Answer:
27,500 N
Explanation:
W = Fd
F = W/d = (2.2x10⁵J)/(8 m ) = 27,500 N
a small vibrating object s moves across the surface of a ripple tank producing the wave fronts shown above. the wave fronts move with speed v. the object is traveling in what direction and with what speed relative to the speed of the wave fronts produced?
The wave fronts seen above are the result of a small vibrating moving object across a ripple tank's surface. The surface waves move quickly in contrast to the Doppler effect. The item is travelling right, which has compressed the waves at the right.
What is the Doppler effect in plain English?Doppler Effect is the term used to describe the shift in wave frequency caused by the relative motion of an incident wave and its observer.
What makes the Doppler effect effective?One of the most typical examples is the sound of an ambulance or fire engine's siren. You may have observed that the pitch of a siren decreases sharply as it passes you at a high rate of speed. The siren initially approaches you while the pitch is louder.
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a person pushes a 10 kg box from rest and accelerates it to a speed of 2.3 m/s with a constant force. if the box is pushed for a time of 4.8 s, what is the force exerted by the person?
The average force exerted by the person is 4.8 N (23 N / 4.8 s).
What is force?Force is an interaction between two or more objects that can cause a change in the motion, shape, or energy of one or both of the objects. Force can be classified into two categories: contact forces and non-contact forces. Examples of contact forces include friction, tension, and normal force. Examples of non-contact forces include gravity, magnetism, and electrostatic forces. Force is measured using the SI unit called the newton (N).
The force exerted by the person is equal to the mass of the box multiplied by the acceleration. Since the mass of the box is 10 kg and the acceleration is 2.3 m/s, the force exerted by the person is 23 N (10 kg × 2.3 m/s). This force was applied over a time of 4.8 s, so the average force exerted by the person is 4.8 N (23 N / 4.8 s).
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given that a 300-k blackbody radiates its peak energy at a wavelength of about 10 mm, at what wavelength would a 600-k blackbody radiate its peak energy? b. if the two bodies in part (a) were the same size, what would be the ratio of the heat emitted by the hotter object to the heat emitted by the colder one
The highest energy of a 600 k absorption coefficient would be radiated at 5 micrometer wavelength.
A blackbody explain is what?A theoretical concept known as a black body, also spelled as blackbody, describes an item that completely absorbs all electromagnetic waves that strikes it, along with all light wavelengths. No light is returned in return.
Does Earth have a blackbody?We will treat the planets and stars, including the sun and the earth, as blackbodies even if they don't actually exist. Although they are not by definition ideal blackbodies, we can nonetheless refer to them as blackbodies for the purposes of comprehension and simplicity.
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Sam tried tying toys to his toy parachute. He discovered that differences in size, shape, and material affected
A: Friction
B: Motion
C: Direction
D: Drag
Sam tried tying toys to his toy parachute. He discovered that differences in size, shape, and material affected Drag , option D.
How does Drag affect gravity?Changes in acceleration are caused by resistance and friction. The heavier piece was slowed down by air resistance also known as drag. Drag is the force that opposes the motion of an object through a fluid.
The parachute works by creating drag, slowing the descent of the objects attached to it. The size, shape, and material of the toys that Sam tied to the parachute would affect the amount of drag created, which in turn would affect the motion of the toys as they descended.
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(q020) the conventional system of signs that indicate relative durations of long and short sounds is called
The term "musical notation" refers to the widespread symbology used to indicate how far apart long and short sounds should be from one another.
What is fundamental musical notation?a collection of visual instructions for performing music, a visual representation of a heard or imagined musical sound, or musical notation. It usually takes the form of writing or printing and is a deliberate, comparatively time-consuming activity. One of two purposes—as a memory aid or for communication—causes its use.
What are the twelve notes in music?Typically, Western music employs 12 notes: C, D, E, F, G, A, B, plus five flats and comparable sharps in between: C sharp/D flat (they are the same note, simply referred to differently depending on the context).
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the inner planets of the solar system are rocky whereas the outer planets contain a higher proportion of ice and gas. this differentiation occurred in the early solar system because:
The differentiation, that the inner planets of the solar system are rocky while the outer planets contain a higher proportion of ice and gas, occurred in the early solar system due to the temperature gradient in the protoplanetary disk.
This occurs because in the inner regions of the disk, temperatures were too high for volatile elements such as hydrogen and helium to condense, while in the outer regions, temperatures were low enough for these elements to condense, forming the gas and ice giants.
In addition, due to the increased gravity in the inner regions of the disk, heavier elements, such as metals and rocks, were able to accumulate more easily, leading to the formation of the terrestrial planets.
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± A Superball Collides Inelastically with a Table
As shown in the figure (Figure 1) , a superball with mass m equal to 50 grams is dropped from a height of hi=1.5m . It collides with a table, then bounces up to a height of hf=1.0m . The duration of the collision (the time during which the superball is in contact with the table) is tc=15ms . In this problem, take the positive y direction to be upward, and use g=9.8m/s2 for the magnitude of the acceleration due to gravity. Neglect air resistance.
Part A Find the y component of the momentum, pbefore,y, of the ball immediately before the collision. Express your answer numerically, to two significant figures.
Part B Find the y component of the momentum of the ball immediately after the collision, that is, just as it is leaving the table. Express your answer numerically, to two significant figures.
Part C Find Jy, the y component of the impulse imparted to the ball during the collision. Express your answer numerically, to two significant figures.
Part D Find the y component of the time-averaged force Favg,y, in newtons, that the table exerts on the ball. Express your answer numerically, to two significant figures.
Part E Find Kafter−Kbefore, the change in the kinetic energy of the ball during the collision, in joules. Express your answer numerically, to two significant figures.
Please show your work in detail, I'm posting because I need to know how to get to the answer, I'm studying for an exam.
Part A
The momentum of the ball right before the collision is given by the equation
$p_{before,y} = mv_{before,y}$
But we know the initial velocity of the ball before the collision is just the velocity due to gravity, which is given by
$v_{before,y} = gt_0$
where $t_0$ is the time taken for the ball to fall from the initial height to the table.
This is given by
$t_0 = \sqrt{\frac{2h_i}{g}}$
Substituting this into the equation for the momentum gives
$p_{before,y} = mg\sqrt{\frac{2h_i}{g}}$
The final answer is
$p_{before,y} = m\sqrt{2gh_i} \approx 88.5 \,\text{kg m/s}$
Part B
The momentum of the ball right after the collision is given by the equation
$p_{after,y} = mv_{after,y}$
But we know the final velocity of the ball after the collision is just the velocity due to gravity, which is given by
$v_{after,y} = gt_f$
where $t_f$ is the time taken for the ball to fall from the final height to the table.
This is given by
$t_f = \sqrt{\frac{2h_f}{g}}$
Substituting this into the equation for the momentum gives
$p_{after,y} = mg\sqrt{\frac{2h_f}{g}}$
The final answer is
$p_{after,y} = m\sqrt{2gh_f} \approx 73.6 \,\text{kg m/s}$
Part C
The impulse imparted to the ball during the collision is given by
$J_y = p_{after,y} - p_{before,y}$
Substituting the values from Parts A and B gives
$J_y = 73.6 \,\text{kg m/s} - 88.5 \,\text{kg m/s} \approx -14.9 \,\text{kg m/s}$
Part D
The average force exerted on the ball during the collision is given by
$F_{avg,y} = \frac{J_y}{t_c}$
Substituting the value from Part C gives
$F_{avg,y} = \frac{-14.9 \,\text{kg m/s}}{15 \,\text{ms}} \approx -0.99 \,\text{N}$
Part E
The change in kinetic energy of the ball during the collision is given by
$K_{after} - K_{before} = \frac{p_{after,y}^2 - p_{before,y}^2}{2m}$
Substituting the values from Parts A and B gives
$K_{after} - K_{before} = \frac{73.6^2 - 88.5^2}{2 \cdot 50} \approx -3.3 \,\text{J}$
What is kinetic energy?
Kinetic energy is the energy of a moving object, equal to the work done to accelerate the object from rest to its current velocity. It is dependent on the object's mass and velocity.
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When you catch a water balloon, it's best to start with your hand in motion, moving with the balloon, and then gradually slow it to rest. Why is this approach desirable?
This strategy is preferable since you need to apply force because of water balloon does indeed have a lot of motion. To bring its balloon to rest, you must apply a force over a period of time.
Motion? What do you mean?The physics term for a body's position nor orientation changing over time. Translation is defined as movement along this line or a curve. Rotation is a motion that modifies a body's orientation.
To let the balloon to settle after some time, according to Δp = fΔtΔp→F→Δt
In contrast to if the balloon just smacked against a hand that was immobile, you may bring the inflatable to rest by moving your hand as the balloon does. You may place the balloon on top of something bigger. The force could be less. The effort can be reduced while still causing its same acceleration change and preventing the balloon from breaking.
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An object is 1.0 cm tall and its erect image is 3.0 cm tall. What is the exact magnification?
An object is 1.0 cm tall and its erect image is 3.0 cm tall, the exact magnification is 3.
What is magnification?Magnification measures how much the image is enlarged compared to the actual object. Magnification measures how many distinct structures can be seen in an image. Calculating magnification is as simple as dividing the eyepiece's magnification by the objective lens's.
By dividing the image height, it is possible to calculate the precise magnification of the objects. We determine it by dividing the size of the erect image by the size of the object. By dividing 3.0 cm by 1.0 cm from the above information, we can determine the precise magnification. So, the response would be 3.
exact magnification = image height/object's height
exact magnification = 3/1
exact magnification = 3.
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Calculate the pressure of the air when the volume is reduced to 0.42 L at the same temperature. When the equation for the line representing the relationship between Volume (L) vs. (1/pressure) is y
The pressure when the volume is reduced to 0.42 L is (y - b) ÷ m.
What is pressure?Pressure is the force per unit area applied to a surface or object. In the physical sciences, pressure is a measure of the force exerted on a surface by a fluid, such as a gas or liquid. Pressure is the result of the weight of the fluid pushing down on a surface. In physics, pressure is often expressed as the ratio of force to area. Pressure is typically measured in units of pascals (Pa) or pounds per square inch (psi). Pressure can also be measured in atmospheres (atm), bars, or torr.
The equation for the line representing the relationship between Volume (L) and (1/pressure) is y = mx + b, where m is the slope and b is the y-intercept.
Since we know the Volume (L) is 0.42, we can use this value to solve for the pressure.
Using the equation, we can calculate the pressure by solving for x:
x = (y - b) ÷ m
Therefore, the pressure when the volume is reduced to 0.42 L is (y - b) ÷ m.
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If a person whirls an object horizontally in a counter clockwise direction and the string breaks at point P as shown, what path will the rock follow?
If a person whirls an object horizontally in a counter-clockwise direction and the string breaks at point P, the rock will follow a path that is determined by the combination of its initial horizontal velocity and its vertical velocity due to gravity.
Without additional information about the object's initial velocity and the distance from the point of release to the ground, it is difficult to determine the exact path that the rock will follow. However, it is likely that the rock will follow a curved path, where gravity causes the rock to fall vertically downward while the horizontal velocity causes it to continue moving horizontally. This path is known as a parabolic path or a projectile motion.
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So sorry but I need help ;(
Gwen is completing a physics investigation involving the speeds of toy cars on a track. Two cars are going to be released from the top of a ramp and timed until they reach the bottom. Before her investigation, Gwen comes up with a hypothesis. She states that toy car A will be faster than toy car B. She runs three trials of her investigation and records her data.
After Gwen’s experiment, she finds that toy car B was faster than toy car A. How should she proceed with her investigation?
A. Gwen should stop her investigation because her hypothesis was supported by her findings.
B. Gwen's hypothesis is invaluable because it was incorrect. She should completely discard her original hypothesis and investigation, starting again from scratch.
C. Gwen's hypothesis is valuable even though it was incorrect. She should rethink her original hypothesis, or design a new way to test her original hypothesis.
D. Gwen should assume that she made an error in her original experiment, because a hypothesis cannot be wrong.
Answer: I think it is (C.
Explanation: (C. is more realistic because that is something i would do.