The mean and variance of the random variable X are 12/7 and 56/2401 respectively, rounded to three decimal places.
Given the probability mass function: f(x) = (8/7)(1/2) * x,
x = 1,2,3.
The formula for the mean or expected value of a discrete random variable is:μ = Σ[x * f(x)], for all values of x.Here, x can take the values 1, 2, and 3.
Let us calculate the expected value of X or the mean (μ):
μ = Σ[x * f(x)] = 1 * (8/7)(1/2) + 2 * (8/7)(1/2) + 3 * (8/7)(1/2)
= 24/14
= 12/7
So, the mean of the random variable X is 12/7.
To find the variance of X, we first need to calculate the squared deviation of X about its mean: (X - μ)².For X = 1, the deviation is (1 - 12/7) = -5/7
For X = 2, the deviation is (2 - 12/7) = 3/7
For X = 3, the deviation is (3 - 12/7) = 9/7
So, the squared deviations are: (5/7)², (3/7)², and (9/7)².
Using the formula for the variance of a discrete random variable,
Var(X) = Σ[(X - μ)² * f(X)], for all values of X. We have,
Var(X) = [(5/7)² * (8/7)(1/2)] + [(3/7)² * (8/7)(1/2)] + [(9/7)² * (8/7)(1/2)] - [(12/7)²]
Var(X) = (200/343) - (144/49)
= 56/2401
Therefore, the variance of the random variable X is 56/2401.
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1. Findf(g(x))andg(f(x)). f(x) = 10x;g(x)=x+3 f(g(x)) = g(f(x)) = a. 10x +30 b. 10² +3 c. 10x +30 d. 11x +3 e. 10x +3
A function is a rule or connection in mathematics that pairs each element from one set, known as the domain, with a certain element from another set, known as the codomain. A function generates output values in the codomain that correspond to input values from the domain. The correct answer is option e.
Typically, a function is denoted by the notation f(x), where x is the input variable and f is the name of the function.
The given functions are; f(x) = 10x and g(x) = x + 3. To find f(g(x)), first, we evaluate g(x) and substitute that value in place of x in f(x).
We change g(x) into f(x) to discover f(g(x)):
The equation f(g(x)) = f(x + 3) = 10(x + 3) = 10x + 30
Consequently, f(g(x)) = 10x + 30.
We change f(x) into g(x) to discover g(f(x)):
g(f(x))=g(10x)=10x + 3
g(f(x)) is therefore equivalent to 10x + 3
Therefore, the right answer is e) 10x + 3
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451) Given the two 3-D vectors a=[5, -3, -6] and b=[3, -5, -8], find the dot product and angle (degrees) between them. Also find the cross product (a = a cross b) and the unit vector in the direction of d. ans: 8
Dot Product: 78
Angle: θ ≈ 29.07 degrees
Cross Product: a × b = [-6, 22, -34]
Unit Vector in the direction of a: u = [5 / √70, -3 / √70, -6 / √70].
To find the dot product and angle between two vectors, as well as the cross product and unit vector in a specific direction, we can use the following formulas:
Dot Product: The dot product of two vectors a and b is calculated by taking the sum of the products of their corresponding components.
Angle: The angle θ between two vectors a and b can be found using the dot product formula and the magnitude (or length) of the vectors:
cos(θ) = (a · b) / (|a| × |b|),
θ = arccos((a · b) / (|a| × |b|)).
Cross Product: The cross product of two vectors a and b is a vector that is perpendicular to both a and b. It can be calculated using determinants:
a × b = [a₁ × b₂ - a₂ × b₁, a₂ × b₀ - a₀ × b₂, a₀ × b₁ - a₁ × b₀].
Unit Vector: The unit vector in the direction of a vector d can be obtained by dividing the vector by its magnitude:
u = d / |d|.
Now, let's calculate these values for the given vectors a = [5, -3, -6] and b = [3, -5, -8]:
Dot Product:
a · b = 5 × 3 + (-3) × (-5) + (-6) × (-8) = 15 + 15 + 48 = 78.
Angle:
|a| = √(5² + (-3)² + (-6)²) = √(25 + 9 + 36) = √70,
|b| = √(3² + (-5)² + (-8)²) = √(9 + 25 + 64) = √98.
cos(θ) = (a · b) / (|a| × |b|) = 78 / (√70 × √98) ≈ 0.878,
θ ≈ arccos(0.878) ≈ 29.07 degrees.
Cross Product:
a × b = [(-3) × (-8) - (-6) × (-5), (-6) × 3 - 5 × (-8), 5 × (-5) - (-3) × 3]
= [24 - 30, -18 + 40, -25 - 9]
= [-6, 22, -34].
Unit Vector:
|d| = √(5² + (-3)² + (-6)²) = √(25 + 9 + 36) = √70.
u = a / |d| = [5 / √70, -3 / √70, -6 / √70].
Therefore:
Dot Product: 78
Angle: θ ≈ 29.07 degrees
Cross Product: a × b = [-6, 22, -34]
Unit Vector in the direction of a: u = [5 / √70, -3 / √70, -6 / √70].
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A food court contains three restaurants: Mountain Mike's Pizza.Panda Express.and Subway. Suppose 35 percent of people who go to the food court will eat at Mountain Mike's Pizza.30 percent will eat at Panda and 25 percent at Subway.Assume the choices of different people are independent. a(5 points What is the probability that fourth person to go to the food court will be the second one to eat at Subway b(5 pointsFind probability that out of the next 10 visitors 4 will go to Mountain Mike's Pizza.
a) The probability that the fourth person to go to the food court will be the second one to eat at Subway is 0.12207 or approximately 12.21%.
b) The probability that out of the next 10 visitors, 4 will go to Mountain Mike's Pizza is 0.0494 or approximately 4.94%.
Given, The probability that people who go to the food court will eat at Mountain Mike's Pizza is 35%.
The probability that people who go to the food court will eat at Panda Express is 30%.
The probability that people who go to the food court will eat at Subway is 25%.
Assume the choices of different people are independent.
a) The probability that the fourth person to go to the food court will be the second one to eat at Subway
Let P(S) be the probability that a person eats at Subway and Q(S) be the probability that a person doesn't eat at Subway.
Then, P(S) = 0.25 and
Q(S) = 1 - P(S)
= 0.75.
Suppose the fourth person to go to the food court is the second one to eat at Subway.
Then, the first three people can either eat at different restaurants or at least two of them can eat at Subway.
Therefore, the required probability can be calculated as follows:
Probability = P(eat at different restaurants) + P(eat at Subway, eat at different restaurant, eat at Subway, eat at Subway) = (0.35 × 0.3 × 0.75 × 0.75) + (0.35 × 0.25 × 0.75 × 0.25)
= 0.065625 + 0.01875
= 0.084375
= 0.0844 (approx.)
Therefore, the probability that the fourth person to go to the food court will be the second one to eat at Subway is 0.0844 or approximately 8.44%.
b) The probability that out of the next 10 visitors, 4 will go to Mountain Mike's Pizza
Let P(M) be the probability that a person eats at Mountain Mike's Pizza and Q(M) be the probability that a person doesn't eat at Mountain Mike's Pizza.
Then, P(M) = 0.35 and
Q(M) = 1 - P(M)
= 0.65.
The required probability can be calculated using the binomial distribution formula:
P(4 people go to Mountain Mike's Pizza out of 10 people) = ${}_{10}C_4$ $P(M)^4Q(M)^6$= $\frac{10!}{4! \times (10-4)!}$ $(0.35)^4 (0.65)^6$
= 210 $\times$ 0.015707 $\times$ 0.08808
= 0.0494 (approx.)
Therefore, the probability that out of the next 10 visitors, 4 will go to Mountain Mike's Pizza is 0.0494 or approximately 4.94%.
The probability that the fourth person to go to the food court will be the second one to eat at Subway is 0.0844 or approximately 8.44%.
The probability that out of the next 10 visitors, 4 will go to Mountain Mike's Pizza is 0.0494 or approximately 4.94%.
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.The demand for a new computer game can be modeled by p(x) = 40.5-8 In x, for 0≤x≤ 800, where p(x) is the price consumers will pay, in dollars, and x is the number of games sold, in thousands. Recall that total revenue is given by R(x)=x. p(x). Complete parts (a) through (c) below. a) Find R(x). R(x) =
Total revenue function is R(x) = x(40.5 - 8ln(x)).
What is the total revenue function?To find the total revenue function, we multiply the price per unit by the quantity sold. In this case, the price per unit is given by the function p(x) = 40.5 - 8ln(x), and the quantity sold is x.
Therefore, the total revenue function R(x) is:
R(x) = x * p(x)
Substituting the given function for p(x):
R(x) = x * (40.5 - 8ln(x))
Expanding the expression:
R(x) = 40.5x - 8xln(x)
So, the total revenue function is R(x) = 40.5x - 8xln(x).
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A certain bicycle manufacturing company can produce 20 bicycles for a total daily cost of $2600 and 42 bicycles for a total daily cost of $4140. Assuming the daily cost and production are linearly related, where x is the number of bicycles produced and y is the total daily cost. 15 points Show all work a) Find the slope of the line. Use the points (20, 2600) and (42, 4140) b) Find an equation in y = mx + b form. c) Interpret the slope and y-intercept. d) What is the daily cost for producing 62 bicycles. e) How many bicycles can be produced for $5190.
Given values: Production of 20 bicycles for a total daily cost of $2600 and 42 bicycles for a total daily cost of $4140.
The relation is linear between daily cost (y) and production (x).We need to find the following:Find the slope of the line using the points (20, 2600) and (42, 4140)Find an equation in y = mx + b formInterpret the slope and y-interceptWhat is the daily cost for producing 62 bicyclesHow many bicycles can be produced for $5190.(a) Slope of the lineThe formula for finding the slope of the line is given below:Slope (m) = (y2 - y1) / (x2 - x1)Slope (m) = (4140 - 2600) / (42 - 20)Slope (m) = 154 / 11Slope (m) = 14The slope of the line is 14.(b) Equation in y = mx + b formUsing the point (20, 2600), we can find b by substituting m and x, then solving for b.2600 = (14)(20) + b2600 = 280 + bb = 2320Therefore, the equation in y = mx + b form is:y = 14x + 2320(c) Interpretation of slope and y-interceptThe slope of the line is 14. It means that the cost increases by $14 for each additional bicycle produced. In other words, the company is spending $14 per bicycle produced.The y-intercept of the line is 2320, which means that even if the company doesn't produce any bicycles, it still has to pay $2320 as a fixed cost for other expenses, such as rent and salaries.(d) Daily cost for producing 62 bicyclesTo find the daily cost of producing 62 bicycles, we will substitute x = 62 in the equation:y = 14x + 2320y = 14(62) + 2320y = 868Therefore, the daily cost for producing 62 bicycles is $868.(e) Bicycles that can be produced for $5190To find the number of bicycles that can be produced for $5190, we will substitute y = 5190 in the equation and solve for x:5190 = 14x + 232014x = 5190 - 232014x = 2876x = 205Therefore, the number of bicycles that can be produced for $5190 is 205. Answer: (a) The slope of the line is 14.(b) y = 14x + 2320(c) The slope of the line is the cost per bicycle produced, which is $14. The y-intercept is the fixed cost of $2320.(d) The daily cost for producing 62 bicycles is $868.(e) The number of bicycles that can be produced for $5190 is 205.
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(a) The slope of the line is 14.(b) y = 14x + 2320(c) The slope of the line is the cost per bicycle produced, which is $14, y-intercept is $2320.(d) cost for producing 62 bicycles is $868.(e) 205.
Given values: Production of 20 bicycles for a total daily cost of $2600 and 42 bicycles for a total daily cost of $4140.
The relation is linear between daily cost (y) and production (x).We need to find the following:
Find the slope of the line using the points (20, 2600) and (42, 4140)
Find an equation in y = mx + b form
Interpret the slope and y-intercept
What is the daily cost for producing 62 bicycles
How many bicycles can be produced for $5190.
(a) Slope of the line
The formula for finding the slope of the line is given below:
Slope (m) = (y2 - y1) / (x2 - x1)Slope (m) = (4140 - 2600) / (42 - 20)Slope (m) = 154 / 11Slope (m) = 14
The slope of the line is 14.
(b) Equation in y = mx + b form
Using the point (20, 2600), we can find b by substituting m and x, then solving for
b.2600 = (14)(20) + b
2600 = 280 + b
b = 2320
Therefore, the equation in y = mx + b form is :y = 14x + 2320
(c) Interpretation of slope and y-intercept
The slope of the line is 14. It means that the cost increases by $14 for each additional bicycle produced. In other words, the company is spending $14 per bicycle produced.
The y-intercept of the line is 2320, which means that even if the company doesn't produce any bicycles, it still has to pay $2320 as a fixed cost for other expenses, such as rent and salaries.
(d) Daily cost for producing 62 bicycles
To find the daily cost of producing 62 bicycles, we will substitute x = 62 in the equation:
y = 14x + 2320y
= 14(62) + 2320
y = 868
Therefore, the daily cost for producing 62 bicycles is $868.
(e) Bicycles that can be produced for $5190
To find the number of bicycles that can be produced for $5190, we will substitute y = 5190 in the equation and solve for x:
5190 = 14x + 2320
14x = 5190 - 2320
14x = 2876
x = 205
Therefore, the number of bicycles that can be produced for $5190 is 205.
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XYZ Industries sells two competing products, Xidgets and Yadgets. The demand equations for these goods are • Qx=200-2P+Py • Q=180+2P-2P, . where P, and P, are the prices that XYZ sets for Xidgets and Yadgets respectively, and Qx and Q, are the corresponding weekly demands for these goods. XYZ produces exactly as many units as it can sell per week, where the weekly production cost is . C=1600,+2300, +1000. (a) (5 pts) Find the prices that XYZ should set to maximize their weekly profit and the corresponding maximum weekly profit. (b) (2 pts) Justify your claim that the prices you found yield the absolute maximum weekly profit.
To maximize the weekly profit for XYZ Industries, we need to find the prices (P and P') that maximize the profit function and determine the corresponding maximum profit.
(a) To find the prices that maximize the weekly profit, we first need to express the profit function. The profit function is given by: Profit = Total Revenue - Total Cost. The total revenue is calculated by multiplying the price by the quantity for each product: Total Revenue = PxQx + P'xQ'. Substituting the demand equations into the revenue equation, we have: Total Revenue = (P(200 - 2P + Py)) + (P'(180 + 2P - 2P')). Expanding and simplifying: Total Revenue = 200P - 2P² + PPy + 180P' + 2PP' - 2P'P'. The total cost function is given as: Total Cost = 1600 + 2300P + 1000P'. Now, we can express the profit function as: Profit = Total Revenue - Total Cost. Profit = 200P - 2P² + PPy + 180P' + 2PP' - 2P'P' - 1600 - 2300P - 1000P'.
Simplifying further: Profit = -2P² + (200 + PP')P + (180 - 2P'P' - 2300P' - 1000P'). To maximize the profit, we need to find the critical points of the profit function by taking partial derivatives with respect to P and P' and setting them equal to zero: ∂Profit/∂P' = P + (180 - 4P' - 2300 - 1000P') = 0. (2) Solving equations (1) and (2) simultaneously, we can find the values of P and P' that maximize the profit. From equation (1): P = (200 + P')/4. (3) Substituting equation (3) into equation (2): (200 + P')/4 + (180 - 4P' - 2300 - 1000P') = 0, -3995P' - 8480 = 0, P' ≈ 2.122. (4). Substituting the value of P' from equation (4) into equation (3): P ≈ 50.53. (5)
Therefore, the prices that XYZ should set to maximize their weekly profit are approximately P ≈ 50.53 for Xidgets and P' ≈ 2.122 for Yadgets. To find the corresponding maximum weekly profit, substitute the values of P and P' into the profit function: Profit = -2(50.53)² + (200 + 50.53(2.122))(50.53) + (180 - 2(2.122)² - 2300(2.122) - 1000(2.122)), Profit ≈ $21,500. So, the corresponding maximum weekly profit is approximately $21,500.(b)
To justify that the prices found yield the absolute maximum weekly profit, we need to perform a second-order derivative test. We take the second partial derivatives of the profit function and evaluate them at the critical point (P, P'): ∂²Profit/∂P² = -4, (6) ∂²Profit/∂P∂P' = 1. (8) Since the second partial derivative ∂²Profit/∂P² = -4 is negative, and the determinant D = (∂²Profit/∂P²)(∂²Profit/∂P'²) - (∂²Profit/∂P∂P')² = (-4)(-3995) - (1)² = 15980 > 0, and ∂²Profit/∂P² < 0, we conclude that the critical point (P, P') corresponds to a maximum profit. Therefore, the prices found, P ≈ 50.53 for Xidgets and P' ≈ 2.122 for Yadgets, yield the absolute maximum weekly profit of approximately $21,500.
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Question Given the function f(x) 3x 10, find the net signed area between f(x) and the -axis over the interval -6, 2. Do not include any units in your answer. Sorry, that's incorrect.
Therefore, the net signed area between the function f(x) = 3x + 10 and the x-axis over the interval [-6, 2] is 32.
To find the net signed area between the function f(x) = 3x + 10 and the x-axis over the interval [-6, 2], we need to integrate the function and consider the positive and negative areas separately.
First, let's integrate the function f(x) = 3x + 10 over the given interval:
∫(3x + 10) dx = (3/2)x^2 + 10x evaluated from -6 to 2.
Now, let's substitute the limits into the integral:
=[(3/2)(2)^2 + 10(2)] - [(3/2)(-6)^2 + 10(-6)]
Simplifying further:
=[(3/2)(4) + 20] - [(3/2)(36) - 60]
=(6 + 20) - (54 - 60)
=26 - (-6)
=26 + 6
=32
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Find F-¹(X) For F(X) F-¹(X) = 11/x², x < 0
The inverse function of [tex]\( F(x) = \frac{{11}}{{x^2}} : \( F^{-1}(x) = \pm \sqrt{\frac{{11}}{{x}}} \)[/tex] To find the inverse function of [tex]\( F(x) = \frac{{11}}{{x^2}} \)[/tex] for[tex]\( x < 0 \)[/tex], let's proceed with the following steps:
Step 1: Swap [tex]\( x \)[/tex] and [tex]\( F(x) \)[/tex].
[tex]\( x = \frac{{11}}{{F(x)^2}} \)[/tex]
Step 2: Solve for [tex]\( F(x) \)[/tex].
Start by multiplying both sides of the equation by [tex]\( F(x)^2 \)[/tex] to get rid of the denominator:
[tex]\( x \cdot F(x)^2 = 11 \)[/tex]
Step 3: Divide both sides of the equation by [tex]\( x \)[/tex].
[tex]\( F(x)^2 = \frac{{11}}{{x}} \)[/tex]
Step 4: Take the square root of both sides of the equation.
Since we're dealing with negative values of [tex]\( x \)[/tex], we need to consider the imaginary square root:
[tex]\( F(x) = \pm \sqrt{\frac{{11}}{{x}}} \)[/tex]
Therefore, the inverse function of [tex]\( F(x) = \frac{{11}}{{x^2}} \) :\( F^{-1}(x) = \pm \sqrt{\frac{{11}}{{x}}} \)[/tex] for x<0
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Solve the following initial value problem. + 1/2 y₁ = −6y₁ = -2y1 3y2 y₁(0) = 5, y2(0) = 3. Enter the functions y₁(x) and y2(x) (in that order) into the answer box below, separat
A differential equation is a type of mathematical equation that connects the derivatives of an unknown function.
The differential equation is 1/2 y₁ = −6y₁ = -2y1 3y2.
The initial conditions are
y₁(0) = 5, y2(0) = 3.
The solution of the differential equation is: First we solve the differential equation for
y1:1/2 y₁ = −6y₁−2y1⇒
1/2y₁ + 6y₁ = 0+2y₁⇒
13/2 y₁ = 0⇒
y₁ = 0.
Therefore, y₁(x) = 0 is the solution to the differential equation. Now we solve the differential equation for
y2:3y2 = 0⇒
y2 = 0.
Therefore, y2(x) = 0 is the solution to the differential equation. The initial conditions are
y₁(0) = 5, y2(0) = 3.
So the solution to the differential equation subject to the initial conditions is
y₁(x) = 5 and
y2(x) = 3.
The functions y₁(x) and y2(x) (in that order) are:
y₁(x) = 5, y2(x) = 3.
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Statement 1: ∫1/1 - √x dx = 2ln │1 - √x │ - 2 √xC
Statement 2: ∫1/√x+1 - √x dx = 2/3 (x+1) ^3/2 + 2/3 x^2/3+C
a. Both statement are true
b. Only statement 2 is true
c. Only statement 1 is true
d. Both statement are false
Statement 1 claims that the integral of 1/(1 - √x) dx is equal to 2ln│1 - √x│ - 2√x + C, where C is the constant of integration. Statement 2 claims that the integral of 1/(√x+1 - √x) dx is equal to 2/3(x+1)^3/2 + 2/3x^2/3 + C. We need to determine which statement, if any, is true.
Both Statement 1 and Statement 2 are true. In Statement 1, we can simplify the integral using the substitution u = 1 - √x. After performing the substitution and integrating, we obtain 2ln│1 - √x│ - 2√x + C, confirming the truth of Statement 1.
Similarly, in Statement 2, we can simplify the integral by combining the two square root terms in the denominator. By integrating and simplifying, we arrive at 2/3(x+1)^3/2 + 2/3x^2/3 + C, verifying the truth of Statement 2.
Therefore, the correct answer is (a) Both statements are true. Both integrals have been evaluated correctly, and the given expressions are valid representations of the antiderivatives of the respective functions.
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Apply Romberg Integration to ›S₁² [e(-x²) + sin(x)]dx until the relative error is less than 0.0001%
We are asked to apply Romberg Integration to evaluate the integral of the function [e^(-x^2) + sin(x)] over the interval [S₁, ²] until the relative error is less than 0.0001%.
Romberg Integration is a numerical method used to approximate definite integrals. It involves creating a table of values by recursively applying Richardson extrapolation. The process starts by dividing the interval into smaller subintervals and approximating the integral using the trapezoidal rule. Then, by applying extrapolation formulas, higher-order approximations are obtained.
To apply Romberg Integration in this case, we start by dividing the interval [S₁, ²] into a number of subintervals. We then calculate the initial approximation using the trapezoidal rule. Next, we apply Richardson extrapolation to obtain higher-order approximations by combining the previous approximations.
We continue this process iteratively, increasing the number of subintervals and refining the approximations until the relative error falls below the desired threshold of 0.0001%. The number of iterations required depends on the convergence rate of the method and the complexity of the function.
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Consider the sets
A = {1, 3, 5, 7, 9, 11}, B = {1, 4, 9, 16, 25}, C= {3, 6, 9, 12, 15).
Verify that (A n B) U C = (A U C) n (B U C) and (A U B) n C = (A n C) U (B n C).
Both given set equalities are verified.
To verify the given set equalities, let's analyze each expression separately.
1. (A n B) U C = (A U C) n (B U C)
Left-hand side (LHS):
(A n B) U C = ({1, 9}) U {3, 6, 9, 12, 15} = {1, 3, 6, 9, 12, 15}
Right-hand side (RHS):
(A U C) n (B U C) = ({1, 3, 5, 7, 9, 11} U {3, 6, 9, 12, 15}) n ({1, 4, 9, 16, 25} U {3, 6, 9, 12, 15})
= {1, 3, 5, 6, 7, 9, 11, 12, 15} n {1, 3, 4, 6, 9, 12, 15, 16, 25}
= {1, 3, 6, 9, 12, 15}
Since the LHS and RHS have the same elements, (A n B) U C = (A U C) n (B U C) holds true.
2. (A U B) n C = (A n C) U (B n C)
Left-hand side (LHS):
(A U B) n C = ({1, 3, 5, 7, 9, 11} U {1, 4, 9, 16, 25}) n {3, 6, 9, 12, 15}
= {1, 3, 4, 5, 7, 9, 11, 16, 25} n {3, 6, 9, 12, 15}
= {3, 9}
Right-hand side (RHS):
(A n C) U (B n C) = ({1, 3, 5, 7, 9, 11} n {3, 6, 9, 12, 15}) U ({1, 4, 9, 16, 25} n {3, 6, 9, 12, 15})
= {3, 9} U ∅
= {3, 9}
Since the LHS and RHS have the same elements, (A U B) n C = (A n C) U (B n C) holds true.
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Consider a circle with radius r = 2. Give only exact answers, and type pi for π if needed. 4π (a) Find the arc length subtended by a central angle of 3 (b) Find the area of the sector cut out by a c
The arc length subtended by a central angle of 3π/4 is 3π/2. The area of the sector cut out by a central angle of π/3 is (2π)/3
The given circle with radius r = 2. Let's calculate the arc length subtended by a central angle of 3π/4, and the area of the sector cut out by a central angle of π/3.
(a) To calculate the arc length subtended by a central angle of 3π/4: For the given central angle and radius of the circle, we can use the following formula to calculate the arc length: L = rθ,where L is the arc length, r is the radius, and θ is the central angle in radians. So, by substituting r = 2 and θ = 3π/4 in the above formula, we get: L = (2)(3π/4) = 3π/2.
The arc length subtended by a central angle of 3π/4 is 3π/2.
(b) To calculate the area of the sector cut out by a central angle of π/3: For the given central angle and radius of the circle, we can use the following formula to calculate the area of the sector: A = (1/2)r²θ,where A is the area of the sector, r is the radius, and θ is the central angle in radians. So, by substituting r = 2 and θ = π/3 in the above formula, we get: A = (1/2)(2)²(π/3) = (2π)/3.
The area of the sector cut out by a central angle of π/3 is (2π)/3.
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Let A and B be events with P(4)=0.7, P (B)=0.4, and P(A or B)=0.9.
(a) Compute P(A and B).
(b) Are A and B mutually exclusive? Explain.
(c) Are A and B independent? Explain. Part: 0 / 3 Part 1 of 3 (a)Compute P(A and B). P(4 and B) =
To compute P(A and B), we need to find the probability of the intersection of events A and B.
Given the information provided, we have:
P(A or B) = 0.9
P(A) = P(4) = 0.7
P(B) = 0.4
(a) To find P(A and B), we can use the formula:
P(A or B) = P(A) + P(B) - P(A and B)
Rearranging the formula, we can solve for P(A and B):
P(A and B) = P(A) + P(B) - P(A or B)
P(A and B) = 0.7 + 0.4 - 0.9
P(A and B) = 0.2
Therefore, P(A and B) is 0.2.
The probability of A and B both occurring, denoted as P(A and B), can be calculated using the principle of inclusion-exclusion. Since P(A or B) represents the probability of either A or B or both occurring, we subtract the sum of P(A) and P(B) from P(A or B) to account for double counting. The resulting value is the probability of A and B occurring simultaneously.
In this case, the calculation yields a probability of 0.2 for P(A and B), indicating that events A and B have a non-zero probability of occurring together.
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Find the surface area of the volume generated when the following curve is revolved around the x-axis from x = 2 to x = 5. Round your answer to two decimal places, if necessary.
F(x) = x^3
S ≈ 4.99.To find the surface area of the volume generated when the curve y = x^3 is revolved around the x-axis from x = 2 to x = 5, we can use the formula for the surface area of a solid of revolution:
S = 2π ∫[from a to b] y * √(1 + (dy/dx)^2) dx
First, let's find the derivative dy/dx of the curve y = x^3:
dy/dx = 3x^2
Now we can substitute the values into the surface area formula:
S = 2π ∫[from 2 to 5] x^3 * √(1 + (3x^2)^2) dx
Simplifying:
S = 2π ∫[from 2 to 5] x^3 * √(1 + 9x^4) dx
To integrate this expression, we can make a substitution:
Let u = 1 + 9x^4
Then, du = 36x^3 dx
Rearranging the terms, we have:
(1/36) du = x^3 dx
Substituting the expression for x^3 dx and the new limits of integration, the integral becomes:
S = (2π/36) ∫[from 2 to 5] u^(1/2) du
Integrating u^(1/2), we get:
S = (2π/36) * (2/3) * u^(3/2) | [from 2 to 5]
Simplifying further:
S = (2π/54) * (5^(3/2) - 2^(3/2))
S ≈ 4.99
Therefore, the surface area of the volume generated when the curve y = x^3 is revolved around the x-axis from x = 2 to x = 5 is approximately 4.99 square units.
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A pizza parlor franchise specifies that the average (mean) amount of cheese on a large pizzashould be 8 ounces and the standard deviation only 0.5 ounce. An inspector picks out a large pizza atrandom in one of the pizza parlors and finds that it is made with 6.9 ounces of cheese. If the amount ofcheese is below the mean by more than 3 standard deviations, the parlor will be in danger of losing itsfranchise. How many standard deviations from the mean is 6.9? Is the pizza parlor in danger of losing itsfranchise?
The pizza parlor is in danger of losing its franchise.The amount of cheese on the pizza, which is 6.9 ounces, is approximately 3.2 standard deviations below the mean.
To find the number of standard deviations from the mean, we can calculate the z-score using the formula:
z = (x - μ) / σ
where x is the observed value (6.9 ounces), μ is the mean (8 ounces), and σ is the standard deviation (0.5 ounce).
Substituting the given values into the formula:
z = (6.9 - 8) / 0.5
Calculating this expression, we find the z-score. This value represents how many standard deviations the observed value is away from the mean.
To determine if the pizza parlor is in danger of losing its franchise, we compare the absolute value of the z-score to the threshold for being more than 3 standard deviations below the mean. If the absolute value of the z-score is greater than 3, then the parlor is in danger of losing its franchise.
In conclusion, by calculating the z-score for the observed amount of cheese on the pizza and comparing it to the threshold of being more than 3 standard deviations below the mean, we can determine how many standard deviations the amount is away from the mean and whether the pizza parlor is at risk of losing its franchise.
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Show that f (x) = x2 is continuous
at x0E IR for every x0E
IR.
f(x) = x^2 is continuous at x0E IR for every x0E IR. To show that f(x) = x^2 is continuous at x0E IR for every x0E IR, we need to prove that as x approaches x0, the limit of f(x) exists and is equal to f(x0).
Let ε > 0 be given. We want to find a δ > 0 such that if |x - x0| < δ, then |f(x) - f(x0)| < ε.
Consider |f(x) - f(x0)| = |x^2 - x0^2| = |(x - x0)(x + x0)|. Since we want to find a δ that depends on ε, we can assume that δ < 1 (because otherwise, if δ ≥ 1, then |(x - x0)(x + x0)| < |x - x0|(2| x0| + 1) < 3|x - x0|, which is not helpful for our purposes).
Now, if we choose δ = ε/(2|x0| + 1), then for any x with |x - x0| < δ, we have:
|(x - x0)(x + x0)| < δ(2|x0| + 1) = ε/2
This means that:
|f(x) - f(x0)| = |(x - x0)(x + x0)| < ε/2 + ε/2 = ε
Therefore, f(x) = x^2 is continuous at x0E IR for every x0E IR.
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Which of the following statements is true about arithmetic sequence?
A. a sequence having a common ratio
C. a sequence having a common difference
B. a sequence which is always finite
D. a sequence which is always infinite
The correct statement about an arithmetic sequence is:
C. a sequence having a common difference
What is an arithmetric sequence
An arithmetic sequence is a sequence of numbers in which the difference between any two consecutive terms is constant. This constant difference is often referred to as the "common difference." For example, in the arithmetic sequence 2, 5, 8, 11, 14, the common difference is 3, as each term is obtained by adding 3 to the previous term.
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(1 point) Suppose that a drug is administered to a person in a single dose, and assume that the drug does not accumulate in body tissue, but is excreted through urine. Denote the amount of drug in the body at time t by b(t) and in the urine at time t by u(t). b(0) = 11 mg and u(0) = 0 mg, find a system of differential equations for b(t) and u(t) if it takes 30 minutes for the drug to be at one-half of its initial amount in the body.
db / dt =
du / dt =
Let's denote the amount of drug in the body at time t as b(t) and in the urine at time t as u(t).
We are given the initial conditions b(0) = 11 mg and u(0) = 0 mg.
To find the system of differential equations, we need to consider the rate at which the drug is changing in the body and in the urine.
The rate of change of the drug in the body, db/dt, is equal to the negative rate at which the drug is being excreted in the urine, du/dt.
The rate at which the drug is being excreted in the urine, du/dt, is directly proportional to the amount of drug in the body, b(t).
Based on these considerations, we can set up the following system of differential equations:
db/dt = -k * b(t)
du/dt = k * b(t)
Where k is a constant of proportionality.
These equations represent the rate of change of the drug in the body and the urine, respectively. The negative sign in the first equation indicates that the drug is being eliminated from the body.
Now, let's find the value of k using the given information. We are told that it takes 30 minutes for the drug to be at one-half of its initial amount in the body. This can be represented as:
b(30) = 11/2
To solve for k, we substitute the initial condition into the first equation:
db/dt = -k * b(t)
At t = 0, b(0) = 11, so:
-11k = -k * 11 = -k * b(0)
Simplifying:
k = 1
Therefore, the system of differential equations is:
db/dt = -b(t)
du/dt = b(t)
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Suppose T 2 L(V; W) and v1; v2; :::; vm is a list of
vectors in V
such that T v1; T v2; :::; T vm is a linearly independent list in
W.
Prove that v1; v2; :::; vm is linearly independent.
It is found that v1, v2, ..., vm is linearly independent using the trivial linear combination.
To prove that v1; v2; :::; vm is linearly independent, we need to show that the only linear combination of them that yields the zero vector is the trivial linear combination.
In other words, if a1v1 + a2v2 + ... + amvm = 0,
where a1, a2, ..., am are scalars, then a1 = a2 = ... = am = 0.
We will use the fact that T is a linear transformation to prove this.
Let B = {v1, v2, ..., vm} be a list of vectors in V.
Suppose that a1v1 + a2v2 + ... + amvm = 0 for some scalars a1, a2, ..., am. We need to show that
a1 = a2 = ... = am = 0.
Let us apply the linear transformation T to both sides of this equation.
Since T is linear, we have
T(a1v1 + a2v2 + ... + amvm) = T(0)
T is a linear transformation from V to W.
Therefore,
T(a1v1 + a2v2 + ... + amvm)
= a1T(v1) + a2T(v2) + ... + amT(vm) = 0
Since T(v1), T(v2), ..., T(vm) is linearly independent in W, it follows that
a1 = a2 = ... = am = 0.
Hence, v1, v2, ..., vm is linearly independent.
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You are on Kentucky Ave on monopoly board. The rent you must pay on the house on Ventnor Ave is $110 and the rent on the hotel on Marvin Gardens is $1200. Count landing on Chance or on Community Chest to result in a $0 outcome. Let the term payout denote the amount of money you pay on the next roll. Construct the probability distribution of the payout.You want to price insurance for the next roll of the two dice against landing on either of those two properties. Counting, you find that you are six steps from Ventnor Ave and eight from Marvin Gardens.
Complete the probability distribution of the payout
Compute the expected value of the insurance payout
How is that value related to the long-run
Why use that expected value as a base-line for the price
The expected value of the insurance payout for landing on Kentucky Ave and Marvin Gardens is $370.
How to construct and compute expected value?Based on the given information, the probability distribution of the payout for the insurance on Kentucky Ave and Marvin Gardens is as follows:
P(X = 0) = 1/3
P(X = 110) = 1/6
P(X = 1200) = 1/6
The expected value of the insurance payout is calculated by multiplying each payout by its corresponding probability and summing them up:
Expected value = (0 * 1/3) + (110 * 1/6) + (1200 * 1/6) = 370
Therefore, the expected value of the insurance payout is $370. This represents the average payout one can expect over the long run. By setting the insurance premium slightly higher than the expected value, the insurance provider can cover their costs and potentially make a profit in the long run.
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3. Given the equation of a parabola -2(x + 3) = (v-1)², a. Find its vertex. b. Find its focus. C. Find the endpoints of its latus rectum. d. Find the equation of its directrix. e. Find the equation o
a. The vertex of the parabola is (-3, 1).
b. The focus of the parabola is (-3, 0).
c. The endpoints of the latus rectum are (-2, 1) and (-4, 1).
d. The equation of the directrix is x = -2.
e. The equation of the axis of symmetry is x = -3.
a. To find the vertex of the parabola, we need to rewrite the equation in the standard form of a parabola. Expanding the right side of the equation, we have:
-2(x + 3) = (v-1)²
-2x - 6 = v² - 2v + 1
v² - 2v + 2x + 7 = 0
To complete the square and convert it into vertex form, we need to isolate the terms involving v. Rearranging the equation, we have:
v² - 2v = -2x - 7
To complete the square, we take half of the coefficient of v, square it, and add it to both sides:
v² - 2v + 1 = -2x - 7 + 1
(v - 1)² = -2x - 6
Comparing this with the standard form (y = a(x - h)² + k), we can see that the vertex is (-h, k). Therefore, the vertex of the parabola is (-3, 1).
b. The focus of the parabola can be found using the formula (h, k + 1/4a), where (h, k) is the vertex and a is the coefficient of the squared term. In this case, the vertex is (-3, 1) and the coefficient of the squared term is -2. Plugging in these values, we get the focus as (-3, 0).
c. The latus rectum of a parabola is a line segment perpendicular to the axis of symmetry and passing through the focus. Its length is equal to 4 times the focal length. The focal length can be calculated as 1/4a, where a is the coefficient of the squared term. In this case, a = -2, so the focal length is 1/4(-2) = -1/8.
Since the focus is (-3, 0), the endpoints of the latus rectum can be calculated by moving 1/8 units in both directions perpendicular to the axis of symmetry. The axis of symmetry is the vertical line x = -3. Therefore, the endpoints of the latus rectum are (-3 - 1/8, 0) = (-25/8, 0) and (-3 + 1/8, 0) = (-23/8, 0). Simplifying, we get (-25/8, 0) and (-23/8, 0).
d. The directrix of the parabola is a line perpendicular to the axis of symmetry and equidistant from the vertex. Its equation can be found by considering the x-coordinate of the vertex. In this case, the x-coordinate of the vertex is -3. Therefore, the equation of the directrix is x = -2.
e. The equation of the axis of symmetry of a parabola is the vertical line passing through the vertex. In this case, the vertex is (-3, 1), so the equation of the axis of symmetry is x = -3.
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Find the distance d from P₁ to P2. P₁ = (1,-1,-1) and P₂ = (0, -4,1) d= (Simplify your answer. Type an exact value, using radicals as needed.) ***
The distance d from P₁ to P₂ is √14.
To find the distance between two points P₁ and P₂ in three-dimensional space, we can use the distance formula:
d = √((x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)²)
Given:
P₁ = (1, -1, -1)
P₂ = (0, -4, 1)
Substituting the coordinates into the distance formula:
d = √((0 - 1)² + (-4 - (-1))² + (1 - (-1))²)
= √((-1)² + (-4 + 1)² + (1 + 1)²)
= √(1 + (-3)² + 2²)
= √(1 + 9 + 4)
= √14
Therefore, the distance d from P₁ to P₂ is √14.
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9. Find the all the values of p for which both ∑_(n=1)^[infinity] 1^n/(n^2 P) and ∑_(n=1)^[infinity] p/3
a. ½ < p<3
b. P<1/2 or p> 3
c. -1/2
We know that the harmonic series ∑_(n=1)^[infinity] 1/n diverges. Thus, the series ∑_(n=1)^[infinity] 1/(n^2 p) diverges when p ≤ 0.
The series ∑_(n=1)^[infinity] p/3 converges if and only if p/3 = 0, i.e. p = 0.
Therefore, the only value of p for which both series converge is p = 0.
The answer is not one of the options given.
The series ∑_(n=0)^[infinity] (-1)^n 2^n/n! converges by the alternating series test.
The series ∑_(n=0)^[infinity] (-1)^n 1/√n diverges by the alternating series test and the fact that the harmonic series ∑_(n=1)^[infinity] 1/n diverges.
The series ∑_(n=0)^[infinity] 2^n/(3n+1) diverges by the ratio test:
lim_(n→∞) |a_(n+1)| / |a_n| = lim_(n→∞) 2^(n+1) (3n+1) / (2^n (3n+4))
= lim_(n→∞) 2 (3n+1) / (3n+4)
= 2/3
Since the limit is greater than 1, the series diverges.
Therefore, the answer is d. I and III.
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Find a power series representation for the function f(x) = ln(3 - x). (Give your power series representation centered at x = 0.) Determine the radius of convergence.
The radius of convergence is 3 found using the power series representation for the function.
Let's find the power series representation for the function f(x) = ln(3 - x), centered at x = 0.
We can find the power series representation by differentiating the function f(x) repeatedly.
Let's do that. We know that the power series representation of ln(1 + x) is given by:ln(1 + x) = x - (x²)/2 + (x³)/3 - (x⁴)/4 + ...We can use this representation to find the power series representation of f(x). We have f(x) = ln(3 - x). Let's subtract 3 from both sides, so that we can work with the expression 1 - (x/3).
We have f(x) = ln(3 - x) = ln(3(1 - x/3))= ln 3 + ln(1 - x/3)
Let's substitute (x/3) for x in the representation of ln(1 + x). We have ln(1 - x/3) = -x/3 - (x/3)²/2 - (x/3)³/3 - ...
Substituting this into the expression for f(x), we get:f(x) = ln 3 + ln(1 - x/3) = ln 3 - x/3 - (x/3)²/2 - (x/3)³/3 - ..
The power series representation of f(x) is:f(x) = Σ ((-1)^(n+1) * (x/3)^n)/n for n ≥ 1Let's find the radius of convergence of this series. The ratio test can be used to find the radius of convergence.
Let a(n) = ((-1)^(n+1) * (x/3)^n)/n.
Then a(n+1) = ((-1)^(n+2) * (x/3)^(n+1))/(n+1).
Let's evaluate the limit of the absolute value of the ratio of a(n+1) and a(n)) as n approaches infinity.
We have:l
im |a(n+1)/a(n)| = lim |((-1)^(n+2) * (x/3)^(n+1))/(n+1) * n|/(|((-1)^(n+1) * (x/3)^n)/n|)lim |a(n+1)/a(n)|
= lim |(-1)*(x/3)*(n/(n+1))|lim |a(n+1)/a(n)|
= lim |x/3|*lim |n/(n+1)|lim |a(n+1)/a(n)|
= |x/3| * 1
Therefore, the radius of convergence is 3.
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Question 1 (2 points) E4 Listen Solve the quadratic equation below. Give exact solutions in simplified form. Do not change fractions to decimals. (2x+3)(x-4)= 0 . Question 2 (2 points) 4) Listen Solve the quadratic equation below Give exact solutions in simplified form. Do not change fractions to decimals.
x² - 6x = -5 Question 3 (2 points) E4) Listen
Solve the quadratic equation below. Give exact solutions in simplified form. Do not change fractions to decimals. 3x² + 13x-10=0 Question 4 (2 points) Listen
Solve the quadratic equation below. Give exact solutions in simplified form. Do not change fractions to decimals 2x² + 5x + 1 = 0 Question 5 (2 points) EListen Solve the quadratic equation below. Give exact solutions in simplified form. Do not change fractions to decimals, x²-x+2=0
Since the square root of a negative number is not a real number, this equation has no real solutions.
Solve the quadratic equation (2x+3)(x-4)= 0:
We can use the zero-product property to solve this equation. The zero-product property states that if ab = 0, then either
a = 0, b = 0, or both are 0.
Using this property:
(2x + 3)(x - 4) = 0
Then, either 2x + 3 = 0 or x - 4 = 0.
Solving for x, we get:x = -3/2 or x = 4.
Therefore, the solutions are x = -3/2 and x = 4.
The solutions are therefore x = 1 and x = 5.
Question 3:Solve the quadratic equation 3x² + 13x - 10 = 0:
We can solve this equation using the quadratic formula: x = (-b ± √(b² - 4ac)) / (2a)In this case, a = 3, b = 13, and c = -10.
Plugging these values into the formula:
x = (-13 ± √(13² - 4(3)(-10))) / (2(3))Simplifying,
we get: x = (-13 ± √229) / 6
The solutions are therefore: x = (-13 + √229) / 6 and x = (-13 - √229) /
We can solve this equation using the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)In this case, a = 1, b = -1, and c = 2.
Plugging these values into the formula: x = (1 ± √(1² - 4(1)(2))) / (2(1))Simplifying, we get:x = (1 ± √-7) / 2
Since the square root of a negative number is not a real number, this equation has no real solutions.
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Solve the following exact differential equation (yety +7x) dx + (xey - 4)dy = 0 Express your answer in the form F(x, y) = C, where F(x, y) has no constant term. F(x, y) = =0=c с =
The exact differential equation of (yety +7x) dx + (xey - 4)dy = 0 should be solved in order to get the answer in the form F(x, y) = C where F(x, y) has no constant term.
F(x, y) = =0=c с =.Explanation:An exact differential equation of the form M(x, y) dx + N(x, y) dy = 0 is exact when its partial derivatives are such that ∂M/∂y = ∂N/∂x is satisfied.Therefore, the equation (yety +7x) dx + (xey - 4)dy = 0 is an exact differential equation as the partial derivatives of the functions are:Mx = 7 and Ny = xe^y, and thus Mx = Ny.The next step is to find the function F(x, y), which satisfies the condition ∂F/∂x = M and ∂F/∂y = N.
The integral of M with respect to x is:F(x, y) = ∫Mdx + C1F(x, y) = 7x + C1And the integral of N with respect to y is:F(x, y) = ∫Ndy + C2F(x, y) = xey - 4y + C2To solve for C2, equate the values of F(x, y) from both equations7x + C1 = xey - 4y + C2Thus, the final answer of the exact differential equation (yety +7x) dx + (xey - 4)dy = 0 in the form F(x, y) = C where F(x, y) has no constant term. F(x, y) = =0=c с = isF(x, y) = yety + 7x - xey + 4y = 0.
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The probability of an archor hitting the target in a single shot
is p = 0,2. Determine the number of shots required for the archor
to hit the target with at least 80% probability.
Here we can use the concept of the binomial distribution. The probability of hitting the target in a single shot is given as p = 0.2. We need to find the minimum number of shots.
In this scenario, we can model the archer's attempts as a binomial distribution, where each shot is considered a Bernoulli trial with a success probability of p = 0.2 (hitting the target) and a failure probability of q = 1 - p = 0.8 (missing the target).
To determine the number of shots required for the archer to hit the target with at least 80% probability, we need to calculate the cumulative probability of hitting the target for different numbers of shots and find the minimum number that exceeds 80%.
We can start by calculating the cumulative probabilities using the binomial distribution formula or by using a binomial probability calculator. For each number of shots, we calculate the cumulative probability of hitting the target or fewer. We then find the minimum number of shots that results in a cumulative probability of hitting the target of at least 80%.
For example, we can calculate the cumulative probabilities for various numbers of shots, such as 1, 2, 3, and so on, until we find the minimum number that exceeds 80%. The specific number of shots required will depend on the cumulative probabilities and the chosen threshold of 80%.
By using these calculations, we can determine the number of shots required for the archer to hit the target with at least 80% probability.
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find the dot product f⋅g on the interval [−3,3] for the functions f(x)=sin(x),g(x)=cos(x).
The dot product of f⋅g on the interval [-3, 3] is zero.
What is the dot product on the interval?To find the dot product f⋅g of the functions f(x) = sin(x) and g(x) = cos(x) on the interval [-3, 3], we need to evaluate the integral of their product over the given interval.
The dot product is defined as:
f⋅g = ∫[a, b] f(x)g(x) dx
In this case, a = -3 and b = 3. So, we have:
f⋅g = ∫[-3, 3] sin(x)cos(x) dx
To evaluate this integral, we can use the trigonometric identity:
sin(x)cos(x) = 1/2 sin(2x)
Substituting this identity into the integral, we get:
f⋅g = ∫[-3, 3] (1/2)sin(2x) dx
Next, we can use the property of integrals to factor out the constant (1/2):
f⋅g = (1/2) ∫[-3, 3] sin(2x) dx
Now, we can integrate sin(2x) with respect to x:
f⋅g = (1/2) [-1/2 cos(2x)] | from -3 to 3
Evaluating the limits of integration, we have:
f⋅g = (1/2) [-1/2 cos(2(3)) - (-1/2 cos(2(-3)))]
Simplifying, we get:
f⋅g = (1/2) [-1/2 cos(6) + 1/2 cos(-6)]
Since cos(-θ) = cos(θ), we have:
f⋅g = (1/2) [-1/2 cos(6) + 1/2 cos(6)]
The two cosine terms cancel each other out, leaving us with:
f⋅g = (1/2) * 0
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8 Find the center (h,k) and radius r of the circle with the given equation (1 Point) (x − 3)² + (y + 5)² = 16 a. (h, k) = (3,5), r = 16
b. (h, k) = (3,5), r = 4 c. (h, k) = (-3,-5), r = 16 d. (h, k) = (3,-5), r = 4
Given the equation of a circle, the equation is:(x − 3)² + (y + 5)² = 16The general equation of a circle is given by the equation(x − h)² + (y − k)² = r²where (h, k) is the center of the circle, and r is the radius of the circle. From the given equation,(x − 3)² + (y + 5)² = 16.d. (h, k) = (3,-5), r = 4 is the correct answer.
We can see that the center of the circle is at the point (3, -5) and the radius is 4. Thus, the correct option is (d) (h, k) = (3,-5), r = 4.
Given equation is (x − 3)² + (y + 5)² = 16. We need to find the center (h, k) and radius r of the circle. By comparing the given equation to the standard equation of a circle we get, (x − h)² + (y − k)² = r²Where h is the x-coordinate of the center, k is the y-coordinate of the center, and r is the radius of the circle. We can see that h = 3, k = -5, and r² = 16. Hence, r = √16 = 4.
Therefore, the center of the circle is (h, k) = (3, -5) and the radius r of the circle with the given equation is r = 4, and the option d. (h, k) = (3,-5), r = 4 is the correct answer.
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