Ethanol (C2H5OH) reacts with oxygen gas in a combustion reaction. How many liters of carbon dioxide gas are produced at STP when 375 mL of a 75.0% ethanol solution by mass with a density of 1.22 g/mL reacts with excess oxygen?

Answers

Answer 1

The volume of carbon dioxide produced when 375 mL of a 75.0% ethanol solution by mass with a density of 1.22 g/mL reacts with excess oxygen is  667.52 L.

We are told in the question that the solution contains 75.0% ethanol solution by mass.

Hence;

Density of solution = mass/volume

mass = Density × volume = 1.22 g/mL × 375 mL = 457.5 g

Mass% = mass of solute/ mass of solution × 100

Mass of solute = x

Mass of solution = 457.5 g

Mass percent = 75.0%

Substituting values;

75 = x/457.5 + x × 100

75/100 = x/457.5 + x

0.75(457.5 + x) = x

343.125 + 0.75x = x

343.125  = x -  0.75x

x = 343.125/0.25

x = 1372.5 g

The equation of the reaction is;

C2H6O(l) + 3O2(g) → 2CO2(g) + 3H2O(l)

Number of moles of ethanol =  1372.5 g/46 g/mol = 29.8 moles

From the reaction equation;

2 moles of ethanol produces 2 moles of carbon dioxide

29.8 moles of ethanol also produces 29.8 moles of carbon dioxide

If 1 mole of carbon dioxide occupies 22.4 L

29.8 moles of carbon dioxide occupies 29.8 moles × 22.4 L/ 1 mole

= 667.52 L

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Explanation:

This is the correct answer because you know there is 11 oxygen moles in 1 mole of sugar so using dimensional analysis you can solve it. You start will 11 moles of oxygen, and multiply by Avogadro's number(6.022 x 10 ^23) to get the amount of atoms. I don't see it as an answer, but I am confident in this, so I would ask your teacher specifically.

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Answers

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Explanation:

0.57mol HCl         1mol H2          

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The balanced chemical displacement reaction is given as:

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HOW TO CALCULATE MASS:

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Answers

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Temperature should always be in K not in ⁰C or ⁰F

To convert from C to K use

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Enter your C value in the ( ⁰C ) and you can get K

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