It looks like the system is supposed to be
[tex]\mathbf x'=\begin{bmatrix}0&-1\\2&3\end{bmatrix}\mathbf x+\begin{bmatrix}e^t\\e^{-t}\end{bmatrix}[/tex]
with the initial condition, [tex]\mathbf x(0)=\begin{bmatrix}5&4\end{bmatrix}^\top[/tex].
Compute the eigensystem for the coefficient matrix:
[tex]\begin{vmatrix}-\lambda&-1\\2&3-\lambda\end{vmatrix}=\lambda^2-3\lambda+2=(\lambda-1)(\lambda-2)=0[/tex]
[tex]\lambda_1=1\implies\begin{bmatrix}-1&-1\\2&2\end{vmatrix}\mathbf v_1=\mathbf 0\implies\mathbf v_1=\begin{bmatrix}1\\-1\end{bmatrix}[/tex]
[tex]\lambda=2\implies\begin{bmatrix}-2&-2\\2&1\end{bmatrix}\mathbf v_2=\mathbf 0\implies\mathbf v_2=\begin{bmatrix}1\\-2\end{bmatrix}[/tex]
So we have the characteristic solution,
[tex]\mathbf x_c=C_1e^{\lambda_1t}\mathbf v_1+C_2e^{\lambda_2t}\mathbf v_2[/tex]
[tex]\mathbf x_c=C_1e^t\begin{bmatrix}1\\-1\end{bmatrix}+C_2e^{2t}\begin{bmatrix}1\\-2\end{bmatrix}[/tex]
For the non-homogeneous part, we can guess a particular solution of the form
[tex]\mathbf x_p=te^t\begin{bmatrix}a\\b\end{bmatrix}[/tex]
(We might have started with [tex]e^t[/tex] instead, but that is already accounted for in the first characteristic solution.)
Its derivative is
[tex]{\mathbf x_p}'=e^t\begin{bmatrix}a\\b\end{bmatrix}+te^t\begin{bmatrix}a\\b\end{bmatrix}=e^t\begin{bmatrix}at+a\\bt+b\end{bmatrix}[/tex]
Substitute [tex]\mathbf x_p[/tex] into the system and solve for [tex]a,b[/tex]:
[tex]e^t\begin{bmatrix}at+a\\bt+b\end{bmatrix}=te^t\begin{bmatrix}0&-1\\2&3\end{bmatrix}\begin{bmatrix}a\\b\end{bmatrix}+e^t\begin{bmatrix}1\\-1\end{bmatrix}[/tex]
[tex]\begin{bmatrix}at+a\\bt+b\end{bmatrix}=\begin{bmatrix}-bt+1\\(2a+3b)t-1\end{bmatrix}[/tex]
[tex]\implies a=1,b=-1[/tex]
and so the particular solution is
[tex]\mathbf x_p=te^t\begin{bmatrix}1\\-1\end{bmatrix}[/tex]
The general solution to the system is then
[tex]\mathbf x=\mathbf x_c+\mathbf x_p[/tex]
[tex]\mathbf x=C_1e^t\begin{bmatrix}1\\-1\end{bmatrix}+C_2e^{2t}\begin{bmatrix}1\\-2\end{bmatrix}+te^t\begin{bmatrix}1\\-1\end{bmatrix}[/tex]
Use the given initial conditions to solve for the remaining coefficients.
[tex]\mathbf x(0)=\begin{bmatrix}5\\4\end{bmatrix}[/tex]
[tex]\implies\begin{bmatrix}5\\4\end{bmatrix}=C_1\begin{bmatrix}1\\-1\end{bmatrix}+C_2\begin{bmatrix}1\\-2\end{bmatrix}[/tex]
[tex]\implies C_1=14,C_2=-9[/tex]
Then the solution to the initial value problem is
[tex]\mathbf x=14e^t\begin{bmatrix}1\\-1\end{bmatrix}-9e^{2t}\begin{bmatrix}1\\-2\end{bmatrix}+te^t\begin{bmatrix}1\\-1\end{bmatrix}[/tex]
[tex]\mathbf x=\begin{bmatrix}14e^t-9e^{2t}+te^t\\-14e^t-18e^{2t}-te^t\end{bmatrix}[/tex]
100%
BE
A leaf fell into a river and traveled 140 meters in 4 minutes.
How many meters did the leaf travel per minute?
Answer:
35 meters / minute.
Step-by-step explanation:
Speed of the leaf = 140 / 4 = 35 meters / minute.
3g-9+11g-21 simplyfy
Answer:
g = 15/7
Step-by-step explanation:
3g - 9 + 11g - 21
group like terms
3g + 11g = 21 + 9
14g = 30
g = 30/14
g = 15/7
It is known that 4 PLEASE HELP
Answer:
4 < 2a -4 < 10
Step-by-step explanation:
You have an expression for 'a'. To get an expression for 2a-4, multiply it by 2 and subtract 4.
4 < a < 7
8 < 2a < 14 . . . . . . multiply by 2
4 < 2a -4 < 10 . . . subtract 4
Kyanna has 4 pears, 6 apples, and 3 oranges. Write a ratio to show oranges to pears.
Answer:
3:4
Step-by-step explanation:
HELP!!!
on thursday, mabel handled 90 transactions. anthony handled 10% more transactions than mabel. cal handled 2/3 of the transactions that anthony handled, and Jade handled 16 more transactions than cal. how many transactions did jade handle?
Answer:
82
Step-by-step explanation:
Mabel = 90Anthony = 90 + 10% = 90 +90*0.1 = 99Cal = 2/3*99 = 2*33 = 66Jade = 16 + 66 = 82A college library has five copies of a certain text on reserve. Three copies (1, 2, and 3) are first printings, and the remaining two (4, and 5) are second printings. A student examines these books in random order, stopping only when a second printing has been selected. One possible outcome is 4, and another is 214. (a) List the outcomes in S. (b) Let A denote the event that exactly one book must be examined. What outcomes are in A
Answer:
S = { (4), (5), (1,4), (1,5), (2,4), (2,5), (3,4), (3,5), (1,2,3,4), (1,2,3,5), (2,1,3,4) (2,1,3,5), (3,1,2,4), (3,1,2,5) }
A ={(4), (5)}
Step-by-step explanation:
Given that:
Among the three copies, (1,2,3) are the first printings, and (4,5) are the second printings.
A student who examines these books in random order stops when a second printing has been selected.
Thus, we can compute the sample space associated with these experiments as:
S = { (4), (5), (1,4), (1,5), (2,4), (2,5), (3,4), (3,5), (1,2,3,4), (1,2,3,5), (2,1,3,4) (2,1,3,5), (3,1,2,4), (3,1,2,5) }
Suppose A represents the event that we must examine exactly one book.
Then the outcomes of A are:
A ={(4), (5)}
can someone please help me with this?!
Answer:
26) Let the first number be x.
Sum of three consecutive even numbers:
[tex]x+(x+2)+(x+4)=-84[/tex]
[tex]x+x+2+x+4=-84\\[/tex]
[tex]3x+6=-84[/tex]
Subtract 6 from both sides:
[tex]3x+6-6=-84-6[/tex]
[tex]3x=-90[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3}=\frac{-90}{3}[/tex]
[tex]x=-30[/tex]
To find the other two numbers, add 2 and 4 respectively:
[tex](-30+2=-28)(-30+4=-26)[/tex]
27) Let the first number be x.
Sum of three consecutive odd integers:
[tex]x+(x+2)+(x+4)=141[/tex]
[tex]3x+6=141[/tex]
Subtract 6 from both sides:
[tex]3x+6-6=141-6\\3x=135[/tex]
Divide both sides by 3:
[tex]\frac{3x}{3}=\frac{135}{3}\\x=45[/tex]
To find the other two numbers, add 2 and 4 respectively:
[tex](45+2=47)(45+4=49)[/tex]
28) Let the first number be x.
Sum of four consecutive integers:
[tex]x+(x+1)+(x+2)+(x+3)=54[/tex]
[tex]4x+6=54[/tex]
Subtract 6 from both sides:
[tex]4x+6-6=54-6\\4x=48[/tex]
Divide both sides by 4:
[tex]\frac{4x}{4}=\frac{48}{4}\\x=12[/tex]
To find the other three numbers, add 1, 2 and 3 respectively:
[tex](12+1=13)(12+2=14)(12+3=15)[/tex]
29) Let the first number be x.
Sum of four consecutive integers:
[tex]x+(x+1)+(x+2)+(x+3)=-142[/tex]
[tex]4x+6=-142\\[/tex]
Subtract 6 from both sides:
[tex]4x+6-6=-142-6[/tex]
[tex]4x=-148[/tex]
Divide both sides by 4:
[tex]\frac{4x}{4}=\frac{-148}{4}\\x=-37[/tex]
To find the other three numbers, add 1, 2 and 3 respectively:
[tex](-37+1=-36)(-37+2=-35)(-37+3=-34)[/tex]
27. Reason Adam invests $8,000 in an account that
earns 1.25% interest, compounded quarterly
for 20 years. On the same date, Jacinta invests
$8,000 in an account that earns continuous
compounded interest at a rate of 1.25% for
20 years. Who do you predict will have more
money in their account after 20 years? Explain
your reasoning.
Answer:
Jacinta will have more money
Step-by-step explanation:
For the same amount of investment and interest rate, compound interest is greater with greater number of compounds.Continuous compound is closer to daily compound which makes more compounds and returns than quarterly compound.The interest amount is provided below for quarterly and daily compound:
2,268.202,307.89Jacinta will have more money
Change 66 inches to feet
Answer:
5.5
Step-by-step explanation:
divide the length value by 12
Answer:
5.5 ft
Step-by-step explanation:
30cm=1ft
12inch= 1ft
66/12 = 5.5ft
Simplify the given expression below: (−3 + 2i) ⋅ (2 + i) A. −8 + i B. −6 + 3i C. −3 + 4i D. −1 + 2i
Answer:
-8 + i
Step-by-step explanation:
(-3 + 2i) * (2 + i)
= -6 + -3i + 4i + 2i^2
= -6 + i - 2
= -8 + i
How many proportional relationships are shown in the coordinate plane below?
Choose 1 answer:
(Choice A)
0
(Choice B)
1
(Choice C)
2
(Choice D)
3
Answer:
D. 3
Step-by-step explanation:
We can see from the graph that there are 3 lines. All 3 lines look linear, and if a line is linear, x and y are proportional. Therefore, if all 3 lines are linear, then we have 3 proportional relationships.
prove cos x / 1+sinx = tan ( π\4 - x/2)
Answer:
[tex]\displaystyle \frac{\cos x}{1 + \sin x} = \tan\left(\frac{\pi}{4} - \frac{x}{2}\right)[/tex].
Overview of the steps:
Apply the double-angle identity of sines and cosines to the left-hand side of the equation.Apply the Pythagorean identity to the left-hand side of the equation.Apply the angle sum and difference identity of sines and cosine to the right-hand side of the equation.Step-by-step explanation:
Double-angle identity of sines and cosines:
[tex]\cos (2\,\alpha) = \cos^2\alpha - \sin^2\alpha = (\cos\alpha + \sin\alpha)\, (\cos\alpha - \sin\alpha)[/tex].[tex]\sin(2\,\alpha) = 2\, \sin\alpha\, \cos\alpha[/tex].Pythagorean identity for the sine and cosine of the same angle:
[tex]1 = \cos^2\alpha + \sin^2\alpha[/tex].
Angle sum and difference identity of sines and cosines:
[tex]\sin(\alpha - \beta) = \sin\alpha\, \cos\beta - \cos\alpha \, \sin\beta[/tex].
[tex]\cos(\alpha - \beta) = \cos\alpha\, \cos\beta + \sin\alpha \, \sin\beta[/tex].
Consider [tex]x[/tex] as the sum of two angles of size [tex](x/2)[/tex]. Start by applying the double-angle identity to the left-hand side.
[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\end{aligned}[/tex].
Apply the Pythagorean identity to rewrite the "1" in the denominator as [tex]\left(\cos^2(x / 2) + \sin^2(x / 2)\right)[/tex].
[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{\sin^2(x/2) + 2\,\sin(x/2)\, \cos(x/2) + \cos^2 (x/2)}\end{aligned}[/tex].
Note that the denominator is now a perfect square. On the other hand, the numerator is in the form [tex](x^2 - y^2)[/tex], which is equal to [tex](x + y)\, (x - y)[/tex]. Rewrite and simplify this expression:
[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{\sin^2(x/2) + 2\,\sin(x/2)\, \cos(x/2) + \cos^2 (x/2)} \\[1em] &= \frac{(\cos(x/2) + \sin(x/2))\, (\cos(x/2) - \sin(x/2))}{\left(\sin(x/2) + \cos(x/2)\right)^2} \\ &= \frac{\cos(x/2) - \sin(x/2)}{\sin(x/2) + \cos(x/2)}\end{aligned}[/tex].
The tangent of an angle is equal to the ratio between its sine and its cosine. Apply the angle sum and difference identity of sine and cosine to the right-hand side.
Note, that the sine and cosine of [tex](\pi/4)[/tex] are both equal to [tex]\left(\sqrt{2}/2\right)[/tex].
[tex]\begin{aligned}\text{R.H.S.} &= \tan\left(\frac{\pi}{4} - \frac{x}{2}\right) \\ &= \frac{\sin((\pi/4) - (x/2))}{\cos((\pi/4) - (x/2))}\\ &= \frac{\left(\sqrt{2}/2\right)\, \cos(x/2) - \left(\sqrt{2}/2\right)\, \sin(x/2)}{\left(\sqrt{2}/2\right)\, \cos(x/2) + \left(\sqrt{2}/2\right)\, \sin(x/2)} \\ &= \frac{\cos(x/2) - \sin(x/2)}{\cos(x/2) + \sin(x/2)}\end{aligned}[/tex].
Therefore:
[tex]\displaystyle \text{L.H.S.} = \frac{\cos(x/2) - \sin(x/2)}{\sin(x/2) + \cos(x/2)} =\text{R.H.S.}[/tex].
[tex]\displaystyle \frac{\cos x}{1 + \sin x} = \tan\left(\frac{\pi}{4} - \frac{x}{2}\right)[/tex].
Find the measure of angle A.
2x +13 5x
Write the number 0.00044 in scientific notation.
explain the rules for multiplicación and division to convert units. How do you know when to multiply and when to divide to convert units of measurement
Answer:
What do u mean? For example, meters (works with other units of measurement) its based on an Acronym. King Henry Died By Drinking Chocolate Milk. The first letters stand for: Kilo, Hecto, Deca, Base (your unit of measurement), Deci, Centi, Mili
Step-by-step explanation:
helpp me please !!!!
Step-by-step explanation:
55. 162 +54=216
216-75=141
balance $141
Solve for f: −5f=20
30 POINTS TO SOMEONE WHO HELPS
Answer:
[tex]\huge\boxed{\sf f = -4}[/tex]
Step-by-step explanation:
[tex]\sf -5f = 20\\\\Dividing\ both\ sides\ by\ -5\\\\\frac{-5f}{-5} = \frac{20}{-5} \\\\f = -4[/tex]
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AnonymousHelper1807
Calculate the distance between (6 − 5i) and ( 1 + 3i).
A: /113
B: /29
C: /53
D: /89
Answer: D
Step-by-step explanation:
i just had this question on a quiz and it said the correct answer was /89
Expand and simplify
(2x2 + 3)(4x + 5) - 8x(x - 2)
If simplifying the following problem, what
would be the correct first and third
steps?
8 - 4 [5(2-2)] + 3
Answer: First step would be doing the () first. The third step would be 4 times 0. I think so, forgive me if I’m wrong.
Step-by-step explanation:
Rewrite the given inequality as two linear inequalities. ∣8x+9∣<4
Answer:
[tex]8x+9<4[/tex] and [tex]8x+9>-4[/tex].
Step-by-step explanation:
The given inequality is
[tex]|8x+9|<4[/tex]
We need to rewrite the given inequality as two linear inequalities.
We know that |8x+9|>0 but (8x+9) can be positive or negative.
For [tex]|8x+9|<4[/tex], the value of (8x+9) must be lies between -4 and 4.
i.e., [tex]-4<8x+9<4[/tex]
If 8x+9 positive, then
[tex]8x+9<4[/tex] ...(1)
If 8x+9 negative, then
[tex]8x+9>-4[/tex] ...(2)
Therefore, the two inequalities are [tex]8x+9<4[/tex] and [tex]8x+9>-4[/tex].
what is the answer please help 3[(8-4)^5 ÷ 8 please please help me!
Solution:
3[(8 - 4)^5] ÷ 8
3[4^5] ÷ 8
3[1024] ÷ 8
3072 ÷ 8
384
Best of Luck!
Answer:
384
Step-by-step explanation:
[tex]3[(8-4)^5][/tex]÷[tex]8[/tex]
Using the rules of PEMDAS I know that I have to do the math inside of the parenthesis first.
8 - 4 = 4
Our new equation is
[tex]3[(4)^5][/tex]÷[tex]8[/tex]
Next we have to solve for the exponent.
[tex]4^5[/tex] = [tex]4*4*4*4*4[/tex] = 1,204
Our new equation looks like:
[tex]3[1024][/tex]÷[tex]8[/tex]
Now we will multiply, because we follow the rules of operation.
[tex]3 *1024= 3072[/tex]
Finally we will divide 3,072 by 8.
[tex]3072/8= 384[/tex]
Our final answer is:
384
2,802,136 expanded complete the expanded form
Answer:
200000+800000+0+2000+100+30+6
Step-by-step explanation:
2,000,000
800,000
0
2,000
100
30
+ 6
_________
Eight avocados cost $4.
How much do 16 avocados cost?
How much do 20 avocados cost?
How much do 9 avocados cost?
16 avocados costs = $8, 20 avocados costs = $10 and 9 avocados costs = $4.5
What is the Cost?The amount of money that a company spends on the creation or production of goods or services.
Given that, Eight avocados cost $4.
Therefore, each of them costs = 4/8 = 1/2
So, 16 avocados = 16*1/2 =$8
20 avocados = 20*1/2 =$10
9 avocados = 9*1/2 =$4.5
Hence, 16 avocados costs = $8, 20 avocados costs = $10 and 9 avocados costs = $4.5
For more references on Cost, click;
https://brainly.com/question/15135554
#SPJ2
For g(x)=x^2-2, determine g(x+2)
Answer:g(x)=-4^2+4x-5
Step-by-step explanation:
The formula for calculating the density of an object is D=-, where m is mass and v is volume.
m
Rewrite the formula in terms of m. Then rewrite the formula in terms of v.
Answer:
M= D x V, V= M x D
Step-by-step explanation:
You just do the opposite of division since the original is:
Density= Mass/ Volume
The perimeter of a rectangular window is 43 feet. The width of the window is 5 ft more than the length. Find the width of the window
Answer:
13.25 ft
Step-by-step explanation:
Let w represent the width of the window. Then w-5 represents the length, and the perimeter is ...
P = 2(L+W)
43 = 2((w-5) +w) = 4w -10
53/4 = w = 13.25 . . . feet
The width of the window is 13.25 ft.
One cattle farmer plans to grow his cattle population 2% each year, modeled by the function f(t) = 100(1.02)t. Another farmer intends to add 20 cattle per year, modeled by the function g(t) = 100 + 20t. For this application, the domain is restricted to t ≥ 0. If the farmers become partners, which function represents the total cattle they will have after t years? h(t) = 200(21.02)t h(t) = 200(20.4)t h(t) = 100(1.02)t + 20t + 10 h(t) = 2,000t(1.02)t + 100
Answer:
h(t) = 100(1.02)t + 20t + 10
Step-by-step explanation:
I got it right on the test : )
Answer:
h (t) = 100(1.02)t + 20t + 100
Step-by-step explanation: edge 2021
took the unit test got it right.
The graph of f(x) = 0.5x is replaced by the graph of g(x) = 0.5x + k. If g(x) is obtained by shifting f(x) up by 5 units, then what is the value of k?
Answer:
k = 5
Step-by-step explanation:
The value of k is added to each y-coordinate, so represents the amount of up-shift. If the shift up is 5 units, then k=5.
Answer:
k = 5
Step-by-step explanation:
I got it right on the quiz
Write the word form of the following decimals. 432.98
Answer: Four hundred and thirty two point nine - eight.
Step-by-step explanation:
Hey there! I'm happy to help!
With the numbers before the decimal, you just say it normally. After the decimal, you just name the digits.
So, you would call this number four hundred thirty-two point nine eight.
Have a wonderful day! :D
