albert worked for 8 hours and earned $24. how much does albert earn for 24 hours
Answer:
$72
Step-by-step explanation:
Lindsey is a member of the swim team at a local university. She has been working hard to perfect her dive for an upcoming swim meet. Lindsey's dive can be modeled by the quadratic equation y = – 16x2 + 33x + 45, where x is time in seconds, and y is Lindsey's height in the air in feet.
1. At what time will Lindsey be 30 feet in the air?
2. How high is the diving board? Explain your thinking.
Answer:
1. [tex]x = 2.45s[/tex]
2. The diving board is 45 ft high.
Step-by-step explanation:
• When Lindsey is 30 feet in the air, y = 30.
[tex]30 = -16x^2 + 33x +45\\\\-16x^2 + 33x +15 = 0\\\\16x^2 - 33x -15 = 0\\[/tex]
Using quadratic formula, solve for x:
[tex]x = \frac{33 + \sqrt[]{(-33)^2 - 4(16)(-15)} }{2(16)}[/tex]
[tex]x = 2.45s[/tex]
• If we calculate the height of Lindsey in the air when she is standing on the diving board, we can find the height of the diving board above the ground.
When she is standing on the board, x = 0 as no time has passed after jumping.
[tex]y = -16(0)^2 + 33(0) +45\\\\y = 45 ft[/tex]
This is all the questions I need answers to:
A two-digit locker combination has two non-zero digits and no two digits are the same. Event A is defined as choosing an even digit for the first number, and event B is defined as choosing an odd digit for the second number.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
A. 4/9
B. 1/2
C. 5/9
D. 5/8
A locker combination consists of two non-zero digits, and each combination consists of different digits. Event A is defined as choosing an even number as the first digit, and event B is defined as choosing an even number as the second digit.
If a combination is picked at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 1/6
B. 5/18
C. 1/2
D. 5/9
A jar contains 5 red marbles and 8 white marbles.
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
If two marbles are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?
A. 3/13
B. 10/39
C. 5/12
D. 8/13
A bag contains 5 blue marbles, 8 green marbles, 4 red marbles, and 3 yellow marbles.
Event A = drawing a green marble on the first draw
Event B = drawing a blue marble on the second draw
If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?
A. 2/19
B. 1/6
C. 4/19
D. 5/19
A jar contains 3 pink balls, 6 blue balls, and 3 red balls.
Event A = drawing a red ball on the first draw
Event B = drawing a pink ball on the second draw
If two balls are drawn from the jar, one after the other without replacement, what is P(A and B) expressed in simplest form?
A. 3/44
B. 4/9
C. 3/11
D. 1/4
House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?
A. 1/9
B. 5/72
C. 5/8
D. 2/3
House numbers along a street consist of two-digit numbers. Each house number is made up of non-zero digits, and no digit in a house number is repeated.
Event A is defined as choosing 8 as the first digit, and event B is defined as choosing a number less than 6 as the second digit.
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?
A. 2/7
B. 5/14
C. 5/13
D. 6/13
A two-digit locker combination is made up of two non-zero digits. Digits in a combination are not repeated and range from 3 through 8.
Event A = choosing an odd number for the first digit
Event B = choosing an odd number for the second digit
If a combination is chosen at random, with each possible locker combination being equally likely, what is P(A and B) expressed in simplest form?
A. 1/5
B. 3/14
C. 5/18
D. 2/5
A locker combination consists of two non-zero digits. The digits in a combination are not repeated and range from 2 through 9.
Event A = the first digit is an odd number
Event B = the second digit is an odd number
If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
A. 3/8
B. 3/7
C. 1/2
D. 4/7
There are 15 tiles in a bag. Of these, 7 are purple, 5 are black and the rest are white.
Event A = drawing a white tile on the first draw
Event B = drawing a purple tile on the second draw
If two tiles are drawn from the bag one after the other and not replaced, what is P(B|A) expressed in simplest form?
A. 1/5
B. 1/3
C. 7/15
D. 1/2
I know theres a lot here but please hurry :) thx 100 points to the first person to answer all correctly! thx :)
The is probability P(B|A) expressed in simplest form is 1/2 (Option B) See computation below.
How do we derive the above?P (A) = [[tex][\mathrm{C}_{5}^{1} \mathrm{C}_{8}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 8)/(9 x 8)
P (A) = '5/9
P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 4)/(9 x 8)
= '5/18
P(B|A) = P (AB)/P(A)
= ('5/18)/('5/9)
P(B|A) = 1/2
How do we derive P(A and B) in the simplest form?From the above we already have P (AB)
this is given as
P (AB) = [tex][\mathrm{C}_{5}^{1} \mathrm{C}_{4}^{1}]/ \mathrm{A}_{9}^{2}[/tex]
= ('5 x 4)/(9 x 8)
P(AB) = '5/18
How do we derive P(A and B) in the simplest form where a jar contains 5 red marbles and 8 white marbles?Note that:
Event A = drawing a white marble on the first draw
Event B = drawing a red marble on the second draw
P(A) = 8/13; while
P (B) = (5/12) because the first marble was not replaced, thus reducing th sample to 12.
Thus
P(A and B) = P(A)*P(B) = 8/13 * 5/12
P(A and B) = 10/39 (Option B)
If Jasmine draws two marbles from the bag, one after the other and doesn’t replace them, what is P(B|A) expressed in simplest form?Event A - Probability of Drawing a Green Marble is 8/20
Event B - Probability of Drawing a Blue Marble is 5/19
Thus P(B|A) = (8/20) * (5/19)
= [tex]\frac{8 * 5 }{20 * 19}[/tex]
= 40/380; divide numerator and denominator by 20
P(B|A) = 2/19 (Option A)
Event A = Probability of Drawing a red ball = 3/12
Event A = Probability of Drawing a pink ball without replacing the read in Event A = 3/11
Thus P (B and A) =
3/12 x 3/11
P (B and A) = 3/44 (Option A)
If a house number along this street is picked at random, with each number being equally likely and no repeated digits in a number, what is P(A and B) expressed in simplest form?The conditions given are as follows:
The house number comprises of nonzero digits and are of two digits ranging from 1 to 9.As per the condition, the First digit 8 can be selected in 9 ways; and Second digits is less than 6 can be selected in waysThe sum total of ways thus is
9 x 8
= 72 ways........X
Recall that
Event A is defined as selecting 8 as the first numeral
The only way to select this is one way
Event B is defined as choosing a number less than 6 as the second digit, that is 1, 2, 3, 4, 5
Thus, the possible number of ways to fill second digit = 5/8
Thus, the possible number of ways to form two digits 'AnB' =
('AnB') = 1 x 5 = 5 .................y
Hence Probability (AnB) = 5/72 (Option B)
Given that the non-zero digits are in a combination are not repeated and range from 3 through 8, thus the odd numbers between 3 and 8 are:
3, 5, 7
total numbers is 3, 4, 5, 6, 7, 8
Hence; Event A = choosing an odd number for the first digit = 3/6
Event B = choosing an odd number for the second digit (recall that the numbers are not repeated) = 2/5
= [tex]\frac{2*3}{3*6}[/tex]
= 6/30
= 1/5 (Option A)
If a combination is picked at random with each possible locker combination being equally likely, what is P(B|A) expressed in simplest form?
Event A = the first digit is an odd number
Event B = the second digit is an odd number
The numbers from 2 to 9 are:
2,3,4,5,6,7,8,9
The odd numbers between 2 and 9 are:
3,5,7,9
P (A) = 4/8
P (B) = 3/7
P(B|A) = (3/7)/(4/8)
P(B|A) = 3/7
Event A = drawing a white tile on the first draw
Event B = drawing a purple tile on the second draw
P(B|A) = (P(AnB)/P(A)
|n| = 15 * 14 = 210
| A| = 3*14 = 42
| AnB| = 3*7 = 21
P (A) = 42/210 = 6/30
P (AnB) = 21/210 = 1/10
P(B|A) = (1/10)/6/30)
P(B|A) = 1/10 * 30/6
P(B|A) = 30/60
P(B|A) = 1/2 (Option D)
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What is (-2)-(-2 1/6) and how do i get that answer?
Answer:
1/6
Step-by-step explanation:
-2 - (-2 1/6)
multiply the number in the parentheses by -1
-2 + 2 1/6
-2 + 2 cancels out
Leaving 1/6 as your answer.
PLEASE HELP ME WITH THIS MATH PROBLEM!!
Step-by-step explanation:
in general we would need a probabilty table or a probability calculator service on the internet.
but in this case we know.
the man value is 64. and the standard deviation is 6.
so, one standard deviation +/- interval from the mean value is 70 and 58.
and the interval of 2 standard deviations from the mean value is 76 and 52.
and 64 and 76 are exactly the limits we are asked for.
so, remember the normal distribution rule :
68% are within 1 standard deviation.
95% are within 2 standard deviations.
99.7% are within 3 standard deviations.
and 50% are below (and also above) the mean value.
so, we know, 50% of the 350 (= 175) students scored below 64.
95% of the students scored between 76 and 52. as there are 5% left, half of these 5% (= 2.5%) scored even below 52).
so, 95% + 2.5% = 97.5% of the 350 (= 341.25) students scored below 76.
therefore, the number of students that scored between 64 and 76 is
341.25 - 175 = 166.25 ≈ 166
A school is watching students as they enter the football game for students who are dressed
inappropriately. they estimate that 7% of all students are dressed inappropriately. out of a group
of 40 students, what is the probability that exactly 2 are dressed inappropriately? round to 3 decimal places.
Using the binomial distribution, it is found that there is a 0.242 = 24.2% probability that exactly 2 are dressed inappropriately.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.The values of the parameters are given as follows:
n = 40, p = 0.07.
The probability that exactly 2 are dressed inappropriately is given by P(X = 2), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{40,2}.(0.07)^{2}.(0.93)^{38} = 0.242[/tex]
0.242 = 24.2% probability that exactly 2 are dressed inappropriately.
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Find the coordinates of the midpoint of the segment whose endpoints are given W (-3,-7) and X (-8,4)
1. (-11/2) -(11/2)
2.(-5/2)-(3/2)
3.(-5/2-(11/2)
The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.
The complete options are given below.
1. (-11/2) -(11/2)
2.(-5/2)-(3/2)
3.(-5/2-(11/2)
4. (-11/2) -(-3/2)
What is the midpoint of line segment AB?Let C be the mid-point of the line segment AB.
A = (x₁, y₁)
B = (x₂, y₂)
C = (x, y)
Then the midpoint will be
x = (x₁ + x₂) / 2
y = (y₁ + y₂) / 2
The end points are given below.
(-3, -7) and (-8, 4)
We have
(x₁, y₁) = (-3, -7)
(x₂, y₂) = (-8, 4)
Then the mid-point will be
x = (- 3 - 8) / 2
x = -11 / 2
y = (-7 + 4) / 2
y = -3/2
Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).
Then the correct option is D.
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Question 3(Multiple Choice Worth 5 points)
(06.03 LC)
Determine the equation of the graph, and select the correct answer below.
(-1, 3)
i need help finding this for clever
Answer:
The dog is 16 years old.
Step-by-step explanation:
X/4 + 6 = X/8 + 8
X/4-X/8 = 8-6
0.125X = 2
X = 2/0.125
X = 16
Answer:
16 years old
Step-by-step explanation
Dividing the dog’s age by 4 and adding 6
D÷4 + 6
dividing the dog’s age by 8 and adding 8
D÷8 + 8
equating both
D÷4 + 6 = D÷8 + 8
=> D÷4 - D÷8 = 2
multiplying by 8 both sides
=> 2D - D = 16
=> D = 16
hence, the dog is 16 years old
Given lJK , which is an isosceles right triangle, IJ=4 and m
As IJK is isosceles
IJ=JKHypotenuse must not counted counted among equal sides so
IK²=2(LJ)²Apply roots
IK=LJ√2Option C
y=-6x-8
y=-6x+8
Solve the system of linear equations
Answer: No solution
Step-by-step explanation:
Both of these equations have the same number as to coefficient of x (-6) but have a different constant (-8 and 8). This means that there are no solutions to this system of equations.
a) Write 2 expressions for the area of the shaded region.
b) Find the length of the shaded region if the perimeter is 48cm.
c) Find the area of the shaded region if perimeter is 48cm.
Answer:
(a)9×3=37' 97 and 8 are factors of 37
Write the rate in lowest terms a printer can print 22 pages in 55 seconds
Answer:
2/5
Step-by-step explanation:
22/11=2
55/11=5
The probability of a drawing a blue marble from a box of 18 marbles is 2/3. How many green marbles should be added to the box in order to reduce the probability to 1/2?
Answer:
6 green marbles should be added.
Step-by-step explanation:
If the probability of drawing a blue marble from 18 marbles is 2/3 then there are 12 blue marbles because 18 times 2/3 is 12. This means that to reduce this probability to 1/2 you need to add 6 more marbles to the total amount to get it to 24. Now the probability of getting a blue marble is 12/24 which is 1/2.
Use the FOIL method to evaluate the expression:
Answer:
[tex]\sf b.) \ 1 +2\sqrt{7}[/tex]
Explanation:
Foil method: (a + b)(c + d) = ac + ad + bc + bd
Solving steps:
[tex](4 - \sqrt{7} )(2 + \sqrt{7} )[/tex]
[tex](4)(2) + 4(\sqrt{7} ) + (-\sqrt{7} )(2) + (-\sqrt{7} )(\sqrt{7} )[/tex]
[tex]8 + 4\sqrt{7} - 2\sqrt{7} - 7[/tex]
[tex]8 -7 + 4\sqrt{7} - 2\sqrt{7}[/tex]
[tex]1 +2\sqrt{7}[/tex]
option b) 1 + 2√7
Step-by-step explanation:Foil property method :-
[tex] \red{ \boxed{ \orange{ \rm (a + b)(c + d) = ac + ad + bc + bd}}}[/tex]
then, on substituting the values,
[tex]\sf⇒ \: \: 8 + 4 \sqrt{7} - 2 \sqrt{7} - 7[/tex]
[tex]\sf⇒ \: \: \green{ \underline{\bold{ \red{1 + 2 \sqrt{7} }}}}[/tex]
Progress
Solve for x. Round to the nearest tenth, if necessary
Answer:
x ≈ 1.1
Step-by-step explanation:
using the cosine ratio in the right triangle
cos41° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{0.8}{x}[/tex] ( multiply both sides by x )
x × cos41° = 0.8 ( divide both sides by cos41° )
x = [tex]\frac{0.8}{cos41}[/tex] ≈ 1.1 ( to the nearest tenth )
Which of the following is equivalent to 8-3x > 2(3x - 5) ?
A. 18>9x
B. 9x<13
C. 11>9x
D. -8x>2
Answer:
A
Step-by-step explanation:
Given:
[tex]8-3x > 2(3x-5)[/tex]
Simplify by distributing:
[tex]8-3x > 6x-10[/tex]
Add 10 to left side and add 3x to the right side:
[tex]18 > 9x[/tex]
please help me find the HCF of this
Answer: a
Step-by-step explanation:
[tex]a^{2}=a \cdot a\\a^{2}+ab=a(a+b)[/tex]
Therefore, the HCF is a.
Answer:
a
Step-by-step explanation:
Factorizing both terms :
a² = a × aa² + ab = a × (a + b)The HCF of the terms is a.
Maria is on a hike. if she hikes to the scenic lookout on the following map first, she will have to hike farther than if she went straight to the end of the hike. 3 connected points on a coordinate plane. the point labeled, "maria," is at 4, -4. the point labeled, "end," is at -5, 5. a solid line connect the points "maria" and "end." the point labeled, "scenic lookout," is at 2, 3. dashed lines connect "maria" to "scenic lookout" and connect "scenic lookout" to "end." coordinate values on the map are in kilometers. how much shorter is the path straight to the end of the hike than past the scenic lookout? round your final answer only to the nearest kilometer. \text{km}kmstart text, k, m, end text
The path straight to the end of the hike is 6 km farther than past the scenic lookout.
How to determine the difference in the parts?The map is not given, but the question can still be answered
From the question, the positions are given as::
Maria = (4, -4)
Scenic = (2, 3)
End = (-5, 5)
The distance between Maria and the end point is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 1 = \sqrt{(4 + 5)^2 + (-4 -5)^2}[/tex]
[tex]Route\ 1 = 13[/tex]
The distance between Maria and the scenic lookout is calculated using:
[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]
So, we have:
[tex]Route\ 2 = \sqrt{(4 - 2)^2 + (-4 -3)^2}[/tex]
[tex]Route\ 2 = 7[/tex]
The distance between both routes is:
Distance = 13 - 7
Evaluate
Distance = 6
Hence, the path straight to the end of the hike is 6 km farther than past the scenic lookout.
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Which equation is equivalent to the given equation?
-4(X - 5) + 8x = 9x - 3
Answer:
-5x=-23
Or
X=23/5
Step-by-step explanation:
32 divided by 4x [16x1/2]-2
Select all that apply. Which of the following corresponds to absolute zero?
In thermodynamic system, Absolute Zero is that temperature implies Lowest energy level i.e. option a) 0 K or -273° C.
What is Absolute Zero?
Absolute Zero can describe as, in a thermodynamic system, there are certain energy levels depending upon the potentials of temperature. At Absolute zero the potentials of temperature are 0 K in Kelvin scale and -273° C in Celsius scale.
The question seem's to be incomplete. The option could be.
a) 0 K and -273° C
b) 273 K and 0° C
c) -273 K and 0° C
d) 0 K and 273° C
Hence, As per theory Value of The absolute zero is 0 K and -273° C
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Round 508.0219 to the nearest hundredth
Answer:
508.02
HOPE THIS HELPS
Todo <3
Step-by-step explanation:
Which ordered pair is not a solution of the linear equation shown?
1
y=-x
2
OA) (2, 1)
B) (1.-—-)
1,
2
OC) (4,8)
OD) (-2,-1)
Answer:
C : (4,8)
Step-by-step explanation:
The equation y = (1/2) x
Or, 2y = x ==> x = 2y
means that, for any value of x, the y value must be one-half that value or, in other words, for any value of y, x must be twice the value of y
A, B and D will satisfy the above equation if you plug in values of x and y given
In C we have x = 4 and y =8 so x = y/2 NOT 2y
x(y − 3) + n(3 − y)
(c) Given that the average speed for the entire journey was 80 km/h, form an equation in x and solve the equation.
Answer:
80x = y
Step-by-step explanation:
Which numbers are the extremes of the proportion shown below?
3-604
=
8
A. 3 and 8
B. 3 and 6
C. 4 and 6
D. 4 and 8
Answer:
A 3 and 8
Step-by-step explanation:
if a/b=c/d, the extremes are "a" and "d". The means would then be "b" and "c"
The extremes of the proportion are 3 and 8.
To find the extremes of a proportion, we need to identify the numbers that are positioned at the far ends of the proportion. In the given proportion:
3/4 = 6/8
The numerator of the first fraction, 3, and the denominator of the second fraction, 8, are the extremes. These numbers form the far ends of the proportion.
Therefore, the extremes of the proportion are 3 and 8.
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PLEASE HELP I WILL MARK BRAINLEST
#1
Error at sign shift due to -Correct version
[tex]\\ \rm\Rrightarrow (x^3+2x^2-x)-(3x^3-3x^2+2x-4)[/tex]
[tex]\\ \rm\Rrightarrow x^3+2x^2-x-3x^3+3x^2-2x+4[/tex]
[tex]\\ \rm\Rrightarrow x^3+5x^2-3x+4[/tex]
#2
Not multiplied 3x with x[tex]\\ \rm\Rrightarrow (x^2-3x+2)(x+1)[/tex]
[tex]\\ \rm\Rrightarrow x(x^2-3x+2)+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-3x^2+2x+x^2-3x+2[/tex]
[tex]\\ \rm\Rrightarrow x^3-2x^2-x+2[/tex]
Using the relationships between
perpendicular lines and their slopes, explain
why horizontal and vertical lines will always
be perpendicular.
Be sure to include the slopes of horizontal
and vertical lines as part of your answer
Answer:
They will always intersect at one point
Step-by-step explanation:
^^
Write the algebraic expression for the following statement.
A number decreased by 7 is 5.
Answer:
the algebraic expression is ; x-7=5
