Find the equation of a line passing through (-2/3, 5) that is parallel to 4x-2y=6. Express your answer in point-slope form.

Answer:

10

Step-by-step explanation:

(-12) + (-8) +30

-(12+8)+30

-20 + 30

10

Answer:

(0, 10)

Step-by-step explanation:

Answer:

y = -4x + 10

Step-by-step explanation:

y = -4x + b

-6 = -4(4) + b

-6 = -16 + b

10 = b

Answer: 15

Step-by-step explanation:

Answer:

Step-by-step explanation:

P = 1800

R = 10%

T = 2 years

I = PRT

= 1800 * 10/100 * 2

= 1800 * 0.1 * 2

I = £360

The amount that will be gotten back as interest will be £360

Principal =  £1800

Rate = 10%

Time = 2 years

Simple Interest will be calculated as:

= (P × R × T) / 100

= (£1800 × 10 × 2)/100

= £36000/100

= £360

Therefore, the interest is £360.

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Answer:

18

Step-by-step explanation:

6^2 plus 3^2 = 324, square root 324 =18

Answer:

[tex]\sqrt{45}[/tex]

Step-by-step explanation:

The line represents the hypotenuse of a right triangle with legs 6 and 3. For any right triangle, the Pythagorean Theorem states that [tex]a^2+b^2=c^2[/tex], where [tex]a[/tex] and [tex]b[/tex] are two legs of the triangle and [tex]c[/tex] is the hypotenuse.

Therefore, we have:

[tex]6^2+3^2=c^2,\\c^2=36+9,\\c=\boxed{\sqrt{45}}[/tex]

Answer:

a. 24.12 ft³/hr b. 0.0768 ft/hr

Step-by-step explanation:

a. Find the rate at which the volume of water in the pool is increasing at time t=6 hours.

The net rate of change of volume of the cylinder dV/dt = volume flow rate in - volume flow rate out

Since volume flow rate in = P(t) and volume flow rate out = R(t),

dV/dt = P(t) - R(t)

[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]

We need to find the rate of change of volume when t = 6.

From the table when t = 6, P(6) = 47 ft³/hr

Also, substituting t = 6 into R(t), we have R(6)

[tex]\frac{dV}{dt} = P(t) - 18e^{0.04t}[/tex]

[tex]\frac{dV}{dt} = 47 - 18e^{0.04X6}\\\frac{dV}{dt} = 47 - 18e^{0.24}\\\frac{dV}{dt} = 47 - 18 X 1.27125\\\frac{dV}{dt} = 47 - 22.882\\\frac{dV}{dt} = 24.118 ft^{3}/hr[/tex]

dV/dt ≅ 24.12 ft³/hr

So, the rate at which the water level in the pool is increasing at t = 6 hours is 24.12 ft³/hr

b. How fast is the water level in the pool rising at t=6 hours?

Since the a rate at which the water level is rising is dV/dt and the volume of the cylinder is V = πr²h where r = radius of cylinder = 10 ft and h = height of cylinder = 5 feet

dV/dt = d(πr²h)/dt = πr²dh/dt since the radius is constant and dh/dt is the rate at which the water level is rising.

So, dV/dt = πr²dh/dt

dh/dt = dV/dt ÷ πr²

Since dV/dt = 24.12 ft³/hr and r = 10 ft,

Substituting the values of the variables into the equation, we have that

dh/dt = dV/dt ÷ πr²

dh/dt = 24.12 ft³/hr ÷ π(10 ft)²

dh/dt = 24.12 ft³/hr ÷ 100π ft²

dh/dt = 0.2412 ft³/hr ÷ π ft²

dh/dt = 0.2412 ft³/hr

dh/dt = 0.0768 ft/hr

So, the arate at which the water level is rising at t = 6 hours is 0.0768 ft/hr

[tex]\\ \Large\sf\longmapsto 11+12[/tex]

[tex]\\ \Large\sf\longmapsto 23[/tex]

[tex]\boxed{\Large{\sf P(G)=\dfrac{No\:of\:green\:marbles}{Total\:marbles}}}[/tex]

[tex]\\ \Large\sf\longmapsto P(G)=\dfrac{11}{23}[/tex]

Answer:

11/23

Step-by-step explanation:

11 green marbles and 12 orange marbles = 23 marbles

P(green) = green marbles / total marbles

               = 11/23

Answer:

The numbers 3(pi)/2, 5(pi)/2 satisfy the conclusion of Rolle's Theorem

Step-by-step explanation:

1. The function must be continuous.  

Trigonometric functions are continuous.  

2.  It must be true that f(a) = f(b) = 0

For this case sin(pi) = sin(3pi) = 0

3. Therefore by Rolle's Theorem, there exist a point, x, such that f(x) = 0

For this case f(x) = cos(x)

And cos(x) = 0 at x = 3(pi)/2,5(pi)/2

Answer:

3.) A,B,AB,O

Step-by-step explanation:

Non-numeric data refers to categorical data, or data that is not expressed quantitatively. Answers (1) and (2) contain quantitative data, so they would be eliminated as potential answer choices and therefore (4) would also be eliminated. This leaves answer (3), which does not have quantitative data and is therefore non-numeric.

Answer:

(1.1155 ; 1.1245)

Step-by-step explanation:

Given that :

Sample mean, xbar = 1.12

Sample standard deviation, s = 0.011

Sample size, n = 25

Since we are using the sample standard deviation, we use the T distribution ;

The confidence interval is defined as :

C. I = Xbar ± Tcritical * s/√(n)

Degree of freedom, df = n - 1 = 24

Tcritical(0.05, 24) = 2.064

C. I = 1.12 ± (2.064 * 0.011 / √25)

C.I = 1.12 ± 0.0045408

Lower boundary = (1.12 - 0.0045408) = 1.1155

Upper boundary = (1.12 + 0.0045408) = 1.1245

(1.1155 ; 1.1245)

Answer:

x=6

Step-by-step explanation:

5x - 11 = 19

5x = 30

x = 6

20characters

5x = 19+11 5x = 30 x = 30/5 x = 6

Answer:

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

Let L represent the length of the rectangle. Then the width is W=5+3L, and the perimeter is ...

  P = 2(L+W)

  240 = 2(L +(5 +3L))

  120 = 5 +4L

  115 = 4L

  115/4 = L = 28.75 . . . . cm

  W = 5+3L = 5 +3(28.75) = 91.25 . . . . cm

The length and width of the rectangle are 28.75 cm and 91.25 cm.

=============================================================

Explanation:

Let's say the shed comes in 40 equal pieces. Each piece takes the same amount of time to assemble. Why am I picking 40? Because 8*5 = 40.

This will allow us to rewrite the fractions with a common denominator.

So Jack can build 8/40 of the shed in the same amount of time Kyle can build 25/40 of the shed.

Instead of writing fractions (which honestly are a pain to deal with), I'm going to write "8 pieces" and "25 pieces" to represent "8/40" and "25/40" respectively. Just keep in mind that there are 40 pieces total.

So again, Jack can assemble 8 pieces in the time it takes Kyle to assemble 25 pieces.

---------------

The ultimate goal is to have Kyle assemble 40 pieces while Jack puts together some unknown number of pieces (some number between 8 and 40). Let's say it's x.

We can then form this proportion

[tex]\frac{\text{Jack's initial 8 pieces}}{\text{x pieces}}=\frac{\text{Kyle's initial 25 pieces}}{\text{goal of 40 pieces}}[/tex]

which simplifies or cleans up to

5/x = 25/40

-----------------

Let's solve for x using cross multiplication

8/x = 25/40

8*40 = x*25

320 = 25x

25x = 320

x = 320/25

x = 12.8

So in the time it takes Kyle to assemble all 40 pieces, Jack can put together 12.8 pieces of the shed. However, we can't have Jack put together some fractional piece, because each "piece" is as small as it gets. We can't get any smaller. It would be like saying a fractional part of an atom or a lego block.

So we'll round 12.8 down to 12.

Jack can assemble 12 pieces in the time it takes Kyle to assemble 40 pieces.

Let's then convert this back to fraction form

12 pieces = 12/40 of a shed = 3/10 of a shed.

Answer:

don't know...........

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For point a:

[tex]fx|H(x) = 1;0< x<1\\\\fX|T(x) = 2x; 0\leq x \leq 1\\\\fx(x) = P(H \bigcap X = x) +P(T \bigcap X=x)\\\\[/tex]

[tex]=P(H)fX|H(x)+P(T)fX|T(x)\\\\= p(1) + (1-p)2x\\\\= p(1 -2x)+2x\\\\[/tex]

Using the PDF of the X value

[tex]fX(x) =2x +p(1 - 2x); \ 0\leq x\leq 1[/tex]

0 ; otherwise

For point b:

[tex]E(X)=\int^{1}_{0} \ x fX (x)\ dx=\int^{1}_{0} \ x(2x+p(1-2x))\ dx\\\\=\int^{1}_{0} \ (2x^2+(x-2x^2)p) dx\\\\[/tex]

[tex]= 2(\frac{x^3}{3}) + (\frac{x^2}{2}-2(\frac{x^3}{3}) \begin{vmatrix} x=1\\ x=0\end{vmatrix} \\\\[/tex]

[tex]= \frac{2}{3} + (\frac{1}{2} - \frac{2}{3})p\\\\= \frac{2}{3} -\frac{p}{6}\\\\= \frac{(4 - p)}{6}[/tex]

9514 1404 393

Answer:

  5, 10, 20

Step-by-step explanation:

Suppose the three numbers are x, 2x, and 4x. Then they have the required ratios. After the transformation, we have ...

  ((x+3) +(4x -8))/2 = 2x . . . . . 2nd term is average of 1st and 3rd

  5x -5 = 4x   ⇒   x = 5

The original numbers are 5, 10, 20.

_____

After the adjustment, the arithmetic sequence is 8, 10, 12.

Answer:

what i dont understand

Step-by-step explanation:

Step-by-step explanation:

combination

is answer of this question

Answer:

how long will it take before your investment is wort$6000?

Answer:

0.375 dollars

Step-by-step explanation:

1 pound = 16 oz

1 oz = 1/16 pound

2 oz = 2/16

2/16 * 3 = 0.375

Answer:

15.56

Step-by-step explanation:

Given the vectors ||u|| = 5√2 units, and ||v|| = 6√2 units.

||u + v|| ≈  5√2 +  6√2

||u + v|| ≈  (5+6)√2

Since √2≈ 1.4142

||u + v|| ≈   11(1.4142)

||u + v|| ≈  15.56

Hence the correct option is D

Answer: 11.05

Step-by-step explanation: got it right

Answer:

6 × ( 3x - 4)

Step-by-step explanation:

Not much to explain.

Hope this helps!

If there is something wrong, please let me know

I think that car travelled 128 km in one hour and 384km in 3 hours

Answer: 384 km

Step-by-step explanation:

Convert m/ph to k/ph by multiplying the equivalent of 1 mile in kilometers    

 (1m = about  1.6km) by the total number of miles.

 80  x  1.6 =  128

 You now have the distance traveled per hour in m/ph converted to k/ph.

 All you do now is multiply it by the time traveled:

 (128 kilometers per one hour for 3 hours)

 128 kph x 3 = 384km

Answer:

30 in²

Step-by-step explanation:

Parallelogram height is,

6/2 (since it's a 30°-60°-90° triangle)

= 3

Area = base × height

= 10×3 in²

= 30 in²

Answered by GAUTHMATH

Answer:

I didn't find the answer in the options

the height of the bigger triangle is 11√6/√3 = 11√2

x = 11√2 × √2 = 11×2 = 22

Answered by GAUTHMATH

Answer:

made up of about 20 common amino acids. The proportion of these amino acids varies as a characteristic of a given protein, but all food proteins—with the exception of gelatin—contain some of each. Amino nitrogen accounts for approximately 16% of the weight of proteins. Amino acids are required for the synthesis of body protein and other important nitrogen-containing compounds, such as creatine, peptide hormones, and some neurotransmitters. Although allowances are expressed as protein, a the biological requirement is for amino acids.

Proteins and other nitrogenous compounds are being degraded and resynthesized continuously. Several times more protein is turned over daily within the body than is ordinarily consumed, indicating that reutilization of amino acids is a major feature of the economy of protein metabolism. This process of recapture is not completely efficient, and some amino acids are lost by oxidative catabolism. Metabolic products of amino acids (urea, creatinine, uric acid, and other nitrogenous products) are excreted in the urine; nitrogen is also lost in feces, sweat, and other body secretions and in sloughed skin, hair, and nails. A continuous supply of dietary amino acids is required to replace these losses, even after growth has ceased.

Amino acids consumed in excess of the amounts needed for the synthesis of nitrogenous tissue constituents are not stored but are degraded; the nitrogen is excreted as urea, and the keto acids left after removal of the amino groups are either utilized directly as sources of energy or are converted to carbohydrate or fat.

Answer:

Choice B.

[tex]4x - 2y = 0[/tex]

Step-by-step explanation:

Has integer coefficients and equal to 0.