Answer:
A. (6x + 7)(6x - 7)
Step-by-step explanation:
use difference of squares, which says a^2 - b^2 =(a+b)(a-b)
take the square roots of the two numbers, 6x and 7, and use them as a and b
Priya wants to sketch a graph of the polynomial f defined by f(x)=x^3+5x^2+2x-8. She knows f(1)=0, so she suspects that (x-1) could be a factor of x^3+5x^2+2x-8 and writes (x^3+5x^2+2x-8) = (x-1) (?x^2+?x+?) and draws a diagram.
1. Finish Priya's diagram
2. Write f(x) as the product of (x-1) and another factor.
3. Write f(x) as the product of three linear factors.
4. Make a sketch of y=f(x).
Given the polynomial f(x)=x³+5x²+2x-8 and f(1)=0.
Factorization is the process of determining the components of a given value or mathematical statement. The integers that are multiplied to create the original number are known as factors. The components of 18 include, for instance, 2, 3, 6, 9, and 18, as well as;
18 = 2 x 9
18 = 2 x 3 x 3
18 = 3 x 6
In a similar way, the factors in the case of polynomials are the polynomials that are multiplied to create the original polynomial. For instance, (x + 2) (x + 3) are the elements of x2 + 5x + 6. The original polynomial is produced when we multiply both x +2 and x +3. We can also locate the polynomials' zeros after factorization. Zeroes in this situation are x = -2 and x = -3.
2. Now, to write f(x) as the product of (x-1) and another factor.
x³+5x²+2x-8 = (x-1)(x²-6x+8).
3. Now, to write f(x) as the product of three linear factors.
x³+5x²+2x-8 = (x-1)(x²-6x+8)= (x-1)(x-4)(x-2)
4. Look at the sketch below.
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image Which of the following statements is true for ∠a and ∠b in the diagram?
Answer:
You have not added a picture soi can not help answer this question.
Step-by-step explanation:
Add the picture by either taking a photo or screenshot of the question then upload it.
HELP ASAP PLS ILL MARK YOU BRAINLIEST
Answer:
c is the answer.
Alison has three times as many dimes as quarters in her purse. She has $9.35 altogether. How many coins of each type does she have?
========================================================
Work Shown:
x = number of quarters
3x = number of dimes
0.25x = value of just the quarters, in dollars
0.10(3x) = 0.30x = value of just the dimes, in dollars
0.25x+0.30x = 0.55x = total value in dollars
0.55x = 9.35
x = (9.35)/(0.55)
x = 17
Alison has 17 quarters and 3x = 3*17 = 51 dimes
17 quarters = 17*0.25 = $4.25
51 dimes = 51*0.10 = $5.10
17 quarters + 51 dimes = $4.25 + $5.10 = $9.35
The answers are confirmed.
This should be easy. Answer it please :D
Answer:
is it 1 ques or 4 different questions?
what is 10.465 - (-25.21)
Answer: 35.675
Step-by-step explanation:
10.465−(−25.21)
The opposite of −25.21 is 25.21.
10.465+25.21
Add 10.465 and 25.21 to get 35.675.
35.675
Please answer!!
-3 + 4/7 - 1/5
Step-by-step explanation:
please mark me as brainlest
Answer:
-92/35
Step-by-step explanation:
-3 + 4/7 - 1/5 =
-21/7 + 4/7 - 1/5 =
-(21*5) / (7*5) + (4*5)/(7*5) - (1*7)/(5*7) =
-105/35 + 20/35 - 7/35 =
-105+20-7 / 35 = -92/35
Determine the inequality that can be used to model when the population of bacteria will be greater than or equal to 656,100. Then solve the inequality for t.
The inequality is 100*[tex]3^{t}[/tex]≤ 656100.
The correct option is (B).
What is inequality?A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.
Given:
From the table attached below:
a=300, r= 900/300 = 3
As, it is GP
Now,
f(t) = [tex]ar^{t-1}[/tex]
f(t) = [tex]300*3^{t-1}[/tex]
f(t) = 300/3 *[tex]3^{t}[/tex]
f(t) = 100*[tex]3^{t}[/tex]
Inequality is used to determine greater than or equal to 656100
100*[tex]3^{t}[/tex]≤ 656100
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3. Find the measure of angle TOS in the figure below.
∠ROQ and ∠TOS are vertically opposite angles, so must be equal, which means they are 122°
∠TOS = 122°Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?
The function g(x) = ∛(x -3) is positive at the interval x > 3
Complete questionGiven g(x) = ∛(x -3), on what interval is the function positive?
How to determine the positive interval?The function is given as:
g(x) = ∛(x -3)
Set the radicand to positive
x - 3 > 0
Add 3 to both sides
x > 3
Hence, the function is positive at the interval x > 3
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1
A circle is defined by the equation given below.
x² + y²
2y -
What are the coordinates for the center of the circle and the length of the radius?
X
= 0
ig Algebr
OA. (1, 1), 2 units
OB. (-1,-1), 2 units
OC. (,1), 4 units
OD. (-1,-1), 4 units
Reset
Next
The coordinates for the center and length of the radius of this circle are equal to (½, 1), 2 units.
How to determine the coordinates?Mathematically, the standard form of the equation of a circle is given by;
(x - h)² + (y - k)² = r²
Where:
h and k represent the coordinates at the center.r is the radius of a circle.In order to determine the coordinates for the center and the length of the radius of this circle, we would use completing the square method:
x² + y² - x - 2y - 11/4 = 0
x² - x + ¼ + y² - 2y = 11/4 + ¼
(x - ½)² + y² - 2y + 1 = 12/4 + 1
(x - ½)² + (y - 1)² = 4
Comparing with the standard form, we have:
h = ½k = 1r = √4 = 2 units.Read more on circle here: https://brainly.com/question/14078280
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Complete Question:
A circle is defined by the equation given below.
x^2 + y^2 − x − 2y − 11/4 = 0
What are the coordinates for the center of the circle and the length of the radius?
Please help!!!
Consider the segment UV.
Type the correct answer in each box. Use numerals instead of words.
The scale on a map is 1 : 25000
How many kilometres on the ground is represented by 7 cm on the map?
Answer:
175000 km
Step-by-step explanation:
the 1:25000 essentially means that every centimeter represents 25000 kilometers. so the answer is 175000 by multiplying 7 and 25000
What is the missing reason in the proof?
A.) Segment addition
B.) Congruent Segments Theorem
C.) Transitive Property of Equality
D.) Subtraction Property of Equality
Answer:
I think it's C. transitive property of equality
Given the function, f(x)=√x-2 +3, choose the correct transformation.
right 2, up 3
Right2, down 3
left 2, up 3
left 2, down 3
There are 12 ducks and 11 geese in a certain park. Find the ratio of geese to ducks.
Tried every app none have the answer please help
Answer:
opotion has not correct answer
answer is 15.
Answer:
[tex]3^\frac{7}{10}[/tex] or [tex]\sqrt[10]{3^7}[/tex]
Step-by-step explanation:
[tex]\left(\sqrt{3}\right)\left(\sqrt[5]{3}\right)=\sqrt[10]{3^7}\quad[/tex]
(√3)([tex]\sqrt[5]{3}[/tex]) = √3 · [tex]\sqrt[5]{3}[/tex]
{√3 = [tex]3^{\frac{1}{2}}[/tex]} {radical rule: [tex]\sqrt{x}=x^1^/^2[/tex]}
[tex]\sqrt3[/tex][tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex]
{[tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{5}}[/tex]} {radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex]}
[tex]3^{\frac{1}{2}}[/tex] · [tex]\sqrt[5]{3}[/tex] = [tex]3^{\frac{1}{2}}[/tex] · [tex]3^{\frac{1}{5}}[/tex] {exponent rule: [tex]a^x*a^y=a^x^+^y[/tex]}
(1/2 + 1/5 = 5/10 + 2/10 = 7/10)
[tex]=3^\frac{7}{10}[/tex] {opposite of radical rule: [tex]\sqrt[n]{x} = x^1^/^n[/tex] ; [tex]x^\frac{a}{b}=\sqrt[b]{x^a}[/tex]}
= [tex]\sqrt[10]{3^7}[/tex]
so, the simplified version of this equation can either be written as:
[tex]3^\frac{7}{10}[/tex] or [tex]\sqrt[10]{3^7}[/tex]
hope this helps!!
(I can't clearly see the last option, but if it's either of these, then it's correct)
2(2x – 1) + 7 < 13 or –2x + 5≤-10
Answer:
x<2 or x ≥ 15/2
Step-by-step explanation:
What is the value of y?
Enter your answer in the box
Y=_
Answer:
the angles of a triangle always equal 180 so
34+x-5+4y=180
simplify
29+x+4y=180
-29
x+4y=151
-4y
x=-4y+151
then put this into the original equation
29-4y+151+4y=180
simplify
29+151=180
so this proves that this works
-1/4x-151=y
Hope This Helps!!!
I’m confused nd stuck
Answer:
B. (4,2)
Step-by-step explanation:
The answer is where the lines intersect.
Hope this helps!
If not, I am sorry.
Answer:
(4,2)
Step-by-step explanation:
the solution is where both lines intersect. We would write the point as (x,y). That’s why the answer is (4,2) not (2,4)
i need this answer a.s.a.p!!!
Answer:
Should have ended with "at most -15, not "at least -15."
Step-by-step explanation:
[tex]\leq[/tex] -15 means less than or equal to -15
So it can be -15, but also anything less than -15. The phrase "at most -15, not "at least -15" says exactly that.
What is the product? Assume x>0.
(√3x + √5)√15x+2√30
O 3x√√5+3√165x+10-√√6
O 3x√5 +6√10x +5√3x +10√/6
O 3x√5+10√6
0 6√3x+10√6
Step-by-step explanation:
well you can distribute the sqrt(15x) to the (√3x + √5) and then combine the radicals using the product property of radicals: [tex]\sqrt[n]{a} * \sqrt[n]{b} = \sqrt[n]{ab}[/tex].
[tex](\sqrt{3x} + \sqrt{5})\sqrt{15x} + 2\sqrt{30}\\(\sqrt{3x} * \sqrt{15x}) + (\sqrt{5} * \sqrt{15x}) + 2\sqrt{30}\\\sqrt{45x^2} + \sqrt{75x} + 2\sqrt{30}\\[/tex]
Now we can simplify the radicals using the same property we used to combine them but instead of combining into one radical we'll separate them into two radicals where one of the radicals simplifies into a number without a radical
[tex](\sqrt{9} * \sqrt{x^2} * \sqrt{5}) + (\sqrt{25} * \sqrt{3x}) + 2\sqrt{30}\\3x\sqrt{5} + 5\sqrt{3x} + 2\sqrt{30}[/tex]
What is the midpoint of the class interval 80-89?
The midpoint of the class interval 80-89 is 84.5.
What is mid point of a class interval?The mid point of a class interval is also called the class mark of the class interval.
The midpoint is defined as the average of the upper and lower class limits.
Therefore, the midpoint of the class interval 80-89 can be calculated as follows:
mid point = 80 + 89 / 2
mid point = 169 / 2
mid point = 84.5
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Which is not a characteristic of the absolute value parent function?
Answer:
B
Step-by-step explanation:
the range of y=|x| is not all real numbers its [0,inf)
sign - ...
Zekrom
tan A + sin A/tan A-sin A
= sec A +1/sec A-1
We need to prove
[tex]\frac{\tan A+\sin A}{\tan A-\sin A}=\frac{\sec A+1}{\sec A-1}[/tex]
[tex]\text{LHS}=\frac{\tan A+\sin A}{\tan A-\sin A}\\\\=\frac{\frac{\sin A}{\cos A}+\sin A}{\frac{\sin A}{\cos A}-\sin A}\\\\=\frac{\sin A+\sin A \cos A}{\sin A-\sin A \cos A}\\\\=\frac{\sin A(1+\cos A)}{\sin A(1-\cos A)}\\\\=\frac{1+\cos A}{1-\cos A}\\\\=\frac{1+\frac{1}{\sec A}}{1-\frac{1}{\sec A}}\\\\=\frac{\sec A+1}{\sec A-1}\\\\ =\text{RHS}[/tex]
Estimate the sum
6 13/28 + 8 3/32
Answer:
14 will be the answer...
Step-by-step explanation:
6 13/28 = 6
8 3/32 = 8
6 + 8 = 14
can you help me solve this question
Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6
Step-by-step explanation:
a^2+b^2=c^2
3^2+2^2=c^2
9+4=c^2
13=c^2
3.6=c
Use the multiplication law for logarithm to expand the following expression:[tex]log_{8} (21)[/tex]
- worth 20pt
Answer:
[tex]\log_8{(3)} + \log_8{(7)}[/tex]
Step-by-step explanation:
Product Rule for Logarithms
[tex]\log_b{(mn)} = \log_b{(m)} + \log_b{(n)}[/tex]
Instead of 21 you can write 3 · 7, because 21 = 3 · 7.
[tex]\log_8{(21)} = \\= \log_8{(3 \cdot 7)} =\\= \log_8{(3)} + \log_8{(7)}[/tex]
Find all solutions of the equation in the interval .
Write your answer in radians in terms of .
If there is more than one solution, separate them with commas.
The solutions to the trigonometric equation in the desired interval are given as follows:
[tex]\theta = \frac{\pi}{3}, \theta = \frac{5\pi}{3}[/tex]
What is the solution to the trigonometric equation?The trigonometric equation is given by:
[tex]\sqrt{3}\cot{\theta} - 1 = 0[/tex]
Solving it similarly to an equation, we have that:
[tex]\sqrt{3}\cot{\theta} = 1[/tex]
[tex]\cot{\theta} = \frac{1}{\sqrt{3}}[/tex]
Since [tex]\cot{\theta} = \frac{1}{\tan{\theta}}[/tex], we have that the equation is equivalent to:
[tex]\tan{\theta} = \sqrt{3}[/tex]
The tangent is positive in the first and in the fourth quadrant. In the first quadrant, the angle [tex]\theta[/tex] with [tex]\tan{\theta} = \sqrt{3}[/tex] is:
[tex]\theta = \frac{\pi}{3}[/tex]
In the fourth quadrant, the equivalent angle is:
[tex]\theta = 2\pi - \frac{\pi}{3} = \frac{5\pi}{3}[/tex]
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help pls i’ll do anything D:
Answer:
search it up ok that's all you can do