Find the areas of the trapezoids.

Answer: Subtituting CD =5 in AB + CD = JK

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

• AB + CD = JK (equation 1 )

• CD = 5 (equation 2)

So, we simply have to combine the equations.

Substituting CD =5 in equation 1:

AB + CD = JK

AB+(5) =JK

Feel free to ask for more if needed or if you did not understand something.  

Answer:

x=-3

Step-by-step explanation:

\left(5^3\right)^2\cdot 5^{x+4}=5^7

Apply\:exponent\:rule

x+10=7

x=-3

Answer:

x = -3

Step-by-step explanation:

(5^3)^2 · 5^(x+4) = 5^7

First of all, we simplify (5^3)^2. When you have an exponent in parentheses that is raised to another exponent that is outside the parentheses, you multiply the exponents.

(5^3)^2 = 5^(3·2) = 5^6

We cannot simplify 5^(x+4) or 5^7 any further, so our equation is now:

5^6 · 5^(x+4) = 5^7

We can divide 5^6 from both sides to get:

5^(x+4) = (5^7)/(5^6)

When exponents of like terms are divided we can subtract the exponents.

5^(x+4) = 5^(7-6)

5^(x+4) = 5^1

This last part is a bit trickier. When exponents of like terms are multiplied we add the exponents. We can use this knowledge to determine that 5^(x+4) is made up of 5^x · 5^4. Now we have:

5^x · 5^4 = 5^1

We can divide both sides by 5^4.

5^x = (5^1)/(5^4)

We simplify the right side by the same way we did earlier when we divided exponents:

5^x = 5^(1-4)

5^x = 5^-3

We can see that x = -3, but using logarithms, we can finish isolating x. Taking the log base 5 of both sides, we get:

x = log₅(5^-3)

If you don't already know, log₅(5^-3) means what exponent do you raise 5 to in order to get 5^-3. After stating it like this, we can clearly see that log₅(5^-3) equals -3.

So x = -3

Another way we could have solved the logarithm is by using one of the laws of exponents. In this case, we would use logₐ(x^y) = y(logₐm). This would give us:

x = -3(log₅5)

x = -3(1)

x = -3

Either way works.

The steps that you need is to add subtract and divide all the slopes to get your answer

Answer:

Sample Answer:   Start by choosing two data points. Calculate the difference between the second y value and the first y value. Then divide that by the difference between the second x value and the first x value.

Answer:

(√10 +2√8)(√10 -2√8)=

(10 -8√5 + 8√5 -32)

10+0-32

10-32

= -22

Hope this helps.

Answer:

The other person is right, A. -22

Step-by-step explanation:

y=895•1.07^x Y is the population of quails and X is the amount of years that have passed.

Answer:

Make N alone

There is an 8 so we subtract 8 from both sides so the equation is still equal

-4 - 8 = -12

Because we are subtracting N it is positive

N = 12

8 - 12 = -4

Hope this helps

Step-by-step explanation:

Answer:

x = 45°

Step-by-step explanation:

Look at the picture*

Answer:

3x+6y =0

-6y

3x=-6y

x=-2y

Step-by-step explanation:

Answer:

[tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Distributive Property

Algebra I

Terms/CoefficientsFactoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

y = (4x - 1)²(4 - x⁵)⁴

Step 2: Differentiate

Product Rule:                                                                                                 [tex]\displaystyle y' = \frac{d}{dx}[(4x - 1)^2](4 - x^5)^4 + (4x - 1)^2\frac{d}{dx}[(4 - x^5)^4][/tex]Chain Rule [Basic Power Rule]:                                                                       [tex]\displaystyle y' = [2(4x - 1)^{2 - 1} \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^{4 - 1} \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(4x - 1) \cdot \frac{d}{dx}[(4x - 1)]](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot \frac{d}{dx}[(4 - x^5)]][/tex]Basic Power Rule:                                                                                         [tex]\displaystyle y' = [2(4x - 1) \cdot 4x^{1 - 1}](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^{5 - 1}][/tex]Simplify:                                                                                                          [tex]\displaystyle y' = [2(4x - 1) \cdot 4](4 - x^5)^4 + (4x - 1)^2[4(4 - x^5)^3 \cdot -5x^4][/tex]Multiply:                                                                                                         [tex]\displaystyle y' = 8(4x - 1)(4 - x^5)^4 - 20x^4(4x - 1)^2(4 - x^5)^3[/tex]Factor:                                                                                                           [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 2(4 - x^5) - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute 2:                                                             [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 5x^4(4x - 1) \bigg][/tex][Distributive Property] Distribute -5x⁴:                                                         [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3 \bigg[ 8 - 2x^5 - 20x^5 + 5x^4 \bigg][/tex][Brackets] Combine like terms:                                                                     [tex]\displaystyle y' = 4(4x - 1)(4 - x^5)^3(-22x^5 + 5x^4 + 8)[/tex]Factor:                                                                                                           [tex]\displaystyle y' = -4(4x - 1)(4 - x^5)^3(22x^5 - 5x^4 - 8)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Answer:

False

Step-by-step explanation:

(x^3)(x^4) = (xxx)(xxxx) = x^7 when multiplying you add the exponents

(x^5)÷(x^2) = (xxxxx)÷(xx) = xxx or x^3 because two of the x's reduce therefore when dividing you subtract the exponents

(x^2)^3 = (x^2)(x^2)(x^2) = (xx)(xx)(xx) = x^6 when raising a power to a power you multiply the exponents

Answer:

Look at the attachment

The equation is an illustration of a linear function.

The equation for the number of pages left in the book is [tex]b =p- rd[/tex]

The total number of pages is:

[tex]Total = p[/tex]

The daily rate is:

[tex]Rate = r[/tex]

So, the number of pages read in d days is:

[tex]Pages = Rate \times Days[/tex]

This gives

[tex]Pages = r \times d[/tex]

Multiply

[tex]Pages = rd[/tex]

The number of pages left (b) is then calculated as:

[tex]b =Total - Pages[/tex]

So, we have:

[tex]b =p- rd[/tex]

Hence, the equation for the number of pages left in the book is [tex]b =p- rd[/tex]

Read more about linear equations at:

https://brainly.com/question/14323743