Evaluate 3a-5b when a=-3 and b=-2

Answer:

15

Step-by-step explanation:

so if its a 6 faced dice then there is a 3/6 numbers greater than 3. which simplifies to 1/2. 30(1/2)= 15

The graph is attached with the answer.

When two algebraic expressions are equated using an inequality operator , The statement formed is called In equality.

The given Inequality is 2x + y ≤ 2

in slope intercept form can be written as

y ≤  -2x +2 , here slope is -2 and intercept is 2

As an equation it will be

y = -2x +2

x         y

0 ,       2

1 ,       0

2         -2

The graph is plotted

The area is shaded and the test for the origin is applied , and it lies in the shaded region.

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The graph of x >2 is attached below

Clearly, the graph of x> 2 could be area beyond 2 on positive X axis

What is graph?

The graph is a demonstration of curves  which gives the relationship between x and y axis.

The question seems to be incomplete, because options are missing.
so the option can be of several graphs.

Thus, The correct Graph of x >2 has been attached below.

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Composite functions occur when we take two functions and input one into the other as x.

Example:

[tex]f(x) = 2x[/tex]

[tex]g(x) = 3x^2[/tex]

[tex](f\circ g)(x)=f(g(x))[/tex]

[tex](f\circ g)(x) = 2(3x^2)[/tex]

We're given:

To find [tex](f\circ g)(x)[/tex], input g into f as x:

[tex]f(x)= 3x +2[/tex]

[tex](f\circ g)(x)=3(x^2+1) +2\\(f\circ g)(x)=3x^2+3 +2\\(f\circ g)(x)=3x^2+5[/tex]

[tex](f\circ g)(x)=3x^2+5[/tex]

The mean will be 10.08 and the standard deviation will be 1.27.

The complete question is given below:-

The Mountain States Office of State Farm Insurance Company reports that approximately 84% of all automobile damage liability claims were made by people under 25 years of age. A random sample of twelve automobile insurance liability claims is under study.

Find the mean and standard deviation of this probability distribution.

For samples of size 12, what is the expected number of claims made by people under 25 years of age?

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

Standard deviation is defined as the amount of variation or the deviation of the numbers from each other.

Given that:-

The mean will be calculated by the formula below:-

Mean = [tex]\mu[/tex] = np = 12 x 0.84 = 10.08

The standard deviation will be calculated as:-

Standard deviation = [tex]\sqrt{npq}[/tex] = [tex]\sqrt{12\times 0.84\times 0.16}[/tex] = 1.27

Therefore the mean will be 10.08 and the standard deviation will be 1.27.

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Answer:

k(magnitude of vector a).vector a

Step-by-step explanation:

Given question is based on vectors so,

vectors :- Vectors in math is a geometric entity that has both magnitude and direction. Vectors have an initial point at the point where they start and a terminal point that tells the final position of the point. Various operations can be applied to vectors such as addition, subtraction, and multiplication.

To produce an another vector form a given vector we increase its magnitude only not its direction as we have to produce another vector from a given vector.

as its clear from the graph given in the question that only the magnitude of  vector a is increased to produce another vector b

hence we multiply any constant ('k') with the magnitude of vector a to increase its magnitude.

and finally multiply the increased magnitude with the vector 'a' itself.

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Based on the characteristics of the function and the image generated by the graphing tool, we conclude that the first choice represents the function [tex]y = \sqrt{x} - 4[/tex].

In this question we have a radical function ([tex]f(x) = \sqrt{x}[/tex]) translated vertically 4 units in the -y direction. The domain of the function is [0, + ∞). A quick and efficient approach consists in graphing the function and comparing with each image to determine the right choice.

We present the graph description in the image attached below and we conclude that the first choice represents the graph of the function.

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a) When x = -2, g(x) = 5.

b) When x = -4, g(x) = 7.

c) When g(x) = 6, x = -3

d) When g(x) = -1, x = 4

Answer: B -60

Step-by-step explanation: When you plug in -60 into the equation it all equals out into -12 = -12, which is true. All of the other solutions don't work.

Answer:

B. x = -60

Step-by-step explanation:

8 + x/3 = 1/6 (x-6) - 1

Multiply both sides by 6.

48 + 2x = x - 6 - 6

x = -12 - 48

x = -60

Answer:

0 m/s

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

In asin(bx - c) + d, a is the amplitude. In this case, it's 2.

Brainliest, please :)

The function that includes the given points of (0,−2),(5,13),(−2,−8),(4,10) is the second encircled option by the top right in the image attached.

Note that all function of  (0,−2),(5,13),(−2,−8),(4,10)  can be seen as all the brackets are placed in the form (X, Y), Y=P(x)

In the case above, how we arrived at the answer, you have to fill up the X's in the brackets using the X's in the Options.

Then since P(x) is the number one see in place of Y in the brackets, then that the top Right option is correct as it has −2.

Therefore, The function that includes the given points of (0,−2),(5,13),(−2,−8),(4,10) is the second encircled option by the top right in the image attached.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\texttt {\:Thomas's age = 44 years } [/tex]

[tex]\texttt {\:Hulian's age = 36 years } [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Assume Thomas's age be ' x ' } [/tex]

[tex] \textsf{and that of Huilan's age be y } [/tex]

[tex] \texttt{we have two conditions :} [/tex]

[tex]\qquad \tt \rightarrow \:y = x + 8[/tex]

it can be simplified as : -

[tex]\qquad \tt \rightarrow \:y - x= 8 \: \: \: \: \: \: \: \: \: - (1)[/tex]

[tex] \texttt{Next condition } [/tex]

[tex]\qquad \tt \rightarrow \:x + y = 80 \: \: \: \: \: \: \: - (2)[/tex]

`` Add both equations ``

[tex]\qquad \tt \rightarrow \:y - x + x + y = 8 + 80[/tex]

[tex]\qquad \tt \rightarrow \:2y = 88[/tex]

[tex]\qquad \tt \rightarrow \:y = 44[/tex]

[tex] \large \textsf{For x :} [/tex]

[tex]\qquad \tt \rightarrow \:y - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:44 - x = 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 44 - 8[/tex]

[tex]\qquad \tt \rightarrow \:x = 36[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

[tex]\fbox {36 years old}[/tex]

Step-by-step explanation:

Let :

⇒ Age of Huilan = x

⇒ Age of Thomas = x - 8

Then :

⇒ x + x - 8 = 80

⇒ 2x = 88

⇒ x = 44

Thomas's age :

⇒ x - 8

⇒ 44 - 8

⇒ 36 years old

The range, the mean, and standard deviation are mathematically given as

Participants ranged in age from 4 to 26.24 ( M = 26.24 , SD = 8.04 ). Option D.

Given the data presented below the given

A look at the result shows that the lowest and highest values are between 1s and 58, with a mean and standard deviation of 26.10 and 8.90, respectively.

Participants' ages varied from 18 to 58 (m-26.14, std dev = 8.01), hence option (d) is accurate.

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Answer:

(3, 0) and (−1, −8)

Equation's:

2x − (x² − 9) = 6

2x - x²  + 9 = 6

-x² + 2x + 9 - 6 = 0

-x² + 2x + 3 = 0

x² - 2x - 3 = 0

x² - 3x + x - 3 = 0

x(x - 3) + 1(x - 3) = 0

(x + 1)(x - 3) = 0

x = -1, x = 3

If x = -1, then y = (-1)² - 9 = -8

If x = 3, then y = (3)² - 9 = 0

(x, y) = (-1, -8), (3, 0)

Answer:

A maybe?

Step-by-step explanation:

by looking at the graph you can see there are two points with one being at (0, 3) (given) and the other being at (1, 1) (by looking at the graph). You can use the slope formula (y2 - y1) / (x2 - x1) which gives you the slope.

Plug Values In:

(1-3) / (1-0) = -2/1 = -2

slope of f(x) = -2

slope of g(x) = -7 (slope-intercept form y=mx+b where m is the slope and b is the y-intercept)

I'm honestly not quite sure what it means by greater than since technically the slope of f(x) is greater than the slope of g(x) but does it mean how much it's changing by in which case the sign doesn't matter. Although I'm just going to assume it purely means the value in which case A is true.

Answer:

y= 5x+165

Step-by-step explanation:

the slope is 5, so five per day, plus the y-intercept, or when x = 0

Brainliest pls

Answer:

A. 15

Step-by-step explanation:

Hypotenuse = 22

Since the two angles other than the 90° are both

45° , it means that the two legs of the right triangle are of equal length.

So, (x)²+ (x)² = 22²

2x² = 22²

x² = 484/2

x² = 242

x = √242

x = 15.55

x ≈ 15

Answer:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

=4.08 /2 = 2.04 check

Answer:                                                                                                                 I HOPE THAT MY ANSWER WILL HELP U        

Step-by-step explanation:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

=4.08 /2 = 2.04 check

Answer:

[tex]A) \ x=-1 \ ^ +_-\frac{\sqrt{13} }{\sqrt{6}}.[/tex]

Step-by-step explanation:

if to solve the given equation, then

D=6²+42=78;

[tex]\left[\begin{array}{ccc}x=\frac{-6-\sqrt{78}}{6} \\x=\frac{-6+\sqrt{78}}{6} \end{array} \ = > \ \left[\begin{array}{ccc}x=-1-\sqrt{\frac{13}{6} } \\x=-1+\sqrt{\frac{13}{6} } \end{array}[/tex]

Answer:

11

Step-by-step explanation:

for each full cup of sugar, you need 3 one-third measuring cups.

we have 3 full cups so 3×3=9

and another 2 for the 2/3, 9+2=11

so a total of 11 scoops

An opportunity cost of 9 percent, is $42.

We have given that,

The present value of $100 is to be received 10 years from today,

assuming an opportunity cost of 9 percent,

present value =$100

N=10 years

I/y=9

PV= FV/(1+r)^n

Where FV is the future value.

Use the given values in the formula we get,

Therefore the correct answer is 42.

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Answer:

[tex]\boxed {t < 15}[/tex]

Step-by-step explanation:

Given :

⇒ t - 3 < 12

Add 3 to each side :

⇒ t - 3 + 3 < 12 + 3

⇒ t < 15

Answer: t < 15

Step-by-step explanation:  

rearrange the terms                                       t - 3 < 12

calculate the sum or difference                    t < 12 + 3

answer                                                             t < 15                            

The dimensions of the garden with the largest area she can enclose are given by 24*14 square yards.

The area (A) of the rectangle with length L and Width W is given by,

A=L*W

The maximum of [tex]y=ax^2+bx[/tex] occurs at x = -b/2a

Let the length and width of the garden be L and W respectively.

Now let my friend use cedar fencing for one width and cheaper metal fencing for rest sides.

Rate of cedar fencing is $17/yard

Then she has to pay for cedar fencing = 17W

rate of cheaper metal fencing is $7/yard

Then she has to pay for metal fencing = 7W+7*2L = 7W+14L

Then according to condition,

17W+7W+14L = 672

24W+14L = 672

12W+7L = 336

7L = 336-12W

L = (336-12W)/7

Then the area of the rectangular garden is given by,

A = L*W

[tex]A=\frac{336-12W}{7}\times W\\A=-\frac{12}{7}W^2+48W[/tex]

So here a = -12/7 and b = 48

Then maximum of W occurs at,

W = -48/(2*(-12/7)) = (48*7)/(2*12) = 336/24 = 14

Then maximum width = 14 yards

then length (L) = (336-12*14)/7 = 168/7 = 24 yards

Hence the dimensions with the leargest area she can enclose is given by = 24 * 14 square yards.

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Parent function

Now look the transformations

x is changed and shifted 6 units right

Then

Horizontally Streched with a factor of 5

Answer:

B)  The graph of k(x) is vertically stretched by a factor of 5 and shifted 6 units right.

Step-by-step explanation:

Translations

For a > 0

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]y=a\:f(x) \implies f(x) \: \textsf{stretched parallel to the y-axis (vertically) by a factor of}\:a[/tex]

[tex]y=f(ax) \implies f(x) \: \textsf{stretched parallel to the x-axis (horizontally) by a factor of} \: \dfrac{1}{a}[/tex]

Given functions:

[tex]f(x) = x^2[/tex]

[tex]k(x) = 5(x - 6)^2[/tex]

Parent function:  [tex]f(x) = x^2[/tex]

Translated 6 units right:  [tex]f(x-6)=(x-6)^2[/tex]

Then stretched vertically by a factor of 5:   [tex]5f(x-6)=5(x-6)^2[/tex]

[tex]\implies 5f(x-6)=5(x-6)^2=k(x)[/tex]

Therefore, the graph of k(x) is vertically stretched by a factor of 5 and shifted 6 units right.

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Answer:

56

Step-by-step explanation:

so 7 appetizers times 8 main courses

I do a easy trick where I multiple so

7×8=56

Answer:

2.5 pi

Step-by-step explanation:

Comment

If you were trying to get the area of a whole circle, you would use

Area = pi r^2

You have to modify the formula to show that just part of the circle has an area that you are interested in.

The new formula is

Area = (theta/360) pi r^2

Givens

r = 30 cm

theta = 100

Solution

Area = (100 / 360) * pi * r^2       Substitute the givens into this formula

Area = (5 / 18) * pi * 3^2              Expand

Area = (5 / 18) * pi * 9                  Cancel 9 into 18

Area = 5/2 * pi

Area = 2.5 * pi

Answer:

No.

Step-by-step explanation:

This problem in scientific notation would be 9.3 * 10^10.