The approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.
To find the approximate mean, first, we add all the numbers in the data set, and then we divide that sum by the total number of values in the data set.
The formula for finding the approximate mean is as follows: Approximate mean = sum of the values in the data set / total number of values in the data set.
The following data set is given: Number of cars sold by a salesman in the past 10 weeks: 3, 5, 2, 4, 7, 5, 6, 3, 2, 4.
To find the approximate mean, we first need to add all the values: 3 + 5 + 2 + 4 + 7 + 5 + 6 + 3 + 2 + 4 = 41 The sum of all the values is 41.
Next, we need to divide this sum by the total number of values in the data set. In this case, the total number of values is 10. Therefore, the approximate mean for the given data set is: Approximate mean = 41 / 10 = 4.1
Therefore, the approximate mean of the number of cars sold by the salesman in the past 10 weeks is 4.1.
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Triangle DEF has vertices at D(−3, 5), E(−10, 4), and F(−11, 8). Triangle D′E′F′ is the image of triangle DEF after a reflection. Determine the line of reflection if D′ is located at (3, 5).
y = 5
x = −3
y-axis
x-axis
The line of reflection for the image of triangle DEF is the y-axis.
To determine the line of reflection for the image of triangle DEF, we need to find the axis along which the reflection occurred. We can do this by examining the coordinates of the corresponding points before and after the reflection.
Given that D' is located at (3, 5) after the reflection, we can compare the x-coordinates of D and D'. The x-coordinate of D is -3, and the x-coordinate of D' is 3. We notice that there is a change in sign, indicating a reflection across the y-axis.
Therefore, the line of reflection for the image of triangle DEF is the y-axis.
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Select the expression that is equivalent to (n²-25)
A. n² +10n - 25
B. n²-10-25
C. (n+5)(n-5)
D. (n-5) ²
Answer:
C. (n+5)(n-5)
Step-by-step explanation:
Select the expression that is equivalent to (n²-25)
Let's check each option. A and B are wrong, so we only check C & D.
C. (n + 5) (n - 5)
n² - 5n + 5n - 25
n² - 25
D. (n - 5)²
(n - 5) (n - 5)
n² - 5n - 5n + 25
n² - 10n + 25
So, the correct answer is C. (n+5)(n-5)
LU In a class of y children, n mathematics books, each costing p shillings, were lost. The teacher decided that the cost of the lost books be shared equally among the children. How much money did each child pay?
In the class , each child needs to pay (n * p) / y shillings to cover the cost of the lost books.
In the given scenario, there is a class of "y" children, and "n" mathematics books were lost, each costing "p" shillings. The teacher decides to distribute the cost of the lost books equally among all the children.
To find out how much money each child needs to pay, we need to divide the total cost of the lost books by the number of children in the class.
The total cost of the lost books can be calculated by multiplying the number of lost books ("n") by the cost of each book ("p").
Total cost = n * p
To distribute the cost equally among all the children, we divide the total cost by the number of children ("y"):
Cost per child = Total cost / Number of children
Substituting the values, we get:
Cost per child = (n * p) / y
Therefore, each child in the class needs to pay (n * p) / y shillings to cover the cost of the lost books.
It's important to note that this calculation assumes that the total cost is evenly distributed among all the children, regardless of whether they were responsible for losing the books or not.
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Select the correct answer. If function g has the factors (x − 7) and (x + 6), what are the zeros of function g? A. -7 and 6 B. -6 and 7 C. 6 and 7 D. -7 and -6
Answer:
-6 and 7.
Step-by-step explanation:
If we have a function called g, and we know that it has two factors: (x - 7) and (x + 6), then we can find the values of x that make g equal to zero. We call those values the "zeros" of the function g. To find the zeros, we just need to solve the equation (x - 7)(x + 6) = 0. The answer is that the zeros of g are -6 and 7.
3
2
пал
2 4
6 8 10
1
-1
Determine the period.
-2
-3
14/
The period of the function in this problem is given as follows:
5 units.
How to obtain the period of the function?A periodic function is a function that has the behavior repeating over intervals in the domain of the function.
Then the period of the function has the concept defined as the difference between two points in which the function has the same behavior.
Two consecutive peaks of the graph of the function in this problem are given as follows:
Input of 1 and input of 6.
Hence the period of the function is given as follows:
6 - 1 = 5 units.
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A cell phone company charges an initial price of $500 for a new phone and then $60 each month after the purchase. If C (t) is a rational function that represents the average monthly cost of owning the cell phone, what is the range of the function?
The range of the rational function is the set of all real numbers larger than 60 but less than 560, therefore;
Range; [60, 560]
What is a rational function?A rational function, f(x) is a function that can be expressed in the form f(x) = p(x)/q(x), where the functions p(x) and q(x) are polynomial functions.
The initial fee charged by the cell phone company = $500
The monthly charge after purchase = $60
The total cost of owning the cell phone = $500 + $60·t
The average monthly cost of owning a cell phone is therefore;
C(t) = (500 + 60·t)/t
The range of the function is the set of all possible values o C(t), which can be frond from the limit of the function, as follows;
[tex]\lim\limits_{x\to\infty}C(t) = \lim\limits_{x\to\infty}\frac{500 + 60\cdot t}{t} = \lim\limits_{x\to\infty}(\frac{500 }{t} + 60)[/tex] = 60
The limit of the average monthly cost indicates that the range of the function approaches $60 as t approaches infinity.
When t = 1, we get; C(1) = (500 + 60 × 1)/1 = 560
The range of the function is therefore, the set of all real numbers, larger than $60 but less than $560
The range of the function is therefore; [60, 560]
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Q1. An industry analyst wants to compare the average salaries of two firms, both to each other and to the industry. Firm A's average salary is 93% of the industry average, Firm B's average salary is $58,000, and the industry average salary is 96% of Firm B's average salary. a. Determine the industry average salary. b. Determine Firm A's average salary. c. Express Firm B's average salary as a percentage of Firm A's average salary. Round the percentage to two decimals.
a.The Industry Average Salary is $55,680. b.The Firm A's Average Salary is $51,718.40 .c. Firm B's average salary is approximately 112.27% of Firm A's average salary.
a. To determine the industry average salary, we can use the information that the industry average salary is 96% of Firm B's average salary. Firm B's average salary is $58,000. Therefore, we can calculate the industry average salary as follows:
Industry Average Salary = 96% of Firm B's Average Salary
= 0.96 * $58,000
= $55,680
b. Firm A's average salary is stated as 93% of the industry average salary. To calculate Firm A's average salary, we can multiply the industry average salary by 93%:
Firm A's Average Salary = 93% of Industry Average Salary
= 0.93 * $55,680
= $51,718.40
c. To express Firm B's average salary as a percentage of Firm A's average salary, we can divide Firm B's average salary by Firm A's average salary and multiply by 100:
Percentage = (Firm B's Average Salary / Firm A's Average Salary) * 100
= ($58,000 / $51,718.40) * 100
≈ 112.27%
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(BRAINLIEST AND 95 PTS TO CORRECT ANSWER!! PLS HELP!!) Part B: A student would like to show their teacher that they have practiced long enough for the day. Which measure of center should the student give to their teacher? Explain your answer. (2 points)
The measure of center that the student should give to their teacher is the median.
What is median, in statistics?In statistics, the median is a measure of central tendency that represents the middle value in a dataset when it is ordered from least to greatest. It divides the dataset into two equal halves, where half the values are smaller than the median and half are larger.
The median is useful because it is not influenced by extreme values or outliers in the dataset, unlike the mean (average). It provides a representative value that indicates the central position of the data.
The median is a better measure of center in this case since the data is skewed. The value of median is not affected by skewness
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The ordered pair (2, 10) is a point on a direct variation equation. Write the direct variation equation.
Answer:
Y=KX so its 10=K2
Step-by-step explanation:
Plug in the Number OR K=y/x
f(x) = 8x – 2
g(x) = 9x + 2
What is h(x) = f(x) – g(x)?
h(x) = 17x + 14
h(x) = x + 4
h(x) = –x – 4
h(x) = –x + 14
Answer:
h(x) = -x - 4
Step-by-step explanation:
Given:
f(x) = 8x - 2
g(x) = 9x + 2
Substituting these values into the equation h(x) = f(x) - g(x)
h(x) = (8x - 2) - (9x + 2)
Simplify
h(x) = 8x - 2 - 9x - 2
Combining like terms
h(x) = (8x - 9x) - (2 + 2)
h(x) = -x - 4
Hope this helps.
Identify the value of x. Give your answers in simplest radical form.
The figure shows right triangle A B C. Angle A B C is a right angle. Angle A C B measures 45 degrees. Side A B has a length of 3 units. Hypotenuse A C has a length of x units.
The value of x, representing the length of the hypotenuse AC, is 3√2 units.
In a right triangle ABC, with angle ABC measuring 45 degrees and side AB having a length of 3 units, we can use trigonometric ratios to find the length of the hypotenuse AC, represented by x.
Since angle ABC is 45 degrees, we know that it is a special right triangle, specifically a 45-45-90 triangle.
In such a triangle, the lengths of the sides are in a specific ratio: 1:1:√2.
In this case, side AB is 3 units, which represents the length of one of the legs. By the ratio mentioned earlier, the hypotenuse AC (x) will be √2 times the length of AB.
Therefore, we have:
AC = AB [tex]\times[/tex] √2
AC = 3 [tex]\times[/tex] √2
AC = 3√2 units
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simplify 1200×1260÷800 leaving your answer in standard form
The simplified form of the expression 1200 × 1260 ÷ 800 in standard form is 1890.
To simplify the given expression, we perform the multiplication and division operations according to the order of operations (PEMDAS/BODMAS).
First, we perform the multiplication: 1200 × 1260 = 1,512,000.
Next, we perform the division: 1,512,000 ÷ 800 = 1890.
The result, 1890, is in standard form.
In standard form, a number is expressed as a product of a number between 1 and 10 (inclusive) and a power of 10. In this case, 1890 is already in the appropriate format and does not require any further modification.
Therefore, the simplified form of the expression 1200 × 1260 ÷ 800 is 1890 in standard form.
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The midpoint of AB is M(1,2). If the coordinates of A are (8,-4), what are the coordinates of B?
The midpoint of AB is M(1,2). If the coordinates of A are (8,-4), The coordinates of point B are (-6, 8).
To find the coordinates of point B, we can use the midpoint formula, which states that the midpoint between two points (x₁, y₁) and (x₂, y₂) is given by:
Midpoint = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)
We are given the midpoint M(1, 2) and the coordinates of point A (8, -4). Let's denote the coordinates of point B as (x, y).
Using the midpoint formula, we can set up the following equations:
1 = (8 + x) / 2 (equation 1)
2 = (-4 + y) / 2 (equation 2)
Let's solve these equations to find the values of x and y.
From equation 1:
2 = 8 + x
x = 2 - 8
x = -6
From equation 2:
4 = -4 + y
y = 4 + 4
y = 8
Therefore, the coordinates of point B are (-6, 8).
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Answer:
B = (-6, 8)
Step-by-step explanation:
To find the coordinates of B, given the coordinates of A and the coordinates of the midpoint of AB, use the Midpoint formula.
[tex]\boxed{\begin{minipage}{7.4 cm}\underline{Midpoint formula}\\\\$M(x,y)=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)$\\\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ are the endpoints.\\\end{minipage}}[/tex]
Let A = (x₁, y₁) = (8, -4)
Let B = (x₂, y₂)
Given M is (1, 2), substitute the points into the midpoint formula:
[tex](1,2)=\left(\dfrac{x_2+8}{2},\dfrac{y_2-4}{2}\right)[/tex]
[tex](1,2)=\left(\dfrac{x_2}{2}+4,\dfrac{y_2}{2}-2\right)[/tex]
Equate the x-coordinates and solve for x₂:
[tex]\begin{aligned}1&=\dfrac{x_2}{2}+4\\\\1-4&=\dfrac{x_2}{2}+4-4\\\\-3&=\dfrac{x_2}{2}\\\\-3\cdot 2&=\dfrac{x_2}{2}\cdot 2\\\\-6&=x_2\\\\x_2&=-6\end{aligned}[/tex]
Equate the y-coordinates and solve for y₂:
[tex]\begin{aligned}2&=\dfrac{y_2}{2}-2\\\\2+2&=\dfrac{y_2}{2}-2+2\\\\4&=\dfrac{y_2}{2}\\\\4\cdot 2&=\dfrac{y_2}{2}\cdot 2\\\\8&=y_2\\\\y_2&=8\end{aligned}[/tex]
Therefore, the coordinates of B are (-6, 8).
Please answer this picture
your picture is not so clear can you upload again
really need help with is problem if any math wizards are on
Answer:
2
DNE
-3
3
Step-by-step explanation:
(1) DNE because it is not continuous
(2) DNE because it is not continuous
(3) -3 because at 4, f(x) = -3
(4) x can be any value of -5-2k (where k is a positive integer) or 3. So you can just put 3.
find the midpoint of the line segment with endpoints (-9,-1) and (7,0)
Answer:
Midpoint = (-1, -1/2)
Step-by-step explanation:
We can find the midpoint using the midpoint formula which is given by:
M = (x1 + x2) / 2, (y1 + y2) / 2, where
M is the coordinates of the midpoint,(x1, y1) are one point on the line segment,and (x2, y2) are another point on the line segment.Thus, we can plug in (-9, -1) for (x1, y1) point and (7, 0) for (x2, y2) in the midpoint formula:
M = (-9 + 7) / 2, (-1 + 0) / 2
M = (-2) / 2, (-1) / 2
M = -1, -1/2
Thus, (-1, -1/2) is the midpoint of the line segment with endpoints (-9, -1) and (7, 0).
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Find the average rate of change of each function over the interval (0, 3). Match each representation with its respective average rate of change.
-1
-2
X
0
6
= 2² + 2x - 5
1
3
2
3 4
-3
The correct matches are:
-1: 0
-2: 0
X: 14/3
0: 0
6: Not used
= 2² + 2x - 5: Not used
To match the representations with their respective average rates of change, we need to calculate the average rate of change for each function over the interval (0, 3) and compare it to the given values.
Let's calculate the average rate of change for each function:
Function: 2² + 2x - 5
To find the average rate of change, we need to calculate the difference in function values divided by the difference in x-values:
Average rate of change = (f(3) - f(0)) / (3 - 0)
Average rate of change = ((2² + 2(3) - 5) - (2² + 2(0) - 5)) / 3
Average rate of change = (13 - (-1)) / 3
Average rate of change = 14 / 3
Match: X = 14/3
Function: -1
Since the function is constant, the average rate of change is 0.
Match: 0
Function: 2
Since the function is constant, the average rate of change is 0.
Match: 0
Function: 3
Since the function is constant, the average rate of change is 0.
Match: 0
Function: -2
Since the function is constant, the average rate of change is 0.
Match: 0
Function: -3
Since the function is constant, the average rate of change is 0.
Match: 0
Therefore, the correct matches are:
-1: 0
-2: 0
X: 14/3
0: 0
6: Not used
= 2² + 2x - 5: Not used
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The following data set shows the number of books checked out from a library
during the first two weeks of the month:
19, 10, 15, 99, 12, 18, 15, 16, 12, 13, 18, 17, 19, 13
Which of the following statements is true based on the data set?
O There is one outlier, indicating very few books were checked out on that day.
O There is one outlier, indicating an abnormally large number of books were checked
out on that day.
O There are two outliers, indicating very few books were checked out on those two
days.
O There are two outliers, indicating an abnormally large number of books were checked
out on those 2 days.
The statement "There is one outlier, indicating an abnormally large number of books were checked out on that day" is true based on the data set.
To determine if there are any outliers in the given data set of the number of books checked out from a library during the first two weeks of the month, we can examine the values and look for extreme values that deviate significantly from the rest of the data.
The data set is as follows:
19, 10, 15, 99, 12, 18, 15, 16, 12, 13, 18, 17, 19, 13
To identify outliers, we can use different methods, such as the interquartile range (IQR) or z-scores. Let's calculate the IQR to determine if there are any outliers:
Arrange the data set in ascending order:
10, 12, 12, 13, 13, 15, 15, 16, 17, 18, 18, 19, 19, 99
Calculate the first quartile (Q1) and third quartile (Q3):
Q1 = 13 (median of the lower half)
Q3 = 18 (median of the upper half)
Calculate the interquartile range (IQR):
IQR = Q3 - Q1 = 18 - 13 = 5
Define the lower and upper boundaries for outliers:
Lower bound = Q1 - 1.5 * IQR = 13 - 1.5 * 5 = 5.5
Upper bound = Q3 + 1.5 * IQR = 18 + 1.5 * 5 = 25.5
Based on these calculations, any value below 5.5 or above 25.5 would be considered an outlier.
Looking at the data set, we can see that there is indeed one outlier, which is the value 99. It is significantly larger than the rest of the values and falls above the upper bound.
Therefore, the statement "There is one outlier, indicating an abnormally large number of books were checked out on that day" is true based on the data set.
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2(x+5)-5 x 12 example pls
When x = 3, the expression 2x - 50 evaluates to -44.
To demonstrate an example using the expression 2(x + 5) - 5 × 12, let's simplify it step by step:
Start with the given expression.
2(x + 5) - 5 × 12
Apply the distributive property.
2x + 2(5) - 5 × 12
Simplify within parentheses and perform multiplication.
2x + 10 - 60
Combine like terms.
2x - 50
The simplified form of the expression 2(x + 5) - 5 × 12 is 2x - 50.
Let's consider an example for substituting a value for the variable x:
Suppose we want to evaluate the expression when x = 3. We substitute x = 3 into the simplified expression:
2(3) - 50
Now, perform the calculations:
6 - 50
The result is -44.
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Question
evaluate the expression 2(x+5)-5 x 12.
Which of the following is the prime factorization of 15?
1x15
3x5
2x2x5
5x2
Answer: The prime factorization of 15 is 3x5.
Solve this system of by rewriting the statements into a set of 2 equations. Then solve the equations using the addition method The surm of two numbers is 21. The difference of the two numbers is 19. What are the two numbers?
Answer:
the two numbers are 20 and 1.
A gaming system costs $600 and is on sale for 15% off. After the discount, there is a 5% tax. What is the final price of the gaming system?
Answer$535.50
Step-by-step explanation:
15% is equal to .15
So, multiply 600.00x .15=90
600.00 - 90.0=510.
510. 00x .05=25.50
510.00+25.50=535.50
Your answer is $535.5
Find the third, fourth, and fifth terms of the sequence defined by
a1 = 1, a2 = 3,
and
an = (−1)nan − 1 + an − 2
for
n ≥ 3.
The third term (a3) of the sequence is -8, the fourth term (a4) is 35, and the fifth term (a5) is -183. These values are obtained by applying the given formula recursively and substituting the previous terms accordingly. The calculations follow a specific pattern and are derived using the provided formula.
The sequence is defined by the following formula:
a1 = 1, a2 = 3,
and
an = (-1)nan - 1 + an - 2 for n ≥ 3.
To find the third term (a3), we substitute n = 3 into the formula:
a3 = (-1)(3)(a3 - 1) + a3 - 2.
Next, we simplify the equation:
a3 = -3(a2) + a1.
Since we know a1 = 1 and a2 = 3, we substitute these values into the equation:
a3 = -3(3) + 1.
Simplifying further:
a3 = -9 + 1.
Therefore, the third term (a3) is equal to -8.
To find the fourth term (a4), we substitute n = 4 into the formula:
a4 = (-1)(4)(a4 - 1) + a4 - 2.
Simplifying the equation:
a4 = -4(a3) + a2.
Since we know a2 = 3 and a3 = -8, we substitute these values into the equation:
a4 = -4(-8) + 3.
Simplifying further:
a4 = 32 + 3.
Therefore, the fourth term (a4) is equal to 35.
To find the fifth term (a5), we substitute n = 5 into the formula:
a5 = (-1)(5)(a5 - 1) + a5 - 2.
Simplifying the equation:
a5 = -5(a4) + a3.
Since we know a4 = 35 and a3 = -8, we substitute these values into the equation:
a5 = -5(35) + (-8).
Simplifying further:
a5 = -175 - 8.
Therefore, the fifth term (a5) is equal to -183.
In summary, the third term (a3) is -8, the fourth term (a4) is 35, and the fifth term (a5) is -183.
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Find the critical value t Subscript c for the confidence level c=0.99 and sample size n=22.
tc=?
The critical value tₕ for a confidence level of 0.99 and a sample size of 22 is approximately 2.831.
To find the critical value tₕ for a given confidence level and sample size, we can use a t-distribution table or a statistical software.
For a confidence level of 0.99, we need to determine the critical value tₕ such that the area under the t-distribution curve to the right of tₕ is equal to (1 - c) / 2. In this case, (1 - c) / 2 = (1 - 0.99) / 2 = 0.005.
Since the sample size is 22, we have n - 1 degrees of freedom, which is 22 - 1 = 21. We need to find the critical value tₕ with 21 degrees of freedom that corresponds to an area of 0.005 in the upper tail of the t-distribution.
Using a t-distribution table or a statistical software, we find that the critical value tₕ is approximately 2.831.
Therefore, the critical value tₕ for a confidence level of 0.99 and a sample size of 22 is approximately 2.831.
It is important to note that the critical value may vary slightly depending on the specific t-distribution table or statistical software used. However, the value obtained above is a reasonable approximation based on commonly used tables or software.
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Select an expression that is equivalent to V(6x²). (6x5)
A. 32/6x7/5
B. 32/37/3
C. 62/37/3
D. 62/6x7/5
The expression that is equivalent to x√6 is option C, 62/37/3.The correct choice is C. 62/37/3.
To find an expression that is equivalent to √(6x²), we need to simplify the square root.
Using the properties of square roots, we know that the square root of a product is equal to the product of the square roots. Therefore, we can simplify the expression as follows:
√(6x²) = √6 * √(x²)
The square root of x² is simply x, and the square root of 6 cannot be simplified further. Therefore, the expression can be simplified as:
√(6x²) = x√6
Among the given options, the expression that is equivalent to x√6 is option C, 62/37/3.
Therefore, the correct choice is C. 62/37/3.
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Assume that Canes customer would buy. A maximum of 82000. Units of Alpha and62000 of beta assume that the raw material availability for production is limited to 162000 pounds how many units of each product should Cane produce to maximize profits
The units of each product that Cane should produce to maximize profits will be 62000 units of Beta and 7600 units of
Alpha.
Contribution margin per poundAlpha Beta
Selling price 130 90
Variable cost 78 48
Contribution margin 52 42
Pound per unit 5 2
Contribution margin per pound 10.4 21
Pound Unit
Beta 62000*2 = 124000 62000
Alpha 38000 38000/5 = 7600
Total 162000
Maximum contribution margin = (38000*10.4+124000*21) = 2999200
Highest price = 10.4+5 = 15.40 per pound
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I need some statistics help (this question got deleted)
A researcher hypothesizes that zylex, a new antidepressant, will affect concentration. It is known that scores on a standardized concentration test is normally distributed with a μ= 50 and a σ= 12. A random sample of n=16 participants, aged 19-35, are chosen from the State of New Jersey. The sample is put on a six month dosage plan of zylex. After six months, all the participants are given a standardized concentration test. The researcher records the data and calculates a sample mean of M=56. Are the data sufficient to conclude that the drug, zylex, does have an effect on concentration?
Based on the above research scenario, please answer the following questions:
1. Name the population: ____________________________________
2. Name the sample: _______________________________
3. What is the independent variable? ________________
4. What is the dependent variable? _
_______________________
5. What is the appropriate hypothesis test? __________________
6. What two means are you comparing in this test? ____________________________
7. Please calculate the appropriate hypothesis test using all four steps:
Step 1:
Step 2:
Step 3:
Step 4: _______________________________
Write the statistical statement for your results: __________________________________
Interpret your results (relating back to the hypothesis): _____________________________________________________________________________ _____________________________________________________________________________ _____________________________________________________________________________
Is there a probability of Type I error? Yes ______ No ______ If yes, what is the probability of a Type I error? ________
Is yes, how could you have decreased that probability? __________________________________
Is there a probability of Type II error? Yes____ _ No______
If it is appropriate, please calculate effect size: Answer:________
How many gallons of a 50% antifreeze solution must be mixed with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze?
Answer: 180 gallons needed
Step-by-step explanation:
Zykeith,
Assume x gallons of 50% antifreeze is needed
Final mixture is x + 60 gallons
Amount of antifreeze in mixture is 0.4*(x+60)
Amount of antifreeze added is .5x + .1*60 = .5x + 6
so .5x + 6 = .4(x + 60)
.5x -.4x = 24 -6
.1x = 18
x = 180
Let x be the number of gallons of the 50% antifreeze solution needed. We know that the resulting mixture will be 70 + x gallons. To get a 40% antifreeze mixture, we can set up the following equation:
[tex]{\implies 0.5x + 0.1(70) = 0.4(70 + x)}[/tex]
Simplifying the equation:
[tex]\qquad\implies 0.5x + 7 = 28 + 0.4x[/tex]
[tex]\qquad\quad\implies 0.1x = 21[/tex]
[tex]\qquad\qquad\implies \bold{x = 210}[/tex]
[tex]\therefore[/tex] We need 210 gallons of the 50% antifreeze solution to mix with 70 gallons of 10% antifreeze to get a mixture that is 40% antifreeze.
[tex]\blue{\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}}[/tex]
c) A company is considering expanding its business. The expansion will cost 350million initially for the premises and a further sh150 million to refurbish the premises with new equipment. Cash flow projections from the project show the
following cash flows over the next six years.
Year Net cash flows
Sh 000
1 70000
2 70000
3 80000
4 100000
5 100000
6 120000
The equipment will be depreciated to a zero resale value over the same period and after the sixth year, it is expected that the new business could be sold for sh350 million.
Required:
Calculate:
i. The payback period for the project. (5 marks)
ii. The accounting rate of Return (ARR) , using the average investment method.
(5 marks)
iii. The net present value (NPV) of the project. Assume the relevant cost of capital is 12%.
(5 marks)
iv. The internal Rate of Return (IRR) of the project. (5 marks)
i. The payback period for the project is 6 years.
ii. The accounting rate of return (ARR) using the average investment method is 21.18%.
iii. The net present value (NPV) of the project is -165,143.
iv. The internal rate of return (IRR) of the project is approximately 19.61%.
i. The payback period for the project:
To calculate the payback period, we need to determine how long it takes for the cumulative net cash flows to equal or exceed the initial investment of 350 million + 150 million.
Year 1: 70,000, Year 2: 70,000, Year 3: 80,000, Year 4: 100,000, Year 5: 100,000, Year 6: 120,000.
Cumulative Cash Flow:
Year 1: 70,000
Year 2: 70,000 + 70,000 = 140,000
Year 3: 140,000 + 80,000 = 220,000
Year 4: 220,000 + 100,000 = 320,000
Year 5: 320,000 + 100,000 = 420,000
Year 6: 420,000 + 120,000 = 540,000.
The cumulative cash flows exceed the initial investment of 500 million (350 million + 150 million) in Year 6.
So, the payback period for the project is 6 years.
ii. The accounting rate of return (ARR) using the average investment method:
ARR = Average Annual Profit / Average Investment
Average Annual Profit = Sum of Net Cash Flows / Number of Years
Average Annual Profit = (70,000 + 70,000 + 80,000 + 100,000 + 100,000 + 120,000) / 6
Average Annual Profit = 540,000 / 6
Average Annual Profit = 90,000
Average Investment = (Initial Investment + Residual Value) / 2
Average Investment = (500 million + 350 million) / 2
Average Investment = 425 million.
ARR = 90,000 / 425,000 = 0.2118 or 21.18%
iii. The net present value (NPV) of the project:
To calculate NPV, we discount each cash flow to its present value using the cost of capital of 12%.
NPV = (Net Cash Flow1 / [tex](1 + r)^1)[/tex] + (Net Cash Flow2 / [tex](1 + r)^2)[/tex] + ... + (Net Cash Flow6 / (1 + r)^6) - Initial Investment.
[tex]NPV = (70,000 / (1 + 0.12)^1) + (70,000 / (1 + 0.12)^2) + (80,000 / (1 + 0.12)^3) + (100,000 / (1 + 0.12)^4) + (100,000 / (1 + 0.12)^5) + (120,000 / (1 + 0.12)^6) -[/tex] (350 million + 150 million)
Calculating each term and summing them up:
NPV = 54,017 + 48,234 + 54,497 + 62,313 + 55,631 + 60,165 - 500 million
NPV = -165,143
Therefore, the net present value (NPV) of the project is -165,143.
iv. The internal rate of return (IRR) of the project:
To calculate the IRR, we find the discount rate that makes the NPV equal to zero. Using a financial calculator or Excel, we can determine that the IRR for this project is approximately 19.61%.
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Triangle JKL has vertices at J(−1, −5), K(−2, −2), and L(2, −4). Determine the translation direction and number of units of the image of triangle JKL if vertex J′ is at (−3, −5).
4 units down
4 units up
2 units to the right
2 units to the left
A triangle JKL has vertices at J(−1, −5), K(−2, −2), and L(2, −4) and J′ at (−3, −5). The translation direction is 2 units to the left. The number of units of the image of triangle JKL is 2 units to the left only.
Given that a triangle JKL has vertices at J(−1, −5), K(−2, −2), and L(2, −4) and J′ at (−3, −5). We have to determine the translation direction and the number of units of the image of triangle JKL. Let's first find the translation direction to determine the image of triangle JKL.
Seeing the position of J and J', we can determine that the translation was made in the left direction because J has moved from the point (-1,-5) to (-3,-5). Thus, the translation direction is 2 units to the left. Now, let's calculate the number of units of the image of triangle JKL.
Let's draw a rough sketch of the triangle JKL and locate its vertices J(-1,-5), K(-2,-2), and L(2,-4).To find the number of units of the image of triangle JKL, we need to find the horizontal and vertical distances between the vertices of the original triangle and its image.
We can use the horizontal distance between J and J′ as a reference to calculate the remaining distances. J has moved 2 units to the left, so the horizontal distance between J and J′ is 2. Now, let's calculate the vertical distance between J and J′. The coordinates of J and J′ are (-1,-5) and (-3,-5), respectively.
The difference between the y-coordinates of J and J′ is 0, which means that J and J′ are on the same horizontal line. Therefore, the vertical distance between J and J′ is 0. Hence, the image of the triangle JKL has moved 2 units to the left and 0 units vertically. Thus, the number of units of the image of triangle JKL is 2 units to the left only.
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