Find X and y-intercepts for
12x +6y =108

Answer:

The correct answer is C. Statement: m∠3 + m∠5 = 180° and m∠4 + m∠6 = 180° Reason: definition of supplementary angles.

This statement uses the definition of supplementary angles, which states that two angles are supplementary if their measures add up to 180 degrees. Since ∠3 and ∠6 are corresponding angles, and ∠4 and ∠5 are also corresponding angles, their measures must add up to 180 degrees in order for the parallel lines to be cut by the transversal.

Answer:

Option, D. Statement: ∠7 ≅ ∠6 and ∠8 ≅ ∠5 Reason: Vertical Angles Theorem

Step-by-step explanation:

In this question that you have put:

7 ≅ ∠6 and ∠8 ≅ ∠5 Reason =

Vertical Angles Theorem ( Or in similar terms VAT )

Make sure that you remember the following:

vertical angles are the angles that are opposite each other when the two line " meet together "

Thus, your answer to your questions is.

D. Statement: ∠7 ≅ ∠6 and ∠8 ≅ ∠5 Reason: Vertical Angles Theorem

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Answer:

[tex]\mbox{\large $0.5 + 0.16 \bar {3}$ = \boxed{\dfrac{199}{300}}}[/tex]

Step-by-step explanation:

[tex]0.16\bar{3} = 0.16333333333\\[/tex]

the 3 repeats until infinity

Let's multiply this by 100 to move the non-repeating part to the left of the decimal point

0.1633333333...... x 100 = 16.333333333333333...

.333333 = 1/3

Therefore the recurring number multiplied by 100 is
[tex]16 + \dfrac{1}{3} = \dfrac{16 \times 3 + 1}{3}=\dfrac{49}{3}[/tex]

Since this fraction was arrived at by multiplying by 100, divide this fraction by 100 to get back the fraction in its original decimal value of 0.163333

[tex]\dfrac{49}{3} \div 100[/tex]

To divide by a number, multiply by the reciprocal of that number

Reciprocal of 100 is 1/100:

[tex]\dfrac{49}{3} \div 100 = \dfrac{49}{3} \times \dfrac{1}{100} = \dfrac{49}{300}[/tex]

(You can verify this by dividing 49 by 300 in a calculator and seeing that the result is 0.163333333333333333333 i.e. 0.16333 recurring

We want to add 0.5 to this.

0.5 = [tex]\dfrac{1}{2}[/tex]

so
0.5 + 0.16333333 = 0.6633333

[tex]= \dfrac{1}{2} + \dfrac{49}{300}[/tex]

We can write [tex]\dfrac{1}{2}[/tex] as [tex]\dfrac{150}{300}[/tex]  by multiplying numerator and denominator by 150

So we get

[tex]0.5 + 0.1633333 = \dfrac{150}{300} + \dfrac{49}{300} = \dfrac{150+49}{300} = \dfrac{199}{300}[/tex]

If you perform this division on a calculator you will get the answer as 0.663333 = [tex]0.66\bar{3}[/tex] which is what you get when you add 0.5 and [tex]0.16\bar{3}[/tex]

Answer:

2.3333 inches

Step-by-step explanation:

To find the appropriate scale factor, we need to determine how many times smaller the piece of paper is compared to the dog. We can start by finding the ratio of the length of the paper to the length of the dog:

3 inches / 9 inches = 1/3

Similarly, the ratio of the width of the paper to the height of the dog is:

5 inches / 7 inches = 5/7

So, the smaller of these two ratios, 1/3, is the appropriate scale factor for Meredith to use in her drawing. This means that the length of the dog in the drawing will be 9 inches * 1/3 = 3 inches, and the height will be 7 inches * 1/3 = 2.3333 inches.

The sector area of the sector defined by the minor arc CB is given as follows:

7.5 cm².

The area of a circle of radius r is given by π multiplied by the radius squared, as follows:

A = πr².

We have that the radius is half the diameter, hence it's measure is given as follows:

r = 3 cm.

The angle measure of arc CB is given as follows, considering that BD is half the circle = 180º.

CB + 84º = 180º.

CB = 96º.

An entire circle has an angle of 360º, hence the area of the sector is given as follows:

A = 96/360 x π x 3²

A = 7.5 cm².

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There are 56 servings in a 28 pound bag of dog food.

The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

Given:

Each day Fei yen's dog eat dog food = 8 ounces

Fei yen bought a 28 pound bag of dog food.

And we know that 1 pound = 16 ounces

Then ,the food in ounces

= 28 x 16

= 448 ounces

Now, the number of 8 ounces servings are in a 28 pound bag of dog food

= 448 / 8

= 56

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The solution is Option E.

The solution to the system of equations is the point of intersection of line and the lines intersect at the point A ( 3 , 2 )

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

Let the first point be P ( -3 , -4 )

Let the second point be Q ( 7 , 6 )

Now , the slope of the line is m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Slope m = 10 / 10 = 1

Now , the equation of line is y - y₁ = m ( x - x₁ )

y - 6 = 1 ( x - 7 )

y - 6 = x - 7

y = x - 1   be equation (1)

Now , the point of intersection of lines is at ( 3 , 2 )

Substitute the value of x and y in the equation , we get

when x = 3 , y = 2

2 = 3 - 1

2 = 2

Hence , the solution to the equation is ( 3 , 2 )

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If Kashif and Ali invested equal sums in the two different banks at 9 % and 10% , then in 6 years Ali will have $0.0945 more than Kashif .

We use the formula for compound interest, to calculate the amount that each person will have after 6 years  ;

Amount after 6 years for Kashif is :

⇒ A = P(1 + r/n[tex])^{nt}[/tex]

where A = (amount after 6 years) ; P = (initial investment)

r = interest rate = 9%  ; n = 1 ; t = time period (6 years) ;

So, A = P(1 + 0.09/1)⁶  ⇒ P(1.09)⁶  ;

Amount after 6 years for Ali is :

⇒ A = P(1 + 0.10/1)⁶ = P(1.10)⁶  ;

So , difference in the amounts that Kashif has compared to Ali after 6 years is  ⇒ P(1.09)⁶ - P(1.10)⁶  ;

Simplifying this expression, we get:

⇒ P(1.09⁶ - 1.10⁶)  ;

≈ -$0.0945     ;

Since the value is negative, it means that after 6 years, Ali will have more money than Kashif and difference between their amounts is approximately $0.0945    .

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40%=

5

2

​

5

2

​

⋅40=16 cars at 8000 each =128,000 in sales

40−16=

​

24 cars at 9000 each

​

=216,000 in sales

Total sales: 128,000+216,000=344,000

Total expense: 6500⋅40=260,000

Total profit: 344,000−260,000=84,000

Answer:

$84000

Step-by-step explanation:

40% of the cars would be 16 cars that are sold for $8000 each.

16×$8000=$128000

The remaining 60% of cars would be 24 cars to be sold at $9000 each.

24×$9000=$216000

The total profit = the sum - the amount he paid for all cars.

total profit = ($128000+$216000) - (40×$6500)

total profit = $344000 - $260000

total profit = $84000

Answer:

-5x-96/12

Step-by-step explanation:

Firstly we want ot combine the multiplied terms into one fraction:

(1x/3-3)+(-3/4 x-5)

Then we multiply by 1:

(x/3-3)+(-3/4 x-5)

Find common denominator:

(x/3+3(-3)/3)+(-3/4 x-5)

Combine fractions with common denominator:

(x+3(-3)/3)+(-3/4 x-5)

Multiply the numbers:

(x-9/3)+(-3/4 x-5)

Combine multiplied terms into a single fraction:

x-9/3+(-3x/4 -5)

Find common denominator:

x-9/3+(-3x/4 + 4(-5)/4)

Combine fractions with common denominator:

x-9/3+(-3x + 4(-5)/4)

Multiply the numbers:

x-9/3 + (-3x-20/4)

Find common denominator:

4(x-9)/12 + 3(-3x-20)/20

Combine fractions with common denominator:

4(x-9)+3(-3x-20)/12

Distribute:

4x-36+3(-3x-20)/12

Distribute:

4x-36-9x-60/12

Subtract the numbers:

4x - 96 - 9x/12

Combine like terms:

-5x - 96/12

Answer: -5x-96/12

The measures of the angles formed by the cords and secant in the circle are found using circle theorems and presented as follows;

A secant is a line that has two points of intersection on a circle.

The specified parameters are;

1. The measure of arc  [tex]m\widehat{AB}[/tex] = 80°, and the measure of [tex]m\widehat{CD}[/tex] = 15°

Angle at the center of the circle = 2 × Angle at the circumference

Angle at the center of the circle = The arc angle of the circle

Therefore;

m∠DAC = 15°/2 = 7.5°

m∠ACO = 80°/2 = 40°

The external angle of a triangle theorem, indicates that we get;

m∠1 = 40° + 7.5° = 47.5°

m∠1 = 47.5°

2. m∠BOD = 100°, [tex]m\widehat{AC}[/tex] = 90°

The intersecting chords theorem indicates that we get;

m∠BOD = (1/2)×([tex]m\widehat{AC}[/tex] + [tex]m\widehat{BD}[/tex])

Therefore; 100° = (1/2)×(90° + [tex]m\widehat{BD}[/tex])

[tex]m\widehat{BD}[/tex] = 2 × 100° - 90° = 110°

[tex]m\widehat{BD}[/tex] = 110°

3. [tex]m\widehat{AB}[/tex] = 90°, [tex]m\widehat{CD}[/tex] = 20°

Therefore; m∠ACO = 90°/2 = 45°

m∠DAC = 20°/2 = 10°

The external angle theorem indicates that we get;

m∠COD = 45° + 10° = 55°

m∠COD = 55°

4. m∠1 = 35°, [tex]m\widehat{AB}[/tex] = 50°, therefore;

m∠ACO = 50°/2 = 25°

m∠CAO = 35° - 25° = 10°

[tex]m\widehat{CD}[/tex] = 2 × m∠CAO

Therefore; [tex]m\widehat{CD}[/tex] = 2 × 10° = 20°

[tex]m\widehat{CD}[/tex] = 20°

5. m∠AOC = (1/2)×([tex]m\widehat{AC}[/tex] + [tex]m\widehat{BD}[/tex])

Therefore; m∠AOC = (1/2)×(90° + 110°) = 100°

m∠AOC = 100°

6. [tex]m\widehat{CD}[/tex] = 20° and [tex]m\widehat{AB}[/tex] = 70°

The external secant, tangent theorem, indicates that we get;

m∠APB = (1/2) × ([tex]m\widehat{AB}[/tex] - [tex]m\widehat{CD}[/tex])

m∠APB = (1/2) × (70° - 20°) = 25°

m∠APB = 25°

7. [tex]m\widehat{AB}[/tex] = 50°,

The angle at the center of a circle is twice the angle subtended at the circumference, therefore;

m∠ADB = 50°/2 = 25°

m∠ADB = 25°

8. m∠CAD = 45°

The angle formed by an arc at the center of a circle theorem, indicates that we get;

[tex]m\widehat{CD}[/tex] = 2 × m∠CAD

[tex]m\widehat{CD}[/tex] = 2 × 45° = 90°

[tex]m\widehat{CD}[/tex] = 90°

9. m∠ACB = 70°

m∠ACB is the angle subtended by the arc [tex]m\widehat{AB}[/tex] on the circumference

Therefore;

[tex]m\widehat{AB}[/tex] = 2 × m∠ACB

[tex]m\widehat{AB}[/tex] = 2 × 70° = 140°

[tex]m\widehat{AB}[/tex] = 70°

10. m∠AOB = 80°, [tex]m\widehat{AB}[/tex] = 60°

m∠(AOB) = (1/2) × ([tex]m\widehat{AB}[/tex] + [tex]m\widehat{CD}[/tex])

Therefore; m∠(AOB) = 80° =  (1/2) × (60 + [tex]m\widehat{CD}[/tex])

80° =  (1/2) × (60 + [tex]m\widehat{CD}[/tex])

[tex]m\widehat{CD}[/tex] = 2 × 80° - 60° = 100°

[tex]m\widehat{CD}[/tex] = 100°

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Answer: 37 points

Step-by-step explanation:

Answer:

Answer is Below ------v

1. clockwise

2. 3

1. (y, -x)

2. (3x,3y)

Answer:

x + 3y = 9

Step-by-step explanation:

The simplified product of the ^3sqrt2x^5 x ^3sqrt64x^9 is [tex]24\sqrt{2} x^{17}[/tex]

Simplifying an expression is just another way to say solving a math problem. When you simplify an expression, you're basically trying to write it in the simplest way possible. At the end, there shouldn't be any more adding, subtracting, multiplying, or dividing left to do.

For finding the simplified product we will first remove the squareroot possible and simplify the value in a simplest way as possible. In the given question, first we will simplifying [tex]\sqrt{64}[/tex] and after simplifying it we will then apply [tex]a^{n} . a^{m} = a^{n+m}[/tex], and lastly we will multiply the two numbers i.e., 3 and 8.

[tex]3\sqrt{2}x^5x^3\sqrt{64}x^9[/tex]

[tex]3\sqrt{2}x^5x^3\sqrt{8^{2} }x^9[/tex]

[tex]3.8\sqrt{2}x^{5+3+9}[/tex]

[tex]3.8\sqrt{2}x^{17}[/tex]

[tex]24\sqrt{2}x^{17}[/tex]

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Answer:

Step-by-step explanation:

Greetings!!!

The given two numbers ratio.

[tex] \frac{5}{4} [/tex]

The smaller number is 32

[tex] \frac{5}{4} \times 32[/tex]

convert elements into fraction

[tex] \frac{5}{4} \times \frac{32}{1} [/tex]

Apply fraction rule

[tex] \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d} [/tex]

Multiply the numbers

[tex] \frac{5 \times 32}{4 \times 1} [/tex]

Divide the numbers

[tex] \frac{32}{8} = 8 \\ 8 \times 5 = 40[/tex]

Hope it helps!!!

Answer: b (b²+b+4)

Step-by-step explanation:
b²=bb
b³=b²b
=b²b+bb+4b
=b(b²+b+4)

The given expression is a fraction in the form of[tex](n^2 + 2n + 5)/n[/tex], which is an element of the set Omega ([tex]n^2[/tex]). This expression is true.

The given expression is a fraction in the form[tex](n^2 + 2n + 5)/n[/tex], which belongs to the set Omega[tex](n^2).[/tex] This statement is valid, as the fraction is simply a simplified form of a polynomial, which is an element of the Omega set. The numerator of the fraction is [tex]n^2 + 2n + 5[/tex], which is a quadratic equation in n. The denominator is n, which is a linear equation in n. As the numerator and denominator are both polynomials of n, the fraction is an element of the Omega set. Therefore, the statement is true.

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If repetitions of colors are allowed, there are 59,049 possible selections of collars for the 5 cats.

If Dave can choose from 9 different colors for each of his 5 cats, then he has 9 choices for the first cat, 9 for the second cat, and so on. To find the total number of possible selections, we can multiply the number of choices for each cat together:

9 x 9 x 9 x 9 x 9 = 59,049

In this case, there are 9 ways to choose the collar color for the first cat. Since Dave can choose from the same 9 colors for each of the 5 cats, so he has 9 choices for each cat. Therefore, by the principle of counting, the total number of ways to choose collars for all 5 cats is:

Therefore, if repetitions of colors are allowed, there are 59,049 possible selections of collars for the 5 cats.

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The expression that is equivalent to 5^6 is A.125 x 125

Index forms are defined as mathematical forms of writing numbers that are too large or small in more convenient forms.

Other terms for index forms are called standard forms or scientific notations.

They are also described as numbers or variables that are raised to an exponent.

From the information given, we have that;

5⁶

This is replicating 5 in 6 places, we have the representation as;

5 × 5 × 5 × 5 × 5 × 5

Hence, the expression is 125 x 125

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By applying the slope of the function at that point, linear approximation provides an estimate of the value of a function close to a beginning point.

When estimating the value of a function at a nearby location, linear approximation uses the slope of the function at a particular position. In order to arrive at the starting position, it first calculates the difference between the two points, multiplies it by the slope, and adds it. This provides a rough estimate of the function's value at the new location. A technique for calculating a function's value close to a beginning point is called linear approximation. It is predicated on the notion that a linear function can be used to roughly approximate the function close to the point of interest. This indicates that the value of the function at surrounding places can be inferred from the slope of the function at the point in question.

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After 38 hours, there will be 43.1 mg of the radioactive substance remaining.This means that the amount of a radioactive substance decreases exponentially over time

Radioactive decay follows an exponential decay curve. This means that the amount of a radioactive substance decreases exponentially over time. The equation for this is: [tex]A(t) = A0*e^(-λ*t\\[/tex])Where A(t) is the amount of substance at time t, A0 is the initial amount of substance, and λ is the decay constant. In this problem, A0 = 100 mg, t = 29 hours, and A(t) = 50 mg. We can use this to solve for λ:50 mg = 100 mg * [tex]e^(-λ*29)λ =[/tex] -0.027Now that we have the decay constant, we can calculate the amount of substance remaining after 38 hours:A(38) = 100 mg * [tex]e^(-0.027*38[/tex]).A(38) = 43.1 mg.Therefore, after 38 hours, there will be 43.1 mg of the radioactive substance remaining.

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The total cost of the skateboard is $76.07.

The first step is to determine the price of the skateboard after the 12% discount. A discount reduces the price of an item.

Price after discount = price before discount x (1 - percent discount)

$79.86 x (1 - 12/100)

$79.86 x (1 - 0.12)

$79.86 x 0.88

= $70.28

Price after the sales tax = (1 + sales tax) x price after discount

= (1 + 8.25/100) x $70.28

(1 + 0.0825) x $70.28

1.0825 x $70.28 = $76.07

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8 is (6x^2-7x-5)/(2x + 1)

The function f(x) = 6log₂x - 3 increasing at the greatest rate in the interval [1/8, 1/2].

The maxima and minima of a function are the extreme values within the range; in other words, they are the maximum and minimum values of a function, respectively, at a given position.

Let the function be f(x) = 6log₂x - 3

For the interval x ∈ [2, 6]

f(x) ∈ [-0.678, 3]

For the interval x ∈ [1/8, 1/2]

f(x) ∈ [ -9.96, -5.32]

For the interval x ∈ [1, 2]

f(x) ∈ [-3, -0.67]

For the interval x∈ [1/2, 1]

f(x) ∈ [-5.32, -3]

The function increased most rapidly in the interval [1/8, 1/2], as can be seen from the function value and its interval values.

Therefore, the range [1/8, 1/2] is where the function f(x) = 6log₂x - 3 increases at the fastest pace.

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Caleb can choose which 20 items to buy in 1140 ways if he wants all 3 cheeses.

To choose 20 items at the grocery store, Caleb has narrowed down his selections to 5 vegetables, 8 fruits, 3 cheeses, and 7 whole grain breads. Since he wants all 3 cheeses, he only needs to choose 17 more items.

The number of ways he can choose these 17 items from the remaining vegetables, fruits, and breads is given by the combination: C(5+8+7, 17) = C(20, 17) = 1140.

This formula means that there are 20 items to choose from, and Caleb wants to choose 17. The order doesn't matter, so we use a combination.

Therefore, Caleb can choose which 20 items to buy in 1140 ways if he wants all 3 cheeses.

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Answer:

Y < (1/3) x - 5

Given point D is the centroid of triangle ABC, BD = 4x + 2 and DF = 3x and the value of x is -1

Centroid is a term used in triangles and it is equals to the reciprocal of three-second of the distance from each midpoint of the given triangle to each vertices.

Given point D is the centroid of triangle ABC, BD = 4x + 2 and DF = 3x and Centroid is a term used in triangles and it is equals to the reciprocal of three-second of the distance from each midpoint of the given triangle to each vertices.

we know that,

BD = 4x+2

DF = 3x

So by the given formulae, we used to solve the x value as,

BD = (1/(3/2)) [DF]

BD = (2/3)[DF]

4x+2 = (2/3)(3x)

4x+2 = 2(x)

4x+2 = 2x

4x-2x = -2

2x = -2

x = -1

Therefore, the value of x is x = -1

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Ashton has 4.5 bags of pecans. since you can't have half a bag, he might need to round up to 5 bags

A fraction represents a part of a whole.

If Ashton used 1/4 of the pecans in a soup recipe, he has 3/4 of the pecans left.

To find out how many pounds of pecans he has left.

we can multiply the original amount of pecans by 3/4:

3/4 x 6 pounds = 4.5 pounds

So Ashton has 4.5 pounds of pecans left to split into bags.

If he splits the remaining pecans into 1-pound bags, then he has:

4.5 pounds ÷ 1 pound/bag = 4.5 bags

Therefore, Ashton has 4.5 bags of pecans. However, since you can't have half a bag, he might need to round up to 5 bags

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The complete question

Ashton picked 6 pounds of pecans. He used 1/3 of the pecans in a soup recipe. Ashton puts the pecans that are left in 1/4 pound bags. How many bags of pecans does he have

Answer:

J(t) = 230,600(1.009)^t

Step-by-step explanation:

J(t) = 230,600(1 + 0.009)^t, or

J(t) = 230,600(1.009)^t                                                                                                                                                                                                              If this is Wrong ill do. it again!!