Find the electron and hole mobilities, and the resistivity of intrinsic silicon at 300K. Is intrinsic silicon a semiconductor

Answers

Answer 1

Answer:

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.

Explanation:

Solution:

At 300K:

Let suppose mobility of electron in intrinsic semiconductor = [tex]M_{e}[/tex]

Mobility of electron in intrinsic semiconductor is:

[tex]M_{e}[/tex]  = 1300 [tex]cm^{2}[/tex]/volt.sec

Let suppose mobility of hole in intrinsic semiconductor = [tex]M_{h}[/tex]

[tex]M_{h}[/tex] = 500 [tex]cm^{2}[/tex]/volt.sec

We know that, intrinsic silicon semiconductor has equal number of holes and electrons. So,

At 300 K

Intrinsic Carrier Concentration = 1.5 x [tex]10^{10}[/tex]/[tex]cm^{3}[/tex] = C

And,

Conductivity of intrinsic Silicon is:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

e = 1.6 x [tex]10^{-19}[/tex] C

So, plugging in the values, we get:

σ = C x ([tex]M_{h}[/tex] + [tex]M_{e}[/tex]) e

σ = 1.5 x [tex]10^{10}[/tex] x (500 + 1300) x 1.6 x [tex]10^{-19}[/tex]

σ = 4.32 x [tex]10^{-6}[/tex]

So, now we can find the resistivity.

Resistivity = 1/σ

Resistivity = 1/ 4.32 x [tex]10^{-6}[/tex]

Resistivity = 231.481 K Ohm

Yes, Intrinsic Silicon is the semiconductor.


Related Questions

PLEASE ANSWER QUESTION 12!!! THANKSSS

Answers

i swear it’s north and and south but i’m not sure

What is it known as when a force is applied to an object for an amount of time?


momentum


impulse


inertia


acceleration

Answers

Answer:

Impulse. Impulse is when a force is applied to an object for an amount of time.

Explanation:

It can't be momentum because momentum is the motion of a moving body, that is measured as a product of its mass and velocity.

It' cant be inertia because inertia is when an object doesn't move/ it does nothing as well as an object remaining unchanged.

And it can't be acceleration because acceleration is when how fast an object can go/ there velocity.

And that leaves us with impulse, so that's the correct one.

Hope this helped!

Answer:

impulse

Explanation:

took the test

find the length of the smallest standing wave that can be formed with light having frequency 600 THz

Answers

Answer:

[tex]L=2.5*10^-^7m[/tex]

Explanation:

From the question we are told that

Frequency of light  [tex]f= 600 THz[/tex]

Generally the equation for wave is mathematically given as

[tex]\lambda=\frac{c}{\gamma}[/tex]

Where

[tex]1THz=10^1^2[/tex]

[tex]\lambda=\frac{3*10^8}{600*10^1^2}[/tex]

[tex]\lambda=0.5*10^-^6m[/tex]

Generally the equation for a fundamental Frequency  is mathematically given as

[tex]L=\frac{\lambda}{2}[/tex]

[tex]L=\frac{0.5*10^-^6}{2}[/tex]

Therefore the length of the smallest standing wave

[tex]L=2.5*10^-^7m[/tex]

There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper. If the magnetic field is toward the right, and if each side of the loop has length L, the net magnetic torque acting on the loop is:

Answers

Answer:

IBL²

Explanation:

Given that

Current flowing in the wire, is I

Magnetic field towards the right, is B

Length of each side of the loop, is L

Number of windings on the loop, is N

Torque exerted on the wire, is T

The torque, T is usually given by the formula

Torque, T = NBIAsinθ,

and if N = 1 and sinθ = 1 also, then we have

Torque, T = BIA

And we know that Area A from this particular question will be given as = L². If we then substitute A for L², we then have

Torque, T = IBL²

If an object falls and ends with a velocity of 58.8 m/s, how long was the

object falling?

Answers

Answer:

the time taken for the object to fall is 6 s.

Explanation:

Given;

final velocity of the object, v = 58.8 m/s

initial velocity of the object, u = 0

The height of fall of the object is calculated as;

v² = u² + 2gh

v² = 2gh

[tex]h = \frac{v^2}{2g} \\\\h = \frac{(58.8)^2}{2(9.8)} \\\\h = 176.4 \ m[/tex]

The time to fall through the height is calculated as;

[tex]h =ut+ \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t= \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 176.4}{9.8} } \\\\t = 6 \ s[/tex]

Therefore, the time taken for the object to fall is 6 s.

When cold milk
is added to hot
coffee, the milk
warms up and the
coffee cools down.
What can be said
about the energy
of the milk and
the energy of
the coffee when
this happens?

Answers

Answer:

See explanation below.

Explanation:

The internal energy (kinetic energy) of the milk particles increases thus warming the milk up, while the internal energy of the coffee particles reduce their initial average speed as they are imparting energy to the slow milk particles.

2. A rock is shot straight up into the air with a slingshot that had been stretched 0.30 m. Assume
no air resistance.
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
m= 500 g
A
• Y=0
Position A
Position
System/Flow
O
k=100N
- 100
a 옝
&x=0.30m
Om
KE PE, PE
KE PE, PEe Ethermal
Initial
Final
b. Quantitative Energy Conservation Equation
C
Determine the greatest height the rock could reach.

Answers

Answer:

e

Explanation:

Order the following from smallest to largest. Place the smallest value at the top of your list.
= 10kg
= 100g
= 1,000,000mg

Answers

Answer:

mg, g, kg,

Explanation:

Tip King Henry Died Unit Drinking Chocolate Milk

Mg is in the back so its smallest then unit which is g and finally King also known as Kilogram which is the biggest

What force is required to give an object with mass 300 kg an acceleration of 2 m/s^2

Answers

Fnet=ma would be the formula you use. I will just do it step by step to show you.

Fnet=ma
Fnet=300•2
Fnet=600N

How does water move from the surfaces of lakes, rivers, and the ocean directly back into the atmosphere?
A.precipitation
B.evaporation
C.condensation

Answers

Answer:

B. Evaporation

Explanation:

Because I am absolutely positive

Please give Brainlyest

Help me and get points..


When a basketball player jumps to make a shot, once his or her feet are off the ground, the jumper's acceleration


A) Depends on the time in the air.


B) Depends on launch speed.


C) Is usually greater for taller players (but not always).


D) All the above are true


E) Is 10 m/s/s

Answers

Answer:

B) Depends on launch speed.

Explanation:

This is true when considering the basketball player in a given basketball game. The speed at which the player jumps up is a strong factor which determines the acceleration of his acceleration. The direct co-relation show that, speed and acceleration of the basketball player are interrelated.

A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an amplitude of 0.143 mm and a frequency of 76.9 Hz and is traveling in the negative direction of an x axis. If the wave equation is of the form y(x,t) = ym sin(kx + ωt), what are (a) ym, (b) k, and (c) ω, and (d) the correct choice of sign in front of ω?

Answers

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s  d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.


Which contact force always acts against the direction of movement?
A. spring

В.
friction
C.
impact
D. normal

Answers

Answer:

the answer to your question is b

if the tension of the cable is 25.0 N what is the mass of the ball

Answers

Answer:576

Explanation:

A football is thrown from the edge of a cliff from a height of 22 m at a velocity of 18 m/s [39degrees above the horizontal]. A player at the bottom of the cliff is 12 m away from the base of the cliff and runs at a maximum speed of 6.0 m/s to catch the ball.

Is it possible for the player to catch the ball? Support your answer with calculations.


Please and thankyou!

Answers

Answer:

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff  2 s later. Thus, it is not possible for the player to catch the ball.

Explanation:

Given;

vertical height of the cliff, h = 22 m

velocity of the ball, u = 18 m/s at an angle 39⁰

vertical component of the velocity, [tex]u_y = u \ sin \theta[/tex]

The time for the ball to get to the bottom of the cliff is calculated as;

h = ut + ¹/₂gt²

h = (u sinθ)t + ¹/₂ x 9.8 x t²

22 = (18 sin 39)t + 4.9t²

22 = 11.328t + 4.9t²

4.9t² + 11.328t  - 22 = 0

Solve the above equation with formula method;

a = 4.9, b = 11.328, c = -22

[tex]t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-11.328\ \ +/- \ \ \sqrt{(-11.328)^2 - 4(4.9\times -22)} }{2(4.9)}\\\\t = 1.26 \ s[/tex]

The time for the player to get to the bottom of the cliff;

Given maximum speed, Vx = 6.0 m/s and horizontal distance, X = 12 m;

[tex]t = \frac{X}{V_x} \\\\t = \frac{12}{6} \\\\t = 2 \ s[/tex]

The ball will get to the bottom of the cliff in 1.26 s, while the player will reach the bottom of the cliff 2 s later. Thus, it is not possible for the player to catch the ball.

Find the Horizontal (x) vector for these forces.

Answers

Answer:

See the explanation below.

Explanation:

The force is a vector therefore we can decompose the force into components x & y. as we need the horizontal component of the force, we must use the cosine function of the angle.

[tex]F_{1x}=30.8*cos(20)\\F_{1x}=28.94[N]\\F_{2x}=34.3*cos(20)\\\\F_{2x}= 32.23[N][/tex]

A sculpture is suspended in equilibrium by two cables, one from a wall and the other

from the ceiling of a museum gallery. Cable 1 applies a horizontal force to the right of

the sculpture and has a tension, Fn. Catble 2 applies a force upward and to the left at an

angle of 37.0° to the negative x-axis and has a tension, Fn. The gravitational force on

the sculpture is 5.00 '10`N. What is Fn?

Answers

Answer:

[tex]T_1=6655.295917 \approx 6655.3N[/tex]

Explanation:

From the question we are told that

Angle of cable 2 [tex]\theta=37.0\textdegree[/tex]

Weight of sculpture [tex]W=5000 N[/tex]

Generally the Tension from cable 2 [tex]T_2[/tex] is mathematically given by

   [tex]T_2sin37\textdegree=5000N[/tex]

   [tex]T_2=5000N/sin37\textdegree[/tex]

   [tex]T_2=8308.2N[/tex]

Generally the Tension from Cable 1 [tex]T_1[/tex] is mathematically given by

   [tex]T_1=T_2 cos37\textdegree[/tex]

   [tex]T_1=8308.2* cos 37\textdegree[/tex]

   [tex]T_1=6655.295917 \approx 6655.3N[/tex]

At t = 0, a car registers at 30 miles/hr. Forty seconds later, the car’s velocity is now at 50 miles/hr. Assuming constant acceleration, what is the distance covered after 40s?

Select one:
a. 0.442 mi
b. .33 mi
c. 0.11 mi
d. 10.33
e. None of the choices given.

Answers

Answer: Choice A) 0.44 miles

=================================================

Work Shown:

1 hour = 60 minutes

1 minute = 60 seconds

1 hour = 60*60 = 3600 seconds

40 seconds = 40*(1/3600) = 40/3600 = 1/90 hours

The car travels 1/90 of an hour. Let t = 1/90.

The initial velocity is vi = 30 mph.

The final velocity is vf = 50 mph.

Apply one of the kinematics equations as given below.

x = distance traveled

x = 0.5*(vi+vf)*t

x = 0.5*(30+50)*(1/90)

x = 0.44444444444444 which is approximate

x = 0.44

The car traveled roughly 0.44 miles. This matches with choice A.

I'm assuming choice A is supposed to say 0.44 instead of 0.442; otherwise, I think your teacher made a typo by putting that 2 in there. Each of the other answer choices are accurate to 2 decimal places, so it would make sense that choice A is also accurate to 2 decimal places as well.

If 0.442 was intended by your teacher, and it's not a typo, then the answer would be E) None of the choices given.

An analog-to-digital converter is a device that can be used with a microphone to take in an audio wave (an analog signal). The device then converts the information to a digitized form that can be stored and used by a computer. The image below shows the steps in the digitization process. The question mark in the image represents how the data is stored after it is processed by the analog-to-digital converter.



How is the information from the audio wave stored after it is processed by the analog-to-digital converter?
A.
It is stored as graphs because it was converted to base ten data.
B.
It is stored as a table of ones and twos because it was converted to a radio wave.
C.
It is stored as a series of ones and zeros because it was converted to binary data.
D.
It is stored as images because it was converted to mathematical equations.
Reset

Answers

Answer:

Answer C It is stored as a series of ones and zeros because it was converted to binary data.

Explanation:

After the Analog to Digital Converter (ADC) the data is stored in a series of numbers encoded in binary mode (combinations of Zeros and Ones).

This agrees with answer labeled as C) in the list of options.

Answer: C

Explanation: Study Island correct

what types of bodies sink in water​

Answers

Answer:

Rocks, coins, honey, vegetable oil, diamonds, etc.

Explanation:

Object that are more dense than water.

ANSWERRR PLEASEEEE!!!

Answers

Answer:

50N to the left

Explanation:

I'll explain if you ask

Answer:

50 newtons to the left

Explanation:

a substance that turns litmus paper blue and contains hydroxide ions is most likely

Answers

Answer:

If it turns the paper blue it would have to be a base.

Explanation:

I hope that answers your question!

Answer:

If it turns the paper blue it would have to be a base.

Explanation:

I hope that answers your question!

By experiment, determine what makes a force attractive or repulsive. Describe your experiments and observations with some examples. 4. What evidence do you see that Newton's third law applies to electrostatic forces

Answers

Answer:

he combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

Explanation:

A very simple experiment that we can do is to rub a brush or plastic comb with a piece of paper, this creates some electrical charges in the comb, we hang the comb by a thread.

We take another comb and we form it with the same paper, when we bring the combs closer, we see that they repel each other, this is proof that the electrical charges created are of the same type.  

If now we rub the comb with another material, for example plastic, and bring it closer to the comb that is hanging, we see that they are approaching, therefore, it is proven that the load created from another type

With these two simple experiments it can be proved that electric charges are of two types, which are called positive and negative.  

4. In the previous experiment we see that when the combs are brought closer, each one has to move, therefore a force must be applied to each one, and the only force is electrostatic. If we observe carefully we see that the breaking of the combs is the same, therefore the force must have the same magnitude in each one and in the opposite direction; this description is equivalent to Newton's third law.

You're driving your new sports car at 80 mph over the top of a hill that has a radius of curvature of 540 m. What fraction of your normal weight is your apparent weight as you crest the hill?

Answers

Answer:

75.84%

Explanation:

We were given Speed of the sports car, v as 80 mph , we can convert to m/s for unit consistency.

v=80mph= 35.76 m/s

The radius of curvature is given as , r = 540 m

✓ the normal weight can be denoted as Wn

✓ the apparent weight of the person can be denoted as Wa

Wn= normal weight= mg

Wa=apparent weight = (mg - mv^2/r)

g= acceleration due to gravity= 9.8m/s^2

The apparent weightand normal weight has a ratio of

Mn/Ma= [mg - mv^2/r]/mg ........eqn(1)

If we simplify eqn(1) we have

Mn/Ma=[g - vr^2/g].............eqn(2)

Then substitute the given values

Mn/Ma=9.8 - [(35.76^2)/540]/ 9.8

=0.758×100%

Mn/Ma=75.84%

Hence, the required fraction is 75.84%

Which common characteristic of planets do Saturn and Earth share?

They have rings.
They have moons.
They are made of rock.
They have thick atmospheres.

Answers

i believe it’s
“they have thick atmospheres”
i hope i’m right and this helped you

The common characteristics  of planets do Saturn and Earth share is they both have moon. Saturn have 13 moons and earth have only one moon.

What is moons of planets?

Moons of planets are spatial objects which revolves around a planet and experiences gravitational pull from the planet. Both saturn and earth are planets of solar system.

The earth that is the only planet planet with living things have only one moon which is called moon itself. Earth is entirely different from the composition and nature of all other planets.

Saturn have 13 moons namely, enceladus, janus, mimas etc. Saturn have some rings made of dust and gases which are not found for any other planet. The composition and gaseous matter in saturn is different from that of earth.

To find more on saturn, refer here:

https://brainly.com/question/12181523

#SPJ6



An 11.0kg object is thrown vertically into the air with an applied force of 145N. What is the

initial acceleration of the object?

Answers

Answer:

13.18m/s²

Explanation:

According to Newton's second law of motion

Force = Mass * acceleration

Given

Mass = 11kg

Force = 145N

Required

acceleration

From the formula

Acceleration = Force/Mass

Acceleration = 145/11

Acceleration = 13.18m/s²

Hence the initial acceleration of the object is 13.18m/s²

PLEASE HELP (100)

A block M, with mass of 4 kg, is released from rest and slides down a ramp that is angled at 28° above the horizontal (from the bottom of the ramp). The length of the ramp, d, is 3 meters. How much work is done by the gravitational force as the block slides down the ramp?

Answers

Answer:

The work done will be [tex]W=55.27\: J[/tex]

Explanation:

The work equation is given by:

[tex]W=F\cdot x[/tex]

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

[tex]F_{x-direction}=mgsin(28)[/tex]

Therefore, the work done will be:

[tex]W=mgsin(28)*3[/tex]

[tex]W=4*9.81*sin(28)*3[/tex]

[tex]W=55.27\: J[/tex]

I hope it helps you!

What are two main forces that act in gases in a star?

Answers

Answer:

hydrogen and helium

Explanation:

the sun is so hot that the huge amount of hydrogen is undergoing a constant star wide nuclear reaction

Answer:

the correct answer is C and D

I took a test hope it helps

when someone pushes a large crate across floor. what forces act upon the crate
friction, applied, gravity or air resistance?

Answers

Answer:

Friction, Applied Force and Gravity

glucose+oxygen--->carbon dioxide+water+energy= What reaction??

Fill in the answers to describe this chemical equation.

Name the reactants in this reaction.

Name the products in this reaction.

How many oxygen atoms are involved in this reaction?

Is this equation balanced, and how can you tell?

Is this reaction endothermic or exothermic, and how can you tell?


I REALLY NEED HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

combustion reaction

glucose,oxygen

carbon dioxide,water,energy

8

no. required balanced equation is:

C6H12O6+6O2--->6CO2+6H2O+energy

endothermic as it needs heat in the form of sunlight.

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