Evaluate the integral below by interpreting it in terms of areas. In other words, draw a picture of the region the integral represents, and find the area using geometry.-5 ∫5 sqrt(5^2−x^2) dx my lower limit is -5 and my upper is 5. How do I solve this problem? do i graph this equation and use left or right approximation?

Climate change is causing an increase in air temperature, sea surface temperature, sea level, ocean acidity, and snow cover, but not humidity.  

Humidity

Climate change is the long-term change in average weather patterns, and is caused by increased atmospheric concentrations of greenhouse gases. Earth's vital signs that have been on the rise due to climate change include air temperature, sea surface temperature, sea level, ocean acidity, and snow cover. Humidity is not one of these vital signs, and actually is expected to decrease in some areas due to climate change.

Climate change is causing an increase in air temperature, sea surface temperature, sea level, ocean acidity, and snow cover, but not humidity.

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The formula for the bill total for the week by summing the daily bill amounts is  (=sum(B25:H25)).

Numerous common mathematical operations are carried out by the Excel Math Functions, such as fundamental arithmetic, conditional sums and products, exponents and logarithms, and trigonometric ratios. Please take note that the Excel Statistical Operations and Excel Engineering Functions categories also offer other math-related Excel functions.

Given finding the  bill total for the week in cell B26

To sum the daily bill amounts, use Excel's Sum function, which is a pretty simple mathematical procedure. You can manually input the sum function by typing (=sum) in the field designated for the sum, after which you provide the parameters (=sum(B25:H25)). When you hit "enter," the outcome is presented immediately. By selecting the Sum Function from the Ribbon or by hitting Alt + =, this can also be done automatically.

Hence the formula is  (=sum(B25:H25)).

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Countless pointy corners are called cusps. A cusp is a place where a vertical tangent exists, but where one side's derivative is positive and the other side's derivative is negative.

The above example of a paradigm is y=x23. The derivative's upper limit as you move left toward zero is. As you move toward zero from the right, the derivative's limit is +. A vertical tangent exists at x=0.

Cusps have vertical tangents (when describing functions). A vertical tangent, however, is not a cusp by itself. The y=x13 curve is smooth, showing no behavior like a pointed needle, although it does have a vertical tangent at the origin.

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Answer: -24

Step-by-step explanation:

⇒4(-8)+8

in such questions, first solve the bracket. In this question there is only a single term within the bracket, -8. Brackets usually mean multiplication. So we multiply 8 by 4 to get 32. Now since we need to give 32 a sign as well, so in case of multiplication we multiply the sign of 8 and 4 together i.e negative and positive respectively. Negative positive multiplied give us negative. Therefore the sign of 32 will be negative.

⇒- 32 + 8

now again we are stuck with the sign issue. Notice that we have both a negative and a positive sign as well. How do we know if we are supposed to add or subtract? In order to decide which operation we apply on the two numbers, we first multiply the signs. Negative positive multiplied give negative, therfore we will do subtraction. 32 subtracted from 8 gives 24. Now again we are supposed to give 24 a sign. Unlike in multiplication, when we do addition or subtraction, instead of multiplying the signs to give the result a sign, we look for the sign of the greater operand, i.e 32, because 32 is greater than 8 and has a negative sign, so we give 24 a negative sign. H

⇒-24 answer

⇒4(-8)+8

⇒- 32 + 8

⇒-24 answer. hope the helps ...

The mean of the data is 31. Then the mean absolute deviation of Leo's test scores will be 9.

It is the average distance between each data point and the mean.

The mean absolute deviation is given as

[tex]\rm MAD = \dfrac{\Sigma _{i = 1}^n|x_i - \mu|}{n}[/tex]

The data is given below.

18, 26, 38, 42

The mean of the data is given as,

μ = (18 + 26 + 38 + 42) / 4

μ = 124 / 4

μ = 31

Then the mean absolute deviation is given as,

MAD = (|18 - 31| + |26 - 31| + |38 - 31| + |42 - 31|) / 4

MAD = (13 + 5 + 7 + 11) / 4

MAD = 36 / 4

MAD = 9

The mean absolute deviation will be 9.

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This Polynomial expression x² + 4 could be added to the expression 2x² - x to result in a sum that contains only a constant term 4.

What is the polynomial expression?

Any expression which consists of variables, constants, and exponents, and is combined using mathematical operators like addition, subtraction, multiplication, and division is a polynomial expression. Polynomial expressions can be classified as monomials, binomials, and trinomials according to the number of terms present in the expression.

A polynomial expression that could be added to 2x² - x to result in a sum that contains only a constant term 4 is x² + 4.

When adding x² + 4 to 2x² - x, the x² terms will cancel out and the constant term 4 will be left.

(x² + 4) + (2x² - x) = (x² + 2x²) + (4 - x) = 3x² -x + 4

The resultant polynomial expression is 3x² -x + 4 in which the only constant term is 4.

Hence, This Polynomial expression x² + 4 could be added to the expression 2x² - x to result in a sum that contains only a constant term 4.

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The areas of the shaded region of the given polygons is as follows

1. Area = 18.84cm²

2. Area = 67cm²

3. Area = 602.88cm²

4. Area = 1.14cm²

5. Area = 182.72cm²

6. Area = 33 cm²

The area of the shaded area is the difference between the total area of the polygon and the area of the portion of the polygon that is not shaded. In polygons, the area of the shaded component might appear in two different ways. A polygon's sides or its center are both potential locations for the shaded area.

Here, we have

1. r= 6 cm, θ = 60°

Area of shaded region = πr² × θ/360

Area = 3.14 × 6× 6 × 60/360

Area = 18.84cm²

2. r= 8 cm

θ = 360-240 = 120

Area = 3.14 × 8× 8 × 120/360

Area = 67cm²

3. r = 16 cm

θ = 360 - 90 = 270

Area = 3.14 × 16× 16 × 270/360

Area = 602.88cm²

4. r= 2 cm

θ =  90

Area = 3.14 × 2× 2 × 90/360

Area = 1.14cm²

5. r= 8 cm

θ =  270

Area  = πr² × θ/360 + 1/2(bh)

Area = 3.14 × 8× 8 × 270/360 + 1/2(8×8)

Area = 182.72cm²

6. R = 7 cm

r = 4 cm

Area = πR² - πr²

= 22/7 × 7² - 22/7 × 4²

= 49 - 16

= 33 cm²

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Full question:

The required sample size for the confidence interval is given as follows:

n = 267.

A confidence interval of proportions has the bounds given by the rule presented as follows:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which the variables used to calculated these bounds are listed as follows:

The margin of error is defined as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

The parameters for this problem are given as follows:

[tex]M = 0.06, \pi = 0.5[/tex]

The estimate is of 0.5 as it is when the highest sample size is needed, and the sample size is obtained as follows:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.06 = 1.96\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.06\sqrt{n} = 1.96 \times 0.5[/tex]

[tex]\sqrt{n} = \frac{1.96 \times 0.5}{0.06}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96 \times 0.5}{0.06}\right)[/tex]

n = 267.

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Answer:

Option B

Step-by-step explanation:

If you replace the X in the P(X) it becomes -1 and then you'll change every x in the equation to -1

2(-1)³ + 2(-1)² -3(-1) -3

which = -2 +2 +3 -3

= 0

Since the answer is 0 it means x + 1 is a factor of 2x³ + 2x² - 3x -3

Answer:

-----------------------

Factorize the given polynomial:

As we see the polynomial is divisible by x + 1.

Correct choice is B.

There amount are 504 different groups of 3 side dishes that a customer can choose from.

There are 9 possible side dishes, and the customer can choose any 3 of them. The number of different groups of 3 side dishes can be determined using the formula:

nCr = n!/(r!(n-r)!).

In this case,

n = 9 and r = 3,

so the number of possible groups is

9!/(3!(9-3)!) = 504.

When a customer buys a family-sized meal at a certain restaurant, they get to choose 3 side dishes from 9 options. The number of different groups of 3 side dishes possible for the customer to choose from can be determined using the formula for combination: nCr = n!/(r!(n-r)!). In this case, n = 9 (the number of possible side dishes) and r = 3 (the number of side dishes chosen). Applying the formula, the number of possible groups of 3 side dishes is 9!/(3!(9-3)!) = 504. This means that there are 504 different groups of 3 side dishes that a customer can choose from.

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The probability of the number of students to be selected randomly short or very short is 0.5048 or 50.48% = 50.5%.A is correct option

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

Number of students who are.

very short: 45,

short: 60,

tall: 82,

very tall: 21

The total number of students will be

Total sample = 45 + 60 + 82 + 21 = 208

The probability that a randomly selected student will be short or very short will be

Favorable sample = 45 + 60 = 105

Then the probability will be

P=105÷208

P=0.5048=50.48%

p=50.5%

option A is correct choice

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It is possible to find the value of S20 by applying arithmetic progression. similar by applying the sum formula.

Formula is used to determine S20.

First term (a) here equals 32, and common difference (d) is equal to 2.9

Sn = n/2 × ( 2a + (n-1) × d)

S20 = 20/2 × ( 2×32 + ( 20 - 1 ) × 2.9 )

S20 = 20/2 × ( 64 + (19 × 2.9) )

S20 = 20/2 × ( 64 + 55.1 )

S20 = 20/2 × 119.1

S20 = 1191

Therefore, value of S20 is 1191

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Answer:

Step-by-step explanation:

[tex]s_{n}=\frac{n}{2} [2a+(n-1)d]\\s_{20}=\frac{20}{2} [2 \times 32+(20-1)\times 2.9]\\=10[64+19\times 2.9]\\=640+551\\=1191[/tex]

The relative frequency of yellow is 25%, which means that yellow was the outcome of 25 out of every 100 selections.

What is the relative frequency?

Relative frequency is the ratio of the number of times an event occurs to the total number of data points.

The relative frequency of landing on yellow is 100/400 = 0.25 or 25%.

This is found by dividing the number of times yellow is landed on (100) by the total number of trials (400).

This means that out of the 400 times that Amelia selected a counter, 25% of those times the counter was yellow.

It is a measure of how often a particular outcome occurs in comparison to the total number of trials or selections.

Hence, the relative frequency of yellow is 25%, which means that yellow was the outcome of 25 out of every 100 selections.

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Answer:

Step-by-step explanation:

250

Answer:250

Step-by-step explanation: just add 10 till you get 250

Answer:

The original number is 62.

Step-by-step explanation:

Solution :

Let,

Units digit = x

Tens digit = 8 - x

★ Original number :

10 (8 - x) + x

80 - 10x + x

80 - 9x

When the digits of the number are interchanged :

10 (x) + 8 - x

10 x + 8 - x

9x + 8

(80 - 9x) - 36 = 9x + 8

80 - 36 - 9x = 9x + 8

44 - 9x = 9x + 8

44 - 8 = 9x + 9x

36 = 18x

x = 36/18

x = 2

Units digit = 2

Tens digit = 8 - x

8 - 2 = 6

Therefore, the original number is 62.

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Answer: [tex]V=-62000x+15200000[/tex]

Step-by-step explanation:

The slope of the line is [tex]\frac{900000-1520000}{100-90}=-62000[/tex].

Using point-slope form, the equation is:

[tex]V-900000=-62000(x-100)\\\\V-900000=-62000x+620000\\\\V=-62000x+15200000[/tex]

Answer:

K) x = - 2 and x = 2

Step-by-step explanation:

Vertical asymptotes occur when the denominator of a fraction equals to zero, but the numerator does not. In the case of y = 1/x^2 - 4, the denominator is x^2 - 4.

The equation x^2 - 4 = 0 represents the points at which the denominator equals to zero, so we can find the solutions for x by solving this equation:

x^2 - 4 = 0

x^2 = 4

x = ±2

So x = 2 and x = -2 represents the vertical asymptote of the graph of y = 1/x^2 - 4

This means that the graph of the function approaches zero as x approaches 2 and -2 from the left and right respectively, but it never touches the x-axis at those points.

Step-by-step explanation:

I've skipped some steps. Hope you get this.

Answer:

(a) [tex]\displaystyle{\int \left(x^2-2x+\dfrac{1}{x^2}\right) \, dx} = \dfrac{x^3}{3} - x^2 - \dfrac{1}{x} + \text{C}}[/tex]

(b) [tex]\displaystyle{\int x\left(x+3\right)^2 \, dx = \dfrac{x^4}{4} + 2x^3 + \dfrac{9x^2}{2} + \text{C}}[/tex]

Step-by-step explanation:

Part A

Consider the indefinite integral with respect to x:

[tex]\displaystyle{\int \left(x^2-2x+\dfrac{1}{x^2}\right) \, dx}[/tex]

We can separately integrate each terms as they are in addition and subtraction:

[tex]\displaystyle{\int x^2 \, dx - \int 2x \, dx + \int \dfrac{1}{x^2} \, dx}[/tex]

For the last term, we can rewrite in negative exponent as [tex]x^{-2}[/tex] so we can apply power rules to all these terms (making it easier):

[tex]\displaystyle{\int x^2 \, dx - \int 2x \, dx + \int x^{-2} \, dx}[/tex]

The middle term -- we can separate the constant out of integral:

[tex]\displaystyle{\int x^2 \, dx - 2\int x \, dx + \int x^{-2} \, dx}[/tex]

Apply the power integration rule (for n ≠ 1):
[tex]\displaystyle{\int x^n \, dx = \dfrac{x^{n+1}}{n+1} + \text{C} \ \ \left(\text{where C is a constant}\right)}[/tex]

But we can add C later after we integrate all these terms, therefore:

[tex]\displaystyle{\dfrac{x^{2+1}}{2+1} - 2\cdot \dfrac{x^{1+1}}{1+1} + \dfrac{x^{-2+1}}{-2+1}}\\\\\displaystyle{\dfrac{x^{3}}{3} - 2\cdot \dfrac{x^{2}}{2} + \dfrac{x^{-1}}{-1}}\\\\\displaystyle{\dfrac{x^3}{3} - x^2 - x^{-1}}[/tex]

Rewrite the negative exponent back to fraction form:

[tex]\displaystyle{\dfrac{x^3}{3} - x^2 - \dfrac{1}{x}}[/tex]

After integrating all terms, we add + C every time. Hence:

[tex]\displaystyle{\int \left(x^2-2x+\dfrac{1}{x^2}\right) \, dx} = \dfrac{x^3}{3} - x^2 - \dfrac{1}{x} + \text{C}}[/tex]

Part B

Consider the indefinite integration with respect to x of:

[tex]\displaystyle{\int x\left(x+3\right)^2 \, dx}[/tex]

First, expand (x + 3)² to x² + 6x + 9:

[tex]\displaystyle{\int x\left(x^2+6x+9\right) \, dx}[/tex]

Then disribute the x inside the brackets:

[tex]\displaystyle{\int \left(x^3+6x^2+9x\right) \, dx}[/tex]

Integrate separately:

[tex]\displaystyle{\int x^3 \, dx + \int 6x^2 \, dx + \int 9x \, dx}[/tex]

Separate the constants:

[tex]\displaystyle{\int x^3 \, dx + 6\int x^2 \, dx + 9\int x \, dx}[/tex]

For the power integration formula, recall above. Thus:

[tex]\displaystyle{\dfrac{x^{3+1}}{3+1} + 6 \cdot \dfrac{x^{2+1}}{2+1} + 9 \cdot \dfrac{x^{1+1}}{1+1}}\\\\\displaystyle{\dfrac{x^{4}}{4} + 6 \cdot \dfrac{x^{3}}{3} + 9 \cdot \dfrac{x^{2}}{2}}\\\\\displaystyle{\dfrac{x^4}{4} + 2x^3 + \dfrac{9x^2}{2}}[/tex]

Add + C after finishing the integration process, hence:

[tex]\displaystyle{\int x\left(x+3\right)^2 \, dx = \dfrac{x^4}{4} + 2x^3 + \dfrac{9x^2}{2} + \text{C}}[/tex]

Let me know if you have any questions!

20Ne, 19F and Mg₂+ are all examples of species or chemical ions.

20Ne is a stable isotope of Neon, 19F- is a negatively charged fluoride ion, and Mg₂+ is a positively charged magnesium ion. They all have a specific number of protons and electrons, which gives them their chemical properties and their unique behavior.

Chemical ions are atoms or molecules that have gained or lost one or more electrons, resulting in a net electrical charge. This charge can be positive (cation) or negative (anion). Examples of common ions include sodium (Na+) and chloride (Cl-), which combine to form table salt (NaCl).

Therefore, the correct answer is as given above

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Adults make up 0.02100 of the probability for whom the test would be positive.

The proportion of adults for which the test would be positive can be calculated by multiplying the probability of a randomly selected adult having the rare disease (0.001) by the probability that the test will be positive for a person with the disease (0.99) and adding it to the probability that the test will be positive for a person without the disease (0.02).

0.001 x 0.99 = 0.00099

0.00099 + 0.02 = 0.02099

0.02099 = 0.02100 (rounded)

Therefore, the proportion of adults for which the test would be positive is 0.02100.The proportion of adults for which the test would be positive is 0.02100, which is calculated by taking into account the probability of a randomly selected adult having the rare disease (0.001) and the probability that the test will be positive for a person with the disease (0.99) and a person without the disease (0.02). This reflects how the test is not perfect and can sometimes give false positives or false negatives. The result of 0.02100 indicates that out of every 1000 adults, 2 of them will have a positive test result.

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Answer:

68 oz.

Step-by-step explanation:

The bag weighs 4.25lbs

1lb=16oz.

4.25*16=68oz.

The total cost of production of six dining tables is $1300.

Production is the act of combining a variety of material and immaterial inputs to create an output. In a perfect world, this output would be a good or valuable good or service for people to use. The three main production factors of land, labor, and capital are known as primary producers of goods or services.

These crucial inputs are not significantly altered by the output process or the end product, nor are they made a crucial component of it. In classical economics, materials and energy are regarded as secondary factors because they are byproducts of land, labor, and capital. Technology and entrepreneurship are sometimes seen as evolved variables in production in addition to the conventional components of production.

Each dining table for $1,000

The second it's $1,100.

The marginal cost of each table increases by $200

The total cost of his production is

Fixed cost + Variable cost

= $1000 + 300= $1300

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Answer: 3x + 5

x = x + 2

3 (x+2) -1

3x + 6 - 1

3x+5

The painting crew will take approximately 38 hours to complete the 24-mile stretch of road.

Painting crew is a group of professional painters responsible for completing painting projects. They typically work on both interior and exterior painting projects and often specialize in specific types of paint finishes, such as faux finishes or specialty finishes. Painting crew members typically have a good understanding of painting techniques and tools, such as brushes and rollers, as well as a basic understanding of the chemistry involved in mixing paints.

This is calculated by taking the remaining miles (24 miles - 9.5 miles = 14.5 miles) and
dividing it by the rate at which they are painting (14.5 miles / 0.25 miles per hour = 58 hours).
Then we subtract the amount of hours they have already worked (58 hours - 9.5 hours = 38 hours).
Therefore, the painting crew will take approximately 38 hours to complete the 24-mile stretch of road.

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The quotient of  4 2/3 and 3/4 in fraction form is 6 2/9.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

There are three main categories of fractions in mathematics. Proper fractions, incorrect fractions, and mixed fractions are these three types. The expressions with a numerator and a denominator are called fractions. We categorize its types based on these two terms.

14/3 ÷ 3/4

⇒ 14/3 × 4/3

⇒ 56/9

⇒ 6 2/9

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The lengths of AD and A'D' are equal False

The area of ABCD and A'B'C'D' are equal False

The complete question is added as an attachment

From the question, we have the following parameters that can be used in our computation:

The quadrilateral A’B’C’ D’ is the result of dilating quadrilateral ABCD about point P by a scale of factor 3

When a shape is dilated by a scale factor other than 1 or -1, the resulting shape would have a different area and a different side length

This implies that ABCD and its image do not have equal side length and equal area

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Therefore, additivity and homogeneity of T are satisfied, T is linear.

T must be linear for both b and c to be true. T is linear, hence additivity is true for every p, q, and P. (R). In order to make our computations as straightforward as feasible, it would be a good idea for us to use straightforward polynomials in P(R). p, q ∈ P(R), where p(x) = [tex]\frac{\pi }{2}[/tex] and q(x) =  [tex]\frac{\pi }{2}[/tex] for all x ∈ R and so we have

T(p + q) =(3(p + q)(4) +5(p + q)'(6)+b(p + q)(1)(p + q)(2) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p + q)(x) d(x) +               c sin((p + q)(0))

           = (3(p(4)+q(4)) + 5(p'(6)+q'(6))+b(p(1)+q(1))(p(2)+q(2)) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p(x)+q(x))d(x)+ c sin(p(0)+q(0)))

           = (3([tex]\frac{\pi }{2}[/tex] +[tex]\frac{\pi }{2}[/tex])+5(0+0)+b([tex]\frac{\pi }{2}[/tex]+[tex]\frac{\pi }{2}[/tex])([tex]\frac{\pi }{2}[/tex]+[tex]\frac{\pi }{2}[/tex]),  [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]([tex]\frac{\pi }{2}[/tex]+[tex]\frac{\pi }{2}[/tex])d(x)+c sin([tex]\frac{\pi }{2}[/tex]+[tex]\frac{\pi }{2}[/tex]))

           = (3([tex]\pi[/tex])+b[tex]\pi ^{2}[/tex],[tex]\frac{15\pi }{4}[/tex])

and

Tp + Tq = (3p(4) +5(p)'(6)+bp(1)(p)(2) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p)(x) d(x) + c sin((p)(0)) +(3(q)(4) +5(q)'(6)+b(q)(1)(q)(2) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](q)(x) d(x) +c sin(q(0)))

           = (3([tex]\frac{\pi }{2}[/tex])+5(0)+b([tex]\frac{\pi }{2}[/tex])([tex]\frac{\pi }{2}[/tex]),  [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]([tex]\frac{\pi }{2}[/tex])d(x)+c sin([tex]\frac{\pi }{2}[/tex])) +  (3([tex]\frac{\pi }{2}[/tex])+5(0)+b([tex]\frac{\pi }{2}[/tex])([tex]\frac{\pi }{2}[/tex]),  [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]([tex]\frac{\pi }{2}[/tex])d(x)+c sin([tex]\frac{\pi }{2}[/tex]))

           =(3([tex]\frac{\pi }{2}[/tex])+[tex]\frac{\pi b}{4}[/tex],[tex]\frac{\pi }{2}[/tex]  [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]d(x) + c) +(3([tex]\frac{\pi }{2}[/tex])+[tex]\frac{\pi b}{4}[/tex],[tex]\frac{\pi }{2}[/tex]  [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]d(x) + c)

           =(3[tex]\pi[/tex]+ [tex]\frac{\pi b}{2}[/tex],[tex]\frac{15\pi }{4}[/tex]+2c)

Since T is linear, additivity of T holds and implies that we have

              (3([tex]\pi[/tex])+b[tex]\pi ^{2}[/tex],[tex]\frac{15\pi }{4}[/tex]) = T(p+q)

                                     =Tp+Tq

                                     =(3[tex]\pi[/tex]+ [tex]\frac{\pi b}{2}[/tex],[tex]\frac{15\pi }{4}[/tex]+2c)

from which we can equate the coordinates to obtain the equations 3π + πb/2= 3π +πb/2 and 15π/4 =15π/4+2c, which imply b = 0 and c = 0, respectively.

Backward direction: If b = 0 and c = 0, then T is linear. Suppose b = 0 and c = 0. Then the map T : R ^3 → R^2 becomes

Tp = (3p(4) +5(p)'(6) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p)(x) d(x) )

we need to prove that T is linear

• Additivity: For all p, q ∈ P(R), we have

 T(p+q) = (3(p + q)(4) +5(p + q)'(6) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p + q)(x) d(x))

             =(3(p(4)+q(4)) + 5(p'(6)+q'(6)) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p(x)+q(x))d(x))

             =  (3p(4) +5(p)'(6)+3q(4)+5q'(6) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p)(x) d(x) + [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]q(x) d(x))

              = (3p(4) +5(p)'(6) , [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](p)(x) d(x)) +(3(q)(4) +5(q)'(6), [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](q)(x) d(x))

             =Tp+Tq

• Homogeneity: For all λ ∈ F and for all (x, y, z) ∈ R^3, we have

                 T(λp) = (3(λp)(4) + 5(λp)'(6), [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex](λp)(x) d(x))

                           =(3λp(4) + 5λp'(6), [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]λ(p)(x) d(x))

                          =(λ(3p(4) + 5p'(6)),λ [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]p)(x) d(x))

                          =λ(3p(4) + 5p'(6), [tex]\int\limits^2_ {-1} \,[/tex] [tex]x^{3}[/tex]p)(x) d(x))

                         =λTp

 Therefore, additivity and homogeneity of T are satisfied, T is linear.

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To draw a box plot for the quiz scores of Professor A's class, you would start by drawing a number line along the horizontal axis and marking the minimum, Q1, median, Q3, and maximum scores.

Then, you would draw a box from Q1 to Q3 to represent the middle 50% of the data in professor A's class. The median score would be marked within the box, and a line would be drawn from either end of the box to the minimum and maximum scores to represent the lower and upper extremes of the data.

The highest quiz score is 20, and the lowest quiz score is 3.

The score that separates the bottom 75% from the top 25% is Q3, which is 16.

By definition, half of the class should have scored more than the median, so 20 students scored more than 14 points.

By definition, the median is 14, so half of the class should have scored more than 14 points, so 20 students scored more than 14 points.

Using the min value and Q1 value, we know that 25% of the students scored less than 12 points.

To determine if 4 is an outlier, we can use the IQR (interquartile range) method, which is calculated by subtracting Q1 from Q3. In this case, the IQR is 4 (16 minus 12). We can then use the IQR to find the lower and upper bounds of the data, which are determined by subtracting 1.5 IQR from Q1 and adding 1.5 IQR to Q3. In this case, the lower bound is 8 (12 minus 1.54) and the upper bound is 20 (16 plus 1.54). 4 is lower than the lower bound; therefore, it is considered an outlier.

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The larger random sample of 4000 people can reduce the bias and variability of the poll result by increasing the chances that the sample reflects the population accurately, reducing the effect of chance on the sample drawn, and increasing the precision of the estimate.

(a) Yes, the larger random sample can reduce the bias of the poll result. A larger sample size increases the chances that the sample accurately reflects the population by reducing the effect of chance on the sample drawn. This in turn reduces the likelihood of sampling bias, which occurs when a sample is unrepresentative of the population being studied.

(b) Yes, the larger random sample can reduce the variability of the result. A larger sample size increases the chances that the sample accurately reflects the population, which reduces the variability of the results. A larger sample size also increases the precision of the estimate, which reduces the variability of the results.

The larger random sample of 4000 people can reduce the bias and variability of the poll result by increasing the chances that the sample reflects the population accurately, reducing the effect of chance on the sample drawn, and increasing the precision of the estimate.

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Answer:

A) 540

B) x = 115/3

Step-by-step explanation:

A) to find the sum of the interior angles of any gon, use this formula: 180(n-2); n = the number of sides of the gon you are given (ex. octagon will be n=8). Therefore, a pentagon will be: 180(5-2) = 540

B) To find x, we can add all the angles and make them equal to 540.

(3x+50) + (2x+60) + (3x-30) + 2x + 2x = 540

12x = 460

x = 115/3

C) Plug-in x for every angle