find the value of the trigonometric ratio​

The volume of air inside the cube is 1887.4 cubic inches. Then the correct option is C.

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A ball inside of a cube has a volume of 113 cubic inches. If each side of the cube measures 12.6 inches.

Then the volume of air inside the cube will be given as the difference between the volume of the cube and the sphere.

Air volume = Volume of the cube - Volume of the sphere

Air volume = 12.6³ - 113

Air volume = 2000.376 - 113

Air volume = 1887.376

Air volume ≅ 1,887.4

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Answer:

1887.4 cubic inches

Step-by-step explanation:

Answer: The answer is 125 degree(third option)

Step-by-step explanation:

x + 55 = 180 {being co interior angles}

or, x = 180 - 55

so, x = 125

Answer:

3

256

sq.units

Step-by-step explanation:

Both parabolas cut each other at (0,0) and (16,16)

Area enclosed by these parabolas

=∫

0

16

4

x

dx−∫

0

16

16

x

2

dx

=[

3

2×4×x

3/2

]

0

16

−[

16×3

x

3

]

0

16

=

3

2×4

4

−

3

4

4

=

3

256

sq. units

Answer: 24 feet

Step-by-step explanation: i just guessed it on pluto and got it right. please leave a like if it worked

The length of another axis for the given ellipse will be around 25.6125 feet so none of the options will be correct.

a regular oval form produced when a cone is cut by an oblique plane that does not intersect the base, or when a point moves in a plane so that the sum of its distances from two other points remains constant.

In another word, an ellipse is a curve that becomes by a point moving in such a way that the sum of its distances from two fixed points is a closed planar curve produced.

General equation of an ellipse

(x 2 / a 2 )+ (y2 / b 2 )= 1

Given that

the plot of land is 40 feet across one axis

so  2a = 40 feet

a = 20 feet

The foci are 16 feet from the center so

c = 16

Now we know that

c = √(b² - a²)  

c² = b² - a²

16² = b² - 20²

b = 25.6125  

So, the length of the minor axis will be around 25.6125 feet.

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Answer:

[tex]x= 80^o[/tex]

Step-by-step explanation:

Given

[tex]\angle Z = 36^o[/tex]

[tex]\angle WYZ = 100^o[/tex]

Required

Find x

[tex]\angle WYZ[/tex] and x are on a straight line.

So:

[tex]\angle WYZ + x= 180^o[/tex]

Make x the subject

[tex]x= 180^o -\angle WYZ[/tex]

Substitute known value

[tex]x= 180^o -100^o[/tex]

[tex]x= 80^o[/tex]

Answer:

80 is correct

Step-by-step explanation:

Answer:

0.3902

Step-by-step explanation:

The question meets the criteria for the calculation of the confidence interval of a one sample proportion ;

Sample size, n = 27

Number of students with faster reaction time = 14

Phat = x / n = 14 / 27 = 0.6296

The confidence interval is calculated thus :

C. I = Phat ± Zcritical * √[p(1 - p)/n]

Zcritical at 99% = 2.576

C. I = 0.6296 ± 2.576 * √[0.6296(0.3704)/27]

C.I = 0.6296 ± 0.2394042

The lower boundary of C.I = 0.6296 - 0.2394042

Lower boundary = 0.3902

Answer:

A.

Step-by-step explanation:

Start with

7y + 5 - 3

Combine like terms:

7y + 2

By combining like terms in 7y + 5 - 3, we end up with 7y + 2 which is the second expression.

Therefore, the expressions are equivalent because they evaluate to equal values for every value of y.

Answer: A.

Answer:

The margin of error for a 90% confidence interval for the mean banking fee is of $0.44.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.645.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Sample of 31:

This means that [tex]n = 31[/tex]

Assume the population standard deviation is $1.50.

This means that [tex]\sigma = 1.5[/tex]

Calculate the margin of error for a 90% confidence interval for the mean banking fee.

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]M = 1.645\frac{1.5}{\sqrt{31}}[/tex]

[tex]M = 0.44[/tex]

The margin of error for a 90% confidence interval for the mean banking fee is of $0.44.

Answer:

It will be 31.4 cm rounded off for circumference

It will be 78.53 cm2 rounded off for area

Step-by-step explanation:

Diameter = 10 cm

Radius = 10/2 cm = 5 cm

Circumference = 2×pi×radius

= 2pi×5

= 31.4 cm

Area = pi × r square

= 25 pi

= 78.53cm2

As both angles are supplementary

[tex]\\ \Large\sf\longmapsto 3x+(2x+3y)=180°[/tex]

[tex]\\ \Large\sf\longmapsto 3x+2x+3y=180[/tex]

[tex]\\ \Large\sf\longmapsto 5x+3y=180[/tex]

[tex]\\ \Large\sf\longmapsto 3y=180-5x[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]

And

[tex]\\ \Large\sf\longmapsto 3x=90[/tex]

[tex]\\ \Large\sf\longmapsto x=\dfrac{90}{3}[/tex]

[tex]\\ \Large\sf\longmapsto x=30[/tex]

Now

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-5(30)}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{180-150}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=\dfrac{30}{3}[/tex]

[tex]\\ \Large\sf\longmapsto y=10[/tex]

The question is incomplete. The complete question is :

A lottery offers one $800 prize, one $700 Prize, two $800 prizes, and four $100 prizes. One thousand tickets are sold at $5 each. Find the expectation if a person buys two tickets. Assume that the player's ticket is replaced after each draw and that the same ticket can win more than one prize. Round to two decimal places for currency problems.

The expected if a person buys two tickets is $__

Answer:

$ -1.52

Step-by-step explanation:

Given :

A lottery offers --

One $800 prize

One $700 prize

Two $800 prize

Four $100 prizes

Let X = net win

    X          P(X)

  795      1/1000

  695      1/1000

  795      2/1000

   95      4/1000

    -5     996/1000

[tex]$E(X) = \sum X \ p(X)$[/tex]

         [tex]$=795 \times \frac{1}{1000} + 695 \times \frac{1}{1000} + 795 \times \frac{2}{1000} + 95 \times \frac{4}{1000} + (-5) \times \frac{996}{1000}$[/tex]

         = 0.795 + 0.695 + 1.59 +  0.38 - 4.98

         = $ -1.52

Answer:

$64.15

Step-by-step explanation:

to solve this problem, first we should figure out how much money that the cashier gave them back, and then subtract that from $80 (which was what Matt and his siblings gave the cashier) to find out how much the perfume cost.

it is given that:

they gave the cashier $80.

the cashier gave them back 1 ten-dollar bill ($10), 1 five-dollar bill ($5), 8 dimes ($0.80 or 80 cents) , and 1 nickel ($0.05 or 5 cents)

$10+$5+$0.80+$0.05=$15.85

the total amount of money that the cashier gave them back is $15.85

to find how much the perfume cost:

$80-$15.85=$64.15

so, the perfume cost $64.15

Answer:

16 cm^2/min

Step-by-step explanation:

dV/dt=24

V=a^3, differentiate with respect to t

dV/dt=3a^2*da/dt, a^2*da/dt=8

S=6a^2, 216=6a^2. a=6. da/dt=(8/36)

dS/dt=12*a*da/dt=12*(8/6)=16 cm^2/min

Answer:

Need to see the problem, but the "zero of the function" is the x value when y=0.

Substitute '0' for y.

Solve for x

Answer: D

Step-by-step explanation:

Volume = πr²h

Radius = 3yd

Height = 12yd

Take π = 22/7

Volume = 22/7×3×3×12

= 2376/7

= 339.4285714yd³

Rounding off to nearest tenth

= 339.43yd³

Answered by Gauthmath must click thanks and mark brainliest

Answer:

WE reject the Null and conclude that the mean coefficient of restitution exceeds 0.82

Step-by-step explanation:

This is a one sample t test :

The hypothesis :

H0 : μ = 0.82

H0 : μ > 0.82

Given the sample data:

0.8411 0.8191 0.8182 0.8125 0.8750

0.8580 0.8532 0.8483 0.8272 0.7983

0.8042 0.8730 0.8282 0.8359 0.8660

Sample size, n = 15

Sample mean = ΣX / n = 0.837

Sample standard deviation, s = 0.0246 (from calculator)

The test statistic :

T = (xbar - μ) ÷ (s/√(n))

T = (0.837 - 0.82) ÷ (0.0246/√(15))

T = 2.676

The critical value at α = 0.05

df = n - 1 ; 15 - 1 = 14

Tcritical(0.05, 14) = 1.761

Reject H0 if Test statistic > Tcritical

Since, 2.676 > 1.761 ; WE reject the Null and conclude that the mean coefficient of restitution exceeds 0.82

Answer:

[tex]a_5= 14[/tex]

[tex]a_{20}= 80[/tex]

[tex]a_{18}= 340[/tex]

Step-by-step explanation:

Solving (a):

We have:

[tex]a_1=2[/tex] --- first term

[tex]d = 5 -2 = 3[/tex] common difference

The 5h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_5= 2+ (5 - 1)*3[/tex]

[tex]a_5= 14[/tex]

Solving (b):

We have:

[tex]a_1 = 4[/tex] --- first term

[tex]d = 8 -4 = 4[/tex] common difference

The 20h term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{20}= 4+ (20 - 1)*4[/tex]

[tex]a_{20}= 80[/tex]

Solving (c):

We have:

[tex]a_1 = 0[/tex] --- first term

[tex]d = 20 -0 = 20[/tex] common difference

The 18th term is:

[tex]a_n= a_1 + (n - 1)d[/tex]

[tex]a_{18}= 0+ (18 - 1)*20[/tex]

[tex]a_{18}= 340[/tex]

Answer:

-3/8 is located on the right of -1

Step-by-step explanation:

-3/8 is left of -1 because -3/8 is larger than -1.

Complete Question

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)  

t=8.169  

P-value= ?

Answer:

a)  [tex]P-value=0[/tex]

b)  Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=10[/tex]

Mean [tex]\=x= 51.3[/tex]

Standard deviation [tex]\sigma=1.2[/tex]

Significance level is taken as [tex]\alpha=0.05[/tex]

t test statistics

[tex]t=8.169[/tex]

Therefore

[tex]P-Value=P(t>8.169)[/tex]

Critical point

[tex]t_{\alpha,df}[/tex]

[tex]\alpha=0.05[/tex]

[tex]df=10-1=>9[/tex]

Therefore

P-value from T distribution table

[tex]P-value=0[/tex]

Conclusion

[tex]P-value (0)< \alpha(0.05)[/tex]

We Reject the Null Hypothesis [tex]H_0[/tex]

Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Answer:

you never showed the chocies

Step-by-step explanation:

Answer:

Casey's monthly charge for making 1,100 minutes of calls is $70.

Step-by-step explanation:

We can write a piecewise function to model the situation.

Since Casey's phone service only charges a monthly fee of $30 for the first 1000 minutes, we can write that for calling t minutes:

[tex]\displaystyle C(t) = 30\text{ if } t\leq 1000[/tex]

In other words, the total cost is only $30 is the total minutes of call is less than  1000 minutes.

However, if the total minutes of calls is greater than 1000, then its $0.40 per minute on top of the 30. Thus:

[tex]\displaystyle C(t) = 30 + 0.4(t-1000)\text{ if } t>1000[/tex]

All together, our piecewise function will be:

[tex]\displaystyle C(t) = \begin{cases} 30 & t\leq 1000 \\ 30 + 0.4(t-1000) & t>1000\end{cases}[/tex]

We want to determine Caseys monthly charge if he makes 1,100 minutes of calls. So, t = 1100. Since 1100 > 1000, we will use the second equation. This yields:

[tex]C(1100)= 30+0.4((1100)-1000)[/tex]

Evaluate:

[tex]\displaystyle C(1100) = 30+0.4(100) = 30+40=\$70[/tex]

Casey's monthly charge for using 1,100 minutes of call is $70.

Answer:

In a pair of similar triangles, the corresponding sides are proportional.

Step-by-step explanation:

Corresponding sides touch the same two angle pairs. When the sides are corresponding it means to go from one triangle to another you can multiply each side by the same number.

Answer:

3

Step-by-step explanation:

[tex] \frac{3x - 3}{x} \div \frac{x - 1}{x} [/tex]

[tex] \frac{3(x - 1)}{x} \times \frac{x}{x - 1} = 3[/tex]

Answer:

Approximately 68% of people have IQs between 84 and 116.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 100, standard deviation of 16.

Percentage of people with IQs between 84 and 116.

84 = 100 - 16

116 = 100 + 16

So within 1 standard deviation of the mean, which, by the Empirical Rule, is approximately 68%.

Answer:

12

Step-by-step explanation:

(18+3)=21

(9-5)=4

4x21=84

84/2=42

42-30=12

Answer:

12

Step-by-step explanation:

((18+3)x(9-5))/2-30

=((21)x(4))/2-30

=(84)/2-30

=42-30

=12

Answer:

We know that the angle which lineer and divided by |AB| equal to 130°

Step-by-step explanation:

if 130° look at the 2x+260 we can say that 2x+260=260° so X equal to Zero (0)

Answer:

[tex] g(4) = \frac{5}{11} [/tex]

Step-by-step explanation:

Given:

[tex] g(x) = \frac{x^2 - 6}{3x + 10}

Required:

g(4)

Solution:

Substitute x = 4 into [tex] g(x) = \frac{x^2 - 6}{3x + 10} [/tex]

Thus:

[tex] g(4) = \frac{4^2 - 6}{3(4) + 10} [/tex]

[tex] g(4) = \frac{16 - 6}{12 + 10} [/tex]

[tex] g(4) = \frac{10}{22} [/tex]

[tex] g(4) = \frac{5}{11} [/tex]