If [tex]\vec A[/tex] and [tex]\vec B[/tex] are perpendicular, then their dot product is zero. This means
[tex]\vec A \cdot \vec B = (\vec\imath + 5\,\vec\jmath + n\,\vec k) \cdot (2\,\vec\imath - \vec\jmath + \vec k) = 2 - 5 + n = 0[/tex]
Solving for n is trivial; it follows that n = 3.
When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, you are obeying which law?
When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
Newton's law of universal gravitationNewton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.
The mathematical interpretation of the above law is
F ∝Mm/r²Removing the proportionality sign,
F = GMm/r².Where:
F = Force of attractionG = Gravitational constantM = Bigger massm = Smaller mass r = Distance between the masses.
From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.
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A ball is thrown vertically upward with an initial speed of 50 m/s. if air resistance does affect motion, then what would be its speed upon returning to its starting point?
Answer:
your answer would 50 m/s I do believe
The correct answer for the speed of the ball upon resting to it's starting point is [tex]50[/tex] m/s.
Given:
Initial speed: [tex]u = 50[/tex] m/s
To calculate the speed upon resting position, Calculate the time requires to reach starting position:
Time required to reach starting point = 2 * (Time require to reach the maximum height)
Time required to reach the maximum height:
[tex]v = u+(-a )t[/tex]
Final velocity([tex]v[/tex]) is [tex]0[/tex] m/s.
Negative sign indicates negative acceleration:
[tex]t= \dfrac{50}{9.8}\\\\ = 5.10[/tex]seconds
Time for start point = [tex]2 * 5.8[/tex]
[tex]=10.6[/tex] seconds
From equation of motion:
[tex]v= u+at[/tex]
[tex]= 50 -9.8* 10.2[/tex]
[tex]= -50.2[/tex] m/s
Negative sign indicates downward direction.
Speed when ball return is is [tex]50[/tex] m/s.
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Two identical blocks are attached to the same massless rope, which is strung around two massless, frictionless pulleys. A massless scale is connected to the same rope and measures the tension in the rope. The two identical blocks are released from the rest. The experiment is then repeated with two new blocks, with masses m1 and m2. When they are released from rest, the system remains at rest, and the scale measures the same tension as in the previous experiment. Find m1 and m2 in terms of m.
Answer:
The value of mass 1, m1= 6/5m
The value of mass 2, m2= 3/5m
Explanation:
case 1:
here tension and the acceleration will be:
for m1;
mg-T=ma2mg - 2T = 2ma .....1.for m2:
2T-mg = ma/2 ..... 2.adding the both equations,
2mg - 2T + 2T-mg = 2ma + ma/2
a = 2/5 g
putting the value of a into the equation 1.
mg - T = m* (2/5)g
T = 3/5 ( mg )
now
case 2:
The two identical blocks are released from the rest, the tension remains the same as the case 1.
so,
for m1:
2T-m2g=0for m2:
2m2g - 2T =0adding both equations we get,
2T-m2g + 2m2g - 2T = 0
m2 = m1 / 2
T = m1*g / 2
here we know that
T (case1) = T (case2)
3/5 ( mg ) = m1*g / 2
m1 = 6/5 m
hence
m2 = 3/5 m
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c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
DExplain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force between them the power of the gravitational pressure among gadgets relies upon on factors, mass and distance. the pressure of gravity the loads exert on every other.
How do the loads of items 1 and a couple of relate to the gravitational pressure among them?Gravitational pressure -an appealing pressure that exists among all items with mass; an item with mass draws every other item with mass; the value of the pressure is immediately proportional to the loads of the 2 items and inversely proportional to the rectangular of the gap among the 2 items.
Since the gravitational pressure is immediately proportional to the mass of each interacting items, greater large items will entice every different with a more gravitational pressure. So because the mass of both item increases, the pressure of gravitational appeal among them additionally increases.
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why aren't there lunar and solar eclipses every month?
The moon's orbital plane is different from that of the earth's orbit around the sun due to which lunar and solar eclipses do not occur every month.
What is a solar eclipse?When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.
Only during the new moon phase, when the moon travels squarely between the sun and Earth and casts shadows on its surface, can a solar eclipse occur.
Due to the moon's orbit being five degrees off-center from Earth's orbit around the Sun, lunar eclipses do not happen every month and the Moon often passes above or below the shadow.
Lunar eclipses would happen every month if there were no tilt. Eclipses of the sun and the moon happen equally often.
Hence lunar and solar eclipses aren't coming every month.
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The reason why lunar and solar eclipses do not occur every month is because; the plane of orbit of the moon around the earth is not same as that of earth around the sun.
Why don't lunar and solar eclipses occur every month?When the Moon passes between Earth and the Sun, there's solar eclipse while when the earth passes between the Sun and the Moon, casting a shadow on the Moon, there's lunar eclipse.
Hence, because the plane of orbit of the moon around the earth is not same as that of earth around the sun, we do not have lunar and solar eclipses every month.
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a transverse wave passes through a slinky
Last one!
Perpendicular to the wave's energy
Hope this helps!
The farther you bring charged objects
Answer:
Weaker, stronger
Explanation:
hope this helped!
Answer:
[tex]\fbox {weaker, stronger}[/tex]
Explanation:
The farther you bring charged objects from each other, the weaker the electrical force between them, and the bigger the charges on the objects, the stronger the electrical force between them.
Proving
Here we need the formula for Coulomb's Law, which is :
[tex]\boxed {F = \frac{1}{4\pi\epsilon_{0}}\times\frac{q_{1}q_{2}}{r^{2}}}[/tex]
As we can see, when the distance increases, the overall force will decrease as they are inversely proportional.
Similarly, as the product of charges is directly proportional to the electrical force produced, as the charges increase, the force increases.
The line joining all places of zero variation is called?
According to the research, the agonic line is the line joining all places of zero variation.
What is the agonic line?It is a term that refers to the zero declination isogon, that is, it joins the points that do not have magnetic declination.
This line crosses the magnetic and geographic poles of the Earth's surface from which they are aligned and along which there is no magnetic variation.
Therefore, we can conclude that according to the research, the agonic line is the line joining all places of zero variation.
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An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. what amount of force would be
required to keep the object in motion if you ignore the surface friction?
a 0 newtons
b 175 newtons
c 35 newtons
d 5 newtons
Taking into account the Newton's second law, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.
Newton's second lawIn first place, acceleration in a body occurs when a force acts on a body. There are two factors that influence the acceleration of an object: the net force acting on it and the mass of the body.
Newton's second law states that this force will change the speed of an object because the speed and / or direction will change. These changes in velocity are called acceleration.
So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object.
Mathematically, Newton's second law is expressed as:
F= m×a
where:
F = Force [N]m = Mass [kg]a = Acceleration [m/s²]Force required to keep the object in motionIn this case, you know:
F= ?m= 5 kga= 0 [tex]\frac{m}{s^{2} }[/tex]. Acceleration is a magnitude that measures the change in velocity in a given period. That is to say that if the object changes speed, that change is measured with acceleration. So if an object is moving at a constant speed, there is no change in speed and its acceleration is zero.Replacing in Newton's second law:
F= 5 kg× 0 m/s²
Solving:
F= 0 N
Finally, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.
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What name describes an object that orbits a planet?
Answer:
It can be either a moon or a satellite
Explanation:
a moon is a piece of space debris that orbits a planetdue to the planets gravitational force. Inherently, satellite mimics a moon but it is used for collecting data and etc
can you please help me with this
Answer:
1.76 seconds/cycle
Explanation:
Frequency is 10 cycles / 17.6 seconds
PERIOD is 1/frequency = 17.6 seconds/10 cycles = 1.76 s/c
cycle is a vibration , so the unit may be 1.76 second / vibration
A 25-kg piece of equipment can be hung by steel wires of length 1.00 m, 2.00 m, or 3.00 m. If all the wires have the same diameter, which one will stretch the greatest distance
If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.
What is the distance?Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.
|AB| is a symbol for the distance between two points A and B.
A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.
Hence, they will all stretch by the same percentage.
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5. In the image below, the focus lines are shown. What can be done to bring the apple into focus?
A. Make the lens rounder.
B. Make the lens flatter.
C. Move the apple farther from the eye.
D. Nothing should be done because the apple is already in focus.
In the image below, the focus lines are shown. The step can be done to bring the apple into focus is make the lens rounder. The correct option is A.
What is lens?
The lens is in spherical shape may be diverging or converging.
As light enters the eye, it is focused on the retina. Changing the pupil diameter, regulates the amount of light entering the eye. Changing lens shape will focus the light.
The changes in lens shape needed to maintain focus as the object distance changes.
Thus, the correct option is A.
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You are on a boat in a fog and know there are cliffs ahead of you somewhere, but you cannot see them. you use your fog horn to send out a blast of sound (assume the temperature of the air is 20 oc) and the time it takes for the sound to return to you is 20.0 s. how far away are the cliffs (in metric units)
The distance of the cliff from where you are is determined as 3,430 m.
Distance of the cliffApply the formula for echo.
v = 2d/t
where;
v is speed of sound at 20 ⁰C = 343 m/sd is distance = ?t is time = 20 s2d = vt
d = vt/2
d = (343 x 20)/2
d = 3430 m
Thus, the distance of the cliff from where you are is determined as 3,430 m.
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what determines the velocity of an object
a girl swims along the length of 80m in swimming pool and comes back in 1.5sec. find her distance and displacement
the distance is the first 80m+the second 80m she came back. So the distance is 160m. but the displacement is 0, because she came back by the direction she went.
Five resistors each have resistance R. Three of the resistors are connected in series and this combination is then connected in parallel with the two other resistors which have been connected in series with each other. What is the equivalent resistance for this arrangement
Answer:
6/5 * R
Explanation:
The 3 in series sum to 3R for one branch of the parallel circuit
the 2 in series sum to 2R for the other side of the parallel circuit
now find the equivalent R of the parallel circuit with 3R and 2R
here is one way
Requiv = 1 / ( 1/(3R) + 1/(2R) ) =
1/ ( 5/(6R) ) =
6R/5
the equiv resistance = 6/5 * R
In a Laundromat, during the spin-dry cycle of a washer, the rotating tub goes from rest to its maximum angular speed of 8.70 rev/s in 6.80 s. You lift the lid of the washer the instant the angular speed reaches the maximum value, and notice that the tub decelerates and comes to a stop in 19.0 s. Assuming that the tub rotates with constant angular acceleration while it is starting and stopping, determine the total number of revolutions undergone by the tub during this entire time interval.
Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have
[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]
In this time, the tub undergoes an angular displacement of
[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]
In the next 19.0 seconds the tub has acceleration
[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]
and in this time, the tube undergoes an additional displacement of
[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]
So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].
A 500. gram cart with a speed of 0.360 m/s hits a barrier and bounces back with a return velocity of -0.240 m/s. what is its change in momentum?
a. 60.0 kg*m/s
b. 0.300 kg*m/s
c. -0.300 kg*m/s
d. .0600 kg*m/s
e. -.0600 kg*m/s
The change in the momentum of the cart,given the data is 0.06 Kgm/s (Option D)
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
Change in momentum = mass (final velocity - initial velocity)
How top determine the change in the momentumFrom the data given above, the following data were obtained:
Mass (m) = 500 g = 500 / 1000 = 0.5 KgInitial velocity (u) = 0.360 m/sFinal velocity (v) = -0.240 m/s.Change in momentum =?Change in momentum = m(v + u) (renounce)
Change in momentum = 0.5 (-0.24 + 0.36)
Change in momentum = 0.5 × 0.12
Change in momentum = 0.06 Kgm/s
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The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state. Before the change, the atoms are close together but are able to slide past one another.
A diagram has a triangle at center with gas on top, liquid on bottom right, solid on bottom left. An arrow from gas to liquid is labeled O, and an arrow from liquid to gas is labeled N. An arrow from solid to liquid is labeled P, and an arrow from liquid to solid is labeled Q. An arrow from solid to gas is labeled L, and an arrow from gas to solid is labeled M.
Which arrow represents the change of state described above?
M N P Q
Answer:
its Q
Explanation:
*picture choice question*
Which is a renewable
resource?
Answer:
B
Explanation:
That is solar energy and the sun will be releasing energy constantly for the rest of its life, meaning renewable
hen approaching a curve, it is best to: A. Search for possible collision traps and escape paths B. Stay close to the centerline if there is oncoming traffic C. Squeeze the clutch lever to slow down D. Shift to a higher gear
Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.
What is Clutch?This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.
Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.
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help pleaaase!!
A train leaves the station from rest and travels along a straight track. if the train is 500 meters from the station when it reaches a velocity of 50m/s what is the acceleration of the train?
Answer:
[tex]2.5m/s^{2}[/tex]
Explanation:
Since the distance ,s = 500m
Initial velocity, u = 0m/s
Final velocity, v = 50m/s
We can one of the kinematics equations to find the acceleration.
[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]
Answer:
S=D÷T
Explanation:
50=0.5÷T
T= 100
which of the following is not a lever?
a. winch
b. scissors
c. can openers
d. tweezers
Answer:
a?
Explanation:yes it is a
7.Name three values you could measure as scalars and three values you could measure as
vectors.
scalars: distance, speed, time
vectors: displacement, velocity, acceleration
Gyroscopic wander can be divided in to two categories, one is DRIFT, what is the other?
Gyroscopic wander can be divided into two categories and these are:
DriftToppleWhat is gyroscopic wander?Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.
Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:
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If a star is moving away from you at constant speed, the absorption lines in its spectrum will.
Answer:
The absorption lines will shift to the red (become longer).
This is because of the extra distance that a wavelength λ must travel between the vibrations of the source producing the spectrum.
Note that the Doppler effect of the source is slightly different for light waves than it is for sound waves because sound waves require a medium in which to travel while light waves do not require such a medium (example air).
Calculate the mass of an object whose weight is 400n and accleration due to gravity is 10 m/ s
Answer:
40kg
Explanation:
w=m×
w=400n
g=10
m=?
400/10=m×10/10
m=40
Which two statements are true for reversible reactions that reach dynamic equilibrium?
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
What is dynamic equilibrium?The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.
The chemical reaction is a method for creating novel chemicals with unique features.
The correct statement for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."
Therefore, the correct answer will be an option (C).
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. An object is dropped from a height of 75.0 m above ground level. (a)
Determine the distance traveled during the first second. (b) Determine
the final velocity at which the object hits the ground. (c) Determine the
distance traveled during the last second of motion before hitting the
ground.
a) 4.9 m
b) 38.3 m/s
c) 33.4 m
What are three equation of motion?The three equations are,
v = u + at
v² = u² + 2as
s = ut + ½at²
According to the question,
Let hold the y-axis in the direction of gravity.
Initial velocity 0 = 0 /,
Initial height ℎ0 = 0 , and finish height ℎ = 75.0
gravitational acceleration = 9.8 /²
a) Determine the distance traveled during the first second.
By third equation of motion
[tex]S_{0} = v_{0} t +\frac{1}{2} gt^{2}[/tex] where [tex]v_{0}[/tex] =0
then [tex]S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m[/tex]
b) Determine the final velocity at which the object hits the ground
let – velocity of object, when it falling to the ground
– moment falling to the ground, and obtain from condition:
ℎ = ℎ() = 75.0
[tex]v_{f} = v_{0} +gt = gt[/tex]
[tex]h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s[/tex]
c) Determine the distance traveled during the last second of motion before hitting the ground.
From the above equation we get,
[tex]\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m[/tex]
Therefore,
a) 4.9 m is the distance traveled during the first second.
b) 38.3 m/s is the final velocity at which the object hits the ground
c) 33.4 is the distance traveled during the last second of motion before hitting the ground.
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