Find the equation of the line joining the points (4, 9) and (-1, 0)

Assuming  He wants to earn interest on this money rather than keep extra money he does not need. The choice that would be the best for his situation is  $250 to open a regular savings.

A regular savings account is a saving acount that enables you to save and earn interest based on the amount saved because it is an interest bearing account.

Although this account gives you interest but the interest rate is low. Since Tim has $1200 in his checking account  assuming he withdraw $100 twices, Tim will have $1,000 ($1,200-$200).

Now if he open a regular saving with $250 he will have $750 left ($1,000-$250) with which he can earn interest with.

Inconclusion the choice that would be the best for his situation is  $250 to open a regular savings.

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Answer:

19

please make this answer brainliest If I helped you!

Answer:

c=19

Step-by-step explanation:

110-91=19

129-110=19

148-129=19

4x19 = 76              (91-76=15)

            76+15 =91

5x19= 95                  ( 110-95=15)

           95+15= 110

6x19 = 114            (129-114 =15)

             114+15=129

7x19=133              (  148-133 =15)

         133+15 = 148

okay okay what is emoji aaaaa

Answer:

[tex]\huge\boxed{\bf\: 83 \: yd^{2}}[/tex]

Step-by-step explanation:

Consider rectangle ABCD.

Here,

AB = DC = 9 yd (length = l)

AD = BC = 7 yd (width = w)

Area of this rectangle:

= l * b

= 9 * 7

= 63 yd²

[tex]\rule{150pt}{2pt}[/tex]

Now, take rectangle DEGF.

Here,

DE = FG = 5 yd (length = l)

DF = EG = 4 yd (width = w)

Area of this rectangle:

= l * b

= 5 * 4

= 20 yd²

[tex]\rule{150pt}{2pt}[/tex]

Total area of the compisite figure:

= Area of rectangle ABCD + Area of rectangle DEGF

= 63 yd² + 20 yd²

= 83 yd²

[tex]\rule{150pt}{2pt}[/tex]

Answer:

$600

Step-by-step explanation:

This can be modeled as an exponential equation.

General form of an exponential function: [tex]y=ab^x[/tex]

where:

Therefore:

[tex]\implies 75=a(0.5)^3[/tex]

[tex]\implies 75=0.125a[/tex]

[tex]\implies a=\dfrac{75}{0.125}[/tex]

[tex]\implies a=600[/tex]

Therefore, the computer initially cost $600.

Answer:

Step-by-step explanation:

gerald=2x

guy=x

gill= aproximately 0.3x

2x+x+0.3x=99

2.3x=99

x=43.04

The age of the guy is 29.72 years, the age Gerald is 59.44 years and the age of gill is 9.8 years.

The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers. Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.

As per the given data in the question,

The equation according to the given statement will be,

The age of Gerald is 2x,

The age of the guy is x and the age of the gill is 0.33x.

So, the equation will be,

x + 2x + 0.33x = 99

3.33x = 99

x = 99/3.33

x = 29.72

Age of Gerald, 2x = 2(29.72) = 59.44 years.

Age of guy, x = 29.72 years and,

Age of gill, 0.33x = 0.33(29.72) = 9.8 years.  

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Answer:

9 4/12

Step-by-step explanation:

Just add the mixed numbers 4 + 5 = 9

Add the fraction numerators 1 +3 = 4

*Since the denominator is the same, we just add the numerators

9 4/12

Answer:

as decimal 9.33333

Step-by-step explanation:

4 1/12 + 5 3/12 = 28/3 = 9 1/3

Answer:

-3y

Step-by-step explanation:

-15(y2)4 ÷5y3y4

Rewrite the division as a fraction

-15(y2)4

 5y3y4

Multiply y3 by y4 by adding the exponents

-5(y2)4

  5y7

Cancel the common factor of -15 and 5

-3(y2)4

  y7

Multiply the exponents in (y2)4

-3y8

 y7

Cancel the common factor of y8 and y7

Factor y7 out of -3y8

y7(-3y)

 y7

Multiply by 1

y7(-3y)

 y7 × 1

Cancel the common factor which is y7 and y7

Rewrite the expression

-3y

 1

Divide -3y by 1

-3y

Answer:

iam thinking the answer is ""-262,5ft""

The height of the rocket when the distance between them is 10 feet will be h = 24.49 feet.

The height is a vertical distance between two points. It is given that A model rocket is launched 25 feet from you. When the rocket is at height h, the distance d between you and the rocket is given by d = 625 + h² where h and d are measured in feet.

The height will be calculated by forming the two equations from the given data in the question.

25  =  625  +  h²

100  =  4  (  625   +  h² )

100  =  ( 2500   +  4h²  )

By solving both the equations:

100  -  25  =  2500  -  625  +  4h²   -   h²

3h²   =  1800

h   =   √600

h   =   24.49 feet

Therefore the height of the rocket when the distance between them is 10 feet will be h = 24.49 feet.

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Step-by-step explanation:

for me it is best as a first step to combine this all to one big fraction, and then simplify the whole expression.

you do know that when multiplying the same variable with exponent we simply add the exponents. and she we divide the same variable with exponents, we subtract them from each other (as the overlapping exponent parts cancel each other out).

(3ac³f³)/(8a²bcf⁴) × (12ab²c)/(18ab³c²f) =

= (3×12a²b²c⁴f³)/(8×18a³b⁴c³f⁵) =

= (3×12c)/(8×18ab²f²) = 12c / (8×6ab²f²) =

= 2c / (8ab²f²) = c / (4ab²f²)

Answer:

Step-by-step explanation:

The given relations can be used to write three equations for the angle values.

  t + y + z = 180 . . . . . sum of all angle measures

  y + z = 5t . . . . . . . . second and third total 5 times the first

  y + 30 = z . . . . . . third angle is 30 more than the second.

__

Using the third equation to substitute for z in the first two equations gives ...

  t + y + (y +30) = 180   ⇒   t +2y +30 = 180

  y + (y +30) = 5t   ⇒   2y +30 = 5t

Using the second of these equations to substitute for (2y+30) in the first, we have ...

  t +5t = 180

  t = 180/6 = 30 . . . . . . divide by the coefficient of t

Using this value in our equation for 5t gives ...

  2y +30 = 5(30)

  2y = 120

  y = 60

Then the value of angle z is ...

  y +30 = z = 60 +30

  z = 90

The first, second, and third angles are 30°, 60°, and 90°, respectively.

Answer:

I BELIEVE the answer would be 30

[tex]2+8p-3(12-5p)-(2-3p)(4)\\\\=2+8p-36+15p-8+12p\\\\=35p-42[/tex]

Answer:

The answer is 4x² – x – 4 = 0

Step-by-step explanation:

Where,

So, one quadratic polynomial satisfying is given condition is 4x² – x – 4 = 0

Sum of zeroes = 1/4

Product of zeros = 1

Remember this formula

x² – (α + β)x + αβ

x² – 1/4x + 1

4x² – x – 4 = 0

Thus, The quadratic polynomial is

4x² – x – 4 = 0.

Answer:

Step-by-step explanation:

The correct answer for this question is 30 students

Sure hope this helps you :)

Answer:

100 square feet (100 ft²)

Step-by-step explanation:

Formula

Area of stage

Area of trapezoid:-

Area of parallelogram

Total:-

Answer:

They both have a y intercept of 0

Step-by-step explanation:

Linear equations are written in the form y = mx + b. m is the slope and b is the y-intercept. It also states that they intersect at the origin, so they must have a y-intercept of 0.

Step-by-step explanation:

87 and z are opposite so the are equal. The x equation is on the same line as the 87 degree angle so those 2 added together have to equal 180 so subtract 87 from 180 and get 93 and set 93 equal to 9x-87 and solve to get x=20

Answer:

=> z = 87° { vertically opposite angle }

=> 87° + (9x-87) = 180° { linear pair }

=> 87 +9x-87 = 180

=> 9x = 180°

=> x = 180/9

=> x = 20°

A quadratic model would be the most appropriate model for the given data set.

A quadratic model can be defined as a mathematical model which represents a quadratic equation with a single variable of degree 2.

Aso, a quadratic model is mainly symmetrical because the relationship between its variables when plotted on a graph forms a parabola.

In this scenario, the value of the graph at y(1) is equal to y(2) and y(0) is approximately equal to y(3) as shown in the image attached below, which simply means it is symmetrical about this axis.

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The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.

The test statistic can be calculated using the formula below

[tex]t = \frac{x-\mu}{\sigma / \sqrt{n} }[/tex]

Solving for the mean and standard deviation, we can substitute the values into the above equation which will be

[tex]t = \frac{x-\mu}{\sigma / \sqrt{n} } = 6.274[/tex]

Using the data from the test statistic, we can calculate the p-value of the data

[tex]p-value = p(z < 6.274)= 0.0001 = 0.00[/tex]

From the calculation above, the test statistic and p-value of the given data are

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Answer:

Step-by-step explanation:

hello :

an equation for the line is : y=ax+b   when a is the slope

so : a= 3           y =3x+b

passes

through the point (-5,-9)   x=-5   y= -9  means ; -9 =3(-5)+b   so: b=6

conclusion : y=3x+6

Answer: B    because   y=0      3x+6 =0   3x =-6     x= -2

A) 144 in

is your answer. good luck

This is made easy if you know the Laplace transform pair

[tex]u(t - c) y(t - c) \mapsto e^{-cs} Y(s)[/tex]

where u(t) is the Heaviside step function and Y(s) is the Laplace transform of y(t).

We rewrite f, g, and h in terms of u :

[tex]f(x) = (x^2+2x+1) (u(x) - u(x-3)) + e^{-5x} u(x-3)[/tex]

[tex]g(x) = \sin(3x) (u(x-5) - u(x-10))[/tex]

[tex]h(x) = (u(x) - u(x-4)) + 2(u(x-4)-u(x-8)) + 3 (u(x-8)-u(x-16))[/tex]

and we also rearrange terms to get the right shift in argument:

[tex]f(x) = (x^2+2x+1) u(x) - ((x-3)^2+8(x-3)+16) u(x-3) + e^{-15} e^{-5(x-3)} u(x-3)[/tex]

[tex]g(x) = [\cos(15) \sin(3(x-5)) + \sin(15) \cos(3(x-5))] u(x-5) \\\\ ~~~~~~~~~~- [\cos(30) \sin(3(x-10)) + \sin(30) \cos(3(x-10))] u(x - 10)[/tex]

[tex]h(x) = u(x) + u(x-4) + u(x-8) - 3 u(x - 16)[/tex]

Now we can apply the known transform pair, along with

[tex]x^n \mapsto \dfrac{n!}{s^{n+1}}[/tex]

[tex]e^{ax} \mapsto \dfrac1{s-a}[/tex]

[tex]\sin(ax) \mapsto \dfrac{a}{s^2+a^2}[/tex]

[tex]\cos(ax) \mapsto \dfrac{s}{s^2+a^2}[/tex]

The transforms of f, g, and h are then

[tex]F(s) = e^{-s} \left(\dfrac2{s^3} + \dfrac2{s^2} + \dfrac1s\right) - e^{-3s} \left(\dfrac2{s^3} + \dfrac8{s^2} + \dfrac{16}s\right) + \dfrac{e^{-15} e^{-3s}}{s + 5} \\\\ = \boxed{e^{-s} \left(\dfrac2{s^3} + \dfrac2{s^2} + \dfrac1s\right) - e^{-3s} \left(\dfrac2{s^3} + \dfrac8{s^2} + \dfrac{16}s\right) + \dfrac{e^{-3(s+5)}}{s + 5}}[/tex]

[tex]G(s) = \dfrac{3\cos(15) e^{-5s}}{s^2+9} + \dfrac{s \sin(15) e^{-5s}}{s^2+9} - \dfrac{3\cos(30)e^{-10s}}{s^2+9} - \dfrac{s \sin(30) e^{-10s}}{s^2+9} \\\\ ~~~~~~~ = \dfrac{3(\cos(15)-\cos(30)) + s(\sin(15) - \sin(30))}{s^2+9} \\\\ ~~~~~~~ = \boxed{\dfrac{6\sin\left(\frac{45}2\right)\sin\left(\frac{15}2\right) - 2s \cos\left(\frac{45}2\right)\sin\left(\frac{15}2\right)}{s^2+9}}[/tex]

[tex]H(s) = \boxed{\dfrac{e^{-s} + e^{-4s} + e^{-8s} - 3 e^{-16s}}s}[/tex]

Answer:

5x-1=6x-9

5x-1-6x= -9

5x-6x= -9+1

-x= -8

(-1)*(-x)= (-1)*(-8)

x=8

Answer:

259.15

Step-by-step explanation: