Answer:
a mistake
Explanation:
Need help fast ! 10 points!
How is thermal energy different from heat?
A. Heat is a form of energy, while thermal energy is a form of energy transfer
B. Thermal energy is a form of energy, while heat is a form of energy transfer
According to force-field analysis, _____. change will occur when the sum of the opposing forces is zero equilibrium occurs when there are no forces acting for or against change change occurs when forces in one direction exceed forces in the opposing direction ignoring forces against change facilitates the change process
Answer: Change occurs when forces in one direction exceed forces in opposing direction
Explanation:
Force field analysis is the basic tool typically used in root cause analysis which enable an individual to take certain action after the identification of the root cause.
According to force-field analysis, there is a change when the forces in one direction exceed the forces in opposing direction.
explain how are frequency, wavelength, energy, and penetrating ability of the waves change and differ from one another PLEASE HELP YOU WILL GET 56 POINTS IT HAS TO BE CORRECT PLEASE HELP YOU WILL GET 56 POINT IT HAS TO BE CORRECT
If we compare the energy of visible light to the energy of X-rays, we find that X-rays have a much higher frequency. Usually, electromagnetic radiation with higher frequency (energy) have a higher degree of penetration than those with low frequency.
A ball dropped from a window strikes the ground 2.76 seconds later. How high is the window above the ground
Answer:
37.33m
Explanation:
Using the equation of motion
S = ut + 1/2gt^2
Time t = 2.76secs
g = 9.8m/s^2
S = 0 + 1/2(9.8)(2.76)^2
S = 4.9*7.6176
S = 37.33
Hence the window is 37.33m above the ground
Identify the part of the water cycle when ocean water may end up in the river.
Condensation.
Precipitation.
Collection.
Evaporation.
Answer:
Collection. or Precipitation.
Explanation:
b or d
The part of the water cycle when ocean water may end up in the river is to be considered as the condensation.
What is condensation?
It is the change with regard to the state of matter from the gas phase into the liquid phase. Also, it should be considered as the reverse of vaporization.
So based on this, we can say that The part of the water cycle when ocean water may end up in the river is to be considered as the condensation.
Learn more about water here: https://brainly.com/question/26094433
The coefficients of friction between the load and the flatbed trailershown are μs = 0.40 and μk = 0.30. Knowing that the speed of the rigis 72 km/h, determine the shortest distance in which the rig can bebrought to a stop if the load is not to shift
Answer:
50.97 m
Explanation:
m = Mass of truck
[tex]\mu_s[/tex] = Coefficient of static friction = 0.4
v = Final velocity = 0
u = Initial velocity = 72 km/h = [tex]\dfrac{72}{3.6}=20\ \text{m/s}[/tex]
s = Displacement
Force applied
[tex]F=ma[/tex]
Frictional force
[tex]f=\mu_s mg[/tex]
Now these forces act opposite to each other so are equal. This is valid for the case when the load does not slide
[tex]ma=\mu_s mg\\\Rightarrow a=\mu_s g\\\Rightarrow a=0.4\times 9.81\\\Rightarrow a=3.924\ \text{m/s}^2[/tex]
Since the obect will be decelerating the acceleration will be [tex]-3.924\ \text{m/s}^2[/tex]
From the kinematic equations we have
[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -3.924}\\\Rightarrow s=50.97\ \text{m}[/tex]
So, the minimum distance at which the car will stop without making the load shift is 50.97 m.
An ice-hockey player weighing 900 N is skating with a velocity of 8.0 m/s when they slam into a member of the opposing team who is standing still. They become tangled together and move down the ice with a velocity of 5.0 m/s. What is the mass of the other player
Answer:
Mass of player 2 is 55.044kg
Explanation:
Step one:
given data
Weight of player 1= 900 N
mass= weight/acceleration due to gravity
mass of player= 900/9.81
m1= 91.74kg
v1= 8m/s
mass of player 2
m2= ?
v2= 0m/s
Step two:
from the problem description, after impact, they both moved with a common velocity of V= 5m/s, hence the collision is an inelastic collision
the expression for inelastic collision is
m1v1+m2v2=(m1+m2)V
substitute
91.74*8+m2*0=(91.74+m2)5
733.92=458.7+5m2
275.22=5m2
divide both sides by 5
m2=275.22/5
m2=55.044kg
The weight of player two is
=55.044*9.81
=539.98N
A 1.25 m long string attached to a 60.0 Hz vibra
tor created a standing wave with 5 loops. What was the velocity of the waves in the string?
Unit= m/s
Answer:
The velocity of the waves in the string is 30 m/s.
Explanation:
Given;
frequency of the wave, F = 60.0 Hz
number of loops, n = 5
length of the string, L = 1.25 m
1 loop, L = λ/2
For 5 loops;
[tex]L = \frac{5\lambda}{2}[/tex]
where;
λ is the wavelength
[tex]L = \frac{5 \lambda}{2} \\\\5 \lambda = 2L\\\\\lambda = \frac{2L}{5} \\\\\lambda = \frac{2 \ \times \ 1.25}{5} \\\\\lambda = 0.5 \ m[/tex]
The velocity of the waves in the string is calculated as;
V = Fλ
V = (60)(0.5)
V = 30 m/s
Therefore, the velocity of the waves in the string is 30 m/s.
A car accelerates uniformly from rest to 23 m/s over a distance of 30 meters. What is the acceleration of the car?
Answer:
a= 17.69 m/s^2
Explanation:
Step one:
given data
A car accelerates uniformly from rest to 23 m/s
u= 0m/s
v= 23m/s
distance= 30m
Step two:
We know that
acceleration= velocity/time
also,
velocity= distance/time
23= 30/t
t= 30/23
t= 1.30 seconds
hence
acceleration= 23/1.30
accelaration= 17.69 m/s^2
A car moving at a speed of 36 km/h reaches the foot of a smooth
incline, when the engine is switched off. If the angle of inclination is 30
degrees, how much distance does the automobile travel up the ramp?
Answer:
d = 10.2 m
Explanation:
When the car travels up the inclined plane, its kinetic energy will be used to do the work in climbing up. So according to the law of conservation of energy, we can write that:
[tex]Kinetic\ Energy\ of\ the \ Car = Work\ Done\ while\ moving\ up\ the\ plane\\\frac{1}{2}mv^{2} = Fd[/tex]
where,
m = mass of car
v = speed of car at the start of plane = (36 km/h)(1000 m/1 km)(1 h/3600 s)
v = 10 m/s
F = force on the car in direction of inclination = W Sin θ
W = weight of car = mg
θ = Angle of inclinition = 30°
d = distance covered up the ramp = ?
Therefore,
[tex]\frac{1}{2}mv^{2} = mgdSin\theta\\\frac{1}{2}v^{2} = gdSin\theta\\\frac{1}{2}(10\ m/s)^{2} = d(9.81\ m/s^{2}) Sin\ 30^{0}[/tex]
d = 10.2 m
A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 29.0 m/s. Then the truck travels for 25.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s.
(a) How long is the truck in motion?
(b) What is the average velocity of the truck for the motion described?
Answer:
44.5s ; 22.64 m/s
Explanation:
The motion of the truck could be separated into 3 different phases :
First :
Time of motion :
Initial Velocity, u = 0 ; final velocity, v = 29 m/s
Acceleration, a = 2 m/s²
Recall: acceleration = change in velocity / time
Time = change in velocity / acceleration
Time = (29 - 0) / 2 = 14.5 second
Distance traveled = ((29 + 0) /2) * 14.5 = 210.25 m
Second :
Time = 25 seconds at constant speed
29 m/s for 25 seconds
v*t = 29 * 25 = 725 m
Third:
5 seconds before coming to rest
((29 + 0) /2) * 5
14.5 * 5 = 72.5 m
A.)
Length of journey = (14.5+ 25 + 5) = 44.5 seconds
B.)
Average velocity = total distance / total time taken
Average velocity = (210.25 + 725 + 72.5) / 44.5
= 1007.75 / 44.5
= 22.646067
= 22.64 m/s
5.
A constant force of 15 N in the negative y direction acts on a particle as it moves from the origin
to the point (3î +31 - 1k) m. How much work is done by the given force during this
displacement?
+45 J a.
-45 J b.
+30 J C.
-30 J d.
+75 J e.
The work done by the given force should be -45 joules
Calculation of the work done:
Since force acts in the negative y direction
So,
F = -15j
here the displacement vector is d = 3i+3j-1k
Now
work done is W = dot product of force and displacement
= [-15j ] . [ 3i+3j-1k]
=-45 joules
Therefore, The work done by the given force should be -45 joules
Learn more about force here:
https://brainly.com/question/93252
In a chemical reaction atoms will do what?
How much mass is required to exert a force of 25 Newtons, accelerating at 5 m/s2?
Answer:
5
Explanation:
pls help
Tell me something you know about football. (i.e. how to play the game, a team, players)
some positions are quarterback, offence, defense, linebacker, and wider receiver hoped it helped :)
In Europe, gasoline efficiency is measured in km/L. If your car's gas mileage is 32.0 mi/gal , how many liters of gasoline would you need to buy to complete a 142-km trip in Europe
Answer:
10.44 liters of gasoline.
Explanation:
First, we need to convert the units of the car from mi/gal to km/L as follows:
[tex] mileage = 32.0 \frac{mi}{gal}*\frac{1.609 km}{1 mi}*\frac{1 gal}{3.785 L} = 13.60 km/L [/tex]
That means that for every liter of gasoline the car travels 13.60 kilometers.
So, to complete a 142-km trip in Europe the volume of gasoline needed is:
[tex] V = \frac{1 L}{13.60 km}*142 km = 10.44 L [/tex]
Therefore, to complete a 142-km trip in Europe we need to buy 10.44 liters of gasoline.
I hope it helps you!
If your mass is 68.05 kg,how much gravitational force would you experience on mars?
Given :
Mass, m = 68.05 kg.
To Find :
How much gravitational force would you experience on mars ?
Solution :
Acceleration due to gravity on mars is, g = 3.711 m/s²
( You can find it on internet )
Now, weight can be given as :
W = mg
W = 68.05 kg × 3.711 m/s²
W = 252.533 kg m/s² = 252.533 N
Hence, this is the required solution.
Consider the table, graph, and equation below. Which of the three has the greater
rate of change, if any? Explain your reasoning
10 points
8
6
2
2
6
do
o
1
2
3
3
6
9
12
y=0.5x + 1
FASHIDYF2A ChamondBAN 40N6zdoldY2RENVKhulo YeOA/formResponse
Answer:
.
Explanation:
A string, 0.28 m long and vibrating in its third harmonic, excites an open pipe that is 0.82 m long into its second overtone resonance. The speed of sound in air is 345 m/s. The speed of transverse waves on the string is closest to
Answer:
117.8 m/s
Explanation:
Given that:
String length, L = 0.28
pipe length, L' = 0.82
Speed of sound in air, v = 345 m/s
n = 3 (3rd harmonic)
Frequency, f of 3rd harmonic ;
f = (v*n) / 2L - - - - (1)
for the pipe: ; 3rd harmonic
f = (v*n) / 2L' - - - (2)
Equating (1) and (2)
(v*n) / 2L = (v*n) / 2L'
2L' * v * n = v* n * 2L
v = vL / L'
v = (345 * 0.28) / 0.82
v = 96.6 / 0.82
v = 117.80487
v = 117.8 m/s
Saturn's volume is more than 10,000 times as large as Mercury's.
true
false?
Since Saturn's volume is equivalent to 763.59 earths and Mercury is only 0.055 of one earth, then Saturn's volume is over 10,000 times larger than Mercury's.
Answer: TRUE
Moving a ball up a hill
O A. increases its chemical energy
OB. decreases its chemical energy
O C. increases its potential energy
OD. decreases its potential energy
Answer:
C increase in potential energy
How will you know which dye diffuses the most quickly?
Answer:
If there is a large difference between the concentration of one fluid and the concentration of the other, then the particles will diffuse faster. In the experiment, the dye particles in the food coloring are very concentrated.
Explanation:
A 16.9 kg monkey is swinging on a 5.32 m long vine. It starts at rest, with the vine at a 43.0° angle. How fast is the monkey moving at the bottom of its swing? (Unit = m/s)
Answer:
v = 5.7554 m/s
Explanation:
First of all we need to know if the angle of the vine is measured in the horizontal or vertical.
To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:
h₀ = h sinα
h₀ = 5.32 sin43° = 3.6282 m
As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:
Δh = 5.32 - 3.63 = 1.69 m
In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:
Ep = Ek
From here, we can calculate the speed of the monkey.
Ep = mgΔH
Ek = 1/2 mv²
The potential energy is:
Ep = 16.9 * 9.8 * 1.69 = 279.9
Now with the kinetic energy:
1/2 * (16.9) * v² = 279.9
v² = (279.9) * 2 / 16.9
v² = 33.12
v = √33.12
v = 5.7554 m/sHope this helps
A 9800 N car traveling at 22 m/s strikes a concrete bridge support and comes to a complete halt in 0.5 sec. Calculate the impulse of the force.
Answer:
21977.56kg⋅m/s
Explanation:
Step one:
Given data
Weight of car= 9800N
The mass of the car is
m= w/g
m= 9800/9.81
m=998.98kg
Velocity of car= 22 m/s
time of impact= 0.5 seconds
Required
The impulse of the force F
Step two:
Ft= mv
Ft= 998.98*22
Ft=21977.56kg⋅m/s
The impulse is 21977.56kg⋅m/s
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with a frequency of 41.2 kHz. A car is approaching him at a speed of 33.0 m/s. The wave is reflected by the car and interferes with the emitted sound producing beats. What is the frequency of the beats
Answer:
the frequency of the beats is 8.7687 kHz
Explanation:
Given the data in the question;
The frequency for stationary source and moving observer is;
f' = f( 1 +( v_observer/v_sound))
we know that, speed of sound in dry air = 343 m/s
so we substitute
f' = 41.2 kHz( 1 + (33.0 m/s / 343 m/s) ) = 41.2kHz( 1 + 0.0962) = 41.2kHz(1.0962)
f' = 45.1634 kHz
Now the frequency for stationary observer and moving source with frequency f' will be
f" = f'( 1 / (1 - ( v_observer/v_sound)))
45.1634 kHz( 343 / 343 - 33)
we substitute
f" = 45.1634 kHz( 1 / (1 - (33.0 m/s / 343 m/s)))
f" = 45.1634 kHz( 1 / (1 - 0.0962))
f" = 45.1634 kHz( 1 / 0.9038 )
f" = 45.1634 kHz( 1.1064 )
f" = 49.9687 kHz
Now the beat frequency will be;
f_beat = f' - f
we substitute
f_beat = 49.9687 kHz - 41.2 kHz
f_beat = 8.7687 kHz
Therefore, the frequency of the beats is 8.7687 kHz
Two charged particles, with charges q1=qq1=q and q2=4qq2=4q, are located on the x axis separated by a distance of 2.00cm2.00cm . A third charged particle, with charge q3=qq3=q, is placed on the x axis such that the magnitude of the force that charge 1 exerts on charge 3 is equal to the force that charge 2 exerts on charge 3.Find the position of charge 3 when qqq = 2.00 nCnC .
Answer: Charge 3 is located on the x-axis a distance of 0.67 cm from charge 1 and 1.33 cm from charge 2.
Explanation: Electrostatic Force is the force of repulsion or attraction between two charged particles. It's directly proportional to the charge of the particles and inversely proportional to the distance between them:
[tex]F=k\frac{|q||Q|}{r^{2}}[/tex]
k is an electrostatic constant
For the system of 3 particles, suppose distance from 1 to 3 is x meters, so, distance from 2 to 3 is (0.02-x) meters.
Force will be
[tex]F_{13}=F_{23}[/tex]
[tex]k\frac{q_{1}q_{3}}{r_{13}^{2}} =k\frac{q_{2}q_{3}}{r_{23}^{2}}[/tex]
[tex]\frac{q_{1}}{r_{13}^{2}} =\frac{q_{2}}{r^{2}_{{23}}}[/tex]
Substituting:
[tex]\frac{2.10^{-6}}{x^{2}} =\frac{8.10^{-6}}{(0.02-x)^{2}}[/tex]
[tex]8.10^{-6}x^{2}=2.10^{-6}(0.0004-0.04x+x^{2})[/tex]
[tex]4x^{2}=x^{2}-0.04x+0.0004[/tex]
[tex]3x^{2}+0.04x-0.0004=0[/tex]
Solving quadratic equation using Bhaskara:
[tex]x_{1}=\frac{-0.04+\sqrt{(0.04)^{2}+0.048} }{6}[/tex]
[tex]x_{2}=\frac{-0.04-\sqrt{(0.04)^{2}+0.048} }{6}[/tex]
x₂ will give a negative value and since distance can't be negative, use x₁
[tex]x_{1}=\frac{-0.04+\sqrt{0.0064} }{6}[/tex]
x₁ = 0.0067 m
The position of charge 3 is 0.67 cm from charge 1 and 1.33 cm from charge 2.
HELP URGENT WILL GIVE BRAINLIEST
Answer:
F • t= m•∆v
Explanation:
the impulse experienced by the object equals the change in momentum of the object. in equation form: F • t= m•∆v
forces applied to the collision
Answer: I think this is the answer, In a collision, there is a force on both objects that causes an acceleration of both objects; the forces are equal in magnitude and opposite in direction. For collisions between equal-mass objects, each object experiences the same acceleration.
Explanation: I had a question similar to this, Hope this helps!
A container with a mass of 5 kg is lifted to a height of 8m
Answer:
392 Nm or J
Explanation:
Work is equal to force times distance. The force required is the mass times acceleration - in this case F = 5kg x 9.81 ( gravity) = 49N. So work is 49N x 8m = 392 Nm or Joules.
Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 478 N/C. If the particles are free to move, what are their speeds (in m/s) after 52.4 ns
Answer:
the speed of electron is 4.42 x 10⁶ m/s
the speed of proton is 2406.7 m/s
Explanation:
Given;
electric field strength, E = 478 N/C
charge of the particles, Q = 1.6 x 10⁻¹⁹ C
mass of proton, Mp = 1.673 x 10⁻²⁷ kg
mass of electron Me = 9.11 x 10⁻³¹ kg
time of motion, t = 54.2 ns = 54.2 x 10⁻⁹ s
The magnitude of charge experienced by the particles is calculated as;
F = EQ
F = 478 x 1.6 x 10⁻¹⁹
F = 7.648 x 10⁻¹⁷ N
The speed of the particles is calculated as;
[tex]F = \frac{mv}{t} \\\\v = \frac{Ft}{m} \\\\v_e = \frac{(7.684 \times 10^{-17})(52.4\times 10^{-9})}{9.11\times 10^{-31}} \\\\v_e = 4.42 \ \times \ 10^6 \ m/s[/tex]
[tex]v_p = \frac{Ft}{m_p} \\\\v_p = \frac{(7.684 \times 10^{-17})(52.4\times 10^{-9})}{1.673\times 10^{-27}} \\\\v_p = 2406.7 \ m/s[/tex]
