Answer:
15
Step-by-step explanation:
First you have to order the numbers from least to greatest
13, 13, 15, 20, 24
Then you find the value in the middle.
You have five numbers so your middle value is the number between the the two numbers on the left and the two numbers on the right which is 15.
Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
128 Superscript StartFraction x Over 3 EndFraction
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 1 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
(2)x
Answer:
(A)[tex]128^{x/3}[/tex]
(D)[tex](4(2^{1/3}))^x[/tex]
Step-by-step explanation:
We want to determine which of the expression is equivalent to:
[tex]\sqrt[3]{128}^ x[/tex]
By the law of indices:
[tex]\sqrt[3]{128}=128^{1/3}\\$Therefore:\\\sqrt[3]{128}^ x \\=(128^{1/3})^x\\=128^{x/3}[/tex]
Similarly:
[tex]\sqrt[3]{128}^ x \\=\sqrt[3]{64*2}^ x\\=(4\sqrt[3]{2})^ x\\=(4(2^{1/3}))^x[/tex]
The expressions that are equivalent to (∛128)ˣ are; (128)^(x/3) and (4(2^(1/3))ˣ
How to use law of indices?We want to find the expression that is equivalent to (∛128)ˣ
From law of indices, we have that;
(∛128)ˣ = [(128)^(1/3)]ˣ
This can be further expressed as;
(128)^(x/3)
Similarly, we have the simplified expression at;
[(128)^(1/3)]ˣ = (64 * 2)^(x/3)
⇒ (4³ * 2)^(x/3)
⇒ (4(2^(1/3))ˣ
Read more about law of indices at; https://brainly.com/question/11761858
#SPJ6
what is log 8/3 base 5
Answer:
3 to the power of 8 / 5
Step-by-step explanation:
Two similar cardboards have areas of 24cm² and 150cm². If the length of the bigger one is 10cm ,what is the length of the smaller one,?
Answer:
4 cm
Step-by-step explanation:
You want the length of the smaller of two similar pieces of cardboard when the larger has an area of 150 cm² and a length of 10 cm, while the smaller has an area of 24 cm².
Scale factorThe scale factor for lengths is the square root of the scale factor for areas. It will be ...
√(24/150) = 0.4 . . . . . . = smaller / larger
The smaller cardboard has a length of ...
0.4 × 10 cm = 4 cm
__
Additional comment
Sometimes folks like to write this as a proportion:
[tex]\dfrac{\text{smaller length}}{\text{larger length}}=\sqrt{\dfrac{\text{smaller area}}{\text{larger area}}}[/tex]
Solving this for "smaller length" gives the expressions we used above:
smaller length = (larger length) × √(smaller area/larger area)
Penny had a bag of marbles. She gave one-third of them to Rebecca, and then one-fourth of
the remaining marbles to John. Penny then had 24 marbles left in the bag. How many marbles were
in the bag to start with?
pls explain.
Given That:
x - (Rebecca's share + John's share) = 24
x - (x/3 + x/4) = 24
12x/12 - (4x / 12 + 3x / 12) = 24
5x/12 = 24
5x = 24 x 12
5x = 288
x = 57 or 58
Use the circle to answer the questions.
A circle with radius 5.4 centimeters.
The diameter is
cm.
The circumference in terms of Pi is
Using 3.14 for Pi, the approximate circumference of the circle is
cm.
Answer:
C = 10 π cm
Step-by-step explanation:
Diameter is 2 x radius = 2*5.4 = 10.8 cm
radius r = 5 cm
diameter d = 10 cm
circumference C = 31.4 cm
area A = 78.5 cm2
In Terms of Pi π
circumference C = 10 π cm
area A = 25 π cm²
Formulas: Circle Formulas in terms of Pi π, radius r, and diameter d
Radius and Diameter:
r = d/2
d = 2r
Area of a circle:
A = πr2 = πd2/4
Circumference of a circle:
C = 2πr = πd
Answer:
c
Step-by-step explanation:
got it right on my test
Find the SURFACE AREA of this composite solid. Show work
Answer:
8
Step-by-step explanation:
4+4
6-6+8
A classroom will be assembled so that the desks fit within an area that is 8 m by 12 m. The desks will be surrounded by a border that will be the same width on all sides of the rectangular room, to
allow for walking space. The area of the border will equal 20% of the area of the space that the desks
occupy. What is the width of the border, to the nearest hundredth of a meter?
Answer:
0.46 m
Step-by-step explanation:
area of desks: 8 m by 12 m = 8 m * 12 m = 96 m^2
20% of this area is 20% * 96 m^2 = 19.2 m^2
The area of the border is 19.2 m^2.
Let the path around the desks have width x.
The area of desks plus path is a rectangle 2x + 8 by 2x + 12.
area of desks plus path = (2x + 8)(2x + 12)
= 4x^2 + 24x + 16x + 96 = 4x^2 + 40x + 96
The area of the border is the area of the rectangle that includes the border minus the rectangle that has just the desks.
area of border = (4x^2 + 40x + 96) - (96) =
= 4x^2 + 40x
Above, we have the area of border = 19.2, so we get this equation:
4x^2 + 40x = 19.2
4x^2 + 40x - 19.2 = 0
x^2 + 10x - 4.8 = 0
We now use the quadratic formula to solve the equation for x.
[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
[tex] x = \dfrac{-10 \pm \sqrt{10^2 - 4(1)(-4.8)}{2(1)} [/tex]
[tex] x = \dfrac{-10 \pm \sqrt{100 + 19.2 )}{2} [/tex]
[tex] x = \dfrac{-10 \pm \sqrt{119.2 )}{2} [/tex]
[tex] x = 0.46 [/tex] or [tex] x = -10.46 [/tex]
We discard the negative solution.
Answer: the border is 0.46 m wide.
Solve 5 + x - 14 = x - 7
Answer:
No solution
Step-by-step explanation:
5+x-14=x-7
-9+x=x-7
2+x=x
2=0
No solution
If A = T, then SM ___ MO. > = < NEED HELP
Answer:
I'm not sure but I think the answer is >
Step-by-step explanation:
It looks rig but if I were u I wouldn't trust me
i just did the quiz, It's > !
anybody know this :( please help
Answer:
the set of all the real values which are strictly greater than zero which is all positive real numbers
Step-by-step explanation:
In interval notation: (0, ∞)
Any exponential function with a positive base and positive multiplier will have a horizontal asymptote at y=0 and will extend to +∞. That's what this one does.
Range of a function--
The range of a function is the set of all the values that are attained by a function.
We are asked to find the range of the function f(x)
the set of all the real values which are strictly greater than zero
x > 0
please mark me brainliest :)
I need help with this question
Answer:
15
[tex] \\ [/tex]
Step-by-step explanation:
[tex] = \sqrt{ {12}^{2} + {9}^{2} } \\ = \sqrt{144 + 81} \\ = \sqrt{225} \\ = 15[/tex]
Answer:
the missing side of the triangle is of length 15
Step-by-step explanation:
This problem is asking to find the hypotenuse (longest side) of a right angle triangle, so we can use the Pythagorean theorem, which tells us that the square of the hypotenuse in a right angle triangle equals the addition of the squares of the legs of the triangle (in our case 9 and 12).
We can then find the length of the hypotenuse applying the square root on both sides:
[tex]hyp^2=leg_1^2+leg_2^2\\hyp^2=9^2+12^2\\hyp^2=81+144\\hyp^2=225\\hyp=\sqrt{225} \\hyp=15[/tex]
The scatter plot below shows the relationship between two variables, x and y. Which kind best fits the data?
Answer:
The last one on the bottom right
Step-by-step explanation:
When we are trying to fit a line for a number of points, we can fix this line at several points on the graph. However, out of the several lines that we can fit, only one of these lines would work perfectly and it is called the line of best fit.
The reason why it is called the line of best fit is that it is drawn in a manner in which it leaves equal number of points above it as below it.
Supposed we have 15 points for our graph with the line of the slope passing thorough 5, the line of best fit in this case would leave 5 points above and another 5 below the line.
Leaving 6 and 4 is also manageable, but in case where 3 and 7 are left above and below the line, then it becomes a problem
Thus, out of all the representations we have, the one on the bottom right best works
The perimeter of a scalene triangle is 14.5 cm. The longest side is twice that of the shortest side. Which equation can be used to find the side lengths if the longest side measures 6.2 cm?
Answer:
Step-by-step explanation:
If the longest side is 6.2 cm, and it is twice the length of the shortest, then we can write an equation as 2x=6.2, where x is the short side length.
Then, since a triangle has 3 sides, the medium side length is 14.5-6.2-x.
Hope that helped,
-sirswagger21
If a student with 2 absences got a score of 12 what would be the score for a student who had 3 absences
Which of the following does not come from domesticated animals?
a. milk from cows, sheep, and goats
c. fertilizer to help crops grow better
b. labor to pull the plows
d. furs for shelter and warmth
Triangle P Q R is shown. Angle R P Q is 99 degrees and angle P Q R is 31 degrees. The length of Q R is 11. Determine the measures of all unknown angles and side lengths of ΔPQR. Round side lengths to the nearest hundredth.
Answer:
[tex]\angle PRQ = 50^\circ[/tex]
PR = 5.74 units and
PQ = 8.53 units
Step-by-step explanation:
We are given the following details:
[tex]\angle RPQ =99^\circ[/tex]
[tex]\angle PQR =31^\circ\\\text{Side QR} = 11\ units[/tex]
To find:
[tex]\angle PRQ =?\\Side\ PR = ?\\Side\ PQ = ?[/tex]
We know that the sum of all the angles of a triangle is equal to [tex]180^\circ[/tex]
i.e.
[tex]\angle PQR +\angle PRQ +\angle RPQ =180^\circ\\\Rightarrow 31^\circ +\angle PRQ +99^\circ =180^\circ\\\Rightarrow \angle PRQ = 180-130\\\Rightarrow \angle PRQ = 50^\circ[/tex]
To find the sides, we can use Sine rule:
As per Sine rule:
[tex]\dfrac{a}{sin A} =\dfrac{b}{sin B} =\dfrac{c}{sin C}[/tex]
Where a, b and c are the sides opposite to [tex]\angle A,\angle B,\angle C[/tex] respectively.
Using Sine rule in given triangle:
[tex]\dfrac{11}{sin 99} =\dfrac{b}{sin 31} =\dfrac{c}{sin 50}\\\\\text{Solving }\dfrac{11}{sin 99} =\dfrac{b}{sin 31} \\\Rightarrow b = \dfrac{11}{sin 99} \times sin31\\\Rightarrow b =5.74\ units\\\\\text{Now, Solving }\dfrac{11}{sin 99} =\dfrac{c}{sin 50} \\\Rightarrow c = \dfrac{11}{sin 99} \times sin50\\\Rightarrow c =8.53\ units[/tex]
So, sides are
PR = 5.74 units and
PQ = 8.53 units
Answer:
Answer:
PR = 5.74 units and
PQ = 8.53 units
Step-by-step explanation:
We are given the following details:
To find:
We know that the sum of all the angles of a triangle is equal to
i.e.
To find the sides, we can use Sine rule:
As per Sine rule:
Where a, b and c are the sides opposite to respectively.
Using Sine rule in given triangle:
So, sides are
PR = 5.74 units and
PQ = 8.53 units
Step-by-step explanation:
In right triangle ABC, ∠C is a right angle and sin A = sin B. What is m∠A?
Answer:
If sinA = sinB, that means that ∠A = ∠B. Because this is a right triangle, ∠A = 45°.
Based on the equation 3x + 8y = 48, what is the missing value in the table?
Answer:
24x
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
I did the edu test hope this helps♡
Which of the following is equal to the fraction below?
Answer:
D
Step-by-step explanation:
(5/9)^8
You distribute the exponent 8 to both the 5 and the 9, so D is just 1 step more simplified.
Answer: The correct option is (D) {5^8}{9^}.
hope this helps. ;)
A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Two marbles are chosen from the bag. What expression would give the probability that one marble is yellow and the other marble is red?
- 30%
- 40%
- 50%
- 60%
Answer:
2/15 = 13 1/3 %
Step-by-step explanation:
eight yellow marbles, nine green marbles, three purple marbles, and five red marbles = 25
P(yellow) = yellow/ total =8/25
Keep
7 yellow marbles, nine green marbles, three purple marbles, and five red marbles = 24
P(red) = red/total =5/24
P(yellow then red) = 8/25 * 5/24 = 1/15
Then we have (red, yellow) =
P(red) = red/ total =5/25 = 1/5
Keep
8 yellow marbles, nine green marbles, three purple marbles, and four red marbles = 24
P(yellow) = yellow/total =8/24 = 1/3
P(red, yellow) = 1/5*1/3 = 1/15
Add them together
1/15 + 1/15 = 2/15 =
David wants to find the solutions of this system of equations: –4x – 7 = y x2 – 2x – 6 = y Which statement is true? Plz its urgent!!
Answer:
(-1, -3)
Step-by-step explanation:
The given equations are:
[tex]-4x-7=y ...... (1)[/tex]
and
[tex]x^2 - 2x - 6 = y ....... (2)[/tex]
Equating (1) and (2):
[tex]-4x -7 =x^{2}-2x-6\\\Rightarrow x^{2}-2x-6+4x+7=0\\\Rightarrow x^{2}+2x+1=0\\\Rightarrow (x+1)^2=0\\\Rightarrow x = -1[/tex]
The two values of x are repeating in nature i.e. x = -1
So, value of [tex]x[/tex] is -1.
Putting value of [tex]x[/tex] in equation (1):
[tex]-4 \times (-1)-7=y \\\Rightarrow y=-3[/tex]
The solution is represented as ([tex]x,y[/tex])
So, the solutions are :
(-1, -3)
Answer:
2
Step-by-step explanation:
give brainliest
someone please help
Answer:
See explanation for answers
Step-by-step explanation:
prism = 12*4 + 5*4 + 12*4 + 5*4 + 12*5 + 12*5 = 256 ft²
lateral surface area of pyramid = 4*1/2*5*5 = 50 ft²
area of square base of the pyramid = 5*5 = 25 ft²
total exposed surface area of the figure = 256 + 50 - 25 = 281 ft²
The price of an item has been reduced by 15%. The original price was $17
Answer:
17/100*85= $14.45
Step-by-step explanation:
Divide by 100 and multiply by (100-15) 85 to get the result.
What is the circumference and area of a circle in which the diameter of the circle is 16 feet
Answer:
The circumference is 50.27 and the area is 201.06 I rounded up to the nearest hundredths. And I used actually pi not just 3.14, here it is in the terms of using 3.14 circumference is 50.24 no rounding and area is 200.96 and no rounding, I hope this helps
Step-by-step explanation:
Record 3 2/25 as a decimal. Please help!!!!!
Answer:
1.28 is the decimal form
Step-by-step explanation:
and 128/100 or 128% is the percentage for 32/25.
// have a great day //
find the circumference
Answer:
25.12
Step-by-step explanation:
C = 2*3.14*4
C = 8*3.14
C = 25.12
Answer:
C =25.12 cm
Step-by-step explanation:
The circumference is given by
C = 2* pi *r
C = 2 * 3.14 * 4
C =25.12 cm
If a quadrilateral has 3 angles measure 60,45 and 100; find the measure of the fourth angle
Answer:
The fourth angle is 155
Step-by-step explanation:
The sum of the angles of a quadrilateral are 360 degrees
60 + 45 + 100 + x = 360
Combine like terms
205+x = 360
Subtract 205 from each side
205+x-205 = 360-205
x =155
Answer:
155
Step-by-step explanation:
What is the diameter of a circle with a radius of 9.5 cm ?
Answer:
9.5(2) = 19 is the diameter
Step-by-step explanation:
Answer:
19 cm
Step-by-step explanation:
Diameter is twice the radius, thus 2 x 9.5 cm = 19 cm
The revenue generated by the band is given by the expression 50x+150
Select all of the ordered pairs that are solutions to the inequality:
50x + 150y > 1500
(1, 10)
(10, 1)
(0, 10)
(40, 0)
Answer:
(1, 10) and (40, 0)
Step-by-step explanation:
Given expression 50x+150
inequality is
50x + 150y > 1500
it means that if we plug value of x and y from given option in 50x+150 then it should be greater than 1500.
lets check for all the option
(1,10)
50*1 + 150*10 = 50+1500 = 1550
Since , 1550 is greater than 1500, (1,10) is the solution for the inequality given
(10, 1)
50*10 + 150*1 = 500+ 150 = 650
Since , 650 is less than 1500, (10,1) is not the solution for the inequality given
(0, 10)
50*0 + 150*10 = 0 + 1500 = 1500
Since , 1500 is equal to 1500 but not greater than 1500, (0,10) is not the solution for the inequality given
(40, 0)
50*40 + 150*0 = 2000 + 0 = 2000
Since , 200 is greater than 1500, (40,0) is the solution for the inequality given above.
Thus, from the given option there are two solution for 50x + 150y > 1500
(1, 10) and (40, 0)
(1, 10) (40, 0) as the person above/below stated.
Which of the following is the complete factorization of 10x - 3 - 3x2? -(3x + 1)(x - 3) -(3x - 1)(x - 3) (3x - 1)(x + 3)
Answer:
[tex]=-\left(3x-1\right)\left(x-3\right)[/tex]
Step-by-step explanation:
[tex]10x-3-3x^2\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(3x^2-10x+3\right)\\\mathrm{Factor}\:3x^2-10x+3:\quad \left(3x-1\right)\left(x-3\right)\\3x^2-10x+3\\\mathrm{Write\:in\:the\:standard\:form}\:ax^2+bx+c\\=3x^2-10x+3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(3x^2-x\right)+\left(-9x+3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}3x^2-x\mathrm{:\quad }x\left(3x-1\right)\\3x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=3xx-x[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)[/tex]
