Find the midpoint of PQ¯¯¯¯¯¯¯¯ with endpoints P(0, 2) and Q(6,−2). Then write an equation of the line that passes through the midpoint and is perpendicular to PQ¯¯¯¯¯¯¯¯ . This line is called the perpendicular bisector.

Answer:

b

Step-by-step explanation:

tan equal to (opposite side) /(adjacent side)

am not able to write root 3 on phone but its something like this

(a¤3)/a

in which¤3 is root 3

Answer:

the answer is b when we have two positives it makes a negitive therefore its b

Step-by-step explanation:

hopefully this answer can help you to answer the next question.

Answer:

3x+4

Step-by-step explanation:

You have to combine like terms to get 3x+4.

Answer:

R theta 1 = 20 x

R theta 2 = 11 x  - 6

R ( theta 1 + theta 2) = 31 x - 6     adding equations

R pi = 31 x - 6       since theta 1 + theta 2 = 180 deg

x = (R pi + 6)  / 31

This equation depends only R

If one lets R be one then   x = (pi + 6) / 31

This would give x = .29489 rad for the value of pi is deg

The numerical value of x appears to depend on the value of R

Answer:

? = 42

Step-by-step explanation:

24/8 = ?/14

cross mult

24/8 = x/14

336=8x

x = 42

Answer:

Option B

You use sine rule to find the missing angles

Answered by GAUTHMATH

For any triangle ABC, The correct option the given triangle is B. m∠B=47, m∠C=28, b=28.

For any triangle ABC, with side measures |BC| = a. |AC| = b. |AB| = c,

we have, by law of sines,

[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b} = \dfrac{sin\angle C}{c}[/tex]

Remember that we took,

[tex]\dfrac{\sin(angle)}{\text{length of the side opposite to that angle}}[/tex]

We have been given angle A = 105 degrees and side a = 37, side c = 18.

[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle C}{c}\\\\\dfrac{sin\angle 105}{37} = \dfrac{sin\angle C}{18}\\\\sin\angle C = \dfrac{sin\angle 105}{37} \times 18 \\\\sin\angle C = 28[/tex]

By angle sum property;

A + B + C = 180

105 + 28 + B = 180

B = 180 - 133

B = 47

Therefore,

[tex]\dfrac{sin\angle A}{a} = \dfrac{sin\angle B}{b}\\\\\dfrac{sin\angle 105}{37} = \dfrac{sin\angle 47}{b} \\\\b = 28[/tex]

Hence, the correct option the given triangle is B. m∠B=47, m∠C=28, b=28.

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Answer:

phthagoras

Step-by-step explanation:

Answer:

Hence the degrees of freedom are associated with the critical value is 25.

Step-by-step explanation:

Using two independent samples, two population means are  

compared to determine if a difference exists, the population standard deviation is equal.  

sample size 1 = [tex]n_{1}[/tex]= 15 and sample size 2 = [tex]n_{2}[/tex] = 12  

since, population standard deviations are equal, required degrees of freedom              

[tex]= n_{1} + n_{2} - 2 \\= 15 + 12 - 2\\ = 25[/tex]  

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from angle x, we know the opposite side and the adjacent side. Therefore, we should use the tangent function to solve.

tan(x) = 8/10

x = tan^-1(8/10)

x = 38.7 degrees

Hope this helps!

Answer:

The answer is the Second Option

Step-by-step explanation:

Answer:

the second one sqrt(10) + sqrt(15) -sqrt(14) - sqrt(21)

Step-by-step explanation:

Answer and explanation:

Given two natural numbers n and n+3, we prove that the difference or their squares is even thus:

(n+3)²-(n)²= (n+3)(n+3)-(n)²

=n²+3n+3n+9-n²

=6n+9

Since the value of the difference of square of the natural numbers n and n+3 is in the form 6n+9, the difference is not an even number.

Answer:

Question 3: 220 centimeters

Question 4: 31.4 millimeters

Step-by-step explanation:

Question 3:

Formula for circumference: 2πr

2πr

Exchange π for 22/7

2 · (22/7) · r

Exchange r (radius) for 35

2 · (22/7) · 35

Simplify:

2 · (22/7) · 35

44/7 · 35

220; 220 centimeters

Question 4:

Formula for circumference: 2πr

2πr

Exchange π for 3.14

2 · 3.14 · r

Exchange r (radius) for 5

2 · 3.14 · 5

Simplify:

2 · 3.14 · 5

6.28 · 5

31.4; 31.4 millimeters

Answer:

Step-by-step explanation:

Concept:

Here, we need to know the idea of circumference.

The circumference is the perimeter of a circle. The perimeter is the curve length around any closed figure.

Circumference = 2πr

Solve:

Question # 1

r = 35 cm

π = 22/7

Circumference = 2πr

Circumference = 2 (22/7) (35)

Circumference = 2 (110)

Circumference = 220 cm

Question # 2

r = 5 mm

π = 3.14

Circumference = 2πr

Circumference = 2 (3.14) (5)

Circumference = 10 (3.14)

Circumference = 31.4 mm

Hope this helps!! :)

Please let me know if you have any questions

The median GPA of the  percussionists is 2.8

This question appears incomplete.

Here is the complete question :

Members of a band class were arguing over which instruments are played by the best academic students. A survey was conducted, and here are the results:

All 13 flute players had a grade point average (GPA) between 3.84 and 3.88.

There were only 3 percussionists. One had a GPA of 2.4, one had a GPA of 2.8, and one had a GPA of 3.2.

Among the saxophone players, 4 had a GPA of 3.9, and the other 5 had a GPA of 4.0.

For percussionists, the median GPA is _____.

Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order

Median is a measure of central tendency

Other measures of central tendency include  mean and mode.

The GPA of the 3 percussionists are 2.4, 2.8 and 3.2

This data has already been arranged in ascending order.

The number that is in the middle is 2.8

Conversely, if the GPA is arranged in descending order, it is 3.2, 2.8 and 2.4

The number that is in the middle is 2.8

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Answer:

x=24 y=33

Step-by-step explanation:

If a diameter or radius is perpendicular to a chord, then it bisects the chord and its arc.

Answer:

152

Step-by-step explanation:

Substitute the given value for x.

[tex]8(3(6)+1)\\8(18+1)\\8(19)\\152[/tex]

Answer:

152

Step-by-step explanation:

8(3x+1)

Let x = 6

8(3*6+1)

Multiply inside the parentheses

8(18+1)

Add inside the parentheses

8(19)

Multiply

152

Answer:

162

Step-by-step explanation:

because this is a parallelogram :

m<2 = m<4 so

4x - 22 = 3x - 12

4x - 3x = 22 - 12

x = 10 replace x with 10 in the equation for m<4

3x - 12 is 30 - 12 = 18

m<4 and m<1 are supplementary and their sum is equal to 180

m<4 + m<1 = 180

m<1 = 180 - 18

m<1 = 162

A function is only a function if it passes the vertical line test, meaning every x-value has only one y-value. In the case of this graph, it does not pass the vertical line tests and has multiple y-values for each x-value.

Correct Answer: A. No; the graph fails the vertical line test.

B is incorrect because y-values can have more than 1 x-value, such as a function like y = 2. The opposite is the correct statement; x-values can have no more than 1 y-value. For example, x = 2 would not pass the vertical line test.

Hope this helps!

Answer:

(21 and 54): 3

(55 and 90): 5

(16 and 30): 2

(42 and 91): 7

(66 and 121): 11

Step-by-step explanation:

Answer:

9.9

Step-by-step explanation:

Let the side of ZX = x

4/8 = x/19.8

Cross-multiply

8x = 79.2

Divide both sides by the coefficient

8x/8 = 79.2/8

x = 9.9

Answer:

Step-by-step explanation:

In a parallelogram, this one in particular:

KR = RM

JR = RL

We are looking in the end for the length of JR, but that means that we need to solve for x somehow to plug in the expression for JL, and then split that in half. Here's how we're going to go about it. I know that

KM = KR + RM, but since KR and RM are the same length, the equation becomes

KM = 2KR. Filling that in with the expressions I'm given for KM and KR:

3x - 5 = 2(x + 7) and

3x - 5 = 2x + 14 and

x = 19. Now I can find the length of JL:

JL = 4x - 10 so

JL = 4(19) - 10 and

JL = 66

Knowing that JR = RL and JL is 66 units long, JR = RL = 33 units each.

Answer:

x

Step-by-step explanation:

Answer:

4.

Step-by-step explanation:

The highest exponent is 4 so the degree is 4.

Answer:-3x2-5x+2

Step-by-step explanation:

Distribute -2x to x+3, and then x+1 to x-2

[tex]-2x^{2}[/tex] [tex]-6x[/tex] [tex]-x(x-2)+1(x-2)[/tex]

[tex]-2x^{2} -6x-x^{2} +2x+1x-2[/tex]

[tex]-3x^{2} -3x-2[/tex]

Sorry it’ll be -3x2 -5x +2

Hi there!  

»»————-　★　————-««

I believe your answer is:  

760

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the answer...}}\\\\(35+5)[16+(12\div 4)]\\------------------\\\text{Follow \textbf{PEMDAS}}\\\\\rightarrow 35+ 5 = 40\\\\40[16+(12\div 4)]\\\\\rightarrow 12\div4 = 3\\\\\rightarrow 16 + 3 = 19\\\\40(19)\\\\\rightarrow 40 * 19\\\\\boxed{760}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

Step-by-step explanation:

Distance = the square root of (x2-x1)2 + (y2-y1)2Added:Distance Formula: Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula:square root of x2-x1 squared +y2-y1 squared

The value of x is (√12) - 2, when the distance between (x,1) and (-2,5) is 2√7 units.

The distance or length of any line on the graph,

[tex]d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

where,

d = distance/length of the line between point 1 and 2,

(x₁ , y₁) = coordinate of point 1,

(x₂ , y₂) = coordinate of point 2,

Given that the distance between (x,1) and (-2,5) is 2√7 units. Therefore we can write,

[tex]d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}[/tex]

[tex]2\sqrt7= \sqrt{(x + 2)^2 + (1-5)^2}[/tex]

Squaring both the sides of the equation,

[tex](2\sqrt7)^2= (\sqrt{(x + 2)^2 + (1-5)^2})^2[/tex]

4 × 7= (x + 2)² + (-4)²

28 = (x+2)² + 16

28 - 16 = (x+2)²

12 = (x+2)²

x+2 = √12

x = (√12) - 2

Hence, the value of x is (√12) - 2.

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Answer:

(0.7465 , 0.8429 )

Step-by-step explanation:

Confidence Level - "P" values  

90% 1.645

Confidence Interval - "P" values  

(0.7465 , 0.8429 )  

Answer:

∠ HFG = 79°

Step-by-step explanation:

The inscribed angle HFG is half the measure of its intercepted arc, that is

∠ HFG = [tex]\frac{1}{2}[/tex] × 158° = 79°

This question is solved by proportions

Doing this, we found that there were 144 students.

20736 was distributed. The number of rupees for each student is the number of students.

Considering n students, the amount each student receives is:

[tex]A = \frac{20736}{n}[/tex]

Considering each student received n rupees:

[tex]n = \frac{20736}{n}[/tex]

Applying cross multiplication:

[tex]n^2 = 20736[/tex]

[tex]n = \sqrt{20736}[/tex]

[tex]n = 144[/tex]

Thus, there were 144 students.

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