Answer:
Our atmosphere has five different layers. They are:
1. Troposphere: This is the most important layer of the atmosphere with an average height of 13 km from the earth. It is in this layer that we find the air that we breathe. Almost all the weather phenomena such as rainfall, fog and hailstorm occur here.
2. Stratosphere: This layer extends up to a height of 50 km. It presents the most ideal condition for flying airplanes. It contains a layer of ozone gas which protects us from the harmful effect of the sun rays.
3. Mesosphere: This layer extends up to a height of 80 km. Meteorites bum up in this layer on entering from the space.
4. Thermosphere: In this layer, the temperature rises very rapidly with increasing height. The ionosphere is a part of this layer. It extends between 80-400 km. This layer helps in radio transmission. Radio waves transmitted from the earth the reflected back to the earth by this layer.
5. Exosphere: It is the uppermost layer where there is very thin air. Light gases such as helium and hydrogen float into space from here.
I need to choose a theme for my physics assignment My experiment is finding g
How to find g (acceleration due to gravity)
Solution:We know,
Acceleration due to gravity (g)
[tex] = \frac{GM}{ {R}^{2} } [/tex]
where, G = Gravitational constant
[tex] = 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\ [/tex]
M = Mass of the earth
[tex] = 6 \times {10}^{24} \: kg[/tex]
R = Radius of the earth
[tex] = 6.4 \times {10}^{6} m[/tex]
Putting these values of G, M and R in the above formula, we get
[tex]g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2} [/tex]
So, the value of acceleration due to gravity is
[tex]9.8m/s ^{2} [/tex]
Hope it helps.
Do comment if you have any query.
A person of mass 70 kg stands 0.5 m from one end of a 2 m long uniform plank (of negligible mass) that is
being held in equilibrium by two vertical ropes attached to the ends of the plank. What is the tension in the
rope closer to the person?
Help
Hi there!
We can begin by using a summation of torques, with the fulcrum being at the rope farthest from the person (the other end).
Thus:
F1 = weight of person
R1 = distance of person to fulcrum (farther end)
F2 = Tension of rope closest to person
R2 = distance of rope to fulcrum
∑τ = 0 = R2F2 - R1F1
R2F2 = R1F1
Plug in values:
2F2 = 1.5(700N)
2F2 = 1050 N
F2 = 525 N = Tension of closest rope
Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high?
Answer:
2 times more work
Explanation:
Work is a force times distance
W = Fd
The barbell does not change mass so its weight (force) is constant.
That means work is directly proportional to the distance traveled.
twice the distance means twice the work.
¿Por qué el origen de ciertos metales se relaciona con la dinámica terrestre?
name two examples where the cohesive force dominates over the adhesive force and vice versa
Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.
What is the difference between cohesive force and adhesive force?Cohesive forces are the forces that draw molecules of the same type together. Adhesive forces are those that draw molecules of various types together.
The force that draws molecules of the same substance together is called the cohesive force. The force that holds molecules of various substances together is known as the adhesive force.
Between molecules of the same substance, there are cohesive forces. There is a natural tendency to resist separation due to these intermolecular forces between like elements. Conversely, adhesive forces draw disparate molecules together.
In physics, cohesion refers to the intermolecular attraction that exists between two adjacent parts of a substance, especially one that is solid or liquid. A piece of matter is held together by this force. Adhesion is a term for the intermolecular forces that act when two dissimilar substances come into contact.
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. If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration change
Answer:
a1 = -w^2 A sin w t where w is the angular frequency
a2 = - (2 w)^2 A sin 2 w t where w2 = 2 w1
a2 / a1 = 4 sin 2 w t / sin w t
Since sin 2 w t / sin w t = 2 sin w t will change twice as fast
a2 / a1 = 8 the max acceleration must change 8 tims as fast
What is the volume of 150g of a substance that has a density of 150g of a substance that has a density of 11.3g/cm3
Answer:
25.0 cm3
Explanation:
The volume is 25.0 cm3 .
E5. A ball is thrown downward with an initial velocity of 12 m/s.
Using the approximate value of g 10 m/s2, what is the
velocity of the ball 1.0 seconds after it is released?
Hi there!
We know the following kinematic equation:
vf = vi + at
Where:
vf = final velocity
vi = initial velocity
a = acceleration
t = time
In this instance, the ball is experiencing a constant acceleration of that of gravity, thus:
vf = 12 + 10(1) = 22 m/s (if downward is considered positive in this instance)
What will be the speed of these waves (in terms of V) if we increase M by a factor of 18.0, which stretches the wire to double its original length
The speed of the chord wave allows finding a new speed when the mass is increased and the chord length is:
The velocity is: v = [tex]\frac{v_o}{3}[/tex]
A wave is a periodic movement of the particles that carries energy, but not matter, the speed of the waves is related to the properties of the medium by the relationship.
[tex]v = \sqrt{\frac{T}{\mu } }[/tex]
Where v is the speed of the wave, T the force and μ is the linear density.
Indicates that the applied mass increases by a factor of 18.0 and the length of the head is increased to twice the original.
The linear density of the cable is
[tex]\mu = \frac{m}{l}[/tex]
Where m is the mass of the cable and l is the length.
Let's use the subscript "o" for the initial conditions.
M = 18.0 m₀
l = 2 l₀
We look for the density.
[tex]\mu = \frac{18.0 m_o}{2.0 l_o}[/tex]mu = 18.0 mo / 2 lo
[tex]\mu = 9.0 \mu_o[/tex]
We substitute in the expression for the velocity assuming that the tension is kept constant.
[tex]v= \sqrt{\frac{T}{9.0 \mu} }[/tex]
[tex]v= \frac{v_o}{3}[/tex]
In conclusion, using the speed of the chord wave we can find a new speed when the mass is increased and the chord length is:
The velocity is: v = [tex]\frac{v_o}{3}[/tex]
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A motorcycle moves according to the velocity-time graph
shown in Figure 3.28. Find the average acceleration of
the motorcycle during each of the following segments of
the motion: (a) A, (b) B, and (c) C.
Answer:
a) 1 m/s²
b) -1 m/s²
c) 0 m/s² (constant speed, not accelerating)
Explanation:
A
delta speed = 10 - 0
delta time = 10 - 0
delta speed / delta time = 10/10
delta speed / delta time = 1
B
ds = 5 - 10
dt = 15 - 10
ds / dt = -5 / 5
ds / dt = -1
C
ds = 5 - 5
dt = 25 - 15
ds / dt = 0 / 10
ds / dt = 0
The average acceleration of A, B, and C will be 1 m/s², -1 m/s², and 0 m/s².
What is acceleration?An object is considered to have been accelerated if its velocity changes. Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign. These examples demonstrate how acceleration occurs whenever a moving object modifies its direction, speed, or both.
There are different types of acceleration :
Uniform accelerationNon-Uniform AccelerationAverage accelerationAverage acceleration is defined as the average change in velocity with respect to the average change in time.
SI unit is m/s² and it is vector quantity.
According to the question,
For A, Acceleration= (v₁-v₀)/(t₁-t₀)
⇒10-0/10-0
= 1 m/s².
For B, Acceleration= (v₃-v₂)/(t₃-t₂)
⇒5-10/15-10
= -1 m/s²
For C, Acceleration will be constant because change in velocity is constant, this is the case of uniform motion, so its acceleration is also going to be constant (as per the definition of acceleration change in velocity ratio change in time).
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2) A ray of light in air is approaching the boundary with water at an
angle of 52 degrees. Determine the angle of refraction of the light
ray. (Refractive index of air = 1, water = 1.33)
=
Answer:
Explanation:
ASSUMING the 52° is the angle of incidence measured from the perpendicular to the surface
n₁sinθ₁ = n₂sinθ₂
1 sin52 = 1.33sinθ₂
θ₂ = arcsin(sin52 / 1.33)
θ₂ = 36°
as measured from the perpendicular to the surface
10. What is Newton's 3rd Law?
O A. For every action there is an equal and opposite reaction.
B. Acceleration depends on two variables, the mass of the object and the amount of
force.
C. An object at rest will stay at rest, an object in motion will stay in motion, unless an
unbalanced force acts upon it.
D. The amount of matter in an object.
7. What is Newton's 2nd Law? *
Answer:
A. For every action there is an equal and opposite reaction.
Is acceleration included in a force diagram? Why?
Answer:
No
Explanation:
Acceleration is not a "Force"
The only things added on a force diagrams are forces that are acting on the object. Force causes acceleration to change but it is not a force itself and is not included on a force diagram.
Help please..
Kepler’s third law states that:
A. the orbits of the planets are elliptical.
B. the planets move slower when they are closer to the Sun and faster when they are farther from the Sun.
C. the square of the ratio of the periods of any two planets revolving around the Sun is equal to the cube of the ratio of their average distance from the Sun.
D. objects attract other objects with a force that is directly proportional to the product of their masses, and inversely proportional to the square of the distance between them.
Answer:
c
Explanation:
HELPP
When two forces are in opposite directions, and they are the exact same magnitude, the forces will _______.
a. subtract from each other
b. cancel out
c. go on infinitely
d. eventually reach equilibrium
Answer:
i think the correct answer is B. cancel out
The coefficient of kinetic friction for a 22 kg bobsled on a track is 0.10. What force is required to push it down a 5.0 degree incline and achieve a speed of 62 km/h at the end of 75 m
Hi there!
We must begin by converting km/h to m/s using dimensional analysis:
[tex]\frac{62km}{1hr} * \frac{1hr}{3600sec}*\frac{1000m}{1km} = 17.22 m/s[/tex]
Now, we can use the kinematic equation below to find the required acceleration:
vf² = vi² + 2ad
We can assume the object starts from rest, so:
vf² = 2ad
(17.22)²/(2 · 75) = a
a = 1.978 m/s²
Now, we can begin looking at forces.
For an object moving down a ramp experiencing friction and an applied force, we have the forces:
Fκ = μMgcosθ = Force due to kinetic friction
Mgsinθ = Force due to gravity
A = Applied Force
We can write out the summation. Let down the incline be positive.
ΣF = A + Mgsinθ - μMgcosθ
Or:
ma = A + Mgsinθ - μMgcosθ
We can plug in the given values:
22(1.978) = A + 22(9.8sin(5)) - 0.10(22 · 9.8cos(5))
A = 46.203 N
If it takes 50.0 seconds to lift 10.0 Newtons of books to a height of 7.0
meters, calculate the power required to lift it?
A 5 kg bowling ball travelling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of larger ball after the collision? Hint: Use the conservation of momentum equation to solve this problem.
Answer:
1.5 m/s
Explanation:
Conservation of momentum means the momentum of the system before the collision is the same as after.
The before, after momentum of each ball is ...
5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)
10 kg ball: (10 kg)(0 m/s), (10 kg)(v)
The sum of the "before" products is the same as the sum of the "after" products:
(5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v
(10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides
v = (15 kg·m/s)/(10 kg) = 1.5 m/s
The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.
6. A 15.53 kg bag of soil falls 5.50 m at a construction site. If all the energy is retained by the soil in the bag, how much will its temperature increase
The increase in the temperature of the soil when bag fall from the given height is 0.065 ⁰C.
The given parameters:
mass of the bag, m = 15.53 kgheight of fall, h = 5.5 mspecific heat capacity of soil, C = 0.200 kcal/kg ⁰CApply the principle of conservation of energy as follows;
[tex]mgh = mC \Delta T\\\\gh = C \Delta T\\\\\Delta T= \frac{gh}{C}[/tex]
Convert the value of C in kcal/kg ⁰C to J/kg ⁰C
1 kcal = 4180 J
[tex]0.200 \ kcal/kg ^0 C= 0.2 \times 4180 (J/kg ^0C) = 836 \ J/kg^0 C[/tex]
The increase in the temperature of the soil is calculated as follows;
[tex]\Delta T= \frac{gh}{C}\\\\\Delta T= \frac{9.8 \times 5.5}{836} \\\\\Delta T= 0.065 \ ^0C[/tex]
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An electromagnet does not attract a piece of iron.Is it true ? Give reason
Answer:
False..
Explanation:
An electoMagnets attract iron due to the influence of their magnetic field upon the iron. ...
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air acts as an ideal gas, calculate the work done per mol of the air.
A. -80.35 J
B. 80.35 J
C. -811.93 J
D. 811.93 J
(please show calculation)
can use this formula W=nRT ln(p1/p2)
Answer:
B.-80.35 J
i dont know the calculation
At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away
Answer:
op
Explanation:
At a distance of 1 cm from the source, the flux from the isotropic source is one hundred times brighter. Which source is brighter fifty centimeters away
i mark u brainliest answer please answer me
Answer:
bathing and wear clean clothes 2 pollute 3throwing waste in land air water pollution
Kinesha and her friend were watching a solar eclipse. Kinesha explains to her friend that a solar eclipse means that Earth is located between the Sun and the Moon. Her friend tells Kinesha that her explanation is incorrect. Why?
this is where the sun and moon line up where you asleep only a tiny bit of the sun it's pretty cool to see
Explanation:
a solar eclipse means when the moon goes infront of the sun and the earth turns dark
2. An auditorium has 58 seats in the first row, 62 seats in the second row, 66 seats in the third row, and so
on.
a)Find the explicit formula of this arithmetic sequence.
B) find the number of seats in the twentieth row.
A racecar can be slowed with a constant acceleration of -14 m/s2. If the car is going 75 m/s, how many meters will take to stop?
Answer:
Explanation:
v² = u² + 2as
s = (v² - u²)/2a
s = (0² - 75²) / (2(-14))
s = 200.8928
s = 200 m
Answer:
Identification
Explanation:
:-;..........
why is cooking faster with a pressure cooker. plz help me I beg
Explanation:
The same thing happened in pressure cooker but the temperature inside is most higher.
hope you like my answer
thank you
Because cooking reactions speed up at a higher temperature also the boiling temperature of water increases and hence, the food cooks faster.
source:
https://www.vedantu.com/question-answer/a-pressure-cooker-reduces-cooking-time-for-food-class-9-chemistry-cbse-5feaba32e9fb3d3419e4a61a
The less dense areas created as a sound wave propagates are called
A. rarefactions✅
B. troughs
C. crests
D. compressions
Answer:
C. crests
don't trust me though
Answer:
The less dense areas created as a sound wave propagates are called rarefactions.
Explanation:
Hoped this helped.
)Suppose you have two insulated buckets containing the same amount of water at room temperature. You also happen to have two blocks of metal of the same mass, both at the same temperature, warmer than the water in the buckets. One block is made of aluminum and one is made of copper. You put the aluminum block into one bucket of water, and the copper block into the other. After waiting a while you measure the temperature of the water in both buckets. Which is warmer
The water in the bucket containing the aluminium block is warmer than the bucket containing the copper block.
The specific heat is the amount of heat needed or required to elevate the temperature of 1 gram of a substance by 1° C.
At standard conditions;
the specific heat of aluminium = 0.215 cal/gm/° Cthe specific heat of copper = 0.0923 cal/gm/° CWe know that:
Heat loss by the metal block = Heat gained by the water bucketTherefore, since the specific heat of aluminium is higher than that of copper, the water bucket containing aluminium block will be warmer than the bucket containing the copper block.
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There is a uniform magnetic field of magnitude B, pervading all space, perpendicular to the plane of rod and rails. The rod is released from rest, and it is observed that it accelerates to the left. In what direction does the magnetic field point?
The right hand rule to find the direction of the magnetic field for a falling bar is:
The charge is positive the magnetic field is outgoing, horizontally and towards us. The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.
The magnetic force is given by the vector product of the velocity and the magnetic field.
F = q v x B
Where the bolds indicate vectors, F is the force, q the charge on the particle, v the velocity and B the magnetic field.
In the vector product, the vectors are perpendicular, which is why the right-hand rule has been established, see attached:
The thumb points in the direction of speed. Fingers extended in the direction of the magnetic field. The palm is in the direction of the force if the charge is positive and in the opposite direction if the charge is negative.
They indicate that the bar is dropped, therefore its speed is vertical and downwards, it moves to the left therefore this is the direction of the force, we use the right hand rule, the magnetic field must be horizontal, we have two possibilities:
If the charge is positive the magnetic field is outgoing, horizontally and towards us. If the charge of the bar is negative, the magnetic field is incoming, that is, horizontal away from us
In conclusion using the right hand rule we can find the direction of the magnetic field for a falling bar is:
The charge of the bar is negative, the magnetic field is incoming, that is horizontal away from us.The charge is positive the magnetic field is outgoing, horizontally and towards us.
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