Find the volume of this cuboid 5cm

Answer:

23

Step-by-step explanation:

Answer:

y = -3x - 1

Step-by-step explanation:

First find the slope then the Y-intercept

Answer:

ti 5

Step-by-step explanation:

its 5

Answer:

[tex] 84 \: {cm}^{2} [/tex]

Step-by-step explanation:

Area of the figure = Area of rectangle + Area of trapezoid

[tex] = 18 \times 3 + \frac{1}{2} \{(18 - 11) + 3) \}(9 - 3) \\ \\ = 54 + \frac{1}{2} \{7 + 3 \}6\\ \\ = 54 + 10 \times 3\\ \\ = 54 + 30 \\ \\ = 84 \: {cm}^{2} [/tex]

Answer:

the one on the bottom and Lewis made one less of whatever Bryan made

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

bryan- 7x4=28

lewis- 6x4=24

28+24=52

Answer:

b

Step-by-step explanation:

cause a negative number is to the left of zero and a positive to the right

9514 1404 393

Answer:

  x = 18

Step-by-step explanation:

The parallel lines cut the transversals proportionally.

  (2x -1)/40 = 21/24

  2x -1 = 35 . . . . . . . multiply by 40

  2x = 36 . . . . . . . . add 1

  x = 18  . . . . . . . . . divide by 2

Answer:

18

Step-by-step explanation:

This is a 5 sided shape, aka a pentagon, and we know that five sided shape's angles add up to 540, so our equation is:

(9x-6)+(3x+23)+95+(7x-4)+90=540.

Combine like terms:

We get 25x+90=540

x = 18

Answer:

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx[/tex]

Required

Solve

Let

[tex]u = \frac{x^2}{4}[/tex]

Differentiate

[tex]du = 2 * \frac{x^{2-1}}{4}\ dx[/tex]

[tex]du = 2 * \frac{x}{4}\ dx[/tex]

[tex]du = \frac{x}{2}\ dx[/tex]

Make dx the subject

[tex]dx = \frac{2}{x}\ du[/tex]

The given integral becomes:

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du[/tex]

Recall that: [tex]u = \frac{x^2}{4}[/tex]

Make [tex]x^2[/tex] the subject

[tex]x^2= 4u[/tex]

Square both sides

[tex]x^4= (4u)^2[/tex]

[tex]x^4= 16u^2[/tex]

Substitute [tex]16u^2[/tex] for [tex]x^4[/tex] in [tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du[/tex]

Simplify

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du[/tex]

In standard integration

[tex]\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)[/tex]

So, the expression becomes:

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)[/tex]

Recall that: [tex]u = \frac{x^2}{4}[/tex]

[tex]\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c[/tex]

Answer:

166 years older.

Step-by-step explanation: Subtract 1751 from 1917

Answer:

The top right one 3(x+4)=30

Step-by-step explanation:

Answer:

The answer should be the one on the top right.

Step-by-step explanation:

So we know that the whole entire model equals 30, and each of the three sections are s+4. So, in order to get 30, the equation has to have something to do with three times s+4. We can eliminate the one on the top left because the model does not have a 12 involved. We can also eliminate the bottom left because it only represents one of the three s+4s. The bottom right can be taken off because the 3 in that equation is only multiplied to s, and not s+4. The top right works because it is saying that s+4 multiplied by 3 times is equal to 30. There you go! I hope this helps❤️

Answer:

1. Assume the contrary, namely that √2 + √3 + √5 = r, where r is a rational number.

Square the equality √2 + √3 = r − √5 to obtain 5 + 2

√6 = r2 + 5 − 2r

√5. It follows

that 2√6 + 2r

√5 is itself rational. Squaring again, we find that 24 + 20r2 + 8r

√30

is rational, and hence √30 is rational, too. Pythagoras’ method for proving that √2 is

irrational can now be applied to show that this is not true. Write √30 = m

n in lowest

terms; then transform this into m2 = 30n2. It follows that m is divisible by 2 and because

2( m

2 )2 = 15n2 it follows that n is divisible by 2 as well. So the fraction was not in lowest

terms, a contradiction. We conclude that the initial assumption was false, and therefore

√2 + √3 + √5 is irrational.

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] step - 1 : define[/tex]

[tex] \sin( {30}^{o} ) = \frac{a}{12} [/tex]

[tex] step - 2 : solve[/tex]

Answer:

158 m²

Step-by-step explanation:

I made this into 3 rectangles.

Figure 1:

9•8=72

The 9 is from the 13 m side, but I've taken 4 m off from the overlapping square.

Figure 2:

6•7=42

The 7 is from the 10 m side, but I've taken 4m off from the overlapping square again.

Remaining Area:

If you extend the lines into figures 1 and 2 from the top left corner and bottom right corner vertically, you will get a rectangle that is (11 m) x (4 m). This is not yet accounted for.

11•4=44

Add together: 72 + 42 + 44 = 158

*Note: You could also find the area of the squares a much easier way by subtracting the overlapping part after finding the area of both figures , but this is how I did it*

Answer:

ABC

Step-by-step explanation:

Answer:

YZX ~ ABC

Step-by-step explanation:

For Angle Y, there is one curved line, so you must go to the other triangle and find which angle has one curved line too, in this case that is angle A. Then, Angle Z has three curved lines, and in the other triangle, Angle B has three curved lines, so you now have AB, which only leaves C left. So your final answer is ABC.

THINGS TO REMEMBER:

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Question: Write an expression for how much it would cost to park for 3d hours on a holiday during peak hours.

-----

Answer: 3d × 2  or  3d + 3d

-----

Explanation: This is because during holidays the amount of d doubles. However since this is on a holiday DURING peak hours it would be 3d × 2

-----

Question 2: Then, if the basic off-hours parking rate is $2.50 per hour, how much would a person pay to park for 3d hours in the situation described above?

-----

Answer: $15

-----

Explanation: Since d represents dollars we would multiply 2.50 times 3 which would give us 7.5 then we double this since it is during holidays giving us $15

-----

NOTE: I AM SO SORRY IF THIS IS WRONG AND I MISSED SOMETHING. IF IT IS WRONG THEN PLEASE MAKE SURE TO TELL ME SO I CAN FIGURE OUT WHAT I MISUNDERSTOOD

Again I'm sorry but I hope I helped a little bit.    

Answer:

The slope is 9 3/4 or 9.75

Step-by-step explanation:

slope= rise/run or y/x

29.25/3=9.75 or 9 3/4

Answer:

shifted left 7 & shifted down 3

Step-by-step explanation:

Answer:

the answer is one solution (70)

Step-by-step explanation:

2(a+11)=-3(16-a)

distribute

2a+22=-48+3a

subtract 2a from both sides

22=-48+a

add 48 to both sides

70=a

the answer is one solution (70)

Answer:

Since a blogger has 400 subscribers to her blog in January, and the number of subscribers has grown by a factor of 1.5 every month since the, to write a sequence to represent the number of subscribers in the 3 months that followed, the following reasoning has to be made:

January: 400 subscribers

February: 400 x 1.5 = 600 subscribers

March: 600 x 1.5 = 900 subscribers

April: 900 x 1.5 = 1,350 subscribers

The sequence to represent the number of subscribers in the 3 months that followed are :

First month = 600 subscribers

Second month = 900 subscribers

Third month = 1350 subscribers

The blogger has 400 subscriber to her blog in January.

The number of subscriber has grown by a factor of 1.5 every month since then.

Therefore, the sequence to represent the number of subscribers in the 3 months that followed can be calculated below

January Subscribers = 400

February Subscribers = 1.5 × 400 = 600

March Subscribers = 1.5 × 600 = 900

April subscribers = 1.5 × 900 = 1350

learn more on sequence here:https://brainly.com/question/21324508?referrer=searchResults

Answer:

????????????????xhrhrhdhehdhzh

Answer:

??????????????????????????????????????????????????????????????????????????///////

Step-by-step explanation:

Answer:

Commutative Property

Step-by-step explanation:

It looks like Associative property which is when you change the GROUP, but actually it’s commutative because it didn’t change any numbers in the group, just the order of where they were.

Associative: (25 + 19) + 15 = (15 + 19) + 25

Commutative: (25 + 19) + 15 = (19 + 25) + 15

It didn’t change the numbers, only the order. Therefore, it would be commutative property

Answer:

25+19=44

44+15=59

19+25=44

44+15=59

Answer:

$26.99

Step-by-step explanation:

i multiplied $89.99×.7 to get $62.993 and subtracted that from the regular amount.

hope this is right and helps :)

Answer:

Step-by-step explanation:

89.99(1-70/100)

89.99(30/100)

$26.997

$27 (rounded to nearest cent)

Answer:

I. -9 + y = 18

Step-by-step explanation:

Double-check to see if I was correct

The equations I. and III. satisfies the condition when y = 27

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

The value of y = 27

So , substituting the value of y in all of the given equations , we get

I.  

-9 + y = 18

when y = 27

Substituting the value of y , we get

-9 + 27 = 18

18 = 18

So , I. satisfies the condition and the equation is TRUE

II.

-18 + y = 45

when y = 27

Substituting the value of y , we get

-18 + 27 = 45

9 ≠ 45

So , II. does not satisfy the condition and the equation is FALSE

III.

5y = 135

when y = 27

Substituting the value of y , we get

5 x 27 = 135

135 = 135

So , III. satisfies the condition and the equation is TRUE

IV.

2y = 49

when y = 27

Substituting the value of y , we get

2 x 27 = 29

54 ≠ 29

So , IV. does not satisfy the condition and the equation is FALSE

Hence , the equations I. and III. are TRUE

To learn more about equations click :

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Answer:

They multiplied by 100

Step-by-step explanation:

1 x 1.5 = 1.5

10 x 1.5 = 15

100 x 1.5 = 150

Answer:48ft

Step-by-step explanation:

Answer:

[tex]x = 2.5[/tex]

Step-by-step explanation:

Given

[tex]AC = 2x - 1[/tex]

[tex]AB = 2x + 1[/tex]

[tex]BC = 2\sqrt{7[/tex]

[tex]\angle A = 60^{\circ}[/tex]

Required

Find x

To find x, we make use of cosine formula which states:

[tex]a^2 = b^2 + c^2 - 2bcCosA[/tex]

In this case:

[tex]BC^2 = AB^2 + AC^2 - 2*AB*BC*CosA[/tex]

Substitute values

[tex](2\sqrt{7})^2 = (2x + 1)^2 + (2x-1)^2 - 2*(2x + 1)*(2x - 1)*Cos(60^{\circ})[/tex]

Evaluate all exponents

[tex]4*7 = (4x^2 + 4x + 1)+(4x^2 - 4x + 1) - 2(4x^2 - 1)*cos(60^{\circ})[/tex]

Open brackets

[tex]28 = 4x^2 + 4x + 1+4x^2 - 4x + 1 - (8x^2 - 2)*cos(60^{\circ})[/tex]

Collect Like Terms

[tex]28 = 4x^2 +4x^2+ 4x - 4x+ 1 + 1 - (8x^2 - 2)*cos(60^{\circ})[/tex]

[tex]28 = 8x^2+ 2 - (8x^2 - 2)*cos(60^{\circ})[/tex]

Substitute 0.5 for cos(60)

[tex]28 = 8x^2+ 2 - (8x^2 - 2)*0.5[/tex]

Open bracket

[tex]28 = 8x^2+ 2 - 4x^2 + 1[/tex]

Collect Like Terms

[tex]8x^2- 4x^2 + 2 + 1 - 28 = 0[/tex]

[tex]4x^2 -25 = 0[/tex]

Collect Like Terms

[tex]4x^2 =25[/tex]

Divide both sides by 4

[tex]x^2 =\frac{25}{4}[/tex]

[tex]x^2 =6.25[/tex]

Take positive square root of both sides

[tex]x = \sqrt{6.25[/tex]

[tex]x = 2.5[/tex]

Answer:

5/9

Step-by-step explanation:

Answer:

9%

Step-by-step explanation: