Answer:
(−∞,−7)∪(−7,0)∪(0,7)∪(7,∞)
Step-by-step explanation:
Answer:a. {x|x≠+-7}
Step-by-step explanation:
{REPOST: FORGOT TO INCLUDE PICTURE FOR QUESTION 10}
{Question 10} Please help, need this by tonight! Thanks so much :) {Click on picture}
Answer:
X-intercept: (6, 0)
Y-intercept: (0, -9)
Step-by-step explanation:
Required: Find the X and Y intercept of the standard from equation:
-3x + 2y = -18.
We shall write equation in the form [tex]\frac{x}{a} +\frac{y}{b} =1[/tex] and find the intercepts on X and Y axis:
-3x + 2y = -18
∴ -3x + 2y = -18
∴ -3x/-18 + 2y/-18 = 1
∴ x/6 + y/-9 = 1
Comparing this equation with [tex]\frac{x}{a} +\frac{y}{b} =1[/tex], we get:
intercept of X-axis = a = 6
intercept of Y-axis = b = -9
Thanks.
Answer:
The y-intercept for the line is ( 0, -9 ).
Hope this helps!
Step-by-step explanation:
The y-intercept is where the graph intercepts the y-axis and is the y-value of the point, ( x, y ).
Money is accepted as final payment for
O costs, benefits
O minting, exchange rates
goods, services
and
Money is anything generally accepted as final payment for goods, services, and debt.
First, let us understand the money supply:
The money supply is the total amount of currency and liquid assets in a country's economy on the day measured. Cash and deposits that can be utilized virtually as quickly as cash are roughly included in the money supply.
Money supply refers to the total amount of money held by the public for a particular point.
Governments print paper money and coins through a combination of central banks and treasuries. Bank regulators impact the money supply available to the public by requiring banks to retain reserves, determining how to grant credit, and other monetary matters.
We can say that we are using the money for goods purchasing, service requirements, and for the debt taken.
Thus, money is anything generally accepted as final payment for goods, services, and debt.
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{Question 9} Please help! Need this by tonight! Thanks so much! {Click on picture}
Step-by-step explanation:
3x + 2y = -18
Set y = 0
3x + 2 × 0 = -18
3x + 0 = -18
3x = -18
x = -6
.: the x-intercept = -6
You can choose to put it in coordinate form (-6, 0).
[tex]Answer: \boxed {(-6,0)}[/tex]
Step-by-step explanation:
The x-intersection coordinate of the equation 3x+2y=-18 is (x,0)
Hence, y=0
3x+2(0)=-18
3x+0=-18
3x=-18
Divide both parts of the equation by 3:
x=-6
Thus, (-6,0)
Find the value of x.
I really need help. Please help
Step-by-step explanation:
Using Triangle Intersection Theorem,
2(LM)=2+x
[tex]2(2x - 11) = 2 + x[/tex]
[tex]4x - 2 2 = 2 + x[/tex]
[tex]3x = 24[/tex]
[tex]x = 8[/tex]
Meredith is decorating a picture frame to give to her grandmother the frame has an area of 80 in² and a length of 10" Meredith wants to glue a piece of ribbon around the edge of the frame how many inches ribbon does Meredith need
Answer:36
Step-by-step explanation:
(c) The area that lies between Z=-1.71 and Z=0.08 is
(Round to four decimal places as needed.)
The area between z = -1.71 and z = 0.08 is 0.4883, in median .
What is median ?
The value of the middle observation found after the data are arranged in ascending order is referred to as the median of the data. In many cases, it is challenging to take all of the facts into account when representing something, and in these cases, median is helpful. The median is one of the simple to compute statistical summary metrics. The median is also known as the place average since it uses the data that is in the centre of a sequence to determine its value.
=> P(-1.71 < Z < 0.08 ) = P(Z < 0.08 ) - P(Z < -1.71)
= 0.5319 - [1 - P(Z < 1.71)]
= 0.5319- [1 - 0.9564]
= 0.4883
Hence, the area between z = -1.71 and z = 0.08 is 0.4883.
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helppppppppppppppppppp
Answer:
f(-7) = 18
f(-3) = 14
f(4) = 7
Step-by-step explanation:
f(-7)
l-7-8l + 3
l-15l + 3
15 + 3
18
F(-3)
l-3-8l + 3
l-11l + 3
11 + 3
14
F(4)
l4-8l + 3
l-4l + 3
4 + 3
7
Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A sample of 2400 bacteria selected from this population reached the size of 2892 bacteria in four hours. Find the hourly growth rate parameter.
Answer: [tex]\frac{\ln(241/200)}{4}[/tex]
Step-by-step explanation:
If [tex]P(t)[/tex] represents the number of bacteria after [tex]t[/tex] hours, then [tex]P(t)=2400e^{kt}[/tex], where [tex]k[/tex] is the hourly growth rate parameter.
Using the fact that [tex]P(4)=2892[/tex],
[tex]2892=2400e^{4k}\\\\e^{4k}=\frac{241}{200}\\\\4k=\ln(241/200)\\\\k=\frac{\ln(241/200)}{4}[/tex]
What is the prime factored form of the lowest common denominator of
2/3 + 7/10
Answer:
common denominator = 2·3·5
Step-by-step explanation:
You want the factorization of the common denominator of 2/3+7/10.
DenominatorsThe denominators of the fractions in the given sum are 3 and 10. Their prime factors are ...
3 = 3
10 = 2·5
Common denominatorThe common denominator factors will be the product of the unique factors in the above list:
common denominator = 2·3·5
__
Additional comment
Using the common denominator, the sum is ...
20/30 +21/30 = 41/30 = 1 11/30
A line slope is1 and its Y-intercept is -8. what is the equation in slope Internet form?
Step-by-step explanation:
the slope-intercept form is
y = ax + b
with "a" being the slope, and "b" being the y-intercept (the y- value when x = 0).
so, we have
y = x - 8
The following scatterplot shows two variables, x and y, along with a least-squares model.
Which of the following is a high leverage point with respect to the regression?
A (5,8)(5,8)
B (20,31)(20,31)
C (27,22)(27,22)
D (30,60)(30,60)
E (80,70)
Answer:
D(30,60)
Step-by-step explanation:
It was way outside the other points that are around the line.
The point (30,60) is a high leverage point on the regression plot.
What is High leverage points?High leverage points are those that are extreme but follow the regression equation's trend.
High leverage points are distinct from outliers, which deviate from the graph's or plot's pattern or trend.
Looking closely at the regression plot, the coordinate (30,60) follows the trend of the plot, however, it is farther from the majority of the points on the graph.
Hence, the point (30,60) is a high leverage point on the regression plot.
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Giving an arithmetic sequence with a33=66 and a common difference of 2.
Find a1;
Hint: Use an = a1 + (n-1) d
a1= ___________
Find the sum of the first 30 terms:
Hint: Use an = a1 + (n-1) d and Sn = n/2 (a1 + an)
S30 = __________
The first term [tex]a_{1}[/tex] = 2 and the sum of first 30 terms [tex]s_{30}[/tex] = 930
What is an Arithmetic progression?Arithmetic Progression (AP) is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value.
Arithmetic sequence is gotten by adding a known term by a constant value.
if [tex]a_{33}[/tex] = 66 and d = 2 and [tex]a_{n}[/tex] = [tex]a_{1}[/tex] + (n -1)d and n = 33
Then
[tex]a_{33}[/tex] = [tex]a_{1}[/tex] + 32d,
making [tex]a_{1}[/tex] subject of the equation we have
[tex]a_{1}[/tex] =66 - 32 x 2
[tex]a_{1}[/tex] = 66 - 64
[tex]a_{1}[/tex] = 2
if n = 30, [tex]a_{1}[/tex] =-2, d = 2
Then
[tex]a_{30}[/tex] = 2 + ( 30 - 1) x 2
[tex]a_{30}[/tex] = 2 + 29 x 2
[tex]a_{30}[/tex] = 60
if [tex]s_{n}[/tex] = n/2([tex]a_{1}[/tex] + [tex]a_{n}[/tex])
Then,
[tex]s_{30}[/tex] = n/2 ( [tex]a_{1}[/tex] + [tex]a_{30}[/tex]) where n = 30
[tex]s_{30}[/tex] = 30/2( 2 + 60)
[tex]s_{30}[/tex] = 930
In conclusion, the sum of he first 30 terms is 930 and the first term is 2
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Sat question solve
2^x=x^2
The logarithm function can be used to convert large problem of multiplication and division into simple addition or subtraction. The value of x for the given equation is 2.
What is Logarithm?Logarithm function is defined as the inverse of the exponential function.
If a^(b) = c, then b = log(c) at the base of a.
The given equation is as below,
2^x=x^2
Take logarithm both sides,
x log(2) = 2 log(x)
=> x / log(x) = 2 / log(2)
Compare the denominator and numerator at both sides of the equation to get,
x = 2.
Hence the solution of the given equation is x = 2.
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(2,-4) and (-8,4) find the slope of the line going through the given points
Answer:
Step-by-step explanation: formula is (y2 - y1) / (x2 - x1)
so in this case it is: (4-(-4) / (-8 - 2) -> 8/-10 -> -4/5(final solution)
The tangent to g(x) = ar³ + 3x² + bx+c has a minimum gradient at the point (-1; -7). For which values of x will g be concave up?
The gradient of the function at the point (-1 -7) is 3a - 6.
What is the gradient of the function?
A function's gradient is also known as its slope, and the slope (of a tangent) at a given point on a function is known as its derivative.
We have,
g(x) = ax³ + 3x² + bx + c
Take the derivative of the function with respect to x, then substitute the x-coordinate of the point of interest in for the x values in the derivative to find the gradient.
to know the gradient of the function ax³ + 3x² + bx + c at the point (-1, -7) we would do the following:
Take the derivative with respect to x:
g'(x) = 3ax² + 6x + b
Substitute the x-coordinate (x = -1)in for x:
gradient = 3a(-1)² + 6(-1) + b = 3a - 6
So the gradient of the function at the point (-1 -7) is 3a - 6.
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Help find the slope of the line passing through the points??
Answer: [tex]\frac{11}{5}[/tex]
Step-by-step explanation
(y2-y1)/(x2-x1)
which means (5-(-6))/-4-(-9)=[tex]\frac{11}{5}[/tex]
URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!
Answer:
the interior angles of a triangle add to be 180 degrees.
the value of angle x = 36 degrees
the value of angle y = 84 degrees
If EF measures 12 meters the approximate area of circle b
The EF is the diameter. Then the area of the circle is 113.04 square meters.
circle :
A circle is a circular shape without corners or line segments. In terms of geometry, it has the shape of a closed curve.
EF = diameter
EF = 12 meter
then, radius = d/2 = 12/2 = 6 meter
Area of the circle is calculated as:
area = πr²
area = 3.14 x 6 x 6
area = 113.04 square meter
The given que is incomplete . The correct question is given as :
The EF is the diameter. If EF measures 12 meters, the approximate area of circle B is square meters.
The EF is the diameter. Then the area of the circle is 113.04 square meters.
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What is an adjacency matrix Mcq?
An adjacency matrix is defined as the square matrix that is used to describe the finite graph
What is an adjacency matrix?An adjacency matrix is defined as the square matrix that is used to describe the finite graph which is also an example of graph theory.
The adjacency matrix is made up of rows and columns which is used to represent a simple labelled graph. it is also called connection matrix.
The properties of an adjacency matrix include the following:
Matrix powers,SpectrumIsomorphisms.The adjacency matrix can be used to represent indirect or direct graph.
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An adjacency matrix is a square matrix used to describe the finite graph.
What exactly is an adjacency matrix?An adjacency matrix is a square matrix used to describe a finite graph, which is also a kind of graph theory.
The adjacency matrix, which consists of rows and columns, is used to depict a basic labeled graph. It is also known as a connection matrix. The adjacency matrix can represent either an indirect or direct graph.
An adjacency matrix has the following properties:
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A straw is placed inside a rectangular box that is 4 inches by 2 inches by 10 inches, as
shown. If the straw fits exactly into the box diagonally from the bottom left corner to
the top right back corner, how long is the straw? Leave your answer in simplest
radical form.
10 in.
4 in.
2 in.
Answer:
The length of the straw in the simplest radical form is [tex]2\sqrt{30}[/tex] inches
Step-by-step explanation:
The length of the straw can be calculated as follow
The first step is to calculate the diagonal of the base of the rectangular box by using Pythagorean theorem
[tex]c^{2}=a^{2}+b^{2}[/tex]
Where [tex]c[/tex] is the base diagonal or the hypotenuse, [tex]a[/tex] is the short leg, [tex]b[/tex] is the long leg
Substitute [tex]2[/tex] for [tex]a[/tex], [tex]4[/tex] for [tex]b[/tex] in the Pythagorean theorem
[tex]c^{2}=2^{2}+4^{2}[/tex]
Simplify the right side of the equation
[tex]c^{2}=4+16[/tex]
[tex]c^{2}=20[/tex]
Take the square root of the right side to get the value of [tex]c[/tex]
[tex]c=\sqrt{20}[/tex]
Factor [tex]20[/tex] by [tex]4[/tex]
[tex]c=\sqrt{4\times 5}[/tex]
Substitute [tex]2^{2}[/tex] for 4
[tex]c=\sqrt{2^{2}\times 5}[/tex]
Rewrite the value of [tex]c[/tex] in the simplest radical form
[tex]c=2\sqrt{5}[/tex]
Since the value of [tex]c[/tex] is [tex]2\sqrt{5}[/tex], then the length of the diagonal of the base is
[tex]2\sqrt{5}[/tex] inches
The second step is to calculate the length of the straw by using Pythagorean theorem
[tex]c^{2}=a^{2}+b^{2}[/tex]
Where [tex]c[/tex] is the diagonal from the bottom left corner to the top right back corner or the hypotenuse, [tex]a[/tex] is the short leg, [tex]b[/tex] is the long leg
Substitute [tex]2\sqrt{5}[/tex] for [tex]a[/tex], [tex]10[/tex] for [tex]b[/tex] in the Pythagorean theorem
[tex]c^{2}=(2\sqrt{5})^{2}+10^{2}[/tex]
Simplify the right side of the equation
[tex]c^{2}=20+100[/tex]
[tex]c^{2}=120[/tex]
Take the square root of the right side to get the value of [tex]c[/tex]
[tex]c=\sqrt{120}[/tex]
Factor [tex]120[/tex] by [tex]4[/tex]
[tex]c=\sqrt{4\times 30}[/tex]
Substitute [tex]2^{2}[/tex] for 4
[tex]c=\sqrt{2^{2}\times 30}[/tex]
Rewrite the value of [tex]c[/tex] in the simplest radical form
[tex]c=2\sqrt{30}[/tex]
Since the value of [tex]c[/tex] is [tex]2\sqrt{30}[/tex], then the length of the diagonal from the bottom left corner to the top right back corner or the hypotenuse is
[tex]2\sqrt{30}[/tex] inches
Since the length of the diagonal from the bottom left corner to the top right back corner is [tex]2\sqrt{30}[/tex] inches, then the length of the straw is [tex]2\sqrt{30}[/tex] inches
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I need the answer fast
Over 48.6 hours are worked by 2.28 percent of faculty members each week.
Given that,
In a college, a full-time faculty member typically puts in 43 hours each week.
We have to find how many faculty members work more than 48.6 hours each week, assuming the standard deviation is 2.8 hours.
What is z-score?The Z-score determines the measure's standard deviations away from the mean. After calculating the Z-score, we look at the p-value associated with it in the z-score table. This p-value is the probability that the measure's value is smaller than X, or the percentile of X. By subtracting 1 from the p-value, one can determine the likelihood that the value of the measure is greater than X.
In a college, a full-time faculty member typically puts in 43 hours each week. 2.8 hour standard deviation.
This means μ=43 and σ=2.8
What proportion of academic staff employees put in more than 58.6 hours each week.
When X = 48.6, the proportion is calculated by deducting 1 from the p-value of Z.
So,
Z=X-μ/σ
Z=48.6-43/2.8
Z=5.6/2.8
Z=2
Z=2 has a p-value of 0.9772
1 - 0.9772 = 0.0228
0.0228*100% = 2.28%
Therefore, Over 48.6 hours are worked by 2.28 percent of faculty members each week.
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write an equation of the passing through the point (4,-1) and perpendicular to line y=2x-5
Answer: Line perpendicular to y = 2x - 5 is y = (-1/2)x.
Step-by-step explanation:
The graph shows the cube root parent function.
-5
5.
-5-
5
Which statement best describes the function?
A. The function is always increasing.
OB. The function is increasing when x < 0.
C. The function is increasing when x > 0.
D. The function is never increasing.
The graph of the function is increasing when x>0.
What is graph?
Graph a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.
What is cube root parent?
The basic parent cube root function is of the form f (x) = ∛x. It increases on the interval (-∞, ∞). It increases on the interval [0, ∞). It is positive on (0, ∞) and negative on (-∞, 0). It is a non-negative function always (on [0, ∞)). Its absolute min is 0 but no absolute max. Its domain and range is the set of all real numbers.
Given,
The function f(x) = ∛x
Let x = 1, we get f(x) = 1,
x =2, f(x) = 8
if x =3, f(x) = 27.
As we know, with increase in the value of x, the value of f(x) is also increasing.
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there are 3 towns, ainsly broking and Cinderford
Check the picture below.
[tex]\textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)\cos(C)\implies c = \sqrt{a^2+b^2-(2ab)\cos(C)} \\\\[-0.35em] ~\dotfill\\\\ b = \sqrt{7^2+11^2~-~2(7)(11)\cos(92^o)} \\\\\\ b = \sqrt{ 170 - 154 \cos(92^o) }\implies b\approx 13.24~km[/tex]
now, to find the bearing from C to A hmmm, let's use the Law of Cosines again, to find the angle at A, once we get that, we'll simply add 37 to it :)
[tex]\textit{Law of Cosines}\\\\ \cfrac{a^2+b^2-c^2}{2ab}=\cos(C)\implies \cos^{-1}\left(\cfrac{a^2+b^2-c^2}{2ab}\right)=\measuredangle C \\\\[-0.35em] ~\dotfill\\\\ \cos^{-1}\left(\cfrac{7^2+13.24^2-11^2}{2(7)(13)}\right)\approx\measuredangle A \implies \cos^{-1}\left(\cfrac{ 103.3 }{ 185.36}\right)\approx\measuredangle A \\\\\\ 56.13^o\approx \measuredangle A\hspace{15em} \underset{\textit{Bearing of C from A}}{\stackrel{56.13~~ + ~~37}{\boxed{\approx 93.13^o}}}[/tex]
The solution to the system of equations x + y = 40 and x = 4y is:
(32, 8).
(29, 11).
(8, 32).
Answer:
(32, 8)
Step-by-step explanation:
Substitute 4y for x in x + y = 40 and solve for y. Then find x.
[tex]4y + y = 40[/tex]
[tex]5y = 40[/tex]
[tex]y = 8[/tex]
[tex]x = 4(8) = 32[/tex]
Four lengths have a mode of 12 km and a range of 5 km. One of the lengths is 14 km. What are the other three lengths?
The other three length are 9km,12km,14km as mode is 12km
What is mode?
The value that appears most frequently in a set of values is referred to as the mode. It is the value that shows up the most frequently. The value that consistently appears in a given set is known as the mode in statistics. The mode or modal value is the value or number that appears most frequently in a data set and has a high frequency. Along with mean and median, there are three other ways to measure central tendency.
The mean, median, and mode all have the same values for this distribution. This indicates that this value—the one that appears the most frequently in the data—is the average, the centre, and the mode.
Four lengths have a mode of 12 km and a range of 5 km.
The range is the largest number minus the smallest number.
As mode is 12 so one more number is 12 as well.
Now another number given 14km, so the last number is (14-5 = 9)
Hence the other three lengths are 9km,12km,14km.
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7x=2x²+1, solve the equation
Answer:
[tex] x =\dfrac{7+\sqrt{41}}{4},\dfrac{7-\sqrt{41}}{4} [/tex]
Step-by-step explanation:
The given equation is ,
[tex]\longrightarrow 7x = 2x^2+1[/tex]
We can rewrite it as ,
[tex]\longrightarrow 2x^2-7x + 1=0 [/tex]
On comparing with the standard form of quadratic equation [tex] ax^2+bx + c [/tex] , we have ;
[tex]a = 2[/tex][tex]b = - 7[/tex][tex]c = 1[/tex]On using the quadratic formula , we have;
[tex]\longrightarrow x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\[/tex]
[tex]\longrightarrow x =\dfrac{-(-7)\pm\sqrt{(-7)^2-4(2)(1)}}{2(2)} \\[/tex]
[tex]\longrightarrow x =\dfrac{7\pm\sqrt{49-8}}{4}\\ [/tex]
[tex]\longrightarrow x =\dfrac{7\pm\sqrt{41}}{4}[/tex]
separate the solutions ,
[tex]\longrightarrow x =\dfrac{7+\sqrt{41}}{4},\dfrac{7-\sqrt{41}}{4} [/tex]
And we are done !
use implicit differentiation to find y" in terms of x and y.
Using implicit differentiation, the value of y in terms of x and y is; y = 0.5/(dy/dx)
How to solve implicit differentiation?In implicit differentiation, what we do is that we differentiate each side of an equation using the two variables (usually x and y) by treating one of the variables to be as a function of the other.
We are given the equation;
4x = 4y² + 1
Thus, first differentiation gives;
4 = 8y(dy/dx)
y(dy/dx) = 0.5
y = 0.5/(dy/dx)
This is the result when using implicit differentiation on the given function where y is the subject of the formula.
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Use the recipe to find how much hair conditioner Helena
needs to make a half batch and a double batch?
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Find the arc length of the curve y =
1/2(e^x + e^-x) from x = 0 to x = 4.
The arc length of the given curve is L= 1/2([tex]e^{4} - \frac{1}{e^{4} }[/tex]).
What is arc length?
The distance between two places along a segment of a curve is known as the arc length.
Main Body:
So, we have [tex]y=\frac{1}{2} (e^{x} +e^{-x} )[/tex]
This is in the form y=f(x), so we know arc length L on [0,4] is given by,
L=[tex]\int\limits^4_0{\sqrt{1+(\frac{dy}{dx} })^{2} \, dx[/tex]
The derivative y=
dy/dx= [tex]\frac{1}{2} (e^{x} +e^{-x} )[/tex]= sinhx
([tex]\frac{dy}{dx}^{2}[/tex])= sinh²x
L=[tex]\int\limits^4_0{\sqrt{1+sinh^{2}x \, dx[/tex]
L= [tex]\int\limits^4_0{\sqrt{cosh^{2}x \, dx[/tex]
L=[tex]\int\limits^4_0{coshx \, dx[/tex]
Now putting the limits as given=
L= [tex]sinhx\left \{ {{y=4} \atop {x=0}} \right.[/tex]
L= [tex]\frac{1}{2} (e^{x} -e^{-x} )[/tex]|⁴₀
L=1/2([tex]e^{4} - \frac{1}{e^{4} }[/tex])
Hence the answer is 1/2( [tex]e^{4} - \frac{1}{e^{4} }[/tex]).
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