Do ocean currents move cold water from the tropics to the poles where the water warms?

No. this is not true for a spherical capacitor.

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The solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.

The amount of chemical substance that can dissolve in water at a specific temperature can be known as the solubility in water. The unit of solubility is generally in mg/L (milligrams per liter) or ppm (parts per million).

In the water the oxygen gets dissolved when the Oxygen is absorbed in water by direct diffusion and by surface-water agitation. The Solubility of oxygen in water is so small and by diffusion process alone in still water, it was calculated that it would take 6 years for oxygen to diffuse from surface to a depth of 6 meters in quiet water.

So, the  solubility of oxygen in water increases with the increase in the partial pressure of oxygen at a constant temperature and concentration.

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The zone in the map that has the greatest amount of land area suitable for people to live is zone B.

The equator is the imaginary line that divides the earth horizontally into two equal halves of North and South zones.

The countries that are located close to the equator include the following:

Ecuador, Colombia,

From the map, the zone with the greatest amount of land area suitable for people to live is the zone closest to the equator which is zone B.

The temperature of these areas are close to moderate through out the year.

The zone B also contains land mass that is part of the largest continent which is Asia.

Therefore, the zone in the map that has the greatest amount of land area suitable for people to live is zone B.

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The properties of Calcium are as follows:

Elements are defined as any substance which cannot be split into simpler units aby a ordinary chemical process.

Elements are the building block of all forms of matter.

Calcium one of the known 118 elements.

In the period table, Calcium has the following properties:

In conclusion, calcium is an element in the periodic table.

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Answer:

Frictional Force

Explanation:

Resistance is the resistance that one surface or object encounters when moving over another.

Tension could only occur on a rope or something that can be stretched tight.

Kinetic Energy would allow it to continue rolling-not stop.

The length of the shortest curve would be √2.

The paraboloid x2 + y2 = z2 + 1 is a doubly ruled surface, which means, it can be swept out by a moving the line in space in two different ways.

So, then we have to verify the fact that the line defined by the two given points lies entirely on the surface of the paraboloid.

The vector valued function that describes the straight line connecting the points (1, 0, 0) and (1, 1, 1) is

r (t) = < 1, t, t >, t ∈ R

and it can be stated by inspection that this satisfies the equation of the paraboloid.

Thus, it is found that the length of the line segment connecting the points is √2

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The energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J if each carbon atom emits one photon.

E = h ν = h c / λ

n = m / Mol * Avogadro's constant

E = Energy

h = Planck's constant

c = Speed of light

λ = Wavelength

n = Number of atoms

m = Mass

mol = Molar mass

h = 6.626 * [tex]10^{-34}[/tex] J s

λ = 745 nm = 7.45 * [tex]10^{-7}[/tex] m

c = 3 * [tex]10^{8}[/tex] m / s

m = 44 g C

mol = 12.01 g C

Avogadro's constant = 6.022 * [tex]10^{23}[/tex]

Energy emitted per photon, [tex]E_{1}[/tex] = ( 6.626 * [tex]10^{-34}[/tex] * 3 * [tex]10^{8}[/tex] ) / 7.45 * [tex]10^{-7}[/tex]

[tex]E_{1}[/tex] = 2.67 × [tex]10^{-19}[/tex] J

Total energy emitted, E = [tex]E_{1}[/tex] * n

E = ( 2.67 × [tex]10^{-19}[/tex] * 44 * 6.022 * [tex]10^{23}[/tex] ) / 12.01

E = 5.89 × [tex]10^{5}[/tex] J

Therefore, the energy obtained when 44 g of carbon is irradiated is 5.89 × [tex]10^{5}[/tex] J

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Answer:

The reason that the Greeks might not have had any questions to the evidence that heavier objects fall faster than light objects is because they would be questioning statistics which is that heavier objects and lighter objects do not fall at different rates but at the same its just the pending on the weight ex. a brick and a feather you drop a brick it falls quick because of its weight and a feather because of it's weight it falls a lot slower but at the measurement of the objects falling quicker than the other they don't its irrelevant.

The Initial Temperature of the Iron sphere is 253.40 C.

When two items are connected by a permeable barrier and there is no net energy flow between them, they are said to be in thermal equilibrium. This does not imply that no energy passes between the objects in thermal equilibrium; rather, an equal amount of energy flows back.

Thermal equilibrium can also relate to how heat is distributed within a single, isolated body.

Given,

Specific heat of iron = 470 J/KgC

Specific heat of water = 4200 J/KgC

Temperature of Water = 10 C

Final Temperature of Iron = 30 C

Initial Temperature of Iron = T

Heat lost by Iron = Qlost

                             = Miron SΔT

                             = (200/1000) * 470 * (T-30)

Heat gain by water = Qgain

                                 = Mwater SΔT

                                 = (500/1000) * 4200 * 10

According to the thermal equilibrium,

Qlost = Qgain

=> (200/1000) * 470 * (T-30) =  (500/1000) * 4200 * 10

=> T- 30 = 223.40

=> T = 253.40 C

Thus, the Initial Temperature of the Iron sphere is 253.40 C.

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By unit conversion, the flow rate is 600,000 liters/min or 158503.23 gallons/min.

We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as

a = xb

where a is unit a, b is unit b and x is the constant of conversion.

From the question above, we know that

Q = 10 m³/s

Convert to liters / min

Q = 10 m³/s

Q = 10 x1000 liters/(1/60 min)

Q = 600,000 liters/min

Convert to US gallons/min

Q = 600,000 liters/min

Q = 600,000 x 0.264 gallons/min

Q = 158503.23 gallons/min

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He has derived a lot of equations but the most common one is E=mc^2

(Energy=Mass×Speed of light squared)

Thermal insulators stop the loss of accumulated heat, metal flat plates absorb solar radiation, and tubes absorb solar energy with the least amount of heat loss.

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The density of the material is p =5.6 sl/ft^3 .

What is density?

The substance's mass per unit of volume is known as its density (volumetric mass density or specific mass). Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). Density is mathematically defined as mass divided by volume.

The difference between an object's weight in a normal atmosphere and its weight inside water determines the force of buoyancy for an object of any shape:

Fb = Fw atm - Fw water

= 8.05 lb - 5.26 lb

=2.79 lb

We may determine the density of an object's structure by knowing its weight in the standard atmosphere, buoyant force, and water density:

p = (p h2o. Fw atm)/ Fb

putting the values and calculating we get :

p =5.6 sl/ft^3

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(a) If she wishes to land on the other bank directly at a point directly across from her starting point, the direction she must swim is 50.3⁰ north east.

(a. ii) The time of her motion is 111.8 seconds.

(b) If she wishes to cross the shortest possible time, then she must swim the shortest possible distance. Her direction must be 90 degrees and she will swim 50 m north.

The time taken for the swimmer to land on the other bank directly at a point directly across from her starting point is calculated as;

(V₁t)² = (d²) + (V₂t)²

where;

0.7t² = 50² + 0.5t²

0.7t² - 0.5t² = 50²

0.2t² = 2500

t² = 2500/0.2

t² = 12,500

t = √12,500

t = 111.8 seconds

Resultant displacement = V₁t = 0.7 m/s x 111.8 s = 78.26 m

cos θ = adjacent side / hypotenuse side

cos θ = 50 m / 78.26 m

cos θ = 0.6389

θ = arc cos(0.6389)

θ = 50.3⁰

Thus, if she wishes to land on the other bank directly at a point directly across from her starting point, the direction she must swim is 50.3⁰.

If she wishes to cross the shortest possible time, then she must swim the shortest possible distance. Her direction must be 90 degrees and she will swim 50 m north.

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Answer:

Na+ca+CO=NACo^3

Explanation:

NA Burns violently with explosions that may spatter the material. Used for making gasoline additives, electric power cable, sodium lamps, other chemicals.

The cannonball dropped of a 65 m high castle wall will be in the air a time of: 3.642 s

The free fall formula and the procedure we will use is:

t = √[ (2*h) / g]

Where:

Information of the problem:

Applying the time formula we get:

t = √[ (2*h) / g]

t = √[ (2*65 m) / 9.8 m/s²]

t = √[ 130 m / 9.8 m/s²]

t = √[ 13.265 s²]

t = 3.642 s

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

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Answer:

moving

Explanation:

Magnetic north was drifting at a rate of up to about 9 miles (15 km) a year. Since the 1990s, however, the drift of Earth's magnetic north pole has turned into “more of a sprint,” scientists say. Its present speed is about 30 to nearly 40 miles a year (50-60 km a year) toward Siberia.

The magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per minute) if the wheel's diameter is 40 cm is [tex]4.418m/s^2[/tex].

Acceleration and change in velocity has both magnitude and acceleration because it is a vector quantity. Units are used to describe magnitude. The factors that affect acceleration include time, velocity, force, and many others. Both translation and rotation are possible.

The vector's magnitude determines its length. The vector's direction determines its direction. As a result, the acceleration's magnitude matches the acceleration vector's magnitude, and its direction matches the acceleration vector's direction.

Acceleration of speck of clay

[tex]a_R=V^2/R[/tex]

[tex]a_R=(\omega R^2)/R[/tex]

[tex]a_R=\omega R[/tex]

Given, the frequency of Potters wheel

f=45rpm

f=45(1min/60sec)

f=45/60 revolution/sec

ω=2πf

ω=2(3.14)(45/60)

ω=4.7 rad/sec

[tex]a_R=(4.7 rad/sec)^2(0.40/2 m)[/tex]

[tex]a_R=4.418m/s^2[/tex]

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According to the diameter and thickness of the gold medal, the volume of the gold medal is 8478mm³.

As a gold medal is a cylinder, so the volume of a gold medal (V) = Ah

Where h is the thickness of the medal and A is the area of the medal.

So, A = πr²               Here r is the radius = diameter÷2

V = πr²h                                                   =   60÷2

   = π × 30² × 3                                        = 30

   =8478

So the volume of the gold medal is 8478mm³.

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The moment applied is 40 Nm.

We need to know about torque to solve this problem. Torque is the rotational equivalent of linear force. It can be determined as

τ = F x r

where τ is torque, F is perpendicular force and r is radius.

From the question above, the parameter given are

F = 200 N

r = 20 cm

Convert radius to meter

r = 20 cm

r = 20 x 10¯² m = 0.2 m

By substituting the parameters, we get

τ = F x r

τ = 200 x 0.2

τ = 40 Nm

Hence, the moment applied is 40 Nm

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By applying the wave equation, the wavelength is 2.68 meters.

We need to know about wave equations to solve this problem. The displacement of the wave on the y-axis can be explained by the wave equation

y = A cos (kx - ωt)

where y is y-axis displacement, A is amplitude, k is wave number, x is x-axis displacement, ω is angular speed and t is time.

the wavenumber and angular speed of the wave equation can be determined respectively by

k = 2π / λ

ω = 2πf

where k is the wavenumber, λ is wavelength and f is frequency.

From the question above, we know that:

f = 0.5 Hz

A = 0.35 m

v = 1.34 m/s

When the amplitude is doubled, it doesn't affect the wavelength. Hence

v = λ . f

1.34 = λ . 0.5

λ = 2.68 m

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The mean velocity of helium atoms at room temperature (t~300k) and the de broglie wavelength is 1.3635 * 105 cm/s  and 0.73 Armstrong respectively

In 1923, Louis-de-Broglie presented the notion of De-Broglie waves, that were also later tested with and proven by Davisson and Germer in 1927. These waves describe the nature of the particle-related wave.

Another variation of the de Broglie wavelength formula exists for particles having mass, such as electrons, protons, and so on, but not for photons. At non-relativistic speeds, a particle's momentum is equal to its rest mass m multiplied by its velocity v.

The de Broglie wavelength is measured in meters. Because it is so little, it is measured in nanometres or Angstroms.

Uavg = √(3KT/M)

Uavg = √((3×1.38〖×10〗^(-23)×300K)/(4×1.67×〖10〗^(-27) ))

Uavg = 1.3635 * 105 cm/s

λ = h/ mv

λ = (6.67×〖10〗^(-34))/((4×1.67×〖10〗^(-27))×(1.3635×〖10〗^3))

= 0.7323 * 10-10 m

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The angle to make should be 68 degree.

What is a projectile motion?

A projectile is any object thrown into space upon which the only acting force is gravity.

When a particle is thrown obliquely near the earth’s surface, it moves along a curved path under constant acceleration directed towards the center of the earth. The path such a particle takes is called projectile and the motion is called projectile motion.

From the equation we have initial velocity as 16.8 m/s

angle= 56 degrees

R1= V² sin2∅1/g

R2= V² sin2∅2/g

R1=R2

V² sin2∅1/g= V² sin2∅2/g

sin2∅1/g= sin2∅2/g

∅2= sin2∅2

∅2= sin(2* 56)

∅2= 68 degrees

When a particle is projected in the air with some speed the only force acting on it during its time in the air is the acceleration due to gravity (g).

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Water flows at a rate of 3.11 kilograms / seconds through a hose with a diameter of 3 centimetres. then the speed of the water in the hose would be 4.40 meters / second.

The total displacement covered by any object per unit of time is known as velocity. The velocity of an object depends on the magnitude as well as the direction of the object.

As given in the problem if Water flows at a rate of 3.11 kg/s through a hose with a diameter of 3 cm.

Area of the hose = πD²/4

                            =3.14*3*3/40000

                            =7.065×10⁻⁴ meter²

The discharge of the water = 3.11/1000

                                              =3.11×10⁻³ meter³

The discharge of the water = area of hose ×velocity

3.11×10⁻³ meter³ = 7.065×10⁻⁴ meter²×velocity

velocity = 3.11×10⁻³ /  7.065×10⁻⁴

             =4.40 metes/ second

Thus,the speed of the water in the hose would be 4.40 metes/ second.

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The wavelength of electromagnetic waves is 2.88 meters.

We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic waves in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as

c = λ . f

where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.

From the question above, we know that

f = 104.3 MHz = 104.3 x 10⁶ Hz

By substituting the given parameter, we can calculate the frequency of radiowaves

c = λ . f

3 x 10⁸ = λ . 104.3 x 10⁶

λ = (3 x 10⁸) / (104.3 x 10⁶)

λ = 2.88 m

Hence, the wavelength of radiowaves is 2.88 meters.

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The heat added is 348.165 kj

The enthalpy of vaporization, commonly known as the heat of vaporization or heat of evaporation, is the amount of energy required to turn a liquid material into a gas. The enthalpy of vaporization depends on the pressure at which the transition occurs.

The heat of vaporization varies with temperature, yet for small temperature ranges and decreased temperature ranges, a constant heat of vaporization can be assumed. The heat of vaporization decreases with rising temperature until it totally disappears at a point known as the crucial temperature. The liquid and vapor phases are indistinguishable beyond the critical temperature, and the material is referred to as a supercritical fluid.

Given that;

M = 150g = 0.15kg

T = 75oC

Heat capacity, h =2321.1 kj/kg

Q = m h

Q = 0.15* 2321.1

Q = 348.165 kJ

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The partial pressure of [tex]$\mathrm{Cl}_2$[/tex] in the flask is [tex]$1.067 \mathrm{~atm}$[/tex]

Partial pressure can be derived through the following:

Total pressure of a gas mixture = sum of the partial pressures of individual gases

[tex]\mathrm{P}(\text { total })=\mathrm{P}\left(\mathrm{f}_2\right)+\mathrm{P}\left(\mathrm{Cl}_2\right)[/tex]

Partial pressure = Mole fraction [tex]$\times$[/tex] Total pressure

Let us represent the mass of each gas as [tex]\mathrm{m}.[/tex]

Number of moles of [tex]$F_2=\mathrm{m} / 38$[/tex] (molar mass of [tex]$\left.\mathrm{Fl}_2\right)=38 \mathrm{~g} / \mathrm{Lol}$[/tex]

Number of moles of [tex]$\mathrm{Cl}_2=\mathrm{m} / 71$[/tex](molar mass of [tex]$\mathrm{Cl}_2$[/tex] )

Mole fraction of [tex]$F_2=(\mathrm{m} / 38) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.65$[/tex]

Mole fraction of [tex]$\mathrm{Cl}_2=(\mathrm{m} / 71) /(\mathrm{m} / 38)+(\mathrm{m} / 71)=0.35$[/tex]

Partial pressure of [tex]$\mathrm{Cl}_2=0.35 \times 3.05=1.067 \mathrm{~atm}$[/tex]

Partial Pressure of [tex]$\mathrm{F}_2=0.65 \times 3.05 =1.98 \mathrm{~atm}$[/tex]

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The frequency of the first harmonic mode in string is 13.2Hz.

As, we know

[tex]v = \sqrt{\frac{T}{u} }[/tex]

where, v = velocity

T = tension in string

[tex]v = \sqrt{\frac{70(2)}{0.050}[/tex]

v = 52.9m/s

Also,

f = v / λ

where, f = frequency

v = velocity

λ = amplitude

f = 52.9 / 4

f = 13.2Hz

Therefore,  frequency of the first harmonic mode in string is 13.2Hz.

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230km far does it travel during 14.2 minutes.

A car travels straight down a highway with cruise control set to = 100 km/h

how far does it travel during 14.2 minutes

so, now we use

Distance = velocity [tex]\times[/tex] time

1 min = 1/60 hour

14.2 min = 14.2 / 60 hour

= 0.23 hour

now,

Distance = 1000[tex]\times[/tex]0.23 km

= 230km

so.  230km  it travel in 14.2 minutes

Distance is the length of the path between two points. and it's standard unit is meter while displacement is shortest distance between final position and initial position and it also has meter as a standard unit.

written as m.

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The particle with a velocity of 4 m/s and with an acceleration 10 m/s2 in a sec will travel a distance of: 9 m

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

x = (vi* t) + (a * t²)/2

Where:

Information about the problem:

Applying the distance formula, we have:

x = (vi* t) + (a * t²)/2

x = (4 m/s * 1 s) + (10 m/s² * (1 s)²)/2

x = 4 m + (10 m/s² * 1 s²)/2

x = 4 m + (10 m)/2

x = 4 m + 5 m

x = 9 m

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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