find the speed of light in each of the following materials. (a) cubic zirconia m/s (b) sodium chloride m/s (c) polystyrene m/s

Nuclear/Radioactive Decay:  occurs when the nucleus of an atom becomes unstable and spontaneously loses energy in the form of radiation emission.

Gamma Decay: a form of radioactive decay that a nucleus may undergo. This type of decay differs from other because no particles are ejected from the nucleus. Instead, a high energy electromagnetic radiation (gamma ray) photon is released.

The number in the box will be 225.

This example displays the form of gamma decay.

As a result, the wall is 17 m away when a bat flying through a cave makes a sound and then hears its echo 0.1 seconds later.

Distance of the wall from the bat (d) = speed of sound wave (s) x time (1)

Putting the values and we get;

Distance of the wall from the bat (d)=340 ms x 0.05 s = 17 m

Thus, the distance of the wall is 17 m when a bat flying in a cave emits a sound and receives its echo 0.1 s later.

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A constant acceleration for an object guarantees that its velocity will change continuously throughout time and not remain constant.

Similarities.Acceleration and velocity are both vector quantities, meaning they have both a magnitude and a direction.Both expressions are capable of being zero, positive, or both.

The rate at which in displacement is known as velocity.The rate at which velocity changes is called acceleration.Due to the fact that it includes both magnitude and direction, velocity is an vector quantity.As the rate at which velocity changes, acceleration is likewise a vector quantity.

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A basketball player shoots a basketball at 5.98 m/s at a 56.7° angle. If the goal is 7.24 m away, 2.205 sec time does the ball take to reach the horizontal position of the goal.

The same as for speed, "m/s" is the SI unit for velocity. While velocity is the rate at which a body's displacement changes, speed is the rate at which a body's distance travelled changes. While velocity is a vector quantity and requires both magnitude and direction to be described, speed is a directionless quantity.

As an example, consider the speed of a car driving north on a highway or the speed of a rocket after launch.

Given that,

initial speed (u) = 5.98 m/s

angle (θ) = 56.7°

distance (R) = 7.24 m

Now, considering motion along horizontally,

R = (u cosθ) × t

or, 7.24 = 5.98 (cos 56.7°) × t

or, t = 2.205 sec

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Answer:

2.21

Explanation:

Answer: 31.1 m/s²

Explanation:

avg. accel. = (Vfinal - Vinitial) / Δt

Vfinal = 14 m/s

Vinitial = 0 m/s

Δt = 0.45 s

avg. accel. = (14 m/s - 0 m/s)/0.45 s = 31.1 m/s²

Answer:

889.2 J

Explanation:

F = ma = (12 kg)(3.9 m/s²) = 46.8 N

W = Fd = (46.8 N)(19 m) = 889.2 J

Answer:1/64. im glad i could at least try to help lol im in middle school and i just ran through a bunch of articles 4 u

(a) The maximum speed of the object is 1.37 m/s.

(b) The locations of the object when its velocity is one-third of the maximum speed is 5.87 cm.

In easy words, speed is the rate at which some thing actions in a specific direction. For instance as the rate of a vehicle journeying north on a highway, or the rate a rocket travels after launching. The scalar method absolutely the cost value of the rate vector is constantly be the rate of the motion.

Velocity is a vector expression of the displacement that an item or particle undergoes with appreciate to time . The preferred unit of speed value (additionally called speed ) is the meter according to second (m/s). Alternatively, the centimeter according to second (cm/s) may be used to specific speed value.

Maximum speed for the object:

[tex]w=\sqrt{ \frac{k}{m}\\\\\\w=\sqrt{ \frac{77.5}{0.215}\\\\\\\\\\\\\w=\sqrt{ 360.46}\\\\\\\\w=18.98[/tex]

Maximum velocity = ωr

v=  18.98*0.0725

v= 1.37.

Maximum velocity = ωr = 1.37.

The speed of the object at a distance x from its mean position is given as:

[tex]v=w\sqrt{a^2- x^{2} } } \\so,\\ v=x\\x=\sqrt[]{8(*7.25} \\x= 5.87[/tex]

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Because whilst depth of incident mild will increase, it approach that wide variety of photons will increase in incident mild.

If wide variety of incident photons will increase, then wide variety of emitted picture graph electrons additionally will increase, therefore the picture graph electric powered contemporary will increase.

The photoelectric impact. In the photoelectric impact, mild waves (pink wavy lines) hitting a steel floor motive electrons to be ejected from the steel.

Current in picture graph electric powered impact is immediately proportional to the depth of the incident mild. paintings function, preventing potential, most kinetic electricity are unbiased of depth of incident mild, they rely upon the frequency, wavelength of the incident mild and cloth of the steel.

Using L for luminosity, the depth of mild system becomes I=LA I = L A . Because mild waves unfold in all directions, to correctly calculate mild depth, the denominator withinside the system have to be the floor vicinity of a sphere. In fact, maximum electromagnetic calculations are achieved over a sphere.

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The magnitude of the magnetic field at the center of the loop is 3.31 x 10⁻⁶ T.

The magnetic field is the region of space around which the influence an magnetic force is felt.

Mathematically, the formula for magnetic field at the center of a loop is given as;

B = μ₀I / 2r

where;

The magnitude of the magnetic field at the center of the loop is calculated as;

B = ( 4π x 10⁻⁷ x 0.58 ) / ( 2 x 0.11 )

B = 3.31 x 10⁻⁶ T

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The shear force V and bending moment M is 0.15 kN and 0.15 kNm respectively.

What is shear force?

A force acting in a direction parallel to (over the top of) a surface or cross section of a body is known as a shear force. It is determined as the algebraic total of all transverse forces operating on either side of a beam or frame section.

What is bending moment?

A bending moment is the reaction in a structural element caused by an external force or moment that causes the element to bend.

In this question,

Moment about A,

[tex]B_y[/tex] * 0.6 = (6 kN/m * 0.3m) * (0.15m)

[tex]B_y[/tex] = 0.45 kN

Force balance along Y direction,

[tex]A_y[/tex] + [tex]B_y[/tex]  = 6 kN/m * 0.3 m = 1.8 kN

[tex]A_y[/tex]  + 0.45 = 1.8

[tex]A_y[/tex]  = 1.35 kN

At a section 200mm (or 0.2m right of A)

V = [tex]A_y[/tex]  - (6*0.2) = 1.35 - 1.2 = 0.15 kN

M = -[[tex]A_y[/tex]  * 0.2] + [6*0.2*(0.2/2)] = 0.27-0.12 = 0.15 kNm

The shear force V and bending moment M is 0.15 kN and 0.15 kNm respectively.

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The binding stress of the spear gear in the table is 502.22 Pa.

The diameter of the pinion is equal to:

d(p) = Nm(p)

Where

m = module = 5

Np = number of teeth of pinion = 26

d(p) = 5* 26 = 130 = 0.13 m

The pitch line velocity is equal to:

v(t) = d(p)*2pi*w(p)/120

Where

wp = speed of the pinion = 1800 rpm

v(t) = 12.25 /s

The factor B is equal to: 0.396

The factor A is equal to:

A = 50 + 56*(1 - B) = 50 + 56*(1-0.396) = 83.82

The dynamic factor is:

K(v) = A/A+√200v(t) B

K(v)= 0.832

The geometry bending factor at 20°, the application factor Ka, load distribution factor Km, the size factor Ks, the rim thickness factor Kb and Ki the idler factor can be obtained from tables

JR = 0.41

Ka = 1

Kb = 1

Ks = 1

Ki = 1.42

Km = 1.7

The diametrical pitch is equal to:

p(d) = 1/m = 1/5 = 0.2

The bending stress is equal to:

σ = w(t)p(d)k(a)k(m)k(g)k(b)k(i)/FJ(g)K(v)

σ = 502.22 Pa

Therefore, the binding stress of the spear gear in the table is 502.22 Pa.

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The time taken by the drum to come to rest is 2.55 seconds and the angle that it makes is 14π.

The drum rotates around the central axis with angular velocity of 11 rad/s. After that it slow down with constant rate of 4.3 rad/s².

(a) The time taken by the drum to come at rest will he given by,

W' = W + at

W is initial angular velocity,

W' is final angular velocity,

a is the rate of slowing down,

t is the time taken.

Putting values,

11 = 4.3t

t = 11/4.3

t = 2.55 seconds.

(b) The angular displacement will be given by,

2aS = W'² - W²

S is the angles made while slowing down,

Putting values,

2(4.3)S = (11)²

S = 14 rad.

So, the angle made is 14π.

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The probability of getting a prime number ( 2, 3, 5, 7) between 1 to 8 is 1/2. The total outcomes possible for spinning the spinner and tossing the coin is 16.

Branch of mathematics concerning numerical descriptions of how likely an event is to occur is called probability.

Total number of outcomes = 8.

Let, the probability of getting a prime number ( 2, 3, 5, 7) between 1 to 8

P(E) = (no. of outcomes) /( total no. of outcomes)

=4/8

=1/2

When a coin is tossed,  there are two possible outcomes that are H(head), and T(tail).

If you spin the spinner , there are 8 possibilities.

Total outcomes = 8 * 2

=16

There are 16 outcomes, when spinning a spinner numbered from 1 to 8 and tossing a coin.

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If you hear an echo 0.15 seconds after banging, the barn is 25.725 m long.

An echo is a sound that results from the return of sound waves to the listener from a surface. It is the reflection of sound, which reaches the listener after the direct sound has passed.

Given data:

you hear an echo 0.15 seconds after banging.

we know that speed of sound in air is 343 m/s.

As in this time sound waves goes to the barn and returns back.

Hence, the barn is = 343×0.15/2 m long = 25.725 meter long.

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The best statement is option A.There is more cold, dense gas in the disk than in the bulge.

Star-forming regions are concentrated in galaxies with high concentrations of the material that stars are made of: gas and dust. These concentrations of gas and dust can be "pushed" to the point where they collapse to form stars, depending on the type of galaxy and the types of gravitational interactions it may encounter. Gravity pushes gas and dust to form stars more efficiently in spiral arms than in other parts of the spiral galaxy. This is why spiral arms have more star-forming regions and collections of young stars (open clusters) than other parts of a spiral galaxy.

Thus, due to heavy gravity, gas are more cold and dense in the disk.

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A monochromatic light source with a power output of 59.0W radiates light of wavelength 600nm uniformly in all directions.

A. B(max) = 3.89 × 10⁻⁸ T

B. E(max) = 11.67 N/C

Single-wavelength light sources are known as monochromatic lights, where mono stands for only one and chroma for color. Monochromatic lights are defined as visible light that falls within a certain range of wavelengths. It has a wavelength that falls within a constrained wavelength range.

The whole spectrum is theoretically included in each higher-order maximum, but because of potential partial overlap with the next-order maximum, it can be challenging to identify the pattern for a given color. Monochromatic lighting solves this issue.

The intensity of the wave is calculated as:

I = P/A

or, I = P/4πR²

or, I = 59.0 W/ 4π(5.10m)²

or, I = 0.1805 W/m²

A. Emax for the light at a distance of 5.10m from the source.

E(max) = [tex]\sqrt{2u_0cI}[/tex]

or, E(max) = 11.67 N/C

Where, [tex]u_0[/tex] = 4π × 10⁻⁷ T.m/A

c = 3 × 10⁸ m/sec

I = 0.1805 W/m²

B. The amplitude of the magnetic field is calculated as follows:

B(max) = E(max)/c

or, B(max) =  (11.67 N/C) / (3 × 10⁸ m/sec)

or, B(max) = 3.89 × 10⁻⁸ T

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1. Sound waves interact with other objects by transmitting energy and causing vibrations. Examples include sound waves reflecting off of walls and objects, sound waves interfering with one another, and sound waves bouncing off of surfaces and producing echoes.

2. Sound waves are waves of pressure that travel through a medium, such as air or water, and can be heard when they reach a person's ear.

3. Three interactions of sound waves include reflection, interference, and reverberation.

4. Wave interaction is the process in which two or more waves interact with each other to produce an effect. This effect can be a change in amplitude, frequency, or direction.

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At the dew point, air can no longer absorb water vapor. When air cools above its dew point, water vapor becomes a liquid. This is a physical process known as condensation.

While you breathe out (exhale), your lungs put carbon dioxide again into the air. but, the breath you exhale doesn't only contain carbon dioxide. It additionally includes moisture from your mouth and lungs. This moisture is inside the form of water vapor, the gasoline shape of water.

While you exhale on a chilly day, the air that goes out is saturated and the temperature of the air you exhale is warmer than the encompassing air.

The water vapor to your breath condenses into many tiny droplets of liquid water and ice that you could see within the air as a cloud. It seems pretty similar to fog.

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An object is thrown vertically up in the air. Its initial velocity is 6 m/s. The object's maximum height is 1.83673 m.

Projectile motion can be regarded as a form of motion that can be  experienced by an object when its been projected near the Earth's surface and follows curved path under the action of gravity only.

Given, the velocity of ball, u= 6 m/s

Here, v be the final velocity, u be the initial velocity and H be the height.

Velocity of the ball at maximum height is zero, v=0

v² - u² =2aH                          

0−(6)²=2×(−9.8)×H        

⟹H= 1.83673 m              

Thus, the object's maximum height is 1.83673 m.

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The correct statement about the given two object when placed in a container is b)Object B has a greater density than object T. So, correct option is b.

At the point when an item stay balance while lowered, its gravity should be equivalent to the lightness force, which is equivalent to the fluid weight dislodged by the lowered volume:

[tex]V_s[/tex]ρ[tex]_l[/tex]g=mg=Vρ₀g

=>[tex]V_s[/tex]ρ[tex]_l[/tex]=Vρ₀

=>ρ₀=([tex]V_s[/tex]ρ[tex]_l[/tex])/V

where ρ₀,ρ[tex]_l[/tex]  are densities of the object and liquid, separately. are the volume lowered and the item volume, separately.

In the event that object B is completely lowered, the thickness of article B is equivalent to the fluid thickness (on the grounds that ).

With respect to protest T as it's just to some extent lowered, the mass of the fluid dislodged is same as mass of article. And keeping in mind that the volume uprooted is just a piece of the entire item volume (), this implies that the fluid thickness is more noteworthy than object T's thickness.

Hence, correct option is b.

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(Complete question) is:

Two objects, T and B, have identical size and shape and have uniform density. They are carefully placed in a container filled with a liquid. Both objects float in equilibrium. Less of object T is submerged than of object B, which floats, fully submerged, closer to the bottom of the container. Which of the following statements is true?

a. Object T has a greater density than object B.

b. Object B has a greater density than object T.

c. Both objects have the same density

Time period of the pendulum, T = 19.7 s

The time period of the pendulum is given by :

T = [tex]2\pi \sqrt{\frac{l}{g} }[/tex], l is the length of the pendulum

substituting,

l = 174.32 meters

What is the time period?

Time period (plural time periods) is the amount of time that a behavior lasts or a condition persists. Depending on the type of activity or situation under consideration, it may be measured in seconds or in millions of years.

Hence, the answer is 174.32 m

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Answer:

d) temperature

Explanation:

Answer:

D) temperature

Explanation:

Temperature is a measure, an actual measurable number of the average kinetic energy of the particles of one substance.

The resistance of the circuit is  0.51ohm if the current in a RL circuit drops from 1.5A to 1.3 A in first second.

We know very well that in an RL circuit if a current is changing from one state to another state is given by the below formula

I[tex]_t[/tex] = I₀×[tex]e\frac{-t}{RL}[/tex]

where  I[tex]_t[/tex] is current flowing in RL circuit at any time,

I₀ is the maximum current flows in R-L circuit.

R is defined as resistance of circuit

and L is  inductance of circuit.

RL circuit works differently if battery is connected and it works differently if battery is disconnected. It works by charging the inductor when battery is applied.

We have  I[tex]_t[/tex]=1.3A,I₀=1.5A,R=?,L=14H

=>1.3=1.5×[tex]e\frac{-1}{R.14}[/tex]

=>    [tex]e\frac{-1}{R.14}[/tex]=1.3/1.5

=>1.5/1.3=[tex]e\frac{1}{R.14}[/tex]

Taking ln on both sides of equation.

ln(1.5/1.3)=ln([tex]e\frac{1}{R.14}[/tex])

=>ln(1.5)-ln(1.3)= 1 / (R×14)

=>0.405-0.262=1/(R×14)

=>R×14= 1 /0.14

=>R=1/(0.14×14)

=>R=1/1.96

=>R=0.51ohm

Hence, resistance value is 0.51 ohm

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Refraction is the bending of light (it also happens with sound, water and other waves) as it passes from one transparent substance into another.

A potential problem is that you are willing to accept a 5% chance of being wrong if you reject the null hypothesis.

The significance level is the probability of rejecting the null hypothesis if it is true. For example, a significance level of 0.05 indicates a 5% risk of concluding that there is a difference when there is actually no difference. Rejecting the true null hypothesis results in a Type I error.

The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

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At the instant it is thrown, the ball is known to be moving perpendicular to the b-field and is moving at velocity v and time taken is 1.259*10^-3 sec

F=Q(V*B)

V=velocity vector

B=magnetic field vector

q=charge

F=q(Vi*b-k)

=q|v||b|j

|Fb|=q|V|B|

t=D/v

t=2518/20000sec=1.259*10^-3sec

During the time t, the deflection of charge is negtive y direction

y=Vt+1/2at²

y=1/2ayt²

a=acceleration is -ve y direction

=Fb/m

m=mass of charge

Fb=magnetic force

ay=q|V||B|/m

q=-158.85 mc

ay=1.24*10⁵m/s

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The new pressure of the system when we move the piston to the 1.20 L mark is obtained as  0.833 atm.

We know that if we want to obtain any of the parameters that has to do with a gas we have to apply any of the gas  laws that pattern to the ideal gas and in this case we are looking at an ideal gas.

We are told that;

Initial pressure     [tex]P_{1}[/tex]= 1 atm,     Initial volume   [tex]V_{1}[/tex]= 1 L

 Final pressure      [tex]P_{2}[/tex] = ? ,          Final volume [tex]V_{2}[/tex]= 1.20 L

By the use of the formula;

 [tex]P_{1}[/tex] [tex]V_{1}[/tex] =  [tex]P_{2}[/tex]  [tex]V_{2}[/tex]

[tex]P_{2}[/tex] = 1 atm * 1L/1.20 L

= 0.833 atm

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Missing parts;

Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.

A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?

At the end of 20 ns, the electron's velocity will be approximately 5.2 × 10⁶ m/s.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field. The attraction forces that keep together atomic nuclei and electrons at the atomic scale are brought on by the electric field.

Given that:

the electric field is 1.25 kN/C

So, acceleration of the electron: a = eE/m

= (1.6 × 10⁻¹⁹×1.25×10³)/(9.1×10⁻³¹) m/s²

= 2.6 × 10¹⁴  m/s².

Hence, after  the end of 20 ns the electron's velocity will be = at

= 2.6 × 10¹⁴ × 20 × 10⁻⁹ second

= 5.2 × 10⁶ m/s.

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Energy is transferred by a sound wave between particles, when sound waves get closer then frequency of wave is high.

Pulses caused by brief disturbances of the medium Wavepackets: like harmonic waves, but with finite extent. We usually focus on harmonic waves that extend forever. They are useful because they have simple math, and accurately describe a lot of wave behavior.

A harmonic wave moving in the positive x direction can be described by the equation y(x,t) = A cos(kx - wt).

Sound waves or electromagnetic waves that are created from a point source are spherical waves, i.e., they move radially from the source in all directions. These waves can be represented by circular arcs. These arcs are surfaces of constant phase (e.g., crests)

In general for spherical waves the intensity will fall off as 1/r2 i.e., the amplitude falls off as 1/r. We have all sorts of waveforms, but thanks to superposition, if we find a nice simple set of solutions, easy to analyze, we can write the more complicated solutions as superpositions of the simple ones.

It is a mathematical fact that any reasonable waveform can be represented as a superposition of harmonic waves. This is Fourier analysis, which many of you will learn for other applications.

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