earth exerts a gravitational force on the moon, keeping it in its orbit, the reaction to this force, in the sense of newton's third law is

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Answer 1

According to Newton's third law, the response to this force is, the gravitational force exerted on Earth by the Moon.

What is gravitational force?

Newton's Third Laws are a pair that describe the gravitational attractions of the Earth and Moon. If object A applies a force to object B, consequently object B must apply a force to object A in the opposite direction and of equal strength. Equal and opposing gravitational pulls are exerted by the Earth's gravity on the Moon and the Moon's gravity on the Earth. The Earth's gravity keeps the Moon in an orbit around us. The direction of the Moon's motion is continually changing. This indicates that, despite moving at a constant pace, the Moon is always accelerating due to gravity. Therefore, there is a gravitational force exerted on Earth by the Moon.

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Related Questions

If a person is pushing against a stationary wall with a force of 20 n, what force is being exerted back on the person?.

Answers

If a person is pushing against a stationary wall with a force of 20N, then the force of same magnitude will be exerted back on to the person by the wall.

What is Force?

Force is the external agent which is capable of changing an object's state of rest or motion. A force can be a push or a pull. It has both the magnitude and direction.

According to Newton's third law of motion, forces always acts in equal but opposite pairs. This law can also be defined as for every action, there is an equal but opposite reaction. It means that when a person pushes on a wall with a force of 20N, the wall pushes back on the person with a force equal in strength to the force which is exerted i.e., 20N but opposite in direction.

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The ability of a covalently bonded atom to attract the shared electrons is called.

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Electronegativity is the capacity of a covalently connected atom to draw the shared electrons.

The capacity of an atom to draw the shared electrons from a covalent connection to itself is known as electronegativity. If the electronegativity of the linked atoms is the same, then the shared electrons will be distributed evenly. The electrons in a bond will not be distributed evenly if one of the atoms is more electronegative and hence attracts more of the bond's electrons. The more electronegative atom will "take" the electrons, resulting in two ions and an ionic connection, if the difference in electronegativity is great enough to prevent any sharing of the electrons.

Think of a tug-of-war match. The rope remains in the middle if the two teams are of equal strength. The rope is tugged in the direction of the team that is more powerful. The rope eventually ends up on the side of the stronger team if one team is much stronger than the other. If this happens, the weaker team is no longer able to hold onto the rope. Chemical bonding are comparable to this. The electrons are shared evenly if the electronegativity of the two bonding atoms is equal. The bond's electrons are more drawn to an atom if it has a higher electronegative charge. The electrons won't be shared, leading to an ionic bond, if one atom is much more electronegative than the other atom.

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how fast does water flow from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water? ignore viscosity.

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The speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s

v = √ 2 g h

v = Speed of water

g = Acceleration due to gravity

h = Height

g = 9.8 m / s²

h = 6.2 m

v = √ 2 * 9.8 * 6.5

v = √ 127.4

v = 11.29 m / s

This is derived from an equation of motion,

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Distance

u = 0

v² = 2 a s

v = √ 2 a s

Therefore, the speed of water flowing from a hole at the bottom of a very wide, 6.2- m -deep storage tank filled with water is 11.29 m / s

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a 4.50-kg object moves through a distance of 13.8 m as it slows down uniformly from 22.0 m/s to 13.5 m/s. what is the magnitude of the acceleration of the ball?

Answers

The magnitude of the acceleration of the ball is 25.3 m/s²

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

Calculation:-

v² = u² -2as

13.5² = 22² - 2a × 13.8

1182.25 - 484 = - 27.6a

698.25/27.6 = -a

a = - 25.3 m/s²

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if it requires 5.0 j of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be required to stretch it an additional 4.0 cm ?

Answers

2.5 J work will be required to stretch it an additional 4.0 cm.

Work done is elaborated in such a manner that it consists of each force exerted on the frame and the full displacement of the frame. This block is preceded by using a regular force F. The purpose of this pressure is to transport the body a certain distance d in an immediate course inside the path of the pressure.

The work is stated to be accomplished while force is implemented on an object's movements via a distance within the route of the utility of pressure. Scientists use the joule to measure work. One joule is the same as the paintings achieved by way of a force of one newton to move an item one meter in the path of the force.

Calculation:-

Work done is inversely proportional to the distance,

W₁/W₂ = L₂/L₁

W₂ = W₁L₁/L₂

      = 5 × 2 /4

       = 2.5 J

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. A stone is thrown from ground level vertically upwards with a velocity of 40 m/s.
Find the maximum height to which the stone rises and its total time of flight, neglecting
air resistance.

Answers

Explanation:

maximum height to which the stone can reach is 80 m

h=80

total distance = 2h

= 160 m

The total distance travelled by the stone would be the distance it covered while moving up and then the distance it covered while coming back down.

A ball rolls across a table at a constant speed for 0.62 m. It then falls onto the floor. It takes the ball 0.35 seconds to cover the 0.62 m path, as shown in the drawing below. The table top is 1.2 meters above the floor. Find x the distance that the bail travels horizontally after it eaves the table top.

Answers

Answer:

Explanation:

Missing drawing!

(q011) suppose you are studying a visible-light image of a distant galaxy, and you see a dark lane cutting across the bright disk. that dark line is most likely caused by

Answers

The reason some regions of the Milky Way's disk appear dark is because

stars in this direction are obscured by interstellar dust.

Astronomers have observed many different stars at each stage of their formation process. They have moved away from the Sun over the past 4.5 billion years. Location-to-location density variation increases as the cloud collapses. Once a protostar with a mass of less than 0.08 solar mass is formed, its internal temperature never reaches a sufficient level to initiate thermonuclear fusion. This quirky star is called a brown dwarf and sits between a planet (such as Jupiter) and a star. Coalsacks are clouds of interstellar dust about 600 light-years away that block light from the stars from reaching us. It is a type of celestial object called a dark nebula. The "inside" star that can be seen with binoculars is actually closer than the coal sack itself.

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if the capacitor and inductor in part a are connected in an l-c circuit, what will be the resonance angular frequency of that circuit?

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If the capacitor and inductor in part a are connected in an l-c circuit,  the resonance angular frequency of that circuit isThe energy transferred in an oscillatory manner between the capacitor and inductor in an LC circuit occurs at an angular frequency ω=[tex]\sqrt{1LC}[/tex] ω = 1 L C .

What is Angular frequency?

The length of time it takes an item to complete one oscillation is called the time period.The shortest angle an item makes when spinning in a circle from its starting location to its stopping position is known as the angular displacement.In other terms, you may say that it is the rate at which rotation changes or the pace at which changes in sinusoidal waves occur. It is the angular displacement of a wave element per unit of time. For instance, if you describe an object as having a high angular frequency, you are describing how quickly it turns. The size of the angular velocity is known as the angular frequency.

However, it is a scalar quantity, meaning that it lacks direction.

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calculate the reynolds numbers for the flow of water through a garden hose with a radius of 0.900 cm, when the nozzle is attached to the hose. the flow rate through the hose is 0.500 l/s.

Answers

35820 is Reynold's number which thereby also is greater than 2000 making the flow turbulent

Reynold’s number is the magnitude of inertial forces upon coefficient of viscosity i.e. viscous forces  present in the fluid that is put through movement within the fluid due to various fluid velocities.

Re = 2ρvr / η ------- Equation 1

Here ρ = density of water = 1000 kg/m³

η = coefficient of viscosity of water = 1.005 x 10⁻³

r = 0.9 cm = 0.9 x 10⁻² m

For v

v = Q(Flow rate) / A(area)

Q = 0.5 L/s = 0.0005 m³/s

A = πr² = 3.14 x (0.9 x 10⁻² )² => 2.54 x 10⁻⁴m

v = 0.0005 / 2.54 x 10⁻⁴

≅ 2 m/s

Putting all the values in equation 1

Re = 2 x (10³) x (2) x ( 0.9 x 10⁻²) / 1.005 x 10⁻³

≅ 35820

∴ Re > 2000, The flow is not laminar.

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Laminar flow requires a Reynolds number lower than 2000.

When considering a fluid in motion, the flow of the fluid is referred to as laminar flow if it exhibits a streamlined and smooth flow rather than fluctuations that are erratic and chaotic. In the beginning, Irish innovator Osborne Reynolds categorized fluid flow as turbulent or laminar.

First, use the expression for the fluid's flow rate Q in terms of tube area A and the velocity of the flowing fluid v to calculate the velocity of the fluid v. As a result, the expression comes from,

Q = Av

v = Q/A

The only way to possibly achieve laminar flow through the hose or the nozzle would be to significantly reduce the flow rate to a level below the Reynolds number of 2000.

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You are seated in a bus and notice that a hand strap that is hanging from the ceiling hangs away from the vertical in the backward direction. From this observation, you can conclude that.

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From this observation, You cannot conclude anything about the direction of the velocity of the bus.

The fact that the hand strap moves backward from vertical is assumed.

The direction of the strap depends on the velocity of the bus; if the bus is moving faster in one direction, the strap will move faster in the opposite direction.

The strap is bent backwards by the pseudo-action on it, which is the cause of the movement backwards.

angle of inclination is given by Tan∅  = α/g

where a=bus acceleration

∅ = inclination of strap with respect to vertical

Consequently, we are unable to draw any conclusions about the velocity of the bus direction of motion.

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What minimum height h must the track have for the marble to make it around the loop-the-loop without falling off?.

Answers

The minimum height of the loop without falling it off is 2.7(R-r).

What is height?

height is the measurement of someone or something .

Sol-It is given that capital art Israelis of loop. The loop. Small M. Is the mass of the marble. Small art is radius of the marble. We have to find minimum height edge. The track must have for the marble to make it around the loop. The loop without falling off coming to the solution. We have art is radius of solid marvel. Capital art is radius of circular, loop. Track moment of inertia of this is all in I is equal to two divided by five M. R squared. Thank you lad velocity of the marvel is equal. Do your makeup when the slides down the incline plane and regis the top of the loo. Let this be equation to and let this be equation three gain in potential energy related to center of mass is equal to mg. Multiplied by to capital R minus smaller. Let this be equation four. From law of conservation. Oh Nrg we have Equation one is equal to equation too plus equation three plus equation four substituting we have M G multiplied by H plus R is equal to half M V squared plus half I omega squared plus MG multiplied by two R -R. M G multiplied by H plus R. Is equal to half M B squared plus half. Multiplied by two divided by five M R squared. Omega square plus MG.

Hold square plus M G. Multiplied by two R minus R divide M G. On both sides we have H. Plus art Is equal to seven divided by 10, multiplied by R -R. Plus to r minus R. H plus odd as it will do 2.7 R -1.7 are therefore H is equal. Do 2.7 multiplied by R -R. Hence it can be concluded that height of the track. H is equal to 2.7 multiplied by R -R.

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a resistor dissipates 1.5 w when it is connected to a battery with a potential difference of 12 v. what is the resistance of the resistor?

Answers

Answer:

96 Ω

Explanation:

Power = V^2 / R

1.5     =   12^2 / R

R = 12^2 / 1.5 = 96 Ω

5. What is the formula for Newton’s Second Law?

Answers

Answer:

F=ma ( Force=Mass x Acceleration)

Explanation:

Answer: F = M*A

Explanation:   F= force M= mass of an object A=acceleration

an object is revolving uniformly in a horizontal circle of radius 1.0 m with a speed of 1.0 m/s, calculate its centripetal acceleration. g

Answers

The centripetal acceleration is 1 m/s^2 .

Centripetal force is applied when there is a object revolving in circular path. This path is applied in the opposite direction of the center of the circular path and also this would be perpendicular to the velocity direction.

The value of centripetal force is

Fc = [tex]\frac{mv^{2} }{r}[/tex]

where m is the mass of the object

v is the velocity and r is the radius of the object.

Now as we know that

F = ma

where a is the acceleration

so we can write that

a = v^2/r

putting the values, we get

a = 1^2/1

a = 1/1

a = 1 m/s^2

Hence the centripetal acceleration is 1 m/s^2.

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A stone p,thrown upward with an velocity 20m/s.At the sametime and 30m vertical above, a second stone is released. After what time and at what height do they collide(g=10ms‐²)​

Answers

The time and height at which they collide at 1 second and 15 m respectively when the stone is thrown upward with a velocity of 20m/s.

Let ball A be at the bottom and ball B be at the top.

Assume that you are sitting at B and watching A move.

You (B) appear to be content with yourself. However, both you (B) and A are accelerating in the same general direction. So, the acceleration of A relative to you (B) is 0.

As a result, A will appear to be approaching you uniformly moving at 20 m/s toward you.

A reaches you (B) in 1 second if the distance of 20 meters is divided by that speed.

Now that you have assumed you were stationed at B, you have thought about these motions and time. However, whichever reference frame you use, the time it takes for A to reach B shouldn't vary.

The collision between A and B occurs in 1 second.

Assuming g = 10 m/s2,

B falls freely and travels a distance of 1/2(g)([tex]1^{2}[/tex])=5.

They thus collide at a height of (20-5)m, or 15m, above the earth.

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Brain waves that are lowest in frequency and highest in amplitude are called _____________ waves.

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Brain waves that are lowest in frequency and highest in amplitude are called delta waves.

What are brain waves?

Brain waves such as alpha waves or delta waves refer to the oscillations in the electrical differential of potential from different parts of the brain, which occur as a differential due to the action that an individual is making and it may indicate the brain areas working in a particular activity such as sleep.

Therefore, with this data, we can see that brain waves depend on the differential electrical potential that produces oscillations in the brain in response to the activity of different parts of our brain.

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a 75 kg road bicycle racer rides down the highway from pikes peak. during one stretch of the ride, he descends 5 meters in 12.5 seconds, while accelerating from 35 km/hr to 55 km/hr. assuming rotational kinetic energy and dissipative forces to be negligible, what average power is supplied by the gravitational force during this time?

Answers

The average power supplied by the gravitational force during this time is 21717 Watt.

The mass of the road bicycle racer riding down the highway is 75kg.

The height through which he descends is 5 meters and the time taken by it is 12.5 seconds, the initial velocity of the bicycle is 35km/h(9.7m/s) and the final velocity of the bicycle is 55 km/h(15.27m/s).

The acceleration applied due to earth on the bicycle can be found as,

V²-U² = 2aS

V is the final velocity,

U is the initial velocity,

a is the acceleration created due to earth,

s is the height of the bicycle.

Putting values,

(15.27)²-(9.7)² = 2(a)(5)

a = 13.9m/s².

Now, the work done by the earth on the bicycle is,

W = 75(13.9)(5)

W = 267712.5 Joules.

The power supplied = Work done/time

Power supplied = 21717 Watt.

So, the power supplied by earth is 21717 Watts.

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A body of mass M moving with velocity V collides head on with another body of mass 2M which is initially at rest. Determine the ratio of kinetic energy of colliding bodies before and after collision 

Answers

The ratio of kinetic energy of colliding bodies before and after collision is 9:1

What is kinetic energy?

Kinetic energy refers to be the energy that an object possesses due to its motion. It is defined as the work required to accelerate a body of specified mass from rest to a specified velocity. After the body acquires this energy during acceleration, it retains this kinetic energy as long as the velocity does not change.

Kinetic energy of the body before collision (KE₁): ¹/₂ mv²

Velocity (v') after collision:

v' = [(m₁ - m₂)/(m₁ + m₂)] v

Since, m₁ = 2m

m₂ = m

Substitute the values in the formula:

v' = [m/3m]v

v' = v/3

Now, kinetic energy after collision (KE₂):  ¹/₂ mv'²

=  ¹/₂ m(v/3)²

=  ¹/₂ m(v²/9)

Now the ratio of kinetic energies:

KE₁ / KE₂ = (¹/₂ mv²) / (¹/₂ m(v²/9))

KE₁ / KE₂ = 9/1

Or 9:1

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predict how you think two inductors in series will act as an equivalent inductor. will they add together, add as 1/l or some other relationship?

Answers

The total inductance of inductors connected in series is equal to the sum of the inductances of the individual inductors.

Briefing:

The amount of voltage dropped across an inductor for a specific rate of current change through it is the undisputed indicator of inductance.

The total voltage reduced as a result of a change in current will be additive with each inductor if inductors are linked in series (sharing the same current and experiencing the same rate of change in current), resulting in a higher total voltage than either of the individual inductors alone. Greater inductance results from higher voltage at the same rate of current change.

As a result, the overall inductance of a series of inductors is greater than the sum of the inductances of each individual inductor. Similar to how series resistances are calculated, the series total inductance formula takes the same form:

L(total) = L1+L2+L3….Ln

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what is the total magnification of a microscope with two lenses when one lens has a magnification of 10x, and the other lens has a magnification of 30x?

Answers

The total magnification of a microscope or set of lenses is 300x.

Magnification is the process of enlarging an object's image in relation to its size using a mirror, whether it be convex or concave.

There is no unit for magnification. The fact that it is a measurement ratio is the cause. It is the proportion of an object's size to that of an image.

Calculating the overall magnification is straightforward math once each lens's specific magnification is known. Add the combined magnification of the lenses.

Given

magnification of the first lens, l1 =  10x

magnification of the second lens, l2 =  30x

Total magnification = product of the magnification of all the lenses.

Thus, to compute the total magnification of a microscope, multiply the two lenses' magnification powers.

Consequently, the lenses' combined magnification will be - 10*30.

Thus the total magnification of a microscope or set of lenses is 300x.

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a ferris wheel with a radius of m is rotating at a rate of one revolution every minutes. how fast is a rider rising when his seat is m above ground level?

Answers

Using the concepts of Ferris wheel, we go that the speed of the rider is 2πm /min above ground level if a Ferris wheel with a radius of m is rotating at a rate of one revolution every minutes

The height of the rider at any time  is (x + m) .

From the right triangle

sinθ = x/m ---------------(eq1)

Differentiating both sides with respect to t, we get:

d(sin)/dt= [(1/m)×(dx/dt)]

Using chain rule,

cosθ×(dθ/dt)= [(1/m)×(dx/dt)] -------------(eq 2)

When the height of the rider is  1m.

X = m - m

Then the value of x is  0.

Put the value of x in the equation (I)

Sinθ = 0/m = 0

We need to calculate the value of (dθ/dt)

A Ferris wheel makes 1 revolution per minute.

 (dθ/dt)= 2π

Now, substitute the value of sinθ and  (dθ/dt) in equation (II)

√1-0 x 2π= [(1/m)×(dx/dt)]

dx/dt =2πm

Hence, if a Ferris wheel with a radius of m is rotating at a rate of one revolution every minutes, the speed of rider rising when his seat is m above ground level is to be 2πm meters /sec.

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11 How far away does a ball land that rolls off a 2 m high table rolling at 9 m/s
a) 5.75 m
b) 10.25 m
c) 13.75 m/s
d) none of the above

*Please Show Equation*
Thank You!

Answers

Answer:

H = 1/2 g t^2      time to fall H

t = (2 H / g)^12 = (2 * 2 / 9.80)^1/2 = .639 sec

Sx = Vx * t = 9 m/s * .639 s = 5.75 m      horizontal distance traveled

3. A luxury ship cruises at Miami, Florida at 150 mph and is brought to a stop uniformly by a motor
boat in 500 ft. Find the (a) acceleration and (b) the time required to stop.
Given:

Answers

a) Acceleration is calculated as 29.54 m/s^2

b) Time required to stop is calculated as 2.27 seconds

What is acceleration?

The rate of change of the velocity of an object with respect to time is called as acceleration and it is a  vector quantity. Acceleration is the rate at which velocity changes with time in terms of both speed and direction. An object moving in a straight line is accelerated if it's speed goes up or down.

Given, speed = 150 mph

1mph = 0.447 m/s

150mph = 67.056 m/s

and distance = 500 ft

1ft = 0.30 m

500 ft= 152.4 m

time=  distance / speed

= 152.4/ 67.056

=  2.27 sec

Acceleration= velocity/ time

= 67.056/2.27

Acceleration = 29.54 m/s^2

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Is rebel a synonym or antonym of the word conform

Answers

‘Rebel’, is the antonym of the word ‘Conform’.

if the car speeds up at a steady 1.7 m/s2 , how long after starting is the magnitude of its centripetal acceleration equal to the tangential acceleration?

Answers

Using the theories of centripetal acceleration, we got that 9.388 sec after the starting  magnitude of its centripetal acceleration equal to the tangential acceleration.

We know that centripetal acceleration is given by =v²/r,

where v is the velocity along curved road and r is the radius of the curved road.

We have from the question, Acceleration (a) = 1.7m/sec²

Radius(R) = 150 m

Therefore,  

a=v²/r

=>1.7=v²/150

=>v²=1.7×150

=>v²=255.0

=>v = 15.96 m/sec

Now, we know that the formula for tangential acceleration is the product of acceleration and its time ,which means

v = a x t

15.96 = 1.7 x t

t = 9.388 sec.

Hence, if the car speeds up at a steady 1.7 m/s2 , the time  after starting when the magnitude of its centripetal acceleration equal to the tangential acceleration is 9.388 sec

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A 1600kg car is traveling over a hill that has a radius of curvature of 25m. The car is slowing down as it goes over the hill. It slows down at a constant rate from a speed of 25ms to a speed of 10ms over a distance of 50m ending at the top of the hill. The net acceleration of the car at the top of the hill is most nearly.

Answers

The net acceleration of the car at the top of the hill is 6.6 m/s²

According to the question,

Mass of the car, m = 1600 Kg

Final speed of the car = 10 m/s

Distance covered by the car, d = 50 m

Radius of curvature of the hill, r = 25 m

Initial speed of the car, u = 25 m/s

The acceleration of the car is calculated by applying the third equation of motion,

v² = u² + 2as

where, v is the initial speed

            u is the final speed and

            a is the acceleration of the car

2as = v² - u²

a = [tex]\frac{v^{2-u^{2} } }{2a}[/tex]

a =[tex]\frac{10^{2}- 25^{2} }{2 X 50 }[/tex]

a =  - 5.25 [tex]m/s^{2}[/tex]

The centripetal acceleration of the car at the top of the hill is given as,

[tex]a_{c} =\frac{v^{2} }{r\\}[/tex]

[tex]a_{c} =\frac{10^{2} }{25} \\a_{c = 4m/s^{2}[/tex]

The net acceleration of the car at the top of the hill is calculated as;

[tex]a_{net} = \sqrt{a^{2} } +a_{c^{} }[/tex]

[tex]a_{net} = \sqrt{-5.25} ^{2} - 4^{2}[/tex]

      = 6.6[tex]m/s^{2}[/tex]

Thus, the net acceleration of the car at the top of the hill is 6.6 m/s²

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How can planetary scientists estimate the ages of the outflow channels and valley networks on mars?.

Answers

Planetary scientists estimate the ages of the outflow channels and valley networks on mars by craters

Due to impact of meteorite, volcanic activity, or an explosion , there occurs a depression at a certain area , that is called crater .

Ages of the outflow channel and valley network can be estimated by counting the number of impact craters. Because of the almost constant  rate at which impacts have occurred in the solar system .

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As you hold your leg in this position, the upper leg exerts a force on the lower leg at the knee joint. What is the magnitude of this force?

Answers

The upper leg applies the exact same amount of force on the knee as the tendon applies on the lower leg. f = 215.6 N

This is only logical as the net result of these forces is the canceling out and the leg staying stable in its position.

The magnitude of a force is how much it accelerates the object it acts on and is represented by a scalar. Size can also be viewed as a strength. Riding a bicycle is a simple example of force magnitude. It is a simple machine that converts human-supplied energy into kinetic energy.

The force exerted on the pedal results in the formation of energy. Work is done to convert this energy into kinetic energy and move the bicycle forward. Force magnitude describes the sum of all forces acting on an object. If all forces act in the same direction the force magnitude increases. If forces act on an object in different directions the magnitude of the force will decrease.

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how much work must be done on a particle with a mass of m to accelerate it from rest to a speed of 0.089 c ? express your answer in terms of mc2 .

Answers

0.14 mc² work is done on a particle with a mass of m to accelerate it from rest to a speed of 0.089 c

Define kinetic energy.

A particle or an item that is in motion has a sort of energy called kinetic energy. When an object undergoes work, which involves the transfer of energy, by exerting a net force, the object accelerates and thereby gains kinetic energy.

kinetic energy of mass particle: KE = mc²( γ- 1 )

here γ is Lorentz constant

γ = [tex]\frac{1}{\sqrt{1 - \frac{v}{c}^{2} } }[/tex]

γ = [tex]\frac{1}{\sqrt{1 - \frac{0.089c}{c}^{2} } }[/tex]

γ = 1.14

here,

particle start from rent so initial KE = 0

and final KE = mc²(1.14 - 1 )

final KE = 0.14mc²

so,

work done to increase speed of particle

W = final KE - initial KE

Work = 0.14 mc²

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