Answer:
y = 4x - 8
Step-by-step explanation:
y = 4x + b
4 = 4(3) + b
4 = 12 + b
-8 = b
find the value of the trigonometric ratio.
Answer:
12/13
Step-by-step explanation:
sinX = opposite/hypotenuse = 12/13
SOMEONE HELP ME PLEASE
express the following shaded area using a definite integral. use geometry to calculate the area. please show work too
Answer:
Integrate( sqrt(9-x^2) from x=-3 to x=3)
Step-by-step explanation:
The equation for a full circle is (x-h)^2+(y-k)^2=r^2 where (h,k) is center and radius is r.
Your center, your (h,k) is (0,0). Your radius, your r, is 3.
So your equation is (x-0)^2+(y-0)^2=3^2 or more simply x^2+y^2=9.
We also must consider we don't have full circle.
Solving for y will give us the circle in terms of top half if we take positive values and bottom half if we take negative values. Since y is positive in the picture, you only see top half, we will only take the positive cases for y.
Subtracting x^2 on both sides gives: y^2=9-x^2
Square root both sides: y= sqrt(9-x^2)
(I did not choose -sqrt(9-x^2) because again y is positive).
So the x's in the picture range from -3 to 3.
The integral is therefore,
Integrate( sqrt(9-x^2) from x=-3 to x=3)
Two trains leave towns 1542 kilometers apart at the same time and travel toward each other. one train travels 11 km/h slower than the other. if they meet in 6 hours, what is the rate of each train?
Rate of the slower train:
Rate of the faster train:
Answer:
Slower trains: 123 km/h
Faster train: 134 km/h
Step-by-step explanation:
In order to solve this problem, one must know the following formula:
[tex]speed*time=distance[/tex]
The problem gives one the following information:
There are two trains heading towards each other, one is (11 km/h) faster than the other.There are (1542 km) between the two trains.It takes 6 hours for the two trains to meet each other.Let ([tex]speed_1[/tex]) represent the speed of the slower train and ([tex]speed_2[/tex]) represent the speed of the faster train.
One can form an equation, let (x) represent the speed of the slower train. Using the distance equation, one can state that the speed of each train times the travel time equals the distance. Since the trains met each other in (6) hours, and the combined distance traveled between the two trains is (1542 km); one can use this information to form an equation.
[tex](travel\ time)(speed_1)+(travel\ time)(speed_2)=distance[/tex]
Substitute,
[tex]6(x)+6(x+11)=1542[/tex]
Simplify, distribute, multiply every term inside of the parenthesis by the term outside of it. Then combine like terms,
[tex]6x+6x+66=1542[/tex]
[tex]12x+66=1542[/tex]
Inverse operations,
[tex]12x+66=1542[/tex]
[tex]12x=1476[/tex]
[tex]x=123[/tex]
Solve for the speed of the faster train. It is given that it is (11 km/h) faster than the slower train.
[tex]speed_1+11=speed_2\\123+11=speed_2\\134=speed_2[/tex]
name least to greatest
3780
3.78
0.378
378
0.0378
Answer:
0.0378
0.378
3.78
378
3780
Answer: 0.0378, 0.378, 3.78, 378, 3780
Step-by-step explanation:
Chocolate beans are packed in 250 g and 750 g packages. The number of 250 g packages and 750 g packages are in the ratio 1 : 2. If two of the 750 g packages are replaced into 250 g packages, then the ratio becomes 5 : 3. Find
a) the original number of 250 g packages,
b) the total mass of the chocolate beans.
Answer:
a) 4 packages
b) 7000 g or 7 kg
Step-by-step explanation:
x is the number of 250g packages and y is the number of 750g packages.
2x = y
3(x + 2 x (750 : 250)) = 5(y - 2)
3(x + 6) = 5(y - 2)
3(x + 6) = 5(2x - 2)
3(x + 6) = 5(2(x - 1))
3(x + 6) = 5 * 2 * (x - 1)
3(x + 6) = 10(x - 1)
3x + 18 = 10x - 10
(3x + 18) + 10 = (10x - 10) + 10
3x + 28 = 10x
28 = 10x - 3x
28 = 7x
x = 28/7
x = 4
y = 2 * 4 = 8
(250 * 4) + (750 * 8) = 7000 g
Multiply the polynomials.
[tex]\\ \sf\longmapsto( 7x {}^{2} + 9x + 7)(9x - 4) \\ \\ \sf\longmapsto {7x}^{2} (9x - 4) + 9x(9x - 4) + 7(9x - 4) \\ \\ \sf\longmapsto 63x {}^{3} - 28 {x}^{2} + {81x}^{2} - 36x + 63x - 28 \\ \\ \sf\longmapsto {63x}^{3} + 53 {x}^{2} + 27x - 28[/tex]
Option d is correct
hipe it helps you...............
hipe it helps you...............
Which number lines have points that represent additive inverses? Check all
that apply
-54-3 -2 -1 0
1
2
3
4 5
-513 2-1
0
1
2.
3
4 5
5 4 3 2 1
1
2
3 4
-54-3-2-1
0
1
2
3 4 5
Answer:
2nd and fourth one
Step-by-step explanation:
I just did it and if you look at both of them and if you look closely they each have a negative and a positive
What is the volume of this figure?
Answer:
156.25
Step-by-step explanation:
1/2 × b ×h =12.5
12.5 ×9 =156.25 hope you ace it
1. Find(x) + g(x)
4 options to pick from
helpppppppp will mark brainlest
Answer:
-8
Step-by-step explanation:
what do you think, when you look at the examples given in the problem definition ?
don't you see the pattern, that f(x) = x+2 ?
f(1) = 1+2 = 3
f(2) = 2+2 = 4
f(3) = 3+2 = 5
so, if we follow this assumption, then
f(-10) = -10 + 2 = -8
The included side between
The included side between
The included side between
Answer:
what?????............. :O
Help me with this please (khan academy)
Answer:
5*2 +2*2 = s*2
s = 5.38
s = 5.4
What is the greatest common factor of 15n^5, 30n^3, and 45n^2
Answer:
15n^2 as it the highest expression that is common among these three.
help me pls pls help
Answer:
third one is a required answer.
x =2y
or
1/x=y
Answer:
Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7
Step-by-step explanation:
Step 1: Define proportional relationship
According to Khan Academy, "proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other."
Step 2: Find the proportional relationship
Looking at option 3, we see that x is always 2 times bigger than y. This means as y increases, x is twice that amount. So if y is 10, x would be 20 and so on. Therefore, Option 3 is the correct answer.
Answer: Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7
Find derivative of 3x^2+4 using limits
The derivative of a function f(x) is defined as
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]
For f(x) = 3x ² + 4, we have
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]
[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]
Find the measure of the indicated angle to the nearest degree
[tex] \cos(θ) = \frac{6}{32} \\ θ = 79.19[/tex]
THE LOGO SHOWN BELOW HAS A TOTAL AREA OF 125cm² AND THE SQUARE HAS SIDE LENGTH 5cm.CALCULATR THE WIDTH OF THE LOGO.
Answer:
Please show an image
can someone help me out
The length of a rectangle is 9 inches more than half the width. Find the length if the perimeter is 60 inches.
Answer:
Length = 10.435 inches
Step-by-step explanation:
Let the length be l
Let the width be w
Since the length is 9 inches more than half the width.
Then;
L = 0.5w + 9
Perimeter of a rectangle is;
P = 2Lw
Thus;
P = 2w(0.5w + 9)
Since perimeter = 60
Then;
2w(0.5w + 9) = 60
w² + 18w = 60
w² + 18w - 60 = 0
From quadratic formula;
w ≈ 2.87 in
L = 0.5(2.87) + 9
L = 10.435 in
(15×4)6÷6[{32÷4(7x2-15+5)}+3]
(15×4)6÷6[{32÷4(7x2-15+5)}+3]
= -2
[ use BODMAS rule]
Please help! Math question!
Answer:
n=4
Step-by-step explanation:
3n - (2+n) = 6
Distribute the minus sign
3n -2-n = 6
Combine like terms
2n-2 =6
Add 2 to each side
2n-2+2 = 6+2
2n = 8
Divide by 2
2n/2 = 8/2
n=4
Which of the following values are in the range of the function graphed below? Check all that apply
Answer:
B, C, D
Step-by-step explanation:
In this problem, the range is what the output, or y, can be. The origin, or the middie of the graph, is when x=0 and y=0. From the 10s on the screen, we can gather that 5 lines = a distance of 10 on the graph. Using this information, we can say
5 lines = distance of 10
divide both sides by 5 to find the distance for each line
1 line = distance of 2
The function goes from y=0 to three lines down, for a distance of 6. The range is therefore [-6,0] as all values from -6 to 0 on the y axis are included on the graph, including 0 and -6. In this range, -6, -2, and -1 are all included.
I need the answer ASAP
1. Add Area (Split the shape up to two or more known
shapes first)
12.5 ft
11.6 ft
19.2 ft
16.7 ft
Answer:
Step-by-step explanation:
The shape cam be split into a triangle and a trapezoid
✔️Area of the trapezoid = ½(a + b)h
Where,
a = 12.5 ft
b = 16.7 ft
h = 11.6 ft
Plug in the values
Area of the trapezoid = ½(12.5 + 16.7)*11.6
Area of trapezoid = 169.36 ft²
✔️Area of the triangle = ½*b*h
b = 16.7 ft
h = 19.2 - 11.6 = 7.6 ft
Area of the triangle = ½*16.7*7.6
= 63.46 ft²
✔️Area of the shape = 169.36 + 63.46
= 232.82 ft²
why does an absolute value equation equal to zero only has 1 equation
Answer:
see below
Step-by-step explanation:
The reason why an absolute value equation equal to zero only has one solution
We set the absolute value equation equal to ± the solution
±0 = 0 There is only one value for ±0 which is 0, therefore there is only one solution
What is the scale factor of this dilation?
A 1/5
B 1/2
C 1
D 2
( 1,-2), gradient = -3
Answer:
if you are required to find the equation of a straight line use the formula y-y1= m (x-x1)
y+2=-3(x-1)
y+2=-3x+3
y= -3x+3-2
y -3x+1
hope this helps
Answer:
y = -3x + 1
Step-by-step explanation:
(y -(-2)) = -3(x-1)
y+ 2 = -3x+ 3
y = -3x + 1
Can SOMEONE PLEASE HELP ME? I really need to get this work done by tonight. PLEASE
Help pls will give brainliest
Answer:
[(12+24)*7]/2=126. + area of circle. πr²/2= 72*3=216
Step-by-step explanation:
the answer is 342 if we assume valume of π to 3
(a-√a/√a-1) - (√a+1/a+√a) : √a+1/a. solve a
Answer:
Step-by-step explanation:
[tex]\displaystyle \ \Large \boldsymbol{} \frac{a-\sqrt{a} }{\sqrt{a}-1 } -\frac{\sqrt{a}+1 }{a+\sqrt{a} } :\frac{\sqrt{a}+1 }{a} = \\\\\\\frac{\sqrt{a}(\sqrt{a} -1 ) }{(\sqrt{a}-1) } -\frac{\sqrt{a}+1 }{\sqrt{a}(\sqrt{a}+1 )}\cdot \frac{\sqrt{a}\cdot \sqrt{a} }{\sqrt{a}+1 } = \\\\\\\sqrt{a} -\frac{\sqrt{a} }{1+\sqrt{a} } =\frac{a+\sqrt{a}-\sqrt{a} }{1+\sqrt{a} } = \\\\\\\frac{a}{\sqrt{a}+1 } \cdot \frac{\sqrt{a}-1 }{\sqrt{a}-1} } =\boxed{\frac{a\sqrt{a} -a}{a-1} }[/tex]