find the magnitude of the acceleration acm of the center of mass of the spherical shell. take the free-fall acceleration to be g = 9.80 m/s2 .

Answers

Answer 1

The acceleration of center of mass of spherical shell = 2.94 [tex]m/s^{2}[/tex]

What is center of mass ?

A position established in relation to an object or set of objects is the center of mass. It is the average location of all the pieces of the system, weighted according to their masses.

According the given information

Two forces act along the line of motion. Gravity down the slope,

m g sin([tex]\alpha[/tex]), and friction up the slope, F. They provide the linear acceleration and F also provides the torque about the Center of mass. This gives the equations of motion:

m a = m g sin([tex]\alpha[/tex]) - F

I dV/dt = F R

A spherical shell of mass m has moment of inertia I = 2/3 m R^2. Furthermore a pure rolling relates dV/dt and a through a = R dV/dt. So the two equations become

m a = m g sin([tex]\alpha[/tex]) - F

2/3 m a = F

These we solve for a and F:

Substituting F from the second equation gives

m a = m g sin([tex]\alpha[/tex]) - 2/3 m a

a = 3/5 g sin([tex]\alpha[/tex])

a = 3/5 × 9.80m/s^2 sin(30.0) = 2.94 [tex]m/s^{2}[/tex]

The acceleration of center of mass of spherical shell = 2.94 [tex]m/s^{2}[/tex]

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Related Questions

a player catches a ball. consider the action force to be the impact of the ball against the player's glove. what is the reaction to this force?

Answers

When then the ball is stopped by the hand due to reaction force by the hand which is equal in magnitude but is opposite in direction to the force applied by the ball.

According to Newton's third law of motion, the reaction would be equal and opposite to the person pushing on the ball, so the ball pushing on the person.

When a ball is thrown on the floor or a wall, it bounces back. The force exerted by the ball on the ground or wall is the action force. The force that the ground or wall exerts on the ball in response to the action force causes the ball to jump or bounce back.

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what parameters do hubble's law relate to each other

Answers

Answer:

Hubble's law is considered a fundamental relation between recessional velocity and distance. However, the relation between recessional velocity and redshift depends on the cosmological model adopted and is not established except for small redshifts.

Explanation:

The relationship between recessional distance and velocity is thought to be governed by Hubble's law. Although it is not confirmed save for minor redshifts, the relationship between recessional velocity and redshift relies on the cosmological model used.

What is Hubble's Law?

Although Hubble was a real person, a spacecraft that was launched into space was given his name. He found that the galaxies that seem to be farthest from us are accelerating their distance from us, while the galaxies that are nearer to us are lagging.

Hubble's law is therefore that. If you study higher-level astronomy, you can do a mathematical operation known as Hubble's law. You can determine a mathematical relation that says that anything moves quicker the further distant it is from you.

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A 20 kg wooden crate is dragged 12 m across a rough level floor by a rope. The force of tension in the rope is 50 N at an angle of 25° above the horizontal and the crate is moving at a constant speed of 1.50 m/s. Find the magnitude of the normal force [N].

Answers

To solve this problem, we can use the equations of motion and Newton's second law of motion. The equation of motion for an object moving at constant speed is:

x = x0 + v0t + (1/2)at^2

where x is the final position, x0 is the initial position, v0 is the initial velocity, t is the time, and a is the acceleration.

In this case, the initial position is 0 m (since the crate starts at the beginning of the 12 m distance), the initial velocity is 0 m/s (since the crate starts at rest), and the time is 12 s (since the crate moves at a constant speed of 1.50 m/s).

We can use these values to solve for the acceleration:

12 m = (1/2)(a)(12 s)^2

a = 0.5 m/s^2

Now that we know the acceleration, we can use Newton's second law of motion to find the normal force:

F = ma

N = (20 kg)(0.5 m/s^2)

N = 10 N

This is the magnitude of the normal force on the crate. Note that this is the normal force exerted by the floor on the crate, not the force of tension in the rope. To find the force of tension in the rope, we would need to consider the angle of the rope and the direction of the force.

Why is it important to shift gears correctly when driving a vehicle?

Answers

Shifting gears correctly is important when driving a vehicle to ensure that the car is operating at its most efficient level.

By selecting the correct gear, you can ensure that the engine works at its optimal speed, allowing it to produce the most power with the least fuel. This helps you save money on fuel costs and reduces your car’s environmental impact.

Shifting gears correctly allows you to control the speed of your car. When accelerating, you need to select a higher gear so that the engine produces more torque, enabling your car to accelerate faster. When slowing down, you should select a lower gear to reduce the engine’s revolutions per minute (RPM), allowing you to slow down quickly and safely.

Finally, correctly shifting gears also ensure your passengers' safety, including yourself. If you shift gears too quickly or at the wrong time, you increase the risk of your car stalling, which can be dangerous in certain situations. In addition, selecting the wrong gear for your traveling speed can lead to acceleration and braking, leading to an uncomfortable and potentially difficult ride.

In conclusion, it is important to shift gears correctly when driving a vehicle to ensure efficient fuel use, control the speed of the car, and keep you and your passengers safe.

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Which of the following is a classic challenge of emerging adulthood? O needing to financially support oneself O getting along with a spouse O taking on adult roles with ease O raising children

Answers

A typical problem of becoming an adult is getting along with our partner.

Adulthood is the stage of life when a person has fully developed physically and intellectually. Adulthood is typically assumed to start around 20 or 21 years old. Old age begins at the age of 60 and follows middle age, which starts around the age of 40.

The topic of adult development is briefly discussed after that. See human development and human behaviour for a comprehensive discussion.

Early and middle adulthood are physically characterised by slow, steady losses in body functioning, which quicken when old age is reached. Through the mid-20s, muscular mass continues to rise before progressively declining after that. Up until around age 30, the skeletal mass grows; after that, it starts to diminish, first in the core skeleton (the pelvis and spine), then in the peripheral skeleton.

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on a violin, a correctly tuned string has a frequency of 460 hz. if the string produces a sound at 510 hz when under a tension of 25.0 n, what should the tension be to produce the correct frequency?

Answers

The tension be to produce the correct frequency is 306N

What is the frequency?

The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.

f= 1/2L[tex]\sqrt[/tex] μT

so

fα[tex]\sqrt[/tex] T

∴ f 1/f 2 = [tex]\sqrt[/tex]T 1/T 2

In our example, f 1 = 460 Hz, and T 1 =?

​and for f = 510 Hz, T 2 = 255.

510/460  = [tex]\sqrt[/tex]T 1/255.

∴T 1 =( 510/510 )=306N.

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a thin, circular hoop is released at the top of an incline that is 8:0 mlong and makes an angle of 370 above the horizontal. what is its speed at the bottom of the incline? assume it rolls without slipping. a. 5:5 m

Answers

The speed at the bottom of the incline is  6.87 m per second.

What is conservation of energy?

The conservation of the energy is a fundamentally law of physics, chemistry stating that the total of the energy of an isolated by the system is constant despite internally changes. It is mostly common expressed as “energy can neither to be created nor destroyed”, and it is the basis of the first-ever law of the thermodynamics.

As per the given question

The length of the inclined plane L= 8.00m

angle of inclination is = 37°

Height of the inclined plane h= L sin ø

     (8.00m) sin 37°

     =4.814 m

Let's take m= mass of hoop

Let's take r=radius of hoop

Let's v be the velocity of the hoop bottom to the inclined plane.

Now we can apply conservation of energy at the top of the inclined plane  and at to the bottom of the inclined plane.

mgh = ¹/₂ mv²

mgh = ¹/₂ mv² + ¹/₂ Iω²

Where, I = moment of inertia

ω = angular velocity

I = L/ω

mgh = ¹/₂ mv² + ¹/₂ (L/ω)ω²

mgh = ¹/₂ mv² + ¹/₂ Lω

mgh = ¹/₂ mv² + ¹/₂ mvrω

ω = vr

mgh = ¹/₂ mv² + ¹/₂ mvrvr

gh = ¹/₂ v² + ¹/₂ (vr)²

gh = ¹/₂v² (1 + r²)

v=gh

v=√(9.8m/s^2)(4.814m)

v=6.87 m/s

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Label the parts of the skin and subcutaneous tissue. 0.22 Cutaneous blood vessels Book Hypodermis Sweat pores Epidermis Hairs Dermis Lamellar corpuscle Sweat gland

Answers

Skin is the largest organ in the body and covers the body's entire external surface. It is made up of three layers, the epidermis, dermis, and the hypodermis, all three of which vary significantly in their anatomy and function.

Give a brief about layers of skin?

The skin is the largest organ of the body and covers the entire outer surface of the body. It consists of her three layers of epidermis, dermis and hypodermis, all three of which differ greatly in anatomy and function. The structure of the skin consists of a complex network and serves as the body's first barrier against pathogens, ultraviolet radiation, chemicals, and mechanical damage. It also regulates temperature and the amount of water released into the environment. This article describes the relevant anatomy of the epidermal layer of the skin, its structure, function, embryology, vasculature, innervation, surgical considerations, and clinical relevance.

Therefore, Skin is the largest organ in the body and covers the body's entire external surface. It is made up of three layers, the epidermis, dermis, and the hypodermis, all three of which vary significantly in their anatomy and function.

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A 1,193 kg car moving at 27.6 m/s hits a stationary truck with a mass of 4,302 kg. If the two vehicles become stuck together in the collision, how fast do they move away from the point of impact?

use units and work out

Answers

The final momentum will be the sum of the initial momentum of the two vehicles. The final velocity of the combined mass will be 5.9 m/s.

What is collision?

Collision is a short range force exerted by an object on other object make them move either to the same side or opposite sides based on their mass.

Momentum of a moving body is the product of its mass and velocity. During a collision, the initial momentum will be equal to the final momentum.

The momentum of the car  = mass × velocity

                                             = 1193 Kg × 27.6 m/s

                                             = 32926 kg m/s

The initial momentum of the truck is zero because it was stationary.

The final momentum with the velocity v, of the combined mass is equal to the total initial momentum i.e. 32926 kg m/s.

32926 kg m/s =  (1193 Kg  + 4302 Kg) v

v = 32926 kg m/s /   (1193 Kg  + 4302 Kg)

  = 5.9 m/s.

Therefore, the final velocity of the vehicles when they stuck together is 5.9 m/s.

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jasper and gemma are going to play on a teeter totter. gemma gets on first. when jasper gets on, gemma moves into the air, but she does not move to the top. a girl sits on the left side of a black line resting at its middle on a brown triangle and a boy on the right. which statement could correctly explain the forces acting on the teeter totter? the forces are balanced because jasper weighs the same as gemma. the forces are unbalanced because jasper weighs the same as gemma. the forces are balanced because jasper weighs more than gemma. the forces are unbalanced because jasper weighs more than gemma.

Answers

The forces are balanced because Jasper weighs the same as Gemma.

Force:

A force is an influence that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, such as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F.Since forces are perceived as pushes or pulls, this can offer a simple explanation of how forces are described.

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a water supply pipe of diameter 2.50 cm carries water from the water main to a sprinkler that is at the top of a small hill. the sprinkler nozzle is 0.50 cm in diameter and the water exits the sprinkler nozzle with a speed of 10.0 ms-1 . if the sprinkler is 8.00 m above the supply pipe, find:

Answers

The volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

What is Bernoulli's equation?

According to Bernoulli's principle of fluid dynamics, a fluid's speed increases at the same time as its static pressure or potential energy decreases. The Bernoulli equation is regarded as the definition of energy conservation for flowing fluids. This is thought to be the qualitative behaviour that reduces pressure in high-velocity zones. Also, referred to as the Bernoulli effect.

Calculations:

Using continuity equation, Bernoulli's equation.

A1×V1 = A2×V2

Where,

A1 = area of the supply pipe

V1 = volume of supply pipe

A2 = area of sprinkler

V2 = volume of sprinkler

Given,

Diameter of supply pipe = 2.5cm therefore radius = 1.25cm.

Diameter of sprinkler = 0.5cm therefore radius = 0.25cm.

V1 = (A2×V2) /A1

V1 = (π [tex]r_{2}[/tex]²× V2) / (π [tex]r_{1}[/tex]²)

V1 = {π (0.25) ² × 8} / { π (1.25) ²}

V1 = 0.32m/s.

Hence, the volume of the sprinkler for the given water supply is V1 = 0.32m/s, by using Bernoulli's equation.

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A motorbike undergoes a constant acceleration from rest and travels a distance
of 60 m in 6.0 s.
What is the acceleration of the motorbike?

Answers

Acceleration equals velocity/time. We have time, 6 seconds; but need to find velocity. Using kinematic equations we know velocity equals distance/time. Our distance is 60m and our time is 6s. Giving us a velocity of 60m/6s = 10m/s. Now we input our velocity and our time values into our acceleration equation.
a = v/t. 10m/s / 6s = 60m/s.

the work function for lead is 4.14 ev. ultraviolet light of wavelength 153 nm is incident on the clean surface of a lead sample. we wish to predict the stopping voltage we will need for electrons ejected from the surface. (a) what is the photon energy of the ultraviolet light?

Answers

speed of the electron is v= 1.371 x 10⁶ m/s.

briefly:-

wavelength of the ultraviolet light beam ARE , λ = 130 nm = 130 x 10⁻⁹ m

the work function of molybdenum surface IS, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

energy of the incident light is :-

E = hf

where;

Planck's constant h= 6.626 x 10⁻³⁴ J/s

f = c / λ

E = hν = hc/λ

E =15.29810-19 J

Photo electric effect equation is;-

E = W₀ + K.E

Where;

K.E =the kinetic energy of the emitted  are electron K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J *- 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of  emitted electron is ;

K.E = ¹/₂mv²

where;

m =mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

K.E. = 1/2 m v2.

V=1.371 x 10⁶ m/s.

speed of the electron is v=1.371 x 10⁶ m/s.

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after protecting the goal, a 90 kg goalie celebrates by leaping 110 cm off the ground. how much work was done in the celebration?

Answers

A 90 kg goaltender celebrate by jumping 110 cm into the air after defending the goal. 970.20 J was work done throughout the celebration.

What is work done?

The sum of the displacement as well as the components of the force applied of the object in the displacement direction is the work done by a force. The body moves with certain acceleration when we push a blocks with certain force, and work is completed.

Briefing:

m = mass of the body = 90 kg

g = gravitational force

h = height = 110cm

Formula -

work done = mgh

                   = 90 × 9.8 × 110

                   = 970.20 J

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what is the velocity of a 900-kg car initially moving at 3000 cm/s, just after it hits a 150-kg deer initially running at 12000 mm/s in the same direction? assume the deer remains on the car.

Answers

The velocity of car is v= 27.42 m/s.

Given;-

the 900 kg car initially moving at 30 m/s and just after it hits a 150 kg deer initially run at 12 m/s in the same direction are:-

m1 = 900kg

m2= 15okg

v1= 30 m/s

v2= 12 m/s

so, velocity is

v=(900*30 + 150*12)/(900+150)

v= 27.42 m/s.

What happens when two things collide in terms of velocity?

When two objects collide, they are both subject to forces that are equal in strength and directed in opposite directions. Such forces frequently result in the acceleration of one object and the deceleration of the other object (lose momentum).

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a balloon originally had a volume of 0.439 l at 44°c and a pressure of 729 torr. to what temperature must the balloon be cooled to reduce its volume to 378 ml if the pressure remained constant?

Answers

According to Charles' Law, the V/T = k, V1/T1=V2/T2, in case v1= 4.39, T1= 44C=317 K (being O C= 273 K) V2=3.78 L T2=?. Charles law, 4.39L/317K = 3.78L/T2. T2x=4.39L/317K = 3.78 L. T2= 3.78L/4.39/317k, T2=273K=0 C

How do you determine a balloon's new volume?

Place the bucket into the larger container, fill it with water, then submerge the inflated balloon completely. After that, remove the bucket, pour the water from the larger container into the measuring container, and measure the volume of the water.

What are the two-volume calculation formulas?

The basic formula for volume is length, breadth, and height, as opposed to length, width, and height for the area of a rectangular shape. The calculation is unaffected by how you refer to the various dimensions; for instance, you can use "depth" instead of "height."

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g water is pumped a vertical distance of 38 m at the rate of 25 1/s. how much work is done in 2.5 min?

Answers

16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

What do you understand by work done?

The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force. Work is accomplished when we push a block with some force; the body moves more rapidly.

What is the distance?

Distance is the sum of an object's movements, regardless of direction. The distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Calculation:

Given,

Distance= 38m

Rate = 25mL/s = 0.25L/s

To find work done in 2.5mins Or 150seconds

Potential energy (P.E) = (mgh) /t

P.E = (mgh) /t

     = (0.25 Ls-¹ * 9.81 * 38m) / 1sec

     = 93.195 Watts

For 1 sec 93.195 watt is used

For 2.5mins Or 180 seconds = 93.195 × 180= 16775 watts or 16.7kW power is used for the work done.

Hence, 16775 watts or 16.7kW is the amount of work done in 2.3 minutes when the water is pumped for a distance of 38m/s.

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what does it mean to say that a beam of light is polarized? the beam has a magnetic field, but no electric field. the beam itself is charged, carrying either positive or negative charge. the direction of the beam's electric field alternates between two possibilities. the beam has an electric field, but no magnetic field.

Answers

Plane polarized light consists of waves that has magnetic field in which the direction of vibration is the same for all waves.

Polarization, in Physics, is defined as a phenomenon caused due to the wave nature of electromagnetic radiation.Sunlight travels through the vacuum to reach the Earth, which is an example of an electromagnetic wave. These waves are called electromagnetic waves because they form when an electric field interacts with a magnetic field.Light is the interaction of electric and magnetic fields travelling through space. The electric and magnetic vibrations of a light wave occur perpendicularly to each other. The electric field moves in one direction and the magnetic field in another ‘perpendicular to each other. So, we have one plane occupied by an electric field, another plane of the magnetic field perpendicular to it, and the direction of travel is perpendicular to both.

Plane polarized light consists of waves in which the direction of vibration is the same for all waves.The process of transforming unpolarized light into polarized light is known as polarization.

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moons that show few craters probably

Answers

Moons that display few craters presumably. They all pass straight over the equator of the globe. Uranus's five biggest moons. have the closest magnetic field axis.

Which 4 moons are known?

There are many fascinating moons around the globe, but the Galilean satellites—Io, Europa, Ganymede, and Callisto—the first four moons identified beyond Earth—hold the most scientific curiosity.

Can Earth have Two moons?

Moon and Earth

The basic explanation is that Earth only has one moon, that we name “the moon”. It is the biggest and brightest object in the night sky, and the only solar system body except Earth that humanity have visited in our space travel activities.

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Use the formula for the law of universal gravitation to calculate the gravitational force between the large ball and the small ball.

Answers

The gravitational force between the large ball and the small ball, given their respective masses is 1.2×10¯¹³ N

How do I determine the gravitational force?

Gravitational force between two objects is given as shown below:

F = GM₁M₂ / r²

Where

F is the force of attraction G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apart

Using the above formula, we can obtain the gravitational force between the the large and small ball as follow:

Mass of small ball (M₁) = 5.0×10⁻³ KgMass of large ball (M₂) = 9.0×10⁻² KgDistance apart (r) = 0.5 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Gravitational force (F) =?

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 5.0×10⁻³ × 9.0×10⁻²) / 0.5²

F = 1.2×10¯¹³ N

Thus, the gravitational force is 1.2×10¯¹³ N

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what is the number n of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to f

Answers

The 24th harmonic is the highest that could be heard  by a person.

A wave or signal that is harmonic has a frequency that is an integral (whole number) multiple of the frequency of the source signal or wave that it is being compared to. The frequency of such a signal or wave relative to the frequency of the reference signal or wave is also referred to as a component of the harmonic series by the word. The first harmonic is sometimes referred to as the basic frequency or initial wave. Higher harmonics are the next harmonics in the series. In addition to the total number of harmonics being periodic at that particular frequency, the fundamental frequency of all harmonics is also.

The word "harmonic" is used in a variety of industries, including music, radio, and all other wave-based technologies.

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Which of the following is the unit of coefficient of radiant heat transfer?
a) W/m2
b) W/m K
c) W/m2 K
d) W/K

Answers

Watts per square meter kelvin (W/m2K), the SI values for the heat transfer coefficient, are used. Radiation, convection, and conduction are the three mechanisms by which heat may be transferred.

Describe heat transmission in detail:

Any or all of the several processes known as heat transfer are assumed to act as transporters of energy and entropy from one location to another. The specific mechanisms are also known by the terms convection, heat radiation, and conduction.

How is heat transfer demonstrated?

Conduction: When you hold a hot cup of coffee, heat is transferred into your hands. Convection: When the barista "steams" cold milk to produce hot chocolate, heat is transferred. Radiation: Microwave-heating a cold cup of coffee

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The kinetic friction force between a 55.0 kg and a horizontal surface is 45.N IF THE initial speed of the object is 24.0m/s and a friction is the only force acting on the object what distance will it slide before coming to a stop

Answers

The distance the 55.0 Kg object will slide before coming to rest, given that it was it was initially tracing at 24 m/s is 351.22 m

How do I determine the distance?

First, we shall obtain the deceleration of the object. Details below

Mass (m) = 55.0 KgForce of friction (F) = -45 NDeceleration (a) = ?

F = ma

Divide both sides by m

a = F / m

a = -45 / 55

a = -0.82 m/s²

Finally, we shall determine the distance the object will slide before coming to rest. Details below

Initial velocity (u) = 24 m/sFinal velocity (v) = 0 m/s Deceleration(a) = -0.82 m/s²Distance (s) =?

v² = u² + 2as

0² = 24² + (2 × -0.82 × s)

0 = 576 - 1.64s

Collect like terms

0 - 576 = -1.64s

-576 = -1.64s

Divide both side by -1.64

s = -576 / -1.64

s = 351.22 m

Thus, we can conclude that the distance is 351.22 m

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when the outer layers of a star like the sun expand, and it becomes a giant, which way does it move on the h-r diagram?

Answers

When a star's outer layers, which are similar to the sun's, expand, the star travels upward and becomes cooler and more bright than the sun.

What is a star ?

Most galaxies have stars distributed throughout them that are born within dust clouds. The Orion Nebula is a well-known illustration of a dust cloud of this type. Even though stars are not alive, we refer to their beginnings and endings as "birth and death." It's a useful, though fantastical, approach to explain the star's ultimately disastrous interaction with matter and energy.

The outer layers start to enlarge, chill, and lose some of their radiance. The name "Red Giant" now refers to the growing star. Convection moves the energy from the shell-burning zone to the star's outer layers. The brilliance of the star eventually rises by a factor of 1000 or so. On the HR diagram, the star will move up and to the right along the Red Giant Branch during this phase of growth.

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Help please like actually someone help me PLEASE

Answers

The final speed of the motorcycle is: 67 m/sec

What is speed?

Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route. In other words, although velocity is a vector, speed is a scalar quantity.

Given that,

initial speed of the motorcycle, u=25 m/sec

Acceleration of the motorcycle, a = 7 m/sec²

According to the equation of motion,

v = u + at

v = 25 m/sec + (7m/sec²) × (6 sec)

v = 67 m/sec

Thus, final speed of the motorcycle is: 67 m/sec

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what is the far point in m of a person whose eyes have a relaxed power of 53.3 d? (assume a lens-to-retina distance of 2.00 cm.)

Answers

According to the question the far point in m of a person's eye is 0.30m.

what is the far point?

In terms of the space the eye can accommodate, this refers to the farthest distance from which an item can be positioned for its picture to be mirrored on the retina. It can also be thought of as the distance from the eyes at which pictures are clearly visible. The units are meters, or m.

Briefing:

P = relaxed power of the eye

F =far point

Given in the question:

The power of the eye is given as

P = 1/di + 1/do

P is power of the eye

di is the distance between eye lens and the image

d₀ is distance between eye lens and image

Given that,

P =53.3d

Take note that the power unit "d" stands for "dioptre," which means "per meter."

If the person can see clearly, the separation between the eye lenses and the picture (di), which is 2 cm, must be identical to that distance.

Thus, di = 2cm = 0.02m

P = 1/di + 1/d₀

1/d₀ = P — 1/di

1/d₀ = 53.3 — 1/0.02

1/d₀ = 53.3—50

1/d₀ = 3.3m

taking reciprocal

d₀ = 1/3.3

d₀ =0.3030m

Then, d₀ = 0.3030m

d₀≈ o.30m

The far point the person can see is 0.30m

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Cigarettes Can Be Used As A Form Of ________. Fiat Money Fake Money Barter
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Cigarettes can be used as a form of ________.

fiat money

fake money

barter

Answers

Cash in dollars. Fiat money refers to any forms of currency that are issued by governments or central banks but are not backed by anything.

What types of exchange mechanisms are examples?

When money is used as a medium of exchange, it speeds up transactions between buyers and sellers because it is commonly accepted as payment for goods and services. Although most societies use money, other exchange methods have included tobacco, salt, gold, and stones.

Exactly what qualifies as a medium of exchange?

A medium of exchange is a device or system that acts as a middleman in transactions involving the exchange of goods between parties. Currency serves as the primary means of exchange in modern economies.

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a string is compressed 1.0 cm. how far must you compress a spring with twice the spring constant to store the same amoutn ofe nergy

Answers

The spring constant for storing the same amount of energy is given as x = 0.707 cm.

What does a string mean?

A string is a computer data type that is similar to an integer and a floating point unit, except it represents text instead of numbers. It is made up of a series of symbols that may also include spaces and numerals.

briefing :

E = /kx2 is the energy that has been stored.

E1 = E2

1/2 k(1.0)² = 1/2 (2k)x²

x^2 = 1/2 (1.0)²

x = 1.0/√2 cm

x = 0.707 cm

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what wavelengths appear in the system's emission spectrum?

Answers

The possible wavelengths that appear In the emission spectrum of the system are [tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Given:

The quantum energy levels allowed In the system are:

[tex]$$\begin{aligned}& E_1=1.0 \mathrm{eV} \\& E_2=2.0 \mathrm{eV} \\& E_3=4.0 \mathrm{eV} \\& E_4=7.0 \mathrm{eV}\end{aligned}$$[/tex]

What is wavelength of the emission?

As the transition of electron takes from one energy level to another, there is an emission of particular wavelength from the transition. The relation between the wavelength of the emission and the energy of the energy level Is expressed as:

[tex]$$E_f-E_i=\frac{h c}{\lambda}$$[/tex]

Here, [tex]$E_f$[/tex] is the final energy level, [tex]$E_i$[/tex] is the Initlal energy level and [tex]$\lambda$[/tex] is the wavelength of emlsslon.

(1). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_2$[/tex] energy level:

[tex]$$\begin{aligned}E_2-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(2-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =1.244 \times 10^{-6} \mathrm{~m} \\& \approx 1200 \mathrm{~nm}\end{aligned}$$[/tex]

(2). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

(3). Transition of electron from [tex]$E_1$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_1 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-31}\right) \times\left(3 \times 10^8\right)}{(7-1)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.207 \times 10^{-6} \mathrm{~m} \\& \approx 210 \mathrm{~nm}\end{aligned}$$[/tex]

(4). Transition of electron from [tex]$E_2$[/tex] to [tex]$E_3$[/tex] energy level:

[tex]$$\begin{aligned}E_3-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(4-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.621 \times 10^{-6} \mathrm{~m} \\& \approx 620 \mathrm{~nm}\end{aligned}$$[/tex]

(5). Transition of electron from[tex]$E_2$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_1-E_2 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-2)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.248 \times 10^{-6} \mathrm{~m} \\& \approx 250 \mathrm{~nm}\end{aligned}$$[/tex]

(6). Transition of electron from [tex]$E_3$[/tex] to [tex]$E_4$[/tex] energy level:

[tex]$$\begin{aligned}E_4-E_3 & =\frac{h c}{\lambda} \\\lambda & =\frac{\left(6.63 \times 10^{-34}\right) \times\left(3 \times 10^8\right)}{(7-4)\left(1.6 \times 10^{-19}\right)} \mathrm{m} \\& =0.414 \times 10^{-6} \mathrm{~m} \\& \approx 410 \mathrm{~nm}\end{aligned}$$[/tex]

Thus, The posslble wavelengths that appear in the emisslon spectrum of the system are[tex]$210 \mathrm{~nm}, 250 \mathrm{~nm}, 410 \mathrm{~nm}, 620 \mathrm{~nm}, 1200 \mathrm{~nm}$[/tex].

Complete question: The allowed energies of a quantum system are 1.0 ev, 2.0 ev, 4.0 ev, and 7.0 ev. what wavelengths appear in the system's emission spectrum

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what should you point out on a demonstration drive when depressing 2023 versa throttle three-quarters of the way to the floor

Answers

You should emphasize during a test drive that the 2021 Versa's CVT replicates shifts like an ordinary automatic transmission by depressing the accelerator approximately 75% of the way to the floor.

Explain the term demonstration drive?A test drive is indeed the act of operating a motor vehicle to evaluate its general operational condition, drivability, and roadworthiness. A test driver is a person who tests cars for a living, whether for an automaker, the automotive press for reviews, or a racing team.

You should emphasize during a test drive that the 2021 Versa's CVT replicates shifts like an ordinary automatic transmission by depressing the accelerator approximately 75% of the way to the floor.

Engine noise that would usually result from continuous acceleration at high revs is reducedAnother more linear acceleration sensation is present.

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