Answer:
The atmosphere has frozen out into the polar ice caps and permafrost as Mars has cooled.
Explanation: Good luck box BrokenTag27
State the universal law of gravitation.
Answer in detail
Answer:
Explanation:
Newton's law of universal gravitation is that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
3. Would prudent to do an observatory M 82 for this class?
Answer: Yes,
If you need any other thing let me know, I'll still be on
Explanation:
light of wavelength 520 nm falls on a slit that is 3.20 um wide. Estimate how far the first bright-sh difrrection fringe is
Answer:
because of the gravity of the earth
A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its original linear momentum. a) Determine what fraction of the kinetic energy is lost in the collision.
The fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
The given parameters;
initial speed of the ball, = vifinal momentum of the ball, Pf = ¹/₃PiThe initial and final momentum of the ball is calculated as;
[tex]P_i = m_ivi[/tex]
[tex]P_f = m_fv_f = \frac{1}{3} m_iv_i[/tex]
The initial and final kinetic energy of the ball is calculated as;
[tex]K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i[/tex]
The change in the kinetic energy is calculated as;
[tex]\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i[/tex]
Thus, the fraction of the kinetic energy of the ball lost during the collision is [tex]\frac{1}{3}[/tex].
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How to calculate angular velocity.
Answer:
Answer below
Explanation:
We can rearrange this statement to get the angular velocity equation: = r v / |r|2, where all of these variables are vectors and |r| is the radius's absolute value. The angular velocity is really a pseudovector with a direction perpendicular to the plane of rotational movement.
The rotating movement of bodies is described by angular velocity. It determines how quickly they rotate around a central point. Rotations may be divided into two categories. The first explains the motion of an object's centre of mass around a certain point in space, which is referred to as an origin. Planets orbiting the Sun, for example, or an automobile exiting a roadway are two instances.
The first angular velocity equation is similar to the linear velocity equation: = (2 - 1) / t = / t, where 1 and 2 are two values of angles on a circle, and is the difference between them. t is the time it takes for the angle to shift. As you can see, there is a ratio of the positional change in a period for normal velocity, but we utilise angle instead of distance here. Definition of angular velocity using linear velocity The second angular velocity formula, v = r, may be obtained from the linear velocity and radius relationship using the cross product.
_______________________________________________________
(Hope this helps can I pls have brainlist (crown)☺️)
¿Cuál es la densidad de un metal si una muestra tiene una masa de 63.5 g cuando se mide en el aire y una masa aparente de 55.4 g cuando está sumergida en agua?. Considere la densidad del agua como 1000 kg/m3.
La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.
Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido
Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N
Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N
Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N
Pero ;
Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud
volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud
volumen = 0.081 N / 1000 * 10
Volumen = 8.1 * 10 ^ -6 m ^ 3
Densidad = masa / volumen
Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3
= 7,8 * 10 ^ 3 kg / m ^ 3
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Lina applies a constant force of 30 N as she pushes a dresser 3 m. How much work did Lina do on the dresser?
Answer:
The answer will be 90
Explanation:
30N×3m= 90
when energy from battery was added to water, were the gases produced by this made of the same particles as those produced from heating the water?
Batteries often convert chemical energy directly to electrical energy.
From the experiment, the constructed conclusion was that;
The Two different gases with different properties are made from adding energy from a battery to water. The particles that make up these different gases is different from each other. They are different than the ones that were made from heating water.The matter that is composed of substances have to originate from matter that made up some of the original water particles.
When energy from a battery is added to water, two streams of gas bubbles is said to be produced. Then a lit match is put into trapped gas from these two sources, one pops and the other glows brighter.
The study was to test the flammability of gases produced by providing energy to water with electricity.
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The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat’s average kinetic energy? (1 kJ = 1000 J)
Need answers with explanaitions please
A. 4.2 kJ
B. 8.3 kJ
C. 69.0 kJ
D. 139.0 kJ
Answer:
C.69 kJ
Explanation:
kinetic energy
[tex] = 1 \div 2mv {}^{2} [/tex]
What hazardous wastes are common in ordinary households? What can you do to reduce the impact you make on the environment from the use of hazardous wastes?
Answer:
The most common products include aerosols, anti-freeze, asbestos, fertilizers, motor oil, paint supplies, photo chemicals, poisons, and solvents, cleaning supplies.
Explanation:
Use homemade cleaners
You can find local retailers to take rechargeable batteries from laptop computers, cordless power tools, cellular and cordless phones, and camcorders at the Rechargeable Battery Recycling Corporation’s website
Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.
Answer:
hi I don't know sorry sorry forgive me
Explanation:
sorry
. Quỹ đạo chuyển động của một vật là
Answer:
you are very kind Po lang
what is faster?
A. train
B. bus
C. airplane
D. boat
Answer:
airplane
Explanation:
Answer:
a plane would go by far the fastest
Explanation:
it would be airplane ,train, boat, bus
What is the mass, in kilograms, of a large dog that weighs 441 newtons?
Answer:
441 Newtons equals 44.97 kilograms.
The total mass of the carts is 1000 kg. The first
drop is 77.7 m. What is the speed of the coaster
at the bottom of the hill?
Answer:41xm/s
Explanation:
Answer:41xm/s
Explanation:
I found this for you hope it helps.
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
A 2 kg mass starts from rest and slides down an inclined plane 4 m long in 1 second. What net force is acting on the mass along the incline *.
The net force acting on the mass along the incline is equal to 16 Newton.
Given the following data:
Mass = 2 kgDistance = 4 metersTime = 1 secondsTo determine the net force acting on the mass along the incline:
First of all, we would find the acceleration of the mass by using the second equation of motion:
[tex]S = ut+ \frac{1}{2} at^2\\\\4 = 0(1) + \frac{1}{2} a(1)^2\\\\4=\frac{a}{2}\\\\a=2\times 4[/tex]
Acceleration, a = 8 [tex]m/s^2[/tex]
For the net force, we would apply Newton's Second Law of Motion:
[tex]F_{net} = mass \times acceleration\\\\F_{net} =2 \times 8[/tex]
Net force = 16 Newton.
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Find the displacement in the time interval 3 seconds to 4 seconds
A. 1m
B.3m
C.7m
D.9m
Answer:
B. 3m
Explanation:
Took the quiz.
Hope this helps!!
why do we believe 90 percent of the mass of the milky way is in the form of dark matter?
Answer:
The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.
Two electrons are separated by one cm. What is the ratio of the electric force to the gravitational force between them? (me = 9. 11 ´ 10-31 kg, ke = 8. 99 ´ 109 N×m2 /C2 , G = 6. 67 ´ 10-11 N×m2 /kg2 , and e = 1. 6 ´ 10-19 C) a. 2. 3 ´ 102 b. 1. 3 ´ 1020 c. 3. 1 ´ 1022 d. 4. 2 ´ 1042.
The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
The given parameters;
Mass of the electron, [tex]m_e[/tex]= 9.11 x 10⁻¹¹ kgCoulomb's constant, k = 8.99 x 10⁹ Nm²/C²Gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²Charge of electron, q = 1.6 x 10⁻¹⁹ CDistance between the two electrons, r = 1 cmThe electrostatic force between the two electrons is calculated as follows;
[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]
The gravitational force between the two electrons is calculated as follows;
[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]
The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;
[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]
[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]
Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
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What are the variables that affect the force of gravity between objects?
which wave has a higher frequency and why?
Explanation:
the figure in the left side has higher frequency.
because it has more nos. of wave in 1sec.
A child sits on a rotating merry-go-round, 2.1 m from its center. If the speed of the child is 2.2 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?
We have that the the minimum coefficient of static friction is mathematically given as
[tex]\mu= 0.235[/tex]
ForceGenerally the equation for the Force is mathematically given as
[tex]F=n\mu\\\\Where\\\\n = mg\\\\Given\\\\Fc = m(vt2/R)\\\\Therefore\\\\\mu = vt2/gR\\\\\mu = 2.22/(9.8(2.1)) \\\\[/tex]
[tex]\mu= 0.235[/tex]
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What is a lol diagram.
Answer:
LOL Diagrams
a way to represent how the energy is stored in the chosen system during various snapshots and to represent any changes in total energy for the system. Each “L” represents how the energy is stored during a particular snapshot (instant). The “O” shows the objects inside and outside the system.
What is the relationship between momentum and kinetic energy.
Answer:
constant object, momentum increases directly with speed
Explanation:
whereas kinetic energy increases the square of the velocity due to energy momentum
6. Explain the importance of the law of conservation of mass.
Answer:
According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants. The law of conservation of mass is useful for a number of calculations and can be used to solve for unknown masses, such the amount of gas consumed or produced during a reaction.
Explanation:
<3
How much work is needed to stop a 1,110 kg car that is moving straight down the
highway at 59.0 km/h?
Answer:
382.74 kJ.
Explanation:
The work that must be done to stop an 1100 kg car travelling at 59 km/h is - 382.74 kJ.
The work needed to stop an 1100 kilograms car moving with a velocity of 59.0 km/hr would be 147.72 kilojoules.
What is work done?
The total amount of energy transferred when a force is applied to move an object through some distance
The work done is the multiplication of applied force with displacement.
Work Done = Force * Displacement
As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour
the mass of the car = 1100 kilograms
the velocity of the car = 59 kilometers/hour
KE = 0.5mv²
=0.5×1100×(59×1000/3600)²
= 147.72 kilojoules
Thus, the work needed to stop an 1100 kilograms car would be 147.72 kilojoules
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answer question 7 please
The person is in motion
relative to...
Answer:
muscular force in relative to this
What can we say about energy on
the low end of the
electromagnetic spectrum?
A. They have longer wavelengths and less dangers.
B. They have lower frequencies and more energy.
C. They have shorter wavelengths and less dangers.
D. They have higher frequencies and more energy.
Answer:
A. Longer wavelengths and less dangers
Explanation:
Radio waves are at the lowest end of the EM spectrum, they have the longest wavelength of any other EM waves, the lowest energy and, accordingly, the lowest frequency;
Their low energy and frequency means they pose little risk of harm or danger as they don't get absorbed by human being.
