Answer:
to the substance being heated
What is occurring in the umbra?
A. a total solar eclipse
B. a total lunar eclipse
C. a partial lunar eclipse
D. a partial solar eclipse
Answer:
A. a total solar eclipse
Explanation:
During a solar eclipse,the moon comes between the sun and Earth, casting its shadow over the Earth
A 0.5 kg cheeseburger is lobbed at a particularly unhappy customer with a force of 10 N.
While it is being thrown, what is the acceleration experienced by the cheeseburger?
Answer in units of m/s2
What is benford's law.
Answer:
Known variously as the Newcomb–Benford law, the law of anomalous numbers, or the first-digit law, Benford's Law is the observation that the first digit in many real-world collections of numerical data will be tiny, as shown by the example of the first-digit law.
Explanation:
Hope it helps:)
The wheel of bicycle has a radius of 25cm.what will be the magnitude of the angular displacemant in radian and revolution respectively,when the wheel has rolled a distance of 350cm on straight level road?
What is the kinetic energy of a 2,000-kg boat moving at 5.0 m/s?
Answer:
25kJ
Explanation:
K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2
= 25 x 10^3 J = 25kJ
how do i do this question in science?
simple subtract and ummmmmm.....
What types of energy do you acquire when you eat a bowl of hot vegetable soup?
Answer:
you need kinetic energy because it is the energy that is used when In motion
The type of energy that one acquire when you eat a bowl of hot vegetable soup is chemical energy.
What is chemical energy?Chemical power the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.
Some of the heat energy needed for a reaction to continue can be stored as chemical energy in newly created bonds.
Food particles go through a chemical reaction that releases chemical energy when we eat it. The body then uses this energy to carry out its regular tasks.
As a result, when you eat a cup of vegetable soup, you also consume the chemical energy it contains.
Thus, the answer is chemical energy.
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Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
throwing a ball up initially has a lot of kinetic energy because it is moving upwards ( kinetic energy is energy which a body possesses by virtue of being in motion.) this all then get converted to gravitational potential energy, and for a moment it is stationary before it begins to fall again. by the time it has returned again, all the gravitational potential energy has turned back into kinetic.
What is carbon dating?
Answer:
Im pretty sure its number 2
Explanation:
The first one a scientific way of finding the age of something that is very old (such as a dinosaur bone) by measuring the amount of certain forms of carbon in it
How to find density of a gas.
Answer:
Subtract the mass of the cylinder from the mass of the cylinder when it contains gasoline. This is the mass of the gasoline. Divide this figure by the volume, 100 ml, to get the density.
How many sulfur atoms are there in 25 molecules c4h4s2?.
What happens if you drop a chicken wing from the top of the Eiffel Tower
Answer:
I think it will brake or squashed
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)
(a) The normal force on the block is 50.92 N.
(b) The horizontal force on block keeping it in equilibrium is 29.4 N.
The given parameters;
mass of the block, m = 6 kgangle of inclination, θ = 30.0°The normal force on the block is calculated as follows;
[tex]F_n = W \times cos(\theta)[/tex]
where;
W is the weight of the block[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]
The horizontal force on block keeping it in equilibrium is calculated as follows;
[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]
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A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?
Answer:
15 N :D
Explanation:
The size of the drag force on this object falling at a constant speed is determined as 15 N.
Drag force on the objectThe drag force on the object is determined by calculating the net force on the object;
F(net) = W - D
where;
W is weight of the objectD is the drag force of airma = W - D
at constant speed, acceleration, a = 0
0 = W - D
W = D
15 N = D
Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.
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Which of the following is NOT a part of Earth’s atmosphere?
1. mesosphere
2. troposphere
3. asthenosphere
4. stratosphere
Answer:
3
Explanation:
It is part of the Earth's mantle
Answer:
it is the astenospere number 3
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation:
28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?
Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
Physics - Electricity and Magnetism
A ceiling fan operates at three speeds, using 120 V of electricity from the wall. At low speeds, it uses 0.25 A. Calculate the resistance needed to generate that current. Then in 1-2 sentences, describe how the resistance would change at medium and high speeds if larger currents are needed at those speeds. Your answer should include the calculated resistance and a sentence describing your reasoning.
Answer:
480 Ohms for the calculations
Explanation:
For the calculations:
V = 120 and I = 0.25
V = IR
R = V/I
R = 120/0.25
R = 480 Ohms
For the sentences, I am so sorry, I do not have them yet!
I. The resistance which is needed to generate a current of 0.25 Ampere in the ceiling fan is 480 Ohms.
II. Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.
Given the following data:
Voltage = 120 VoltsCurrent = 0.25 AmpereTo calculate the resistance needed to generate that current, we would apply Ohm's law:
Ohm's law states that at constant temperature, the current flowing through an electrical circuit is directly proportional to the voltage (potential difference) applied across the two terminals of the electrical circuit and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex]V=IR[/tex]
Where;
V is the voltage measured in Volts.I is the current measured in Ampere.R is the resistance measured in Ohms.Making R the subject of formula, we have:
[tex]R =\frac{V}{I}[/tex]
Substituting the given parameters into the formula, we have;
[tex]R=\frac{120}{0.25}[/tex]
Resistance, R = 480 Ohms
Since current is inversely proportional to the resistance in the electrical circuit, an increase in the current (larger currents) flowing into the electrical circuit of the ceiling fan would cause the resistance to decrease in magnitude at medium and high speeds.
In conclusion, the larger the current, the lower the resistance would be at both medium and high speeds.
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I rode my bicycle to grandmother's house at 6 km/h in a flat road for 5 min before reach a hill. I went at 2 km/h up the hill for 3minutes. I met a friend and stopped to talk for 5 minutes. I went on at 2 km/h to my grandmother's house. Draw (plot) the v against t graph for this motion.
The graph can be plotted based on the given information which are given
in pairs (velocity and time), and which the coordinate pairs are formed.
Please find attached the required v against t graph created with MS ExcelReasons:
The given data are presented in a tabular form as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 - 5 &6 \\5 - 8&2\\8 -13&0&\\13- &2&\end{array}[/tex]
The velocity time graph can be plotted using the above table values on
MS Excel using the above table elaborated as follows;
[tex]\begin{tabular}{|c|c|c}\underline{Duration (Minutes)} & \underline{Speed (km/h)}\\0 &6 \\5&6\\5 &2\\8&2\\8&0\\13&0&\\13 &2&\end{array}[/tex]
The attached graph can then be created using the Insert → Chart menu
after selecting the data above inputted in the spreadsheet button on MS
Excel.
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Which type of forces creates contact between surfaces?
Answer:
Frictional Force: Frictional force is the force caused by the relative motion of two surfaces that come into contact with each other.
what is the direction of the rotational velocity vector of the jar lid when you open a jar of pickles?
Answer:
Explanation:
The rotational velocity vector is directed away from the jar
jxjxjfjfjfknfnfnnfmfgmmmmmmmm(xmpqitexsy.)
Answer:
Hi! can you give me BRAINLIEST ANSWER please.
I would appreciate it
I need help quickly pls
Answer:
Ok I'm not 100% on this one but, try 3 lifes sorry if u get it wrong D:
Explanation:
1. Explain why the energy of photoelectrons in XPS depends on energy of x-ray source, while energy of Auger electrons does not.
Answer:
Only part of the incident energy from an X-ray source may be used by the ejected electron (some of the energy can be used by the exiting photo electron and some of the energy by the exiting photon).
Auger electrons depend on the energy difference between energy levels of an atom and are fixed - so the ejected electron will have a fixed energy depending on the difference of energy levels of the atom. The Auger effect is called a "radiationless" transition because no radiation is detected outside of the atom.
2Cu + 02 —> 2Cuo
In the equation above, what is the
coefficient of the oxygen molecule?
A) O
B) 1
C) 2.
D) 4
Answer:
C
Explanation:
Two 4 kg blocks hang from a rope that passes over two frictionless pulleys . What is the tension in the horizontal portion of the rope if the blocks are not moving and the rope and the two pulleys have negligible mass?
The tension in the horizontal portion of the rope provided the blocks are not moving and the rope has negligible mass is 40 N
The tension in the rope is a pulling force that acts on the rope when the mass of 4kg is placed on each side of the two frictionless pulley.
According to Newton's second Law;
Force = (Tension) = mass × acceleration due to gravity
∴
We can say:
Tension = 4kg × 9.81 m/s²
Tension = 39.24 N
Tension = 40 N (to the nearest whole number)
Therefore, we can conclude that the tension in the horizontal portion of the rope is 40 N
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A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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how is pure salt obtained from the sea water ?describe in brief
Answer:
Evaporation
Explanation:
Evaporation
Answer:
Salt from sea water is obtained by the process of evaporation. ... The sea water evaporates due to the sun's heat and solid salt is left behind. The left salt is collected and refined to get purified salt. Hence, salt is obtained from sea water by evaporation.