = 59

The nth term of an AP is

[tex]a_{n}[/tex] = a + (n - 1)d

where d is the common difference , then

2 + 19d = 59 ( subtract 2 from both sides )

19d = 57 ( divide both sides by 19 )

d = 3

Answer:

The answer is option D

Step-by-step explanation:

f (n)=-2. (-5)^n-1. Jesus loves you

Answer:

Step-by-step explanation:

(-4 - 4)/(3 - 1)= -8/2= -4

y - 4 = -4(x - 1)

y - 4 = -4x + 4

y = -4x + 8

answer is option 1

Answer:

Yes

Step-by-step explanation:

The best way to solve this question is to use ratios. The first ratio to make is 12:24. This represents how there are 12 boys for 24 girls. Ratios remain equivalent as long as both sides of the ratio are simplified by the same number. So, you can divide both sides by 6. When you divide both sides you get 2:4. Therefore, there are 2 boys for 4 girls.

Answer:

A

Step-by-step explanation:

Answer:

solve:

-3x+10<dividing22

-3x< 12

by a negativie flips sign

x>4

So A is correct because the because its an open circle  on number line

Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66 so B

i guess is by multiplying 3by the first equation and multiply 2by the second equation

Answer:

2nd one

Step-by-step explanation:

I know this because I learned about this

The growth amount is given by the growth rate the duration of the growth

and how the rate is applied to each period.

The correct selections are;

Reasons:

First part;

The given formula for the annual growth rate is; [tex]A(t) = \mathbf{P \cdot \left(1 + r)^t}[/tex]

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{[a]} \right)^{n \cdot t}}[/tex]

Where;

P = The principal

r = The rate per period

n = The number of compounding per period

t = The number of periods

In the above formula, we have that the number of compounding per periods = n

Therefore;

Which gives the fraction of the interest applied to each period as [tex]\displaystyle \frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}}[/tex]

Second part;

When [tex]x = \displaystyle \frac{n}{r}[/tex], we have; [tex]A(t) = \mathbf{P \cdot \left(1 + [b])^{n \cdot t}}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}[/tex]

Therefore;

[tex]\displaystyle b=\frac{r}{n}[/tex]

[tex]\displaystyle \frac{1}{x} = \frac{1}{\left(\frac{n}{r} \right)} =\frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle b=\frac{r}{n} = \mathbf{\frac{1}{x}}[/tex]

[tex]\displaystyle \underline{ b = \frac{1}{x} }[/tex]

Third part;

Where, n = x·r, and [tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t}}[/tex]

We have;

[tex]\displaystyle x= \frac{n}{r}[/tex]

[tex]\displaystyle \frac{1}{x}=\frac{r}{n}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t} = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{[c] \cdot t}}[/tex]

Which gives;

c = n = x·r

Fourth part;

If x is a really large number, we have; [tex]\displaystyle \mathbf{\left(1 + \frac{1}{x} \right)^x}[/tex]

Where x approaches ∞, we have;

[tex]\displaystyle \frac{1}{\infty}=0[/tex]

Which gives;

[tex]\displaystyle \displaystyle \left(1 + \frac{1}{x} \right)^x= \left(1 + \frac{1}{\infty} \right)^\infty = \displaystyle \left(1 + 0\right)^\infty = 1 ^\infty = 1[/tex]

Learn more about growth rate formula here:

https://brainly.com/question/2284816

Answer:

Lacey could afford 4.25lb of cherries

Step-by-step explanation:

Cost of onions= 3 lb x 0.98/1=2.94

21.45-2.94=18.48$

1 lb=4.35

18.48 x 1lb of cherries/4.35=4.25lb of cherries.

Hope I helped please mark brainliest it means a lot to my progression and thanks! <3

1 = 1 = 1 < 2 < 22

1 is equal to 1 is equal to 1 is less than 2 is less than 22

1 = 1    =1    < 2   < 22                                                                                                                1       1       1       1        1        hope help mark brain.....?

Answer:

114 degrees

Step-by-step explanation:

6x+12=3x+63

-3x -12 -3x  -12

3x=51

x=17

6(17) +12 = 114

Usando un sistema de ecuaciones, se encuentra que

Para el sistema, hay que:

$845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial, o sea:

[tex]3x + 5y + 3z = 845[/tex]

$580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial, o sea:

[tex]4x + 2y + z = 580[/tex]

$605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial, o sea:

[tex]x + 3y + 3z = 605[/tex]

Reemplazando la segunda equación en las otras duas:

[tex]z = 580 - 4x - 2y[/tex]

[tex]3x + 5y + 3z = 845[/tex]

[tex]3x + 5y + 3(580 - 4x - 2y) = 845[/tex]

[tex]-9x - y = -895[/tex]

[tex]9x + y = 895[/tex]

[tex]y = 895 - 9x[/tex]

[tex]x + 3y + 3z = 605[/tex]

[tex]x + 3y + 3(580 - 4x - 2y) = 605[/tex]

[tex]-11x - 3y = -1135[/tex]

[tex]11x + 3y = 1135[/tex]

[tex]y = 895 - 9x[/tex], por eso:

[tex]11x + 3(895 - 9x) = 1135[/tex]

[tex]-16x = -1550[/tex]

[tex]x = \frac{1150}{16}[/tex]

[tex]x = 96.875[/tex]

[tex]y = 895 - 9x = 895 - 9(96.875) = 23.125[/tex]

[tex]z = 580 - 4(96.875) - 2(23.125) = 146.25[/tex]

Un problema similar, que también envuelve un sistema de ecuaciones, es dado en https://brainly.com/question/24646137

Darrel has 50 grapes in all.

Lia has 72 green grapes, and she shares them equally between 8 friends. To find out how many grapes each friend receives, divide the total number of grapes by the number of friends:

Number of grapes each friend receives = 72 / 8 = 9

Now, Darrel adds 41 green grapes to his share, so the total number of grapes he has is:

Total grapes for Darrel = Number of grapes Darrel received initially + Additional grapes added by Darrel

Total grapes for Darrel = 9 + 41 = 50

To know more about grapes:

https://brainly.com/question/22694731

#SPJ2

The special right triangle is the right triangle that have acute angle values

that simplify the process of finding its dimensions.

The correct values are;

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.

Reasons:

1. The length of the ladder = 15 ft.

Height of the ladder above the ground, h = 13.8 ft.

Required:

The angle the ladder makes with the ground.

Solution:

The angle the ladder makes with the ground is given by the equation;

[tex]sin(\theta) = \dfrac{Length \ of \ the \ ladder}{Height\ of \ the \ ladder \ above the \ ground} = \dfrac{13.8}{15} = 0.92[/tex]

[tex]\theta = arcsin\left(0.92 \right) \approx 66.93^{\circ}[/tex]

2. The given parameters are;

XY = 11

∠Z = 35°

YZ = Required

In a right triangle, the side facing the acute angle is a leg of the triangle.

Therefore;

XY is the opposite side to ∠Z

[tex]sin(\angle Z) = \dfrac{XY}{YZ}[/tex]

Which gives;

[tex]sin(35^{\circ}) = \dfrac{11}{YZ}[/tex]

[tex]YZ= \dfrac{11}{sin(35^{\circ}) } \approx 19.18[/tex]

YZ ≈ 19.18 ft.

3. AC = 14 ft.

∠A = 30

Required:

The length of the other two sides

Solution:

Where by AC is the hypotenuse side, we have;

CB = AC × sin(∠A)

Therefore;

CB = 14 × sin(30°) = 7

CB = 7 ft.

AB =  AC × cos(∠A) = 14 × cos(30°) = 7·√3

Learn more here:

https://brainly.com/question/12237712

1. The angle the ladder makes with the ground, is approximately 66.93°

2. The length of YZ is approximately 19.18 ft.

3. CB = 7 ft. and AB = 7·√3 ft.