Answer:
TRUE
Explanation:i've seen one and please make me the brainlest
A family uses the microwave to prepare their cat’s food. The cat comes running into the room when the microwave timer sounds, but not when it hears the oven timer. The cat is demonstrating the concept of.
Each cat get 3 ounces of food .
What is ounces?
Ounces is a unit of weight of one sixteenth of a pound approximately 28 gram.
An ounce is also a very small amount.
Sol-
all together there is 24 ounces
(4×6=24)
The divide 24 by 8 to see how much each cat gets
24÷8=3
3 ounces each
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What is the speed of a car if it has a mass of 1000 kg and kinetic energy of 32 kJ?
Answer:
8 m/s
Explanation:
K.E. = 1/2 m v^2
32 000 j = 1/2 (1000) v^2
v = 8 m/s
A 1. 0-kilogram ball is dropped from the roof of a building 40. Meters tall. What is the approximate time of fall?.
The approximate time of fall is 2.9s.
Calculation:-
Assume g = 9.8 m/s² and neglect air resistance.
The initial vertical velocity is zero.
let t = initial time
40 m = (1/2)*g*(t s)² = 0.5*9.8*t²
t² = 40/4.9 = 8.1633
t = 2.857 s
= 2.9s
Falling from a high place to the ground is called free fall. Hope you got it Dropping a ball from the top of a building will make it fall faster. When an object falls it gains speed. Increased speed leads to increased drag.
Eventually, the force of air resistance becomes large enough to balance gravity. The object stops accelerating. When gravity pulls an object to the ground, it always accelerates with a velocity of 9.8 m/s2.
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A 3.5 m long frictionless pendulum of mass 2.0 kg is released from point A at an angle θ of 10 degrees. What is the speed of the pendulum at point D, half the height up to point E?
Answer:
5
Explanation:
melsun slemalawkew melsun asawkecn
According to the rutherford model, which force keeps electrons in orbit around the nucleus?.
The correct answer is centripetal force keeps electrons in orbit around the nucleus.
What is Rutherford model?
Rutherford Atomic Model - J. J. Thomson's "plum pudding" model was unable to account for some experimental findings related to the atomic structure of elements. British scientist Ernest Rutherford carried out an experiment, and using the results of this experiment, he proposed Rutherford's Atomic Model and explained the atomic structure of the elements.
Thus, in the Rutherford model, the centripetal force that maintains the electron in orbit is produced by the electrostatic attraction between the (positive) nucleus and the (negative) electron.
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A light year is approximately 9. 5 trillion km long. 'barnard's star' is 6 light years away from earth. Calculate how many trillions of kilometres this is.
Using the theories of light year, we got that 57.0 trillion km is 'Barnard's star' away from earth.
Light is the fastest-moving stuff in the our universe. It actually travels at 186,000 miles per second (300,000 km/sec). And thus a light-year is about 5.88 trillion miles (9.46 trillion kilometers).
We know very well that ,
1 light year=9.5 trillion km
Therefore,6 light year=6×9.5 trillion km
=>6 light year=57.0 trillion km.
Hence, if a light year is approximately 9. 5 trillion km long, 'Barnard's star' is 6 light years away from earth which is equivalent to 57 trillion of kilometres
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a certain lake, filled with fresh water, is 40 m deep and located at sea level. what is the absolute pressure (in kpa) at the bottom of the lake?
A certain lake, filled with fresh water, is 40 m deep and located at sea level. The absolute pressure (in kpa) at the bottom of the lake will be 492.1 kPa
P1 = rho * g * h
rho = density of water
g = acceleration due to gravity
h = depth
P1 = rho * g * h
= 997 * 9.8 * 40 = 390824 N / [tex]m^{2}[/tex] = 390.8 kPa
P(absolute pressure) = Po + P1
= 101.3 + 390.8 = 492.1 kPa
The absolute pressure (in kPa) at the bottom of the lake will be 492.1 kPa
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a 1500 kg car is traveling at 20 m/s rounds a curve so that it’s centripetal force is 7500 n. what is the radius of the curve
The radius of the curve is 80 m when its centripetal force is 7500 N.
Given Information:
Mass of the Car (m) = 1500 kg
The velocity of the Car (v) = 20 m/s
Centripetal Force (F) = 7500 N.
Now, Centripetal Force is given by,
[tex]F = \frac{mv^{2} }{r}[/tex]
Putting all these values in the formula for centripetal force,
[tex]7500 = \frac{1500*20^{2} }{R}[/tex]
[tex]R = \frac{1500 * 400}{7500} = 80[/tex]
Hence, the radius of the curve is 80 m.
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The sun is almost 22 million times as massive as the moon but it is nearly 400 times as far from earth. Which celestial body, the sun or the moon, exerts the greatest amount of gravitational force on you as you sit in class?.
Answer:
Explanation:
Stronger to the Sun 138 times
F = G·M·m / D²
22 000 000 / 400² ≈ 138
a 2.92 kg particle has a velocity of (2.99 i hat - 3.94 j) m/s. (a) find its x and y components of momentum. px
The momentum of x 8.731 kgms⁻¹ i and y is 11.5 kgms⁻¹ components of momentum.
Momentum is the product of the mass and pace of an item. it's miles a vector quantity, owning importance and a path. Momentum may be the notion of as the "energy" when a frame is moving, which means how a whole lot pressure it can have on any other frame.
A pressure acting for a given quantity of time will change an item's momentum. positioned some other way, an unbalanced force constantly hastens an object - either speeding it up or slowing it down. If the force acts opposite the item's movement, it slows the item down.
Calculation:-
Momentum = mass × velocity
= 2.92 × (2.99 i)
= 8.731 kgms⁻¹ i
Momentum = mass × velocity
= 2.92 × (3.94 j)
= 11.5 kgms⁻¹
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An object of mass 6 kg accelerates from 5 m/s to 9 m/s in 8 s. How much work was done on the object during this time? how much power was applied? what is its change in momentum?
Answer:
(1)540 J
(2)67.5 J/s or 67.5W
(3)look at underline statement in explanation
Explanation:
(1) acceleration = change in speed ÷ time
= (9-5)m/s ÷ 8s
= 0.50 m/s²
resultant force of object during motion
= mass(in kg) × acceleration
= 6 × 0.50 = 3 N
displacement of force applied
= area under speed time graph(when sketched out, it's a trapezium)
= ½ × (5+9) × 8
= 180m
work done is measured in joules
= force × displacement of force applied
= 3N × 180m
= 540 J
detailed explanation:
altho the final unit for the work done should be Nm, but J is equal to Nm.
(2) Power is measured by J/s
therefore power = 540 J ÷ 8s = 67.5 J/s or 67.5 W
(3) the object accelerates constantly along a straight road
Jacob and David devise an experiment to determine how tall the school building is. They stand on the roof of the school where Jacob drops a rock to the ground while David times it. From the time Jacob drops the rock to the time they hear it hit the ground, it takes 0.81 s. If the speed of sound is 340 m/s how tall is the school? Remember that it takes time for the rock to fall to the ground AND time for the sound of it to come back up for them to hear it.
Answer:
The school is 3.40 meters tall.
Explanation:
You need to equations to solve this question. You need to know the time it takes to reach the ground and the time it takes for the two observers to hear it. The distance in both cases is the same, so the two conditions can be equated to each other.
Equations.
d = the height of the buildings
a is the acceleration due to gravity and is a constant 9.8i1 m/s^2
t1 is the time it takes to hit the ground
The initial velocity = 0 because the rock was dropped
Equation One
d = vi*t + 1/2 a t^2
Equation Two
d = v * t2
v is the velocity of sound
t2 is the time it takes for the sound to come back from hitting the ground.
d is the height of the school
Solution
vi*t + 1/2 a t1 ^2 = v * t2
t2 = 0.81 - t1
The times are separate, but they add up to 0.81 so
t1 I+ t2 = 0.81
t2 = 0.81 - t1
Rewrite the equation putting in the givens. Remember vi = 0
1/2 9.81 t1^2 = 340 * (0.81 - t1) Remove the brackets
4.91* t1^2 = 275.4 - 340 t1 Transfer the right side to the left
4.91*t1^2 + 340t1 - 275.4 = 0 Use the quadratic formula to solve
a = 4.91
b = 240
c = -275.4
t1 = (-240 +/- sqrt(240^2 - 4*4.91*-275.4))/(2*4.91)
t1 = .8007 = 0.80
t1 + t2 = 0.81
0.80 + t2 = 0.81 - 0.80
t2 = 0.01
What you have found is the time it takes for the sound to come back to the two observers which is 0.01 seconds
d(height of school) = 340 * 0.01 = 3.4 meters
What do you predict would happen if you brought a negatively charged balloon next to an uncharged piece of paper?.
A portion of the paper near the balloon becomes positive when you place the balloon close to a small piece of paper because the negative charge balloon repels the electrons charge in the paper.
Electric charge, a fundamental characteristic of matter carried by some elementary particles, controls how an electric or magnetic field affects the particles. Positive or negative electric charge exists in distinct natural units and cannot be created or destroyed.
Positive and negative charges are the two main categories of electric charges. When two objects are relatively close to one another and one type of charge is present in excess, they repel one another. When they are relatively close to each other, two objects with excess opposite charges—one positively charged and the other negatively charged—attract to one another.
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A cyclist starts from rest and accelerates at 1.0 m/s2
for 20 seconds. He then travels
with constant velocity for 1 minute and finally decelerates at 2.0 m/s2 until he stops. Find
his maximum velocity and the total distance travelled
The maximum velocity and the total distance traveled are equal to 20 m/s and 1500 m.
What is the velocity?Velocity can be defined as the vector measurement of the direction and magnitude motion of an object. The velocity of an object can be determined by the rate of change in the position w.r.t. time.
From the equation of motion, we can calculate the velocity of the cyclist:
v = u +at
v = 0 + (1) (20)
v = 20 m/s
v = 20 × (3600/1000)
v = 72 Km/h
The distance covered from t = 0 to t = 20 will be:
[tex]S = ut+\frac{1}{2}at^2[/tex]
S = 0 + 0.5 ×1×(20)²
S = 200m
Then travel for 1 minute with a constant speed of 20 m/s:
Distance = v × t = 20 × 60 = 1200 m
Then decelerates at 2 m/s² calculate time:
v = u -at
0 = 20 - (2) t
t = 10 s
The distance covered in t= 10 s and u = 20 here,
S = 20 × 10 - 0.5 ×2 × (10)²
S = 100 m
Therefore, total diatance travlled = 200 + 1200 + 100 = 1500 m
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A very long flat conducting strip of width d and negligible thickness lies on a horizontal plane and carries a uniform current I across its cross section.
a) Show that at points a distance y directly above from its center the field is given by:
assuming the strip is infinitely long. [Hint: Divide the strip into many thin "wires" and sum (integrate) over these]
b) What value does B approach for y >> d ? Does this make sense? Explain.
The b approach for y with magnetic field with uniform current is current is B=(µI/πd ) 1/(tan(d/2y)
The concept of "equivalent uniform current" in wave-current computations is introduced in this paper. For a given observed wave period, wave height, and water depth, this current is defined as the uniform current that produces the same wavelength as the actual depth-varying current. Consider the strip to be the collection of a number of thin parallel wires, each carrying a current I. Because the vertical contributions to the magnetic field cancel, integration along the horizontal component is now performed. b- The magnetic field magnitude with current is B=(µI/πd ) 1/(tan(d/2y)
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Suppose a pv farm requires 2,000 panels to generate power at 40% efficiency. If a new panel were invented that was 50% efficient, how many panels would be required?.
The number of panels required when the efficiency of the machine changes to 50% is 1,600 panels.
What is the efficiency of a machine?The efficiency of a machine or any device is the measure of the ratio of the output energy or output work of the machine or device to the input work or energy of the device.
The efficiency of the PV farm describes how well it converts solar energy from the sun into useful energy.
The smaller the number of panels required by the PV farm, the more efficient the PV farm is and vice versa.
The number of panels required when the efficiency of the machine changes is calculated as follows;
40% ------> 2,000 panels
50% --------> ?
= (40 x 2000) / 50
= 1,600 panels
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If the current in a a wire is 2. 0 amperes and the voltage across the wire is 10 volts, what is the resistance of the wire?.
The resistance of the wire will be 5 ohm.
Resistance is nothing but the opposing force applied during charges moving from one side of the wire to the another side of the wire.
According to the ohm's law we have
V ∝ I
or we can write
V = IR
where, V is the voltage applied and I is the current applied and the R is the resistance of the wire.
so we can write,
R = V/I
R = 10/2
R = 5 Ohm
Hence the resistance of the wire will be 5 ohm.
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a series rlc circuit is built with a 100 ohm resistor, a .55uf capacitor and a 122mh inductor. what would be the resonance frequency for circuit?
The resonance frequency for the circuit having a series connection with a 100-ohm resistor, a .55uf capacitor, and a 122mh inductor is 61.38 Hertz.
What is Resonance?Resonance is the relatively strong selective response of a system or item to an external oscillatory force that makes it vibrate in step or phase. Acoustic resonance is exemplified by the vibration that occurs in a violin or piano string of a certain pitch in response to the nearby singing or playing of a note of the same pitch.
The term that best defines what is causing the windows to vibrate is resonance. It happens when one system's vibration or an external stimulus makes another system vibrate more ferociously and at a certain favored frequency. The windows of the house shake a lot as a result. A resonance that matches a specific form of mechanical resonance has been found on the nuclear scale.
Given:
The resistance, R = 100 ohm,
The capacitance, C = 55 μF,
The inductance, I = 122 mh.
Calculate the Resonance by following the formula,
R = 1 /2[tex]\pi \\[/tex]([tex]\sqrt{LC}[/tex]),
Here R is the resonance,
Substitute the values,
R = 1 / 2 *3.14 *[tex]\sqrt{55 * 10^{-6} * 122 * 10^{-3}}[/tex]
R = 61.38 Hertz
Therefore, the resonance frequency for the circuit having a series connection with a 100-ohm resistor, a .55uf capacitor, and a 122mh inductor is 61.38 Hertz.
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What is the total number of subatomic particles found in the nucleus of an atom of argon?.
The subatomic particles in the nucleus of an atom of argon depend on the nucleus and proton.
What subatomic particles?
A particle that is smaller than an atom is what is known as a subatomic particle. Protons, electrons, and neutrons are the three subatomic particles that make up an atom in most cases.
40Ar
18 protons, 22 neutrons, 18 electrons
There are 18 protons from the argon element. These 18 electrons because it is neutral, and 22 neutrons because 40 - 18 = 22.
Hence the total number of subatomic particles present in the nucleus is 22.
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Please help with one of these questions or both I need it asap it’s argent
Answer: A
Explanation:
loss and degradation of habitat (mainly deforestation), over exploitation (hunting, overfishing), invasive species, climate change, and nitrogen pollution.
If Anna walks walks 80. m to the south, 60. m to the east, 50. m to the north, and then 20. m to the west. What is the total distance Anna has traveled?
A. 210. m.
B. 153. m.
C. 70. m.
D. 50. m.
E. None of the above.
The total distance if Anna walks walks 80m to the south, 60m to the east, 50m to the north, and then 20m to the west is 210m (option A).
What is distance?Distance is the amount of space between two points, usually geographical points, usually (but not necessarily) measured along a straight line.
According to this question, Anna walks walks 80m to the south, 60m to the east, 50m to the north, and then 20m to the west.
The total distance walked can be calculated as follows:
80m (southwards) + 60m (eastward) + 50m (northward) + 20m (westward) = 210m
Therefore, 210m is the total distance traveled by Anna.
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a ball of mass 0.800 kg is carefully balanced on a shelf that is 2.50 m above the ground. what is its gravitational potential energy?
K.E. is supplied by
[tex]K.E. = 1/2. mv2[/tex]
[tex]KE = PE[/tex] because
[tex]1/2*mv2 = mg*h[/tex]
So,[tex]v = \sqrt{(2g/m)}[/tex]
What is potential energy?
An item may store energy according to its location, as we all know. In the instance of a bow and arrow, the bow stores some energy as it is drawn, and this energy is what gives the arrow its kinetic energy when it is released.Similar to this, a spring accumulates energy as it is moved away from its equilibrium state, which we can notice by the tension our hands experience when we stretch it. Potential energy is a type of energy that is created when anything changes position or condition.However, Let's study the definition of potential energy and its formula before moving on to instances and the potential energy unit.
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Complete the following sentence.
If you shine a flashlight at an object in space that is 150,000,000 km from Earth, the light will arrive at the object in approximately
light seconds.
Answer:
the answer two your question is 500
Explain what type of conformity the subjects in muzafer sherif's moving light experiment were most likely experiencing, using evidence from the text to justify your answer.
The conformity most likely experienced by subjects in Muzaffar Sheriff's Moving Light experiment was internalization.
Internalization is defined as a group of people sharing similar thoughts and behaviors purely with little or no influence from one part on the other, without falsifying their behavior just to collect The type of affinities to adopt. This type of affinity is seen in those who participated in Muzaffar Sherif's Moving Light Trial.
Conformity means that people make their beliefs attitudes behaviors or perceptions more conformable to those of the group to which they belong aspire to belong or to which they desire approval. It is the process of changing to Conformity has important social implications and continues to be actively investigated.
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If Jenny has a mass of 45 kg, and is on Earth. What is Jenny's weight?
Answer:
441kg
Explanation:
Lets assume Jenny is on Earth, if she is on the Earth, we time 45kg by 9.8
which means her weight on Earth would be 441kg.
Answer:
441 N is Jenny's weight
Explanation:
Given:
m = 45 kg
g = 9.8 m/s²
___________
P - ?
P = m·g
P = 45·9.8 = 441 N
What happens to air as it expands?
a) It cools.
b) It does not change its temperature.
c) It heats up.
a) It cools.
It cools down as it spreads. The rising air parcel's pressure must decrease with altitude since the atmospheric pressure does.
When air expands, what happens to it?Each molecule has more room to move about as air warms up because the molecules begin to vibrate and collide. Air expands and becomes less dense as a result of each molecule requiring more space to move (lighter).The rising air parcel's pressure must decrease with altitude since the atmospheric pressure does. Air grows larger as it rises. It cools down as it spreads.As it rises, air expands and cools (adiabatic cooling: that is, it cools due to change in volume as opposed to adding or taking away of heat). Condensation or precipitation is what happens.To learn more about Adiabatic cooling refer to:
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a 1.5m long dowel is pivoted about the end so that it is a pendulum of sorts - it can freely swing in a vertical plane. at the other end of the dowel is a brass weight having mass 1.5 kg. (the center of the brass weight is 1.5 m from the pivot point. when the rod is positioned in its swing such that its angle with the vertical is 22.5 degrees, what is the torque on the rod about the pivot due to the presence of the brass weight?
The torque on the rod about the pivot due to the presence of the brass weight is 8.44 N.m.
What is torque?The force that can cause an object to rotate along an axis is measured as torque. In linear kinematics, force is what drives an object's acceleration. Similar to this, an angular acceleration is brought on by torque. As a result, torque can be thought of as the rotational counterpart to force. The axis of rotation is a straight line about which an object rotates.
Given parameters:
Mass of the brass weight, m= 1.5 kg.
Length of the rod, l = 1.5 m.
Angle with the vertical; θ =22.5⁰.
We have to find, torque on the rod about the pivot due to the presence of the brass weight; ζ = ?
Force applied by the brass weight; F = mass × acceleration due to gravity = 1.5 × 9.8 N = 14.7 N.
So, torque on the rod about the pivot due to the presence of the brass weight; ζ = Fl sinθ
= 14.7 × 1.5 × sin22.5° N.m
= 8.44 N.m.
Hence, the applied torque is 8.44 N.m.
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a car is moving with a constant speed of 20 meters per second. what total distance does the car travel in 2.0 minutes?
Answer:
2400 m
Explanation:
Dimensions in units need to match so
2 min = 120 sec
then rate X time = distance
20 m/s X 120 s = 2400 m
Answer:
Explanation:
it is 43km
A man is trying to push a box across a table. He pushes on the box with 5 n and the table provides a frictional force of 2 n. What will be the net force on the box?.
Using the concepts of Force,we got that 3N is the net force acts on the box if a man is trying to push a box across a table. He pushes on the box with 5 n and the table provides a frictional force of 2 n.
We know very well that every object is able to move on the surface of the earth is due to frictional force. If friction is absent then every object skids.
That frictional force always acts opposite in the direction of the movement of the body.
Here the amount of force exerted by a man is 5 N, while the amount of frictional force is 2N,means if 5N is acting on forward direction then 2N acts in opposite direction.
So, the net force acts on the body =Force exerted by man-Frictional force
=>Net force=(5N-2N)=3N
Hence, if A man is trying to push a box across a table. He pushes on the box with 5 n and the table provides a frictional force of 2 n, the net force on the box is 3n.
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if the perimeter of the window is 32 feet, find the exact value of x (in ft) so that the greatest possible amount of light is admitted.
The exact value of x is 4.48 ft so that greatest possible amount of light is admitted .
Norman window shap is rectangular surrounding by semi circle .
let x be the width and h be the height of window.
Therefore, radius of semi- circle is x/2 .
we have given that
perimeter of the window = 32 ft
the perimeter of semi-circle = π × x/2
the perimeter of rectangular = 2h + x
perimeter of window ( rectangular surrounding by semi circle) = 2h + x + πx/2 = 32 ---(1)
Area of rectangular part = x × h
Area of semi circle= π×(x/2)²
Area of window = π×(x²)/4 + xh ---(2)
Now, we must maximize the area of window so that greatest amount of light admitted.
using (1) , h = 16 - x/2 - πx/4
Area of window (A) = πx²/4 + 16x - x²/2 - πx²/4
A = 16x - x²----(3)
for maximize we take first order derivative of area and then put it equal to the zero for finding the critical value of x .
differentating equation (3) with respect to x we get, dA/dx = 16 - 2x
now, dA/dx = 0 so, 16 - 2x = 0 => x= 8
Hence , the exact value of x is 8 .
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Complete question:
Norman window has the shape of rectangle surmounted by semicircle: (Thus the diameter of the semicircle equal to the width of the rectangle labeled x. ) If the perimeter of the window Is 32 feet, find the exact value of x (In ft) so that the greatest possible amount of Iight Is admitted
