Find the area of the following shape. please show me your work so i can understand how to do this.

Answer:

[tex]k=\pm3[/tex]

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant [tex]\Delta = b^2-4ac[/tex] (or, if b is an even number, 1/4 of it) is zero.

I see it! I see it!

Stare at it for a while. First term is [tex]3(2x)^2[/tex], third term is [tex]3(1)^2[/tex], we are missing a double product, but we can play with k. For the LHS to be [tex]3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3[/tex] you just need [tex]4k= \pm12 \rightarrow k=\pm3[/tex].

I don't see it...

Then number crunching it is. Set the discriminant to 0, solve for k

[tex]\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3[/tex]

Answer:

Lacey could afford 4.25lb of cherries

Step-by-step explanation:

Cost of onions= 3 lb x 0.98/1=2.94

21.45-2.94=18.48$

1 lb=4.35

18.48 x 1lb of cherries/4.35=4.25lb of cherries.

Hope I helped please mark brainliest it means a lot to my progression and thanks! <3

Answer:

C: There is

Step-by-step explanation:

Hope this helps!

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Answer:

AB is perpendicular to IB

A pair of segment that are marked perpendicular to each other are JC and CD.

As per the figure given,

∠JCD = 90°

In geometry, when it's stated that angle JCD is 90°, it means that angle JCD is a right angle. When two line segments or rays intersect to form a right angle, it indicates that they are perpendicular to each other.

In the context of the figure given, JC is a line segment , and CD is another line segment. The fact that angle JCD is a right angle (90°) tells that JC is perpendicular to CD.

Hence, as angle JCD is given as 90°, it establishes that JC is perpendicular to CD in the context of the figure given.

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The probability of her NOT drawing a red card are very likely

Answer:

$ 43.25

Step-by-step explanation:

68 - 40% = 40.8

40.8 + 6% = $ 43.25

Answer:

So you can convert e.g. 1 cup of rice or rice flour into grams or ounces etc. easily. Other even more exotic rice varieties converters menu page. You may enter whole numbers, decimals or fractions

Step-by-step explanation:

Answer:

0.9804

Step-by-step explanation:

0.68 ÷ 0.6936 = 0.98039215686275

Usando un sistema de ecuaciones, se encuentra que

Para el sistema, hay que:

$845 por 3 libros de Algebra, 5 libros de Geometría Analítica y 2 libros de Cálculo Diferencial, o sea:

[tex]3x + 5y + 3z = 845[/tex]

$580 por 2 libros de Geometría Analítica, 4 libros de Algebra y 1 libro de Cálculo Diferencial, o sea:

[tex]4x + 2y + z = 580[/tex]

$605 por un libro de Algebra, 3 libros de Geometría Analítica y 3 de Cálculo Diferencial, o sea:

[tex]x + 3y + 3z = 605[/tex]

Reemplazando la segunda equación en las otras duas:

[tex]z = 580 - 4x - 2y[/tex]

[tex]3x + 5y + 3z = 845[/tex]

[tex]3x + 5y + 3(580 - 4x - 2y) = 845[/tex]

[tex]-9x - y = -895[/tex]

[tex]9x + y = 895[/tex]

[tex]y = 895 - 9x[/tex]

[tex]x + 3y + 3z = 605[/tex]

[tex]x + 3y + 3(580 - 4x - 2y) = 605[/tex]

[tex]-11x - 3y = -1135[/tex]

[tex]11x + 3y = 1135[/tex]

[tex]y = 895 - 9x[/tex], por eso:

[tex]11x + 3(895 - 9x) = 1135[/tex]

[tex]-16x = -1550[/tex]

[tex]x = \frac{1150}{16}[/tex]

[tex]x = 96.875[/tex]

[tex]y = 895 - 9x = 895 - 9(96.875) = 23.125[/tex]

[tex]z = 580 - 4(96.875) - 2(23.125) = 146.25[/tex]

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Darrel has 50 grapes in all.

Lia has 72 green grapes, and she shares them equally between 8 friends. To find out how many grapes each friend receives, divide the total number of grapes by the number of friends:

Number of grapes each friend receives = 72 / 8 = 9

Now, Darrel adds 41 green grapes to his share, so the total number of grapes he has is:

Total grapes for Darrel = Number of grapes Darrel received initially + Additional grapes added by Darrel

Total grapes for Darrel = 9 + 41 = 50

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Answer:

alan received 24 votes

Step-by-step explanation:

bark

Answer:

Step-by-step explanation:

K, but what's the question?

Answer:

128 130

Step-by-step explanation:

128 129 130

The growth amount is given by the growth rate the duration of the growth

and how the rate is applied to each period.

The correct selections are;

Reasons:

First part;

The given formula for the annual growth rate is; [tex]A(t) = \mathbf{P \cdot \left(1 + r)^t}[/tex]

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{[a]} \right)^{n \cdot t}}[/tex]

Where;

P = The principal

r = The rate per period

n = The number of compounding per period

t = The number of periods

In the above formula, we have that the number of compounding per periods = n

Therefore;

Which gives the fraction of the interest applied to each period as [tex]\displaystyle \frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}}[/tex]

Second part;

When [tex]x = \displaystyle \frac{n}{r}[/tex], we have; [tex]A(t) = \mathbf{P \cdot \left(1 + [b])^{n \cdot t}}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{r}{n} \right)^{n \cdot t}[/tex]

Therefore;

[tex]\displaystyle b=\frac{r}{n}[/tex]

[tex]\displaystyle \frac{1}{x} = \frac{1}{\left(\frac{n}{r} \right)} =\frac{r}{n}[/tex]

Which gives;

[tex]\displaystyle b=\frac{r}{n} = \mathbf{\frac{1}{x}}[/tex]

[tex]\displaystyle \underline{ b = \frac{1}{x} }[/tex]

Third part;

Where, n = x·r, and [tex]\displaystyle A(t) = \mathbf{P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t}}[/tex]

We have;

[tex]\displaystyle x= \frac{n}{r}[/tex]

[tex]\displaystyle \frac{1}{x}=\frac{r}{n}[/tex]

[tex]\displaystyle A(t) = P \cdot \left (1 + \frac{1}{x} \right)^{[c] \cdot t} = \mathbf{P \cdot \left (1 + \frac{r}{n} \right)^{[c] \cdot t}}[/tex]

Which gives;

c = n = x·r

Fourth part;

If x is a really large number, we have; [tex]\displaystyle \mathbf{\left(1 + \frac{1}{x} \right)^x}[/tex]

Where x approaches ∞, we have;

[tex]\displaystyle \frac{1}{\infty}=0[/tex]

Which gives;

[tex]\displaystyle \displaystyle \left(1 + \frac{1}{x} \right)^x= \left(1 + \frac{1}{\infty} \right)^\infty = \displaystyle \left(1 + 0\right)^\infty = 1 ^\infty = 1[/tex]

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Answer:

60 / 300 simplified 6/30 simplified 1/5 (20%)

Step-by-step explanation:

Maybe asking ratio?

Answer:

Yes

Step-by-step explanation:

The best way to solve this question is to use ratios. The first ratio to make is 12:24. This represents how there are 12 boys for 24 girls. Ratios remain equivalent as long as both sides of the ratio are simplified by the same number. So, you can divide both sides by 6. When you divide both sides you get 2:4. Therefore, there are 2 boys for 4 girls.

Answer:

Equation of parabola: y = a(x-h)2 + k or x = a(y-k)2 +h, but the simple version is  y2 = 4ax.

Step-by-step explanation:

Answer:

zeroes or x-intercepts

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

1/2 of 20 is 10

Answer:

10

Step-by-step explanation:

Answer:

The answer is option D

Step-by-step explanation:

f (n)=-2. (-5)^n-1. Jesus loves you

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

[tex]H_0: \mu_1 - \mu_2 = 0[/tex]

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

[tex]H_1: \mu_1 - \mu_2 \neq 0[/tex]

Two groups of 22 patients, hence, the standard errors are:

[tex]s_1 = \frac{45.1}{\sqrt{22}} = 9.6154[/tex]

[tex]s_2 = \frac{26.4}{\sqrt{22}} = 5.6285[/tex]

The distribution of the differences is has:

[tex]\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14[/tex]

The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{s}[/tex]

In which [tex]\mu = 0[/tex] is the value tested at the null hypothesis.

Hence:

[tex]t = \frac{25 - 0}{11.14}[/tex]

[tex]t = 2.2438[/tex]

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

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1 = 1 = 1 < 2 < 22

1 is equal to 1 is equal to 1 is less than 2 is less than 22

1 = 1    =1    < 2   < 22                                                                                                                1       1       1       1        1        hope help mark brain.....?

Answer:

d = 3

Step-by-step explanation:

The sum to n terms of an AP is

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] ( a + l)

where a is the first term and l the last term

Here a = 2, l = 59 and sum = 610 , then

[tex]\frac{n}{2}[/tex] (2 + 59) = 610

[tex]\frac{n}{2}[/tex] × 61 = 610 ( divide both sides by 61 )

[tex]\frac{n}{2}[/tex] = 10 ( multiply both sides by 2 to clear the fraction )

n = 20

Then the sequence has 20 terms with a₂₀ = 59

The nth term of an AP is

[tex]a_{n}[/tex] = a + (n - 1)d

where d is the common difference , then

2 + 19d = 59 ( subtract 2 from both sides )

19d = 57 ( divide both sides by 19 )

d = 3

Answer:

a line through (-4,2) and (-8,-3) has slope = (2+3)/(-4+8) = 5/4 = (y-2)/(x+4)

cross multiply

5x +20 = 4y-8

5x -4y =-28

Step-by-step explanation:

Answer: (1,10)

Step-by-step explanation:

Assuming these are the correctly written equations:

-x + 5y = 49, and

x - 4y = -39

I'll rewrite them:

5y = x + 49

y = (1/5)x + (49/5)

-4y = -x -39

y = (1/4)x + (39/4)

=====

I'll assume the question is to find the point these two lines intersect (?).

See the attached graph.  They intersect at (1,10).

Answer:

Step-by-step explanation:

Given function:

Find f(-8):

f(-8)

Answer:

The difference between 12 and a number ➜ 12 - p

The sum of a number and 12 ➜ 12 + p

The quotient of a number and 12 ➜ [tex]\frac{p}{12}[/tex]

The expression in the box for the quotient of a number and 12, the sum of a number and 12 and the difference between 12 and a number are p/12 , 12 + p and p - 12.

Expression in mathematics is combination of variables with the use of operations and given rules. It can be in the form of equation, numbers etc.

If x and y are the arbitrary numbers.

And sum of the numbers are x + y,

difference of the numbers are x - y and

quotient of number x and y is x/y.

Here we have the expression and their representation,

the quotient of a number and 12 = p/12

the sum of a number and 12 = p + 12

the difference between 12 and a number =  p - 12.

Therefore the expression in the box for the quotient of a number and 12,

the sum of a number and 12 and the difference between 12 and a number are p/12 , 12 + p and p - 12.

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Answer:

2nd one

Step-by-step explanation:

I know this because I learned about this