Find the Product or expression of: (4x-2)2​

Answers

Answer 1

Answer:

8x-4

Explanation:

Distributive property:

A(B+C)=AB+AC

(4x-2)2

Switch sides.

→ 2(4x-2)

Multiply.

⇒ 2*4x=8x

⇒ 2*2=4

Rewrite the problem down.

⇒ = 8x-4

[tex]\Longrightarrow: \boxed{\sf{8x-4}}[/tex]

Hence, the final answer is 8x-4.

I hope this helps you! Let me know if my answer is wrong or not.

Answer 2

Answer: 8x - 4

Explanation:

(4x -2)*2

apply distributive property

2* 4x - 2 * 2

Multiply the monomials = 8x

2*4x - 2*= 8x-2*2

calculate =

8x-4

Answer: 8x - 4


Related Questions

a 56-kg student runs at 6.2m/s, grabs a hanging 10.0m long rope, and swings out over a lake. He releases the rope when his velocity is zero.
a) what is the tension in the rope just before he releases it?
b) what is the maximum tension in the rope during the swing?

Answers

Answer:

0.52     8.9  

Explanation:

calc.

The tension in the rope just before the student releases it is 576 N.

What is tension?

Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object.

Just before the student releases the rope, his velocity is zero. At this point, all of his kinetic energy has been converted into potential energy. Therefore, we can write:

1/2 m [tex]v^2[/tex] = mgh

h = [tex]v^2[/tex] / (2g) = [tex](6.2 m/s)^2[/tex] / (2 x 9.8 [tex]m/s^2[/tex]) ≈ 1.95 m

m g = 56 kg x 9.8 [tex]m/s^2[/tex] ≈ 549 N

The tension required to keep the rope taut is equal to the horizontal component of the force due to the weight of the student, which is:

T = m g / cos(θ)

tan(θ) = h / L

tan(θ) = 1.95 m / 10.0 m ≈ 0.195

θ ≈ 10.9°

So, T = m g / cos(θ) ≈ 576 N

To find the maximum tension in the rope during the swing, we can use conservation of angular momentum.

L = I ω

I = (1/3) m [tex]L^2[/tex]

I = (1/3) x 10.0 kg x [tex](10.0 m)^2[/tex] ≈ 3333.3 kg[tex]m^2[/tex]

The angular velocity of the rope just after the student releases it is:

ω = v / L

ω = 6.2 m/s / 10.0 m ≈ 0.62 rad/s

L = I ω ≈ 2070 N m s

Thus, the angular momentum of the system just after the student releases the rope is 2070 N m s.

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why do fennec fox have big ears? explain why in big detail!

Answers

Answer:

Explanation:

The fennec may be the world's smallest fox, but it sports outlandishly large ears! In fact, relative to body size, it has the largest ears of any member of the canid family. It uses those big ears to listen for sounds of prey in the sand. The ears also help dispel body heat to keep the fox cool.

Residents of a community currently pay a fee for recreational services in their neighborhood, such as tennis courts, running trails, a pool. To assess whether there is support for raising a fee for the upcoming summer, a random sample of 50 residents is contracted and asked this question: “Would you support a $10 increase in the recreational fee to support programs for the health and well-being of the children in the community?” Of the 50 residents contacted, 42 approved of the fee increase. Which statement describes a likely source of bias present in survey results?

Answers

A likely source of bias in the survey is undercoverage bias because some parts of the community may not be represented in the survey results.

Bias present in the survey

The bias present in the survey may lead to error in the result obtained from the random sampling survey.

Source of bias in the survey

One of the likely source of bias in the survey is undercoverage.

It is not possible to ascertain the accurate opinion of the entire community from the 50 residents chosen for the survey.

Thus, a likely source of bias present in survey is undercoverage bias because some parts of the community may not be represented in the survey results.

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Answer:

B. Question wording bias may be present because the question leads those responding toward a certain response.

Explanation:

Can a machine multiply both force and speed at same time??​

Answers

Answer:

No

Explanation:

It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.

It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.

Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting to physiological changes B. the high levels of serotonin causing hormone imbalance C. increased levels of norepinephrine causing anxiety sensitivity D. stress levels, life experiences, and friends’ stresses Please select the best answer from the choices provided A B C D

Answers

Answer:

fluctuations in the levels of female reproductive hormones

Explanation:

Women are more prone to anxiety due to a variety of biological, psychological, and cultural factors. Although the exact cause is unknown, recent research suggests that fluctuations in the levels of female reproductive hormones and cycles play an important role in women's enhanced vulnerability to anxiety.

Answer: D. stress levels, life experiences, and friends’ stresses

Explanation:

Which statement is true about a wave that is created by causing vibrations in
particles of matter?
A. It can travel through empty space.
B. It is not an electromagnetic wave.
C. It does not need a medium.
D. It moves through a magnetic or electric field.

Answers

Answer:

A

Explanation:

A. it can travel through empty space

Find the magnitude of the sum of these two vectors:​

Answers

Answer:

Explanation:

You can decompose those vectors into their components in x and y direction. For the first vector:

[tex]\vec{r}_{1}=r_{1}\cos 30\hat{i}+r_{1}\sin 30\hat{j}=3.14(\frac{1}{2}\sqrt{3}\hat{i}+\frac{1}{2}\hat{j})=1.57\sqrt{3}\hat{i}+1.57\hat{j}[/tex]

For the second vector:

[tex]\vec{r}_{2}=r_{2}\cos 60\hat{i}-r_{2}\sin60 \hat{j}=1.355\hat{i}-1.355\sqrt{3}\hat{j}[/tex]

The sum of two vectors will be:

[tex]\vec{r}=\vec{r}_{1}+\vec{r}_{2}=(1.57\sqrt{3}+1.355)\hat{i}+(1.57-1.355\sqrt{3})\hat{j}\approx 4.0711\hat{i}-0.77415\hat{j}[/tex]

The magnitude of the sum of two vectors is:

[tex]r=\sqrt{(4.0711)^{2}+(-0.77415)^{2}}\approx 4.14[/tex] meter

Answer:

4.14m

Explanation:

A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?

How far does it get pushed in 10 s?

Answers

Fy=ma

Fn-mg=ma
Fn-6(10)=6a
Fn=6a+60

Fx=ma

10-Ff=ma
10-(Fn)(0.1)=6a
0.1Fn=-6a+10
Fn=-6a+10/0.1

(substitute)
-6a+10/0.1=6a+60
-6a+10=0.6a+6
-6.6a=-4
a≈0.61m/s^2

Use Kinematics to find x in 10s

x=Vt+1/2at^2
x=0+1/2(0.61)(10)^2
x≈30.3m

I hate physics :p hope this is accurate

Q19. Convert 2.05 x 10^5 seconds into years​

Answers

Explanation:

no. of seconds in a year = 60 × 60 × 24 × 365

= 31,536,000 seconds

so 2.05 × 10⁵ into years = 0.0065 years (approximately)

Which of the rays drawn above would be correct as the light goes from the air into the water?

Answers

Answer:

the answer to this question is option c

there process which eventually takes place is called refraction

Explanation:

please do consider as brainlest if useful

.. In the reaction 238 92U ---- X + 2 4 He, the particle represented by X is . answer choices . 234 90 Th. 234 92 U. 238 93 Np. 242 94Pu. ... Which conditions are required

My question
• Complete the following reaction:
238 92U = ______ + ________ + 4 2He

…Is this the same question as the answer

Answers

Answer:

234 90 +energy

Explanation:

because alpha decrease by 4 2helium

at 27 degrees C and 750 mmhg a sample of hydrogen occupies 5.0 L how much space will occupy at STP​

Answers

Answer:

Explanation:

The number of mole of the hydrogen sample at 27 C and 750 mmHg pressure is:

[tex]n=\frac{PV}{RT}=\frac{(0.9898\times 10^{5})(5\times 10^{-3})}{(8.314)(27+273)}\approx 0.0198[/tex] mol

This number of mole will be the same although we change the pressure and temperature. For STP (Temperature = 0 C = 273 K, and Pressure = 760 mmHg = 76 cmHg = 1 Bar = 1.01 x [tex]10^{5}[/tex] Pa):

[tex]P'V'=nRT' \rightarrow V'=\frac{nRT'}{P'}=\frac{0.0198(8.314)(273)}{1.01\times 10^{5}}\approx 44.49 \times 10^{-5}[/tex] in [tex]m^{3}[/tex]. But in L, we find that V' = 0.4449 L

What is the average acceleration of a me
that reaches 24 m/s in 5.5 seconds?
F 0.20 m/s2
G 2.5 m/s
H 10 m/s2
J 208 m/s

Answers

Answer:

See below

Explanation:

Assuming starting from zero velocity

vfinal = at

24   = a (5.5)

a = 4.36  m/s^2        I think part of your question is missing....what was the initial velocity?

In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it. The strings are both 50.0 cm long. The upper ball has a mass of 2.20 kg and it is initially 10.0 cm higher than the lower ball, which has a mass of 2.70 kg. Find the frequency of the motion after the collision. Find the maximum angular displacement of the motion after the collision.

Answers

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

Speed of the 2.2 kg ball when it collides with 2.7 kg ball

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

Final speed of both balls after collision

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

Maximum displacement of the balls after the collision

P.E = K.E

[tex]mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m[/tex]

Maximum angular displacement

The maximum angular displacement of the balls after the collision is calculated as follows;

[tex]cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0[/tex]

Frequency of the motion

[tex]f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz[/tex]

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Which nucleus completes the following equation?

Answers

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

you move a 25 N object 5.0 meters. how much work did you do?

Answers

Answer:

125J

Explanation:

[tex]work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules[/tex]

What does the atomic numbers equal? A number of protons in the atomic nucleus B number of protons and neutrons in the atomic nucleus C number of neutrons in the atomic nucleus​

Answers

Answer:

number of protons

explanation:

the atomic number of an atom is equal to the number of protons

An aquarium heater transfer 1200kJ of the heat to 75000g of water. What is the increase in the waters temperature?

Answers

Answer:

Energy = mcΔt

where m the mass ,  c specific heat capacity

Δt is the change in temperature

1200x10^3=75x4184xΔt

Δt=3.82°

Explanation:

1. A drag racer accelerates from rest at 18ft/sec^2. How long does it take to acquire a speed of 60mph? What is required?
2. A contestant ran a 100-m dash in 10.6sec. What was his speed a) In feet per second and b) in miles per hr?

Answers

(1) The time taken for the drag racer to accelerate is 4.89 s

(2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

(1) To calculate the time required to accelerate 18 ft/sec² from rest to a velocity of 60 mph, we use the formula below.

Formula:

t = (v-u)/a........... Equation 1

Where:

t = timev = Final velocityu = initial velocitya = acceleration.

From the question,

Given:

a = 18 ft/sec² = (18×0.3048) = 5.4864 m/s²v = 60 mph = (60×0.44704) = 26.82 m/su = 0 m/s ( from rest)

Substitute these values into equation 1

t = (26.82-0)/5.4864t = 4.89 seconds

(2) To calculate the speed of the contestant, we use the formula below

Formula:

s = d/t............ Equation 1

Where:

s = speed of the contestantd = distancet = time.

From the question,

Given:

d = 100 mt = 10.6 s

Substitute these values into equation 1

s = 100/10.6s = 9.43 m/s

(a) In feet = (9.43/0.3048) = 30.94 ft/s

(b)  in miles per hr = (9.43×2.24) = 21.12 miles per hr

Hence, (1) The time taken for the drag racer to accelerate is 4.89 s (2) The speed of the contestant (a) in feet per second is 30.89 ft/s (b) in miles per hr is 21.12 miles per hr.

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When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energy of the system after the collision? ​

Answers

nothing

Explanation:

we can say that it was certainly bad for the shopkeeper obviously and we should not be making questions about the physics behind that accident and should call the cops or 911

How long does it take a photon to escape the sun?

Answers

Answer:

About 5000 years.

Explanation:

Answer:

Explanation:

it will take more than half a million years for the photon to escape the sun. If you think it's about a centimeter, then it will take about 5,000 years for the photon to get outside the su

Two children are playing tetherball, in which a ball at the end of a cord spins around a pole. After a really good hit, the ball makes three complete revolutions in 2.0 s. What is the angular speed of the ball?

Answers

Answer:

3 pi R / s     or   9.42 R/s    or  540 degrees/sec

Explanation:

Ball covers 2 pi radians each rotation

2 pi * 3 R / 2  s =   3 pi R / s

the angular speed of the ball is 3 pi R / s     or   9.42 R/s    or  540 degrees/sec

What is angular speed ?

Angular speed can be defined as the measures of speed of how fast the central angle of a rotating body changes with respect to time

Angular speed mainly implies how quickly the rotation of an object occur means it is described as the change in the angle of the object per unit of time.

To calculate the speed of a rotational motion the angular speed value need to be known, hence  The angular speeds formula is used to calculate the distance traveled by an object in terms of rotation and revolutions per unit of time.

The unit of angular speed of an object is radian per second and Both angular speed, angular velocity are determined by using the same formula, angular velocity is  vector quantity which describes both magnitude and direction.

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Two horses pull horizontally on ropes attached to a stump. The two forces Fu and F2 that they apply to the stump are such that the net (resultant) force R has a magnitude equal to that of Fu and makes an angle of 90° with Fu. Let F1 = 1300 N and R = 1300 N also. Find the magnitude of F and its direction (relative to Fi)

Answers

For two horses pull horizontally on ropes attached to a stump, the magnitude of F and its direction is mathematically given as

F=1711 N

dF= 135 degrees

What is the magnitude of F and its direction?

Generally, the equation for the components of F1   is mathematically given as

For The x axis

1210 - F2x = 0

F2x = 1210

For the y axis

F2y = R

F2y = 1210

In conclusion

F = sqrt(2)*1210

F=1711 N

Fopt the direction of F2

dF= 90 + 45

dF= 135 degrees

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A simple circuit has a voltage of 8V and a current of 3A. Find the resistance (R) in the
circuit.

Answers

Answer:

2.67 ohm

Explanation:

V=IR

R=V/I

In which V is voltage and I is current and R is resistance

An object moving in a straight line has a velocity v in m/s that varies with time t in s according the following function. v= 8+2.5 12 to 11. The instantaneous acceleration of the object at t = 2 sis (A) 2 m/s (B) 4 m/s (0) 6 m/s2 D) 8 m/s2 (E) 10 m/s2 12. The displacement of the object between t = 0 and t = 6 s is (A) 120 m (B) 180 m (C) 228 m (D) 242 m (E) 260 m​

Answers

The instant acceleration of the object is 10 m/s² and the displacement of the object is 228 m.

Instantaneous acceleration

The instant acceleration of the object is determined by taking the derivative of the velocity as follows;

v = 8 + 2.5t²

a = dv/dt

a = 5t

a(2) = 5(2)

a(2) = 10 m/s²

Displacement of object

The displacement of the object is determined by taking the integral of velocity as follows;

v =  8 + 2.5t²

x = ∫v

x = 8t + 2.5t³/3

x(0) = 0

x(6) = 8(6) + 2.5(6)³/3

x(6) = 228 m

Thus, the displacement of the object is 228 m.

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During a phase change,the temperature remains constant although heat is still being added. what is the best explanation for what the heat energy is being used to do

Answers

During the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.

What is a phase change?

A phase change is the conversion of one state of matter to another. e.g. solid to liquid or liquid to gas.

Substances can exists in three states namely;

solidgaseousliquid

In a change of phase, heat energy is needed to break the existing bonds between the molecules of the initial state. For example, heat energy is needed to break the bonds of ice to form water.

However, during this phase change, the temperature remains constant.

Therefore, during the phase change in which heat is being added but the temperature remains constant, the heat energy is used to break the bonds in the molecules.

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What is the best definition of
work?
A. net force equals zero
B. a force exerted over a distance
a
C. pair of forces where one is of greater strength

Answers

Answer:

Work is best defined as a force exerted on a body to cause it move over a certain distance.

work=force×displacement×cosθ

Explanation:

Difine Ripple Factor
-,- ty!!​

Answers

Answer:

The answer is in the picture above.

A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to the block. The magnitude of the block's acceleration is 1.2 m/s2. If P is increased to 5.0 N, determine the magnitude of the block's

Answers

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Frictional force between the block and the horizontal surface

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

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a current of 180 mini amphere passes through a conductor for 5minute calculate the quantity of electricity transported​

Answers

Answer:

Explanation:

You can calculate the total electric charge that passes through the conductor as [tex]q=It=(180\times 10^{-3})(5\times 60)= 54 C[/tex]. It means that the number of electron that passes through the conductor is:

[tex]n=\frac{q}{e}=\frac{54}{1.6\times 10^{-19}}=33.75\times 10^{19}[/tex]

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